Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

When an ideal gas undergoes undestrained expansion, no cooling occurs because the molecules

Answer»

Are above the inversion temperature 
Exert no attractive force on the other 
Do WORK EQUAL to the loss in KE 
COLLIDE without loss of energy 

Answer :B
Discussion
2.

What is syngas ? Why is it called so?

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Solution :MIXTURES of CO and `H_(2)` is CALLED syngas. It is so named because it is used for the synthesis of methanol and a number of hydrocarbons.
Discussion
3.

Which of the following ions perform important biological functions in maintenance of the ion balance and nerve impulse conduction?

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`Li^(+) RB^(+)`
`Na^(+) K^(+)`
`CS^(+) Fr^(+)`
`Rb^(+) Cs^(+)`

Answer :B
Discussion
4.

Volume strength of 1.5 N H_2O_2 is

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1.5
4.5
16.8
8.4

Solution :Volume STRENGTH of hydrogen peroxide -=Normality of hydrogen peroxide`xx`5.6
= `1.5 xx5.6`= 8.4
`underset((2xx34g))(2H_(2)O_(2))to2H_(2)O+underset((22.4liters))(O_(2)dowmarrow)`
Volume strength of Hydrogen peroxide `= ("Normality "xx "Equivalent WEIGHT of "H_(2)O_(2)xx2.24)/(68)`Volume strength of hydrogen peroxide = Normality`xx5.6`
Discussion
5.

Which elements of group shows anamolous behaviour. Explain with examples.

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Solution :First element of each group shows anamolous behaviour. Ex. Li elements of group-1, Be element of group-2. BORON to fluorine elements of group 13 to 17.
Li and Be from different covalent compound than other elements of group.
DIAGONAL Relationship : In fact the behaviour of lithium and beryllium is more similar with the second element of the following group i.e., magnesium and aluminium, respectively. This SORT of similarity is commonly REFERRED to as diagonal relationship in the periodic properties.
Discussion
6.

The stabilisation of a half filled d-orbital is more prounced than that of the p-orbital why?

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Solution :(i) Symmetry : The half filled orbitals are more symmetrical than partially filled ORBITAL and this symmetry leads to GREATER stability.
(II) Exchange energy : The ELECTRONIC with same spin in the different orbitals of the same subshell can exchange their position. Each such exchange energyand this is known as exchange energy. Greater the number of exchanges, greater the exchange energy and greater the stabitity.
In d - orbital 10 exchanges are possible but in p - orbital 6 exchange are possible.
Discussion
7.

Which of the following reaction defines Delta H _(f)^(@) ?

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`C_("diamond") + O_(2)(g) RARR CO_(2)(g)`
`(1)/(2)H_(2)(g)+(1)/(2)F_(2)(g) rarr HF(g)`
`N_(2)(g)+3H_(2)(g)rarr2NH_(3)(g)`
`CO(g)+(1)/(2)O_(2)(g)rarr CO_(2)(g)`

Answer :B
Discussion
8.

Which halides of element of group 13 exist as dimer in vapour state ?

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AL
B
Ga
In

Solution :BORON does not exist as DIMER in vapour state.
Discussion
9.

Which one of the following test is used to detect phosphorous in an organic compound?

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a)Silver NITRATE test
b)Copper OXIDE test
C)Ammonium molybdate test
d)LASSAIGNE's test

Answer :C
Discussion
10.

What transition in the hydrogen spectrum would have the same wavelength as the Balmer transition, n = 4 to n = 2 of He^(+) spectrum ?

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Solution :For H - like particles in general `bar(v) = (2pi^92) m Z^(2) e^(4))/(CH^(3)) ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2))) = RZ^(2) ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2)))`
`:.` For `He^(+)` spectrum, for Balmer transition, n = 4 to n = 2
`bar(v) = (1)/(lamda) = RZ^(2) ((1)/(2^(2)) - (1)/(4^(2))) = R xx 4 xx (3)/(16) = (3R)/(4)`
For hydrogen spectrum `bar(v) = (1)/(lamda) = R ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2))) = (3)/(4)R or (1)/(n_(1)^(2)) - (1)/(n_(2)^(2)) = (3)/(4)`
which can be so for `n_(1) = 1 and n_(2) = 2`, i.e., the transition is form n = 2 to n = 1
Discussion
11.

