Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

On a ship sailing in Indian ocean where the temperture is 26.1^@C, a ballon is filled with 20.18L of air. What will be the volume of the ballon when the ship reaches Pacific ocean, where temperature is 23.4^@C ?

Answer»

Solution :The CHARLES. law is given as,`(V_1)/(V_2) =(T_1)/(T_2)`

The volume of BALLOON at pacific ocean =
` V_2- (V_1 T_2 )/(T_(12)) = (20.18 xx 296 .4)/( 299.1 ) = 20 L`
Discussion
2.

Oleum is mixture of H_(2)SO_(4) and SO_(3) i.e. H_(2)S_(2)O_(7) which is obtained by passing SO_(3) is solution of H_(2)SO_(4).In order to dissolve SO_(3) in oleum, dilution of oleum is done by water in which oleum is converted into pure H_(2)SO as shown below: H_(2)SO_(4)+SO_(3)+H_(2)Oto2H_(2)SO_(4) (pure) When 100 gm oleum is diluted with water then total mass of diluted oleum is known as percentage labelling in oleum. For example: 109% H_(2)SO_(4) labelling of oleum sample means that 109 gm pure H_(2)SO_(4) is obtained on diluting 100 gm oleum with 9 gm H_(2)O which dissolves al free SO_(3) in oleum. If the number of moles of free SO_(3), H_(2)SO_(4), and H_(2)O be x, y and z respectively in 118% H_(2)SO_(4) labelled oleum, the value of (x+y+z) is

Answer»

`2.2`
`3.2`
`3.4`
`4.2`

Solution :118% `H_(2)SO_(3)` labelled oleum
100G oleum + 18G water
`underset("80 g")(SO_(3))+underset("18 g")(H_(2)O)rarrH_(2)SO_(4)`
`18gH_(2)O` COMBINES with `80_(g)SO_(3)`
So, weight of `SO_(3)` in 100g oleum = 80g
`therefore` No. of moles of `SO_(3)=(80)/(80)=1`
No. of moles of `H_(2)SO_(4)=(20)/(98)=0.2`
No. of moles of `H_(2)O=(18)/(18)=1`
Total no. of moles = 2.2
Discussion
3.

Oleum is mixture of H_(2)SO_(4) and SO_(3) i.e. H_(2)S_(2)O_(7) which is obtained by passing SO_(3) is solution of H_(2)SO_(4).In order to dissolve SO_(3) in oleum, dilution of oleum is done by water in which oleum is converted into pure H_(2)SO as shown below: H_(2)SO_(4)+SO_(3)+H_(2)Oto2H_(2)SO_(4) (pure) When 100 gm oleum is diluted with water then total mass of diluted oleum is known as percentage labelling in oleum. For example: 109% H_(2)SO_(4) labelling of oleum sample means that 109 gm pure H_(2)SO_(4) is obtained on diluting 100 gm oleum with 9 gm H_(2)O which dissolves al free SO_(3) in oleum. If 109% H_(2)SO_(4) labelled oleum, the percent of free SO_(3) and H_(2)SO_(4) are

Answer»

`30%,70%`
`40%,60%`
`60%,40%`
`15%,85%`

Solution :109% `H_(2)SO_(4)` LABELLED OLEUM
100g oleum + `9G H_(2)O`
`80g-18gimplies40g-9g`
`therefore 100g` oleum contain `40G SO_(3) and 60g H_(2)SO_(4)`
`%SO_(3)=(40)/(100)xx100=40`
`%H_(2)SO_(4)=(60)/(100)xx100=60`
Discussion
4.

Oil of Bitter almonds is

Answer»

Nitrobenzene
BENZALDEHYDE
Salicylaldehyde
Phenyl ethanal

Solution :Benzaldehyde
Discussion
5.

Oidentify the incrrect statement ?

Answer»

The INTERMEDIATE PRODUCTS obtained during eletrolysis of 50% `H_(2)SO_(4)` are `H_(2)S_(2)O_(8)` and `H_(2)SO_(5)`
Complate hydrolysis of ONE mole of Marshall's ACID gives one mole of `H_(2)O_(2)` and two moles of SULPHURIC acid
`H_(2)S_(4),H_(2)SO_(5)and H_(2)S_(2)O_(8)` all acts as oxidising agents.
During electrolysis of 50% `H_(2)AO_(4),H_(2)O_(2)` is obtained near anode.

Answer :D
Discussion
6.

OHC-(CHOH)_(4)-CH_(2)OHhas a primary alcoholic group at

Answer»

`1^(st)` CARBON
`2^(nd)` carbon
`6^(th)` carbon
`4^(th)` carbon

Answer :C
Discussion
7.

