52671 + Interview Questions in Chemistry in Class 11

1.	Hydrogen sulphide (H_(2)S) contains 94.11 % sulphur. Sulphur dioxide (SO_(2)) contains 50 % oxygen and water (H_(2)O) contains 11.11 % hydrogen. Shpw that the results are in agreement with the law of reciprocal proportions.
Answer» Solution :Let US fix `1g` of sulphur (S) as the fixed WEIGHT In hydrogen sulphide `(H_(2)S)` Weight of sulphur `= 94.11 g` Weight of hydrogen `=100 - 94.11 =5.89 g` `94.11g` of sulphur have combined have compound with hydrogen `= 5.89 g` `1.0 g` sulphur has combined with hydrogen `= (5.89)/(94.11)g` In sulphur dioxide `(SO_(2))` `50.0 g` of sulphur have combined with OXYGEN `= 50.0 g` `1.0 g` of sulphur has combined with oxygen `= 1.0 g` Thus, the ratios by weight of hydrogen and oxygen combining with a fixed weight of sulphur in the two compounds is or `(5.89)/(94.11):1or5.89:94:11` (This ratio is not the same) In water `(H_(2)O)` Weight of hydrogen `= 11.11 g` Weight of oxygen `= 100-11.11 = 88.89 g` `11.11 : 88.89` Let us compare the ratios (i) and (II). There are related to each other as : `(5.89)/(94.11):(11.11)/(88.89)or0.0625:0.1336or1:2` Since these ratios are the simple whole number multiples of each other, the LAW of Reciprocal Proportion is illustrated.

Discussion

2.	Hydrogen resembles halogens in many respects for which several factors are responsible .Of the following factors which one is most important in this respect ?
Answer» Its tendency to LOSE an electron to FORM a cation. Its tendency to gain a single electron in its valence shell to ATTAIN stable electronic configuration 1 its low negative electron gain enthalpy value. Its small size. Answer :B

Discussion

3.	Hydrogen resembles halogens in many respects for which several factors are responsible the following factors which one is most important in this respect?
Answer» Its TENDENCY to lose an electron to form a CATION. Its tendency to gain an electron to ATTAIN stable electronic configuration. Its low negative electron gain enthalpy value. small size. Answer :B

Discussion

4.	Hydrogen resembles halogens in many respects for which several factors are responsible. Of the following factors which one is most important in this respect ?
Answer» Its tendency to lose an electron to form a cation. Its tendency to GAIN a single electron in its valence shell to attain stable electronic CONFIGURATION Its low NEGATIVE electron enthalpy value Its small size Solution :HYDROGEN resembles HALOGEN in many respects. In its one main tendency is to gain a single electron in its valence shell to attain stable electronic configuration.

Discussion

5.	Hydrogen reacts with different elements to from variety of hydrides. Group 1 and 2 elements form white crystalline, ionic hydrides.Their stability depends upon ionic character and lattice energy. Convalent hydrides are most common type of hydrides. Transition metals form interstitial hydrides. Hydrolith, a source of H_2 is
Answer» `NAH` `CaH_2` `LIH` `BaH_2` SOLUTION :`CaH_2` is CALLED HYDROLITH

Discussion

6.	Hydrogen will resemble alkali metals in many aspects but differs in
Answer» Halide formation Metallic Characters OXIDE formation SULPHIDE formation ANSWER :B

Discussion

7.	Hydrogen resembles alkali metals in many aspects but differs in ________.
Answer» METALLIC CHARACTER OXIDE formation sulphide formation halide formation ANSWER :A

Discussion

8.	Hydrogen reacts with different elements to from variety of hydrides. Group 1 and 2 elements form white crystalline, ionic hydrides.Their stability depends upon ionic character and lattice energy. Convalent hydrides are most common type of hydrides. Transition metals form interstitial hydrides. Which element form hydride ?
Answer» Cr Mo W Sn Solution :It is fact that in GROUP 6, only Cr FORMS HYDRIDE

Discussion

9.	Hydrogen reacts with different elements to from variety of hydrides. Group 1 and 2 elements form white crystalline, ionic hydrides.Their stability depends upon ionic character and lattice energy. Convalent hydrides are most common type of hydrides. Transition metals form interstitial hydrides. The co-ordination number of Na in solid NaH is :
Answer» 4 6 8 12 Solution :NAH has NACL LIKE STRUCTURE

