This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
{:(,"Column-I",,"Column-II"),("A)", (SiO_(3))_(n)^(2n-),"P)","Cyclic silicate"),("B)","Silicone","Q)","Chain silicate"),("D)",(Si_(4)O_(11))_(n)^(6n-),"S)","Pyrosilicate"):} |
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Answer» `rarr` Chain silicate have `(SiO_(3))_(N)^(-2n) ` & ` ( Si_(4)O_(11))_(n)^(-6N)` as general formula |
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| 2. |
{:("Column-I","Column-II"),((A) NO_(3)^(-),(P)"Numerical value of oxidation number of central ato.m is equal to its covalency in the given species "),((B) CO_(3)^(2-), (Q) "Negative charge on central atom "),((C) ICI_(4)^(-),(R)"Maximum possible oxidation number of central atom "),((D) SO_(3)^(2),(S)"Minimum possible oxidation number of surrounding atom "),("",(T) "One co-ordinate covalent bond is present"):} |
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| 3. |
Identify the reactions in which dichromate acts as an oxidising reagent . I . Cr_(2)O_(7)^(2)+6Fe^(2+)+14H^(+)rarr 2Cr^(3+) +6Fe^(3+)+7H_(2)O II. Cr_(2)O_(7)^(2-)+2OH^(-1) rarr2CrO_(4)^(2-)+H_(2)O III. Cr_(2)O_(7)^(2-)+6I+14H^(+)rarr 2Cr^(3+)+3I_(2)+7H_(2)O IV. Na_(2)Cr_(2)O_(7)+2KCI rarr K_(2)Cr_(2)O_(7)+2NaCI |
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| 4. |
{:("Column-I","Column-II"),("A) "NH_(3),"P) EF = MF"),("B) "N_(2)H_(4),"Q) MF = "(EF)_(2)),("C) "N_(3)H,"R) Maximum percentage of nitrogen by mass "),("D) "C_(2)N_(2),"S) Least percentage of nitrogen by mass"):} |
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Answer» `N_(3)H` (hydrazoic acid) % of nitrogen = `(42)/(43)XX100` `C_(2)N_(2)` (cyanogen) % of nitrogen = `(28)/(52)xx100` |
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| 5. |
{:("Column -I","Column-II"),((A) (H_(2)O)_(n),(P)"Ionic bond "),((B) C_(2)H_(2),(Q)"Covalent bond"),((C) KCN ,(R) "Co-ordinate bond "),((D) K_(4)[Fe(CN)_(6)],(S)"Hydrogen bond"):} |
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| 6. |
{:("Column I","Column II"),("(A) Emulsion","p Colloidal solution"),("(B) sol","q Dye test"),("(C) Tyndall effect ","r Milk"),("(D) Colligative properties ","s Haemoglobin"):} |
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| 7. |
{:("Column I","Column II"),("(A) Electrophores","p Movement of molecules of dispersion medium"),("(B) Electro-osmosis","q Determination at Avogador's number"),("(C) Tyndall effect","r Ultra-microscope"),("(D) Brownian motion","s Determination of charge on colloidal particle."):} |
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| 8. |
{:("Column-I","Column-II"),("A) "Cu^(2+)+I^(-)rarrCu_(2)I_(2),"P) Eq.wt.=M.wt/6"),("B) "Cu+Cl^(-)rarrCuCl_(2)+...,"Q) Eq.wt.o=M.wt/5"),("C) "MnO_(4)^(-)+H^(+)+e^(-)rarrMn^(2+)+...,"R) Eq.wt.=M.wt/1"),("D) "Cr_(2)O_(7)^(2-)rarrCr_(2)O_(3)....,"S)Eq.wt.=M.wt/2"):} |
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Answer» B) `Cu^(0)rarrCu^(+2)impliesn-f=2` C) `MN^(+7)rarrMn^(+2)impliesn-f=5` D) `Cr_(2)^(+6)rarrCr^(+3)impliesn-f=3xx2=6` |
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| 9. |
{:("Column I","Column II"),("(A) Chemisorption ","p Exothermic"),("(B) Physical adsorption","q Endothermic"),("(C) Desorption","r Removal of adsorbed material "),("(D) Activation of adsorbent","s Specifi in nature"):} |
