Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

In the following sets of resonating structure, lable the major and minor contributors towards resonance hybrid. (P)underset("(I)")(CH_(3)-overset(Theta)CH-C-=N)harrunderset("(II)")(CH_(3)CH=C=overset(..)N:^(Theta))"(Q)"underset("(I)")(CH_(3)-overset(Theta)CH-CH=CH-NO)harrunderset("(II)")(CH_(3)-CH=CH-CH=overset(o+)underset(O^(Theta))underset(|)N-O^(Theta)) (R)underset("(I)")(CH_(3)-CH_(2)-overset(o+)underset(""NH_(2))underset(|)(C)-NH_(2))harrunderset("(II)")(CH_(3)-CH_(2)-underset(""NH_(2))underset(|)(C)=overset(o+)NH_(2))"(S)"underset("(I)")(CH_(3)-overset(O)overset(||)C-overset(Theta)CH-overset(O)overset(||)C-CH_(3))harrunderset("(II)")(CH_(3)-overset(O^(Theta))overset(|)C=CH-overset(O)overset(||)C-CH_(3)

Answer»

<P>

ANSWER :`{:("(P)I - minorII - MAJOR(Q)I - minorII - major"),("(R)I - minorII - major(S)I - minorII - major"):}`
2.

In the following sets of resonating structure, lable the major contributors towards resonance hybrid.

Answer»

II, II, I, II
II, II, II, I
II, II, II, II
I, I, II, I

Answer :C
3.

In the following sequence of reactions, what is D.

Answer»

PRIMARY amine
an amide
phenyl isocyanate
a CHAIN LENGTHENED hydrocarbon

Solution :
4.

In the following sequence of reactions the products A to G are formed: (i). 2CH_(4)(g)underset(1773K)overset(Delta)toA(g)+B(g) (ii). 4 moles of Aunderset(Ni(CN)_(4)+THF)overset(Delta)tooverset(O_(3)//"oxidation")toD only (iii). Aunderset(C_(2)H_(3)I)overset("1 mole of "NaNH_(2))toEunderset("Red hot tube")overset(3" mole of E")toFoverset(O_(3)//"reductive")toG only Q. Compound G is

Answer»

2-oxobutanal
2-oxobutanoic acid
methyl glyoxal
2-oxopropanoic acid

Answer :A
5.

In the following sequence of reactions the products A to G are formed: (i). 2CH_(4)(g)underset(1773K)overset(Delta)toA(g)+B(g) (ii). 4 moles of Aunderset(Ni(CN)_(4)+THF)overset(Delta)tooverset(O_(3)//"oxidation")toD only (iii). Aunderset(C_(2)H_(3)I)overset("1 mole of "NaNH_(2))toEunderset("Red hot tube")overset(3" mole of E")toFoverset(O_(3)//"reductive")toG only Q. Compound C is:

Answer»

benzene
Mesitylene
Cycloocta-1,3,5j-triene
Cycloocta-1,3,5,7-tetraene

Answer :D
6.

In the following sequence of reactions : "Toluene" overset(KMnO_(4))rarr A overset(SOCl_(2))rarr B underset(BaSO_(4))overset(H_(2)//Pd)rarr C the product C is :

Answer»

`C_(5)H_(5)COOH`
`C_(6)H_(5)CH_(3)`
`C_(6)H_(5)CH_(2)OH`
`C_(6)H_(5)CHO`

Answer :D
7.

In the following sequence of reactions, the amountof D (in g) formed from 72 g of Mg is……….. (The yield (%) corresponding to the product in each step is given in the parenthesis) underset(72g)Mgunderset("Strong heating")overset(N_(2),"excess")tounderset(100%)Aoverset(H_(2)O)tounderset((90%))Boverset("conc."HNO_(3))tounderset((80%))Coverset("Heat")tounderset((90%))D

Answer»


Solution :The complete sequence of reactions is :
`underset(("3moles"))underset(72g)(Mg)underset("STRONG heating")overset(N_(2),"excess")tounderset(A(100%))(Mg_(3)N_(2))underset(-3Mg(OH)_(2))overset(H_(2)O)to`
`underset(B(90%))(2NH_(3))overset("Conc".HNO_(3))tounderset(C(80%))(2NH_(4)NO_(3))overset(Delta)tounderset(+2H_(2)O)underset("2 moles")underset(2xx44g)(2N_(2)O)`
`:'` Mol.mass of `N_(2)O=44` amu
Now, 72 g of Mg give `N_(2)O=2xx44g`
Amount of D (in g)
`=2xx44xx(100)/(100)xx(90)/(100)xx(80)/(100)xx(90)/(100)`
`=57.024g`
`=57.02 g`
8.