Discussion

10.	Hydrogen peroxide solution (20 mL) reacts quantitatively with a solution of KMnO_(4) (20 mL) acidified with dilute H_(2)SO_(4). The same volume of KMnO_(4) solution is just decolurised by 10 mL of MnSO_(4) in neutral medium simultaneously forming a dark brown precipitate of hydrated MnO_(2) . The brown precipitate is dissolved in 10 mL of 0.2 M sodium oxalate under boiling conditions in the presence of dilute H_(2)SO_(4) . Write the balanced equations involved in the reactios and calculate the molarity of H_(2)O_(2).
Answer» Solution :Step 1. To write balanced equations for the reactions involved. (i) In acidic MEDIUM, `MnO_(4)^(-) ` oxidises `H_(2)O_(2)` to `O_(2)` `{:(MnO_(4)^(-)+8H^(+)+ 5e^(-) to Mn^(2+) + 4H_(2)O"]"xx2),(""H_(2)O_(2) to O_(2) + 2H^(+) + 2e^(-) "]"XX5):}/(2MnO_(4)^(-) + 5H_(2)O_(2) + 6H^(+) to 2Mn^(2+) + 5O_(2)+ 8H_(2)O)""...(i)` (ii) In neutral medium , `MnO_(4)^(-)` oxidises `Mn^(2+) ` to `MnO_(2)` . `{:(MnO_(4)^(-)+ 2H_(2)O + 3e^(-) to MnO_(2)+ 4OH^(-)"]"xx2),(""Mn^(2+)+ 4OH^(-) to MnO_(2) + 2H_(2)O + 2e^(-)"]"xx3):}/(2MnO_(4)^(-)+3Mn^(2+) + 4OH^(-) to 5 MnO_(2) + 2H_(2)O)""...(ii)` (iii) In acidic medium. `MnO_(2)` oxidises sodium oxalate to `CO_(2)` `{:(MnO_(2)+ 4H^(+) + 2e^(-) to Mn^(2+) + 2H_(2)O),(""C_(2)O_(4)^(2-) to 2CO_(2) + 2e^(-)):}/(MnO_(2) + C_(2)O_(4)^(2-) + 4H^(+) to Mn^(2+) + 2CO_(2) + 2H_(2)O) ` or `5MnO_(2) + 5C_(2)O_(4)^(2-) + 20 H^(+) to 5Mn^(2+) + 10 CO_(2) + 10 H_(2)O""...(iii)` From the above three balanced equations, it follows that `5C_(2)O_(4)^(2-) -=2MnO_(4)^(-) -=5H_(2)O_(2)""...(iv)` Step 2. To determine the number of moles of `C_(2)O_(4)^(2-)` present in 10 mL of 0.2 M sodium oxalate. No. of moles of sodium oxalate =Molarity `xx` volume in litres `=0.2 xx(10)/(1000)` `=2xx10^(-3)` mole Step 3. To calculate the molarity of `H_(2)O_(2)` From eq. (iv), it follows that `5C_(2)O_(4)^(2-)-= 5H_(2)O_(2)` or `2xx10^(-3)` mole of `C_(2)O_(4)^(2-) -= 2xx10^(-3)` mole of `H_(2)O_(2)` Now `2xx10^(-3) ` mole of `H_(2)O_(2)` is present in 10 mL of `H_(2)O_(2)` `therefore ` Molarity of `H_(2)O_(2)=(2xx10^(-3))/(10)xx1000=0.2` M

Discussion

11.	Hydrogen perxoide acts as oxidising agent?
Answer» netural MEDIUM alkaline medium alkaline and neutral medium ACIDIC and alkaline medium. Solution :(e ) `H_(2)O_(2)` can act s oxidising agent in both acidicand alkaline medium.

Discussion

12.	Hydrogen peroxide oxidises [Fe(CN)_6]^(4-)to [Fe(CN)_6]^(3-) in acidic medium but reduces [Fe(CN)_6]^(3-) to [Fe(CN)_6]^(4-)in alkaline medium. The other products formed are, respectively.
Answer» `(H_2O+O_2)` and `H_2O` `(H_2O + O_2)` and `(H_2O+ OH^-)` `H_2O` and `(H_2O+ O_2)` `H_2O` and `(H_2O+OH^-)` Solution :`[Fe(CN)_6]^(4-) + 1/2H_2O_2 + H^(+) to [Fe(CN)_6]^(3-) + H_2O` `[Fe(CN_6)]^(3-) + 1/2 H_2O_2 + OH^(-) to [Fe(CN)_6]^(4-) + H_2O + 1/2O_2`

Discussion

13.	Hydrogen peroxide is used as an antiseptic under the name
Answer» Bleaching POWDER PERHYDROL NESSEL's REAGENT Catechol Solution :Hydrogen peroxide is used as an antiseptic under the NAME perhydrol

Discussion

14.	Hydrogen peroxide is obtained by the electrolysis of ……
Answer» water sulphuric acid hydrochloric acid fused sodium peroxide Solution :When electrolysis of acidic sulphate salt and form PEROXODISULPHATE and then its hydrolysis OBTAIN `H_2O_2`. `2HSO_(4(aq))^(-) overset"electrolysis"to HO_3SOOSO_3H_((aq)) overset"hydrolysis"to 2HSO_(4(aq))^(-) + 2H_((aq))^(+) + H_2O_(2(aq))`

