Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Temporary hardness of water can be removed (A) By Clark.s process (B) By Boiling water

Answer»

Only A
Only B
BothA and B
NIETHER A nor B

Answer :B
Discussion
2.

Temporary hardness of water can be removed

Answer»

By boiling
By freezing
By the addition of NaCl
By the addition of `Na_2SO_4`

SOLUTION :TEMPORARY HARDNESS of water can be REMOVED by boiling & clark.s method
Discussion
3.

Temperature pressure and molar concentration are the three factors which can disturb the equilibrium in areversiblereaction. Their effect is governedby Le Chatelier's principle .Whereas high concentration of the reactants always favours the formation of the products irrespective of its nature the effect of temperature and pressure depends upon the nature of the reaction . pressure does not disturb theequilibrium point in a reaction in which the reactants and products have same number of moles in the gaseous state. For a reaction CO(g) +H_(2)O(g) hArr CO_(2) (g) +H_(2) (g) at a given temperature the equilibrium amount of CO_(2) (g) can be increased by

Answer»

adding a catalyst
adding and INERT gas
DECREASING the volume of the container
increasing theamount of CO (g).

SOLUTION :Is the CORRECT answer.
Discussion
4.

Temperorary hardness is caused due to the presence of:

Answer»

`CaSO_(4)`
`CaCl_(2)`
`CaCO_(3)`
`Ca(HCO_(3))_(2)`.

ANSWER :d
Discussion
5.

Temperature of1 mole of a gas is increased by 1^(@) at constant pressure. Work done is

Answer»

2 cal
3 cal
4 cal
5 cal

Solution :At temp. T, PV`=`RT
When temp. is INCREASED by `1^(@)`, at CONSTANT pressure, suppose volume increased by `DELTAV`
`:. P ( V+DeltaV) = R (T+1) `or`PV + P DeltaV =RT + R `
But`PV =RT :. P Delta V = R`,
i.e., work done `=R= 2 cal`.
Discussion
6.

Temperature of onemole of helium gas is increased by 1^(@)C. Hence,the increasein its internal energy will be

Answer»

2 CAL
3 cal
4 cal
5 cal

Solution :`C_(v) = ((DeltaU)/(DeltaT))_(V)`or` DeltaU = C_(v)DeltaT`
But for MONOATOMIC GAS,
`C_(v)= (3)/(2) R`. Also `DeltaT =1^(@)` (Given)
Hence, `DeltaU = C_(v)DeltaT = (3)/(2) R = (3)/(2) xx2 = 3 cal`
Discussion
7.

Temperature of an ideal gas increases in:

Answer»

Adiabatic expansion
adiabatic compression
ISOTHERMAL expansion
isobaric expansion

Solution :(a) `q = 0 rArr Delta E = W`
Expansion `rArr W = - Ve rArr Delta E lt 0 rArr Delta T lt 0`
(b) `q=0, W gt 0, Delta E = W rarr Delta E gt 0 rArr Delta T gt 0`
(C ) Isothermal `rArr Delta T = 0`
(d) Isobasc expansion `rArr nC_(P) Delta T = nC_(P) Delta T - nR Delta T`
`nR Delta T = nDelta T (C_(P) - C_(v)) gt 0 rArr Delta T gt 0`
Discussion
8.

Temperature of a flask becomes 27^(@)C to 277^(@)C. At 277^(@)C temperature 0.1 dm^(3) gas bubble out from the flask then calculate volume of flask.

Answer»


ANSWER :`0.15 DM^(3)`
Discussion
9.

Temperature of a gas is tK. What would be the temperature at which volume and pressure, both will reduced to half of the initial values

Answer»

t/2 
t/4 
t/3 
t/8 

ANSWER :B
Discussion
10.

Temperature of 1 mole of a gas is increased by 2^(@)C at constant pressure. Work done is :

Answer»

R
2R
`R//2`
3R

Solution :`w=-nR(T_(2)-T_(1)),w=-1R(2)=-2R`
Discussion
11.

Temperature below which the gas does not obey ideal gas law is

Answer»

CRITICAL TEMPERATURE
Inversiontemperature
Boyletemperature
Reducedtemperature

ANSWER :C
Discussion
12.

The temperatures at which real gases obey the ideal gas laws over a wide range of pressure is called

Answer»

INVERSION TEMPERATURE
Boyle's temperature
Critical temperature
None of these

Answer :B
Discussion
13.