OH^- ions are in acidic solution and H_3O^+ions an in basic solution available is it true ? Explain.

Answer»

Solution :Right there is `OH^-` in ACID solution and `H_3O^+`in base solution ALWAYS present.
because, In acid on `[OH^-]=K_w/([H_3O^+])`
In base solution `[H_3O^+]=K_w/[[OH^-]]`
Discussion
8.

OH group in methyl carbinol is neutral while it is acidic in acetic acid because :

Answer»

methyl carbinol molecules get associated
methyl carbinol is a covalent compound
acetic acid is an ELECTROVALENT compound
in acetic acid OH GROUP is united with ELECTRONEGATIVE carbonyl group

Solution :In methyl carbinol the `+I` effect of `C_(2)H_(5)` decreases the polarity, of OH group while `C = O` group of acetic increases the polarity of `-OH` group
Discussion
9.

Of the two molecules OCS and CS_(2) which one has higher dipole moment value ? Why ?

Answer»

Solution :OCSand `CS_(2)` :

The dipole moment `H_("OCS") = 0.7149 pm 0.0003 " Debye " CS_(2) : S = C = S`
In `CS_(2)`the bond dipole of 2C = S have same values and bond dipoles cancel each ether so dipoles moment of `CS_(2)` is zero .
Among OCS and `CS_(2)` OCS has a HIGHER DIPOLEMOMENT because in OCS oxygen is more ELECTRONEGATIVE that sulphur and C = S and C = O bond in OCS molecules do not cancel each other. On other hand `CS_(2)` due to linear STRUCTURE the bond dipole to two `C = S` bonds cancel each other. On the other hand `CS_(2)` due to linear structure the bond dipoles of two C = S bonds cancel each other and the result and dipole moment value is zero . So OCS has a higher dipole moment than `CS_(2)`.
Discussion
10.

Of the two molecules OCS and CS_(2) which one has higher dipole moment value .Why?

Answer»

Solution :OCS and `CS_(2)`:

The DIPOLE moment `mu_(ocs) = 0. 7149 + 0. 0003` Debye.
`Cs_(2):`S = C = S
In `CS_(2),` the bond dipoles of 2 C = S have same values and bond dipoles cancel each other so dipole moment of `CS_(2)` is zero.
Among OCS and `CS_(2),` OCS has a HIGHER dipole moment because in OCS OXYGEN is more electronegative than sulphur and C =S and C = O bonds in OCS molecules do not cancel each other. On the other HAND `CS_(2)` due to linear structure, the bond dipole of twoC = S bonds cancel each other. On the other hand, `CS_(2)` due to linear structure, the bond dipoles of two C =S bonds cancel each other and the RESULTANT dipole moment value is zero. So OCS has a higher dipole moment than `CS_(2)`.
Discussion
11.

Of the two elements given in each of the following cases, choose the element having a more negative electron gain enthalpy. Explain. N andO

Answer»

Solution :Elements with higher positive value of electron affinity have a more negative value of electron GAIN enthalpy. As NITROGEN has a half filled p-subshell so electron affinity of OXYGEN (O) SHALL be higher.
Discussion
12.

Of the isomeric hexanes , the isomers that give the minimum and number of monochloro derivatives are respectively

Answer»

3-methylpentane and 2,3-dimethylbutane
2,3-dimethylbutane and n-hexane
2,2-dimethylbutane and 2-methylpentane
2,3-dimethylbutane and 2-methylpentane

Solution :`overset"(1)"CH_3-underset(.^(1)CH_3)underset|overset"(2)"CH-overset"(3)"CH_2-overset"(4)"CH_2-overset"(5)"CH_3`
2-Methylpentane has five different types of hydrogens and hence FORMS five MONOCHLORO derivatives. On the other hand , 2,3-dimethylbutane
`underset"(1)"CH_3-underset(._((1))CH_3)underset|overset"(2)"CH-underset"(1)"underset(CH_3)underset|overset"(2)"CH-overset"(1)"CH_3`has TWO different types of hydrogens and hence forms two monochloro derivatives.
Discussion
13.

Of the four oxyacids of chlorine the strongest oxidising agent in dilute aqueous solution is _____

Answer»

`HClO_(4)`
`HClO_(3)`
`HClO_(2)`
HOCl

Solution :`HClO_(4)` is the strongest oxidising agent. The CORRECT order of oxidising POWER is,
`OVERSET(+1)(HClO)ltoverset(+3)(HClO_(2))ltoverset(+5)(HClO_(3))ltoverset(+7)(HClO_(4))`
Discussion
14.

