Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The correct stability orderof the following resonance structure is (I)H_(2)bar(C)-overset(+)N-=N(II) H_(2)C = overset(+)N =bar(N)(III) H_(2)overset(+)C-N =bar(N)(IV) H_(2)bar(C) -N=overset(+)N

Answer»

`(I) GT (II) gt (IV) gt (III)`
`(I) gt (III) gt (II) gt (IV)`
`(II) gt (I) gt (III) gt (IV)`
`(III) gt (I) gt(IV) gt (II)`

ANSWER :B
Discussion
2.

The correct stability order of the following resonance structure is : I) H_(2)C=overset(oplus)(N)=overset(ө)(N)"II) "H_(2)overset(oplus)(C)-N=overset(ө)(N)"III) "H_(2)overset(oplus)(C)-N=overset(ө)(N)"IV) "H_(2)overset(ө)(C)-N=overset(oplus)(N)

Answer»

`(I) gt (II) gt (IV) gt (III)`
`(I) gt (III) gt (II) gt (IV)`
`(II) gt (I) gt (III) gt (IV)`
`(III) gt (I) gt (IV) gt (II)`

ANSWER :B
Discussion
3.

The correct stability order of the following resonanating structures is : underset("(I)")(CH_(2)=C=O)""underset("(II)")(C_(3)overset(-)C-overset(+)C=O)""underset("(III)")(H_(2)C=overset(+)C-overset(-)O)""underset("(IV)")(H_(2)overset(-)C-C-=overset(+)O)

Answer»

`(IV)GT(I)gt(III)gt(II)`
`(II)gt(IV)gt(I)gt(III)`
`(III)gt(II)gt(IV)gt(I)`
`(I)gt(IV)gt(III)gt(II)`

ANSWER :D
Discussion
4.

The correct stability order of the following resonance structures is underset((I))(H_2C = overset(+)N = overset(-)(N)) underset((II))(H_2overset(+)C-N= overset(-)(N)) underset((III))(H_2overset(-)(C)-overset(+)N -=N) underset((IV))(H_2C overset(-)C-N = overset(+)(N))

Answer»

`I GT II gt IV gt III`
`I gt III gt II gt IV`
`II gt I gt III gt IV`
`III gt I gt IV gt II`

ANSWER :B
Discussion
5.

The correct stability order for the following species is

Answer»

`II GT IV gt I gt III`
`I gt II gt III gt IV`
`II gt I gt IV gt III`
`I gt III gt II gt IV`

ANSWER :D
Discussion
6.

The correct stability order for boron halides is

Answer»

`BF_(3)gtBCl_(3)gtBBr_(3)gtBl_(3)`
`BCl_(3)gtBF_(3)gtBBr_(3)gtBr_(3)`
`Bl_(3)gtBBr_(3)gtBCl_(3)gtBF_(3)`
`BBr_(3)gtBCl_(3)gtBl_(3)gtBF_(3)`

Solution :(a) The stability order for boron halides is explained in terms of back-bonding.
Discussion
7.

The correct signs of Delta S for the following four processes respectively are (i) Devitrification of glass (ii) Desalination of sea water (iii) N_(2) (g, 10 atm) rarr N_(2)(g, 2 atm) (iv) C (s, graphite) rarr C (s, daimond)

Answer»

`-,-,+,-`
`+,-,+,-`
`+,-,-,-`
`-,-,-,-`

SOLUTION :EXPANSION of gas results in INCREASE in ENTROPY
Discussion
8.

the correctset of the four quantumnumber forthe valenceelectronor Rubidumatom (z=37) is

Answer»

`5,0,0, +(1)/(2)`
`5,1,9,+(1)/(2)`
`5,1,1,+(1)/(2)`
`6,0,0,+(1)/(2)`

ANSWER :A
Discussion
9.

The correct set of quantum numbers for the unpaired electron of chlorine atom is

Answer»

n=2, l=1, m=0
n=3, l=1, m=0
n=2, l=1, m=1
n=3, l=0, m=0

Answer :C
Discussion
10.

The correct set of quantum numbers for a 4d electron is (Kerala Engineering)

Answer»

`4, 3, 2, +1//2`
`4, 2, 1, 0`
`4, 3, -2, +1//2`
`4, 2, 1, -1//2`

Answer :D
Discussion
11.

The correct set of quantum number for the unpaired electron of chlorine atom is

Answer»

`2, 1, -1, +(1)/(2)`
`2, 0, 0, +(1)/(2)`
`3, 1, 1, pm(1)/(2)`
`3, 0, 0,pm(1)/(2)`

Answer :C
Discussion
12.