Discussion

15.	Hydrogen peroxide is obtained by the electrolysis of ……….. .
Answer» water sulphuric acid hydrochloric acid fused SODIUM peroxide Answer :B

Discussion

16.	Hydrogen peroxide is used as
Answer» An OXIDENT only A REDUCTANT only An ACID only An OXIDANT, a reductant and an acid ANSWER :D

Discussion

17.	Hydrogen peroxide is obtained by the electrolysis of _________.
Answer» water sulphuric acid hydrochloric acid fused SODIUM peroxide Solution :`H_(2)O_(2)` is obtained by the ELECTROLYSIS of a cold 50% solution of `H_(2)SO_(4)`. `2H_(2)SO_(4)to 2H^(+)+2HSO_(4)^(-)` `2HSO_(4)^(-)overset("Electrolysis")rarr UNDERSET(2HSO_(4(aq))^(-)+2H_((aq))^(+)+H_(2)O_(2(aq)))underset(darr" Hydrolysis")underset("Peroxodisulphate")(HO_(3)SOOSO_(3)H_((aq)))`

Discussion

18.	Hydrogen peroxide is manufactured by autoxidation of …………. .
Answer» ANSWER :2-ethylanthraquinol

Discussion

19.	Hydrogen peroxide is a powerful oxidizing agent. It is an electron acceptor in acidic and alkaline mediums. H_(2)O_(2)+H^(+)+2erarr2H_(2)O (in acidic medium) H_(2)O_(2)+2erarr2OH^(-) (in alkaline medium) It can also act as a reducing agent towards powerful oxidizing agents. H_(2)O_(2)rarr2H^(+)+O_(2)+2e In alkalinemedium, however, its reducing nature is more effective. H_(2)O_(2)+2OHrarr2H_(2)O+O_(2)+2e What is the product of the reaction of H_(2)O_(2) with Cl_(2)
Answer» `O_(2)+HOCl` `HCl+O_(2)` `H_(2)O+HCl` `HCl+H_(2)` SOLUTION :`H_(2)O_(2) + Cl_(2) RARR HCl + O_(2)`

Discussion

20.	Hydrogen peroxide is …………. In nature and acts as an ……………… as well as a ……… agent both in ………………. And ……….. Media .
Answer» ANSWER :ACIDIC, OXIDISING , REDUCING , acidic , BASIC

Discussion

21.	Hydrogen peroxide is a powerful oxidising agent. It is an electron acceptor in acidic and alkaline mediums . H_(2)O_(2) + 2H^(+) + 2e^(-) rarr H_(2)O (in acidic medium ) H_(2)O_(2) + 2e^(-) rarr 2OH^(-) (in alkaline medium) It can also act as reducing agent towards powerful oxidising agents . H_(2)O_(2) rarr 2H^(+) + O_(2) + 2e In alkaline medium , however , its reducing nature is more effective . H_(2)O_(2) + 2OH^(-) rarr 2H_(2)O + O_(2) + 2e^(-) In the reaction , H_(2)O_(2) + O_(3) rarr H_(2)O + 2O_(2) , H_(2)O_(2) acts as :
Answer» An ACID An OXIDIZING A reducing agent Both as a reducing agent and an oxidising agent ANSWER :C

Discussion

22.	Hydrogen peroxide is a powerful oxidising agent. It is an electron acceptor in acidic and alkaline mediums . H_(2)O_(2) + 2H^(+) + 2e^(-) rarr H_(2)O (in acidic medium ) H_(2)O_(2) + 2e^(-) rarr 2OH^(-) (in alkaline medium) It can also act as reducing agent towards powerful oxidising agents . H_(2)O_(2) rarr 2H^(+) + O_(2) + 2e In alkaline medium , however , its reducing nature is more effective . H_(2)O_(2) + 2OH^(-) rarr 2H_(2)O + O_(2) + 2e^(-) In which of the following reactions , H_(2)O_(2) acts as an oxidising agent ?
Answer» `IO_(4)^(-) + H_(2)O_(2) rarr IO_(3)^(-) + H_(2)O + O_(2)` `2I^(-) + H_(2)O_(2) + 2H^(+) rarr I_(2) + 2H_(2)O` `Ag_(2)O + H_(2)O_(2) rarr 2Ag + H_(2)O + O_(2)` `2MnO_(4)^(-) + 6H^(+) + 5H_(2)O_(2) rarr 2Mn^(2+) + 8H_(2)O + 5O_(2)` Answer :B