What are the uses of hydrogen peroxide?

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Solution :(i) `H_(2)O_(2)` is used in WATER TREATMENT to OXIDIZE pollutants.
(ii) `H_(2)O_(2)` is used as a mild antiseptic.
(iii) `H_(2)O_(2)` is used as a bleach in textile, paper and hair-care industry.
Discussion
12.

The standard readuction potential at 298 k for the followng half cell reaction are Zn^(2)+2e^(-)rarrZn(s),E^(@)=-0.7623 V Cr^(3+)(aq)+3e^(-)rarrCr(s),e^(@)=-0.740 V Cr^(3+)(aq)+3e^(-)rarrCr(s),E^(@)=-0.70 v 2H^(+)(aq)+2e^(-)rarrH_(2)(g),E^(@)=0.0V F_(2)+2e^(-)rarr 2f^(-)(aq)=2.87V which of the following is the strongest reducing agent

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CR (s)
Zn(g)
`H_(2)(g)`
`F_(2)`(g)

Solution :`(Cr^(3+)//Cr)^(@)=0-0.74` has the most negative `E^(@)` THEREFORE it is the STRONGEST reducing AGENT
Discussion
13.

Which of the following alkenes are more stable than

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SOLUTION :In a-6-HC, b-5-HC, but in GIVEN STRUCTURE only ONE 3-HC POSSIBLE
Discussion
14.

Which has maximum viscosity between ethanol and H_(2)O ?

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SOLUTION :`H_(2)O`. Because INTERMOLECULAR H - bond is STRONG in `H_(2)O`.
Discussion
15.

Which one is primary alcohol ?

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Butene-2-ol
Propan-2-ol
Butan-1-ol
2,3-Dimethlhexane-4-ol

Solution :`UNDERSET("Butanol-1")(H_(3)C-CH_(2)-CH_(2)-OVERSET(1^(@))(C)H_(2)-OH)`
Discussion
16.

What is bleaching powder? How is it prepared?

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Solution :Bleaching powder is `CA(OCI)_(2)` It is prepared by treating chlorine with MILK of LIME. `2Ca(OH)_(2) + 2CI_(2) to CaCl_(2) + underset("Bleaching powder")(Ca(OCI)_(2) + 2H_(2)O`
Discussion
17.

Which of the following will give hydrogen peroxide on hydrolysis

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`H_(2)S_(2)O_(8)`
`H_(2)SO_(5)`
`H_(3)PO_(5)`
`HClO_(4)`

Solution :H_(2) S_(2)O_(8)+ 2H_(2)O to 2H_(2)SO_(4) +H_(2)O_(2)`
`H_(2)SO_(5)+H_(2)O to H_(2)SO_(4)+H_(2)O_(2)`
`H_(3)PO_(5) + 2H_(2)O toH_(2)PO_(4) + H_(2) O_(2)`
`HCLO_(4)`on hydroliysisdoes notproduced`H_(2)O_(2)`
Discussion
18.

Which of the following hydrides are colvalent polymeric?

Answer»

Ca
Ba
Be
Mg

Answer :3
Discussion
19.

Which of the following statements in incorrect:-

Answer»

ENZYMES are in COLLOIDAL state
Enzymes are catalyst
Enzymes can CATALYSE and reaction
Urease is an enzyme

Answer :C
Discussion
20.

Why AI(HO)_(3) is insoluble in excess of NH_(4)OH but soluble in NaOH?

Answer»

Solution :NaOH is strong alkali than `NH_(4)OH and AI(OH)_(3)` being amphoteric DISSOLVES in NaOH due to the FORMATION os soluble `NaAIO_(2)`.
`I(OH)_(3)+NaOHrarrNaAIO_(2) + 2H_(2)O`
Discussion
21.

Which one of the following statements is not correct ?

Answer»

Alcohols are weaker acids than water.
Acid STRENGTH of alcohols decreases in the following ORDER `RCH_(2)OH gt R_(2)CHOH gt R_(3)COH`
Carbon-oxygen bond length in methanol , `CH_(3)OH`is shorter than that of C-O bond length in phenol.

Answer :C
Discussion
22.

Which of the following groups has highest inductive effect?

