Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

In the hydrogen atom, the electrons are excited to the 5th energy level. The number of lines that may appear in the spectrum will be

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4
8
10
12

Solution :No. of lines PRODUCED for JUMP for 5th orbit to 1ST orbit
`= Sigma (n_(2) - n_(1)) = Sigma(5 -1) = Sigma4 = 4 + 3 + 2 + 1 = 10`
2.

In the hydrocarbon overset(7)CH_(3)-overset(6)CH_(2)-overset(5)CH=overset(4)CH-overset(3)CH_(2)-overset(2)C-=overset(1)CH the state of hybridisation of carbon 1,2,3,4 and 7 are in the following sequence.

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`SP,sp,sp^(3),sp^(2),sp^(3)`
`sp^(2),sp,sp^(3),sp^(2),sp^(3)`
`sp,sp,sp^(2),sp,sp^(3)`
NONE of these

Answer :A
3.

In the hydrocarbon CH_(3) - CH_(2) - CH = ""^(.)CH - CH_(2) - C-= CH the state of hybridisation of carbon 1,2,3,4 and 7 are in the following sequence.

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SP, sp, `sp^(3), sp^(2), sp^(3)`
`sp^(2), sp, sp^(3), sp^(2), sp^(3)`
sp, sp, `sp^(2), sp, sp^(3)`
NONE of these

Answer :A
4.

In the hydroboration-oxidation reaction of propene with dibroane, H_2O_2 and NaOH, the organic compound formed is :

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`CH_3CH_2OH`
`CH_3CHOHCH_3`
`CH_3CH_2CH_2OH`
`(CH_3)_3COH`

ANSWER :C
5.

In the Hoope's process for refining of Al the fused materials form three different layers and they remain spearated during electrolysis also. This is because.

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The upper layer is kept attracted by cathode and lower layer is kept attracted by anode.
There is special arrangement in cell to keep the layers separate.
Three layers have DIFFERENT densities
Three layers are maintained at DIFFERENTS temperatures.

Solution :In the Hoope's PROCESS for refining of Al, the fused materials form three different layers and they remain SEPARATED during electrolysis because the three layers have different densities.
6.

In the hardening stage of plaster of paris, the compound formed is

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`CaSO_(4)`
Orthorhombic `CaSO_(4).2H_(2)O`
`CaSO_(4). H_(2)O`
Monoclinic `CaSO_(4).2H_(2)O`

ANSWER :D
7.

In the Haber process N_(2)+ 3H_(2) hArr 2NH_(3) pressure is about 200 atm in pressure of catalyst and temperature is kept 500^(@)C even though the reaction is exothermic. Reason : Energy needed for this reaction is easily obtained at this temperature.

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if both assertion and reason are correct and reason is CORRECTEXPLANATION for assertion.
if both assertion and reason are correct but reason is not correct EXPLANATION for assertion.
if assertion is correct but reason is incorrect.
if assertion and reason boht are incorrect.

Solution :Correct explanation. These are the optimum conditions which are neededfor reactionto PROCEED in the FORWARD direction.
8.

In the ground state, an element has 13 electrons in its "M - shell". The element is

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Copper
Chromium
Nickel
iron

Answer :B
9.

In the gives reaction sequence CH_(3)CH_(2)underset(O)underset(||)C CH_(2)CH_(3)overset(Br_(2)//CH_(3)COOH)rightarrow Xoverset(Br_(2)//NaOH)rightarrow Y X,Y respectively are

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`CH_(3)CH_(2)COCHBrCH_(3)&CH_(3)CH_(2)COCBr_(2)CH_(3)`
`CH_(3)CH_(2)COCBr_(2)CH_(3)&CH_(3)CH_(2)COCBrCH_(3)`
`CH_(3)CH_(2)COCBr_(2)CH_(3)&CH_(3)CH_(2)COCBr_(2)CH_(3)`
`CH_(3)CH_(2)COCHBr_(2)CH_(3)&CH_(3)CH_(2)COCHBr_(2)CH_(3)`

Answer :1
10.

In the grand state, an element has 13 electrons in its M-shell. The element is

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Manganese
Chromium
Nickel
Iron

Solution :`13e^(-)` in M (3rd) shell means `3s^(2) 3p^(6) 3d^(5)`. Hence complete CONFIGURATION will be
`1s^(2) 2S^(2) 2P^(6) 3s^(2) 3p^(6) 3d^(5) 4s^(1) or 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 3d^(5) 4s^(2)`
Hence, the element is chromium (Z = 24) or manganes (Z = 25)
11.

