Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Gases best follow the facts given below A) An ideal gas obeys the mathematical relation PV=nRT B) Rates of diffusion of two gases are in the reciprocal ratio of square roots of their molecular weight C) Total pressure of a mixture of non reacting gases is given by the algebric sum of their partial pressure An ideal gas is captured in a glass tube of uniform arca of cross section by awater column at a given temperature as shown If the tube is held vertical, by what length the water column descends down? (Density of mercury=13.6gm/cc) (P_(atm)=76cm of Hg)

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2.2 cm
3.2 cm
1.03 cm
4.07 cm

Solution :Pressure DUE to water column in terms of mercury is given by `h_1d_1 = h_2d_2`
`27.2 xx 1 = h_2 xx 13.6 implies h_2 = 2 cm`
When HELD vertical , `P_("gas") = P_("atm") + 2 cm of Hg`
`= 76+ 2`
`= 78 cm of Hg`.
`P_1 V_1= P_2V_2 = > 76 xx 40 xx A = 78 xx l xx A`
`implies l = 38.97 implies "DESCENT" = 40 - 38.97`
`= 1.03 cm`.
2.

Gaseous molecules heavy (e.g Br_(2)) or light (H_(2)) in equal number occupy the same volume at same P and T The distance between molcules in a definite volume is much larger than the actual dimension of molecule .

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Solution :Statement REPRESENT AVOGADRO's law which is JUSTIFIED by the EXPLANTION .
3.

Ground state electronic configuration of p atom can be represented as

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`UARR DARR uarr darr uarr uarr uarr`
`uarr darr uarr darruarr darr uarr`
`uarr darr uarr darr uarr darr darr`
`uarr darr uarr darr darr darr darr`

SOLUTION :`1s^2 2s^2 2p^3`
4.

Gaseous elements are monotomic or diatomicComment.

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Solution :NOBLE GASES are monoatomic . Elementary gases are diatomic. However , One GASEOUS element is even available as TRIATOMIC, `O_(3)`.
5.

Gaseous benzene reacts with hydrogen gas in presence of a nickel catalyst to form gaseous cyclohenane according to the reaction C_(6) H_(6) (g) + 3H_(2) (g) rarr C_(6) H_(12) (g) A mixture of C_(6)H_(6) and excess H_(2)has a pressure of 60 mm of Hg in an unknown volume. After the gas had been passed over a nickel catalyst and all the benzene converted to cyclohexane, the pressure of the gas was 30 mm of Hg in the same volume at the same temperature. The fraction of C_(6)H_(6) (by volume) present in the original volume is

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`1//3`
`1//4`
`1//5`
`1//6`

SOLUTION :`C_(6)H_(6) (g) + 3H_(2) (g) rarr C_(6) H_(12) (g)`
Initial pressure = 60 mm
Final pressure = 30 mm
since `p PROP n`
`:.` Initial pressure of 60 mm is because of 4 moles and hence pressure due to one mole = 15 mm
Now if `x` is fraction of `C_(6)H_(6)` which combines then for the REACTION
`{:(C_(6)H_(6),+,3H_(2) rarr,C_(6) H_(12)),(15 - x,,45 - 3X,x):}`
6.

Gas used in refrigirators is

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T.E.L
`C_8H_(18)`
`C Cl_2 F_2`
`C Cl_3 NO_2`

ANSWER :C
7.

Gas released during Bhopal tragedy was

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Methyl isocyanate
POTASSIUM ISOTHIOCYANATE
Sodium isothiocyanate
ETHYL isothiocyanate

Solution :Gas released during Bhopla tragedy was methuyl isocyanate
8.

……gas produce in Duman method but …….gas produce in Kjeldahl's method

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SOLUTION :`N_(2), NH_(3)`
9.

Name the gas law which gives the relationship between the pressure and temperature of a fixed amount of gas at a constant volume.

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SOLUTION :GAY Lussac.s LAW
10.

Gas laws are relationship between the measurable properties of gases. Draw the graph to illustrate the relationship between temperature and pressure of a fixed amount of gas at constant volume.