Answer»

`CH_(3)-`
`CH_(3)CH_(2)-`
`(CH_(3))_(2)CH-`
`(CH_(3))_(3) C-`

ANSWER :D
Discussion
23.

Which will form 2,2-Dibromopropane with HBr ?

Answer»

`CH_2=CH-CH_3`<BR>`CH_3-C-=CH`
`CH_3-undersetunderset(Br)(|)C=CH_2`
Both B & C

Answer :D
Discussion
24.

Which property is the same for 1.0g samples of H_(2) and CH_(4) in separate 1.0L containers at 25^(@)C?

Answer»

PRESSURE in I is the MAXIMUM.
NUMBER of molecules
Average MOLECULAR velocity
Average molecular KINETIC energy

Answer :d
Discussion
25.

Write Lewis symbols for the following atoms and ions: S and S^(2-) , Al and Al^(3+) , H and H^(-)

Answer»

Solution :`""_(16)"S"+2,8,6" "THEREFORE` Lewis symbol `=:overset(* *)S:,S^(2-) "ion" =[:UNDERSET(* *)overset(* *)S:]^(2-)`
`""_(13)AL = 2,8,3" "therefore` Lewis symbol `=*overset(*)Al.,Al^(3+)" ion"=[Al]^(3+)`
`""_(1)H =1" "therefore` Lewis symbol `=H., H^(-)" ion" = overset(*)H*`
Discussion
26.

What are decarboxylation reactions given an example

Answer»

Solution :WHENA MIXTUREOF SODIUMSALT ofcarboxylicacidand sodaline isheatedan alkane isformedduringthisprocess`CO_(2)` molccule is climinated processprocess and this processprocessknow asdecarboxylation
Discussion
27.

What makes a glass different from a solid such as quartz ? Under what conditions could quartz be converted into glass ?

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SOLUTION :Glass is an amorphous solid in which the CONSTITUENT particles (`SiO_4` TETRAHEDRA) have only a SHORT range order and there is no long range order. In quartz. the constituent particles (`SiO_4` tetrahedron) have short range as well as long range order. On melting quartz and then cooling it RAPIDLY, it is converted into glass
Discussion
28.

which among the following pairs of ions cannot be separated by H_(2)S in the presence of dilute HCl ?

Answer»

`Bi^(3+) , Sn^(4+)`
`AL^(3+), Hg^(2+)`
`Zn^(2+), Cu^(2+)`
`Ni^(2+), Cu^(2+)`

Solution :`Br^(3+)` and `Sn^(4+)` ions belong to the same group (group II). They cannot be separated by passing `H_(2)S` through the mixture solution in the presence of dilute HCl
Discussion
29.

Which of the followingare isoelectronicspeciesl.e.Thosehavingthe samenumberof electron ? Na^(+)K^(+)Mg^(2+) ,Ca^(2+) ,S^(2-) Ar

Answer»

SOLUTION :`NA^(+)Mg^(2+)` bothhave `10^(e )`so theyare ISOELECTRONIC
`K^(+)Ca^(2+)S^(2-)Ar18 e^(-)` areisoelectronic .
Discussion
30.

What is formula of V_(C ), P_(C ) T_(C ) ?

Answer»

Solution :`V_(C )=3B, P_(C )=(a)/(27b^(2)), T_(C )=(8A)/(27Rb)`
Discussion
31.

Whatis theCORRECTbond-linestructuralformulaforCH_(3)CH_(2)CH_(2)CH_2 CH_(3)?

Answer»
Discussion
32.

What is positive and negative deviation of real gas at constant pressure for pV to p ?

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SOLUTION :If curve of GRAPH is down from ideal GAS then DEVIATION will be negative. If curve of graph is up from ideal gas then deviation will be positive.
Discussion
33.

The reagent commonly used to determine harness of water titrimetrically is :

Answer»

OXALIC acid
disodium SALT EDTA
sodium citrate
sodium thiosulphate

Solution :N//A
Discussion
34.