Temperature at the foot of a mountain is 30^@C and pressure is 760mm whereas at the top of the mountain these are 0^@C and 710mm. Ratio of the densities of the air at the foot and the top of the mountain is ____(approx)

Answer»


SOLUTION :`(d_1)/(d_2) = (P_1//T_1)/(P_2//T_2) = (760//303)/(710//273) ~~ 1`
Discussion
14.

Temperature at the foot of a mountain is 30^(@)C and pressure is 760 mm whereas at the top of the mountain these are 0^(@)C and 710 mm. Compare the densities of the air at the foot and at the to of the mountain.

Answer»

<P>

SOLUTION :`d=(PM)/(RT)`, Hence, `(d_(1))/(d_(2))=(P_(1))/(T_(1))xx(T_(2))/(P_(2))=(760 mm)/(303 K)xx(273 K)/(710 mm)=(0.964)/(1)`
Discussion
15.

Teflon is also known as PTFE.

Answer»


ANSWER :T
Discussion
16.

Technique of distribution of mixture between two phases, one stationary phase and other mobile phase is

Answer»

DISTILLATION
FILTRATION
CRYSTALLISATION
CHROMATOGRAPHY

ANSWER :D
Discussion
17.

…….technique is applied to separate different fraction of crude oil in petroleum

Answer»

SOLUTION :FRACTIONATING COLUMN TECHNIQUE
Discussion
18.

Tautomers possess

Answer»

same PHYSICAL properties but different CHEMICAL properties
same chemical properties but different physical properties
different physical and chemical properties
same physical and chemical properties

SOLUTION :Tautoments have different functional GROUPS so they have different physical and chemical properties.
Discussion
19.

Tautomerism : Structural Isomers that undergo rapid interconversions and exist in dynamic equilibrium are known as Tautomers and relationship between them is known as Tautomerism. Tautomers generally have different functional groups. At equilibrium more stable tautomer is present in higher amount by ratio remains same until and unless change is made externally. Tautomerism actually arises due to rapid oscillation of an atoms between two polyvalent atoms in a molecule underset("Keto form")(underset(H)underset(|)(C)H_(2)-overset(O)overset(||)(CH)) hArr underset("enol form")(CH_(2)=overset(OH)overset(|)(CH) Above is an example of Keto-enole tautomerism. condition for this type of keto enol tautomerism is presence of alpha-H. amount of enol at equilibrium is known as enolic content. it is more if enol is more stable and less if keto is more stable. Which of the following compounds have higher enolic content than Keto content :

Answer»

II & IV
I,II & IV
II,III & IV
II only

Solution :
Discussion
20.

Tautomerism : Structural Isomers that undergo rapid interconversions and exist in dynamic equilibrium are known as Tautomers and relationship between them is known as Tautomerism. Tautomers generally have different functional groups. At equilibrium more stable tautomer is present in higher amount by ratio remains same until and unless change is made externally. Tautomerism actually arises due to rapid oscillation of an atoms between two polyvalent atoms in a molecule underset("Keto form")(underset(H)underset(|)(C)H_(2)-overset(O)overset(||)(CH)) hArr underset("enol form")(CH_(2)=overset(OH)overset(|)(CH) Above is an example of Keto-enole tautomerism. condition for this type of keto enol tautomerism is presence of alpha-H. amount of enol at equilibrium is known as enolic content. it is more if enol is more stable and less if keto is more stable. Tautomers of which of the following can show geometrical isomerism

Answer»

`CH_(3)-CHO`
`CH_(3)CH_(2)-CHO`
`(CH_(3))_(2)CH-CH=O`

SOLUTION :
Discussion
21.

Tautomerism is exhibited by X number of compounds among the following. What is X.

Answer»




SOLUTION :`alpha - H`.s on saturated .c. paticipated in TAUTOMERISM.
Discussion
22.

Tautomerism is not exhibited by :

Answer»




SOLUTION :QUINONES do not EXHIBIT TAUTOMERISM
Discussion
23.

Tautomerism is exhibited by

Answer»

`(Me_(3)C CO)_(3)CH`


SOLUTION :Only OPTION (c) does not have a `alpha`-H on a SATURATED carbon and HENCE does not EXHIBIT tautomerism while all others do.
Discussion
24.

