InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 101. |
Which one of the following is a slow reaction? (a) Rusting of iron (b) Combustion of carbon (c) Reaction between BaCl2 and dil. H2SO4(d) Reaction between acidified K2Cr2O7 with NaCl. |
|
Answer» (a) Rusting of iron |
|
| 102. |
Which one of the following is the unit of rate of reaction? (a) s-1 (b) mol s-1(c) mol L-1 s-1 (d) mol L s |
|
Answer» (c) mol L-1s-1 |
|
| 103. |
Which one of the following is the unit of rate constant for a first order reaction? (a) mol L-1s-1(b) mol-1 L s-1(c) s-1 (d) mol L S |
|
Answer» s-1 is the unit of rate constant for a first order reaction. |
|
| 104. |
The order of decomposition of acetaldehyde is ………(a) 1 (b) 1.5 (c) 2 (d) 5/2 |
|
Answer» The order of decomposition of acetaldehyde is 1.5. |
|
| 105. |
Fill in the blanks. 1. The rate of the reaction ……….. with the increase in the concentration of the reactants. 2. Higher the concentration of reactants greater is the possibility of and hence the ………..3. In the presence of catalyst the energy of activation is ……….. and hence greater number of molecules change over to products there by increasing the rate of the reaction. 4. Bio availability of drugs within the body and this branch of study is called ……….. 5. ……….. has a half life of 2.5 hours within the body. 6. The change in concentration of species per unit time gives the ……….. of the reaction. 7. The rate constant is equal to the rate of the reaction when concentration of reactants is ……….. 8. Increase in surface area of reactant leads to more collisions per litre per second and hence the rate of the reaction is ……….. 9. Acid hydrolysis of an ester is an example of ……….. 10. Molecularity of a chemical reaction will never be equal to ……….. |
|
Answer» 1. increases 2. collisions, rate 3. lowered 4. Pharmaco kinetics 5. Paracetamol 6. rate 7. unity 8. increased 9. Pseudo first order reaction 10. zero |
|
| 106. |
A large increase in the rate of a reaction for a rise in temperature is due to ……(a) the decrease in the number of collisions (b) increase in the number of activated molecules (c) the shortening of mean free path (d) the lowering of activation energy |
|
Answer» (b) increase in the number of activated molecules An increase in the rate of a reaction for a rise in temperature is due to increase in collision frequency, shortening of mean free path and increase in the number of activated molecules.Increasing the temperature increases reaction rates because of the disproportionately large increase in the number of high energy collisions. It is only these collisions (possessing at least the activation energy for the reaction) which result in a reaction. ∴Answer is (B) |
|
| 107. |
Half life period of a reaction is found to be inversely proportional to the cube of its initial concentration. The order of the reaction is …..(a) 2 (b) 5 (c) 3 (d) 4 |
|
Answer» The order of the reaction is 4 |
|
| 108. |
Identify the molecularity and write the rate law for each of the following elementary reactions :(a) NO(g) + O3(g) → NO3(g) + O(g)(b) H2I(g) + I(g) → 2HI(g)(c) CI(g) + Cl(g) + N2(g) → N2(g) |
|
Answer» (a) NO(g) + O3(g) → NO3(g) + O(g) Molecularity is 2. Rate law : Rate = k [NO] x [O3] (b) H2I(g) + I(g) → 2HI(g) Molecularity is 2. Rate law : Rate = k [H2I] x [I] (c) CI(g) + Cl(g) + N2(g) → N2(g) Molecularity is 3. Rate law : Rate = k [Cl]2 |
|
| 109. |
A certain reaction occurs in the following steps : (i) Cl(g) + O3(g) → ClO(g) + O2(g) (ii) ClO(g) + O(g) → Cl(g) + O2(g) (a) Write the chemical equation for overall reaction. (b) Identify the reaction intermediate. (c) Identify the catalyst. (d) What is the molecularity of each step? |
|