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SOLUTION :
11.

.........gas is used in the process of photosynthesis.

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SOLUTION :`CO_(2)`
12.

Gas laws are relationship between the measurable properties of gases. A definite quantity of an ideal gas is confined in a container of constant volume. When the container is immersed in a bath of melting ice, the pressure of the gas is 800mm of Hg. Find the temperature when the gas pressure is 400mm of Hg.

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SOLUTION :`p_1/T_1 = p_2/T_2`
`p_1 = 800 `MM of Hg,`p_2` = 400 mm of Hg
`T_1` = 273K,`T_2 = ? LT`Substituting we get
800/273 = `400/T_2`
`800xxT_2` = `273xx400`
`therefore T_2 = (273xx400)/800` = 136.5K = 136.5-273 = `-136.5^@C`
13.

……gas is produce in Kjeldahl's method and absorbed in ……..

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SOLUTION :`NH_(3), H_(2)SO_(4)`
14.

Gas deviates from ideal gas bahaviour because molecules

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are colourless
attract each other
contain COVALENT bond
show brownian movement

Answer :B
15.

Gas equation PV=nRT is obeyed by

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only ISOTHERMAL process
only adiabatic process
Both (a) and (b)
None OFTHESE.

ANSWER :C
16.

Gas commonly used in refrigirators is

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T.E.L
`C_(8) H_(18)`
`"CCL"_(2) F_(2) `
`"CCl"_(3) NO_(2)`

Answer :C
17.

Gas (A_(x)) has the ratio of molar specific heats equal to 1.66. The value of x will be _____

Answer»


Solution :`gamma = 1.66 = (5)/(3) RARR` ATOMICITY =1
18.

Gammexane is :

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DDT
hexachlorobenzene (HCB)
benzene hexachloride (BHC)
CHLORAL

Answer :C
19.

Gammaxene is .. . . Isomer of benzene hexa chloride.

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`ALPHA`
`BETA`
`gamma`
`delta`

Solution :`gamma`-FORM
20.

Galvanishing of iron sheets is done by

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CU PLATING
Zn plating
As plating
Tin plating

Solution :Galvinisation of iron sheets is DONE by zinc plating.
21.

Gallium lies below aluminium in group 13 of the periodictablebut itsatomicradiusis smallerthan that ofaluminium. Why so ?

Answer»

Solution :DUE to poorshielding of the valenceelectrons of GABY the inner 3d-electrons , the effectivenuclearcharge of GA is greaterin magnitudethan that of AL. As a result , the electronin gallium experience greaterforce of attractionby the NUCLEUS than in Aland hence atomic size of Ga (135pm)is slightly lessmuch higher than that of Al (143pm).
22.

Gallium has muchhigher atomicnumberthan aluminium yet its atomicradius is lower thanthat of aluminium. Justify.

Answer»

Solution :DUE to poorshielding of the valenceelectrons of Gaby the inner 3d-electrons , the effectivenuclearcharge of Ga is greaterin magnitudethan that of Al. As a RESULT , the electronin gallium experience greaterforce of attractionby the nucleus than in ALAND HENCE atomic size of Ga (135pm)is SLIGHTLY lessmuch higher than that of Al (143pm).
23.

Gallium acts as reducing agent because

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`GA^(3+)` state is less stable than `Ga^(+1)`
`Ga^(3+)` state is more stable than `Ga^(+1)`
`Ga^(3+)` covalence to `Ga^(+1)` REDUCING
None of the above

Solution :The stability of `+1` oxidation state is effective down the GROUP, but here `Ga^(3+)` is more stable than `Ga^(+1)`
24.

Gain of electron or electrons is termed

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combustion
oxidation
reduction
neutralisation

Answer :C
25.

Gadoliniumbelongsto 4f series. Itsatomicnumberis 64.Which of thefollowingis the correctelectronicconfigurationof gadolinium ?

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`[Xe] 4f^(9)5s^(1)`
`[Xe] 4f^(7)5D^(1)6S^(2)`
`[Xe] 4f^(6)5d^(2)6s^(2)`
`[Xe] 4f^(8)6D^(2)`

Solution :NA
26.

