1.

The number of molecules in 22.4cm^(3) of nitorgen gas at STP is

Answer»

`6.02xx10^(20)`
`6.02xx10^(23)`
`22.4xx10^(20)`
`22.4xx10^(23)`

Solution :`22400cm^(3)` is the volume of 1 mol GAS, `22.4cm^(3)` is the volume of `22.4/22400=10^(-3)` mol
No. of MOLECULES `=6.02xx10^(23)xx10^(-3)`
`=6.02xx10^(20)`


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