Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

How many radial nodes for2_(s),4_(p), 5_(d) and 4f orbitals exhibit? How many angular nodes?

Answer»

SOLUTION :
Discussion
2.

How many radial nodes for 2s,4p,5d and4f orbitals exbitals ? How many angulars nodes ?

Answer»

SOLUTION :Formula for total number of NODES =n-1ltbrltgtFor 2s orbitals:Number of radial nodes=1.
For 4p orbitals: Number of radial nodes=n-l-1.
=4-1-1
=2
Number of angular nodes=l
:.Number of radial nodes =n-l-1
=5-2-1
=2 radial nodes.
Number of angular nodes=l
=2
:.5d orbital have 2 radial nodes and 2 angular nodes.
For 4F orbitals:Total number of nodes =n-1
=4-3-1
=0 node.
Number of angular nodes=l
=3 nodes
,gt4 f orbitals have 0 radial node and 3 angular nodes.
Discussion
3.

How many radial and angular nodes are present in 2p orbital.

Answer»


ANSWER :RADIAL nodes = 0 , Angular nodes = 1
Discussion
4.

How many protons and neutrons are there in one atom of ""_(6)^(13)C

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SOLUTION :Atomic number (Z) = 6
MASS number (A) = 13
Number of protons (Z) = 6
Number of neutrons `= A-Z = 13 - 6 = 7`
Discussion
5.

How many properties of gases increases with increasing the temperature, Viscosity, mean free path, collision frequency, rate of diffusion, R.M.S velocity, density at constant pressure, molar volume at constant pressure, molar concentration at constant pressure, vander Waals parameter a.

Answer»


Solution :`eta , LAMBDA , Z , R , u_("rms") , V_m` increases TEMP.
Discussion
6.

How many protons are present in 4 g NaOH ?

Answer»

`6.022xx10^(23)`
`12.044xx10^(23)`
`12.044xx10^(24)`
`6.022xx10^(22)`

Solution :(i) Molecular mass of NaOH `= 23 + 16 +1`
`= 40 g*MOL^(-1)`
(ii) Mole `= ("weight")/("molecular weight")`
`= (4.0)/(40.0) = 0.1` mole NaOH
(iii) NaOH =`(""_(11)Na + ""_(8)O +""_(1)H)`

TOTAL no. of proton `=20` in each molecule of NaOH
(iv) Thus one mole of NaOH have
`20 xx 6.022 xx 10^(23)` total protons.
`:.0.1`one mole of NaOH have (?) protons
`=0.1xx20xx6.022xx10^(23)`
`= 12.044 xx10^(23)` protons
Discussion
7.

How many products will be formed when methylene cyclohexane reacts with NBS?

Answer»


SOLUTION :CYCLO ALKANES PROPERTIES
Discussion
8.

How many products (structural isomers only ) are formed by monochlorination of given compound.

Answer»

4
3
5
6

Answer :B
Discussion
9.

How many products are possible theoretically in the reaction of cis-2-pentene with Cl_2 in H_2O

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SOLUTION :
Discussion
10.

How many products are formed on mono bromination of 1-methyl cyclohexene with NBS ?(Including stereo isomers)

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SOLUTION :
Discussion
11.

How many product will be formed in above reaction .

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ANSWER :D
Discussion
12.

How many product will be formed in above reaction ?

Answer»

2
4
3
6

Solution :FOUR PRODUCTS
Discussion
13.

How many products are expected from 1,2- or 1,4-addition of HBr to 1,3-pentadiene?

Answer»

2
3
4
5

Solution :3
Discussion
14.

How many primary, secondary, tertiary and quaternary carbon atoms are present in the following compound? CH_(3)-underset(CH_(3))underset(|)(C)H-CH_(2)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH_(3)

Answer»

ONE primary, two SECONDARY and one tertiary
Five primary, THREE secondary
Five primary, one secondary, one tertiary and one quaternary
four primary, two secondary and two quaternary

Answer :C
Discussion
15.

How many plance of symmetry (Z) present in the following compound?

