Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Indicate the type of hybridization of each carbon atom in the following molecules: (i) overset(1)(C)H_(3)-overset(2)(C)H=overset(3)(C)H-overset(4)(C)H_(3) (ii) H-overset(1)(C)-=overset(2)(C)-overset(3)(C)-=overset(4)(C)-H (iii) overset(1)(C)H_(3)-overset(2)(C)-=overset(3)(C)-overset(4)(C)H_(3) (iv) overset(1)(CH_(3) (v) overset(1)(C)H_(3)-overset(2)(C)-=N (vi) H-overset(O)overset(1||)(C)-NH_(2) (vii) overset(1)(C)H_(3)-overset(O)overset(2||)(C)-overset(3)(C)H_(3) (ix) H_(2)C=C=O (x) C(CN)_(4) (xi) CH_(3)overset(+)(CH_(2)) (xii) CH_(3)overset(-)(CH_(2)) (xiii) CH_(2)overset(•)(CH_(2))

Answer»


Answer :`{:((i)C_(1)=sp^(3),C_(2)=sp^(2),C_(3)=sp^(2),C_(4)=sp^(3)),((II)C_(1)=sp,C_(2)=sp,C_(3)=sp,C_(4)=sp),((iii)C_(1)=sp^(3),C_(2)=sp,C_(3)=sp,C_(4)=sp^(3)):}`
(iv) All carbon atoms are `sp^(3)`-HYBRIDIZED.
(v) `C_(1)=sp^(3), C_(2)=sp`
(vi) `C_(1) = sp^(2)`
(vii) `C_(1) = sp^(3), C_(2)= sp^(2), C_(3) = sp^(2), C_(4)= sp`
(viii) `C_(1) = sp^(3), C_(2)=sp^(2), C_(3) = sp^(3)`
(ix) `sp^(2), sp (x) sp, sp^(3)`
(xi) `sp^(3), sp^(2) (xii) sp^(3), sp^(3)`
(xiii) `sp^(3), sp^(3)`
Discussion
2.

Indicate the type of bonds present in NH_(4)NO_(5) and state the mode of hybridisation of two N atom in it .

Answer»

Solution :
`NH_(4)^(+)` ion contains COVALENT and dative bonds . (It is formed by donation of lone pair of electrons on N in
`NH_(3)` to `H^(+)` ion). `NO_(3)^(-)` ion also contains covalent and dative bonds. Bonds between `NH_(4)^(+) and NO_(3)^(-)` ions
is IONIC.
N of `NH_(4)^(+)` ion is `sp^(3)` hybridised and is tetrehedral., N of ` NO_(3)^(-)` ion is `sp^(2)` hybridised and is PLANAR.
Discussion
3.

Indicate the sigma and pi bonds in the following molecules: (i) C_(6)H_(6) (ii) C_(6)H_(12) (iii) CH_(2)Cl_(2) (iv) CH_(2) = C = CH_(2) (v) CH_(3) NO_(2) (vi) HCONH CH_(3)

Answer»

Solution :(i) `C_(6)H_(6)`:

In `C- C sigma` bond
In `C - H sigma` bond
In `3C = C pi` bond
(ii) `C_(6)H_(12)`:

In `12C- H sigma` bond
In `6C- C sigma` bond
zero `pi` bond
(iii) `CH_(2) Cl_(2), H underset(sigma)(-) underset(underset(Cl)(|sigma))overset(overset(H)(|sigma))( C)overset(sigma)(-) Cl`
In `2 C - H sigma` bond
In `2C - Cl sigma` bond
TOTAL `4 sigma` bond
(iv) `CH_(2) = C = CH_(2)`:

In `4C - H sigma` bond
In `2C - C sigma` bond
In `2C = C pi` bond
(v) `CH_(3)NO_(2)`:

In `3C - H sigma` bond
In `2N - O sigma` bond
In `1N = O pi` bond
`HCONHCH_(3)`: In `4C - H sigma` bond and In `N - H sigma` bond
`Hunderset(sigma)- overset(overset(O)(pi||sigma))(C )underset(sigma)- overset(overset(H)(|sigma))(N)underset(sigma)- underset(underset(H)(sigma|))overset(overset(H)(|sigma))(C ) underset(sigma)- H`
In `2C- N sigma` bond
In `1C - O sigma` bond
In `1C = O sigma` bond
In `1C = O pi` bond
Discussion
4.