Which of the following is /are correct about redox reactio? MnO_(4)^(ϴ)+H^(ϴ)toMn^(+2)+S_(4)O_(6)^(-2)

Answer»

1mol of `S_(2)O_(3)^(2-)`is oxidised by 8 mol of `MnO_4^(-)`
The above REDOX reaction with the change of pH from 4 to 10 will have an effect on the stiochiometry of the reaction.
Change of pH from 4 to 7 will change the nature of the product.
At pH=7 `S_(2)O_(3)^(2-)` ions are oxidised to `HSO_(4)^(-)`

Solution :a) `5e^(-)+MnO_(4)^(-)rarrMn^(2+)(n=5)`
`2S_(2)O_(3)^(2-)rarrS_(4)O_(6)^(2-)(n=2/2=1)`
Eq of `MnO_(4)^(-)-=` Eq of `S_2O_(3)^(-)`
`5xx` MOLES of `MnO_(4)^(-)-=1xx` moles of `S_2O_(3)^(2-)`
`:.1` mol of `MnO_(4)^(-)-=1xx` moles of `S_(2)O_3^(2-)`
`:.1 ` mol of `S_(2)O_(3)^(2-)=5` mol of `MnO_4^(-)`
b) pH change from 4 to 10 (acidic to strongly BASIC )
`e^(-)+MnO_(4)^(-)rarrMnO_(4)^(2-)(n=1)`
`S_(2)O_3^(-2)rarr2SO_(4)^(-2)+8e^(-)(n=8)`
Eq of `MnO_4^(-) =" Eq of " S_(2)O_3^(2-)`
`:.1` mol of `S_2O_(3)^(2-)=1/8 ` mol of `MnO_4^(-)`
HENCE with change of pH from 4 to 10, will change the stiochiometry of reaction and also changes the product.
c) pH change from 4 to 7 (acidic to neutral medium )
`3e^(+)+MnO_(4)^(-)RARR MnO_(2)(n=3)`
`S_(2)O_3^(2-) rarr 2HSO_(4)^(-)+8e^(-) (n=8)`
Hence it will also effect the stoichiometry of reaction and nature of product.
d) At `pH = 7,S_(2)O_(3)^(2-)` is oxidised to `HSO_4^(-)` ion
Discussion
35.

What happens when white phosphrous is heated with concetrated NaOH solution in an inert atmosphere of CO_(2) ?

Answer»

Solution :White phosphours REACTS with NaHO to form PHOSPHINE.
`underset("Phosphorus")(P_(4))+3NaOH+3H_(2)Ounderset(CO_(2)"atmosphere")overset("Heat")tounderset("Phoshine")(PH_(3))+underset("Sod. hypopsphite")(3NaH_(2)PO_(2))`
Discussion
36.

What is sodalime?

Answer»

SOLUTION :When quick lime or calcium oxide is mixed with SODIUM hydroxide gives SOLID MIXTURE KNOWN as sodalime [CaO + NaOH]
Discussion
37.

The threshold limit value or CO in the air is nearly ____whereas that of CO_2 is nearly _________

Answer»


ANSWER :40 PPM , 5000 ppm
Discussion
38.

Tin plague is

Answer»

Conversion of stannous SALT into STANNIC salt
Conversion of white tin into grey tin
Tin plating
Emission of sound while bending a tin plate

Solution :Tin plague or tin PEST or tin DISEASE is due to an increase in VOLUME when tin is converted into grey tin. As a result, grey tin crumbles to a powder because it is very brittle.
Discussion
39.

Which of the following is not a part of green chemistry?

Answer»

Photichemisty
Sonochemistry
Nuclear chemistry
Biochemistry

Solution :Green chemistry is the way by which the pollution or DETERIORATION to the ENVIRONMENT is MINIMISES. Nuclear chemistry is not the PART of green chemistrt.
Discussion
40.

X underset((ii) dil. H_(2)SO_(4))overset((i) HCN)rarr2-Hydroxypropinoinc acid The structure of X is

Answer»

`CH_(3)COOH`
`CH_(2) = CH - COOH`
`CH_(3)CHO`
`CH_(3)COCH_(3)`

Solution :2-Hydroxpropionic acid is an `ALPHA-` hydroxy acid. This can be prepared from aldehydes or ketones USING `HCN //H_(3)O^(+)`
Discussion
41.

Which one is gaseous pollutant of troposphere?

Answer»

`NO_x`
DUST
MIST
Fumes

Solution :`NO_x`
Discussion
42.