The correct set of four quantum numbers for the valence electron of rubidium (Z = 37) is

Answer»

5, 1, 1, `+1//2`
6, 0, 0, `+1//2`
5, 0, 0, `+1//2`
5, 1, 0, `+1//2`

Solution :Electronic CONFIGURATION of rubidium `(Z = 37)` is `[Kr]^(36) 5s^(1)`
HENCE, for the valence electron `(5s^(1)), N = 5, l = 0, m = 0, s = 1//2`
Discussion
13.

The correct set of oxidation number of nitrogen atom in cyanide ion, ammonium ion, nitrite and nitrate ion, respectively is :

Answer»

`-3,+3,-3,-5`
`-3,+5,-3,+4`
`+3,+1,-3,+5`
`-3,-3,+3,+5`

SOLUTION :
Discussion
14.

The correctset of quantum numberfor 4delectron

Answer»

`4,3-1+(1)/(2)`
`4,2,1,-(1)/(2)`
`4,3,2+(1)/(2)`
`4,2,1,0`

Solution :4D `: N =4,L =2`
`m=+2 `to `-2,2 =+ (1)/(2)`
Discussion
15.

The correct set of four quantum numbers for the valence electrons of Rubidium atom (Z = 37)

Answer»

`5,1,+1/2`
`5,1,1+1/2`
`5,0,1+1/2`
`5,0,0+1/2`

ANSWER :D
Discussion
16.

The correct set of four quantum numbers for the valence electron of rubidium atom (Z = 37) is

Answer»

5,0,0,+1/2
5,1,0,1/2
5,1,1,+1/2
6,0,0,+1/2

Answer :A
Discussion
17.

The correct set of four quantum number for the unpaired electron of the element Z = 21 is

Answer»

`N=3 , l =2 m =1 s=+1/2`
`n=3 , l =1 m =0 s=+1/2`
`n=3 , l =3 m =2 s=+1/2`
`n=4 , l =0 m =0 s=+1/2`

Solution :The element Z = 21 is SC. Electron configuration of it is : `Is^(2) 2s^(2)2p^(6) 3s^(2)3p^(6) 4S^(2) 3d^(3)`The unpaired electron of Z - 21 is `3d^(3)`
(i) n = 3 = principal quantum number
(ii) d orbital has l=2
(iii) as l=2 values of m =+2,1 ,0,-1 ,-2 `therefore` m=+1 is possiblebut only(A)has l=2
(iv) firstelectronin 3d has spin quantum no =+`1/2`
thus n=3, l=2,m=1 and s=`+1/3`
Discussion
18.

The correct sequence which shows decreasing order of the ionic radii of the elements is.....

Answer»

`Na^(+) gt F^(-) gt Mg^(+2) gt O^(-) gt AL^(+3)`
`O^(-2) gt F^(-) gt Na^(+) gt Mg^(+2) gt Al^(+3)`
`Al^(+3) gt Mg^(+2) gt Na^(+) gt F^(-) gt O^(-2)`
`Na^(+) gt Mg^(+2) gt Al^(+3) gt O^(-2) gt F^(-1)`

Solution :`O^(-2) gt F^(-) gt Na^(+) gt Mg^(+2) gt Al^(+3)`

"All the ions are isoelectronic having different atomic numbers and the isoelectronic ion of smaller nuclear CHARGE has larger ionic SIZE."
Discussion
19.

Identify the correct order of innic radii of the following ions

Answer»

`Na^(+)gtMg^(2+)gtAt^(3+)gtO^(2-)GTF^(-)`
`Na^(+)gtF^(-)gtMg^(2+)gtO^(2-)gtAl^(3+)`
`O^(2-)gtF^(-)gtNa^(+)gtMg^(2+)gtAl^(3+)`
`AL^(3+)gtMg^(2+)gtNa^(+)gtF^(-)gtO^(2-)`

Answer :C
Discussion
20.

The correct sequence of the oxidation state of underlined elements is Na_(2)[ul(Fe)(CN)_(5)NO],K_(2)ul(Ta)F_(7),Mg_(2)ul(P)_(2)O_(7),Na_(2)ul(S)_(4)O_(6),ul(N)_(3)H

Answer»

<P>`+3, +5, +5, +2.5, -(1)/(3)`
`+5, +3, +5, +3, +(1)/(3)`
`+3, +3, +5, +5, -(1)/(3)`
`+5,+5, +3, +2.5,+(1)/(3)`

Solution :`Na_(2)[""ul(Fe)(CN)_(5)NO]:+2+x+5(-1)+0=0rArrx=+3`
`K_(2)ul(Ta)F_(7):+2+x+(-7)=0rArr x=+5`
`Mg_(2) ul(P)_(2)O_(7):+4+2x+(-14)=0 RARR x=+5`
`Na_(2)ul(S)_(4)O_(6):+2+4x+(-12)=0` or `4x=10 rArr x=+2.5`
`ul(N)_(3)H:3x+1=0 rArr x=-(1)/(3)`
Discussion
21.

