Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Out of benzene, m–dinitrobenzene and toluene which will undergo nitration most easily and why?

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SOLUTION :Toluene. This is because `-CH_3`GROUP is an electron releasing (electron-donating) group and ACTIVATES the ring. On the other HAND, `-NO_2` group is an electron-withdrawing group and DEACTIVATES the ring. This is why toluene undergoes nitration most easily.
2.

Out of benzene, m-dinitrobenzene and toluene which will undergo nitration most easily and why ?

Answer»

Solution :The ease of nitration depends on the presence of electron density on the compound to form nitrates. Nitration reaction are examples of electrophilic substitution reactions where an electron-rich species is attacked by a nitronium ion `(NO_(2)^(-))`. Now, `CH_(3)^(-)` group is electron DONATING and `NO_(2)^(-)` is electron withdrawing.
Therefore, toluene will have maximum electron density among the three COMPOUNDS followed by benzene.
On the other hand, m-Dinitrobenzene will have the LEAST electron density. Hence, it will undergo nitration with difficulty. Hence, the INCREASING order of nitration is as FOLLOWS :
3.

Out of benzene , ethylene and acetylene, the carbon-carbon bond length is longest in _______

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Answer :benzene (139 pm), ETHYLENE (134 pm) , ACETYLENE (120 pm )
4.

Out of benzen m - dinitrobenzene and toluene whichwill undergo nitration most easilyand why

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Solution :`CH_(3)` groupis an electrondonating groupwhile`NO_(2)` groupis electronwithdrawinggroupthereforemaximumdensitywill be therein toluenefollowedby benzeneand it islestin m- dimitrobenzenethereforecaseofnitrationdecreasesint the ORDER
there `GT `benzene `gt m-` dinitrobenzne
5.

Out of a straight chain alkane and a straight chain alkene having the same number of carbon atoms, which has a higher octane number?

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SOLUTION :STRAIGHT CHAIN ALKENE
6.

Our environment consists of .........

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LITHOSPHERE
Hydrosphere
Atmosphere
All of these

Solution :All of these
7.

Ostwald's dilution law is not obeyed by

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`CH_(3)COOH`
`NH_(4)OH`
HCN
KCl

Solution :It is applicable only for weak electrolytes . All the three except KCI are weak electrolytes.
8.

Ostwald dilution law is applicable to

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Strong ELECTROLYTES
Weak electrolytes
Non-electrolytes
All types electrolytes.

SOLUTION :Ostwald.s DILUTION is for weak ELECTROLYTE.
9.

Osmotic pressure (pi)of a solution is given by the relation

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` PI = NRT`
` pi V=nRT`
` pi RT=n`
NONE of these

ANSWER :B
10.

What is meant by osmotic regulation?

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`pi = NRT`
`piV=nRT`
`piRT=N`
NONE of these

Solution :`pi = CRT`
`pi = (n)/(V) RT`
`pi V = nRT`
11.

Osmotic pressure (pi)

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`PI RT = N `
`V = pi n RT`
` pi = NRT`
` pi V = nRT`

12.

Osmotic pressure of the solution can be increased by

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INCREASING the TEMPERATURE of the solution
decreasing the temperature of the solution
increasing the VOLUME of the vessel
diluting the solution

Answer :D
13.

Orthohydrogen and parahydrogen have

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Same electronic spin, PHYSICAL and CHEMICAL properites
Parallel electronic, and nuclear spin with identical physical and chemical PROPERTIES.
Different electronic spin with differences in physical and chemical properties.
Opposite electronic spin, different nuclear spin and with different PHYSCIAL properties.

Answer :D
14.

Orthofluorophenol is more volatile than its meta and para isomers. Why?

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Solution :Intramolecular HYDROGEN bonding is PRESENT in orthofluorophenol, which does not lead to ASSOCIATION of molecules. Hence it is VOLATILE.
Intermolecular hydrogen bonding is present in metal and para isomers, which LEADS to molecular association.
15.

Orthoboric acid on strong heating gives "…………..".

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ANSWER :`B_(2)O_(3)`
16.

Orthoboric acid (H_(3)BO_(3)) and metaboric acid (HBO_(2)) differ in respect of

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BASICITY
STRUCTURE
Melting point
Oxidation

Solution :ORTHOBORIC ACID `(H_3BO_3)` and metaboric acid`(HBO_2)`differ in respect of
Basicity, Structure and Melting point
17.

Orthoboric acid acts as a Lewis acid . Why ?

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Solution :It ACTS as a weak monobasic lewis acid by accepting a hydroxyl ion.
`underset ("BORIC acid ( lewis acid)")(B(OH)_(3))+H^(+) OH^(-) RARR [B(OH)_(4)]^(-)+H^(+)`
18.

