Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

What is electromeric effect?

Answer»

Solution :It is defiend as the COMPLETE transfer of a shared pair of `pi` electrons to one of the atom joined by a MULTIPLE bond on the DEMAND of an ATTACKING reagent
Discussion
2.

Which of the following reaction(s) can be used for the preparation of alkyl halides? (I) CH_(3)CH_(2)OH+HCl overset("anhyd." ZnCl_(2))to (II) CH_(3)CH_(2) OH+HCl to (III) (CH_(3))_(3)COH+HCl to (IV) (CH_(3))_(2)CHOH+HCl overset("anhyd." ZnCl_(2))to

Answer»

(IV) only
(III) and (IV) only
(I), (III) and (IV) only
(I) and (II) only

Solution :`1^(@)` and `2^(@)` alcohols react with HCl in the presence of ANHYDROUS `ZnCl_(2)` while in case of `3^(@)` alcohol, anhydrous `ZnCl_(2)` is not needed. Therefore, alkyl HALIDES can be prepared by REACTIONS (I), (III) and (IV).
Discussion
3.

Which of the following is soluble in water?

Answer»

`C_2 H_5 OC_2 H_5`
`C_2 H_5OH`
`C_2 H_5 CL`
`C_6 H_6`

ANSWER :B
Discussion
4.

Which of the following statements is/are correct about the coefficient B in the virial equation of state PV_m = RT (1 = B/(V_m) + C/(V_m^2) + .....)

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It is INDEPENDENT of temperature
It is equal to zero at Boyle temperature
It has dimensions of molar volume
It is DEPENDENT on pressure

Solution :`B = b - a/(RT) , B = 0 IMPLIES T = a/(RB)`, units = lit/mol.
Discussion
5.

In which of the following pairs, the two species are isostructural?

Answer»

`BrO_(3)^(-) ` and `XeO_(3)`
`HgCI_(2) ` and `CO_(2)`
`XeF_(4)` and `SF_(4)`
`BF_(3)` and `NF_(3)`

ANSWER :A::B
Discussion
6.

Which of the following is a correct statement regarding D_2O

Answer»

6000g. of ordinary WATER contains 1G. of `D_2O`
The volumetric composition of `H_2O`and `D_2O`in ordinary water is 6000:1
The molar RATIO of `H_2O` and `D_2O` in ordinary water is 6000 : 1
Ordinary water contains 0.16% of `D_2O`

ANSWER :A
Discussion
7.

Which of the following is a strongest oxidising agent ?

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`Br_2`
`I_2`
`Cl_2`
`F_2`

ANSWER :D
Discussion
8.

Which of the following factor decreases across the period ?

Answer»

IONISATION energy
electron affinity
atomic RADIUS
electronegativity

Answer :C
Discussion
9.

Which one ofthe followingreactions does not correspond to thepreparation of"synthetic gasoline" during the Fischer-Tropsch process?

Answer»

`CO+3H_(2)rarrCH_(4)+H_(2)O_(2)`
`NCO+2nH_(2)rarrnCH_(3)OH`
`nCO+2nH_(2)rarrCnH_(2n)+nH_(2)O`
`nCO+(2n+1)H_(2)rarrCnH_(2n+2)+nH_(2)O`

ANSWER :B
Discussion
10.

When 22.4 litres of H_(2(g))is mixed with 11.2 litres of Cl_(2(g)),each at STP, the moles of HCl_((g))formed is equal to -

Answer»

1 MOLE of `HCl_((g))`
2 mole of `HCl_((g))`
0.5 mole of `HCl_((g))`
1.5 mole of `HCl_((g))`

SOLUTION : `H_(2)+Cl_(2) rarr 2HCL`
`22.4 "lt."11.2 "lt."`
1 moleof `HCl=(1)/(2)` mole
Limiting REAGENT is `Cl_(2)`. So, 1 mole HCl is formed.
Discussion
11.

Which of the following species has tetrahedral geometry ?