Of the following, which change will shift the reaction towards the productI_(2)(g) hArr 2I(g) Delta H^(@) ""_(f) (298K) = + 150 kJ

Answer»

INCREASE in CONCENTRATION of I
Decrease in concentration of `I_(2)`
Increase in temperature
Increase in TOTAL pressure

Solution :Le-chatelier.s PRINCIPLE
Discussion
15.

Of the following pairs, the one containing examples of metalloid elements in the periodic table is:

Answer»

NA and K
F and CI
Cu and Hg
SI and Ge

SOLUTION :NA
Discussion
16.

Of the following molecules, which have shape similar to carbon dioxide ?

Answer»

`SnCl_(2)`
`NO_(2)`
`C_(2)H_(2)`
All of these

ANSWER :C
Discussion
17.

Of the following molecules, which have shape similar to carbon dioxide?

Answer»

`SnCl_(2)`
`NO_(2)`
`C_(2)H_(2)`
All of these

Solution :`CO_(2)` - Linear
`C_(2)H_(2)` - Linear
Discussion
18.

Of the following compounds, which has the highest boiling point?

Answer»

n-Butyl CHLORIDE
ISOBUTYL chloride
t-Butyl chloride
n-propyl chloride

Solution :n-Butyl chloride
Discussion
19.

Of the following compounds, the most acidic is

Answer»

`As_(2)O_(3)`
`P_(2)O_(3)`
`Sb_(2)O_(3)`
`Bi_(2)O_(3)`

SOLUTION :`P_(2)O_(3)` is most ACIDIC because electrongativity DECREASES. O atoms in `P_(4)O_(10)`.
Discussion
20.

Of the following acids, the one which has the capability to form complex compound and also possesses oxidising and reducing properties is

Answer»

`HNO_(3)`
`HNO_(2)`
HCOOH
HCN

Solution :`HNO_(2)` acts as reducing oxidising and COMPLEXING AGENT.
Discussion
21.

Of the five isomeric hexanes , the isomer which can give two monochlorinated compounds is

Answer»

n-hexane
2,3-dimethylbutane
2,2-dimethylbutane
2-methylpentane

Solution :2,3-Dimethylbutane has only two TYPES of HYDROGENS and hence FORMS only two monochlorinated COMPOUNDS.
Discussion
22.

Of the five isomeric hexanes, the isomer which can give two mono chlorinated compounds is

Answer»

n-Hexane
2,3-Dimethylbutane
2,2-Dimethylbutane
2-Methylpentane

Solution :The NUMBER of monohalogenation products obtained of different TYPES of hydrogen it CONTAINS.
`underset("2, 3-dimethylbutane")(H_(3)C-underset(H)underset(|)OVERSET(CH_(3))overset(|)C-underset(H)underset(|)overset(CH_(3))overset(|)C-CH_(3))`
2, 3-dimethylbutane have TWO types of hydrogen atoms. So, on monochlorination gives only two monochlorinated compounds.
`H_(3)C-overset(CH_(3))overset(|)underset(H)underset(|)C-overset(CH_(3))overset(|)underset(H)underset(|)C-CH_(3)overset(Cl_(2))toH_(3)C-underset(H)underset(|)overset(CH_(3))overset(|)C-underset(H)underset(|)overset(CH_(3))overset(|)C-CH_(3)`
`H_(3)C-overset(CH_(3))overset(|)underset(Cl)underset(|)C-underset(H)underset(|)overset(CH_(3))overset(|)C-CH_(3)`
Discussion
23.

Of all the Group 13 elements, the element with lowest electronegatively is

Answer»

B
Tl
In
Al

Solution :GROUP 13 ELEMENT with LOWEST ELECTRONEGATIVITY is Al.
Discussion
24.

ODS are used in ........

Answer»

REFRIGERATOR
WATER cooler
airconditioner
All of these

Solution :All of these
Discussion
25.

Odd one out the following among elements in the triad.

Answer»

Li,Na ,K<BR>Cl,Br,I
Ca,SR Ba
Fe,Co,Ni

Answer :a
Discussion
26.

Odd electron bond is not present in

Answer»

`NO`
`ClO_2`
`KO_2`
`Cl_2O`

ANSWER :D
Discussion
27.

Octet rule mostly violated in the compounds formed by

Answer»

ALKALI metals
Alkaline EARTH metals
p - BLOCK elements
transition elements

Answer :D
Discussion
28.

Octet rule is mostly violated in the compounds formed by

Answer»

ALKALI METALS
Alkaline EARTH metals
p-block ELEMENTS
Transition elements

ANSWER :D
Discussion
29.

What is producer gas ?

