Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The gas produced by the passage of air over hot coke is

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Carbon MONOXIDE 
Carbon DIOXIDE 
PRODUCER gas
Water gas 

Answer :C
2.

The gas phase reaction shown is endothermic as written. Which, change(s) will increase the quantity of CH_(3)CH=CH_(2) at equilibrium? (P) Increasing the temperature (Q) Increasing the pressure H_(3)C-CH=CH_(2)hArr

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<P>P only
Q only
Both P and Q
Neither P nor Q

Answer :D
3.

The gas molecules randomly move in all directions and collide with each other and with the wall of the container. If is difficult to determine the speed of an individual molecule but it had become passible to work out the distribution of molecules among different molecular speeds. This is known as Maxwell Boltzmann distribution consider the following graph about Maxwell's distribution of speed at two different temperature T_(1) " and " T_(2) The curve has which of the following characteristics ? (i) It has symmetrical distribution of molecules against molecular velocity (ii) The area under the curve gives the total number of molecules. (iii) The maxima of teh curve shifts towards right as the temperature is raised. (iv) The area under the curve is independent of temperature Select the correct statements from the codes given below:

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(i), (II)
(i), (ii) and (III)
(ii), (iii) and (IV)
all are correct

Answer :C
4.

The gas molecules randomly move in all directions and collide with each other and with the wall of the container. If is difficult to determine the speed of an individual molecule but it had become passible to work out the distribution of molecules among different molecular speeds. This is known as Maxwell Boltzmann distribution consider the following graph about Maxwell's distribution of speed at two different temperature T_(1) " and " T_(2) Select the correct statement (s):

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Most PROBABLE speed increases with increase in temperature
Fraction of total molecules with most probable VELOCITY decreases with increase in temperature
Area under the CURVE increases with increase in the temperature
none of the above

Answer :A::B
5.

The gas molecules randomly move in all directions and collide with each other and with the wall of the container. If is difficult to determine the speed of an individual molecule but it had become passible to work out the distribution of molecules among different molecular speeds. This is known as Maxwell Boltzmann distribution consider the following graph about Maxwell's distribution of speed at two different temperature T_(1) " and " T_(2) Total area under the curve at T_(1) is :

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EQUAL to that under CURVE at `T_(2)`
less than that under curve at `T_(2)`
GREATER than that under curve at `T_(2)`
can be greater or less than that under curve at `T_(2)`, depending on the nature of the gas

Answer :A
6.

The gas molecules randomly move in all directions and collide with each other and with the wall of the container. If is difficult to determine the speed of an individual molecule but it had become passible to work out the distribution of molecules among different molecular speeds. This is known as Maxwell Boltzmann distribution consider the following graph about Maxwell's distribution of speed at two different temperature T_(1) " and " T_(2) The shaded area represents :

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NUMBER of molecules having speed between `u_(1) " and " u_(2)`
number of molecules having speed LESS than the most probable speed
number of molecules having `v_(rms) " at " T_(1)`
FRACTION of molecules having average speed

Answer :A
7.

The gas liberated when aluminium reacts with conc. H_2 SO_4 is

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`H_(2)S`
`O_2`
`SO_2`
`H_2`

Solution :`2Al+6H_(2) SO_(4) rarr Al_(2) (SO_4)_(3)+3SO_(2)+6H_(2)O`
8.

The gas liberated when aluminium reacts with conc. H_(2)SO_(4) is

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`H_(2)S`
`O_(2)`
`SO_(2)`
`H_(2)`

SOLUTION :`2Al+6H_(2)SO_(4)RARR Al_(2)(SO_(4))_(3)+3SO_(2)+6H_(2)O`
9.

The gas liberated by the electrolysis of Dipotassium succinate solution is :

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Ethane
Ethyne
Ethene
Propene

Answer :C
10.

The gas leaked from a storage tank of the Union Carbide plant in Bhopal gas tragedy was:

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Phosgene
Methylisocyanate
Methylamine
Ammonia

Answer :B
11.

The gas leaked from a storage tank of the union Carbide plant in Bhopal gas tragedy was

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AMMONIA
PHOSGENE
METHYLISOCYANATE
Methylamine

Answer :C
12.

The gas emitted by supersonic jet planes that slowly depletes the ozone layer is

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CO
NO
`SO_2`
`O_2`

ANSWER :B
13.

The gas emitted by supersonic jet planes that slowly depletee the ozone layer is

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CO
Nondegradable POLLUTANT
`SO_(2)`
`O_(2)`

ANSWER :B
14.