Answer»

`BH_(4)^(-)`
`NH_(2)^(-)`
`CO_(3)^(2-)`
`H_(3)O^(+)`

Solution :`BH_(4)^(-)`
`BH_(4)^(-) rArr` 4 bond pairs + O lone pair `rArrsp^(3)`
`rArr` hybridised to tetrahedral geometry
`NII_(2)^(-) ` = V-shape ,`"" CO_(3)^(2-)` = TRIANGULAR PLANAR
`H_(3)O^(+)` = pyramidal
Discussion
12.

The three types of pesticides are named as _______ , _______and _________

Answer»


ANSWER :INSECTICIDES HERBICIDES, FUNGICIDES
Discussion
13.

The true statement about benzene is

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Because of unsaturation BENZENE easily undergoes addition reactions.
There are two types `C-C` bonds in benzene molecule
There is a cyclic delocalisation of pi-electrons in benzene
Mono SUBSTITUTION of benzene gives three ISOMERIC products.

Solution :Delocalisation in benzene is due to planarity
Discussion
14.

Which of the following electronic configuration of an atom has lowest Ionisation enthalpy?

Answer»

`1s^2 2s^2 2p^5`
`1s^2 2s^2 2p^3`
`1s^2 2s^2 2p^6 3s^1`
`1s^2 2s^2 2p^6`

ANSWER :C
Discussion
15.

Which is used to reduce pressure in distillation under reduced pressure?

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SOLUTION :(i) WATER PUMP (II) VACUUM pump
Discussion
16.

What are activating and deactivating groups ?

Answer»

SOLUTION :
Discussion
17.

Which of the following statements is not true about classical smog ?

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Its main components are produced by the action of sunlight on emissions of automobiles and FACTORIES
Produced in cold and humid climate
It contains compounds of reducing nature
It contains smoke, fog and SULPHUR dioxide

Solution :Photochemical smog and not the CLASSICAL smog is produced by the action of sunlight on EMISSION of automobiles and factories
Discussion
18.

What is the difference between atomic mass and mass number?

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Solution :(i) MASS number is a whole number because it is the sum of number of protons and number of neutrons.
(ii) Atomic mass the fractional because it is the AVERAGE RELATIVE mass of its atom as COMPARED with mass of an atom of C - 12 ISOTOPE taken as 12.
Discussion
19.

Write the possible isomers for the formula C_4H_9Cl with structures and names.

Answer»

SOLUTION :`C_4H_9Cl` (4 isomers) :
(i) `CH_3-CH_2 - CH_2 - CH_2Cl`:1 - Chlorobutane
(ii) `CH_3 - underset(Cl_3)underset(|)(CH) - CH_2 -CH_3`2- chlorobutane
(iii) `CH_3 - underset(CH_3)underset(|)(CH) - CH_2 - CH-3`1 - Chloro-2-methylpropane
(iv) `CH_3 - underset(Cl)underset(|) OVERSET(CH_3)overset(|)C - CH_3`2-Chloro-2-methylpropane
Discussion
20.

Which of the following statements are false

Answer»

`Ca(OH)_(2)` is called slaked lime
`Mg^(2+)` and `Ca^(2+)` IONS are responsible for the TRANSMISSION of electrical impulses along the NERVE FIBRE
`Ca^(2+)` ion is present in chlorophyll pigment
The enamel on teeth is a double SALT of Mg

Solution :`Mg^(2+)` ion is present in chlorophyll pigment. The enamel on teeth is a double salt of calcium
Discussion
21.

Which technique is used for separation of compound present in aqueous solution ?

Answer»

SOLUTION :DIFFERENTIAL EXTRACTION
Discussion
22.

What happens when benzene reacts with n-propylchloride in presence of anhydrous aluminium chloride?