Discussion

23.	Hydrogen peroxide is an oxidising agent. It oxidises ferrous ion to ferric ion and reduced itself to water. Write a balanced equation.
Answer» Solution :`H_2O_2 ` - OXIDISING agent `Fe^(2+)+H_(2)O_(2) to Fe^(3+)+H_(2)O` (Acetic Medium) Ferrous ION is OXIDIZED by `H_2O_2` to Ferric ion The balanced EQUATION is `Fe^(2+)to Fe^(3+)+e^(-)xx2` `H_2O_(2)+2H^(+)+2cancel(e^(-)) to 2H_(2)O` `2Fe^(2+)to 2Fe^(3+)+cancel(2e^(-))`. `(H_(2)O_(2)+2H^(+)to2H_(2)O)/(2Fe^(2+)+H_(2)O_(2)+2H^(+)to2Fe^(3+)+2H_(2)O)`

Discussion

24.	Hydrogen peroxide is a powerful oxidising agent. It is an electron acceptor in acidic and alkaline mediums . H_(2)O_(2) + 2H^(+) + 2e^(-) rarr H_(2)O (in acidic medium ) H_(2)O_(2) + 2e^(-) rarr 2OH^(-) (in alkaline medium) It can also act as reducing agent towards powerful oxidising agents . H_(2)O_(2) rarr 2H^(+) + O_(2) + 2e In alkaline medium , however , its reducing nature is more effective . H_(2)O_(2) + 2OH^(-) rarr 2H_(2)O + O_(2) + 2e^(-) In which of the following reactions , H_(2)O_(2) acts a reducing agent ?
Answer» `PbO_(2) + H_(2)O_(2) rarr PbO + H_(2)O + O_(2)` `Na_(2)SO_(3) + H_(2)O_(2) rarr Na_(2)SO_(4) + H_(2)O` `2Kl + H_(2)O_(2) rarr 2KOH + I_(2)` `KNO_(2) + H_(2)O_(2) rarr KNO_(3) + H_(2)O` ANSWER :A

Discussion

25.	Hydrogen peroxide is
Answer» NEUTRAL a MONOBASIC ACID a DIBASIC acid a diacidic base Answer :C

Discussion

26.	Hydrogen peroxide is …………… .
Answer» an OXIDISING AGENT a REDUCING agent both an oxidising and a reducing agent neither oxidising nor reducing agent ANSWER :C

Discussion

27.	Hydrogen peroxide is ionise as : H_(2)O_(2) hArr H^(+)+HO_(2)^(-). If p^(h) of H_(2)O_(2) is 5.91 at 25^(@)C the ionic product of H_(2)O_(2) is
Answer» `1.51 XX 10^(-12)` `1.15 xx 10^(-12)` `1 xx 10^(-14)` `1.1 xx 10^(-12)` Solution :`[H^(+)]" at" 25^@C =10^(-5.91) = 1.23 xx 10^(-6)M` `[H^(+)] " at" 25^@C = 10^(-5.91) = 1.23 xx 10^(-6) M` `K = [H^(+)][HO_2^(-)] = [1.23 xx 10^(-6)]^2 = 1.51 xx 10^(-12)`

Discussion

28.	Hydrogen peroxide is ……..
Answer» an OXIDISING AGENT a reducing agent both an oxidising and a reducing agent neither oxidising nor reducing agent Solution :Hydrogen peroxide ACT as an oxidising and reducing agent in both ACIDIC and BASIC medium.

Discussion

29.	Hydrogen peroxide in its reaction with KIO_(4) and NH_(2)OH respectively , is acting as a
Answer» reducing agent , oxidising agent reducing agent , reducing agent oxidising agent, oxidising agent oxidising agent , reducing agent SOLUTION :`overset(+7)KIO_(4)+ underset("Reducing agent ")(H_(2)O_(2)) to overset(+5)(KIO_(3))+ H_(2)O + O_(2)` `overset(-1)NH_(2)OH + underset("Oxidising agent ")(3H_(2)O_(2))to overset(+5)(HNO_(3))+ 4H_(2)O`

Discussion

30.	Hydrogen peroxide in its reaction with KIO_(4) and NH_(2)OH respectivley, is acting as a
Answer» REDUCING AGENT, oxidising agent reducing agent, oxidsing agent oxidisign agent, oxidising agent oxidising agent, reducing agent Solution :(a) `H_(2)O_(2)` acts a reducing agent in its reaction with `KIO_(4)` and as an oxidising agent in its reaction with `NH_(2)OH`. For details, cosult ADDITIONAL important question (Q.48)

Discussion

31.	Hydrogen Peroxide in aqueous solutoin decomposes on warming to give oxygen according to the equation, 2H_(2)O_(2(aq))rarr2H_(2)O_((l))+O_(2(g)), under conditions where one mole of gas occupies 24dm^(3).100cm^(3) of .X.M solution H_(2)O_(2) produces 3dm^(3) of O_(2). Thus X is :
Answer» `2.5` `5.0` `10.0` `30.0` SOLUTION :Volume strength = `(V_(O_(2)(STP)))/(V_("SOLN"))` `n_(O_(2))=(3)/(24)=(1)/(8),V_(O_(2)(STP))=(1)/(8)xx22.4L` IMPLIES Volume strength = `(22.4xx(1)/(8))/(0.1)` `implies M=(V.S.)/(11.2)=(22.4)/(11.2xx0.1)XX(1)/(8)=2.5M`