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| 10. |
{:("Column-I","Column-II"),("A) 22.4 volume "H_(2)O_(2),"P) 11.2 litres"),("B) 32 g oxygen","Q) "9.034xx10^(23)" atoms"),("C) 11.2 L "CO_(2)" at STP","R) 2 mole"L^(-1)),("D) 1 gram equivalent hydrogen at STP","S) "9.64xx10^(24)" electron"):} |
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Answer» 22.4bol `H_(2)O_(2)=22.4xx3.03=67.87g//L` `=~~2" moles/L"` B) 32 G oxygen = 1 mole oxygen = `6.023xx10^(23)` MOLECULES `=6.023xx10^(23)xx16=9.64xx10^(24)` ELECTRONS C) 11.2L `CO_(2)` at STP `=(1)/(2)` mole `CO_(2)=(1)/(2)xx6.023xx10^(23)` molecules `=(1)/(2)xx6.023xx10^(23)xx3` ATOM `=9.034xx10^(23)` atom D) 1 gram equivalent HYDROGEN = 1 g hydrogen |
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| 11. |
{:("Column-I","Column-II"),("A) 16g of "O_(2),"P) 1gm atom of O"),("B) Gram molar volume of "H_(2)O,"Q) 22.4 lit at STP"),("C) 18 g of "H_(2)O,"R) 18 ml"),("D) 1/2 mole "O_(2)+1" gm atom of "H_(2),"S) 11.2 lit at STP"):} |
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Answer» `=(1)/(2)xxg` atoms of O B) molar VOL = 22.4 lit at STP C) 18g `H_(2)O` implies 1 mole implies 1 mole of O = 18ml = 1GM atom of O D) total moles = `(1)/(2)+(1)/(2)=1 implies 22.4` lit at STP `(1)/(2)` mole `O_(2)=(1)/(2)xx2g` atoms of O |
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| 12. |
{:("Column-I","Column-II"),("A) 1.2g of carbon","P) "4.8xx10^(23)" atoms"),("B) 3g of "CO_(2),"Q) "9.034xx10^(23)" atoms"),("C) 11.2 L "CO_(2)" at S.T.P.","Q) 0.1 moles"),("D) 0.2 moles "NH_(3),"S) "9.64xx10^(24)" electrons"):} |
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Answer» B) 32g `O_(2)` implies 1 mole = `6XX10^(23)xx` atoms `=12xx8xx10^(23)e^(-)` C) 11.2L `CO_(2)` `implies (1)/(2)` mole = `(1)/(2)xx6xx10^(23)xx` 3atoms D) 0.2 moles `NH_(3)=0.2xx6xx10^(23)xx4` atoms |
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| 13. |
{:("Column-I","Column-II"),("A) 1 mole NaOH","P) 0.5 mole "H_(2)SO_(4)),("B)0.5 mole "Ca(OH)_(2),"Q) 1 mole HCl"),("C) 2 moles "KMnO_(2),"R) 16 moles Mohr.s salt solution"),("D) 1 mole "K_(2)Cr_(2)O_(7),"S) 5 moles oxalic acid solution"):} |
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| 14. |
{:(,"Column I",,"Column II (pH)"),((A),"MilK",(p),2.2),((B),"Human saliva",(q),6.4),((C),"Human blood",(r),6.8),((D),"Lemon juice",(s),7.4):} |
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Answer» A-p, B-q, C-s, D-r |
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| 15. |
{:(,"Column I",,"Column II "), ((A),B_(2),(p),"Paramagnetic"),((B),N_(2),(q),"Undergoes oxidation "),((C),O_(2)^(-),(r),"Undergoes reduction"),((D),O_(2) ,(s),"Bond order"ge 2 ),(,,(t),"Mixing of s and p-orbitals"):} |
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Answer» It containsunpaired electrons . Hence, it is paramagnetic . Highest occupied molecular orbitals are bonding . Addition of electron increases stability . Hence , it undergoes reduction . BOND order = 1. As 2s and 2p orbitlas are close , mixing of these orbitals taken place. `(B) N_(2)= KK sigma (2s)^(2) sigma^(**) (2s)^(2) pi (2p_(x))^(2) pi(2p_(y))^(2) sigma(2p_(z))^(2)` All electrons are paired . Hence , it is diamagnetic . All orbitalsare completely filled . It is stable. Hence , it can neither gain nor lose electons/s, i.e., it does not undergo oxidition or reduction . Its bond order = 3.2 and 2p orbitals are close . Hence , there is 2s - 2p mixing . `(C) O_(2)^(-)= KK sigma (2s)^(2) sigma^(**) (2s)^(2)sigma (2p_(z))^(2) pi (2p_(x))^(2)` `pi(2p_(y))^(2) pi^(**)(2p_(x))^(2) pi^(**) (2p_(y))^(1)` Itis paramagnetic . Loss of electrons from antibonding molecular orbitals orbitals will increase stability. Hence, it undergoes OXIDATION . Bond order = 1.5 . 