Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Geometrical isomers differ in

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POSITION of FUNCTIONAL group
Position of atoms
patial ARRANGEMENT of atoms
Length of CARBON chain

Answer :A::C
2.

Geometrical isomerism results because molecules has :

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a centre of symmetry
a plane of symmetry
the CAPACITY to rotate the plane of POLARIZED light
two dissimilar groups attached to a DOUBLE bonded carbon atom

Solution :the groups around the double bond restrict rotation and also lie in same plane
3.

Geometrical Isomerism Molecules having same molecular formula but differing in the orientation of atoms in a space due to resistricted rotation. Compound which do not exhibit geometric isomerism

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ether
2-butene
3, 4 dimethyl-3-haxcne
2-chloru - 3-methyl - 2-pentene

Solution :To exhibit geometric isomerism COMPOUND MUST has unsaturation are compound must be cyclic with atleast TWO DIFFERENT groups
4.

Geometrical isomerism is shown by

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CHCl=CHBr

Answer :A::B::D
5.

Geometrical isomerism is possible in:

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isobutene
acetone oxime
acetophenone oxime
benzophenone oxime

Solution :
can SHOW GEOMETRICAL ISOMERISM
6.

Geometrical isomerism is possible in :

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FORMALDEHYDE hydrozone
ACETONE OXIME
acetophebnone oxime
benzophenone oxime

SOLUTION :N//A
7.

Geometrical isomerism is possible about which of the following multiple bonds?

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`C = N`
`N = N`
`C = C `
all of these

SOLUTION :DUE to restrected ROTATION.
8.

Geometrical isomerism is not shown by

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`(CH_3CH_2)_2C = C - undersetoverset(|)(CH_3)(C )H_2CH_3`
`C_2H_5 - undersetoverset(|)(H)(C )= undersetoverset(|)(H) (C ) - CH_2I`
`CH_3CH =C(CL)CH_3`
`CH_3-CH = CH - CH = CH_2`

Solution :DOUBLE bonded carbon with same groups does not show geometrical ISOMERISM
9.

Geometrical isomerism is not possible in

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2,4-hexadiene
benzaldoxime
but-2-ene
benzophenone oxime

Solution :`CH_3overset2CH=overset3CH-overset4CH=overset5CHoverset6CH_3` shows geometrical isomerism AROUND `C_3-C_4` single bond.
shows geometrical isomerism around C=N bond.
`CH_3CH = CHCH_3` and ClCH=CHCl SHOW geometrical isomerism around C =C bond
Benzophenone oxime having TWO identical GROUPS on the doubly bonded carbon does not show geometrical isomerism.
10.

Geometrical isomerism is caused

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by RESTRICTED rotation around C=C bond
by the presence of one ASYMMETRIC carbon atom
DUE to the differennt groups attached to the same functional group
by swing of hydrogenn atom between two divalent atoms.

Solution :GEOMETRICAL isomerism ARISES due to restricted rotation around C=C bond.
11.

Geometrical isomerism CH_(3)-(CH_2)_(3)-O-CH_(3), CH_(3)-CH_(2)-O-CH_(2)-CH_(2)-CH_(3) CH_(3)-underset(CH_(3)underset(|)"CH"-OCH_(2)-CH_(3) is

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POSITION ISOMERISM
Chain isomerism
Metamerism
Optical isomerism

SOLUTION :ALKYL group ATTACHED to divaJent group are different.
12.

geomerical isometism happens due to.......... around p bond

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ANSWER :RESTRICTED ROTATION
13.

Genetic information containing molecules is known as…..

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SOLUTION :DNA (deoxynucleic ACID)
14.

Generally valency of N, P, Cl is ………. .

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3, 2, 1
1, 2, 3
3, 3, 2
3, 3, 1

ANSWER :d
15.

Generally the melting points of isomeric alkanes decreases with branching but among isomeric pentanes, neopentane with two branches has the highest melting point. Why is it so ? Explain.

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SOLUTION :The reason being that neopentane is highly SYMMETRICAL . As a result, it fits CLOSELY in the LATTICE thereby INCREASING the forces of attraction and hence the melting point.
16.

Generally the nature of the non-metal oxides is

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Basic
Acidic
Amphoteric
NEUTRAL

ANSWER :B
17.

Generally the ionisation potential in a period increases, but there are some exceptions. The one which is not an exception is

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Be & B
N & O
Mg & Al
Na & Mg

Answer :D
18.

Generally solids sink into water but ice floats on water. Explain why ?

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SOLUTION :Ice floats on water because it has lower densit than water. The reason for lower density is that in ice, `H_(2)O` molecules are linked together through hydrogen bonds LEAVING large vacant spaces INBETWEEN giving it a cage-like structure which occupies large volume.
19.