[G] Match the salts in Column-I with the ratio of van't Hoff factor in Column-II : {:(,"Column-I",,"Column-II"),("(a)","Glucose, fructose, sucrose","(p)",1:2:3),("(b)","KCl,MgCl"_(2)",FeCl"_(3),"(q)",1:3:4),("(c)",K_(4)[Fe(CN)_(6)],Na_(3)PO_(4)","Al_(2)(SO_(4))_(3),"(r)",2:3:4),("(d)","Urea, KCl, CaCl"_(2),"(s)",1:1:1):} [Note : Assume that the electrolytes are completely ionised.

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ANSWER :(a-s);(b-r);(c-s);(d-p)
27.

Comment over the following statement Ga_2 O_3 is an amphoteric oxide.

Answer»


ANSWER :1
28.

(G) is NaHCO_(3) The other compound formed with (G) is

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`NH_(4)C_(1)`
NaCl
`CaCl_(2)`
Both (a) and (b)

Solution :`NH_(4)HCO_(3)+NaCIrarrNAHCO_(3)+MNH_(4)CI`
`2NaHCO_(3) overset(triangle)rarrNa_(2)CO_(3)+H_(2)O+CO_(2)`
29.

Fusion of AgCl with Na_(2)CO_(3) gives:

Answer»

`Ag_(2)CO_(3)`
silver carbide
AG
`Ag_(2)O`

SOLUTION :`AgCl + Na_(2)CO_(3) rarrNaCl + CO_(2) + Ag`
30.

Fusion bomb involves

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Combinations of lighter nuclei into BIGGER nucleus
Destruction of heavy nucleus into smaller nuclei
Combustion of oxygen
Explosion of TNT

Solution :Fusion BOMB INVOLVES combinations of lighter nuclei into bigger nucleus.
31.

Fusel oil is a mixture of

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Ethers
ALCOHOLS
Alcohols and ethers
Alcohols and ketones

Solution :FUSEL OIL is a MIXTURE of alcohols.
32.

Furan (C_4H_2O)is an ......... compound.

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SOLUTION : AROMATIC
33.

Functional isomer of carboxylic acid is

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Amide
Acid chloride
Fatty acid
Alkylalkanoate

Answer :D
34.

The function of anhydrous AlCl_(3) in the Friedel-Crafts reaction is to

Answer»

To ABSORB water
To absorb hydrochloric acid
To produce an electrophile
To produce nucleophile

SOLUTION :`R + CL + AlCl_3 to overset(oplus)R "(electrophile)" + overset(Ɵ)(A)lCl_4`
35.

Fullerene has 12 rings of 6 memberes and 20 rings of 5 memberes

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SOLUTION :FALSE STATEMENT
36.

Fuel gas with highest calorific value among the following

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COAL GAS
WATER gas
Carburetted water gas
Semi water gas

ANSWER :A
37.

Froth floatation process is used for the concentration of

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OXIDE ores
sulphide ores
chlorine ores
amalgams

Answer :(B)
38.

Fronm where does ozone come in the photochemical smog?

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Solution :(i) Photochemical smog is formed by the combination of smoke, DUST and FOG with air pollutants in the presence of sunlight. (ii) Chemically it is oxidising in nature because of high concentration of oxidising agents such as` N_(3)` and `O_(3)` So it is ALSO called oxidising smog. (iii) Photochemical smog is formed by following reactions:
`N_(2) + O_(2) rarr 2NO`
`2NO + O_(2) rarr 2NO_(2)`
`NO_(2) overset("sunlight")rarr NO+(O)`
`(O)_(3)NO rarr NO_(2) + O_(2)`
`NO_(2) overset("sunlight") rarr NO + (O)`
(iv) NO and `O_(3)` are strong oxidising agents and they can REACT with unburnt hydrocarbons in polluted air to FORM formaldehyde, acrolein and PAN.
39.

From which source maximum hydrogen is obtained ?