2s and 2p orbitals have LARGE DIFFERNECE in energy . There is no 2s - 2pmixing . `(D) O_(2)= KK sigma (2s)^(2) sigma^(**) (2s)^(2)sigma (2p_(z))^(2) pi (2p_(x))^(2)` `pi(2p_(y))^(2) pi^(**)(2p_(x))^(1) pi^(**) (2p_(y)^(1))` It is paramagnetic .Lose of electrons frm anti- bonding molecular orbitals will increase stability . Hence , it undergoes oxidation . Bond order 2. As 2s and 2p have large difference in energy , there is no 2s- 2p mixing |
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| 16. |
{:("Column - I (Vol. of NaOH added)" ,, "Column- II (pH of resultant solution)") , ("A) 150 mL of NaOH" ,, "P)" pH = p^(ka2)), ("B)" 75 mL of NaOH ,, "Q)" = pH = p^(KaI)), ("C)" 25 mL of NaOH ,, "R)" pH = 7 + [(pKa_(3) + logc)/(2)]) , ("D)" 100 mL of NaOH ,, "S)" pH= (P_(k_(a2)) + p_(K_(a3)))/(2)):} |
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Answer» ` underset( _) ( 2.5 m " mole ") ` `pH =P^(Ka_1) ` Further addition of 25 ml NaOH , only`NaH_2PO_4` ( 5 m moles )will be formed Further additionof 25 mlNaOH ( Total 75 ml)`{:(NaH_2PO_4+,NaOH to , Na_2 HPO_4 + H_2O),( 5 m " moles" , 2.5 m " moles ", 0), ( 2.5 , -, -), ( 2.5 m " moles " , - ,2.5 m " moles "):}` ` therefore pH =p^(ka_2) ` Further additionof 25 ml NaOH , only ` Na_2 HPO_4` ( 5 m moles )wll be formed ` pH= (P^(Ka_2)+ P^(Ka_3))/( 2) ` Further addition of 25 ml ( Total 125 ml) ` {:( Na_2HPO_4 +, NaOH to, Na_3PO_4+H_2O) ,( 5 m " moles " , 2.5 m " moles " ,0), (underset(-) (2.5 m " moles ") , - , 2.5 m " moles " ):} ` ` therefore pH = pK^(a_3),` Furtheraddition of 25 ml (Total 150 ml)only`Na_3PO_4 ` salt will be formed ` pH =7+ ( p ^(Ka_3))/(2) + ( 1)/(2)log C ` |
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| 17. |
{:("Column I (Type of crystal)", "Column II (Example/Property)"),("(A) Ionic solids" , "(p) Dry ice"),("(B) Molecular solids", "(q) Brass"),("(C) Covalent solids" , "(r) Generally insulators"),("(D) Metallic solids" , "(s) Generally have low melting points"):} |
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| 18. |
{:("Column I (Type of crystal)", " Column II (Location of cations/anions"),("(A) NaCl", " (p) Cations -fcc, Anions- all tetrahedral voids"),("(B) ZnS" , "(q) Anions -fcc, Cations-all tetrahedral voids"),("(C) CaF"_(2), "(r) Anions-fcc, Cations-all octahedral voids"),("(D) Na"_(2)O, "(s) Anions-fcc,Cations - aternate tetrahedral voids"):} |
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Answer» A-r, B-s , C-p , D-q |
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| 19. |
{:(,"Column I (Solvent)",,"Column II (Nature)",),((A),"Methyl alcohol"(CH_(3)OH),(p),"Protophilic",),((B),"Benzene" (C_(6)H_(6)),(q),"Protogenic",),((C),"Ammonia" (NH_(3)),(r),"Amphiprotic",),((D),"Acetic acid" (CH_(3)CO OH),(s),"Aprotic",):} |
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| 20. |