Discussion

32.	Hydrogen peroxide in its reaction with KIO_4 and NH_2OH respectively, is acting as
Answer» REDUCING AGENT, OXIDISING agent reducing agent, reducing agent oxidising agent, oxidising agent, oxidising agent, reducing agent Solution :`KIO_4 + H_2O_2 to KIO_3+H_2O + O_2` `NH_2 OH + 3H_2O_2to HNO_3 + 4H_2O`

Discussion

33.	Hydrogen peroxide (H_2 O_2) was first prepared by Thenard by acidifying barium peroxide and removal of excess water by evaporation under reduced pressure. Its strength can be expressed as weigth percentage or as volume percentage . 25% solution by weight means 25 g of hydrogen peroxide are present in 100 g of solution and 25 volume of hydrogen peroxide means that 1 litre of this solution will give 25 L of oxygen at NTP. Write chemical reaction for the preparation of H_2 O_2 from hydrated barium peroxide.
Answer» SOLUTION :`UNDERSET("Hydrated barium PEROXIDE")(BaO_2 * 8H_2 O(s) + H_2 SO_4(aq)) to BaSO_4 (s) + H_2 O_2 (aq) + 8H_2 O(l)`

Discussion

34.	Hydrogen peroxide exhibits oxidising property in reaction with
Answer» Ozone Chlorine ACIDIFIED `KMnO_4` Acidified `K_4[FE(CN)_6]` ANSWER :D

Discussion

35.	Hydrogen peroxide can preserved by adding a small amount of
Answer» Aluminimumoxide MANGANESEDIOXIDE SILICONDIOXIDE UREA ANSWER :D

Discussion

36.	Hydrogen peroxide can function as an oxidising agent as well as reducing agent. substantiate this statement with suitable examples.
Answer» Solution :Hydrogen peroxide can act both as an OXIDIZING AGENT and a REDUCING agent. Oxidation is usually performed in acidicmedium while the reduction reactions are performed in basic MEDIUM In acidic conditions : `H_2O_2+2H^++3e^-to2H_2O(E^0=+1.77V)` For example `2FeSO_4_H_2SO_4+H_O_2+2e^-` In basic conditions : `HO^-+OH^-toO_2+H_2O+2e^-` `(E^0=+0.08V)` For example

Discussion

37.	Hydrogen peroxide can be prepared in the laboratory by the action of dilute acids on metallic peroxide. In one method, sodium peroxide is added in samall amount at a time to a dilute solution of sulphuric acid in cold. Sodium peroxide can be replaced by barium peroxide. In this case, a paste of BaO_(2).8H_(2)O is prepared and added gradually to an ice-cold dilute sulphuric acid. Barium sulphate precipitates out leaving behind a dilute solution of hydrogen peroxide. Phosphoric acid can also be used in place of sulphuric acid. Which of the following is used for the preparation of H_(2)O_(2)?
Answer» Anhydrous `BaO_(2)` Anhydrous `Na_(2)O_(2)` `TiO_(2)` `PbO_(2)` Solution :N//A

Discussion

38.	Hydrogen peroxide can be prepared in the laboratory by the action of dilute acids on metallic peroxide. In one method, sodium peroxide is added in samall amount at a time to a dilute solution of sulphuric acid in cold. Sodium peroxide can be replaced by barium peroxide. In this case, a paste of BaO_(2).8H_(2)O is prepared and added gradually to an ice-cold dilute sulphuric acid. Barium sulphate precipitates out leaving behind a dilute solution of hydrogen peroxide. Phosphoric acid can also be used in place of sulphuric acid. The correct increasing order of the acidity of CO_(2),H_(2)O and H_(2)O_(2) is
Answer» `CO_(2)ltH_(2)O_(2)ltH_(2)O` `H_(2)OltH_(2)O_(2)ltCO_(2)` `H_(2)OltH_(2)O_(2)gtCO_(2)` `H_(2)O_(2)gtCO_(2)gtH_(2)O` Solution :N//A