Answer»
Discussion
30.

Octet rule is followed for the centrali atom in the formation of

Answer»

`SF_(6)`
`PF_(5)`
`BeCI_(2)`
`CCI_(4)`

ANSWER :D
Discussion
31.

Octet rule in not followed in

Answer»

`SF_(6)`
`PF_(5)`
`BeCl_(2)`
All the three

Answer :D
Discussion
32.

Octane number is related to

Answer»

Gasoline
Kerosene oil
Diesel oil
Lubricating oil

Answer :A
Discussion
33.

Octahedral shape is due to the hybridisation

Answer»

`SP^(3)d`
`sp^(3)d^(2)`
`sp^(3)`
`sp`

ANSWER :B
Discussion
34.

Octahedral molecule among the following is

Answer»

`SO_(3)`
`CHCI_(3)`
`SF_(6)`
`PCI_(5)`

ANSWER :C
Discussion
35.

____________occurs in large amounts in sea water.

Answer»

NaCl
KCl
Both (a) and (B)
NEITHER a nor b

Answer :C
Discussion
36.

Obtain the relation between equilibrium constant K and K' forward and reverse reaction.

Answer»

Solution :We write reaction of HI synthesis. Its equilibrium is as under.
`H_(2(g)) + I_(2(g)) hArr 2HI_((g))`…(Eq. -i)
For this reaction as PER law of chemical equilibrium `K_c` is as follow.
`K_c="[HI]"^2/([H_2][I_2])=X` ….(Eq.-ii)
At same temperature the reverse reaction-(i) occurs the equilibrium of decomposition of HI reaction is as under.
`2HI_((g)) hArr H_(2(g)) +I_(2(g))`.....(Eq.-iii)
The equilibrium constant `K._c` at same temp. is ,
`K._c=([H_2][I_2])/([HI]^2)=1/X`....(Eq.-iv)
So, `(K_c)(K._c)=([HI]^2)/([H_2][I_2])xx([H_2][I_2])/([HI]^2)=1`
and `K_c=1/(K._c)` ....(RESULT -1)
"Equilibrium constant for the reverse reaction is the inverse of the equilibrium constant for the reaction in the forward direction."
Discussion
37.

Observed the following reaction sequence and choose the correct options.

Answer»

(A) and (B) are diastereomer's of each other.
upon CATALYTIC HYDROGENATION (A) and (B) gives same product.
Product (C) and (D) are Identical
Product (C) and (D) are separated by FRACTIONAL distillation.

Solution :
Discussion
38.

Observe these compound and give answer of following questions. Q. A carbohydrate undergoes the following conversion "D-Lyxose"underset(HCl)overset(NaCN)to'A'overset(H_(2)//Pd-BaSO_(4))to'B'overset(H_(3)O^(o+))to'C' 'C' can be

Answer»

D-Galatose
D-Talose
Both
none of these

Answer :C
Discussion
39.

Observe these compound and give answer of following questions A carbohydrate undergoes the following conversion D-arabinose underset(HCl)overset(NaCN)to'A'overset(H_(2)//Pd-BaSO_(4))to'B'overset(H_(3)O^(o+))'C' 'C' can be

Answer»

D-Glucose
D-mannose
Both
none of these

Solution :
Discussion
40.

Observe the following two reaction of benzene. A) C_6H_6 + CH_3Cl underset(K_1)overset(AlCl_3)to C_6H_5CH_3 B) C_6H_5D + CH_3Cl underset(K_2)overset(AlCl_3)to C_6H_5CH_3 The relation between rate constant of the two reactions will be.

Answer»

`K_1 GT K_2`
`K_2 gt K_1`
`K_1 = K_2`
Not definite

Solution :Electrophilic SUBSTITUTION reactions invovled two STEPS , cleavage of the `C-H or C-D` step (fast step) , which being fast does not effect the RATE of reaction .
Discussion
41.

Observe the following statements regarding purification of bauxite I. During Hall's process, silicon is removed as Si(vapour) II. Bauxite ore contaminated with Fe_(2)O_(3) is purified in Baeyer's process III. During Serpeck's process AIN is formed. The correct answer is

Answer»

I, II and III are CORRECT
Only I and II are correct
Only I and II are correct
Only I and III are correct

ANSWER :D
Discussion
42.

Observe the following statements.Q I. The physical and chemical properties of elements are periodic functions of their electronic confirguration.Q II. Electronegativity of fluorine is less than the electronegativity of chlorine.Q III. Electropositive nature decreases from top to bottom in a group. The correct answer is

Answer»

I, II and III are CORRECT
Only I is correct
Only I and II are correct
Only II and III are correct

ANSWER :B
Discussion
43.