{:("Column - I (Reaction)","Column-II(Eq wt)"),("A) " NH_3 rarrNO_3^(-),"P)" M//3),("B) " FeC_(2)O_(4)rarrFe^(3+)+2CO_(3)^(2-),"Q)" M//6),("C) "H_(2)SO_(5)rarrS_(8),"R)"M//8),("D) "KMnO_(4)rarrMn^(2+),"S)" M//5),(,"T) reducing agent"):} |
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Answer» B) `FeC_(2)O_(4) rarr Fe^(3+)+2CO_(3)^(2-)0M//3` , reducing agent C) `H_(2)SO_(5)rarrS_(8) -M//6` D) `KMnO_(4) rarr Mn^(2+)-M//5` |
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| 21. |
{:("Column - I (Reaction)","Column-II(Eq wt)"),("A) "KMnO_(4)overset(H^(+))rarrMn^(+2),"P)" M//2),("B) " MgC_(2)O_(4)rarrMg^(2+)+CO_(2),"Q)" M//5),("C) "K_(2)Cr_(2)O_(7)rarrCr^(3+),"R)"M//6),("D) "CrO_(5)rarrCr_(2)O^(3),"S)" M//3),(,"T) Oxidising agent"):} |
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Answer» B) `MgC_(2)O_(4)rarr Mg^(2+)+CO_(2)-M//2` C) `K_2Cr_(2)O_(7) rarr Cr(+3) -M//3` , Oxidising agent D) `CrO_(5) rarrCr_(2)O_3-M//3` , Oxidising agent |
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| 22. |
{:("Column I (Reaction)","Column II (Product)"),((A)Cu+dil.HNO_(3),(q)NO_(2)),((B)Cu+conc.HNO_(3),(q)NO_(2)),((C)Zn+dil.HNO_(3),(r)N_(2)O),((D)Zn+conc.HNO_(3),(s)Cu(NO_(3))_(2)),(,(t)Zn(NO_(3))_(2)):} |
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| 23. |
{:(,"Column I( Solutions mixed)",,"Column II ( Heat evolved)"),((A),500 mL of 0.1 "M HCl acid"+200 mL of 0.2 M NaOH "solution",(p),4568J),((B),200 mLof 0.2MH_(2)SO_(4) + 400 mL of 0.5 M KOH "solution",(q),2284J),((C ),500 mL of 0.1M HCl+ 500 mL of 0.1 M NH_(4)OH,(r),2760 J),((D),500 mL of 0.1 M "acetic acid " + 500 mL of 0.1 M NaOH ,(s),2575J):} (a)A-r,B-p,C-s,D-q(b) A-p, B-r, C-q,D-s(c )A-q,B-p, C-s, D-r(d) A-,B-s,C-p,D-r |
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Answer» B. Refer to Solved Problem C. Enthalpy of neutralization`NH_(4)OH` with HCl`= 51.5 kJ mol^(-1)=51500 J mol^(-1)` 500mLof 0.1 M `NH_94)OH =500 XX 0.1` millimoles`=50` millimole`= 0.05` mole `:. `Enthalpy of neutralisation. `=51500 xx 0.05 J = 2575J`. D. Enthalpy of neutralisation of ACETICACID with NAOH `=55.2 kJ mol^(-1) = 55200 J mol^(-1)` 500mL of 0.1 M NaOh` =500 xx 0.1 ` millimole `= 50` millimole `= 0.05 ` mole `:. `Enthalpy ofneutralisation `=55 200 xx 0.05 J = 2760 J`. |
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| 24. |
{:("Column-I (mixed in equal volumes)" ,, "Column -II (Nature of solution)") , ( "A)" 0.2 M HCN + 0.1 M KOH ,, "P) Strong base"), ("B)" 0.2M HCl + 0.1 M KCN ,, "Q) basic buffer") , ("C)" 0.2 M NH_(3) + 0.1 M HCl ,, "R) acidic buffer"), ("D)" 0.2 M KOH + 0.1 M NH_(4) Cl ,, "S) Strong acid"):} |
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Answer» ` rArr ` acid buffer (b)Incomplete neutralization of strong acid ` rArr ` LEFT ( C )Incomplete neutralization of weak base `rArr ` BASIC buffer (d)Incomplete neutralization of strong base `rArr` base left |
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| 25. |
{:("List - I","List - II "),("(mixed in equal volumes)","(Nature of solution)"),((A)0.2 "M HCN" + 0.1 M "KOH", (P)"Strong base"),((B) 0.2 "M HCl" + 0.1 "M KCN", (Q)"basic buffer"),((C)0.2 M NH_(3) + 0.1 M HCl, (R)"acidic buffer"),((D) 0.2 M KOH + 0.1 M NH_(4) Cl,(S)" Strong acid"):} |
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Answer» ` rArr ` acid buffer (b)Incomplete neutralization of STRONG acid ` rArr ` LEFT ( C )Incomplete neutralization of weak BASE `rArr ` basic buffer (d)Incomplete neutralization of strong base `rArr` base left |