Indicate the sigma-and-bonds in the following molecules : C_(6)H_(6), C_(6)H_(12), CH_(2)Cl_(2), CH_(2) = C = CH_(2), CH_(3)NO_(2), HCONHCH_(3)

Answer»

SOLUTION :
Discussion
5.

Indicate the sigma" and " pi bonds in the following molecules. C_(6)H_(6), ""CH_(2)Cl_(2), ""CH_(3)NO_(2), ""CH_(2) = C=CH_(2)

Answer»

SOLUTION :
Discussion
6.

Indicate the primary , secondary , tertiary and quanternary carbon atoms in the following : (i)3-Ethyl-2-methylhexane, (ii)2,2,4-Trimethylpentane .

Answer»

Solution :(i)`underset(1^@)CH_3-oversetoversetoverset(1^@)(CH_3)|underset(3^@)CH-underset(3^@)oversetoversetoverset(2^@"" 1^@)(CH_2CH_3)|CH-underset(2^@)CH_2-underset(2^@)CH_2-underset(1^@)CH_3`
(II)`overset(1^@)CH_3-undersetundersetunderset(1^@)(CH_3)|overset(1^@)overset(CH_3)overset|C-underset(2^@)CH_2-underset(3^@)oversetoversetoverset(1^@)(CH_3)|CH-underset(1^@)CH_3`
Discussion
7.

Indicate the oxidizing and reducing agents in the following reaction : 2Cu^(2+)+4I^(-) rarr 2CuI+I_2

Answer»


ANSWER :`Cu^(2+): ` OXIDIZING AGENT , `I^(-)` : REDUCING agent
Discussion
8.

Indicate the organic structure for product expected when 2-methyl propene is heated with acetyl chloride in presence of anhydrous ZnCl_(2)

Answer»

`(CH_(3))_(2) C CL - CH_(2) - COCH_(3)`
`(CH_(3))_(2) CH - CH_(2) CO - CH_(3)`
`CH_(3) - underset(O)underset(||)(C) - OC (CH_(3))_(3)`
`CH_(3) - underset(O)underset(||)(C) - underset(CH_(3))underset(|)(C) = CH_(2)`

Solution :
Discussion
9.

indicate the numberof unpairedelectronsin (a ) p , (b )Si , (c ) Cr(d )fe and(e ) kr .

Answer»

SOLUTION :Theiratomicnumber and electronconfiguratinis asfollows
Discussion
10.

Indicate the number of unpaired electron in (a) P (b) Si (c) Cr (d) Fe, and (e) Kr

Answer»

Solution :(a) `._(15)P = 1s^(2) 2S^(2) 2p^(6) 3s^(2) 3p_(x)^(1) 3p_(y)^(1) 3p_(z)^(1)`. No of unpaired electron = 3
(b) `._(14)Si = 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p_(x)^(1) 3p_(y)^(1) 3p_(y)^(1)`. No of unpaired electrons = 2
(c) `._(24)Cr = 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3d^(5) 4s^(1)`. No of unpaired electron = 6
(d) `._(26) FE = 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 3d^(6) 4s^(2)`. No of unpaired electron = 4 (in 3 d)
(e) `._(36)Kr` = NOBLES gas. All orbitals are filled. Unpaired electrons = 0
Discussion
11.