Generallythe firstionizationenergyincreases along aperiod.Butthere aresome exceptions. One whichis not anexception is

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N andO
NA andMg
Mg and A1
Be and B

Solution :Inspiteof highernuclearchargethe ionizationenthalpyof O islowerthan thatof Nbecause Nhas exactlyhalf- filledmorestableelectronicconfigurationbut Odoesnot. Similarlyin spiteof highernuclearcharge, ionizationenthalpyofA1 islowerthan thatof Mgbecausein case of A1a lessstronglyattracted 3p- ELECTRONIS to beremoved3s- ELECTRON is to beremoved. Likewise, in SPITE of highernuclearcharge , the ionizationenthalpyof B islower than thatof Bebecausein caseof B , alessstronglyheld 2P- electron is to beremovedwhile incase of Mga morestronglyheld2s- electron isto beremoved.
Howeverin case of Naand Mgionizationenthalpyincreasesas teh nuclearchargeincreases. Thereforeoption (b ) is correct.
20.

Generally rate of the reaction depends on the concentration of

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`R-X`
`AlCl_(3)`

SOLUTION :RATE of reaction DEPENDS on concentration of reactant and substrate.
21.

Generally it is more difficult to purify organic compounds than inorganic compounds because

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They are quite unstable
They are more volatile
Organic compounds have LOW SOLUBILITY
Physical constants for organic compounds and the impurities ASSOCIATED with them are very CLOSE to each other

Answer :D
22.

Generally liquid drops assume spherical shape because

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A SPHERE has MAXIMUM surface area
A sphere has minimum surface area
Sphere is SYMMETRICAL in shape
Sphere is heavy

Solution :SPHERICAL shape is due to ST.
23.

Generally, during the clemmenson reduction gt C=O group converts into gt CH_(2) after reacting with (conc. HCl+Zn-Hg). But in case of beta-diketo compounds, its give unexpected products. Product (X), (X) will be :

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SOLUTION :
24.

Generally, during the clemmenson reduction gt C=O group converts into gt CH_(2) after reacting with (conc. HCl+Zn-Hg). But in case of beta-diketo compounds, its give unexpected products.

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`CH_(3)-UNDERSET(CH_(3))underset(|)(CH)-CH_(2)-CH_(2)CH_(2)-CH_(2)-CH_(2)`
`CH_(3)-underset(CH_(2))underset(|)(CH)-underset(Cl)underset(|)(CH)-CH_(2)-underset(Cl)underset(|)(CH)-CH_(2)-CH_(3)`
`CH_(3)-underset(CH_(3))underset(|)(CH)-underset(O)underset(||)(CH)-underset(CH_(3))underset(|)(CH)-CH_(2)-CH_(3)`

SOLUTION :
25.

Generalised Friedel craft acylation is observed

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Solution :PHENOL and aniline from COMPLEX with CATALYST `AlCl_3` which deactives the ring towards ARES
26.

General name of calcium sulphate is ......

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SOLUTION :PLASTER of PARIS
27.

General electronic configuration of outermost orbit of d-block element is …

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`(N -1) d^(1-10) ns^(1-2)`
`(n -1) d^(1-10) ns^(2)`
`(n -2) d^(1-10) ns^(2)`
`ND^(1-10) ns^(1-2)`

Answer :a
28.

General Characteristics of the Compounds of the Alkali Metals.

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Solution :On combustion in excess of air, lithium forms mainly the oxide, `Li_(2)O`(plus some peroxide `Li_(2)O_(2)`), sodium forms the peroxide, `Na_(2)O_(2)` (and some superoxide `NaO_(2)` ) whilst potassium, rubidium and caesium form the superoxides, `MO_(2)` .
Under appropriate conditions pure compounds `M_(2)O, M_(2)O_(2) and MO_(2)` may be prepared. The increasing stability of the peroxide or superoxide, as the SIZE of the metal ion INCREASES, is due to the stabilisation of large anions by LARGER cations through lattice energy effects.
These OXIDES are easily hydrolysed by water to form the hydroxides. The oxides and the peroxides are colour less when pure, but the superoxides are yellow or orange in colour. The superoxides are also paramagnetic. Sodium peroxide is widely USED as an oxidising agent in inorganic chemistry.
29.

Gelatin is often used as an ingredient in the manufacture of ice cream of

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CAUSING mixture to solidify
improving the flavour
stabilising the colloidal system and PREVENTING the crystal growth
preventing formation of colloid

Answer :C
30.