Discussion

39.	Hydrogen peroxide can be tested with
Answer» A filter paper with a stain of BLACK Pos An acidified solution of `TiO_(2)` KI+ starch solution Acidified `K_(2)Cr_(2)O_(7)` solution with little ether Solution : Hydrogen PEROXIDE can be tested with (1) `H_(2)O_(2)`reacts with KI to form `I_(2)` which on reaction with starch producess BLUE colour soution. `H_(2)_(2)2KI to 2KOH +I_(2) overset("startch") to` blue color (2) `H_(2)O_(2)` on reaction with acidified `K_(2)Cr_(2)O_(7)`forms blue peroxide of chromium which is soluble in ether and PRODUCES blue colored layer. (3) `H_(2)O_(2)` gives orange colour (pertitanic acid) on reaction with acidified titanium dioxide `TiO_(2)+2H_(2)SO_(4) to Ti(SO_(4))_(2)+2H_(2)O- overset(H_(2)O_(2)) to H_(2) TiO_(4)+2H_(2)S_(4)` Per titanic acid (4) `H_(2)O_(2)` tunr balck PbS into white substance `PbS_(4)`

Discussion

40.	Hydrogen peroxide can be prepared by the action of dil. H_(2)SO_(4) or H_(3)PO_(4) on barium peroxide or by bubbling carbon dioxide through a thin paste of barium peroxide. On an industrial scale , it can be prepared by hydrolysis of peroxodisulphuric acid obtained by electrolysis of 50% H_(2)SO_(4) or an equimolar mixture of H_(2)SO_(4) and ammonium sulphate .The strength of H_(2)O_(2) solution can be expressed in a number ways namely normality , molarity , percentage strength and volume of O_(2) produced at N.T.P by decomposition of 1 mL of H_(2)O_(2) acts as an oxidising as well a reducing agent both in acidic and basic media. In acidic medium , H_(2)O_(2) acts a reducing agent in its reaction with
Answer» `FeSO_(4)` `KMnO_(4)` `K_(2)MnO_(4)` `K_(4)[Fe(CN)_(6)]` Answer :B

Discussion

41.	Hydrogen peroxide can be prepared by the action of dil. H_(2)SO_(4) or H_(3)PO_(4) on barium peroxide or by bubbling carbon dioxide through a thin paste of barium peroxide. On an industrial scale , it can be prepared by hydrolysis of peroxodisulphuric acid obtained by electrolysis of 50% H_(2)SO_(4) or an equimolar mixture of H_(2)SO_(4) and ammonium sulphate .The strength of H_(2)O_(2) solution can be expressed in a number ways namely normality , molarity , percentage strength and volume of O_(2) produced at N.T.P by decomposition of 1 mL of H_(2)O_(2) acts as an oxidising as well a reducing agent both in acidic and basic media. What will be the volume of oxygen at NTP liberated upon the complete decomposition of 100 mL of the 2M H_(2)O_(2)solution?
Answer» 2.24 L 22.4 L 44.8 L 11.2 L Answer :A

Discussion

42.	Hydrogen peroxide can be prepared by the action of dil. H_(2)SO_(4) or H_(3)PO_(4) on barium peroxide or by bubbling carbon dioxide through a thin paste of barium peroxide. On an industrial scale , it can be prepared by hydrolysis of peroxodisulphuric acid obtained by electrolysis of 50% H_(2)SO_(4) or an equimolar mixture of H_(2)SO_(4) and ammonium sulphate .The strength of H_(2)O_(2) solution can be expressed in a number ways namely normality , molarity , percentage strength and volume of O_(2) produced at N.T.P by decomposition of 1 mL of H_(2)O_(2) acts as an oxidising as well a reducing agent both in acidic and basic media. The volume of 10 volume H_(2)O_(2) solution that decolourises 200 ml of 2N KMnO_(4) solution in acidic medium is
Answer» 112 ml 336 ml 200 ml 224 ml Answer :D

Discussion

43.	Hydrogen peroxide can be prepared in the laboratory by the action of dilute acids on metallic peroxide. In one method, sodium peroxide is added in samall amount at a time to a dilute solution of sulphuric acid in cold. Sodium peroxide can be replaced by barium peroxide. In this case, a paste of BaO_(2).8H_(2)O is prepared and added gradually to an ice-cold dilute sulphuric acid. Barium sulphate precipitates out leaving behind a dilute solution of hydrogen peroxide. Phosphoric acid can also be used in place of sulphuric acid. The oxide that gives hydrogen peroxide on treatment with a dilute acid is:
Answer» `PbO_(2)` `SrO_(2)` `MnO_(2)` `TiO_(2)` Solution :`PbO_(2), MnO_(2), TiO_(2)`areoxide but`SrO_(2)` is a stonsium PEROXIDE .