Which of the following oxides are amphoteric .(1) BeO (2) SnO (3) ZnO (4) Al_2O_3

Answer»

Solution :(1) COVALENT, (2) covalent, (3) ELECTROVALENT, (4) electrovalant, (5) electrovalent, (6) covalent, (7) electrovalent, (8) electrovalent, covalent and co-ordinate covalent, (9) covalent, (10) electrovalent, (11) covalent, (12) electrovalent, covalent and coordinate covalent.
Discussion
12.

Indicate the correct statement(s) from below :

Answer»

`K_(2)S_(2)O_(6)` , when heated with `K_(2)CrO_(4)` and conc. `H_(2)SO_(4)` and in the presence of diethyl ether GIVES a blue colouration.
Presence of iodine in a sample of table salt can be tested by adding a few drops of `H_(2)SO_(4)` ona given amount of table salt FOLLOWED by addition of a few drops of `H_(2)SO_(4)` into the resulting mixture
`H_(2)O_(2)` needs to be mixed with `FeSO_(4)` to exilise henveneto plienol
Polyhydroxy compounds like SORBITOL, mannitolets are used in trace amounts to stabilise `H_(2)O_(2)`

Solution :(1) `K_(2)S_(2)O_(8)` when heated with`K_(2)CrO_(4) and conc.H_(2)SO_(4)` and in the presence of diethyl ether gives a blue colouration
(2) Presence of iodine in a sample of table salt can be tested by adding a few drops of `H_(2)SO_(4)` on a given amount of table salt followed by addition of a few drops of `H_(2)O_(2)` into the resulting mixture
(3) `H_(2)O_(2)` needs to be mixed with `FeSO_(4)` to oxidise benzene to PHENOL
(4) Poly hydroxy compounds like sorbitol, mannitol ets are used in trace amount to stabilise `H_(2)O_(2)`
Discussion
13.

Indicate the correct of acidity (first ionization) in the following dicarboxylicacids :

Answer»

`I gt II gt III gt IV`
`II gt IV gt I gt III`
`III gt I gt IV gt II`
`IV gt II gt I gt III`

ANSWER :C
Discussion
14.

Indicate the conditions under which the ratio of de Broglie wavelengths of an alpha-particle and a proton will be-

Answer»

when the RATIO of their VELOCITIES is 4:1
when the ratio of their velocities is 1:8
when the ratio of their ENERGIES is 128:1
when the ratio of their velocities is 1:16

Answer :B::C
Discussion
15.

Indicate in which of the following processes nitrogen is recuced ?

Answer»

`NH_(4)^(+) rarrN_2`
`NO_(3)^(-) rarrNO`
`NO_(2) rarr NO_(2)^(-)`
`NO_(3) rarrNH_(4)^(+)`

SOLUTION :Decrease in oxidation number is REDUCTION.
a) `overset(-3)(NH_4^(+))rarroverset(0)(N_2)`
b) `overset(+5)(NO_3^(-)) rarroverset(+2)(NO)`
c) `overset(+4)(NO_2)rarroverset(+3)(NO_2^(-))`
`overset(+6)(NO_3)rarroverset(+3)(NH_(4)^(+))`
Discussion
16.

Indiborane:

Answer»

1 bridged HYDROGEN and TWO terminal HYDROGENS are present.
2 bridged hydrogen and four terminal hydrogens are present
3 bridged hydrogens and three terminal hydrogens are present
none of the above.

ANSWER :B
Discussion
17.

IndianSaltpetre is

Answer»

KNO,
`NaNO_(3)`
NACL
`Na_(2)CO`

SOLUTION :`KNO_(3)` is saltpetre
Discussion
18.

Index of unsaturation (H-deficiency ) of C_8 H_(10)is ........ and if it has a six-membered ring , it can be :

Answer»




All CORRECT

SOLUTION :All are correct
Discussion
19.

