This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
{:("Column-I ","Column-II "),("A) Atm L mol"^(-1),"P)" a//Rb),("B) " sqrt((2RT)/(M)), "Q)" a//b),("C) Boyle temperature ","R)" V_m),("D) Volume of one mole","S) "u_(MP)):} |
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Answer» Solution :`T_b = a/(Rb) , V_m` = molar volume `U_(MP) = sqrt((2RT)/(M)) , a/b = ("atm - LIT"^2)/("mol"^2 XX ("lit")/("mol")) = ("atm - lit")/("mol")` . |
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| 3. |
{:("List -I Salt","List -II Kg"),((A) AgCI,P.27S^(4)),((B)PbI_(2),Q.108(S)^(5)),((C )AS_(2)S_(3),R.4S^(3)),((D)Ag_(3)PO_(4),S.S^(2)):} |
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Answer» ` Ksp = S^(2) ` ` AgCl hArr Ag^(+) +Cl ,AgCl hArr underset(s) Ag^(+)+underset( S) Cl^(+) ` ` Ksp = S^(2) ` ` AS_2 S_3 hArr 2 underset(2S) AS^(+3)+underset( 3S) 3S^(-2) ` ` K_(sp)=[As^(+3) ] ^(2)[S^(-2) ]^(3)=(2S)^(2)(3s)^(3)=108 S^(5)` ` Ag_3 PO_4 hArr 3underset( 3s) Ag^(+)+underset(S) POunderset( 4) overset(-3) ` `K_(sp)=(3S)^(3)(S)=27 S^(4) ` |
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| 4. |
Property to be determined Method used for determination{:("(P) Estimation of carbon and hydrogen in an organic compound","(i) Lassaigne's test"),("(Q) Estimation of nitrogen in aniline","(ii) Carius method"),("(R ) Estimation of chlorine in carbon tetrachloride","(iii) Liebig's method"),("(S) detection of nitrogen, sulphur and halogens","(iv) Kjeldahl's method"):} |
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Answer» |
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| 5. |
Column -I and Column -II contain four entries each. Entries of column-I are to be matched with some entries of column-II. One or more than one entries of column-I may have the matching with the same entries of column-II. |
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Answer» <P> |
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| 6. |
{:("Column-"," Column-II "),("A) Boyle's law ","P)" P_("obs") = P_("atm") +P_("water vapour")),("B) Avagadro's law ","Q)" V_1 = n_1 ((V_2)/(n_2))),("C) Charles' law ","R)" V_t = V_0 (1 + t/273)),("D) Dalton's law ","S)" V_1 = P_2((V_2)/(P_1))):} |
| Answer» SOLUTION :GAS LAWS. | |
| 7. |
Column-1 and column-II contains four entries each. Entries of column-I are to be matched with some entries of column-II .One or more than one entries of column-I may have the matching with the same entries of column-II |
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Answer» |
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| 8. |
Colour of colloids depend on which of the following factors |
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Answer» Size |
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| 9. |
Coloumn I & Column II contain data on Schrondinger Wave-Mechanical model, where symbols have their usual meanings. Match the column :- |
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Answer» |
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| 11. |
Colloids and crystalloids differ w.r.t. |
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Answer» PHYSICAL STATE |
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| 12. |
Colloidion is a colloidal solution of |
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Answer» SOURCE in water |
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| 13. |
Colloidal sulphur is used as |
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Answer» a disinfectant |
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| 14. |
Colloidal solutions of gold prepared by different methods are of different colours because of |
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Answer» variable valency of GOLD |
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| 15. |
colloidal solutions of gold prepared by different methods are of different colours because of : |
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Answer» variable valenct of GOLD |
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| 16. |
Colloidal solution cannot be obtained from two such substances which are |
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Answer» INSOLUBLE in each other |
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| 17. |
Colloidal solutioin of gold cannot be prepared by |
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Answer» BREDIG's are METHOD |
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| 18. |
Colloidal sol found effectivein treating eye diseases is |
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Answer» COLLOIDAL sulphur |
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| 19. |
Colloidal particles of soap sol in water is |
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Answer» NEGATIVELY charged |
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| 20. |
Colloidal gold is prepared by |
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Answer» MECHANICAL dispersion |
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| 21. |
Colloidal gold is given by injection |