In the following sequence of reactions, the alkene affords the compound 'B' CH_(3)CH=CHCH_(3) overset(O_(3))rarrA underset(Zn)overset(H_(2)O)rarr B, The compound B is :

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`CH_(3)COCH_(3)`
`CH_(3)CH_(2)COCH_(3)`
`CH_(3)CHO`
`CH_(3)CH_(2)HO`

Answer :C
9.

In the following sequence of reactions, the alkene affords the compound 'B'CH_3CH - CHCH_3 overset(O_3)(to) A underset(Zn) overset(H_2O)(to)Bthe compound B is

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`CH_3CH_2CHO`
`CH_3COCH_3`
`CH_3CH_2COCH_3`
`CH_3CHO`

ANSWER :D
10.

In the following sequence of reactions products (A) to (H) are formed. Q. Compound G is

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ANSWER :A
11.

In the following sequence of reactions products (A) to (H) are formed. Q. Compound F is

Answer»

`C_(2)H_(6)`
`CH_(3)-C-=CH`

ANSWER :D
12.

In the following sequence of reactions, products (A) to (H) are formed: Compound (H) is:

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SOLUTION :
COMPOUND (H), ANSWER is (a).
13.

In the following sequence of reactions, products (A) to (H) are formed: Compound (G) is:

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SOLUTION :
COMPOUND (G), ANSWER is (a).
14.

In the following sequence of reactions, products (A) to (H) are formed: Compound (F) is:

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SOLUTION :
COMPOUND (F), ANSWER is (C).
15.

In the following sequence of reactions, products (A) to (H) are formed: Compound (D) is:

Answer»




SOLUTION :
COMPOUND (D), ANSWER is (B).
16.

In the following sequence of reactions, products (A) to (H) are formed: Compound (C) is:

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SOLUTION :
COMPOUND (C), ANSWER is (B).
17.

In the following sequence of reactions, products (A) to (H) are formed: Compound (B) is:

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SOLUTION :
COMPOUND (B), ANSWER is (b).
18.

In the following sequence of reactions, identify the compounds (A), (B), (C) and (D) Na_(2)CO_(3)overset(SO_(2))rarr(A)overset(Na_(2)CO_(3))rarr(B)underset("Heat")overset("S")rarr(C)overset(AgBO_(3))rarr(D)

Answer»

`Na_(2)SO_(3), NaHSO_(3), Na_(2)S, Ag_(2)S`
`NaHSO_(3), Na_(2)SO_(3), Na_(2)S_(2)O_(3), Ag_(2)S`
`NaHSO_(3),Na_(2)SO_(4) ,Na_(2)S,Ag_(2)O`
`Na_(2)SO_(3),Na_(2)SO_(4) ,Na_(2)S_(2)O_(3),Ag`

Solution :`Na_(2)CO_(3)+2SO_(2)+H_(2)Orarr2NaHSO_(3)+CO_(2)`
`2Na_(2)SOO_(3)+Soverset(triangle)rarr2Na_(2)S_(2)O_(3)OVERSET(AgNO_(3))RARrAg_(2)+H_(2)SO_(4)`
19.

In the following sequence of reaction the compound A is Aoverset(HBr)toBoverset(alc" "KOH)toCoverset(O_(3),Zn//H_(2)O)toCH_(3)CHO+HCHO

Answer»

ETHYLENE chlorohydrin
Acetic acid
Propene
1-Butene

Answer :C
20.

In the following sequence of reaction the compound A is A overset(HBr)rarrBoverset("alc. KOH")rarr Coverset(O_(3).Zn//H_(2)O)rarrCH_(3)CHO+HCHO

Answer»

Ethylene
Acetic acid
Propene
1 - Butene

Solution :`CH_(3)-CH=CH_(2)OVERSET(O_(3),Zn//H_(2)O)RARR`
`CH_(3)-CHO+HCHO`
21.

In the following sequence of reaction CH_(3)CH_(2)OHoverset(P+I_(2))rarrA underset("ether")overset(Mg)rarrB overset(HCHO)rarrC overset(H_(2)O)rarrD The compound D is

Answer»

propanol
butanal
n-butyl alcohol
n-propyl alcohol

Answer :D
22.

In the following sequence of reaction , CH_3CH_2Br overset(KOH(alc))to X overset(Br_2)to Y overset(KOH(alc))to Z , Z is

Answer»

`CH_2 = CH_2`
`CH_2BrCH_2Br`
`CH-=CH`
`CH_3CH_3 `

SOLUTION :`CH_3CH_2 CHCl_2 + 2NaNH_2 UNDERSET(196K)OVERSET(LIQ. NH_3)to CH_3C -= CH + 2NaCl + 2NH_3`
23.