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| 26. |
Match the following :{:("(P) Equivalent mass of an organic acid","(i) Depression in freezing point"),("(Q) Equivalent mass of an organic base","(ii) Victor Meyer's method"),("(R ) Molecular mass of a volatile organic solid","(iii) Platinichloride method"),("(S) Molecular mass of a non-volatile organic solid","(iv) Silver salt method"):} |
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| 27. |
Column-I lists some of Group reagents which give characteristiccolout/precipitate mentioned cations in column-II. Match each entry of column-I with those given in column-II. |
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| 28. |
Column-I lists some of elements whose salts impart characteristics colour in oxidising flame in the borax bead test. These are mentioned in column-II. Match each entries from column-I and column-II. |
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| 29. |
Column-I lists some of elements whose salts give characteristics colour mentioned in column-II. Match eacy entry of column-I with those given in column-II. |
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| 30. |
{:(,"Column I (Gas) ",,"Column II"( "Ratio " gamma=C_(p) //C_(v))),((A),"Ammonia", (p),1.20),((B),"Carbon dioxide",(q),1.30),((C ),"Carbon monoxide ",(r),1.40),((D),"Helium ",(s),1.66):} (a) A-s,B-r,C-q,D-p(b)A-p,B-q,C-r,D-s(c ) A-s,B-q,C-r,D-p(d) A-r,B-s,C-q,D-p |
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| 31. |
{:("Column I (Defect)", " Column II (Effect)"),("(A) Schottky defect", "(p) Crystal becomes coloured"),("(B) Doping silicon with aluminium" , "(q) n-type semiconductor is formed"),("(C) Doping silicon with arsenic" , "(r) p-type semiconductor is formed "),( "(D) Heating NaCl crystal in presence of sodium vapour" , (s) "Density of the crystal decreases"):} |
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Answer» A-s, B-q, C-r, D-p |
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| 32. |
Column I (Ionizationenthalpy inKj mol^(-1))Column II(Electron gainenthalpy in kJ mol^(-1)) {:((A),,2080,,(p)-328 ),((B),,1314,,(q) + 116),(( c),,1402,,(r )-141),((D) ,,1681,,(s ) +31):} |
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Answer» <P>`A-q , B-s , C- r , D- p` |
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| 33. |
{:("Column I (Defect)", " Column II (Efect)"), ("(A) Ferrites" , "(p) Ferromagnetic"),("(B)" CrO_(2) , "(q) Paramagnetic"),("(C) Nitric oxide (NO)" , "(r) Ferrimagnetic"),("(D) Manganese dioxide" (MnO_(2)) , "(s) Antiferromagnetic"):} |
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Answer» A-r, B-q, C-p, D-s |
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| 34. |
{:("Column I (Crystal)" , "Column II (Crystal system)"),("(A)" "CuSO"_(4).5 H_(2)O, "(p) Hexagonal"),("(B)" Na_(2)SO_(4).10 H_(2)O, "(q) Cubic"),("(C) Dimaond" , "(r) Monoclinic"),(" (D) Graphite" , "(s) Triclinic"):} |
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Answer» A-r,B-s, C-p, D-q |
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| 35. |
{:("Column" (I) , "Column"(II)), ((a) "Presence of halogen" , P. HNO_(3)//AgNO_(3)), ((b) "Presence of sulphur", Q. Na_(2)[Fe(CN)_(5)NO]) , ((c) "Presence of nitrogen" , R. Co(NO_(3))_(2)), ((d) "Presence of"P "and" S , S. FeCl_(3)):} |
