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The number of isomers of C_6H_14 is |
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Answer» 4 `CH_3 - CH_2 - CH_2 -CH_2 - CH_2 -CH_3` `CH_3 - UNDERSET(CH_3) underset(|)(CH) - CH_2-CH_2 - CH_2 -CH_3` `CH_3-CH_2 - underset(CH_3) underset(|)(CH) - CH_2 - CH_3` `CH_3 -underset(CH_3)underset(|)(CH) - underset(CH_3)underset(|)(CH) - CH_3` `CH_3 - underset(CH_3) underset(|)overset(CH_3)overset(|)C - CH_2 - CH_3` |
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