When an atom is placed in the magnetic field, then due to the presence of electrons in it

Answer»

the ORBITALS do not orient themselves relative to the MAGNETIC field
the orbitals orient themselves relative to the magnetic field
there are (2l + 1) different VALUES of m for each value of l
there are (2) different values of m for each value of l

Solution :Magnetic Quantum number given orientation of `e^-` in EXTERNAL field.
Discussion
43.

What is the present by mass of titanium in rutile, a mineral that contains Ti and oxygen if structure can be described as a closest packed array to oxide ions with titanium ions in one-half of the octahedral holes ? What is the oxidation number of Ti ? (Atomic mass of Ti=48)

Answer»

Solution :If no. of oxide ions =n, then octahedral HOLES =n and hence `O^(2-)` ions `=n/2`
`therefore TI:O =n/2 :n=1/2:1=1:2` Hence, FORMULA of the oxide is `TiO_2`. Molar mass of `TiO_2`=48+32 =`80 g mol^(-1)`
`therefore` % of Ti=`48/80xx100`=60% . Oxidation state of Ti in `TiO_2`=+4
Discussion
44.

Which of the following relation is true?

Answer»

`C_p GT C_V`
`C_V gt C_P`
`C_p = C_v`
`C_P = C_v =0`

SOLUTION :`C_p gt C_V`
Discussion
45.

Write the IUPAC names of the products obtained by the ozonolysis of the following compouds : Pent-2-ene

Answer»

SOLUTION :`CH_3-CH=CH-CH_2-CH_3rarrCH_3-CHO+CH_3-CH_2-CHO`
Discussion
46.

What is the frequency of photon, whose momentum is 1.1xx10^(-23) kg ms^(-2)

Answer»

`5xx10^16` HZ
`5xx10^17` Hz
`0.5xx10^18` Hz
`5xx10^18` Hz

Solution :`because E=mc^2, E=HV`
`therefore mc^2 =hv`
`v=(mc^2)/(h)=(1.1xx10^(-23)xx3xx10^8)/(6.6xx10^(-34))=5xx10^18` Hz
Discussion
47.

Which of the following is water gas ?

Answer»

`CO+N_2`
`CO_2+H_2`
`CO+H_2`
`CO+O_2`

ANSWER :C
Discussion
48.

Whatare vicinal dihalides how willyouperpane alkene from vicinal dihaldes

Answer»

SOLUTION :(i) THECOMPOUNDIN whichtwohalogenatomsare attachedto adjecentcarbon-atomarecalledas vicinaldihalids
(II) When VICINAL dihalidsare warnedwithgramulated zincin methanoltheylosea MOLECULE
Discussion
49.

Write note on covalent or molecular hydrides.

Answer»

Solution :Dihydrogen forms MOLECULAR compounds with most of the p-block elements. Most familiar examples are `CH_4, NH_3, H_2O` and HF.
For convenience hydrogen compounds of non metals have also been considered as hydrides. Being covalent, they are volatile compounds.
Molecular hydrides are further classified ACCORDING to the relative numbers of electrons and bonds in their Lewis structure into :
(i) electron-deficient, (ii) electron-precise, (iii) electron - rich hydrides.
An electron-deficient hydride, as the name suggests, has too few electrons for writing its conventional Lewis structure.
Example : Diborane `(B_2H_6)`
In fact all elements of group 13 will form electron-deficient compounds. They ACT as Lewis acids i.e., electron acceptors.
Electron-precise compounds have the REQUIRED number of electrons to write their conventional Lewis structures. All elements of group 14 form such compounds (e.g., `CH_4`) which are tetrahedral in geometry.
Electron-rich hydrides have excess electrons which are present as lone pairs. Example : Elements of group 15-17 form such compounds. (`NH_3` has 1-lone pair, `H_2O` -2 and HF-3 lone pairs).
They will behave as Lewis bases i.e., electron donors. The presence of lone pairs on HIGHLY electronegative atoms like N, O and F in hydrides results in hydrogen bond formation between the molecules. This leads to the association of molecules.
Discussion
50.

Which reaction is a source of energy in our body ?

Answer»

SOLUTION :OXIDATION of glucose( produced by the action ofenzymes on carbonhydrates, etc. that weeat as food )by the OXYGEN that we inhale
`C_(6) H_(12)O_(6) + 6O_(2) rarr6CO_(2) + 6 H_(2)O , Delta H = - 2840 kJ mol^(-1)`
Discussion