Ortho-Nitrophenol is less soluble in water than p- and m- Nitrophenols because

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<P>MELTING point of o-Nitrophenolis lower than
those of m- and p-isomers
o-Nitrophenol is more VOLATILE is steam than
m-and p-isomers .
o-Nitrophenol shown Intermolecular H-
bonding
o-Nitrophenol shows Intermolecular H-bonding

Solution :o-Nitrophenol is less soluble in WATER than p- and
m-nitrphenols because o-nitrphenol shows
intramolecular HYDROGEN bonding .
19.

ortho-Nitrophenol is less soluble in water than p and m-nitrophenols because

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o-nitrophenol is more VOLATILE in steam than those of m-and p-isomers
o-nitrophenol shows intramolecular H-bonding
o-nitrophenol shows intermolecular H-bonding
melting POINT of o-nitrophenol is LOWER than those of m-and p-isomer

Solution :The solubility of ortho-nitrophenol is LESS in water due to intermolecular H-bonding
20.

Ortho nitro phenol and paranitro phenol are

Answer»

Cis-trans ISOMERISM
E, Z configuration
POSITIONAL isomerism
Tautomerism

Solution :Positional isomerism
21.

Ortho hydrogen has magnetic moment___________ that of a proton.

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twice
three times
four times
six times

Answer :A
22.

Ortho, meta and para dichlorobenzenes are

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CHAIN ISOMERS
Positional isomers
Functional isomers
Stereoisomers

Solution :
They are POSITION Isomers.
23.

Ortho effect is special type of effect that is shown by o-subsituents .This ortho-effect operates at the benzoic acids irrespective of the polar type. Nearly all o-substituted benzoic acid are stronger than benzoic acid. Benzoic acid is a resonance stabilised and so the carboxyl group is coplaner with the ring. An o-subsituent tends to prevent this coplanarity.

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ANSWER :B
24.

Ortho effect is special type of effect that is shown by o-subsituents .This ortho-effect operates at the benzoic acids irrespective of the polar type. Nearly all o-substituted benzoic acid are stronger than benzoic acid. Benzoic acid is a resonance stabilised and so the carboxyl group is coplaner with the ring. An o-subsituent tends to prevent this coplanarity. What is the order of K_(a) of following compounds ?

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`I gt II gt III gt IV gt V`
`II gt I gt III gt IV gt V`
`V gt VI gt III gt I gt II`
`III gt II gt I gt V gt IV`

ANSWER :A
25.

Ortho boric acid and metaboric acid differ in respect of

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Basicity
STRUCTURE
M.P
oxidation state

SOLUTION :Basicity, structure and MELTING POINTS.
26.

Ortho and parahydrogen differ in…

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ATOMIC number
atomic mass
spins of protons
number of neutrons

Answer :C
27.

Ortho and para hydrogen differ in....

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PROTON SPIN
Electron spin
Nuclear charge
Nuclear reaction

Solution :Ortho and para hydrogen DIFFER in proton spin.
28.

Ortho and para-nitro phenol can be separated by

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AZEOTROPIC distillation
destructive distillation
steam distillation
cannot be separated

Answer :C
29.

Ortho- and par - hydrogen differ in

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Atomic number
Mass number
Electron SPIN in two ATOMS
Nuclear spin in two atoms

Solution :Nuclean spin of ORTHO - HYDROGEN ` = + 1/2 + 1/2 = 1`
para- hydrogen ` = + 1/2 - 1/2 = 0`
30.

Ortho and para hydrogen differ in

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PROTON spin
electron spin
nuclear charge
both B and c

Answer :A
31.

Original solution of salt or mixture should not be prepared in concentrated HNO_(3) because it:

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is highly corrosive
oxidises `H_(2)S` to S in IIND group
undergoes disproportionation reaction
converts SULPHIDE of `Ba,Sr` and `PB` into insoluble sulphates

Answer :B::D
32.

Orientation of orbitals is given by

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PRINCIPAL QUANTUM NUMBER
SPIN quantum number
Azimuthal quantum number
Magnetic quantum number

ANSWER :A
33.

Organic reactions are given in column-I and reaction names are given in column-II. Match column-I with column-II and chose the correct answer

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`(i) rarr s, (ii) rarr q, (iii) rarr p, (iv) rarr r`
`(i) rarr p, (ii) rarr s, (iii) rarr q, (iv) rarr r`
`(i) rarr s, (ii) rarr p, (iii) rarr r, (iv) rarr q`
`(i) rarr s, (ii) rarr p, (iii) rarr q, (iv) rarr r`

Solution :(i) Substitution reaction : I displaced by `OH^(-)`
`CH_(3)CH_(2)I + KOH rarr CH_(3)CH_(2)OH + KI`
(ii) ELIMINATION reaction: HBr is eliminated `CH_(3)CH_(2)Br + KOH overset("alcohol")rarr CH_(2)=CH_(2) + KBr + H_(2)O`
(iii) Addition reaction: `Cl_(2)` is added to `pi`-BOND
`CH_(2)= CH_(2) + Cl_(2) rarr CH_(2)CL - CH_(2)Cl`
(iv) Rearrangement reaction: `CH_(3)CH_(2)- CH= CH_(2) underset("catalyst")overset("ACID")rarr CH_(3)-underset(underset(CH_(3))(|))(C )HCH_(3)`
34.

