Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Which mineral is known as baryte ?

Answer»

BARIUM sulphide
Barium carbonate
Barium oxide
Barium SULPHATE

ANSWER :D
Discussion
2.

What is the hybrid state of BeCl_(2) in the vapour state ? What will be the change in hybrid state of BeCl_(2) in the solid state ?

Answer»

Solution :In the vapour state at high temperature (1200 K) , Be is SP-hybridized and hence `BeCl_(2)` in linear . In the solid state , `BeCl_(2)` is polymeric. In this structure , each Be has two covalent and two coordinate BONDS . Therefore , in the solid state . Be has `sp^(3)`-HYBRIDIZATION .
Discussion
3.

Which of the following ionization energy values for Calcium show a sudden increase ?

Answer»

THIRD
SECOND
First
Fourth

ANSWER :A
Discussion
4.

What is inert pair effect ?

Answer»

Solution :In case of elements of 4th, 5th and 6th period of p-block elements which COME after d-block elements, the electrons present in the INTERVENING d-or-and-f-orbitals do not shield the s-electrons of the valence shell effectively. As a RESULT, `ns^(2)`-electrons reamain more tightly held by the nucleus and HENCE do not participate in bonding. This is called inert PAIR effect.
Discussion
5.

The values of K_(sp) of two sparingly soluble salts NI(OH)_2 and AgCN are 2.0xx10^(-15)and 6xx10^(-17) respectively . Which salt is more soluble ? Explain .

Answer»

Solution :Value of `K_(sp)` is more than solubility is more according to this , Solubility of `Ni(OH)_2 gt` solubility of AGCN.
Suppose , solubility of `Ni(OH)_2=S_1`
solubility of AgCN = `S_2`
CALCULATION of solubility `S_1` of `Ni(OH)_2` : EQUILIBRIUM in concentrated solution of `Ni(OH)_2` .
`{:(Ni(OH)_(2(s)) hArr , Ni_((aq))^(2+) + , 2OH_((aq))^(-)),("Molarity in solution:", S_1,2S_1):}`
`therefore K_(sp) [Ni(OH)_2] = [Ni^(2+)] [OH^-]^2`
`=(S_1)(2S_1)^2`
`=(4S_1)^3=2.0xx10^(-15)`
`therefore S=(2.0/4.0 xx 10^(-15) )^(1/3)= (0.5 xx 10^(-15) )^(1/3)`
`= 0.7937 xx 10^(-5) "mol L"^(-1)`
`=7.937xx10^(-6)`
The calculation of solubility of `S_2` in AgCN :
`{:(AgCN_((s)) hArr , Ag_((aq))^(+) +, CN_((aq))^(-)),("Molar concentration", S_2,S_2):}`
`therefore K_(sp)=[Ag^+][CN^-]`
`=(S_2)(S_2)=S^2 =6xx10^(-17) = 60XX10^(-18)`
`therefore S_2=sqrt(60xx10^(-18))=7.745xx10^(-8)`
Thus solubility of `Ni(OH)_2` is `S_1= 7.937xx10^(-6)`
solubility of AgCN is `S_2= 7.745xx10^(-8)`
The solubility of `Ni(OH)_2` is more and the solubility of AgCN is less than it.
Discussion
6.

Write IUPAC name of following: (i) (CH_(3))_(4)C (b) [(CH_(3))_(2) CH] CH_(2) (c ) (CH_(3))_(2) CH CH_(2)C (CH_(3))_(3) (d) (C_(2)H_(5))_(4)C (e ) (CH_(3))_(2) CHCH_(2) CH(CH_(3)) CH_(2)CH(CH_(3))_(2) (f) (C_(2)H_(5))_(2) C(CH_(3)) CH (CH_(3))_(2)(g) (CH_(3)CH_(2))_(2) CH- C(CH_(3))_(2)- CH_(2)CH_(2)CH_(3) (h) (CH_(3))_(3)C C(CH_(3))(C_(2)H_(5)) CH_(2)CH_(2)CH_(3)

Answer»

SOLUTION :(a) 2, 2-dimethylpropane (b) 2, 4-dimethylpentane (C ) 2, 4, 4-trimethylpentane (d) 3, 3-dimethylpentane (e ) 2, 4, 6-trimethylpentane (F ) 3-ethyl-2, 3-dimethylpentane (g) 3-ethyl -4, 4-dimethylheptane (h) 3-ethyl-2, 2, 3-trimethylhexane
Discussion
7.