The gas constant R represents work done

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PER MOLECULE 
per DEGREE absolute 
per degree per MOLE 
per mole

Answer :C
15.

The g/L of 5 M aqueous solution of NaOH is ....... (Molecular mass of NaOH : 40 g " mole"^(-1) )

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200
8
12.5
1.25

Answer :A::B
16.

The functional group(s) present in H_(3)C-CH_(2)-O-CH_(2)-overset(O)overset("||")("C")-OCH_(3)

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ETHER, KETONE
Ketone
ESTER, Ether
Ether, Ether

Solution :Ester and Ether are the FUNCTIONAL GROUPS (COOR) (R-O-R).
17.

The functional groups in cortisone are:

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ETHER, ALKENE, alcohol
Alcohol, ketone, alkene, ether
Alcohol, ketone, AMINE
Ether, amine, ketone

Answer :B
18.

The function of sodium pump is a biological process operating in each and every cell of all animals . Which of the following biologically important ions is also a constituent of the pump ?

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`K^(+)`
`Fe^(2+)`
`Ca^(2+)`
`MG^(2+)`

ANSWER :A
19.

The function of ZnCl_(2) in Lucas test for alcohols is

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to act as acid catalyst and react with `HCL` to form `H_(2)ZnCl_(2)`
to act as BASE catalyst and react with NaOH to form `Na_(2)ZN(OH)_(4)`
to act as an AMPHOTERIC catalyst
to act as an NEUTRAL catalyst

Answer :D
20.

The function of "Sodium pump" is a biological process operating in each and every cell of all animals. Which of the following biologically important ions is also a constituent of this pump?

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`Mg^(2+)`
`K^(+)`
`FE^(2+)`
`CA^(2+)`

Answer :B
21.

The function of sand in mortar is

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To decreases the hardness
To make the MASS compacat
To decreases the plasiticity of the mass
To prevent excessive SHRINKAGE which might result in cracsks

SOLUTION :To AVOID shrinkage SAND is added to mortar
22.

The function of gum Arabic in the preparation of Indian ink is

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COAGULATION
peptization
protective action
adsorption

Answer :B
23.

The function of boiling the sodium extract with conc. HNO_(3) before testing for halogen as:

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to make the solution acidic
to make the solution clear
to CONVERT `Fe^(2+)` to `Fe^(3+)`
to destroy `CN^(-)` and `S^(2-)` ions

Solution :If N and S are ALREADY present, they will hinder in test of halogens as `NaCN` and `Na_(2)S` will GIVE white or black precipitate with `AgNO_(3)`. Boiling conc. `HNO_(3)` is thus used to remove `CN^(-)` and `S^(2-)` ions in the FORM of volatile HCN and `H_(2)S`.
24.

The function of anhydrous aluminium chloride in the Friedel-Craft's reaction is

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Absorb water
To absorb hydrochloric ACID
To PRODUCE an ELECTROPHILE
To produce nucleophile

Solution :`AlCl_3` will LEAD to the formation of carbocation.
25.

The fully eclipsed conformation of n - butane is least stable due to the presence of

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BOND OPPOSITION strain only
STERIC strain only
Bond opposition strain as well as steric strain
No strain is present in the molecule.

Solution :Steric strain
26.

The fullform DDT is ........

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SOLUTION :DICHLORODIPHENYLTRICHLOROETHANE
27.

The fuel used to produce electrical energy in the space rocket saturn V which Neil Armstrong reached the Moon is

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`CO+O_(2)`
`F_(2)+O_(2)`
`CH_(4)+O_(2)`
liquid `H_(2)+O_(2)`

ANSWER :D
28.

A fuel has the same knocking property as a mixture of 70% isooctane (2,2,-4 trimethyl pentane) and 30% n heptane by volume, the octane number of the fuel is

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ANSWER :F
29.

The fuel gas having volume composition equal to 44%CH_(4)+48%H_(2)+5%N_(2)+3%CO is

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oil gas
water gas
COAL gas
petrol gas

Solution :Coal gas = 44% `CH_(4)+48% H_(2) + 5% N_(2) + 3% `CO
30.

The fuel gas with highest composition of hydrogen is

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COAL GAS
WATER gas
Semiwater gas
Carburated water gas

Answer :A
31.

The fresh precipitate can be transformed in colloidal state by

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Peptisation
coagulation
Diffusion
None of these

Solution :CONVERSION of fresh PRECIPITATE into colloidal SOLUTIO is KNOWN as peptisation.
32.

The Friedel-Crafts alkylation...

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WORKS well for primary chlorides
Works very well for tertiary chlorides
Works very well for acyl chlorides
Works very well without catalyst

Solution :Friedel crafts REACTION with CARBONIUM ion rearrangement
33.

