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2701.

The number of valence electrons in an element belonging to period 3 and group 2 of the Modern Periodic Table is

Answer»

1
2
3
4

Answer :B
2702.

The number of triple bonds between two C atoms in a molecule of ethyne is

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three
two
one
zero

Answer :C
2703.

The number of structural isomers for C_(6)H_(14) is :

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3
4
5
6

Solution :`CH_(3)-CH_(2)-CH_(2)-CH_(2)-CH_(2)-CH_(3)`
`CH_(3)-CH_(2)-CH_(2)-underset(CH_(3))underset(|)(CH)-CH_(3)`
`CH_(3)-CH_(2)-underset(CH_(3))underset(|)(CH)-CH_(2)-CH_(3)`
`CH_(3)-CH_(2)-underset(CH_(3))underset(|)(CH)-CH_(2)-CH_(3)`
`CH_(3)-underset(CH_(3))underset(|)(CH)-underset(CH_(3))underset(|)(CH)-CH_(3)`
`CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH_(2)-CH_(3)`
There are TOTAL of FIVE STRUCTURAL isomers.
2704.

The number of shells ________ down the group.

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SOLUTION :INCREASES
2705.

The number of periods and groups in the periodic table are ……….

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6,16
7,17
8,18
7,18

Answer :D
2706.

The number of periods and groups in the periodic table are _______

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`6,16`
7,17
8,18
7,18

Answer :D
2707.

The numberof particlespresentin onemoleof anysubstanceis equalto

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`6.023xx10 ^(23)`
`60.23xx 10^(23)`
`6.023 XX 10 ^(27)`
`60.23 xx 10^(27)`

ANSWER :A
2708.

The number of oxygen molecules required for the complete combustion of 5 moles of methane is _________ .

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Answer :`6.023 xx 10^(24)" molecules "11.HXO_(4)`
2709.

The number of oxygen atoms present in 2 moles of a compound, which consists of a bivalent metal anda perchlorate ion is

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4 N
6 N
8 N
16 N

Solution :Let the bivalent METAL ION be `M^(+2)`,then the formula of the compound formed will be `M(ClO_(4))_(2)`.
1 mole of compound contains 8 N oxygen atoms.
`:. ` 2 moles of compound contain 16 N oxygen atoms.
2710.

The number of oxygen atoms present in 2 moles ofa compound, which consists of a bivalent metal anda perchorate ion is

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4 N
6 N
8 N
16 N

Answer :D
2711.

The number of oxygen atoms in 4.4 g of CO_(2) is approximately

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`1.2xx10^(23)`
`6XX10^(22)`
`6xx10^(23)`
`12XX10^(23)`

ANSWER :A
2712.

The number of nodes of an s-orbitals increases with

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the INCREASES in n value
the DECREASES in n value
the increases in 1 value
the decreases in 1 value

Solution :With INCREASE in n value, the number of nodes of 's' orbitals increases.
2713.

The number of nodal regions for an 's'orbital is given by (n - 1). How do you account for this

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SOLUTION :NODAL REGION for 1S ORBITAL
2714.

The number of moles of BaCO_(3) which contains 1.5 moles of oxygen atoms is

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ANSWER :0.5
2715.

The number of moles of a sample that contains 12.046 xx 10^(23) atoms of iron is 2.

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ANSWER :1
2716.

The number of moles of a sample that contain 36 g of water is ………………. .

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1 mole
0.5 mole
4 MOLES
2 moles

Solution :Hint : 18 g of water = 1 mole
`therefore"36 g of water"=(1)/(18)xx36="2 moles"`
2717.

The number of moles in 5 grams of Calcium is …………………. .

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0.5 mole
0.125 mole
1.25 mole
12.5 mole

Solution :Hint : `"No. of MOLES"=("MASS")/("ATOMIC mass")`
`=(5)/(40)=(1)/(8)="0.125 mole"`
2718.

The number of molecules present in one mole of an element is called atomicity of an element.

Answer»

Solution :Correct statement: The number of ATOMS PRESENT in one molecule of an element is called the ATOMICITY of an element.
2719.

The number of molecules of CO_(2)persent in 44 g of CO_(2) is ………… .

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`6.023xx10^(23)`
`3.011xx10^(23)`
`12XX10^(23)`
`3xx10^(10)`

SOLUTION :`6.023xx10^(23)"(Avogadro NUMBER)"`
2720.

Thenumberof moleculesof CO_(2)presentin44 gof CO_(2)is :

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`6.023xx10 ^(23)`
`3XX10^(23)`
`12XX10 ^(23)`
`3xx10 ^(10)`

ANSWER :A
2721.

The number of molecules in 22.4 cm^3of dinitrogen gas at STP is

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`6.002 XX 10^20`
`6.022 xx 10^23`
`22.4 xx 10^20`
`22.4 xx 10^23`

ANSWER :A
2722.

The number of molecules in 16.0 g of oxygen is …………. .