What is the two-dimensional coordination number of a molecule is square close packed layer ?

Answer»

Solution :In The two-dimesional square CLOSE PACKED LAYER,the atom touches 4 nearest neighouring atoms. HENCE,its corrdination number = 4.
Discussion
8.

Which of the following is saturated hydrocarbon ?

Answer»

Ethene
Propane
Ethyne
Butyne

Answer :B
Discussion
9.

There is 1 mol liquid (molar volume 100 ml) in an adiabatic container initial, pressure being 1 bar. Now the pressure is steeply increased to 100 bar ,and the volume decreased by 1 mL under constant pressure of 100 bar. Calculate DeltaH "and" DeltaE. [Given 1 bar = 10^(5) N//m^(2)]

Answer»

`DeltaE=0 J, DeltaHne0 J`
`DeltaH=990 J, DeltaE=10 J`
`DeltaE=20 J, DeltaH=890 J`
`DeltaE=0 J, DeltaH=10 J`

ANSWER :B
Discussion
10.

Which of the following is redox reaction

Answer»

`N_(2)O_5 +H_2O rarr 2HNO_3`
`AgNO_3 +KI rarr AGI + KNO_3`
`BaO_2 + H_2SO_4 rarr BaSO_4 +H_2O_2`
`SnCl_2 +HgCl_2rarr SnCl_4 +HG`

SOLUTION :`OVERSET(+2)(SnCl_2)+overset(+2)(HgCl_2)rarroverset(+4)(SnCl_4)+overset(0)(Hg)`
Discussion
11.

Write separate equations for the oxidation and reduction reactioins occurring in the following redox reaction. 2FE+2HCltoFeCl_(2)+H_(2)

Answer»

Solution :`2Fe+2HCltoFeCl_(2)+H_(2)`
`FetoFe^(2+)+2E^(-)`
`2H^(+)+2e^(-)toH_(2)`
Discussion
12.

Write the electronic configuration of alkali metals ""_(3)Li,_(11)Na, ""_(19)K,""_(37)Rb,""_(55)Cs and ""_(87)Fr

Answer»

SOLUTION :
Discussion
13.

Using s, p, d, f notations, describe the orbital with the following quantum numbers: (a) n = 2, l = 1 (b) n =4, l =0 (c) n = 5, l = 3 (d) n = 3, l = 2

Answer»

Solution :(a) n = 2, l = 1 means 2p orbital (B) n = 4, l =0 means 4s orbital
(c) n = 5, l = 3 means 5F ORBITALS (d) n = 3, l = 2 means 3d orbital
Discussion
14.

This compound shows :

Answer»

geometrical ISOMERISM
opticalisomerism
both (a) and (B)
none of these

SOLUTION :CYCLOHEXENE do not show geometrical isomerism and the compound given is incapable of showing OPTICAL isomerism.
Discussion
15.

Which is correct order of bond length ?

Answer»

`O_(2) LT O_(3) lt O_(2)^(2-)`
`O_(2) lt O_(2)^(2-) lt O_(3)`
`O_(2)^(2-) lt O_(3) lt O_(2)`
`O = O_(2)^(2-) ltO_(3)`

Solution :`O_(2) lt O_(3) lt O_(2)^(2-)`
`O_(3)` (ozone ) has V - shape it BOND length O - O`rarr ` 1.278 Å
Bond order `prop (1)/("Bond length")`
So, `O_(2) lt O_(2)^(2-)`
Discussion
16.

Whichelectronicconfigurationof an elementhas abnormallyhighdifferencebetweensecondandthirdionizationenergy ?

Answer»

`1s^(2)2s^(2)2P^(6)3S^(1)`
`1s^(2)2s^(2)2p^(6)3s^(2)3p^(1)`
`1s^(2)2s^(2)2p^(6)`
`1s^(2)2s^(2)2p^(6)3s^(2)`

Solution :The elementwhichhas two elementin the valenceshellhas highestthirdionizationenergybecausein thiscase , the 3rdelectronhas TOBE lostfromthe INERTGAS CORE. In otherwordsoption ( d) iscorrect.
Discussion
17.

which orbital does not have directional characteristic ?