The correctsequence whichshowsdecreasingorder of the ionicradii ofthe elementis

Answer»

`O^(2-)GT F^(-)gt Na^(+) gt Mg^(2+) gt A1^(3+)`
`A1^(3+)gt Mg^(2+) gt Na^(+) gt F^(-)gt O^(2-)`
`Na^(+)gt Mg^(2+) gt A1^(3+) gt O^(2-) gt F^(-)`
`Na^(+) gt F^(-)gt Mg^(2+)gt O^(2-)gt A1^(3+)`

Solution :For isoelectronic ions , followingthe samereasoningas discussed ASANS .27the correctorderof decreasingionicradii is: `O^(2-)gt F^(-) gt Na^(+)gtMg^(2+) gt A1^(3+)` i.e.,Option(a) ISCORRECT.
Discussion
22.

The correct sequence which shows decreasing order of the ionic radii of the elements is

Answer»

`NA^(+) gt MG^(2+) gt AL^(3+) gt O^(2-) gt F^(-)`
`Na^(+) gt F^(-) gt Mg^(2+) gt O^(2-) gt Al^(3+)`
`O^(2-)gt F^(-) gt Na^(+) gt Mg^(2+) gt Al^(3+)`
`Al^(3+) gt Mg^(2+) gt Na^(+) gt F^(-) gt O^(2-)`

Answer :C
Discussion
23.

The correct sequence of reagents from those listed below for the following conversion is I. NaNH_(2) II. Br_(2) III. H_(2)//Pd-C,quinoloneIV. H_(3)O^(+)

Answer»

IV-I-III
III - IV - I
II - I - III
I - II - III

Answer :C
Discussion
24.

The correct sequence of reagents for the following conversion will be :

Answer»

`CH_(3)MGBR, H^(+)//CH_(3)OH, [AG(NH_(3))_(2)]^(+)OH^(-)`
`CH_(3)MgBr, [Ag(NH_(3))_(2)]^(+)OH^(-), H^(+)//CH_(3)OH`
`[Ag(NH_(3))_(2)]^(+)OH^(-), CH_(3)MgBr^(-), H^(+)//CH_(3)OH`
`[Ag(NH_(3))_(2)]^(+)OH^(-), H^(+)//CH_(3)OH, CH_(3)MgBr`

Answer :D
Discussion
25.

The correct sequence of reactions to convert p-nitrophenol into quinol involves............

Answer»

REDUCTION, DIAZOTIZATION and hydrolysis
hydrolysis, diazotization and reduction
hydrolysis, reduction and diazotization
diazotization, reduction and hydrolysis

Answer :A
Discussion
26.

The correct sequence of decrease in the bond angles of the following hybrides is

Answer»

`NH_(3) gt PH_(3) gt AsH_(3) gt SbH_(3)`
`NH_(3) gt AsH_(3) gt PH_(3) gt SbH_(3)`
`SbH_(3) gt AsH_(3) gt PH_(3) gt NH_(3)`
`PH_(3) gt NH_(3) gt AsH_(3) gt SbH_(3)`

Solution :In similar molecules, as the ELECTRONEGATIVITY of
the central atom decreasesand the size INCREASES,
the bond angle decreases.
Discussion
27.

The correct sequence of deceasing mass of the following is : (i) 6.022 xx 10^(23) atoms of oxygen (ii) 1.0 xx 10^(23) molecules of H_(2)S (iii) 6.022 xx 10^(23) molecules of oxygen

Answer»

(i) `GT` (ii) `gt` (iii)
(i) `gt` (iii) `gt` (ii)
(iii) `gt` (i) `gt` (ii)
(ii) `gt` (i) `gt` (iii)

SOLUTION :(i) `6.022 xx 10^(23)` atoms of oxygen have mass = 16.0 g
(ii) `6.022xx 10^(23)` molecules of `H_(2)S` have mass = 34.0 g
`1.0 xx 10^(23)` molecules of `H_(2)S` have mass
`= (1xx10^(23))/(6.022xx10^(23))xx(34.0g)=5.645g`
(iii) Mass of `6.022xx10^(23)` molecules of oxygen `(O_(2)) = 32 g`.
Discussion
28.