Discussion

44.	Hydrogen peroxide can be prepared by the action of dil. H_(2)SO_(4) or H_(3)PO_(4) on barium peroxide or by bubbling carbon dioxide through a thin paste of barium peroxide. On an industrial scale , it can be prepared by hydrolysis of peroxodisulphuric acid obtained by electrolysis of 50% H_(2)SO_(4) or an equimolar mixture of H_(2)SO_(4) and ammonium sulphate .The strength of H_(2)O_(2) solution can be expressed in a number ways namely normality , molarity , percentage strength and volume of O_(2) produced at N.T.P by decomposition of 1 mL of H_(2)O_(2) acts as an oxidising as well a reducing agent both in acidic and basic media. The correct increasing order of the acidity of CO_(2), H_(2)O and H_(2)O_(2) is
Answer» `CO_(2) LT H_(2)O_(2) lt H_(2)O` `H_(2)O_(2) lt H_(2)O_(2) lt CO_(2)` `H_(2)O lt H_(2)O_(2) gt CO_(2)` `H_(2)O_(2) gt CO_(2) lt H_(2)O` ANSWER :B

Discussion

45.	Hydrogen peroxide can be prepared by action of dil H_(2)SO_(4) or H_(3)PO_(4) on barium peroxide or by bubbling CO_(2) through a thin paste of barium peroxide. On industrial scale, it may be prepared by hydrolysis of peroxy disulphuric acid obtained by electrolsis of50%""H_(2)SO_(4) or equimolar mixture of sulphuric acid and ammonium sulphate. The strength ofH_(2)O_(2) can be expressed in various methods say normality, molarity, strength and volume strength. Volume strength means the volume of O_(2) produced by decomposition of 1 ml of H_(2)O_(2). H_(2)O_(2) acts as an oxidising as well as a reducing agent both in acidic and basic media. Hydrolysis of one mole of peroxodisuphuric acid produces
Answer» TWO MOLES of sulphuric acid Two moles of peroxomonosulphuric acid ONE MOLE of sulphuric acid, one mole of peroxomonosulphuphuric acid One mole of sulphuric acid one mole of peroxomonosulphuphuric and one mole of hydrogen peroxide. Answer :C

Discussion

46.	Hydrogen peroxide can be prepared by action of dil H_(2)SO_(4) or H_(3)PO_(4) on barium peroxide or by bubbling CO_(2) through a thin paste of barium peroxide. On industrial scale, it may be prepared by hydrolysis of peroxy disulphuric acid obtained by electrolsis of50%""H_(2)SO_(4) or equimolar mixture of sulphuric acid and ammonium sulphate. The strength ofH_(2)O_(2) can be expressed in various methods say normality, molarity, strength and volume strength. Volume strength means the volume of O_(2) produced by decomposition of 1 ml of H_(2)O_(2). H_(2)O_(2) acts as an oxidising as well as a reducing agent both in acidic and basic media. 100 volumn hydrogen peroxide solution means
Answer» `1786 N` `3036% H_(2)O_(2)` `8*93 N` All are correct. Answer :D

Discussion

47.	Hydrogen peroxide can be prepared by action of dil H_(2)SO_(4) or H_(3)PO_(4) on barium peroxide or by bubbling CO_(2) through a thin paste of barium peroxide. On industrial scale, it may be prepared by hydrolysis of peroxy disulphuric acid obtained by electrolsis of50%""H_(2)SO_(4) or equimolar mixture of sulphuric acid and ammonium sulphate. The strength ofH_(2)O_(2) can be expressed in various methods say normality, molarity, strength and volume strength. Volume strength means the volume of O_(2) produced by decomposition of 1 ml of H_(2)O_(2). H_(2)O_(2) acts as an oxidising as well as a reducing agent both in acidic and basic media. Which of the following substance on treatment with H_(2)O_(2) gives MnO_(2)
Answer» Acidified `KMnO_(4)` ALKALINE `KMnO_(4)` Alkaline `MnSO_(4)` Both B and C. Answer :D

Discussion

48.	Hydrogen peroxide can be prepared by action of dil H_(2)SO_(4) or H_(3)PO_(4) on barium peroxide or by bubbling CO_(2) through a thin paste of barium peroxide. On industrial scale, it may be prepared by hydrolysis of peroxy disulphuric acid obtained by electrolsis of50%""H_(2)SO_(4) or equimolar mixture of sulphuric acid and ammonium sulphate. The strength ofH_(2)O_(2) can be expressed in various methods say normality, molarity, strength and volume strength. Volume strength means the volume of O_(2) produced by decomposition of 1 ml of H_(2)O_(2). H_(2)O_(2) acts as an oxidising as well as a reducing agent both in acidic and basic media. The correct order of acidity of CO_(2), H_(2)O and H_(2)O_(2) is
Answer» `CO_(2)ltH_(2)O_(2)ltH_(2)O` `H_(2)OltH_(2)O_(2)ltCO_(2)` `H_(2)OltH_(2)O_(2)gtCO_(2)` `H_(2)O_(2)gtCO_(2)gtH_(2)O` Answer :B