Tautomerism is due to spontaneous interconversion of two isomeric forms with differentfunctional groups into each other. The term tautomer means constitutional isomers thatundergo such rapid inter conversion that they cannot be independently isolated. In keto-enol tautomerism although Keto form in general is more stable, but some factors like H-bonding and extended double bonds conjugation may increase the stability of enol form Enolic form of acetyl acelone is stabilized due to (I) resonance as a result of conjugation (II) intra molecular H-bonding(III) dipole- dipole repulsion

Answer»

I and III
II and III
I and II
I only

Solution :Due to two reasons there are
1) EXTEND of conjugation
2) intra molecular HYDROGEN BOND formation.
Discussion
25.

Tautomerism is due to spontaneous interconversion of two isomeric forms with differentfunctional groups into each other. The term tautomer means constitutional isomers thatundergo such rapid inter conversion that they cannot be independently isolated. In keto-enol tautomerism although Keto form in general is more stable, but some factors like H-bonding and extended double bonds conjugation may increase the stability of enol form Which of the following statements are correct of the following

Answer»

I and II are tautomers
III is CONJUGATE BASE of II
I and Ill are tautomers
III is resonance structure of I

SOLUTION :I and II are Tautomers, III is the resonance Structure of I.
Discussion
26.

Tautomer of which of the follwing can show geometrical isomerism

Answer»

`CH_(3)-CHO`
`CH_(3)CH_(2)-CHO`

SOLUTION :
Discussion
27.

Tautomerism exhibited by

Answer»

`(CH_(3))_(3)CNO`
`(CH_(3))_(2)NH`
`R_(3)CNO_(2)`
`R-CH_(2)-NO_(2)`

SOLUTION :
Discussion
28.

Tautomer of which of the following can show geometrical isomerism?

Answer»

`CH_3-CHO`
`CH_3CH_2-CHO`

SOLUTION :N//A
Discussion
29.

Tautomer of which of the following can show geometrical isomerism

Answer»

`CH_3 - CHO`
`CH_3CH_2- CHO`
`(CH_3)_2 CH- CH = O`

SOLUTION :`CH__3 - CH = CH - OH` can SHOW GEOMETRICALISOMERISM
Discussion
30.

Tautomer of following compound is :

Answer»




SOLUTION :N//A
Discussion
31.

Tautomer of following compound is :

Answer»




SOLUTION :More ACIDIC HYDROGEN is TRANSFERRED.
Discussion
32.

Tautomer in following is Diad system :

Answer»

`CH_3COCH_3`
`CH_3CH_2NO_2`

`HCN`

SOLUTION :HCN and CNH
Discussion
33.

Tartonic acid is a product from tartaric acid formed by treatment with

Answer»

HBr
HI
mild OXIDANT
`PCl_(5)`

SOLUTION :
Discussion
34.

Tamarind contains

Answer»

DEXTRO--TARTARIC ACID
laevo-tartaric acid
`(+-)-` Tartaric acid
citric acid

Solution :`(+)-` Tartaric acid
Discussion
35.

TakingZ-axis as the internuclear axis, explain why2p_(x) or 2p_(y)orbital does not combine with 2s obtial to form molecular orbtals ?

Answer»

SOLUTION :The SMALL ++ overlap cancels the +- overlap . HENCE , there is not net OVERLAPPING .
Discussion
36.

Taking Z-axis as the intermolecular axis , when two 2p_(x) orbitals of two atoms/ions overlap, the molecular orbitals formed are ………….and ………

Answer»

<P>

SOLUTION :`pi_(2_(p_(X))),pi_(2_(p_(x)))^(**)`
Discussion
37.

Take the following reaction in consederation. In which enthalpy change is positive. 2A_((g)) hArr C_((g))+ D_((g)) . Which of the following will not affect on equilibrium ?

Answer»

CHANGE in CONCENTRATION of reactants
Change in pressure
Change in temperature
Change in catalyst

Answer :D
Discussion
38.

Take a quick look at environment pollution.