Gd(64) has ………..Unpairedelectronswithsum of spin………

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7,3.5
8,3
6,3
8,4

Solution :E.C. of Gd (Z=64)is `[Xe] 4f^(7)5d^(1)6S^(2)`
Thus , it has 8 UNPAIRED electrons and sumof spins
of 8unpairedelectrons`=8 xx (1)/(2)= 4`
31.

Gay Lussac's Law of Gaseous Volumes.

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Solution :This LAW was given by Gay Lussac in 1808. He observed that when combine or are produced in a chemical reaction they do so in a simple ratio by volume provided all gases are at same TEMPERATURE and pressure.
Thus,100 mL of hydrogen combine with 50 mL of oxygen to give 100 mL of water VAPOUR.
`{:("Hydrogen",+,"Oxygen",rarr,"Water",),(100mL,,50 mL,,100 mL,):}`
Thus, the volumes of hydrogen and oxygen which combine together (i.e. 100 mL and 50 mL) BEAR a simple ratio of 2 : 1.
Gay-Lussac.s discovery of integer ratio in volume relationship is actually the law of definite proportions by volume and stated earlier, was with RESPECT to mass.
32.

State Gay-Lussac.s Law of combining volumes.

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ANSWER :F
33.

Gastric juice contains about 3.0 g HCI per litre. If a person produces about 2.5 L of gastric juice per day, how many antacid tablets each containing 400 mg of Al (OH)_3 are needed to neutralise all the HCI produced in one day.

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ANSWER :14
34.

Gasoline is obatined from crude petroleum oil by its

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FRACTIONAL distilation
Vacuum distilation
Steam DISTILLATION Pyrolysis

Answer :A
35.

Gasoline has an enthalpy of combustion 24000 kJ/mol gallon. When gasoline burns in an automobile engine, approximately 30% of the energy released is used to produce mechanical work. The remainder is lost as heat transfer to the engine's cooling system. As a start on estimating how much heat transfer is required, calculate what mass of water could be heated from 25^(@)C to 75^(@)C by the combustion of 1.0 gallon of gasoline in an automobile?(Given : C(H_(2)O)=4.18 J//g^(@)C)

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34.45 KG
80.383 kg
22 kg
224 kg

Solution :`q=mxxcxxDeltaT, m =q//(cxxDeltaT)`
`=(24 XX 10^(6)xx0.7)//(4.18xx50)`
`=80383 " gor"80.383 " kg"`
36.

The table indicates the value of vander Waal's constant a in L^(2)atm mol 2. The gas which can most easily be liquefied is ?

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`O_2`
`N_2`
`NH_3`
`CH_4`

ANSWER :C
37.

Gases tend to behave non-ideally at low temperatures and high pressures. The deviation from ideal behaviour can be explained by considering two types of corrections. They are volume correction and pressure correction. Which assumption of kinetic theory is not followed when a real gas shows non-ideal behaviour ?

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Gas molecules move at random with no attractive forces between them
The velocity of gas molecules is DEPENDENT on temperature
Amount of SPACE occupied by a gas is much greater than that by ACTUAL gas molecules
During collisions with the walls of the CONTAINER or with another molecules, ENERGY is conserved

Solution :Real gases have IMF.
38.

Gases tend to behave non-ideally at low temperatures and high pressures. The deviation from ideal behaviour can be explained by considering two types of corrections. They are volume correction and pressure correction. Following represents equation of state for a mules of real gas[P + (n^2a)/(V^2)][V-nb] = nRT.Select incorrect statement for a real gas

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Constant 'a' is a measure of force of ATTRACTION among gas molecules
a is expressed in ATM `L^2 mol^(-2) ` b is expressed in `L mol^(-1)`
At high PRESSURE, compression factor is `(1 + (PB)/(RT))`
`(n^2a)/(V^2)` is also called INTERNAL volume

Solution :`(an^2)/(V^2) ` is pressure correction.
39.

Gases tend to behave non-ideally at low temperatures and high pressures. The deviation from ideal behaviour can be explained by considering two types of corrections. They are volume correction and pressure correction. Select incorrect statement(s) :

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Volume CORRECTION is due to finite size of molecules and pressure correction is due to force of ATTRACTION between molecules.
At high temperatures, molecules have greater kinetic energy, and attractive forces are smaller and he behaviour of gases is close to the ideal gas behaviour
Volume correction is also called covolume or excluded volume and is FOUR times the volume of spherical molecules present in one MOLE of the gas
At very low pressure, force of attraction is effective and pressure correction needs further resolution.

Solution :At very ow `P, Z~~ 1`.
40.

