1.

The number of molecules in 16.0 g of oxygen is …………. .

Answer»

`6.023xx10^(23)`
`6.023xx10^(-23)`
`3.01xx10^(-23)`
`3.011xx10^(23)`

Solution :Hint : `"32 G of OXYGEN contain "6.023xx10^(23)" molecules."`
`therefore"16 g of oxygen will contain"`
`(6.023xx10^(23))/(32)xx16=3.011xx10^(23)`


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