Answer»

SOLUTION :s-orbital
Discussion
18.

Which one of the following is a hard base ?

Answer»

`AG^(+)`
`CR^(3+)`
`I^(-)`
`F^(-)`

Solution :Hard base is an anion small in SIZE and HENCE not easily polarizable.
Discussion
19.

Two elements X (at.mass 16) ard Y (at. mass 14) combine to form compounds A, which combine with a fixed mass of X in A, B and C is 1:3:5. If 32 parts by mas of X combines with 84 parts by mass of Y in B, then in C 16 parts by mass of X will combine with

Answer»

14 PARTS by MASS of Y
42 parts by mass of Y
70 parts by mass of Y
84 parts by mass of Y

Answer :C
Discussion
20.

What is the state of hybridisation of carbon in graphite ?

Answer»

SOLUTION :Graphite : Each CARBON atom in graphite is `sp^2` hybridised and is BOUND to three other carbon ATOMS.
Discussion
21.

Two vessels are connected by a valve of negligible volume. One container, A has 2.8 g N_2 at T_1K. The other container, B is completely evacuated. The container A is heated to T_1K, while container B is maintained at (T_2)/3 K. Volume of A is half that of B. If the valve is opened, then

Answer»

6/70 moles of `N_2` will be present in B 
The weight ratio of `N_2` in A and B vessels is 1:6 
`N_2` gas does not enter into B VESSEL 
number of moles of `N_2` released into B vessel is less than that in A vessel 

SOLUTION :`.P.` is same in both vessels.
`((0.1 - x)RT_2)/(v//2) = (x RT_3)/V`
Discussion
22.

Which of the following molecules has sufficient C bar(---)O double bond character?

Answer»

Phenol
o-Cresol
p-Cresol
all have `C BAR(---)O` DOUBLE BOND CHARACTER.

Solution :All have `C bar(......)O` character.
Discussion
23.

What is the energy in joules required to shift the electron of the hydrogen atom from the first Bohr orbit to the fifth Bohr orbit and what is the wavelength of the light emitted when the electron returns to the ground state ? The ground state energy is -2.18xx10^(-11) ergs.

Answer»

SOLUTION :As ground state electronic ENERGY is `-2.18xx10^(-11)` ergs, this means that `E_(n)=-(2.18xx10^(-11))/n^(2)` ergs
`DeltaE=E_(5)-E_(1)=2.18xx10^(-11) (1/1^(2)-1/5^(2))=2.18xx10^(-11) (24/25)=2.09xx10^(-11)` ergs
`=2.09xx10^(-18)J (1 erg =10^(-7) J)`
When electron returns to ground state (i.E., to `n=1`), energy emitted `=2.09xx10^(-11)` ergs.
As `E=hv=hc/LAMBDA or lambda=(hc)/E=((6.626xx10^(-27)" erg sec")(3xx10^(10)" cm s"^(-1)))/(2.09xx10^(-11) ergs)`
`=9.51xx10^(-6) cm=951xx10^(-8) cm=951 Å`
Discussion
24.

What are f-block elements? How many series are there? Why they are called f-block elements?

Answer»

SOLUTION :• The elements, WHOSE LAST electron enters into the f-orbital of the ante-penultimate shell (n-2) are having similar properties are called f-block elements. In these elements (n 2)f orbitas are being FILLED progressively. • The TWO rows of elements placed at the bottom of the neriodic table. They are lanthanid and actinides.
Discussion
25.

Which type of bond formed between NH_(3)andBF_(3) ?

Answer»

SOLUTION :Co-ordinate BOND.
Discussion
26.

What is W ?

Answer»

SOLUTION :W iswavefunctionis itmathermaticaloperator. It DOESNOT havephysicalmeaning .
Discussion
27.

Wurtzite has ___________ formula units per unit cell whereas zinc blende has ______ formula units per unit cell.

Answer»


ANSWER :6,4
Discussion
28.

When boron atom undergoes sp^3 hybridization

Answer»

all the four `sp^3` orbitals contain one electron in each of them
three orbitals contain one electron in each of them and the fourth one is vacant
TWO orbitals contain one electron in each of them and two OTHERS are vacant
one `sp^3` ORBITAL CONTAINS one electron pair while others have lone electrons

Answer :B
Discussion
29.