In the following reactions, ZnO is respectively acting as a/an (i) ZnO + Na_(2)O rarr Na_(2) ZnO_(2) (ii) NzO + CO_(2) rarr ZnCO_(3)

Answer»

Acid and acid
Acid and base
Base and acid
Base and base

Solution :In (i) , NZO acts as an acidic oxide because `Na_(2)O` is a BASIC oxide
In (ii), ZNO acts asa basic oxide because `CO_(2)` is an acidic oxide
Thus, ZnO is an amphoteric oxide.
24.

In the following reactions, ZnO is respectively acting as a/an …… (a)ZnO+Na_2O to Na_2ZnO_2 (b)ZnO+CO_2 to ZnCO_3

Answer»

base and ACID
base and base
acid and base
acid and base

SOLUTION :(1)`underset"ACIDIC OXIDE"(ZnO)+ underset"BASIC Oxide"(Na_2O) to Na_2ZnO_2`
(2)`underset"Basic Oxide"(ZnO)+ underset"Acidic Oxide"(CO_2) to ZnCO_3`
25.

In the following reactions, ZnO is respectively acting as a/an..... (a) ZnO + Na_(2)O to Na_(2)ZnO_(2) (b) ZnO + CO_(2) to ZnCO_(3)

Answer»

base and acid
base and base
acid and base
acid and base

SOLUTION :acid and base
`{:((1)ZnO +Na_(2)O,toNa_(2)ZnO_(2)),("AcidicBasic",),("OxideOxide",):}`
`{:((2)ZnO + CO_(2),to ZnCO_(3)),("BasicAcidic ",),("OxideOxide",):}`
26.

In the following reactions : Compound X is

Answer»




ANSWER :C
27.

In the following reactions, Aoverset("HBr,dark")underset("in the absence of peroxide")rarrunderset(("Major product"))(A)+underset(("Minor products" ))(B) the major prducts (A) and (C) are respecitvely.

Answer»




Solution :
In this case dehydration is governed by Saytzeff's rule according to which hydrogen is preferentially eliminated from the carbon atom with fewer number of hydrogen atoms, `i.e.,` POOR BECOMES POORER. Thus, `2-`methyl butane `-2` is the major product.

This reaction is governed by Maarkovnikov's rule according to which when an unsymmetrical reagent, `e.g., HBr` adds to an unsymmetrical alkene, then the negative part of the reagent is ADDED to that carbon atom of the double BOND which bears the least number of hydrogen atom. Thus, in the above case `2-` methyl `2-` bromo butane will be the major product.
28.

In the following reaction, X is

Answer»




SOLUTION :
29.

In the following reactions which is deuterolysis I) AlCl_3 + 3D_2O to Al(OD)_3 + 3DCl II) CaC_2 + 2D_2O to Ca(OD)_2 + C_2D_2 III) Mg_3P_2 + 6D_2O to 3Mg(OD)_2 + 2PD_3

Answer»

I and II only
II and III only
I and III only
I, II and III

Solution :DISSOLUTION of SALTS in HEAVY water
30.

In the following reaction, what is X? C_(2)H_(2)underset(HgSO_(4),H_(2)SO_(4))overset(H_(2)O,60^(@)C)rarrX iffCH_(3)CHO

Answer»

`CH_(3)CH_(2)OH`
`CH_(3)-O-CH_(3)`
`CH_(3)CH_(2)CHO`
`H_(2)C=CHOH`

ANSWER :D
31.

In the following reaction using isotopic .^(18)O in H_(2)O_(2), 2MnO_(4)^(-)+3H_(2)O_(2)^(18)rarr 2MnO_(2)+3O_(2)+2H_(2)O+2OH^(-) isotopic oxygen goes,

Answer»

with `O_(2)`
with `MnO_(2)`
with `OH^(-)`
ONE with `O_(2)` and one with `MnO_(2)`

ANSWER :A
32.

In the Following reaction using isotope ""^(18)O in H_(2)O_(2). 2MnO_(4)^(-) + 3H_(2)O_(2)^(18) to 2MnO_(2) + 3O_(2) + 2H_(2)O + 2OH^(-) Isotopic oxygen goes :

Answer»

both in `O_(2)`
both in `MnO_(2)`
both in `OH^(-)`
One in `O_(2)` and one in `MnO_(2)`

Solution :`H_(2)""^(18)O_(2) (aq) + 2OH^(-) (aq) to 2H_(2)O (l) + ""^(18)O_(2) (G) + 2e^(-)`
So, all the `""^(18)O` LABEL appers in `""_(18)O_(2)`
33.