Discussion

49.	Hydrogen peroxide can be preapared bythe action of dil. H_(2)SO_(4) or H_(3)PO_(4) on barium peroxide or by bubbling peroxide . On an industrial scale, it can be prepared by hydrolysis of peroxodisulphuric acid obtained by electrolysis of 50% H_(2)SO_(4) or an equimolar mixture of H_(2)SO_(4) and ammonium sulphate . The strength of H_(2)O_(2) solution can be expressed in a number of ways namely normality , molarity , percentage strength and volume strength . Volume strength refers to the volume of O_(2) produced at N.T.P. by decomposition of 1 mL of H_(2)O_(2) solution. H_(2)O_(2) acts as an oxidising as well as reducing agent both in acidic and basic media. Which of the following substances on treatment with H_(2)O_(2) gives MnO_(2)
Answer» acidified `KMnO_(4)` alkaline `KMnO_(4)` alkaline `MnSO_(4)` both (b) and (C) ANSWER :d

Discussion

50.	Hydrogen peroxide can be preapared bythe action of dil. H_(2)SO_(4) or H_(3)PO_(4) on barium peroxide or by bubbling peroxide . On an industrial scale, it can be prepared by hydrolysis of peroxodisulphuric acid obtained by electrolysis of 50% H_(2)SO_(4) or an equimolar mixture of H_(2)SO_(4) and ammonium sulphate . The strength of H_(2)O_(2) solution can be expressed in a number of ways namely normality , molarity , percentage strength and volume strength . Volume strength refers to the volume of O_(2) produced at N.T.P. by decomposition of 1 mL of H_(2)O_(2) solution. H_(2)O_(2) acts as an oxidising as well as reducing agent both in acidic and basic media. 100 volume hydrogen peroxide solution means
Answer» 17.86 N 30.36% `H_(2)O_(2)` `8.93 M` all are correct Solution :Apply the formulae GIVEN in 'Supplement Your Knowledge for COMPETITIONS' All option are correct.

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

Hydrogen sulphide (H_(2)S) contains 94.11 % sulphur. Sulphur dioxide (SO_(2)) contains 50 % oxygen and water (H_(2)O) contains 11.11 % hydrogen. Shpw that the results are in agreement with the law of reciprocal proportions.

Hydrogen resembles halogens in many respects for which several factors are responsible .Of the following factors which one is most important in this respect ?

Hydrogen resembles halogens in many respects for which several factors are responsible the following factors which one is most important in this respect?

Hydrogen resembles halogens in many respects for which several factors are responsible. Of the following factors which one is most important in this respect ?

Hydrogen will resemble alkali metals in many aspects but differs in

Hydrogen resembles alkali metals in many aspects but differs in ________.

Hydrogen perxoide acts as oxidising agent?

Hydrogen peroxide oxidises [Fe(CN)_6]^(4-)to [Fe(CN)_6]^(3-) in acidic medium but reduces [Fe(CN)_6]^(3-) to [Fe(CN)_6]^(4-)in alkaline medium. The other products formed are, respectively.

Hydrogen peroxide is used as an antiseptic under the name

Hydrogen peroxide is obtained by the electrolysis of ……

Hydrogen peroxide is obtained by the electrolysis of ……….. .

Hydrogen peroxide is used as

Hydrogen peroxide is obtained by the electrolysis of _________.

Hydrogen peroxide is manufactured by autoxidation of …………. .

Hydrogen peroxide is …………. In nature and acts as an ……………… as well as a ……… agent both in ………………. And ……….. Media .

Hydrogen peroxide is an oxidising agent. It oxidises ferrous ion to ferric ion and reduced itself to water. Write a balanced equation.

Hydrogen peroxide is

Hydrogen peroxide is …………… .

Hydrogen peroxide is ionise as : H_(2)O_(2) hArr H^(+)+HO_(2)^(-). If p^(h) of H_(2)O_(2) is 5.91 at 25^(@)C the ionic product of H_(2)O_(2) is

Hydrogen peroxide is ……..

Hydrogen peroxide in its reaction with KIO_(4) and NH_(2)OH respectively , is acting as a

Hydrogen peroxide in its reaction with KIO_(4) and NH_(2)OH respectivley, is acting as a

Hydrogen Peroxide in aqueous solutoin decomposes on warming to give oxygen according to the equation, 2H_(2)O_(2(aq))rarr2H_(2)O_((l))+O_(2(g)), under conditions where one mole of gas occupies 24dm^(3).100cm^(3) of .X.M solution H_(2)O_(2) produces 3dm^(3) of O_(2). Thus X is :

Hydrogen peroxide in its reaction with KIO_4 and NH_2OH respectively, is acting as

Hydrogen peroxide exhibits oxidising property in reaction with

Hydrogen peroxide can preserved by adding a small amount of

Hydrogen peroxide can function as an oxidising agent as well as reducing agent. substantiate this statement with suitable examples.

Hydrogen peroxide can be tested with