The frequency transition n = 4 to n = 2 of He+ is equal to the transition in H atom corresponding to which of the following.

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n=3 to n=1
n=2 to n=1
n=32 to n=1
n=4 to n=3

Answer :B
34.

The frequency of the spectral line obtained when the electron in n = 3 of Hydrogen atom drops to the ground state is

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`2.925xx10^(15)` HERTZ
`2.925xx10^(13)` Hertz
`2.925xx10^(13)` Hertz
`36559xx10^(10)` Hertz

Solution :`UPSILON = cbar(upsilon)= cR((1)/(n_2^2) - 1/(n_2^2))`
`=3xx10 xx 109677 [1/1 -1/9]`
`=32.9xx10^(14) [8/9] = 2.925 xx 10^(15) Hz`
35.

The frequency of the radiation emitted when the electron falls from n = 4 to n = 1 in a hydrogen atom will be (Given ionization energy of H = 2.18 xx 10^(-18) J "atom"^(-1) and h = 6.625 xx 10^(-34) Js)

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`1.54 XX 10^(15) s^(-1)`
`1.03 xx 10^(15) s^(-1)`
`3.08 xx 10^(15) s^(-1)`
`2.0 xx 10^(15) s^(-1)`

SOLUTION :`IE. = E_(oo) - E_(1) = 0 - E_(1) = 2.18 xx 10^(-18) J "atom"^(-1)`
Thus, `E_(n) = - (2.18 xx 10^(-18))/(n^(2)) J "atom"^(-1)`
`DELTA E = E_(4) - E__(1) = -2.18 xx 10^(-18) ((1)/(4^(2)) - (1)/(1^(2)))`
`= 2.044 xx 10^(-18) J "atom"^(-1)`
`Delta E = hv`
or `v = (Delta E)/(h) = (2.044 xx 10^(-18)j)/(6.625 xx 10^(-34)JS) = 3.085 xx 10^(15) s^(-1)`
36.

The frequencyof yellowlighthavingwavelength600 nm is

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`5.0 XX 10^(14) Hz`
`2.5 xx 10^(7) Hz`
`5.0 xx 10^(7) Hz`
`2.5 xx 10 ^(14) Hz`

ANSWER :A
37.

The frequency of the characterstic X ray of K_(alpha) line of metal target 'M' is 2500 cm^(-1) and the graph between sqrt(v) Vs 'z' is as follows, then atomic number of M is

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49
50
51
25

Answer :C
38.

The frequency of one of the lines in Paschen series of hydrogen atom is 2.340 xx 10^(14)Hz. What is the quantum number n_(2) which produces this transition ?

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Solution :`bar(v) = R_(H) ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2)))`
`bar(v) = (1)/(LAMDA), C = v lamda or (1)/(lamda) = (v)/(c)`
`:. v = c R_(H) ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2)))`
For Paschen series, `n_(1) = 3`
`:. 2.340 xx 10^(14) = (3 xx 10^(8) ms^(-1)) xx (1.097 xx 10^(7) m^(-1)) ((1)/(3^(2)) - (1)/(n_(2)^(2)))`
or `((1)/(3^(2)) - (1)/(n_(2)^(2))) = (2.340 xx 10^(14))/(3.291 xx 10^(15)) = 0.071`
or `(1)/(n_(2)^(2)) = (1)/(9) - 0.071 = 0.111 - 0.071 = 0.04 or n_(2)^(2) = 25 or n_(2) = 5`
39.

The frequency of light emitted for the transition n = 4 " to " n = 2 of He^(+) is equal to the transition in H atom corresponding to which of the following :

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`n = 3 " to " n = 1`
`n = 2 " to " n = 1`
`n = 3 " to " n = 2`
`n = 4 " to " n = 3`

Solution :`bar(v) = R ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2))) Z^(2)`
`v = (C)/(lamda) = cbar(v) or bar(v) = (v)/(c)`
`:. (v)/(c) = R ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2))) Z^(2)`
or `v = Rc ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2))) Z^(2) = R' ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2))) Z^(2)`
For `He^(+)`, for TRANSITION `n = 4 " to " n = 2`
`v = R' ((1)/(2^(2)) - (1)/(4^(2))) xx 2^(2) = R' ((1)/(1^(2)) - (1)/(2^(2)))`
For H, Z = 1, therefore for same VALUE of v, transition will be form `n = 2 " to " n = 1`
40.