The correct Schordinger.s wave equation for a electron with total energy E and potential energy V is not correctly given by

Answer»

`(DELTA^2 Psi)/(deltax^2) +(delta^2 Psi)/(delta z^2) + (delta^2 Psi)/(delta z^2) + (8 pi^2)/(mh^2) (E-V) Psi = 0`
`(delta^2 Psi)/(deltax^2) +(delta^2 Psi)/(delta y^2) + (delta^2 Psi)/(delta z^2) + (8 pi m)/(h^2) (E-V) Psi = 0`
`(delta^2 Psi)/(deltax^2) +(delta^2 Psi)/(delta y^2) + (delta^2 Psi)/(delta z^2) + (8 pi^2 m)/(h^2) (E-V) Psi = 0`
`barV^2 Psi=0`

SOLUTION :` nabla^2 Psi + (8 pi^2 m)/(h^2) (E-V) Psi=0`
Discussion
29.

The correct representation of 4-hydroxy-2-methylpent-2-en-1-al is

Answer»

`CH_(3)-underset(OH)underset(|)(C)H-CH=underset(CH_(3))underset(|)(C)-CHO`
`CH_(3)-underset(CH_(3))underset(|)(C)H-CH=underset(OH)underset(|)(C)-CHO`
`CH_(3)-underset(OH)underset(|)overset(CH_(3))overset(|)(C)-CH=underset(CH_(3))underset(|)(C)-CHO`
`CH_(3)-underset(OH)underset(|)(C)H-CH_(2)-underset(CH_(3))underset(|)(C)H-CHO`

SOLUTION :`underset("4-Hydroxy-2-methylpent-2-en-1-al")(overset(5)(C)H_(3)-underset(OH)underset(|)overset(4)(C)H-overset(3)(C)H=underset(CH_(3))underset(|)overset(2)(C)-overset(1)(C)HO)`
Discussion
30.

The correct representation for solubility product of SnS_(2) , is

Answer»

`[SN^(4+)] [S^(2-) ]^(2) `
` [Sn^(4+) ][S^(2-) ]`
` [Sn^(4+) ][2S^(2-)]`
` [Sn^(4+) ][2S^(2-)]^(2) `

SOLUTION :` SnS_2 HARR Sn^(+4) +2S^(-2),K_(sp)=[Sn^(+4) ][S^(-2) ] ^(2) `
Discussion
31.

The correct relationship between free energy change in a reaction and the coresponding equilibrium constant K is :

Answer»

`-DELTAG^(CIRC)`=RTInK
`DeltaG`=RTInK
`-DeltaG`=RTInK
`-DeltaG^circ`=RTInK

ANSWER :A
Discussion
32.

The correct relationship between enthalpy (in cal mol^(-1)) of vaporisation of liquid and its boiling point is

Answer»

`DELTA H_("vap") ~~ 21 T_(b)`
`Delta H_("vap") ~~ 1.55 T_(b)`
`Delta H_("vap") ~~ 2//3 T_(b)`
`Delta H_("vap") ~~ 2.303 T_(b)`

Solution :STATEMENT is based on Trauton's rule
Discussion
33.

The correct relationship betw een quantum numbers n, I and m is :

Answer»

`n lt l lt m`
`n lt l LE m`
`n lt l GE ,`
`n ge l gtm`

SOLUTION :We canderive the fact by takingn=3
Discussion
34.

The correct relation among the following is

Answer»

`x=y`
`y=3x`
`3x-y=6k.cal`
`x-3y=36k.cal`

SOLUTION :Resonance ENERGY `=DeltaH_(EXP)-DeltaH_(cal)`.
Discussion
35.

The correct reactivity order of halogen with hydrogen is ?

Answer»

SOLUTION :`F_2 GT Cl_2 gt Br_2 gt I_2`
Discussion
36.

The correct proportion of Ca_(3)SiO_(3) is portland cement is …………. .

Answer»

0.26
0.11
0.4
0.51

Answer :D
Discussion
37.

The correct pK_(a) order of the following acids is :

Answer»

`I gt II gt III`
`I gt III gt II`
`III gt II gt I`
`IIIgt I gt II`

Solution :On the BASIS of stability of conjugate BASE DUE to electronic EFFECTS.
Discussion
38.

The correct orders for bond length are :

Answer»




ANSWER :A::B::D
Discussion
39.

The correct orders are:

Answer»




ANSWER :A
Discussion
40.