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SOLUTION :N//A
Discussion
16.

How many planes of symmetry (Z) present in carbon tetachloride?

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SOLUTION :N//A
Discussion
17.

How many peroxy linkages are present in CrO_(5) ?

Answer»

1
2
3
4

Answer :B
Discussion
18.

How many peaks and radial nodes are present in the radial probability curve of 3s-orbital ?

Answer»

SOLUTION :3s orbital CURVE has 3 peaks.
Number of RADIAL NODES `= n-1 -1 = 2`
Discussion
19.

How many para substituted benzenoid isomers of C_(8)H_(8)O_(2) gives 1,4-dihydroxy benzene on hydrolysis ?

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SOLUTION :
Discussion
20.

How many pairs of electrons are involved in bond formation in case ofnitrogen molecule.

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SOLUTION :THREE PAIRS.
Discussion
21.

How many out of the following is/are intermediate(s) in the bromination reaction of toluene

Answer»


SOLUTION :
Discussion
22.

Howmany orbitals have the quantum numbers :

Answer»

`7`
`3`
`1`
`0`

ANSWER :c
Discussion
23.

How many orbitals do you expect to be present in the 5th shell ?

Answer»

SOLUTION :`5^(2) = 25`
Discussion
24.

How manyorbitalsuptonn=4 ?

Answer»

8
30
16
4

Solution :`n=1 ,n^(2) =1 ` Orbital
`n=2 , n^(2)=4`Orbital
`n=3 ,n^(2) = 9`Orbital
`n=4 ,n^(2) = 16` Orbital
total30Orbital
Discussion
25.

How many orbitals are present in the subshells with (a) n = 3, l = 2 (b) n = 4, l = 2 (c) n = 5, l = 2?

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SOLUTION :In each case, l = 1. Hence, `m = -2, -1, 0, + 1, + 2` i.e., 5 VALUES which means 5 ORBITALS
Discussion
26.

How many orbitals are possible in the 4^(th) energy level?(n=4)

Answer»

Solution :n=4
NUMBER of orbitals in `4^(th)` energy level=l
When n=4,l=0,1,2,3
if l=0orbital=4s=1
if l=1orbital=`4p_x,4p_y,4p_z`=3
If l=2orbital=`4d_(xy),4d_(YZ),4d_(zx)4d_(X^(2)-y^(2)),4d_(z^(2))=5`
If l =2 orbital=`-3,-2,-1,0,+1,+2,+3=7`
NUmber of orbitals in`4^(th)` energy level =16
Discussion
27.

How many orbitals are possible in the 3rd energy level ?

Answer»

SOLUTION :n=3,main SHELL is m
Total NUMBER of orbitals in 3RD energy level=?
Discussion
28.

Howmanyorbitalsare thereif n= 3, l =2, m_(l) =+ 2?

Answer»

1
2
3
4

Answer :A
Discussion
29.

How many optically stereoisomers are possible for butene-2,3-diol ?

Answer»

1
2
3
4

Solution :Butane-2,3-diol has two ASYMMETRIC CARBON atoms.
`underset("Butane-2,3-diol")(CH_(3)-overset(OH)overset(|**)(CH)-overset(OH)overset(|**)(CH)-CH_(3))`
Optically active stereoisomers are I and III
`{:(""CH_(3) ""CH_(3)""CH_(3)),("|""|""|"),(" "OH-C-H""H-C-OH""H-C-OH), ("|""|""|"),(""H-C-OH""OH-C-H""H-C-OH),("|""|""|"),(""CH_(3)""CH_(3)""CH_(3) ),("(I)(II)(III)"):}`
III is MESO form and is not optically active.
Discussion
30.

How many orbitals are possible for n=4?