The frequency of an electromagnetic radiation is 2xx10^6 Hz. What is its wavelength in metres (Velocity of light =3xx10^8 ms^(-1))

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`6.0xx10^14`
`1.5xx10^4`
`1.5xx10^2`
`0.66xx10^(-2)`

SOLUTION :When `c=vxxlambda` than `lambda=c/v=(3xx10^8)/(2xx10^6)=1.5xx10^2` m
41.

The frequency of a wave of light is 12xx10^14 s^(-1) . The wave number associated with this light is

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`5XX10^(-7) m`
`4XX10^(-8) cm^(-1)`
`2xx10^(-7) m^(-1)`
`4xx10^(4) cm^(-1)`

Solution :Frequency `v=12xx10^14 s^(-1)` and VELOCITY of light `c=3xx10^10 cm s^(-1)` . We know that the wave number `barv=v/c =(12xx10^14)/(3xx10^10)=4xx10^4 cm^(-1)`
42.

The frequency of a radiation having a wave number of 2 xx10^(14) "cm"^(-1) will be x xx 10^(24) s^(-1) .Then the value of x is ____

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Solution :`V= cbarv = (3XX 10^(10)) (2xx10^(14)) = 6xx10^(24)s^(-1)`
43.

The frequency associated with photon of radiation having a wavelength of 6000 Å is

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`5xx10^(14)HZ`
`4.26xx10^(10)Hz`
`2xx10^(14)Hz`
`5xx10^(15)Hz`

Answer :A
44.

The freezing point of 3.75xx10^(-2)M aqueous solution of weak acid HA is 272.9K. The molality of the solution was found to be 0.0384 molal. Find the [H^(+)] of the solution on adding 3.75xx10^(-2) moles of NaA to one litre of the above solution. (K_(f) "of water" =1.86 "molal"^(-1))

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ANSWER :`6.89xx10^(-3)M;`
45.

The freezing point of 0.05M urea solution is differnet from that of 0.05 M sodium chloride solution The depression in freezing point is directly propotional to the number of species present in the solution .

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SOLUTION :EXPLANTION is CORRECT REASON for STATEMENT
46.

The freezing point depression constant for water is1.86 ^(@) K kg mol ^(-1), I f5g Na_2 SO_4 is dissolved in 45 g water the depression in freezingpoint as 3.64 ^(@) C The Vant Hoff factor forNa_2 SO_4 is

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`2.50`
`2.63`
`3.64`
`5.50`

ANSWER :A
47.

The freezing point depression constant for water is 1. 86^(@)K gm mol ^(-1). If 5g Na _(2) SO_(4) is dissolved in 45 g water, the depression in freezing point is 3.64 ^(@)C. The van't Hoff factor for Na _(2) SO _(4) is ……

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`2.50`
`2.63`
`3.64`
`5.50`

Solution :`K _(f) = 1. 86 , W_(2) = 5g, DELTA T _(f ) =3.64, M _(2) = 142, W_(1) = 45 g`
`Delta T_(f) = I xx K _(f)`
`i = (Delta T _(f) xxM _(2) xx W_(1))/( K _(f) xx W _(2) xx 1000)`
`= (3.64 xx 142 xx 45)/(1. 86 xx 5 xx 1000)`
`i = 2.5`
48.

The free energy changes for the two reactions given below are : (i) SO_(2)(g) + Cl_(2)(g) rarr SO_(2)Cl_(2)(g) , DeltaG= - 2270 cal (ii) S(rhom) + O_(2)(g) + Cl_(2) (g) rarr SO_(2)Cl_(2)(g) , DeltaG = - 74060 cal Find the Delta G for the reaction : S ( rhom ) + O_(2)(g) rarr SO_(2)(g)

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SOLUTION :EQN. (ii) - Eqn. (i) gives the required result.
49.

The fragrance of flowers is due to the presence of some steamm volatile organic compounds called essential oils. These are generally insoluble in water at room temperature but are miscible with water vapour in vapour phase. A suitable method for the extraction of these oils from the flowers is

Answer»

distillation
crystallisation
distillation under reduced pressure
STEAM distillation

Solution :Steam distillation is USED to separate SUBSTANCES which are steam volatile and are IMMISCIBLE with water.
50.

The fragrance of flowers is due to the presence of some steam volatile organic compounds called essential oils. These are generally insoluble in water at room temperature but are miscible with water vapour in vapour phase. A suitable method for the extraction of these oils from the flowers is :

Answer»

Distillation
Crystallisation
Distillation under REDUCED PRESSURE
Steam distillation

Solution :SUBSTANCES (i.e., essential oils) are insoluble in water and have high vapour pressure at 373 K and hence can be separated by steam distillation.