Answer»

Solution :The major product of the reaction is isopropyl benzene (cumcnc).
The initially formed `CH_(3)CH_(2) overset(+)(CH_(2))` gets rearranged to more stable secondary CARBOCATION `CH_(3) overset(+)(CHCH_(3))`Hence the major product is isopropyl benzene and minor product is PROPYL benzene.
`CH_(3)CH_(2)CH_(2)Cl+AlCl_(3) Leftrightarrow CH_(3)CH_(2) overset(+)(CH_(2))+AlC_(4)^(-) , CH_(3) CH_(2) overset(+)(CH_(2)) overset(H^(-)" shift")to CH_(3) overset(+)(CH) CH_(3)`
Discussion
23.

Which of the following have maximum strongly of attractive inductive effects? (a) CH_(3)CH_(3)Cl, CH_(3)CH_(2)Br, CH_(3)CH_(2)F, CH_(3)F (b) CH_(3)COOH, CH_(2)ClCOOH, CHCl_(2)COOH (c ) (CH_(3))_(3) C COOH, (CH_(3))_(2) CHCOOH, CH_(3)COOH

Answer»

SOLUTION :(a) `CH_(3)F` (b) `CHCl_(2)COOH` (c ) `CH_(3)COOH`
Discussion
24.

Which elements contain maximum and minimum ionisation enthalpy in period ?

Answer»

Solution :Alkali metal having LESS ionisation ENTHALPY and noble GAS having high ionisation enthalpy.
Discussion
25.

Which of the following is the strongest base ?

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NaOH
KOH
`CA(OH)_(2)`
`MG(OH)_(2)`

Solution :KOH is the STRONGEST base SINCE K is most electropositive .
Discussion
26.

Which of the following has the highest point ?

Answer»

o-xylene
m-xylene
p-xylene
Toluene

Answer :C
Discussion
27.

Which of the following ions will cause hardness in water sample ?

Answer»

`CA^(2+)`
`Na^(+)`
`Cl^(-)`
`K^(+)`

ANSWER :A
Discussion
28.

Which statement is false?

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Elements of VB group are transition elements.
elements of VA group are ALLL metalloids
elements of IA and IIA groups are metals
element of IVA group are NEITHER strongly electronegative nor strongly electropositive.

Answer :B
Discussion
29.

Which of the following is incorrect

Answer»

`H_(2)O_(2)` is a weak acid
`H_(2)O_(2)` is a weak alkali
`H_(2)O_(2)` acts as on oxidising agent
`H_(2)O_(2)` is a reducing agent

Solution :`H_(2)O_(2)` is slightly stronger acid than water, it forms two series of salt,
`H_(2)O_(2) IFF H^(+)+HO_(2)^(-)` (hydroperoxide ion)
`H_(2)O_(2) iff 2H^(+)+O_(2)^(2-)` (Peroxideion)
`H_(2)O_(2)` behaves as oxidising as well as reducing agent in ACIDIC and BASIC medium.
In acidic medime,
`H_(2)O_(2)+2H^(+)2e^(-) RARR 2H_(2)O`
in basic medime,
`H_(2)O_(2)+OH^(-1)+2e rarr 3OH^(-)`
As reducing agent, in acidic medium,
`H_(2)O_(2) rarr 2H^(+)+O_(2)+2e^(-)`
In alkaline medium,
`H_(2)O_(2)+2OH^(-) rarr 2H_(2)O+O_(2)+2e^(-)`
Discussion
30.

Which one of the following element mostly present in the sun and the stars?

Answer»

Hydrogen
Lithium
 HELIUM
Beryllium

Answer :a
Discussion
31.

Which of the following exhibits chain isomerism?

Answer»

`CH_3CH_2NH_2`
`CH -= C - CH_2CH_3`
`CH_2CH_2CH_2OH`
`CH-= C - CH_2 CH_2CH_3`

Solution :To exhibit CHAIN isomerism organic COMPOUND MUST contain 4-carbons, but for alkyne nee five carbons
`CH -=C-CH_2-CH_2-CH_3 and CH-=C-UNDERSET(CH_3)underset(|)CH-CH_3`
Discussion
32.