The correct order to the packing efficiency in different types of unit cells is _______

Answer»

FCC LT bcc lt SIMPLE CUBIC
fcc gt bcc gt simple cubic
fcc lt bcc gt simple cubic
bcc lt fcc gt simple cubic

SOLUTION :fcc =0.74 , bcc=0.68 , simple =0.524. Hence , fcc gt bcc gt simple
Discussion
41.

The correct order to the packing efficiency in different types of unit cells is ….

Answer»

fcc LT bcc lt simple cubic
fcc GT bcc gt simple cubic
fcc lt bcc gt simple cubic
bcc lt fcc gtsimple cubic

SOLUTION :Fcc = 0.74, bcc = 0.68 , simple = 0.524 , Hence,fcc gt bcc gt simple.
Discussion
42.

The correctorder regarding the electrongetiveively of hybrid orbitals of carbon is

Answer»

` SP LTSP^(2) GT sp^(3)`
`sp lt sp^(2) lt sp^(3)`
`sp gt sp^(2) gt sp^(2)`
`sp gt sp^(2) gt sp^(3)`

Solution :Smaller the size , greater is its electronegetivily.
Discussion
43.

The correctorderregardingthe electronegativityof hybrid orbitalsof carbonis

Answer»

`sp LTSP^(2)GT sp^(3)`
` sp ltsp^(2) lt sp^(3)`
`sp gt sp^(2)lt sp^(3)`
`sp gtsp^(2)gt sp^(3)`

Solution :NA
Discussion
44.

The correct order regarding the electronega tivity of hybrid obritals of carbon is

Answer»

`sp GT sp^(2) lt sp^(3)`
`sp gt sp^(2) lt sp^(3)`
`sp gt sp^(2)gt sp^(3)`
`sp lt sp^(2)gt sp^(3)`

ANSWER :C
Discussion
45.

The correct order of Vander Waals radius of F, Cl and Br is :

Answer»

F GT Br gt CL
Br gt Cl gt F
F gt Cl gt Br
Br gt F gt Cl

Answer :B
Discussion
46.

Arrange in the increasing order of oxidation state of nitrogen for following nitrogen oxides N_(2)O, NO_(2), NO, N_(2)O_(3)

Answer»

`NO_(2)ltNOltN_(2)O_(3)ltN_(2)O`
`N_(2)OltNOltN_(2)O_(3)ltNO_(2)`
`NO_(2)ltN_(2)O_(3)ltNOltN_(2)O`
`N_(2)OltN_(2)O_(3)ltNOltNO_(2)`

ANSWER :B
Discussion
47.

The correct order of the energy of molecular orbitals in a molecules having four electrons

Answer»

`SIGMA^(*)_(2s) GT sigma_(2PZ) gt pi_(2px)`
`sigma_(2s)^(*) lt pi_(2p) lt sigma_(2pz)`
`sigma_(2s)^(*) lt sigma_(2pz) = pi_(2px)`
`sigma_(2pz) lt sigma_(2s)^(*) lt pi_(2px)`

Answer :A
Discussion
48.

The correct order of the acidic nature of oxides is in the order

Answer»

`NOltN_(2)OltN_(2)O_(3)ltNO_(2)ltN_(2)O_(5)`
`N_(2)OltNOltN_(2)O_(3)ltNO_(2)ltN_(2)O_(5)`
`N_(2)O_(5)ltNO_(2)ltN_(2)O_(3)ltNOltN_(2)O`
`N_(2)O_(5)ltN_(2)O_(3)ltNOltN_(2)O`

Solution :ACIDIC nature increases as the O.S. of N increases :
`OVERSET(+1)(N_(2)O)ltoverset(+2)(NO)ltoverset(+3)(N_(2)O_(3))ltoverset(+4)(NO)ltoverset(+5)(N_(2)O_(5))`
Discussion
49.

The correct order of stability of hydrides of alkali metals is

Answer»

`LiHgtNaHgtKHgtRbH`
`NaHgtKHgtRbHgtLiH`
`RbHgtKHgtNaHgtLiH`
`HgtRbHgtKHgtNaH`

SOLUTION :The stabilityorder of HYDRIDES of ALKALI MET ALS is `LiHgtNaHgtKHgtRbH`
Discussion
50.

The correct order of stability for the following superoxides is

Answer»

`KO_(2) GT RbO_(2) gt CsO_(2)`
`RbO_(2) gt CsO_(2) gt KO_(2)`
`CsO_(2) gt RbO_(2) gt KO_(2)`
`KO_(2) gt CsO_(2) gt RbO_(2)`

ANSWER :C
Discussion