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2651.

The pH decreases when milk is changed to curd. Give reason.

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Solution :Change of milk to CURD curdling is also called souring of milk. It is CAUSED DUE to the formation of more LACTIC acid. Thus the number of hydrogen ions (`H^(+)` ions) increases and therefore, the pH decreases.
2652.

The period with electrons in the shell, K, Land M .

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SOLUTION :PERIOD 3 .
2653.

The period number of an element is equal to the from left to right in a period of the periodic table.

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SOLUTION :ELECTRON SHELLS
2654.

The period and group number of an element with atomic number 7 are

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2,3
2,4
2,5
2,15

Answer :D
2655.

The percentage of oxygen in a metallic oxide of a bivalent metal is 20.1%. The molecular weight of the compound is 79.5. Write the molecular formular of the compound, considering the symbol ofthe metal as M and find out the atomic weight of the metal.

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Solution :(i) calculate the number of atoms of oxygen present in the compound
(ii) calculation of the number of atoms of oxygen present in one MOLECULE of themetallic oxide from the percentage of oxygen GIVEN
(III) DETERMINATION OFTHE formula of the compound
(iv) calculation of atomic weight of the metal
(v) `63.5`
2656.

The percentage of metal in two metal oxides, A and B is 74.2% and 59%, respectively. Show that thelaw of multiple proportions is obeyed.

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Solution :`{:("Metal Oxides",,"Percentage of Metal",,"Percentage of OXYGEN"),("A",,"74.2",,"25.8"),("B",,"59",,"41"):}`
In A, 74.2g ofmetal combines with 25.8g OFOXYGEN
? combines with 1 g of oxygen
` = (74.2g)/(25.8 g) = 2.87` g
In B, 59g of metal combines with 41g ofoxygen
? combines with 1 g of oxygen
` =59/41 g = 1.43` g
`:.` The ratio by WEIGHT of metal combining with fixedmass of oxygen in A andB
` = 2.87 : 1.43 = 2 : 1`
Hence, law of multiple proportions is OBEYED.
2657.

The percentage of hydrogen in H_2Ois

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44.45
5.55
88.89
11.11

Solution :11.11
2658.

The percentage of hydrogen in H_(2)O is ……………… .

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8.88
11.2
20.6
`80.0`

Solution :Hint : 1 MOLE of `H_(2)O` has 2.016 g of `H_(2)`
`THEREFORE"Percentage of "H_(2)=(2.016)/(18)xx100`
`=11.2`
2659.

The percentage mass of magnesium in chlorophyll is 2.68% The number of magnesium atoms in 2 g of chlorophyll is _____________

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ANSWER :`1.34xx10^(21)`
2660.

The percentage composition of elements is useful to determine ………………….and ………………….. .

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SOLUTION :EMPIRICAL FORMULA, MOLECULAR formula
2661.

The percentage by weight of O_(2) in CaSO_(4)(O=16, Ca=40, S=32) is ……………. .

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`64%`
`28.2%`
`47.05%`
`16.2%`

Solution :HINT : `"% by weight of "O_(2)`
`=(64)/(136)xx100=47.05%`
2662.

The particles present in strong electrolytes are

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only molecules
MAINLY ions
ions AD molecules
only atoms

Answer :B
2663.

The particle used by Rutherford in alpha-ray scat­tering experiment was

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neutron
electron
HELIUM nucleus
X RAYS

ANSWER :C
2664.

The pair of elements which shows catenation is

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silicon and sodium
CARBON and SULPHUR
carbon and CHLORINE
silicon and sodium

Answer :B
2665.

The Packing efficiency in unit cell is

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In sc `48%`
In ccp `74%`
In BCC `32%`
All of the above

Answer :B
2666.

Give reason - The oxidising power of elements increases from left to right along a period.

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SOLUTION :Because IONISATION ENERGY INCREASES.
2667.

The oxides of the elements of groups 1 and 2 are _____ in nature.

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ANSWER :BASIC
2668.

The oxides of very reactive metals are reduced to metals by :

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ELECTROLYTIC REDUCTION
heating with carbon
heating with aluminium
liquation

Solution :electrolytic reduction
2669.

The oxides of highly reactive metals cannot be reduced by carbon. (TRUE/ FALSE)

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ANSWER :T
2670.

The oxidation state of 'S' in Kal(SO_(4))_(2) .12H_(2)O is

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`-2`
`-1`
2
`+6`

ANSWER :D
2671.

The oxidation state of Fe in Fe_(3)O_(4) is :

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`+2`
`+3`
`(8)/(3)`
`+2,+3`

ANSWER :D
2672.

The oxidation reaction which produces heat and light is

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Endothermic
Photochemical
Combustion
Exothermic

Answer :C
2673.

The oxidation of ethanol gives ethanal.

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ANSWER :T
2674.

The overuse of resources is one major cause of their ____

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SOLUTION :DEPLETION
2675.

The organic compounds that are composed of only carbon and hydrogen atoms are called………………..

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SOLUTION :HYDROCARBONS
2676.

The organic compounds are usually poor conductors of elelctricity .

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ANSWER :T
2677.

The organic compound used in cough syrups and in digestive syrups is……………….

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ETHANOIC acid
Ethyl ethanoate
METHANOL
ethanol

Answer :D
2678.