Gases SO_(2), NH_(3) and C_(2)H_(6) are filled in a closed container at 298 K temperature. If a small hole is made in the container, what will be the correct order of partial pressure of gases after 2 hours. (Atomic weight of S = 32 g, N = 14 g , C = 12 g , H = 1 g)

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<P>`P_(NH_(3))LT P_(C_(2)H_(6))lt P_(SO_(2))`
`P_(C_(2)H_(6))GT P_(SO_(2))gt P_(NH_(3))`
`P_(SO_(2))gt P_(C_(2)H_(6))gt P_(NH_(3))`
`P_(SO_(2))lt P_(C_(2)H_(6))lt P_(NH_(3))`

ANSWER :A::D
41.

Gases show ideal gas behaviour at

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high PRESSURE and high temperature 
LOW pressure and high temperature 
low pressure and low temperature 
high pressure and low temperature 

Answer :B
42.

Gases responsible for acid rain are

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No and `NO_(2)`
`SO_(2)` only
`NO_(2) and SO_(2)`
`CO and CO_(2)`

ANSWER :C
43.

Gases possess characteristic critical temperatureswhichdepend upon the magnitude of intermolecular forces between the gas particles. Critical temperatures of ammonia and carbon dioxide are 405.5 K and 304.10 Krespectively. Which of these gases wil liquefy first when you start cooling from 500 K to their critical temperature ?

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Solution :Higher the critical temperature, more easily the gas liquesfies. As `NH_(3)` has higher critical temperature, on cooling down from 500 K, the critical temperature of `NH_(3)` will be REACHED first. Hence, `NH_(3)` will be liquefied first `CO_(2)` will be liquefied only on further cooling.
44.

Gases possess characteristic critical temperature which depends upon the magnitude of intermolecular forces between the gas particles. Critical temperatures of ammonia and carbon dioxide are 405.5 K and 304.10 K respectively. Which of these gases will liquify first when you start cooling from 500 K to their critical temperature ?

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Solution :Ammonia will liquify first because its critical TEMPERATURE will be reached first. Liquifraction of `CO_(2)` will REQUIRE more cooling.
45.

Gases posses characteristic critical temperature which depends upon the magnitude of intermolecular forces upon the magnitude of intermolecular forces between the particles. Following are the critical temperature of some gases. {:("Gases",H_(2),He,O_(2),N_(2)),("Critical temperature",,,,),("in Kelvin",33.2,5.3,154.3,126):} From the above data what would be the order of liquefaction of these gases ? Start writing the order from the gas liquefying first

Answer»

`H_(2).He,O_(2),N_(2)`
`He, O_(2),H_(2),N_(2)`
`N_(2),O_(2),He,H_(2)`
`O_(2),N_(2),H_(2),He`

Solution :Higher the critical temperature, more easily is the gas LIQUEFIED. Hence, ORDER of liquefaction starting with the gas liquefying first will be : `O_(2),N_(2),H_(2),He`.
46.

Gases don't settle at the bottom of a container?

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SOLUTION :GASES by definition are the least dense state of matter. They have negligible intermolecular forces of attraction. So they are all free to roam separately. So the least dense gas PARTICLES will not sink at the BOTTOM of a container.
47.

Gases deviate from ideal behavior at high pressure. Which of the following statement(s) is correct for non-ideality?

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at high pressure the collision between the gas molecule become enormous
at high pressure the gas molecules MOVE only in ONE DIRECTION
at high pressure, the VOLUME of gas become insignificant
at high pressure the intermolecular interactions become SIGNIFICANT

Solution :at high pressure the intermolecular interactions become significant
48.

Gases deviate from ideal behavior at high pressure which of the following is correct for non-ideallty?

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At HIGH pressure the collision between the gas molecule BECOME enormous
at high pressure the gas molecules move only in one direction
At high pressure, the volume of gas become in significant
At high pressure the INTERMOLECULAR INTERACTIONS become significant

ANSWER :D
49.

Gases deviate from behavior at high pressure. Which of the following statement(s) is correct for non-ideality?

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at hgih pressure the COLLISION between the GAS molecule become enormous
at high pressure the gas MOLECULES move only in one direction
at high pressure, the volume of gas become INSIGNIFICANT
at high pressure the intermolecular interactions become significant

Answer :D
50.

Gases best follow the facts given below A) An ideal gas obeys the mathematical relation PV=nRT B) Rates of diffusion of two gases are in the reciprocal ratio of square roots of their molecular weight C) Total pressure of a mixture of non reacting gases is given by the algebric sum of their partial pressure What is the mass of water vapour in 1 m^3 of air with 0.4 relative humidity at 300K? (Aqueous tension at 300K = 3.6 K Pa)

Answer»

22.12 gm
10.53 gm
4.68 gm
2.86 gm

SOLUTION :`0.4 = (V.P)/(3.6) , VP = 1.44 , W = (PVM)/(RT) = 10.53 gm`.