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Answer» <P> |
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| 36. |
{:("Column-I", "Column-II"),((A)"Boron ",(P)"Vacant orbital in valency shell "),((B)"Phosphorus ",(Q)"Unpaired electron in valency shell "),((C)"Iron ",(R)"Non-metallic properties "),((D)"Calcium",(S)"No unpaired electron "),("",(T)X_(2)O_(3)"type (empirical ratio) oxide formation"):} |
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| 37. |
Match the molecular species in Column-I and their magnetic and molecular orbital properties in Column-II : {:("Column-I","Column-II"),((A)O_(2),(P)"Bond order = 2 "),((B) N_(2),(Q)"Oiamagnetic "),((C)H_(2),(R)"Bond order= 3"),((D)O_(2)^(2-),(S) "Paramagnetic"):} |
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| 38. |
{:("List-I"," ""List-II"),((A)SiF_(4),P."Lewis acid"),((B)CO_(2),Q."Lewis base"),((C) SO_(2),R."Bronstead acid"),((D)NH_(3),S."Bronstead base"):} |
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Answer» ` CO_2 ` cannot add or give ` H^(+) ` ` SO_2`has lone PAIR ` NH_3 ` can give and TAKE `H^(+) `and has lone pair |
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| 39. |
Column-I Column-II (i) Critical temperature (a) Boiling point (ii) Vapour pressure (b) Spherical shape of water droplet (iii) Viscosity (c ) Liquefaction of gases (iv) Surface tension (d) Flow of liquids. |
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| 40. |
Column-I Column-II (i) Boyle's Law (a) V alpha n at constnt T & P (ii) Charle's Law (b) P_(" total ")=p_1+p_2+p_3+"………." at constant T & V (iii) Dalton's Law (c ) V alpha T at constant n & p (iv) Avogadro Law (d) p alpha 1"/"V at constant n & P |
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| 41. |
Match the Column-I with Column-II : {:("List-I", " " "List-II"),((A)CuSO_(4),P."Cationic interaction"),((B)Na_(2)CO_(3),Q."Anionic interaction"),((C)FeCI_(3),R.pH gt 7),((D) K_(2)SO_(4),S. "pH" lt7),(,T."No hydrolysis of ions"):} |
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Answer» ` CO_3^(2-) ` get hydrolysis `rArr ` BASIC solution `rArr pH gt 7` ` Fe^(+3) ` gets hydrolysis `rArr` acid solution `rArr pH lt 7` ` K^(+)and SO_4^(2-) `dont get HYDROLYSED |
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| 42. |
{:("Column-I", ""Column-II), ("(Reaction intermediate)", "(Electronic configuration and valence state)"),("A) Carbocation", "P) Sextet and bivalent"), ("B) Carbanion", "Q) Sextet and trivalent"), ("C) Free radicals", "R) Octet and trivalent"), ("D) Carbene", "S) Heptet and trivalent"):} |
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| 43. |
{:("Column" (I) , "Column" (II)) , ((a) Ph-overset(O)overset(||)(C)-CH_(3) , P. "Aldol condensation"), ((b) CH_(3)-overset(O)overset(||)(C)-H , Q. "Positive iodoform test"), ((c) Ph-overset(O)overset(||)(C)-H , R. "Negative test of Fehling's solution"), ((d) CH_(3)CH_(2)OH , S. "Oxidation with" Cu//Delta):} |
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Answer» <P> |
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| 44. |
{:(,,"Column I ",,"Column II "),((A) ,,"Noble gas ",,(p) [Xe] 5d^(1) 6s^(2) ),((B) ,,"Representiative elemetn ",,(q) [Rn] 6d^(2) 7s^(2)),((C ),,"Transition element ",,(r ) 1s^(2)),(( D) ,,"Inner transitionelement ",,( s) [Kr] 5s^(2) ):} |