In the following reaction, the structure of the major product 'X' is :

Answer»




ANSWER :B
34.

In the following reaction, the products formed is(are)

Answer»

<P>P (MAJOR)
Q (MINOR)
R (minor)
S (major)

Solution :N//A
35.

In the following reaction , the major product is :

Answer»




ANSWER :D
36.

In the following reaction the correct order of percentage of products X, Y and Z is

Answer»

X gt Y gt Z
Z gt Y gt X
Z gt X gt Y
Y gt Z gt X

Answer :C
37.

In the following reaction sequence, the correctstracture ofX, Y and Z are :H-C-=C-COOHoverset(HgSO_(4)//H_(2)SO_(4)//H_(2)O)underset((1))to (X) overset("Heating")underset((2))to(Y) overset(I_(2)//NaOH)to (Z)+CHI_(3)

Answer»


`{:(H_(2)=CH-COOH" ",CH_(3)-underset(OH)underset(|)(CH)-COOH"",underset(COONa)underset(|)(COONa)):}`
`{:(CH_(3)=underset(O)underset(||)(C)-COOH"", CH_(3)=CH-O" ", HCOONa):}`
`{:(O-CH-CH_(2)-COOH" ",CH_(3)-CH=O" ",HCOONa):}`

SOLUTION :`X=H-overset(O)overset(||)(C)-CH_(2)-overset(O)overset(||)(C)-OH `,Y=H-overset(O)overset(||)(C)-CH_(3)Z=HCOONa`
(`beta-`keto carbozylic acid under GO DECARBOXYLATION on HEATING Followed by Iodoform reaction)
38.

In the following reaction sequence , product I,J and L are formed , K represents a reagent. The total number of alkenes possible by dehydrobromination of 3-bromo-3-cyclopentylhexane using alcoholic KOH is

Answer»
39.

In the following reaction sequence, the amount of D (in g) formed formed from 10 moles of acetic acid is ….. (The yield (%) corresponding to the product in each step is given in the parenthesis) CH_3COOH overset"NaOH"to underset"90%""A"underset"630 K"overset"Soda-lime"tounderset"70%""B"overset(Cl_2,hv)tounderset"80%""C"overset"Na,dry ether"tounderset"70%""D"

Answer»


Solution :The complete sequence of REACTION is :
`underset"(2 MOLES)"underset"Acetic acid"(CH_3COOH) underset(-H_2O)overset"NaOH"to underset("Sod. acetate (A) 90%")(CH_3COONA) underset"630 K"overset"Soda-lime"to underset"Methane (B) (70%)"(CH_4)underset"Chlorination"overset(Cl_2, hv)to underset"Methyl chloride (C )80%" (CH_3-Cl) underset"Wurtz reaction"overset"Na, dry ether"to underset"(1 mole)"underset"ETHANE (D)"(CH_3-CH_3)`
From the equations it is evident that
2 moles of acetic acid YIELD ethane = 1 mole
`therefore` 10 moles of acetic acid will yield ethane =`10/2` moles
Yield of D (in moles ) =`10/2xx90/100xx70/100xx80/100xx70/100=1.764`
Mol. mass of ethane =30
`therefore` Yield of D (in g )= 1.764 x 30 = 52.92
40.

In the following reaction sequence , product I,J and L are formed , K represents a reagent. The structure of the product I is

Answer»




ANSWER :D
41.

In the following reaction, product P is R - overset(O)overset(||)(C) - Cl underset(Pd - BaSO_(4))overset(H_(2))rarr P

Answer»

`R CH_(2)OH`
`R COOH`
`R CHO`
`R CH_(3)`

Solution :`RCOCl underset(Pd - BaSO_(4))overset(H_(2))RARR underset((P))(RCHO) + HCL`
42.

In the following reaction overset(ɵ)(O)H+S_(2)O_(3)^(2-)+Br_(2)toSO_(4)^(2-)+Br^(ɵ) Starting with 0.15 " mol of "Br^(2) 0.01 " mol of "S_(2)O_(3)^(2-) and 0.4 " mol of "overset(ɵ)(O)H ions. How many moles of overset(ɵ)(O)H ions are left in the solution after the reaction is complete.