Answer»

Solution :If `n = 4`, the POSSIBLE NUMBER of orbitals are calculated as FOLLOWS.
n = 4 main `""` main shell = N
If `n = 4 "" `L values are 0,1, 2, 3
If `l = 0 ""` 4s orbital = 1 orbital
If `l = 1 ""` 4s orbtial = 1 orbital
If `l = 0 ""` 4s orbital = 1 orbital
If `l = 0 "" m = -1, 0 , +1 = 3` orbitals.
If `l = 2 "" m = -2, -1, 0, +1, + 2 = 5"` orbitals.
If `l = 3"" m = -3, -2, -1, 0, +1, +2, +3 = 7` orbitals
`:.` Total number of orbitals = 16 orbitals.
Discussion
31.

How manyorbital a are therein sushell ?

Answer»

SOLUTION :No . Ofsubshell = (2L + 1) TOTALVALUE o = `m_(1)`
wherel = subshellor angularquantumnumber .
Discussion
32.

How many optically active stereoisomers are possible for butane-2, 3-diol ?

Answer»

1
2
3
4

Solution :
Discussion
33.

How many of the substrates would produce H_(2)S when subjected to hydrolysis? Cr_(2)S_(3),AI_(2)S_(3),BaS,P_(4)S_(10),PSCI_(3),Na_(2)S

Answer»


Solution :`Cr_(2)S_(3),AI_(2)S_(3),P_(4)S_(10),PSCI_(3)`
Discussion
34.

How many of the following will turn moist red litmus blue and finally white ? Li_(2)O, KO_(3), RbO_(2), Cs_(2)O_(2), BeO, MgO, BaO_(2), SrO

Answer»


SOLUTION :`KO_(3),RbO_(2),CS_(2)O_(2),BaO_(2){4}`
Discussion
35.

How many of the following substituents can cause aromatic electrophilic substitution faster than benzene ? (a)-NH_2 , (b)-NR_2 , ( C)-NO_2 , (d)-overset(+)NH_3 (e)-O-oversetoverset(O)(||)C-R , (f) -NH-oversetoverset(O)(||)C-R , (g)-oversetoverset(O)(||)C-Cl , (h)-oversetoverset(O)(||)C-H (i)-SO_3H , (j)-CH_3, (k)-CH-CR_2

Answer»


Answer :6(A,B,E,F,J,K)
Discussion
36.

How many of the following statements is (are) true about resonance. a) Resonance is an intramolecular process. b) Resonance involves delocalization both of s and p electrons. c) Resonance involves delocalization of pi electrons only. d) Resonance decreases potential energy of a molecule. e) Resonance has no effect on the potential energy of a molecule. f) Resonance is the only way to increase molecular stability. g) Resonance is not the only way to increase molecular stability. h) Any resonating molecule is always more stable than any nonresonating molecule. i) The canonical struture explains all features of a molecule. j) The resonance hybrid explains all features of a molecule. k) Resonating structures are real and resonance hybrid is imaginary. l) Resonance hybrid is real and resonating structures are imaginary. m) Resonance hybrid is always more stable than all canonical structures.

Answer»


SOLUTION :RESONANCE
Discussion
37.

How many of the following statements are correct for green vitriol? 1. it can be used for the preparation of Mohr's salt. ltbr 2. It is a hydrated salt and its anhydrous form is white in colour. 3. The decomposition reaction of its anhydrous form is redox in nature. 4. It is used for making fenton's reagent used as a catalyst in organic chemistry. 5. It can be used for the preparation of Potassium ferrocynide. 6. It has same number of molcules of water of crystallization as white vitriol or blue vitriol 7. It turns brownish-yellow on exposure to atmosphere. 8. Its aqueous solution is acidic in natrue due to hydrolysis. 9. Out of the decomposition products of its anhydrous form, only one can turn acidified K_(2)Cr_(2)O_(7) solution green.