Answer» Step I : Cl(g) + O3(g) → ClO(g) + O2(g) Step II : ClO(g) + O(g) → Cl(g) + O2(g) (a) Overall reaction is obtained by adding both the reactions. O3(g) + O(g) → 2O2(g) (b) Reaction intermediate is ClO(g) which is formed in the first step and removed in the second step. (c) Cl(g) acts as a catalyst. It is an example of homo-geneous catalysis in which catalyst Cl(g) forms an intermediate ClO(g) and again is released in the second step. (d) Since both the steps involve two reactants each, both the steps are bimolecular. |
|
| 110. |
Match the following :First order reaction2NO + O2 → 2NO2Second order reactionCH3CHO → CH4 + COThird order reactionPhotochemical11/2order reactionN2 + O2 → 2NOZero order reactionH2O → 2H2O + 1/2O2 |
||||||||||
Answer»
|
|||||||||||
| 111. |
A reaction takes place in two steps, 1. NO(g) + Cl2(g) NOCl2(g) 2. NOCl2(g) + NO(g) → 2NOCl(g) a. Write the overall reaction. b. Identify reaction intermediate. c. What is the molecularity of each step? |
|
Answer» Given : (1) NO(g) + Cl2(g) → NOCl2(g) (2) NOCl2(g) + NO(g) → 2NOCl(g) (a) Overall reaction is obtained by adding both the reactions 2NO(g) + Cl2(g) → 2NOCl2(g) (b) The reaction intermediate is NOCl2, since it is formed in first step and consumed in the second step. (c) Since the first step is a slow and rate determining step, the molecularity is two. Since the second step is a fast step its molecularity is not considered. |
|
| 112. |
Consider the reaction1. Write down 2 steps through which the reaction takes place.2. Find out the slowest step.3. Which is the rate-determining step?4. Find out the order of the reaction. |
|
Answer» 1. 2H2O2 + I- → → H2O +IO- H2O2 + IO- → H2O + I- + O2 2. 2H2O2 + I- → H2O + IO- 3. 2H2O2 + I- → H2O + IO- 4. Order = 2 |
|
| 113. |
A complex reaction takes place in two steps :(i) NO(g) + O3(g) → NO3(g) + O(g)(ii) NO3(g) + O(g) → NO2(g) + O2(g)The predicted rate law is rate = k [NO] [O3].Identify the rate-determining step. Write the overall reaction. Which is the reaction intermediate? Why? |
|
Answer» (i) NO(g) + O3(g) → NO3(g) + O(g) (ii) NO3(g) + O(g) → NO2(g) + O2(g) (a) The first step is slow and rate determining step since the rate depends on concentrations of NO(g) and O3(g). (Given : Rate = k [NO] x [O]) (b) The overall reaction is the combination of two steps. NO(g) + O3(g) → NO2(g) + O2(g) (c) NO3(g) and O(g) are reaction intermediates. They are formed in first step (i) and removed in the second step (ii). |
|
| 114. |
For the reaction, 2X + 3Y → 4Z, reaction may be represented as :(a) Rate = \(-\frac{1}{2}\)\(\frac{d[X]}{dt}\) = \(\frac{1}{3}\)\(\frac{d[Y]}{dt}\) = \(\frac{1}{4}\)\(\frac{d[Z]}{dt}\)(b) Rate = \(-\frac{1}{2}\)\(\frac{d[X]}{dt}\) = \(-\frac{1}{3}\)\(\frac{d[Y]}{dt}\) = \(\frac{1}{4}\)\(\frac{d[Z]}{dt}\)(c) Rate = \(\frac{1}{2}\)\(\frac{d[X]}{dt}\) = \(\frac{1}{3}\)\(\frac{d[Y]}{dt}\) = \(\frac{1}{4}\)\(\frac{d[Z]}{dt}\)(d) Rate = \(\frac{1}{2}\)\(\frac{d[X]}{dt}\) = \(-\frac{1}{3}\)\(\frac{d[Y]}{dt}\) = \(-\frac{1}{4}\)\(\frac{d[Z]}{dt}\) |
|
Answer» Option : (b) Rate = \(-\frac{1}{2}\)\(\frac{d[X]}{dt}\) = \(-\frac{1}{3}\)\(\frac{d[Y]}{dt}\) = \(\frac{1}{4}\)\(\frac{d[Z]}{dt}\) |
|
| 115. |
A reaction occurs in the following steps :(i) NO2(g) + F2(g) → NO2F(g) + F(g)(slow)(ii) F(g) + NO2(g) → NO2F(g)(fast)(a) Write the equation of overall reaction. (b) Write down rate law. (c) Identify the reaction intermediate. |
|
Answer» (a) The addition of two steps gives the overall reaction as 2NO2(g) + F2(g) → 2NO2F(g) (b) Step (i) is slow. The rate law of the reaction is predicted from its stoichiometry. Thus, rate = k[NO2] [F2] (c) F is produced in step (i) and consumed in step (ii) hence F is the reaction intermediate. |
|
| 116. |
Define molecularity of a reaction. |
|
Answer» The number of reacting species taking part in an elementary reaction which must colloid simultaneously in order to bring about a chemical reaction is called molecularity of reaction. |
|
| 117. |
What is the order of reaction whose unit of rate constant and rate of reaction are same |
|
Answer» Zero order.. |
|
| 118. |
Differences between Rate of a reaction and Rate constant. |
||||||||