Answer»

Solution :BALANCE the equation in basic medium
`10H+S_(2)O_(3)^(2-)to2SO_(4)^(2-)+5H_(2)O+8e^(-)`
`underline(2e^(-)+Br_(2)to2Br^(ɵ)]xx4)`
`underline(4Br_(2)+S_(2)O_(3)^(2-)+10overset(ɵ)(O)Hto2SO_(4)^(2-)+8Br^(ɵ)+5H_(2)O)`
`{:[(mol es),(befo re),(REACTION)](0.15)(0.01)(0.4)(0)(0)(0)`
`{:[(mol es),(REACTED),(and),(fo rmed)]:}(0.01xx4)(0.01)(0.01xx10)(0.01xx2)(0.01xx8)(0.01xx5)`
`{:[(mol es),(l eft)]:}[0.15-0.04]0(0.4-0.1)(0.02)(0.08)(0.05)(=0.11)(=0.3)`
So, molar ratio of combination is:
`Br_(2):S_(2)O_(3)^(2-):overset(ɵ)(O)H::4:1:10`
`[overset(ɵ)(O)H]` LEFT after reaction `=0.3` mol
43.

In the following reactionNaOH+SrarrA+Na_(2)S+H_(2)O, A

Answer»

`Na_(2)SO_(4)`
`Na_(2)SO_(3)`
`Na_(2)S`
`Na_(2)S_(2)O_(3)`.

SOLUTION :`4S+6NaOH rarrNa_(2)S_(2)O_(3)+2Na_(2)S+3H_(2)`
44.

In the following reaction H_(3)C-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH=CH_(2) overset(H_(2)O //H^(o+))rarr underset(("Major"),("product"))(A)underset(("Major"),("product"))(B) The major product is

Answer»

`CH_(3)-underset(OH)underset(|)overset(CH_(3))overset(|)(C)-underset(CH_(3))underset(|)(CH)-CH_(3)`
`underset(OH)underset(|)(CH_(2))-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH_(2)-CH_(3)`
`H_(3)C-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-underset(OH)underset(|)(CH)-CH_(3)`
`H_(3)C-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH_(2)-underset(OH)underset(|)(CH_(2))`

Solution :
45.

MnO_(4)^(-)+8H^(+)+n e^(-)rarrMn^(2+)+4H_(2)O The value of n is

Answer»


SOLUTION :Total charge of L.H.S = Total change on R.H.S.
`(-1)+8+(-n)=+2 " or"n = 5`
46.

In the reaction: Cr_(2)O_(7)^(2-) + 14H^(o+) + 6I^(Ө) rarr2Cr^(3+) + 3H_(2)O + 3I_(2) Which element is reduced?

Answer»

Cr
H
O
I

Answer :A
47.

In the following reaction CH_(3)COOH + X overset("conc." H_(2)SO_(4))rarr Y + CO_(2) + N_(2) X and Y are respectively

Answer»

`NH_(3) " and " CH_(3)CONH_(2)`
`NH_(3) " and " CH_(3)NH_(2)`
`HN_(3)" and " CH_(3)CONH_(2)`
`HN_(3) " and " CH_(3)NH_(2)`

Solution :`CH_(3)COOH + HN_(3) overset("conc" H_(2)SO_(4))rarr`
`underset(("Schmidth reaction"))(CH_(3)NH_(2) + CO_(2) + N_(2))`
48.

In the following reaction : C_2H_2 underset(HgSO_4//H_2SO_4)overset(H_2O)to X hArr CH_3CHO What is X ?

Answer»

`CH_3CH_2OH`
`CH_3-O-CH_3`
`CH_3CH_2CHO`
`CH_2=CHOH`

Solution :`underset"ACETYLENE"(HC-=CH)underset(HgSO_4 // H_2SO_4)overset(H_2O)to underset"VINYL ALCOHOL (X)"(CH_2=CHOH) hArr underset"Acetaldehyde"(CH_3CHO)`
49.

In the following reaction C_(2)H_(5)OC_(2)H_(5)+4H overset("Red P+HI")rarr 2X+H_(2)O, X is

Answer»

Ethane
Ethylene
Butane
Propane

Answer :A
50.

In the following reaction As_(2)S_(3)+NO_(3)^(ɵ)+H_(2)OtoAsO_(4)^(3-)+SO_(4)^(2-)+NO+H^(o+) The number of electrons involved in the oxidation reaction is

Answer»

22
24
26
28

Solution :`underset(2x=6)OVERSET(+3)(As_(2))toundersetunderset(2x=10)(2x-16=-6)(2AsO_(4)^(3-))+4e^(-)`
`UNDERLINE(underset(3x=-6)(S_(3)^(2-)toundersetunderset(3x=18)(3x-24=-6)(3SO_(4)^(2-)+23e^(-)))`
`underline(As_(2)S_(3)toAsO_(4)^(3-)+3SO_(4)^(2-)+28e^(-))`