Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The number of sigma-and pi-bonds present in 1, 3-butadiene are respectively

Answer»

9 and 2
8 and 2
9 and 3
9 and 1

Solution :
`sigma`-BONDS = 9, `PI`-Bonds = 2
2.

The number of sigma and pi bonds present in cis-but-2-ene is …… .

Answer»

`9 sigma` and `1pi`
`5 sigma` and `1pi`
`11 sigma` and `1pi`
`8 sigma` and `1pi`

ANSWER :C
3.

The number of sigma and pi bonds in phenol respectively are ……

Answer»

12,3
13,4
13,2
13,3

Answer :D
4.

The number ofsigma and pi bonds inallyl isocyanide are

Answer»

`9 SIGMA, 3pi`
`9 sigma, 9pi`
`3 sigma, 4pi`
`5 sigma, 7pi`

SOLUTION : ` CH_(2) = CH - CH_(2)- N-=C`
5.

The number of sigma and pi-bonds in 1-butene 3-yne are

Answer»

5 SIGMA and 5 pi
7 sigma and 3 pi
8 sigma and 2 pi
6 sigma and 4 pi

Answer :B
6.

The number of resonance structures for N is

Answer»


ANSWER :9
7.

The number of resonance structures for anilinium ion is

Answer»


Solution :In anilimium ION nitrogen has no lone pair, RESONANCE Structures are DUE to Benzene Ring only
8.

The number of reagetns among the following which cannot add to propene by free radical mechanism in presence of organic peroxides is (a). HCl (b). HBr (c) HI (d). CH_(3)SH BrC Cl_(3)

Answer»


ANSWER :2
9.

The number of radial nodes in 3s and 2p respectively are

Answer»

2 and 0
1 and 2
0 and 2
2 and 1

Solution :Radial nodes `= n - L -1`
10.

The number of radial nodes in 3d orbitals will be..........

Answer»


ANSWER :0
11.

The number of radial nodes for 3p orbital is...

Answer»

3
4
2
1

Solution :For H atom WAVE FUNCTION, there are n - Z - 1 radial NODES and (n - 1) total nodes. No. of radial nodes 2N 3p orbital = n - Z - 1 = 3 - 1 - 1 = 1
12.

The number of radial nodes for 3p orbital is .....

Answer»

3
4
2
1

Solution :No. of RADIAL nodes in 3P orbital `= n -l-1 =3 -1-1 = 1`
13.

The number of protons, electrons and neutrons in ""_(35)Br^(80) are respectively

Answer»

35, 35, 80
35, 35, 45
80, 80, 35
45, 45, 35

Answer :B
14.

The number of protons, electrons and neutrons in a species are equal to 17,18 and 18 respectively. Which of the following will be the proper symbol of the species

Answer»

`""_17^32""CL`
`""_17^35""Cl^-`
`""_17^36""Cl`
`""_17^36""Cl^-`

ANSWER :A::C
15.

Thenumberof protonneutronandelectronrespectively . ……….. And ………?

Answer»

1,3,1
1,2,1
1,1,1
2,1,0

Answer :B
16.

The number of properties which are state function amongthe following is Pressure, Volume , Temperature,Heat, Work , Entropy, Enthalpy , Free energy, Internal energy,C_(p) andC_(v).

Answer»


ANSWER :7
17.

The number of products (stereoisomers) formed in the following reaction is (consider only major product)

Answer»


SOLUTION :
18.

The number of primary, secondary, tertiary and quaternary carbons in neopentane are respectively

Answer»

4,3,2 and 1
5, 0,0 and 1
4,0,0 and 1
4,0,1 and 1

Answer :C
19.

The number of primary, secondary and tertiary amines possoble with the molecular formula C_(3)H_(9)N respectively :

Answer»

1,2,2
1,2,1
2,1,1
3,0,1

Solution :N//A
20.

The number of primary, secondary and tertiary amines possible with the molecular formula C_(3)H_(9)N respectively.

Answer»

1, 2, 2
1, 2, 1
2, 1, 1
3, 0, 1

Solution :`UNDERSET(1^(@)-"amines:-2")(C-C-C-NH_(2))""underset(2^(@)-"amines=1")(C-C-NH-C)`
`C-underset( C )underset(|)N-C""C-underset(NH_(2))underset(|)C-C`
`3^(@)`-amines=1
21.

The number of primary alcohol isomers with the formula C_(4)H_(10)O is

Answer»

1
2
3
4

Solution :`C - C - C -C - OH "" C - undersetoverset(|)(C )(C ) - C - OH`
22.

The number of possible theoretical conformations of ethane is

Answer»

Two
Three
Four
INFINITE

Solution :Infinite NUMBER
23.

The number of possible structural isomers f~r a compound with the molecular formula C_7H_16 is

Answer»

8
9
10
12

Answer :B
24.

The number of possible resonance forms for superoxide ion is

Answer»

2
4
3
1

Answer :C
25.

The number of possible monochloro derivatives of 2,2,3,3-tetramethylbutane is

Answer»

2
3
4
1

Answer :D
26.

The number of possible isomers of CH_(6)H_(12), is ________

Answer»

2
3
5
6

Answer :C
27.

Number of isomers for the compound with the molecular formula C_2BrClFI is -----

Answer»

3
4
5
6

Answer :D
28.