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Answer» `A-R , B - s, C- p , D- Q` |
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| 45. |
{:("Column-I ","Column-II "),("A) Low pressure ","P)" Z=1 ),("B) High pressure ","Q) "Z != 1 ),("C) Very high temperature ","R) "Pb < a/V ),("D) Very low pressure ","S) "Pb > a/V):} |
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Answer» high `P , Z > 1 implies` REPULSIVE force dominate high `T implies V to OO implies ` idal gas `implies Z = 1`. very low `P implies V to 00 implies Z = 1.` |
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| 46. |
{:("Column-I"," Column-II "),("A) If temperature of given gas is increased ","P) Average speed of gas molecules will increase "),("B) If the pressure of the given gas increased ","Q) Root mean square speed of gas molecule "),("at constant temperature ","will increase "),("C) If the density of a given gas is lowered ","R) Most probable speed of gas molecule will "),("at constant temperature ","increase "),("D) If the volume of a given gas is increased ","S) Speed of gas molecules will not change "),("at constant temperature ",):} |
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Answer» SOLUTION :a) `T UARR` all velocities `uarr` b,C,d) at constant T velocities don.t CHANGE. |
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| 47. |
{:("Column-I ","Column-II "),("A) Hydrogen gas (P = 200 atm, T = 273K) ","P) Compressibility factor "!= 1 ),("B) Hydrogen gas "(P ~~ 0,T = 273K) ,"Q) Attractive forces are dominant "),("C)" CO_2 (P= 1 atm, T = 273K) ,"R)" PV = nRT ),("D) Real gas with very large molar volume ","S)" P(V - nb) = nRT ):} |
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Answer» Solution :a) `H_2` high `P implies Z > 1 implies ` rep. dominate and `Z = 1 + (Pb)/(RT)` b) `H_2` at `P = 0 implies Z = 1` c) `CO_2` at low `P implies Z < 1 implies` at FORCE dominate `d) V PROP oo implies Z to 1`. |
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| 48. |
{:(,"ColumnI ","Column II "),("(A)" ,"He, Ne , Ar","(p) Representativeelements"),("( B)" ,"Fr, Ra, Ar","(q) Lanthanoids "),("(c )" ,"Ce, Gd, Yb","( r)Noble gases "),("(D)" ,"Rb, Ga, C1","(s )Radioactive elements "):} |
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Answer» <P>`A-s , B- p , C-q , D- r` |
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| 49. |
{:("Column-I", "Column-II"), ("A) "CH_(3)^(+), "P) Electrically neutral"), ("B) "CH_(3)^(-), "Q) having "6e^(-)"in the outer shell"), ("C) "CH_(3)^(*), "R) "sp_(2)), ("D) ":CH_(2), "S) "sp^(3)):} |
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Answer» ` CH_3^(-) ` - `sp^(3)` `CH_3^(*)` - Electrically NEUTRAL , `sp^(3)` `:CH_2 ` - Electrically neutral, `6e^(-)` in the outer shell , `sp^(2)` |
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| 50. |
{:("Column-I", "Column-II"), ( "A) "CH_(2)=CH-Cl, "P) +I effect"), ("B) "CH_(3)-CH=CH-O-CH_(3), "Q) -I effect"), ("C) "CH_(3)CH_(2)CH_(2)-Cl, "R) Hyperconjugation"), ("D) "CH_(3)-CH_(2)-CH_(2)-CH_(3), "S) Resonance"):} |
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Answer» Methoxy propene - +1, -I, hyperconjugation, Resonance PROPYL chloride - -I effect BUTANE - +I effect |
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