The organic compound used for coagulating rubber from latex is…………………..

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methanoic ACID
ETHANOIC acid
ethanol
METHANOL

ANSWER :B
2679.

The organic compound that depresses the central nervous system after consumption is……………………

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ETHANOL
METHANOL
ACETIC acid
ethyl ethanoate

ANSWER :B
2680.

The organic compound contains 2 carbon atoms, the root word according IUPAC is ____________

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Meth-
Eth-
Prop-
But-

Answer :B
2681.

The organic compound mixed with ethanol to make it spurious is:

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METHANAL
Methanoic acid
METHANOL
Ethanoic acid

Solution :Methanol
2682.

The organ which perform different function but have the same basic structure are called.

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Vestigal organ
Analogous organs
Homologous organs
Analytic organs

Answer :3
2683.

The ore which can be purified by gravity separation method is ……………….. .

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HAEMATITE
OXIDE ORES
SULPHIDE ores
both (a) and (b)

ANSWER :D
2684.

The ore of a metal is lighter than the impurities. Which method is suitable for its concentration?

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ANSWER :FORTH FLOATATION PROCESS
2685.

The Siderite is the most important ore of

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ALUMINIUM
iron
copper
`S_(8)`

ANSWER :B
2686.

The order of rectivity of Zn, Fe, Cu and Al is

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Zn GT CU gt Al gt Fe
Zn gt Al gt Cu gt Fe
Al gt Zn gt Fe gt Cu
Zngt Al gt Fe gt Cu

ANSWER :C
2687.

The order of procsses involved in the dressing of an ore is (i) grinding and crushing (ii) hand-picking (iii) Pulverisation

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(i), (ii), (III)
(i), (iii), (ii)
(ii), (iii), (i)
(ii), (i), (iii)

Solution :DRESSING of ORE can be carried out by hand-picking, CRUSHING and grinding, PULVERISATION.
2688.

The order of ease of oxidation of the ions F^(-), OH^(-), Br^(-), SO_(4)^(2-) is _______

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`SO_(4)^(2-) gt F^(-) Br^(-) gt OH^(-)`
`SO_(4)^(2-) lt Br^(-) lt OH^(-) lt F^(-)`
`SO_(4)^(2-) gt F^(-) gt Br^(-) gt OH^(-)`
`OH^(-) lt Br^(-) lt F^(-) lt SO_(4)^(2-)`

SOLUTION :`SO_(4)^(2-) lt F^(-) lt Br^(-) lt OH^(-)`
In an ELECTRONEGATIVE SERIES, EASE of oxidation increases from top to BOTTOM
2689.

The orbitals p and d can form pi bonds, but the s-orbital cannot form a pi bond. Give reasons.

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<P>

Solution :(i) shape of orbitals
(II)SHAPES of p- and d-orbitals in contrast to the shape of 's-' orbitals
(III) type of overlapping in `PI` bond
2690.

The oil drop experiment by R. A. Mullikan was performed to find

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charge on the neutron
charge on the ELECTRON
charge on the Proton
NONE of these

Answer :B
2691.

The [OH^(-)] ion concentration of a solution is 1.0xx10^(-8)M.What is the pH of the solution?

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SOLUTION :The CONCENTRATION of hydroxide ion=`[OH^(-)]=1.0xx10^(-8)`m
pOH=`-log_(10)[OH^(-)]`
pOH=`-log_(10)(1.0xx10^(-8))` pOH=8
pH+pOH=14
`THEREFORE` pH=14-8`implies` pH=6
2692.

The OH^- concentration of a solution is 1.0 xx 10^(-10) M. The solution is

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acidic
basic
neutral
amphoteric

ANSWER :C
2693.

The ………….. Of the elements is a period decreases from left to right and the atomic radii of the element present in a group …………..downwards .

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SOLUTION : ATOMIC SIZE , INCREASES
2694.

The odour of ethanoic acid resembles with:

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TOMATO juice
Kerosene
orange juice
vinegar

ANSWER :D
2695.

The octane number has zero value for

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ISO-OCTANE
n-octane
n-heptane
Tetra ethyl lead

Solution :Octane number is USEDTO check the QUALITY of fuel. It is defined as the percentage by volume of isooctane in a mixture of isooctane and n-heptane.
n-heptane has been given an octane number of zero while iso octane, the octane number of 100.
2696.

The numerical value of ionisation energy of a unipositive ion is approximately equal to

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(a) IP value of neutral ATOM
(b) EA value of neutral atom
(c) IP value of dipositive ion
(d) EA velue of dipositive ion

Solution :The numerical value of ionisation energy of a
uinpositive ion is APPROXIMATELY EQUAL to the electron
AFFINITY of dipositive ion.
2697.

The number of which of the following atomic particles plays a major role in classification of elements in the Modern Periodic Table?

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NEUTRON
ELECTRON
PROTON
all of the these 

ANSWER :C
2698.

The number of water molecules present in a molecule of copper sulphate crystal is

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2
4
7
5

Answer :D
2699.

The number of valence electrons present in Ca atom

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3
2
8
6

Answer :B
2700.

The number of valence electrons present in the 12th element of any period is

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12
2
6
0

Answer :B