The number of possible isomeric structures for the formula C_(4)H_(10) is

Answer»

10
1
2
6

Answer :C
29.

The number of possible enantiomeric pairs formed bymono chlorination of 2-methylbutane is

Answer»

Four
TWO
THREE
ONE

Solution :Enantiomeric PAIRS.
30.

The number of possible aromatic structure for C_(7)H_(8)O is………….

Answer»

4
7
9
5

Solution :
31.

The number of pi molecular orbitals completely filled in the ground state of benzene is:

Answer»

three
one
six
none

Solution :N//A
32.

The number of pi bond present in given compound is/are…… CH_(3)-CH=CH-COOH

Answer»

2
4
3
1

Solution :`CH_(3)- CH underset(underset(PI-"BOND")(uarr))(=) CH- OVERSET(overset(OH)(|))(C ) underset(underset(pi-"bond")(uarr))(=)O`
33.

The number of pi and sigma-bonds in toluene is respectively

Answer»

`3` and `6`
`6` and `12`
`3` and `10`
`6` and `10`

Answer :A::C::D
34.

The number of solutions of sinx=x/10 is

Answer»

10 hcx
`(hc)/(10X)`
`(10)/(hcx)`
`(hcx)/(10)`

Solution :`E = (nhc)/(lambda) = nhc BARV (because barv = 1/(lambda))`
`therefore 10 ` = nhc`barv` or N `=1(10)/(hcv) = (10)/(hcx)`
35.

The number of peroxy rings in CrO_(5) is ___

Answer»

2
3
4
1

Solution :In the given structure `CrO_(5)` POSSESS TWO peroxy rings, where oxidation NUMBER of O atom will be -1.
36.

The number of Pentagons and Hexagons, respectively in Co-Fullerence are

Answer»

`10&20`
`30&30`
`20&10`
`12&20`

ANSWER :D
37.

The number of paired electrons in oxygen atom is :

Answer»

6
16
8
32

Answer :A
38.

The number of p atomic orbitals involved in the formation of a benzene molecule

Answer»

<P>

SOLUTION :SIX p ATOMIC ORBITALS
39.

The number of oxygen molecules present in 100 grams of limestone is

Answer»

`4N_(0)`
`3N_(0)`
`1.5N_(0)`
`N_(0)`

ANSWER :C
40.

The number of oxygen present in 11.2 L of ozone at N.T.P. are______ .

Answer»

`1.20xx10^(24)`
`9.03xx10^(23)`
`6.02 xx10^(23)`
`3.01xx10^(23)`

Solution :`11.2 L " of OZONE " -=(6.02xx10^(23))/(2)" MOLECULES of "O_3`
`-=3xx3.01xx10^(23)" atoms of oxygen "`
`-=9.03xx10^(23)" atoms of oxygen "`
41.

The number of oxygen atoms present in 50 g of calcium carbonate is

Answer»

`6.023xx10^(23)`
`30.1xx10^(23)`
`9.025xx10^(23)`
`1.206xx10^(24)`

ANSWER :C
42.

The number of orbitals in the quantum level n = 4 is

Answer»

4
9
16
18

Solution :In `N^(TH)` ORBIT, `n^2` ORBITALS on there
43.

The number of orbitals in 2p sub-shell is

Answer»

6
2
3
4

Solution :It has 3 ORBITALS `p_x,p_y,p_z`
44.

The number of optically active products obtained form the complete ozonolysis of the given compoundis :

Answer»

0
1
2
4

Answer :A
45.

The number of optically active isomers possible for the compound CH_(3)-underset(OH)underset(|)(CH)-underset(OH)underset(|)(CH)-underset(OH)underset(|)(CH)-CH_(2)OH

Answer»

3
4
8
6

Solution :The MOLECULE is not symmetrical and there are THREE chiral carbon atoms i.e., `n = 3`
`:.` The number of ISOMERS `= 2^(n) = 2^(3) = 8`.
46.

The numberof orbitals dependson whichquantumnumberand notdependson whichquantum number ?

Answer»

Solution :The numberof orbitalsdependson VALUEOF LAND ITSIS equalto no. of valueof `m_(1)`
ITDOES not dependson nand `m_(s)`
47.

The number of of electrons required to balance the following equation NO_3^(-) +4H^(+) + e^(-) rarr 2H_2O +NO is_______

Answer»


SOLUTION :`NO_(3)^(-) +4H^(-)rarr 2H_2 O+No`
In this equation , all the ATOMS are balanced . To balance charge add `3E^(-)` to L.H.S., we have
`NO_3^(-) + 4H^(+)+3e^(-) rarr 2H_(2)O+NO`
48.

The number of nodes possible in radial probability distribution curve of 3d orbital is

Answer»

1
2
3
0

Solution :NODES = N -l-1 , 3-2-1=0 (but not 4)
49.

The number of octahedral sites per sphere in fcc structure is

Answer»

8
4
2
1

Answer :B
50.

Thenumber of O_3 molecules in16 g of ozone is approximately.

Answer»

`2xx10^(23)`
`3xx10^(23)`
`4XX10^(23)`
`6xx10^(23)`

Solution :48 G of `O_3" contains "6.02xx10^(23)" molecules "
`16 g " of " O_3" contains"(6.02xx10^(23))/(48) xx16`
`=2.00xx10^(23)" molecules ".`