Answer»
|
|||||||||
| 119. |
What is SI unit of rate constant of zero order reaction? |
|
Answer» Mol/L/s is SI unit of rate constant of zero order reaction. |
|
| 120. |
Differences between Elementary and complex reaction. |
||||
Answer»
|
|||||
| 121. |
What is SI Unit of rate constant of nth order reaction ? |
|
Answer» (mol)1-n . Ln-1.s -1 |
|
| 122. |
What are complex reactions? |
|
Answer» Reactions taking place in more than one step are called complex reaction. |
|
| 123. |
Calculate the overall order of a reaction which has the rate expression. Rate= K [A]1/2 [B]3/2 |
|
Answer» Order of reaction = 1/2 + 3/2 = 2 |
|
| 124. |
Define order of a reaction. |
|
Answer» Sum of the powers of the concentration of the reactants in the rate equation is called order of reaction. |
|
| 125. |
Define rate constant of a reaction. |
|
Answer» Rate constant is equal to rate of reaction when the product of the molar conc. of reactants is unity. |
|
| 126. |
Define rate equation or rate expression. |
|
Answer» Expression in which reaction rate is given in terms of molar conc. of reactants with each term raised to some power which may or may not be same as the stoichiometric coefficient of the reacting species in a balanced chemical equation. |
|
| 127. |
What is rate law? |
|
Answer» Representation of rate of reaction in terms of concentration of reactants is called rate law. Rate expression and rate equation. |
|
| 128. |
What are the characteristics of rate constant? |
|
Answer» The characteristics of rate constant are as follows :
|
|
| 129. |
Mention any two factors which influence the rate of reaction . |
|
Answer» (1) Pressure or conc. of reactants (2) temperature (3) catalyst. |
|
| 130. |
Define the rate constant. What are the factors which influence the rate constant of a chemical reaction? |
|
Answer» (A) Rate constant : The rate constant of a chemical reaction is defined as the rate of the chemical reaction when the concentration (or active masses) of each reactant has unit value, i.e., 1 mol dm-3 in the case of solution and the pressure is 1 atm in case of gases, e.g., for a reaction, A → products, Rate R = k[A]. If [A] = 1 mol dm-3, then k = R. (B) The rate constant of a reaction depends on the following factors :
|
|
| 131. |
Define and explain the term order of a chemical reaction. |
|
Answer» Order of a chemical reaction : The order of a chemical reaction is defined as the number of molecules (or atoms) whose concentrations influence the rate of the chemical reaction. OR The order of a chemical reaction is defined as the sum of the powers (or exponents) to which the concentration terms of the reactants are raised in the rate law expression for the given reaction. Explanation : Consider a reaction, n1A + n2B → Products Where n1 moles of A react with n2 moles of B. The rate of this reaction can be expressed by the rate law equation as, R = k [A]n1 [B]n2 Where k is the rate constant of the reaction, hence, the order of the reaction is n – n1 + n2, (observed, experimentally). If n = 1, The reaction is called the first order reaction, If n = 2, It is called the second order reaction, etc. If n = 0, It is called the zero order reaction. e.g., photochemical reaction of H2(g) and Cl2(g). |
|
| 132. |
What are the features (or key points) of order of a reaction? |
|
Answer» The features of order of reaction are as follows :
|
|
| 133. |
Explain the difference between instantaneous rate of a reaction and average rate of a reaction. |
||||||||
|
Answer» The difference between instantaneous rate of reaction and averatge rate of a reaction are as Below
|
|||||||||
| 134. |
With the help of an example explain what is meant by pseudo first order reaction. |
|
Answer» Pseudo-first-order reaction: The reaction which is bimolecular but order is one is called a pseudo-first order reaction. This happens when one of the reactants is in large excess. E.g., acidic hydrolysis of the ester (ethyl acetate). CH3COOC2H5 +H2O ------> CH3COOH + C2H5OH similarly inversion of cane sugar or hydrolysis of cane sugar is an example of pseudo first-order reaction. |