Organic liquid vapourises at a temperature below its boiling point in steam distillation because

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Mixture boils when sum of vapour pressure of water and ORGANIC becomes EQUAL to atomspheric pressure.
Steam DISTILLATION is actually distillation under increased pressure.
Water vapour does not contribute to its boiling POINT.
Atmospheric pressure is reduced

Answer :A
35.

Organic particulates include PAH which is an abbreviation for _____

Answer»


ANSWER :POLYCYCLIC AROMATIC HYDROCARBONS
36.

Organic halogen compounds used in industry as solvents are chlorides rather than bromides and iodides. Explain.

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Solution :Organic ALKYL chlorides are used in industry as solvent because chlorides are more VOLATILE than bromides and IODIDES.
37.

organic compound sometimes adjust their electronic as well as steric structures to attain stability. Among the following, the compound having highest dipole moment is:

Answer»




SOLUTION :N//A
38.

Organic compound soluble in water contains

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`C,H`
`C,H,O`
`C,S`
`C,H,CL`

ANSWER :B
39.

Organic compound is………… soluble in organic solvent then continuous extraction technique is used

Answer»


ANSWER :LESS
40.

Organic catalysts differ from inorganic catalysts

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By acting at very high temperature
By acting at LOW temperature
Being used up
Being proteinous in nature

Solution :Organic catalyst are proteinous in nature and obtain from LIVING CELL.
41.

Organic acid without a carboxylicacidgroup is

Answer»

ASCORBIC ACID
vinegar
Oxalic acid
PICRIC acid

SOLUTION :Picric acid is a 2,4,6-trinitrophenol.
42.

Ordinary water contain one part of heavy water per 6000 parts by weight. The number of heavy water molecules present in drop of water of volume 0.01 ml is (Density of water is 1gm//ml)

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`2.5 XX 10^(16)`
`2.5 xx 10^(17)`
`5 xx 10^(16)`
`7.5 xx 10^(16)`

Solution :`6000 -1 0.01 -?`
No. of molecules `(W)/(Mw) xx N`
43.

Oridinary water contain one part of heavy water per 6000 parts of water by weight. The number of heavy water molecules present in a drop of water of volume 0.01 mL is (density of water 1 g/mL)

Answer»

`2.5XX10^(16)`
`5xx10^(17)`
`5xx10^(16)`
`7.5xx10^(16)`

ANSWER :C
44.

Order of the bond strength of C – H bonds involving sp, sp^(2) and sp^(3) hybridized carbon atom is :

Answer»

`SP gt sp^(2) gt sp^(3) `
`sp^(3) gt sp^(2) gt sp`
`sp^(2) gt sp^(3) gt sp`
`sp^(2) gt sp gt sp^(3)`

SOLUTION :Order of STRENGTH C-H bond increases
45.

Order of rate of electrophilic addition reaction with HBr will be :

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IV gt I gt III gt II
I gt II gt III gt IV
I gt III gt II gt IV
IV gt I gt II gt III

Answer :D
46.

Order of oxidation number of S in SO_(3)^(-2),S_(2)O_(4)^(-2)andS_(2)O_(6)^(-2).

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`S_(2)O_(4)^(-2)ltSO_(3)^(-2)ltS_(2)O_(6)^(-2)`
`SO_(3)^(-2)ltS_(2)O_(4)^(-2)ltS_(2)O_(6)^(-2)`
`S_(2)O_(4)^(-2)ltS_(2)O_(6)^(-2)ltSO_(3)^(-2)`
`S_(2)O_(6)^(-2)ltS_(2)O_(4)^(-2)ltSO_(3)^(-2)`

SOLUTION :`underset(+3)underset(darr)(S_(2))O_(4)^(-2)ltunderset(+4)underset(darr)(S)O_(3)^(-2)ltunderset(+5)underset(darr)(S_(2))O_(6)^(-2)`
47.

Order of radioactive disintegration reaction is

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Zero
Ist
2nd
3 rd

Solution :Radioactive disintegrations (INCLUDING the decay of U-235) are the REACTIONS of FIRST ORDER.
48.

Order of K_(a) which can be predicted by following reaction is:

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`NH_(3) gt Ph_(3)CH gt C_(2)H_(2) gt H_(2)O`
`H_(2)O gt HC-= CH gt Ph_(3)CH gt NH_(3)`
`HC -=CH gt H_(2)O gt H_(2)O gt Ph_(3)CH gt NH_(3)`
`Ph_(3)CH gt HC -= CH gt H_(2)O gt NH_(3)`

ANSWER :B
49.

Order of ionization enthlphy in second period of the following is true.

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`Li LT B lt Be lt N lt C `
`Li lt B lt Be lt C lt C`
`Li lt Be lt B lt N lt C`
`Li lt Be lt B lt C lt N `

SOLUTION :The correct ORDER of ionisation ENTHALPY for second periode is
`Li lt B lt Be lt C lt O lt N lt F lt NE`
50.

Order of hydrolysis for the following I. RCOCl II. RCOOR III. RCONH_(2) IV. (RCO_(2))_(2)O

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`I gt IV gt II gt III`
`I gt II gt III gt IV`
`I gt III gt II gt IV`
`IV gt III gt II gt I`

Answer :B