Answer»


Solution :1. `FeSO_(4)+(NH_(4))_(2)SO_(4)+6H_(2)OtoFeSO_(4).(NH_(4))_(2)SO_(4).6H_(2)O` (Mohr salt)
2. Green vitriol is `FeSO_(4).7H_(2)O&` its anhydrous form `(FeSO_(4))` is white.
3. `overset(+2)(2FE)overset(+6)(SO_(4))overset(Delta)tooverset(+3)(Fe_(2))O_(3)+overset(+4)(SO_(4))+SO_(3)(REDOX)`
4. Fact (Fenton's reagent `=FeSO_(4)+H_(2)O_(2)`)
5. `UNDERSET(aq)(FeSO_(4))+underset(aq)(6KCN)toK_(4)[Fe(CN)_(6)]`
6. White vitriol is `ZnSO_(4).7H_(2)O&` blue vitriol is `CuSO_(4).5H_(2)O`
7. Due to its oxidation to `Fe^(3+)`
8. `Fe^(2+) +2H_(2)OhArrFe(OH)_(2)darr+2H^(+)` (acidic solution)
9. Only `SO_(2)` can TURN acidified `K_(2)Cr_(2)O_(7)` solution green.
Discussion
38.

How many of the following statements are correct? 1) The most stable conformer of cis-1,3-cyclohexanediol is chair form. 2) Cis-1,3-cyclohexanediol is more stable than trans -1.3-cyclohexanediol. 3) iN Cis 1,3-cyclohexanediol both the OH groups occupy equitorial positions. 4)The most stable conformerf of trans -1,4-cyclohexanediol is chair form. 5) The most stable conformer of Cis-1,4-cyclohexanediol is boat conformer.

Answer»


ANSWER :4
Discussion
39.

How many of the following statements are correct? 1) The most stable conformer of cis-1, 3-cyclohexanediol is chair form. 2) Cis- 1, 3- cyclohexanediol is more stable than trans -1, 3-cyclohexanediol. 3) In Cis 1, 3-cyclohexanediol both the OH groups occupy equitorial positions. 4) The most stable conformer of trans -1, 4-cyclohexanediol is chair form. 5) The most stable conformer of cis-1, 4-cyclohexanediol is boat conformer.

Answer»


Solution :In chair form of cis-1,3-cyclohexanediol both the OH groups are axial due to INTRA MOLECULAR hydrogen bond. Most STABLE conformer of cis-1,4-cyclohexanediol is boat form.
Discussion
40.

How many of the following species are more stable than (CH_(3))_(3)overset(*)(C)

Answer»


SOLUTION :
Discussion
41.

How many of the following species are aromatic in nature ? Cyclopentadienyl cation, cyclopentadienyl anion, tropylium cation , azulene, cyclopropenyl cation, tetrahydrofuran , cyclooctatetraene, furan , cycloheptatriene.

Answer»


SOLUTION :Five , cyclopentadienyl ANION, tropylium CATION, AZULENE, cyclopropenyl cation, furan.
Discussion
42.

How many of the following show borax bead test B, Be, Mg, Cu, Fe, Cr, Co, Mn, Ni

Answer»


Solution :TRANSITION METAL IONS [ Cr, Mn , Fe , Co , Ni , Cu]
Discussion
43.

How many of the following s-block elements do not give characteristic colours in the flame test ? Li, Be, Ca , Ba , Sr , Mg , Na , K , Cs

Answer»


SOLUTION :TWO , Be and MG
Discussion
44.

How many of the following reagents on reacting with Acetylene. (I) Na , (II) ammoniacal AgNO_3, (III) HCI , (IV) NaOH

Answer»


SOLUTION :d) `CH -= CH + Na to CH -= C^(-) Na^(+) + (1)/(2) H_2`
`CH-= underset("(Ammonical)")(CH + AgNO_3)to underset ("White ppt.")(CH -= C^(-) Ag^(+))`
`CH -= CH + NaOH to CH_3 = CH - CL`
Usually occurs in the presence of `Hg^(2+)`
`CH = CH + NaOH to `no reaction . Because of hard acid, hard based and SOFT acid , soft base (HASB) thepry. But is REACTS wiht `NaNH_2`.
`CH -= CH + NaNH_2 to CH -= C^(-) Na^(+)` Feasible
Discussion
45.

