Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Write the possible structures for the following molecules .Show the direction of the movement of electrons with the help of arrows.

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SOLUTION :
Discussion
2.

Write the possible structures for the following molecules .Show the direction of the movement of electrons with the help of arrows.

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SOLUTION :
Discussion
3.

(vi) MnO_(4)^(-)+Fe^(2+)to Mn^(2+)+Fe^(3+).

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Solution :
Equalise the increase/ decrease in Oxidation number by multiplying Mn species by 1 and Fe species by 5.
`MnO_(4)^(-)+5Fe^(2+)to Mn^(2+)+5Fe^(3+)`
Balance all other ATOMS EXCEPT O and H
`MnO_(4)^(-) +5Fe^(2+)to Mn^(2+)+5Fe^(3+)`.
Balance O atom by adding `H_2O` on the side falling short of hydrogen and equal number `OH^(-)` on the opposite side.
`MnO_(4)^(-)+5Fe^(2+)+8H_2Oto Mn^(2+)+5Fe^(3+)+4H_(2)O+8OH^(-)`
`MnO_(4)^(-)+5Fe^(2+)+8H_(2)O to Mn^(2+)+5Fe^(3+)+4H_(2)O+8OH^(-)`.
Discussion
4.

Write the possible structures for the following molecules .Show the direction of the movement of electrons with the help of arrows.

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SOLUTION :
Discussion
5.

Which one has a higher energy, a photon of violet light with wavelength4000 Å or a proton of red light with wavelength 7000 Å ?

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ANSWER :`6.62xx 10^(-34)` J SEC .
Discussion
6.

Which metal is used in photoelectric cell ?

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CD
K
RB
Na

ANSWER :B
Discussion
7.

Whk h of the following species have the same shape?

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`CO_(2)`
`"CCl"_(4)`
`O_(3)`
`NO_(2)^(-)`

Solution :(C,D)
The SHAPE of following SPECIES are
`CO_(2)` = LINEAR ,`"CCl"_(4)` = tetrahedral
`O_(3)` = bent, `"" NO_(2)^(-) ` = bent
Discussion
8.

Write the possible structures for the following molecules .Show the direction of the movement of electrons with the help of arrows.

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SOLUTION :
Discussion
9.

Which type of bond is observed in Ethane 1, 2-diol in the given option ?

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Co-ordinate COVALENT BOND
Ionic bond
INTRA MOLECULAR H-bond
Inter molecular H-bond

Answer :C
Discussion
10.

Write the possible structures for the following molecules .Show the direction of the movement of electrons with the help of arrows.

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SOLUTION :
Discussion
11.

Write the possible structures for the following molecules .Show the direction of the movement of electrons with the help of arrows.

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SOLUTION :
Discussion
12.

Write the possible structures for the following molecules .Show the direction of the movement of electrons with the help of arrows.

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SOLUTION :
Discussion
13.

Write the possible structures for the following molecules .Show the direction of the movement of electrons with the help of arrows.

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SOLUTION :
Discussion
14.

What are particulate pollutants? Give an example

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Solution :Particulate pollutants are solid PARTICLES in the AIR.
Example: DUST, furmes, mist, smoke.
Discussion
15.

Write the possible structures for the following molecules .Show the direction of the movement of electrons with the help of arrows.

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SOLUTION :
Discussion
16.

Write the possible structures for the following molecules .Show the direction of the movement of electrons with the help of arrows.

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SOLUTION :
Discussion
17.

What is meant by hybridisation ? Compound CH_(2)= C= CH_(2) contains sp or sp^(2)-hybridised carbon atoms. Will it be a planar molecule ?

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Solution :Defination: The phenomenon of mixing of atomic ORBITALS of same ATOM having MUCH less diffrence in their energy to form equal no of orbitals having similar. These compound contains sp and `sp^(2)` hybridised CARBON atom STRUCTURE of allene `(C_(3)H_(4))` is,

Allene molecule `CH_(2)= CH_(2)` is not planar

According to figure: `pi (2p_(y) -2p_(y)) bot pi (2p_(z)-2p_(z))`
`C_(1)` carbon is `sp^(2)` and (H)a and (H)b lie in a plane perpendicular to the plane of the paper so (H)a is up and (H)b is bottom.
`C_(1), C_(2) and C_(3)` are linear. `C_(3)` carbon is `sp^(2)` and (H)c and (H)d lie in the plane of paper
`[("The plane of"),("(H)c adn (H)d")] bot [("The plane of"),("(H)a and (H)b")]`
Thus, the all molecule of allene is non-planar
Discussion
18.

Write the possible structures for the following molecules .Show the direction of the movement of electrons with the help of arrows.

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SOLUTION :
Discussion
19.

What is oxidising agent and reducing agent ? Explain with examples.