Answer»

Solution :Environmental pollution is the effect of undesirable changes in our surroundings that have harmful effects on plants, animals and human beings.
A SUBSTANCE, which causes pollution, is known as pollutant. Pollutants can be solid, liquid or gaseous SUBSTANCES present in greater concentration than in natural abundance and are produced due to human activities or due to natural happenings.
Some pollutants can be degredable, like discarded vegetables. But some pollutants which are slowly degradable remain in the environment in an unchanged form for many decades. For examples, plastic MATERIALS, heavy metals, nuclear wastes, DDT and other many chemicals.
These types of substanes once released into the environment are difficult ot remove. These pollutants cannot be degraded by natural processes. So they are harmful to living organisms.
In the process of environmental pollution, pollutants ORIGINATE from a source and get transported by air or WATER or are dumped into the soil by human beings.
Discussion
39.

Tajmahal is effected by

Answer»

CO
`SO_(2)`
CAO
`CO_(2)`

ANSWER :B
Discussion
40.

Taj Mahal is threatened by pollution from

Answer»

Chlorine
Suphur DIOXIDE
HYDROGEN
OXYGEN

SOLUTION :Taj mMahal is THREATENED by pollution from suphur dioxide
Discussion
41.

Table-tennis ball has a mass 10g and a speed of 90m/s. If speed can be measured within an accuracy of 4% what will be the uncertainty in speed and position?

Answer»

Solution :`m = 10G = 10xx 10^(-3) kg = 10^(-2) kg`
Uncertainty in SPEED `(Delta v) = 4% " of "90 ms^(-1) = (4)/(100) xx 90 = 3.6 ms^(-1)`
`Delta x xx (m xx Delta v) = (h)/(4PI) :. Delta x = (h)/(4pi m Delta v) = (6.626 xx 10^(-34) kg m^(2) s^(-1))/(4 xx 3.14 xx (10^(-2) kg) (3.6 ms^(-1))) = 1.46 xx 10^(-33) m`
Discussion
42.

Table-tennis ball has a mass 10 g and a speed of 90 m/s. If speed can be measured within an accuracy of 4% what will be the uncertainty in speed and position

Answer»

Solution :The Uncertainty in the speed of ball `=(90xx4)/(100)=(360)/(100)=(360)/(100)=3.6 MS^(-1)`
Uncertainty in position = `(H)/(4pi m TRIANGLE V)`
Discussion
43.

System in which there is no exchange of matter , work or energy from surrounding is ____

Answer»

SOLUTION :ISOLATED
Discussion
44.

Synthesis gas is a mixture of

Answer»

`CO+H_(2)`
`CO+N_(2)`
`CO+N_(2)+H_(2)`
`CO+CH_(4)+N_(2)`

ANSWER :A
Discussion
45.

Syngas is a mixture of

Answer»

`CO_(2) + H_(2)`
`CO+H_(2)`
`CO + CO_(2)`
`CO + N_(2)`

ANSWER :B
Discussion
46.

Syngas contains

Answer»

only CO
only `H_2`
both CO and `H_2`
NEITHER CO nor `H_2`

ANSWER :C
Discussion
47.

Syn-gas is a mixture of

Answer»

`CO+N_(2)`
`O_(3)`
`CO+H_(2)`
`CO+H_(2)CO_(3)`

ANSWER :C
Discussion
48.

Symbols ._(35)^(79)Br and .^(79)Br can be written whereas symbols ._(79)^(35)Br and ._(35)Br are not acceptable. Answer briefly.

Answer»

Solution :`._(79)^(35)BR` is not acceptable because atomic number should be written as SUBSCRIPT, while mass number should be written as SUPERSCRIPT. `._(35)Br` is not acceptable because atomic number of an element is fixed. HOWEVER, mass number is not fixed as it depends upon the isotope taken. Hence, it is essential to indicate mass number.
Discussion
49.

Symbols ._(35)^(79)Br and .^(79)Br can be written, where as symbols ._(79)^(35)Br and .^(35)Br are not acceptable. Answer briefly.

Answer»

Solution :The compostion of any atom can be represented by USING the NORMAL element symbol X with superscript on the left side as the mass number A and subscript Z on the left side as atomic number (ie) `._(Z)^(A)X`.
Hence , the symbols `._(79)^(35)Br and ._(35)Br` are acceptable.
Discussion
50.

Symbols ._(35)^(79)Br and .^(79)Br can be written, whereas symbols ._(79)^(35)Br and .^(35)Br are not acceptable. Answer briefly.

Answer»

Solution :Atomic NUMBER of an ELEMENT is FIXED. HOWEVER, mass number is not fixed as it depends upon the isotope taken. Hence, it is ESSENTIAL to indicate mass number.
Discussion