In the given transformation, which the following is the most appropriate reagent?

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`NH_(2)NH_(2), overset(Θ)(OH)`
`Zn-Hg//HCl`
`NA, Liq, NH_(3)`
`NaBH_(4)`

ANSWER :A
12.

In the given selective hydrogenation which combination is incorrect?

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SOLUTION :
LESS stable and less sterically hindered ALKENE will undergo REDUCTION.
13.

In the given reactions: (i). CH_(3)Br overset(Na,ether)to X underset(hupsilon)overset(Br_(2))toY overset(Na,ether)Z (ii) CH_(3)COOH overset(NaOH)to X underset(CaO)overset(NaOH)to Y underset(h upsilon)overset(Br_(2))toZ Identify, X,Y and Z

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X-(i) `CH_(4)` (II) `CH_(3)COONA`
Y-`CH_(3)Br, CH_(3)CH_(3)`
Z-`CH_(3)CH_(3), CH_(3)CH_(2)Br`
X-(i) `CH_(3)CH_(3)` (ii) `CH_(3)COONa`
Y-`CH_(4), CH_(4)`, Z-`CH_(3)Br,CH_(3)CH_(2)CH_(3)`
X-(i) `CH_(3)CH_(3)` (ii)- `CH_(3)COONa`, Y-`CH_(4),CH_(3)CH_(3), Z-CH_(3)CH_(3)CH_(3), CH_(3)Br`
X-(i) `CH_(3)CH_(3)` (ii) `CH_(3)COONa`, Y-`CH_(3)CH_(2)Br,CH_(4)` Z-`CH_(3)CH_(2)CH_(2)CH_(3), CH_(3)Br`

Answer :D
14.

In the given reactions M is the number of major products obtained in I^(st) reaction and N number of major products obtained in II^(nd) reaction. Report your answer as MN.

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SOLUTION :
15.

In the given reaction [X] will be :

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both
None

Solution :
16.

In the given reaction : [X] will be :

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SOLUTION :
17.

In the given reaction X is CH_(3)CHO + CH_(2) (COOH)_(2) overset("Pyridine" //Delta)rarr X

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`CH_(3)COOH`
`C_(2)H_(5)COOH`
`CH_(3)CH = CH - COOH`
`(COOH) CH = CH - (COOH)`

SOLUTION :See Knovengeal REACTION in Some NOTEWORTHY Points
18.

In the given reaction (x) underset("2)"H_2O //Zn)overset("1)"O_3)to underset("(only product)")(CH_3-overset(O)overset(||)C-CH_2-CH_2-CH_2-CH_2-CHO),(x) is

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`CH_3- OVERSET(CH_2)overset(||)C-CH_2-CH_2-CH_2-CH-CH_2`
`CH_3-overset(H)overset(|)C=CH-CH_2-CH_2-CH=CH_2`

SOLUTION :
19.

In the given reaction which of the following is the relation of between K_p and K_c ? N_(2(g)) + 3H_(2(g)) hArr 2NH_(3(g))

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`K_p=K_c`
`K_p GT K_c`
`K_p LT K_c`
`K_p//K_c`= ZERO

ANSWER :C
20.

In the given reaction sequence, Y is

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PHENYL glyoxal
Glyoxal
Benzoic acid
Phenyl ethanal

Solution :
21.

In the given reaction K_(2)Cr_(2)+XH_(2)SO_(4)+YSO_(2)rarrK_(2)SO_(4)+R_(2)(SO_(4))_(3)+ZH_(2)O X,Y,Z are

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1,3,1
4,1,4
3,2,3
2,1,2

Answer :a
22.

In the given reaction : overset(Conc. H_2SO_4)to [X] as major product [X] will be :

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ANSWER :B
23.

In the given reaction : CH_3-underset(Ph)underset(|)CH-oversetoverset(OH)(|)CH-CH_3underset(Delta)overset(conc. H_2SO_4)to Alkenes Total numberof alkenes (including stereo isomers) formed will be

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24.

In the given reaction2X (g) + Y (g) hArr 2 Z (g) + 80kcal, which combination of pressure and temperature will give the highest yield of Z at equilibrium ?