Indentify the correct order of boiling points of the following compounds underset(I)(CH_(3)CH_(2)CH_(2)OH), underset(II)(CH_(3)CH_(2)CH_(2)CHO), underset(III)(CH_(3)CH_(2)CH_(2)COOH)

Answer»

`I GT II gt III`
`III gt I gt II`
`I gt III gt II`
`III gt II gt I`

SOLUTION :
Discussion
20.

Indentify the incorrect statement from the following :

Answer»

Oxides of NITROGEN in the atmosphere can cause the depletion of OZONE layer.
Ozone absorbs infrared radiation
Depletion of ozone layer is because of its chemical raction with chlorofluroakanes
Ozone absorbs the intense ultraviolet radiation of the sun.

Solution :Ozone does not absorb INFRA radiation at all. It absorbs `UV`radiation coming from sun in the upper atmosphere and ACTS as an unbrella thus protecting human being LIVING on earth.
Discussion
21.

Increasing order of stability among the three main conformations (i.e. , eclipse, anti, gauche ) of 2-fluoroethanol is

Answer»

eclipse, anti, gauche
anti,gauche, eclipse
eclipse, gauche , anti
gauche, eclipse , anti

Solution :Because of intramolecular H-bonding , gauche CONFORMATION of 2-fluoroethanol is more STABLE than anti while ecliped conformation is the least stable. THUS, the increasing ORDER of stability is :

Thus, OPTION (a) is correct.
Discussion
22.

Increasing order of stability among the three main conformation (i.e., eclips, anti,gauche) of enthalpy glycol is

Answer»

ECLIPSE, GAUCHE, ANTI
Gauche,eclipse,anti
Eclipse,anti,gauche
Anti,gauche,eclipse

Answer :C
Discussion
23.

Increasing order of stability (a) CH_(3)CH = CH- CHO, (b) CH_(3) overset(+)(C )H- CH= overset(overset(H)(|))(C )- underset(..)overset(..)(O):^(-) (c ) overset(+)( C)H_(2)- CH= CH- overset(overset(H)(|))(C )= O

Answer»

SOLUTION :(C ) `LT` (B) `lt` (a)
Discussion
24.

Increasing order of stability among the three main conformation (i.e. eclipse, anti, gauche) of ethylene glycol is :

Answer»

ECLIPSE, GAUCHE, ANTI
Gauche, eclipse, anti
Eclipse, anti, gauche
Anti, gauche, eclipse

Solution :Gauche STABLE DUE to H-bond
Discussion
25.

Increasing order of rate of reaction with Conc. HNO_(3)//H_(2)SO_(4) is

Answer»

iiiltiilti
iiltiiilti
iltiiiltii
iltiiltiii

Solution :EDG INCREASE REACTIVITY and EWG decrease reactivity TOWARDS EAS.
Discussion
26.

Increasing order of size of hybrid orbitals is

Answer»

`SP, sp^(2),sp^(3)`
`sp^(3), sp^(2),sp`
`sp^(2) , sp^(3), sp`
`sp^(2), sp,sp^(3)`

ANSWER :A
Discussion
27.

Increasing order of rate of reaction with Br_(2)//AlCl_(3) is

Answer»

iiiltiltiiltiv
ivltiiltiltiii
iiltivltiiilti
ivltiiltiiilti

Solution :EDG increase REACTIVITY and EWG decrease reactivity towards EAS.
Discussion
28.

Increasing order of hydrateformation is

Answer»

I LT II lt III lt IV
IV GT III gt II gt I
II gt IGT III gt IV
Ilt II lt III gt IV

Answer :C
Discussion
29.

Increasing order of electronegativity of elements P, Bi, S and Cl is

Answer»

<P>`P LT Bi lt S lt Cl`
`S lt Bi lt P lt Cl`
`Bi lt P lt S lt Cl`
`Cl lt S lt Bi lt P `

ANSWER :C
Discussion
30.