Which of the following element does not form compound with coordination number 5.

Answer»

Si
Pb
C
All

ANSWER :C
Discussion
30.

What do you understand by the form non stoichiometric hydrides ? Do you expect this type of the hydrides to be formed by alkali metals ? Justify your answer.

Answer»

Solution :The Metallic hydride are formed by many d -block and f-block elements.
However, the metals of group 7, and 9 do not form hydride. Even from group 6, only chromium forms CrH. These hydrides CONDUCT heat and electricity though not as efficiently as their parent metals do.
Unlike saline hydrides, they are almost always non-stoichiometric, being deficient in hydrogen.
For example : `LaH_(2.87), YbH_(2.55),TiH_(1.5-1.8),ZrH_(1.3-1.75), VH_(0.56), NiH_(0.6-0.7), PdH_(0.6-0.8)` etc. In such hydrides, the law of constant composition does not hold GOOD.
In these hydrides, hydrogen occupies interstitial space in the metal lattice producing distortion without any change in its type. Consequently, they were termed as interstitial hydrides.
The except for hydrides of Ni, Pd, Ce and Ac, other hydrides of this CLASS have lattice different from that of the parent metal.
The property of absorption of hydrogen on transition metals is WIDELY used in catalytic reduction / hydrogenation reactions for the preparation of large number of compounds.
Some of the metals (e.g., Pd, Pt) can accommodate a very large volume of hydrogen and, therefore, can be used as its storage media.
This property has high POTENTIAL for hydrogen storage and as a source of energy.
Discussion
31.

Which of the following gases have same rate of diffusion at constant P and T ?

Answer»

`C_2H_6`
`C_2H_4`
`N_2`
`CO`

SOLUTION :Same RATE `IMPLIES ` same M .
Discussion
32.

What is the product formed when acetylene reacts with excess of hypochlorous acid ?

Answer»

`CH_3COCl`
`ClCH_2CHO`
`Cl_2CHCHO`
`ClCH_2COOH`

ANSWER :C
Discussion
33.

Which one of the alkaline earth metals carbonate is thermally most and last stalbe. Why?

Answer»

Solution :`BaCO_(3)` is thermally most stable DUE to greater inoic CHARACTER and high LATTICE energy whereas `BaCO_(3)` is thermally LEAST stable because it is COVALENT and has less lattice energy.
Discussion
34.

what is the electronic configuration of Cu^(2+) (Z=29) of least position

Answer»

`[AR]4s^1 3d^8`
`[Ar]4s^23d^10 4p^1`
`[Ar] 4s^1 3d^10`
`[Ar] 3d^9`

Solution :`._29Cu=[Ar]3d^10 4s^1 , Cu^(2+)=[Ar] 3d^9 . 4s^0`
GROUND state of `Cu^29=1s^2 2s^2 2p^6 3s^2 3p^6 3d^10 4s^1`
`Cu^(2+)=1s^2 , 2s^2 2p^6 , 3s^2 3p^6 3d^9`
Discussion
35.

What is the temperature in the rotary Kiln used for the manufacture of cement?

Answer»

SOLUTION :1670 -1870 K
Discussion
36.

Why can dilute solutions of hydrogen peroxide not be concentrated by heating. How can be concentrated solutions of hydrogen peroxide be obtained ?

Answer»

SOLUTION :`H_(2)O_(2)` cannot be concentrated simply by heating since it decomposes much below its b.p. to give `H_(2)O` and `O_(2)`
`"" 2H_(2)O_(2) to 2H_(2)O+O_(2)`
Therefore, concentration of `H_(2)O_(2)` is CARRIED out in a NUMBER of stages,
Discussion
37.

Which of the following reaction is incorrect?

Answer»

`BF_(3)(G) + F^(-)(AQ) rarr BF_(4)^(-)`
`BF_(3)(g) + 2H_(2)O rarr [BF_(3)OH]^(-) + H_(3)O^(+)`
`BCl_(3)(g) + 3EtOH(l) rarr B(OEt)_(3)(l) + 3HCl`
`BCl_(3) (g) + 2C_(5)H_(5)N(l) rarr Cl_(3)B(C_(5)H_(5)N)_(2)(s)`

ANSWER :D
Discussion
38.