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1000 atm and `200^(@)C`
500 atm and `500^(@) C`
500 atm and `200^(@) C`
500 atm and `100^(@)`

Solution :As `n_(p) lt n_(r)`, HIGHER the pressure . Greater will be YIELD of Z. As reactionis exothermic in the forwarddirection, lower the temperature , greater is the yield of Z (As at low temperature , greater is the yield of Z (As at low temperature the reaction is slow, usually optimum temperature is USED ).
25.

In the given molecules the sites undergoes deprotonation and protonation most readily respectively arex & y the x+y=? overset(1)(N_(2)H)-underset(""^(2)NH)underset(||)C-overset(3)(NH)-CH_(2)-CH_(2)-CH_(2)-underset(""^(4)NH_(2))underset(|)CH-overeset(5)(COOH) How many of the following compounds will accept H^(o+) from ammonium ion. How many of the following compounds react with NaHCO_(3) and liberate CO_(2)(g) 1. Salicylic acid2.Pthalic acid3.Picric acid4 Resorcinol 5.Carbolic acid6.Aspirin7.Anisol8.Tarteric acid

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ANSWER :4(v,VI,vii,VIII)
26.

In the given molecules the sites undergoes deprotonation and protonation most readily respectively arex & y the x+y=? overset(1)(N_(2)H)-underset(""^(2)NH)underset(||)C-overset(3)(NH)-CH_(2)-CH_(2)-CH_(2)-underset(""^(4)NH_(2))underset(|)CH-overeset(5)(COOH) How many of the following compounds will accept H^(o+) from ammonium ion. Pyridine ,Aniline,Pyrrole,Tripheryl amine, Benzyl amine,Methyl amine,Di-methyl amine,Tri-methyl amine

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SOLUTION :5 is deprotanated SINCE it is most acidic acid, 2 is protonated since it is most BASIC (guanidinci N).
x=5,y=2so x+y=7
27.

In the given chemical reaction, 2P+H_(2)O+CO_(2) to Q overset(H_(2)O+CO_(2))to 2R overset(NaCl)toS+NH_(4)Cl Identify S.

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`Na_(2)CO_(3)`
`NaOH`
`NaHCO_(3)`
`NH_(3)`

SOLUTION :The given equations are involved in solvay process.
`UNDERSET((P))(2NH_(3))+H_(2)O+CO_(2) to underset((Q))((NH_(4))_(2)CO_(3)) overset(H_(2)O+CO_(2))to underset((R))(2NH_(40HCO_(3)) overset(NaCl)to underset((S))(NaHCO_(3))+NH_(4)Cl`
28.

In the given compound the order of case with which hydrogen atom can be abstracted from carbon I to VI is :

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I gt VI gt IV = V gt I gt III
II gt I gt VI gt III gt IV =V
II gt I gt III gt VI gt IV = V
IV gt II gt I gt III gt IV = V

Answer :B
29.

In the Gattermann reaction of preparation of chlorobenzene from benzene, the catalyst used is …………….. .

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SOLUTION :`Cu//HCl`
30.

In the Friedel-Crafts acylation, the attacking species is

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`AlCl_3`
`CH_3COCl`
`CL^+`
`CH_3CO^+`

ANSWER :D
31.

In the free radical chlorination of methane, the chain initiating step involves the formation of

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CHLORINE RADICAL
HYDROGEN chloride
Methyl radical
CHLOROMETHYL radical

Answer :A
32.

In the formation rection of NH_(3)from N_(2)and H_(2) 140 g of N_(2) and 40 g H_(2)were mixed. Select the option which is/are incorrect?

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Maximum MASS of `NH_(3)` which can be formed is 180 gm
If % yield of reaction is 80%consumed will be 32 gm.
Some `N_(2)(g)` will be left after the reaction.
If `NH_(3)` formed is 85 gm then % yield will be 50%

Answer :A::B::C
33.

In the formation of SF_(6) molecule, the sulphur atom is in

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1 ST EXCITED STATE
second excited state
third excited state
fourth excited state

ANSWER :B
34.

In the formation of N_2^+, the electron is lost from :

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`SIGMA`-ORBITAL
`PI`-orbital
`sigma^(**)`-orbital
`pi^(**)`-orbital

Answer :A
35.

In the formation of homo diatomic neutral molecule, if 'N' atomic orbitals combine, then the total number of bonding molecular orbitals formaed is

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2N
N
`N//2`
`N//4`

ANSWER :C
36.