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Answer» to act as a disinfectant |
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| 22. |
Colloid of which one of the following can prepared by electrical dispersion method as well as reduction method ? |
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Answer» Sulphur |
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| 23. |
Colloid of which one of the following can be prepared by electrical dispersion as well as reduction method? |
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Answer» Sulphur |
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| 24. |
Collodian is a 4% solution of which one of the following alcohol ether mixture |
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Answer» nitroglycerine |
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| 25. |
Collision frequency (Z) of a gas at a particular pressure |
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Answer» decreases with the rise in temperature `= (1)/(2)` collision no. `xx N//V` or `Z = (1)/(2) sqrt2 PI bar(v) sigma^(2) N//V xx N//V` `= (1)/(sqrt2) pi bar(v) sigma^(2) ((N^(2))/(V^(2)))` or `Z prop T` SINCE `bar(v) prop T` |
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| 26. |
Collision diameter is least in case of (1) H_2 , (2) He: (3) CO_2 : (4) N_2 Indicate with the number in brackets. |
| Answer» SOLUTION :He has LEAST `SIGMA.` | |
| 27. |
Collision cross-section is an area of an imaginary sphere of radius sigma around the molecule within which the centre of another molecule cannot penetrate. The volume swept by a single molecule in unit time is V=(pisigma^(2))overline(u)where overline(u) is the average speed If N^(**) is the number of molecules per unit volume, then the number of molecules within the volume V is N=VN^(**)=(pisigma^(2)overline(u))N^(**) Hence, the number of collision made by a single molecule in unit time will be Z=N=(pi sigma^(2)overline(u))N^(**) In order to account for the movements of all molecules, we must consider the average velocity along the line of centres of two coliding molecules instead of the average velocity of a single molecule . If it is assumed that, on an average, molecules collide while approaching each other perpendicularly, then the average velocity along their centres is sqrt(2)overline(u) as shown below. Number of collision made by a single molecule with other molecule per unit time is given by Z_(1)=pisigma^(2)(overline(u)_("rel"))N^(**)=sqrt(2) pisigma^(2)overline(u)N^(**) The total number of bimolecular collisions Z_(11) per unit volume per unit time is given by Z_(11)=(1)/(2)(Z_(1)N^(**))"or" Z_(11)=(1)/(2)(sqrt(2)pisigma^(2)overline(u)N^(**))N^(**)=(1)/(sqrt(2))pisigma^(2)overline(u)N^(**2) If the collsion involve two unlike molecules then the numberof collisions Z_(12) per unit volume per unit time is given as Z_(12)= pisigma _(12)^(2)(sqrt((8kT)/(pimu)))N_(1)N_(2) where N_(1) and N_(2) are the number of molecules per unit volume of the two types of molecules, sigma_(12) is the average diameter of the two molecules and mu is the reduced mass. The mean free path is the average distance travelled by a molecule between two successivecollisions. We can express it as follows : lambda=("Average distance travelled per unit time")/("NO. of collisions made by a single molecule per unit time")=(overline(u))/(Z_(1)) "or"lambda=(overline(u))/(sqrt(2)pisigma^(2)overline(u)N^(**))implies(1)/(sqrt(2)pisigma^(2)overline(u)N^(**)) For a given gas the mean free path at a particular pressure is : |
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Answer» independent to TEMPERATURE |
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| 28. |
Colligative properties of a solution depend in ………………..present in it. |
| Answer» SOLUTION :NUMBER of SOLUTE PARTICLES | |
| 29. |
Colemanite + Na_(2)CO_(3)overset(" Fused")rarr (A)+(B)+CO_(2)underset("solution)((A))+CO_(2)rarr (B)+Na_(2)CO_(3)(B)+conc.HCl rarr NaCl+underset("Acid")((C )) underset("Acid")((C ))+H_(2)O rarr underset("Acid")((D))(D)overset("strong heating")rarr (E )(E )+CuSO_(4)overset("Heated")underset("in flame")rarr underset("Blue coloured compound")((F))Compound (D) is |
| Answer» Solution :`D-H_(3)BO_(3), E-B_(2)O_(3) , F-Cu(BO_(2))_(2)` | |
| 30. |
Colemanite + Na_(2)CO_(3)overset(" Fused")rarr (A)+(B)+CO_(2)underset("solution)((A))+CO_(2)rarr (B)+Na_(2)CO_(3)(B)+conc.HCl rarr NaCl+underset("Acid")((C )) underset("Acid")((C ))+H_(2)O rarr underset("Acid")((D))(D)overset("strong heating")rarr (E )(E )+CuSO_(4)overset("Heated")underset("in flame")rarr underset("Blue coloured compound")((F))Compound (B) is |
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Answer» `Na_(2)B_(4)O_(7)` |
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| 31. |
Colemanite + Na_(2)CO_(3)overset(" Fused")rarr (A)+(B)+CO_(2)underset("solution)((A))+CO_(2)rarr (B)+Na_(2)CO_(3)(B)+conc.HCl rarr NaCl+underset("Acid")((C )) underset("Acid")((C ))+H_(2)O rarr underset("Acid")((D))(D)overset("strong heating")rarr (E )(E )+CuSO_(4)overset("Heated")underset("in flame")rarr underset("Blue coloured compound")((F))Colemanite is |