Whenever a hydrogen atom emits a quantum in the visible region of Balmer series :

Answer»

it may emit another quantum in Balmer series again
it must emit another quantum in ultraviolet region of LYMAN series
second quatum of wavelength 122nm will be emitted
second quantum will be emitted in Paschen series i.e., near infrared region

Solution :Second quantum will be in Lyman series because from `2^(nd)` shell the ELECTRON will FALL to first shell or ground STATE.
`1/(lambda) = R [(1)/(n_1^2) - 1/(n_2^2) ] = 109677 [1/(1^2) - 1/(2^2)]`
`lambda = 122 xx 10^(-7) cm = 122 nm`
After coming to `2^(nd)` orbit then electron can go `1^(st)` orbit. So lyman series is possible .
Discussion
33.

Which of the following is aromatic in nature?

Answer»




ANSWER :C
Discussion
34.

The standard enthalpy of formation of Fe_(2)O_(3)(s) is - 824.2 kJ mol^(-1) . Calculate the enthalpychange for the reaction :4 Fe (s) + 3O_(2) (g) rarr 2Fe_(2) O_(3) (s)

Answer»


SOLUTION :`Delta_(r)H^(@) = [ 2 xx Delta_(F) H^(@) ( Fe_(2)O_(3))] - [ Delta_(f)H^(@) ( Fe)+ 3Delta_(f) H^(@) (O_(2))]`
`= [2(-824.2) ] -[0+0]`
`= - 1648.4kJ`
Discussion
35.

Which of the following options will be correct for the stage of half completion of the reaction A hArr B.

Answer»

`DELTAG^(Θ)=0`
`DELTA G^(Θ) GT 0`
`DeltaG^(Θ)= lt0`
`Delta G^(Θ)=-RT` ln 2

Solution :`Delta G^(@) = - RT` ln K
At the stage of half completion of the reaction A `hArr` B, [A]=[B].
HENCE, K = 1 . Therefore, `Delta G^(@)=0`.
Discussion
36.

Define Graham's law of diffusion.

Answer»

SOLUTION :Graham's DIFFUSION Law : The rate of diffusion or EFFUSION is INVERSELY PROPORTIONAL to the square root of molar mass. The statement is called Graham's law of diffusion/effusion.
Discussion
37.

Which pollutant can be used as fertiliser

Answer»

VEGETABLE WASTE
PLASTIC waste
NUCLEAR waste
D.D.T

ANSWER :A
Discussion
38.

When cyclohexanone and + X The no . Of hybrid orbitals of phosphorus involved formation X.

Answer»


SOLUTION :PHOSPHORUS undergos `SP ^(3)`hybridisaton in X.
Discussion
39.

Which type of bond is not present in HNO_(2) molecule ? .

Answer»

COVALENT
Coordinate
IONIC
Both ionic and coordinate

Solution :STRUCTURE of `HNO_(2) ` is and it contains only covalent bond
Discussion
40.

Which of the following is not an emulsion

Answer»

Butter
Ice cream
Milk
Cloud

SOLUTION :It is LIQUID in GAS COLLOIDAL solution.
Discussion
41.

The standard reduction potential for silver electrode is +0.80 V. It is connected to a standard hydrogen electrode to make a galvanic cell. State whether silver electrode will act as anode or cathode.

Answer»

SOLUTION :CATHODE
Discussion
42.

The wavelength of H_(alpha) line of Balmer series is 6500 Å. What is the wavelength of H_(beta) line of Balmer series?