In the formation of ethylene molecule , the carbon atom makes use of ___________ hybridisation .

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`sp`
`sp^(2)`
`sp^(3)`
`dsp^(2)`

ANSWER :B
37.

In the formation of covalent bond

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transfer of electrons take PLACE
electrons are gained by only ONE atom
with identical spin
EQUALLY SHARED between them

Answer :C
38.

In the formation of B-H-B bridge in diborane, the orbitals involved in overlapping are

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1 s orbital of 'H' atom and one of the each `sp^3`HYBRID orbital of BORON atoms CONTAINING one electron each
orbital of 'H' atom and one of the each vacanthybrid orbital of Boron atoms
ls orbital of 'H' atom and VACANT orbital of one Boron and orbital of another boron containing one electron
1s orbital of 'H' atom and vacant orbital and orbital containing single electron of the same Boron atom

Answer :C
39.

In the formation of Al_(2)O_(3) from Al and O_(2), if 1.5 mole of oxygen is used up, the mass of aluminium that reacted is

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27g
54g
108g
81g

Answer :B
40.

In the formation of a homo diatomic neutral molecule, if N atomic orbitals combine, then the total number of bonding molecular orbital formed is

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2N
N
N/2
N/4

Answer :C
41.

In the following which situation precipitation will be occurs ?

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`Q_(sp)=K_(sp)`
`Q_(sp) gt K_(sp)`
`Q_(sp) LT K_(sp)`
NONE of these

Answer :B
42.

In the following which is not glyceride ?

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Fats
oils
phospholipids
soaps

Solution :soaps are sodium salts of CARBOXYLIC ACID and not glycerides.
43.

In the following which configuration shows halogen's configuration ?

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`[Ne] 2s^(2) 2p^(4)`
`[AR] 3s^(2)3p^(3)`
`[Kr] 4D^(10) 5s^(2) 5p^(5)`
`1s^(1)`

ANSWER :C
44.

In the following the most stable conformation of n-butane is

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ANSWER :B
45.

In thefollowingthe element with thehighestionizationenergy is

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`[Ne] 3 s^(2) 3p^(1)`
`[Ne]3 s^(2)3p^(3)`
`[Ne] 3s^(2) 3p^(2)`
`[Ne] 3s^(2)3p^(4)`

SOLUTION :DUE togreaterstabilityof HALF- filled3p- orbitals the element with configuration( b)has thehighestionizationenthalpy.
Due tohighesteffectivenuclearcharge , it has thefirstionizationenthalpy.
Due tohighesteffectivenuclearcharge , it hasthefirstionizationenthalpy.
46.

In the following table, which of the optionsare correct ?

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ANSWER :a,C,d
47.

In the following system at equilibrium, N_(2)+3H_(2)hArr2NH_(3), the reaction mixture contains 0.005 mol of N_(2), 0.012 mol of H_(2) and 0.002 mol of NH_(3) in a 2 litre vessel. Calculate K_(c).

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Solution :Volume of the vessel is 2 LITRE
`[NH_(3)]=0.002/2=0.001"MOL"L^(-1),[N_(2)]=0.005/2=0.0025"mol"L^(-1)`
`[H_(2)]=0.012/2=0.006"mol"L^(-1)`
`K_(c)=([NH_(3)]^(2))/([N_(2)][H_(2)]^(3))=((0.001)^(2))/((0.0025)(0.006)^(3))=1.852xx10^(3)`.
48.

In the following structures

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Structure II is a meso compound
Structure I & II are DIASTEROMERS
Structure III & IV are diasteromers
STRUCTURES I & IV are enantiomers

Answer :A::B::C::D
49.

In the following statements : (A) Ideal gases are liquefied only at very low temperature (B) Ideal gases cannot be liquefied (C) Ideal gas behaviour is observed by real gases at low pressure (D) Idealgases do not exist The correct statements are :

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A, B, C and D
A, B and C
B, C and D
C and D

Answer :C
50.

In the following six electronicconfiguration (remaining inner orbital are completely flled). Mark the correct optio(s).

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Order of spin MULTIPLICITY : `C-IIgtC-I=C-IIIgtC-IV`
Stabiltiy order : `C-IIgtC-I & C-IVgtC-III`
If `C-V` represents element A then `A^(2+)` acts as diamagnetic.
`C-VI` violates all the THREE ruls of electron configuration

Solution :N//A