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`6.023xx10^(23)`
`6.023xx10^(-23)`
`3.01xx10^(-23)`
`3.011xx10^(23)`

Solution :Hint : `"32 G of OXYGEN contain "6.023xx10^(23)" molecules."`
`therefore"16 g of oxygen will contain"`
`(6.023xx10^(23))/(32)xx16=3.011xx10^(23)`
2723.

The number of molecules in 22.4cm^(3) of nitorgen gas at STP is

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`6.02xx10^(20)`
`6.02xx10^(23)`
`22.4xx10^(20)`
`22.4xx10^(23)`

Solution :`22400cm^(3)` is the volume of 1 mol GAS, `22.4cm^(3)` is the volume of `22.4/22400=10^(-3)` mol
No. of MOLECULES `=6.02xx10^(23)xx10^(-3)`
`=6.02xx10^(20)`
2724.

The number of metals which exist as gas is/are____

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one
two
three
none

Answer :D
2725.

The number of Li atoms in_____________ g. is 6.022xx10^(24)atoms.

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ANSWER :70G
2726.

The number of isomers of C_6H_14 is

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4
5
6
17

Solution :Isomer of HEXANE, `C_6H_14` are
`CH_3 - CH_2 - CH_2 -CH_2 - CH_2 -CH_3`
`CH_3 - UNDERSET(CH_3) underset(|)(CH) - CH_2-CH_2 - CH_2 -CH_3`
`CH_3-CH_2 - underset(CH_3) underset(|)(CH) - CH_2 - CH_3`
`CH_3 -underset(CH_3)underset(|)(CH) - underset(CH_3)underset(|)(CH) - CH_3`
`CH_3 - underset(CH_3) underset(|)overset(CH_3)overset(|)C - CH_2 - CH_3`
2727.

The number of hydrogen atoms in 60 u of ethane is____________

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ANSWER :`7.226xx10^(24)`
2728.

The number of groups and periods in the modern periodic table respectively, are

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7 and 9
18 and 7
7 and 18
9 and 7

ANSWER :B
2729.

The number of gram-atoms in 8 g of He are

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2
`1.204 XX 10^24`
`3.10 xx 10^23`
none of these

SOLUTION :Gram ATOMIC MASS of He = 4
Number of gram - atoms of He
= mass of He/gram atomic mass of He
= 8/4 = 2
2730.

The number of electrons in the valence shell of the atom of an element indicates the ____ to which the element belongs.

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ANSWER :GROUP
2731.

The number of electrons in the outermost shell ofalkali metals is __________ .

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a.1
b.2
c.3
d.7

Solution :41
2732.

The number of electrons in the outermost shell of a nonmetal can be

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1,2,3 or 4
2,3,4 or 5
4,5,6,7 or 8
4,5,0 or 2

Answer :C
2733.

The number of electrons in the outer shell of the most stable or inert atoms is

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1
4
6
8

Answer :D
2734.

The number of electrons in sodium ion is 10.

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ANSWER :T
2735.

The number of electrons in an element with atomic number X and mass number Y will be

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X - Y
Y-X
X + Y
X

ANSWER :D
2736.

The number of ______ determines which elements will be the first and which the last in a period of the periodic table.

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SOLUTION :ELECTRON
2737.

The number of covalent bonds present in pentane is -

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5
12
16
17

Answer :C
2738.

The number of covalent bonds in a molecule of ethylene (C_(2)H_(4)) is

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4
12
6
5

Answer :C
2739.

The number of covalent bonds present in ethylene is

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5
7
6
4

Answer :C
2740.

The number of covalent bonds in ethylene is

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2 double bonds, 2 SINGLE bonds
2 double and 4 single bonds
2 single and 2 double bonds
1 double and 4 single bonds

SOLUTION :Ethylene molecule has a STRUCTURE.

Contains ONE double bond and four single bonds.
2741.

The number of carbon compounds is so large because of its property of :

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Isomerism
Tetravalency of Carbon
Catenation
All of these

Answer :D
2742.

The number of carbon atoms present in the sixth member of alkenes is

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SIX
FIVE
SEVEN
four

Answer :C
2743.

The number of atoms present in the molecule is called Avogadro number.

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SOLUTION :CORRECT statement: The number of atoms PRESENT in the molecule is CALLED its ATOMICITY.
2744.

The number of atoms present in a molecule is called its ……………… .

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SOLUTION :ATOMICITY
2745.

The number of atoms present in a molecule of an element is known as its

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VALENCY
ATOMICITY
CHEMICAL Formula
symbol

SOLUTION :atomicity
2746.

The number of atoms in a molecule of the elementary substance is called …………… .

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ATOMIC number
Avogadro number
atomic MASS
ATOMICITY

Solution :atomicity
2747.

The nucleus of the hydrogen atom is called a

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neutron
electron
proton
none of them

ANSWER :C
2748.

Thenucleusof anatomconsistof protons and electrons ..

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SOLUTION :CORRECT STATEMENT: thenucleusof anatomconsistof protons& neutrons.
2749.

The noble gas with the smallest atomic radius.

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SOLUTION :HELIUM (He) .
2750.

The no. of significant figures in pi are

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1
2
3
infinite

Answer :D