Observe the following statement : (I) Heavy water is harmful for the growth of animals (II) Heavy water reacts with Al_(4)C_(3) and forms deuterated acetylene (III)BaCl_(2).2D_(2)O is an example of interstitial deuterate

Answer»

`1 & 3 `
`1 & 2`
`1,2,& 3`
`2 & 3`

ANSWER :A
Discussion
44.

Observe the following sequence of reactions : Select the correct option regarding the relative basic strength (K_(b)):

Answer»



`CH_(3)-UNDERSET(NH)underset(||)C-NH_(2) gt CH_(3)NH_(2)`

ANSWER :C
Discussion
45.

Observe the following reaction sequence carefully and answer the question that follows. "Boric acid"overset("strong")underset("heat")rarrXoverset(C//Cl_(2))underset(Delta)rarrYoverset(LiAlH_(4))rarrAoverset("excess"NH_(3))underset("low temp")rarrBoverset(200^(@)C)underset(Delta)rarrC overset(NH_(4)Cl)underset("heat")rarrDoverset(NaBH_(4))rarr E overset(3HCl)rarr Z Pick out the incorrect statement from the following with respectto the above paragraph ?

Answer»

Conversion of E to Z is an example of addition reaction
In `"Z"` chlorine atoms are bonded to Boron
Z has PLANAR structure
The REACTIVITY of `"E"` is more than that of Benzene.

Answer :C
Discussion
46.

Observe the following reaction: [Ne(en)_(3)](NO_(3))_(2)+S_(2)O_(3)^(2-)(aq) overset("Slightly")underset("alk.medium")rarr'Y' (darr) violet ppt. Among the following, how many compound decompose the nickel ethylenediamine nitrate reagent with the precipitation of NiS, in the above test. Na_(2)SO_(3),Na_(2)SO_(4),Na_(2)S_(2)O_(3),Na_(2)S_(4)O_(6),H_(2)S, (NH_(4))_(2)S,NaSCN

Answer»


SOLUTION :`H_(2)S,(HN_(4))_(2)S`
Discussion
47.

Observe the following reaction sequence carefully and answer the question that follows. "Boric acid"overset("strong")underset("heat")rarrXoverset(C//Cl_(2))underset(Delta)rarrYoverset(LiAlH_(4))rarrAoverset("excess"NH_(3))underset("low temp")rarrBoverset(200^(@)C)underset(Delta)rarrC overset(NH_(4)Cl)underset("heat")rarrDoverset(NaBH_(4))rarr E overset(3HCl)rarr Z Identify the incorrect statement form the followings about Boric acid

Answer»

Boric ACID crustallizes in a layer structure in which `H_(3)BO_(3)` UNITS are BONDED togethr by Vander Waals forces.
It can't be titrated with `NaOH` by USING Phenolpthalein inducator satisfactorily
`H_(3)BO_(3)` is a weak Lewis acid
It can be titrated with `NaOH` by adding CATECHOL

Answer :B
Discussion
48.

Observe the following reaction sequence carefully and answer the question that follows. "Boric acid"overset("strong")underset("heat")rarrXoverset(C//Cl_(2))underset(Delta)rarrYoverset(LiAlH_(4))rarrAoverset("excess"NH_(3))underset("low temp")rarrBoverset(200^(@)C)underset(Delta)rarrC overset(NH_(4)Cl)underset("heat")rarrDoverset(NaBH_(4))rarr E overset(3HCl)rarr Z Which of the following statement with respect to the paragraph is incorrect?

Answer»

`"X"` on REACTION with metal oxide, GIVES metal metaborates
The compounds C and E are identical
The hybridization of BORON in E and Z are `SP^(2)` and `SP^(3)` respectively
Compound `"A"` on methlation forms hexa methyl derivative

Answer :D
Discussion
49.

Observe the following reaction sequence Calculate molecular mass [W] of product I and report your answer as N, where N=W-:3.

Answer»
Discussion
50.

Observe thefollowing reaction : Ar-C-Hoverset(OH^(-))hArr[X]overset(Ar-overset(O)overset(||)C-H)hArr[Y]+[Z] overset(H^(+)hArrY^(1)+Z^(1)In step -3 if Y transfers H^(-) ion to Z, then Y' andZ' are respectively :

Answer»

`PhCOO^(-)+PhCH_(2)OH`
`PhCOOH+PhCH_(2)O^(-)`
`PhCOO^(-)+PhCH_(2)O^(-)`
`PhCOOH+PhCH_(2)OH`

Solution :Carboxylate ion and alcohol arefinal peoducts.
Discussion