Answer»

Solution :`H_(ALPHA)` line of Balmer series is obtained when `n_(1) = 2, n_(2) = 3`
`H_(beta)` line of Balmer series is obtained when `n_(1) = 2, n_(2) = 4`
Thus, `bar(v) H_(alpha) = (1)/(.^(lamda)H_(alpha)) = R_(H) ((1)/(2^(2)) - (1)/(3^(2))) = R_(H) ((1)/(4) - (1)/(9)) = R_(H) xx (5)/(36)` ...(i)
`bar(v) H_(beta) = (1)/(.^(lamda)H_(beta)) = R_(H) ((1)/(2^(2)) - (1)/(4^(2))) = R_(H) ((1)/(4) - (1)/(16)) = R_(H) xx (3)/(16)`..(ii)
Dividing eqn. (i) by eqn. (iii), we get
`(.^(lamda)H_(beta))/(.^(lamda)H_(alpha)) = (5)/(36) xx (16)/(3) = (20)/(27) :. .^(lamda)H_(beta) = (20)/(27) xx .^(lamda)H_(beta) = (20)/(27) xx 6500 Å = 4814.8 Å`
Discussion
43.

(vii) S_(2)O_(3)^(2-)+I_(2)to S_(2)O_(6)^(2-)+I^(-).

Answer»

SOLUTION :.
Eqalise the increase/ DECREASE in O.N by multiplying the S species by 1 and I species by 3.
`S_(2)O_(3)^(-)+3I_(2)to S_(2)O_(6)^(2-)+3I^(-)`.
Balance all other atoms EXCEPT O and H
`S_(2)O_(3)^(2-)+3I_(2)to S_(2)O_(6)^(2-)+6I^(-)`
Balance O ATOM by adding `H_2O` on the side falling short of Oxygen.
`S_(2)O_(3)^(2-)+3I_(2)+3H_(2)Oto S_(2)O_(6)^(2-)+6I^(-)`
Balance H atom by adding `H+` ion on the side falling short of hydrogen.
`S_(2)O_(3)^(2-)+3I_(2)+3H_(2)Oto S_(2)O_(6)^(2-)+6I^(-)+6H^(+)`.
Add EQUAL number of `OH^(-)` ion on the both side since hte medium is alkaline.
`S_(2)O_(3)^(2-)+3I_(2)+3H_(2)O+6OH^(-)to S_(2)O_(6)^(2-)+6I^(-)+6H^(+)+60H^(-)`.
`S_(2)O_(3)^(2-)+3I_(2)+3H_(2)O+6OH^(-)to S_(2)O_(6)^(2-)+6I^(-)+6H_(2)O`.
Discussion
44.

Write the coordination numbers of cations and anions in the following ionic compounds : (a)Zinc blende (b)Fluorite

Answer»

SOLUTION :ZINC blende=ZnS, `Zn^(2+)=4 , S^(2-)`=4
FLUORITE=`CaF_2, Ce^(2+)`=8 , `F^-` = 4
Discussion
45.

Weakest acid among the following is

Answer»

Acetic acid
Phenol
Water
Acetylene

Solution :ORDER of ACIDIC nature is
`HC -= CH LT H_(2)O lt` Phenol `lt CH_(3)COOH`
Discussion
46.

What happens to the ionic product of water if some acid is added into water ?

Answer»

SOLUTION :If REMAINS UNCHANGED.
Discussion
47.

What happens when quick lime reacts with (i) H_(2)O and (ii) CO_(2)

Answer»

Solution :`CaO + H_(2)O to Ca(OH)_(2)`(calcium hydroxide)
(ii) `CaO + CO_(2) to CaCO_(3)`(calcium CARBONATE)
Discussion
48.

Which of the group has highest +I effect ?

Answer»

`CH_(3)^(-)`
`CH_(3)CH_(2)^(-)`
`(CH_(3))_(2)-CH-`
`(CH_(3))_(3)-C-`

ANSWER :D
Discussion
49.

The rule that explain the reason for chromium to have [Ar]3d^(5)4s^(1) configuration instead of [Ar]3d^(4),4s^(2) is

Answer»

Pauli's exclusion PRINCIPLE
AUFBAU principle
more exchange energy
Heisenberg's principle 

Answer :C
Discussion
50.

Which biological pump is important for biochemical reaction in human body?

Answer»

Ca-Mg
Na-K
Fe-Cu
Ca-Fe

Answer :B
Discussion