How many of the following reagents can be used to distinguish between SO_(2) and CO_(2)? Ca(OH)_(2), (strach +KIO_(3)),(K_(2)Cr_(2)O_(7)+H_(2)SO_(4)),(KMnO_(4)+H_(2)SO_(4)),Ba(OH)_(2),FeCI_(3),Zn[Fe(CN)_(5)(NO)]

Answer»


SOLUTION :(Strach `+KIO_(3)),(K_(2)Cr_(2)O_(7)+H_(2)SO_(4)),(KMnO_(4)+H_(2)SO_(4)),Ba(OH)_(2),FeCI_(3),Zn[Fe(CN)_(5)(NO)]`
Discussion
46.

How many of the following reagents can give benzene from benzene diazonium salt? H_2O, CH_3CH_2OH, H_3PO_4 , H_3PO_2 , HCHO , CH_3COOH, RCHO

Answer»


SOLUTION :`H_3 PO_2 and CH_3 CH_2OH`
Discussion
47.

How many of the following reactions are homogenous reversible reactions? (1) CH_(3)COOH(l)+C_(2)H_(5)OH(l)hArrCH_(3)COOC_(2)H_(5)(l)+H_(2)O(l) (2) C(s)+CO_(2)(g)hArrCO(g)+H_(2)O(g) (3) H_(2)(g)+CO_(2)(g)hArrCO(g)+H_(2)O(g) (4) CO(g)+CI_(2)(g)hArrCOCI_(2)(g) (5) NH_(4)HS_(s)hArrNH_(3)(g)+H_(2)S(g) (6) CaCO_(3)(s)hArrCaO(s)+CO_(2)(s) (7) N_(2)(g)O_(2)(g)hArr2NO(g) (8) CO_(2)(g)+C(s)hArr2CO(g) (9) SO_(2)+NO_(2)(g)hArrSO_(3)(g)+NO(g) (10) NO(g)+(1)/(2)Br_(2)(l)hArr2NOBr(g)

Answer»


SOLUTION :N//A
Discussion
48.

Howmany of the following Reactions will give products that are diastereomers ?

Answer»


Solution :R,R and R,Sare diasteroisomers RECTION 2,3,5 leads to formation of diasteroisomeric PRODUCT
Discussion
49.

How many of the following processes have +ve sign for entropy change? (i) Cl_(2(g)) hArr 2Cl_((g)) (ii) S_(8)("rhombic") hArr 4S_(2(g)) (iii) 3O_(2(g)) hArr 2O_(3(g)) (iv) 60C (graphite ) hArr C_(60(s)) (v) Ag_((aq))^(+) + Br_((aq))^(-) hArr AgBr_((s)) + H_(2)O (vi) H_(2)O_((l)) hArr H_(2)O_((s)) (vii) 2NH_(3(g)) hArr N_(2(g)) + 3H_(2(g)) (viii) CuSO_(4(g)) + 5H_(2)O_((l)) hArr CuSO_(4) .5H_(2)O_((s)) (ix) Ba(OH)_(2).10H_(2)O_((s)) + 2NH_(40Cl_((s))) hArr BaCl_(2(s)) + 2NH_(3(g)) + 12H_(2)O_((l))

Answer»


Solution :(i) `Cl_(2(g)) rarr 2Cl_((g))`
(ii) `S_(8)` (rhombic) `rarr 4S_(2(g))`
(III) 60C (GRAPHITE) `rarr C_(60(s))`
(vii) `2NH_(3(g)) rarr N_(2(g)) + 3H_(2(g))`
(ix) `Ba(OH)_(2). 10H_(2)O_((s)) + 2NH_(4)Cl_((s)) rarr Bacl_(2(s)) + 2NH_(3(g)) + 12H_(2)O_((l))`
Discussion
50.

How many of the following posses non-zero dipole moment Cis ICH= CHI , cis BrCH = CHBr, "tans"CH_3CH = CHCl, "trans " CH_3 - CH = CH-CH_3, cis CHCl=CHCl, "trans" CHCl=CHCl

Answer»


SOLUTION :1,2,3,5 MOLECULES are having DIPOLE movement and REAMING TRANS compounds are not having
Discussion