1.

The number of structural isomers for C_(6)H_(14) is :

Answer»

3
4
5
6

Solution :`CH_(3)-CH_(2)-CH_(2)-CH_(2)-CH_(2)-CH_(3)`
`CH_(3)-CH_(2)-CH_(2)-underset(CH_(3))underset(|)(CH)-CH_(3)`
`CH_(3)-CH_(2)-underset(CH_(3))underset(|)(CH)-CH_(2)-CH_(3)`
`CH_(3)-CH_(2)-underset(CH_(3))underset(|)(CH)-CH_(2)-CH_(3)`
`CH_(3)-underset(CH_(3))underset(|)(CH)-underset(CH_(3))underset(|)(CH)-CH_(3)`
`CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH_(2)-CH_(3)`
There are TOTAL of FIVE STRUCTURAL isomers.


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