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SOLUTION :MAXIMUM HYDROGEN is OBTAINED from PETROCHEMICAL.
40.

From which reaction H_(2)O_(2) act as reducing agent?

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`Ag_(2)O+H_(2)O_(2)to2Ag+H_(2)O+O_(2)`
`2KI+H_(2)O_(2)to2KOH+I_(2)`
`2FeSO_(4)+H_(2)O_(2)+H_(2)SO_(4)toFe_(2)(SO_(4))_(3)+2H_(2)O`
`HNO_(2)+H_(2)O_(2)toHNO_(3)+H_(2)O`

ANSWER :A
41.

From which one of the following both ethylene and acetylene could be prepared in a single step reaction ?

Answer»

`CH_3CH_2OH`
`Br-CH_2-CH_2-Br`
`CH_3CH_2Br`
`Br-CH_2-CH_2-OH`

SOLUTION :`BrCH_2-CH_2Br UNDERSET((-ZnBr_2))OVERSET(Zn//CH_3OH, DELTA)to CH_2=CH_2`
`BrCH_2-CH_2Br overset(NaNH_2 "in LIQ."NH_3)to HC-=CH`
42.

From which of the places the boiling point will be less ? Why sea and mountain ?

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SOLUTION :At HIGH altitudes atmospheric pressure is low therefore liquids at high altitudes BOIL at LOWER temperatures in comparison to that at sea level.
43.

From which of the following having maximum and minimum vapour pressure ? Acetone, ether and ethanol ?

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SOLUTION :Ether having MAXIMUM vapour pressure and ETHANOL having MINIMUM vapour pressure.
44.

From which industry phenol waste produced ?

Answer»

Sugar
PETROLEUM
DETERGENT
PESTICIDES

SOLUTION :Petroleum
45.

From which harmful effect ozone layer protects all living being ?

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Ultraviolet radiations COMING from sunlight.
`CO_2` in atmosphere.
Effect of poisonous GAS from COMBUSTION of hydrocarbon
All of the above

SOLUTION :Ultraviolet radiations coming from sunlight.
46.

From which industry aromatic organic compound are produced ?

Answer»

Dairy
PESTICIDE
FERTILIZERS
SUGAR

SOLUTION :Pesticide
47.

From where does ozone come in the photo-chemical smog ?

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Solution :Sunlight cause photochemical decomposition of `NO_2` into NO and O.
`NO_2 overset(hv)to NO + [O]`
Atomic OXYGEN is a HIGHLY reactive species. It combines with diatomic oxygen and forms ozone.
`O_2 + O + M to O_3 + M`
Where, M is inert GAS such as NITROGEN. This `O_3` is FORMED during the formation of smog.
48.

From where ozone come in the photochemical smog?

Answer»

Solution :(i) Photochemical smog is formed by the combination of SMOKE, dust and fog with air pollutants in the presence of sunlight.
(ii) Chemically it is oxidising in nature because of high concentration of oxidising agents such as `NO_(2) and O_(3)`. So it is also called oxidising smog.
(iii) Photochemical smog is formed by following reactions:
`N_(2) + O_(2) rarr 2NO`
`2NO + O_(2) rarr 2NO_(2)`
`NO_(2) overset("sunlight")rarr NO + (O)`
`(O) + O_(2) rarr O_(3)`
`O_(3) + NO rarr NO_(2) + O_(2)`
`NO_(2) overset("sunlight")rarr NO + (O)`
(iv) No and `O_(3)` are strong oxidising agents and they can REACT with unburnt HYDROCARBONS in polluted air to FORM formaldehyde, acrolein and PAN.
49.

From where the biodegradeble wastes are generated ?

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Solution :Biodegradable WASTES are GENERATED by cotton mills, FOOD processing units, paper mills, and textile FACTORIES.
50.

Fromwherethe firstorbitalof s, p , d, f start?

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Solution :s orbitalfrom n=1 firsts 1 s
p orbitalfrom n= 2 first2p
d orbitalfrom n=3 first3d
F orbitalfrom n= 4 first4 f