Which of the following reaction takes place when a mixture of concentrated HNO_3 and H_2SO_4 reacts on benzene at 300 K.

Answer»

Sulphonation
NITRATION
HYDROGENATION
DEHYDRATION

Solution :`(HNO_3 & H_2SO_4)` is called nitrating MIXTURE .
Discussion
39.

Which of the following metallic oxide exhibit amphoteric nature?

Answer»

`CAO`
`Al_2O_3`
`Na_2O`
`BAO`

ANSWER :B
Discussion
40.

Van dar Waal's equation explains the behaviour of rea gases. What does the van der Waal's constant 'a' indicate?

Answer»

Solution :The van der Waal.s CONSTANT .a. is a measure of the magnitude of intermolecular attractive FORCES in the GAS.
Discussion
41.

What would be the IUPAC name for an element with atomic number 222 ?

Answer»

bibibiium
bididium
didibium
bibibium

Answer :d
Discussion
42.

What are substitution reaction?

Answer»

Solution :In this REACTION an atom or a group of atoms ATTACHED to a carbon atom is replaced by a new atom or a group of atoms.
For EXAMPLE , ` underset("Bromomethane") (CH_(3)) overset ("aq.OH") to underset("Methanol")(CH_(3)OH+ Br^(oplus))`
Here, -Br is replaced by -OH group.
Discussion
43.

Which of the following graph CORRECTLY shows the variation of (x)/(m) with P according to Freundlich equation?

Answer»




ANSWER :A
Discussion
44.

Which of the following molecules constants both polar and non-polar bonds-

Answer»

`NH_(4)CL`
`HCN`
`H_(2)O_(2)`
`CH_(4)`

Answer :C
Discussion
45.

Which of the following molecule have least bond order ? O_(2) , O_(2)^(+) and O_(2)^(-) ?

Answer»

SOLUTION :`THEREFORE O_(2)^(-)` has least bond order.
Discussion
46.

Write the structures of the following compounds : (i) But-2-enoic acid (ii) But-1-en-3-yne (iii) 3, 4, 4-Trimethylhex-1-yne

Answer»

Solution :(i) `CH_(3)-CH=CH-COOH`
(II) `CH equiv C-CH=CH_(2)`
(iii) `CH_(3)-CH_(2)-underset(CH_(3))underset(|)OVERSET(CH_(3))overset(|)(C)-underset(CH_(3))underset(|)(CH)-C equiv CH`
Discussion
47.

What is quick lime? How is it prepared?

Answer»

SOLUTION :QUICK LIME is calcium oxide. It is prepared by HEATING LIMESTONE.
Discussion
48.

Which of the following represent homogeneous catalysis?

Answer»

OIL`+H_(2) overset(Ni)rarr "SATURATED FAT "`
`N_(2)(g)+3H_(2)(g) overset(FE)rarr2NH_(3)(g)`
`CH_(3)COOH+C_(2)H_(5)OH underset(H_(2)SO_(4))overset(H^(+))rarr CH_(3)COOC_(2)H_(5)+H_(2)O`
None of the above.

Solution :In Homogeneous catalysis all the reactants, products and the catalysts have the same physical state.
Discussion
49.

Which of the following is not a general characteristic of equilibria involving physical processes ?

Answer»

Equilibrium is possible only in a closed system at a given temperature.
All measurable properties of the system REMAIN constant.
All the PHYSICAL processes stop at equilibrium.
The opposing processes occur at the same RATE and there is dynamic but stable condition.

Solution :All the physical processes like melting of ice and FREEZING of water etc. do not stop at equilibrium.
Discussion
50.

The salt that is added to table salt to make it flow freely in rainy season is

Answer»

KCl
KI
`Ca_(3)(PO_(4))_(2)`
`Na_(3)PO_(4)`

SOLUTION :`Ca_(3)(PO_(4))_(2) ` Both Ca and P are needed by human beings . Also they PREVENT moisture absorbing power of other components such as `MgCl_(2) , CaCl_(2) , CaSO_(4)` and `MgSO_(4)` present in commercial sodium chloride .
Discussion