|
| 135. |
In a reaction 2A+B→A2B the reaction A will disappear at |
|
Answer» According to the given equation, the rate of disappearance of reactant A is twice the rate of disappearance of reactant B. |
|
| 136. |
The reaction, 3ClO3Θ ClO3Θ + 2 ClΘ occurs in two steps,(i) 2 ClO- → ClO2Θ(ii) ClO2Θ + ClOΘ → ClO3Θ + ClΘThe reaction intermediate isa. ClΘ b. ClO2Θ c. ClO3Θ d. ClOΘ |
|
Answer» Correct answer is b. ClO2Θ |
|
| 137. |
What is the half life of a first order reaction if time required to decrease concentration of reactant from 0.8 M to 0.2 M is 12 h? a. 12 h b. 3 h c. 1.5 h d. 6 h |
|
Answer» Correct answer is d. 6 h |
|
| 138. |
Slope of the graph ln[A]t versus t for first order reaction is a. -k b. k c. k/2. 303 d. -k/2. 303 |
|
Answer» a. -k Slope of the graph ln[A]t versus t for first order reaction is -k. |
|
| 139. |
The order of the reaction for which the units of rate constant are mol dm-3 s-1 isa. 1b. 3 c. 0 d. 2 |
|
Answer» c. 0 The order of the reaction for which the units of rate constant are mol dm-3 s-1 is 0. |
|
| 140. |
Time required for 90 % completion of a certain first order reaction is t. The time required for 99.9 % completion will be a. t b. 2tc. t/2 d. 3t |
|
Answer» Correct answer is d. 3t |
|
| 141. |
The rate constant for the reaction 2N2O5(g) → 2N2O4(g) + O2(g) is 4.98 × 10-4 s-1. The order of reaction isa. 2 b. 1 c. 0 d. 3 |
|
Answer» Correct answer is b. 1 |
|
| 142. |
The rate of reaction increases rapidly on slightly increase in temperature, because(a) The number of activated reactants increases.(b) The number of collisions increases.(c) The number of free path increases.(d) Heat of reaction increases. |
|
Answer» (a) The number of activated reactants increases. |
|
| 143. |
Which of the following relationship is correct for zero order reaction?(a) t3/4 = t1/2(b) t3/4 = 1.5 t1/2(c) t3/4 = 0.25t1/2(d) t3/4 = \(\frac { 1 }{ 3 }\)t1/2 |
|
Answer» (b) t3/4 = 1.5 t1/2 |
|
| 144. |
Which the following statement is true for the first order reaction?(a) The rate of reaction is directly proportional to zera power of concentration of reactants.(b) The unit of rate constant is mol L-1 s-1.(c) The half life of reaction does not depend on initial concentration of reactants.(d) Can not be say directly. |
|
Answer» (c) The half life of reaction does not depend on initial concentration of reactants. |
|
| 145. |
The unit of rate constant of zero order reaction will be(a) mol L-1 s-1(b) L mol-1 s-1(c) s-1(d) mol2 L-1 s-1 |
|
Answer» (a) mol L-1 s-1 |
|
| 146. |
The rate constant of reaction is 7.239 x 10-4 s-1, then the order of reaction will be(a) 0(b) 1(c) 2(d) 3 |
|
Answer» The answer is (b) 1 |
|
| 147. |
Arrhenius equation is:(a) k = – A e-Ea/RT(b) k = A e-Ea/RT(c) k = A e Ea/RT(d) k = e-Ea/RT |
|
Answer» (b) k = A e-Ea/RT |
|
| 148. |
Time required to complete 90% first order reaction will be(a) 1.1 times of half life(b) 2.2 times of half life(C) 3.3 times of half life(d) 4.4 times of half life |
|
Answer» (C) 3.3 times of half life |
|
| 149. |
The reaction between A and B is first order with respect to A and zero order with respect to B. Fill in the blanks in the following table : |
|
Answer» (II)—is 0.2; (III)—is 8 x 10-2; (IV)—is 0.1 |
|
| 150. |
The reaction between A and B is first order with respect to A and zero order with respect to B. Fill in the blanks in the following table:Experiment[A]/mol L-1[B]/mol L-1Initial rate/mol L-1 min-1I0.10.12.0 x 10-2IIx0.24.0 x 10-2III0.40.4yIVz0.22.0 x 10-2 |
|
Answer» rate law = K [A] from I 2.0 × 10-2 = K 0.1 ⇒ K = 2.0 × 10-1min-1 from II 4 .0 × 10-2 = 2 .0 × 10-31 x ⇒ K = 2 .0 × 10-1 mol L-1 from III y = 2.0 × 10-1 × 0.4 ⇒ y = 8 × 10-2 mol 1L from IV 2.0 × 10-2 = 2.0 × 10-1 × z ⇒ z = 0.1 mol L-1 |
|