Increasing order of acidic strength Cl_(3)C COOH lt CH_(3)COOH, CHCl_(2)COOH, CH_(2)ClCOOH

Answer»

Solution :`CH_(3)COOH LT CH_(2)ClCOOH lt CHCl_(2)COOH, lt C Cl_(3)COOH`
Discussion
31.

Increased asthmatic attacks in certain seasons are related to

Answer»

Inhalation of seasonal POLLEN
Eatin of seasonal vegetables
Low TEMPERATURE
Wet and dry environment

Solution :INCREASED asthmatic ATTACKS in CERTAIN persons are related to inhalation of seasonal pollen
Discussion
32.

Increase of pressure favours the forward reaction in the following equilibrium

Answer»

`H_(2(g))+I_(2(g)) harr 2HI_((g))`
`2NO_(2(g)) harr N_2O_(4(g))`
`PCI_(5(g)) harr PCI_(3(g))+CI_(2(g))`
`N_(2(g))+O_(2(g)) harr 2NO_((g))`

Solution :Pressure FAVOURS forward DIRECTION if `Delta NG lt 0`
Discussion
33.

Increase in kinetic energy can overcome intermolecular forces of attraction. How will the viscosity of liquid be affected by the increase in temperature ?

Answer»

Increase
No effect
DECREASE
No REGULAR PATTERN will be followed

Solution :As the temperature increase, the kinetic energy of the molecules of liquid also increases which can overcome the intermolecular forces. Hence, liquid starts flowing.
In other words, as the viscosity of a liquid decreases, there is an increase in temperature. It has been found that the decrease is about 2% per DEGREE RISE in temperature.
Discussion
34.

Increase in enthalpy of the surroundings is equal to decrease in enthalpy of the system. Will the temperature of system and surroundings be the same when they are in thermal equilibrium ?

Answer»

Solution :Yes, the temperature of SYSTEM and surroundings are same when they are in thermal equilibrium.
Thermal equilibrium is defined as when two physical systems are BROUGHT into a connection that does not allow transfer of MATTER between them, and does not allow transfer of energy between them, such a connection is said to permit transfer of energy as HEAT, and is called diathermal.
If a diathermal connection is made between two physical systems and the making of the connection is FOLLOWED by no change of state of either, then the two systems are said to be in relation of thermal equilibrium, It obeys zeroth law of thermodynamics.
Discussion
35.

Increase in enthalpy of the surroundings is equal to decreasein enthalpy of the system. Will the temperature of system and surroundings be the same when they are in thermal equilibrium ?

Answer»

SOLUTION :Yes.When SYSTEM and surroundingsare in THERMAL EQUILIBRIUM , their TEMPERATURES are same.
Discussion
36.

Increase in concentration of pollutant by the process of food chains is called

Answer»

EUTROPHICATION
BIOAMPLIFICATION
DEFLUORIDATION
BIOLOGICAL oxidation

Solution :Bioamplification
Discussion
37.

Increase in average temperature of earth may increases the possibilities of disease like ......

Answer»

asthma
YELLOW FEVER
weak eyesight
headache

Solution :yellow fever
Discussion
38.

Incorredt relation between given compounds are

Answer»

Both are GEOMETRICAL ISOMERS
Both are ENANTIOMERS
Both are OPTICAL isomers
Both are diastereomers

Solution :N//A
Discussion
39.

Incorret statement about addition of halogen to alkenes

Answer»

It is electrophilic addition
Syn addition of halogen to C = C TAKES place
Three MEMBERED CYCLIC halonium ion is intermediate
VICINAL dihalides are formed.

ANSWER :B
Discussion
40.

Incorrect statement (s) regarding H_(2)O_(2) is s/are

Answer»

`H_(2)O_(2)`has HIGHER boiling point than water
AS physical state of `H_(2)O_(2)` chsanges the bond angles and dihesdreal angles chages
`H_(2)O_(2) ` acts as a reading agent during its bleaching action
`H_(2)O_(3)`is manufactured by eleectrolysis of hot dilute aq SOLUTION of `H_(2)SO_(4)`

Answer :CD
Discussion
41.