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Answer» `Ca_(2)B_(2)O_(11)` |
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| 32. |
[Co(H_2O)_6]_((aq))^(3+) + 4Cl_((aq))^(-) hArr [CoCl_4]_((aq))^(2-) + 6H_2O this reaction is endothermic and if blue colour is due to CoCl_(4(aq))^(2-). If this mixture kept in ice than what happen ? |
| Answer» Solution :This reaction is endothermic. If placed in ICE so temperature DECREASES than heat release and reaction proceed in REVERSE direction and blue colour of `CoCl_4^(2-)` decreases and PINK colour of `[Co(H_2O)_6]^(3+)`increases. | |
| 33. |
[Co(H_2O)_6]_((aq))^(3+) + 4Cl_((aq))^(-) hArr [CoCl_4]_((aq))^(2-) + 6H_2O this reaction is endothermic and if blue colour is due to CoCl_(4(aq))^(2-). If this mixture kept in ice than What happened when reaction vessel ofis kept in 80^@C containing water ? |
| Answer» Solution :Thus, temperature increase i.e., ENDOTHERMIC reaction So, reaction will be forward. The CONCENTRATION of BLUE colour product `[CoCl_4]^(2+)`is increases and blue colour BECOME dark. | |
| 34. |
[Co(H_(2)O)_(6)]^(2+)(aq)("pink")+4Cl^(-)(aq)hArr[CoCl_(4)]^(2+)(aq)("blue")+6H_(2)O(l) In the above reaction at equilibrium, the reaction mixture is blue in colour at room temperature. On cooling this mixture, it becomes pink in colour On the basis of this information, which one the following is true ? |
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Answer» `DeltaHgt0` for the FORWARD REACTION |
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| 35. |
[Co(H_2O)_6]^(2+) (aq) " (pink) " + 4Cl^(-) (aq) hArr [COCl_4]^(2-) (aq) "(blue)"+6H_2O (l) In the above reaction at equilibrium,the reaction mixture is blue in colour at room temperature. On cooling this mixture,it becomes pink in colour. On the basis of this information, which one of the following is true ? |
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Answer» `Delta gt 0` for the forward reaction `:.` Decrease in temperature, favours the reverse reaction i.e., reverse reaction is exothermic `(DELTAH LTO)` and for the forward reaction is endothermic `(DeltaH gt 0)`. |
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| 36. |
CO_((g)) + 2H_(2(g)) hArr CH_3OH_((g)) for this reaction is K_c is 0.5. If the concentration of CO and H_2 at equilibrium 0.18M and 0.22 M respectively what is the concentration of CH_3OH ? |
| Answer» SOLUTION :`4.56xx10^(-3)` M | |
| 37. |
Coefficients of MnO_(4)^(-), C_(2)O_(4)^(2-) and H^(+) in the balanced reaction, MnO_(4)^(-)+C_(2)O_(4)^(2-)+H^(+) to Mn^(2+)+CO_(2)+H_(2)O |
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Answer» 2,3 and 8 |
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| 38. |
COD of a water sample is 8ppm the weight of acidified K_(2)Cr_(2) O_(7) required to oxidise the organie matter present in one litre of water sample is |
| Answer» Answer :B | |
| 39. |
Cod Liver oil is |
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Answer» FAT DISPERSED in water |
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| 40. |
COD is a measure of |
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Answer» ORGANIC substances in water |
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| 41. |
Coconut oil on alkaline hydrolysis gives |
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Answer» Glycol |
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| 42. |
Coal tar is the main source of |
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Answer» AROMATIC compounds |
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| 43. |
Coal miners may suffer from …………. . |
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Answer» TUBERCULOSIS |
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| 45. |
Coal gas |
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Answer» BURNS with a smoky flame |
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| 46. |
CO_(3)O_(4) is an oxide of Ca (III) and Cu (II) .If its formula is CO_(x)(II)CO_(y)(II)O_(4) , then what is the value of x and y ? |
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Answer» SOLUTION :The SUM of oxidaiton number of the elements in a compound is equal to ZERO `CO_(x)(II)CO_(y)(II)O_(4)`,2x+3y -4xx2=0 or, 2x+3y=9 The only solution for this EQUATION is x=1 and y=2. |
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| 47. |
CO_(2)andC_(2)H_(2) (acetylene) are non-polar. |
| Answer» SOLUTION :Because both have LINEAR STRUCTURE. | |
| 48. |
CO_2 is used for extinguishing fire because |
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Answer» It has RELATIVELY high CRITICAL temperature |
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| 49. |
CO_(2) is not a poisnous gas but there is increase in concentration of CO_(2) in the atmosphere due to during of fossil fuels and decomposition of limestone. The increase in concentration of CO_(2) may lead to |
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Answer» increase in photosynthesis in plants |
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