Incorrect statement related to an irreversible process is

Answer»

Entropy of the UNIVERSE goes on INCREASING
`GIBBS energy of the system goes on decreasing
Total energy of the universe goes on decreasing
Total energy of the universe remains CONSTANT

Answer :C
Discussion
42.

Incorrect statement regarding waste management is

Answer»

Bio-degradable and non-biodegradable wastes are SEPARATED from garbage waste
Bio-degradable waste is deposited in land-fills and used as manure
Non-biodegradable waste is recycled to convert into useful chemicals
Green FUEL is OBTAINED from RECYCLING of plastic waste which contains LEAD

Solution :Green fuel is obtained from recycling of plastic waste which conatins lead
Discussion
43.

Incorrect statement regarding CO_2is

Answer»

Cardice is the SOLID `CO_(2)`
Dry ice is used as REFRIGERANT 
`CO_(2)` is used in MAKING urea 
`CO_(2)` is insoluble in water. 

Answer :C
Discussion
44.

Incorrect statement is

Answer»

`SO_(2), CO,` Pb and Hg are pollutants
Methyl isocyanate and oil spills from ships are pollutants
SEA WATER is RECEPTOR for CO
Microorganism is sink for DEAD PLANTS and animals

Answer :C
Discussion
45.

Incorrect statement in the following is

Answer»

Dipole - dipole ATTRACTIONS are more, if the molecules have high DIPOLEMOMENT values.
In liquid HBr, dipole - dipole attractions are present.
Dipole - dipole interaction ENERGY between polar molecules as in solids ` prop R^(-3)`
Dipole - dipole interaction energy between rotating molecules ` prop r^6`

ANSWER :D
Discussion
46.

Incorrect statement among the following is

Answer»

To study the reaction MECHANISM TRITIUM is USED
`""_1H^3` is radio active with `t_(1//2)` = 12.26 Y
`""_1H^3`is a b EMITTER and disintegrates to give `""_2He^4`
Both `H_2` and `D_2`can be separated by USING the principle of atomolysis.

Answer :C
Discussion
47.

Incorrect statement among the following is ?

Answer»

In `BF_3` , the BOND order is 1.33
`NO,O_2 ,O_(2)^(+)` and `ClO_2` areparamagneticspecies
` N_2, F_2 and CO` have the same bond order.
Molecular orbital theory is APPLICABLE to diatomic as well as TRIATOMIC molecules.

Answer :C
Discussion
48.

Incorrect statement about Alum

Answer»

In alum each metal ion is surrounded by SIX water molecule.
Aqueous solutions of alums are acidic in nature.
Aqueous solutions of alums shows the PROPERTIES of `M^(+2), M^(+3)` and `SO_(3)^(-2)`.
Alums are not used as STYPTIC agent.

Answer :C::D
Discussion
49.

Inachemical equilibrium,the rate constant for the forward reaction is 2.5 xx 10^2 and the equilibrium constant is 50 . The rate constant for the reverse reaction is …………………… .

Answer»

11.5
5
`2 xx10^2`
`2xx 10^(-3)`

Solution :`K_f = 2.5 XX 10^(2) ,K_C = 50,K_r = ?`
`K_C = K_f/K_r`
`50= (2.5 xx 10^2)/K_r`
`K_r = 5`
Discussion
50.

(i)N_(2(g)) + 3H_(2(g)) hArr 2NH_(3(g)) and (ii) 1/2N_(2(g))+3/2H_(2(g)) hArr NH_(3(g)) their equilibrium constant are respectively K_c(1) and K_c(2) state their relation.

Answer»

SOLUTION :`K_c(1)=(K_c(2))^2` and `(K_c(1))^(1/2)=K_c(2)`
Discussion