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Solution :.Which reactant accept electron and form reduction is known as oxidising AGENT...
"Which reactant lose electron and from oxidation is known as reducing agent...
The reactions shows under are redox reactions.

In above reaction, Na is attached with more ELECTRONEGATIVE element. So oxidation of Na is OCCUR and `Cl_(2),O_(2)` and S attached with more electropositive element so reduction of `Cl_(2),O_(2)` and S occurs.
Each process can be CONSIDERED as two seperate steps :

Here, in first STEP Na loses `e^(-)` and in second step `Cl_(2)` gain `e^(-)`.
Redox reaction is such reaction in which electron transfer into one reaction into another reaction.
Discussion
20.

Why are alkanes referred to as paraffins?

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Solution :Because they have LESSER affinity towards GENERAL reagents. In other words they are INERT, not READILY active.
Discussion
21.

Which of the following do not change with temperature ?

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% w/v
Molality
Density
Molarity

Solution :m. is DEPEND on WEIGHT and if TEMPERATURE is CHANGE than weight will unchange.
Discussion
22.

Write the possible structures for the following molecules .Show the direction of the movement of electrons with the help of arrows.

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SOLUTION :
Discussion
23.

To a buffer solution of CH_(3),COOH and CH_(3),COONa, some HCI is added. Then the reaction involved is

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`CH_3 COOH +OH^(-)to CH_3 COO^(-)+H_2O `
`CH_3 COO^(-)+H^(+)to CH_3 COOH`
` Na^(+)OH^(-)to NaOH`
` CH_3 COO^(-)+ Na^(+) to CH_3 COONa`

Solution :HCL is ACID
`therefore ` basic `CH_3 COO^(-)` REACTS with it
` CH_3 COO^(-)+H^(+) to CH_3 COOH`
Discussion
24.

Whatis the lowestvalueof n thatallowsgorbitalsto exist ?

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<P>

Solution :fororibitalg l = 4
n= (l+ 1)= (4+1) =5
ORBITAL : s p d f q
: 0 1 2 3 4
Discussion
25.

Write the possible structures for the following molecules .Show the direction of the movement of electrons with the help of arrows.

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SOLUTION :
Discussion
26.

Write the possible structures for the following molecules .Show the direction of the movement of electrons with the help of arrows.

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SOLUTION :
Discussion
27.

Which of the following has maximum spin ?

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Electron
Proton
Neutron
All have equal SPIN

Solution :Each GIVEN particle can spin CLOCKWISE or anticlock-wise. HENCE, each of them has two spin VALUES.
Discussion
28.

To reduce a nitroaldehyde to a nitroalcohol the reducing agent of choice is

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`LiAIH_(4)`
`NaBH_(4)`
MOLECULAR `H_(2)`
`SnCl_(2)`

Answer :B
Discussion
29.

Tritium emits

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a - particle
Positron
b - particle
Neutron

Answer :C
Discussion
30.

Which of the following statement(s) is / are not true about the following decomposition reaction :2KCIO_(3)rarr2KCI+3O_(2)

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Solution :writing the O.N each element above its symbol we have
`2KCIO_(3)rarr 2DCI+3O_(32)`
(a) SINCE O.N of k does not change therefore K neither undergoes reduction nor oxidation thus OPTION (a) is not corret
(b)since O.N of CI decreases form +5 in `KCIO_(3)` to -1in KCI therefore CI undergoes reductio i.e option (b) isnot correct
(c ) O.N of O increses form -2 in `KIO_(3)` ot0 in `O_(2)` therefore O is oxidised i.e option (c ) not correct ltbRgt (d)This statement is not correct because CI undergoing reduction and O is undergoing oxidation Thus all option are incorrect
Discussion
31.

Which one of the following is used in purification of sugar and as drying agent ?

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`CA(OH)_2`
`MgSO_4 . 7H_2 O`
`CaSO_4 . 2H_2 O `
`CAO`

SOLUTION :CaO
Discussion
32.

Which of the following reagent is used to detect the presence of -OH groups on adjacent carbon atoms?

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conc. `H_(2)SO_(4)`
Ozone
`HIO_(4)`
Conc. `HNO_(3)`

Solution :`HIO_(4)` CAUSES FISSION of carbon-carbon bond in vicinal diols to give aldehydes.
Discussion
33.

Which of the following is a Lewis acid ?

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`AlCl_3`
`MgCl_2`
`CaCl_2`
`BaCl_2`

Solution :Lewis acids are the species in which octet is not complete and ready to accept electrons. In `AlCl_3`, Al is SURROUNDED by 6 electrons and all THREE Cl ATOMS are surrounded by 8 electrons, therefore, `AlCl_3` is electron accepter. It is a covalent compound.
`._13Al`= 2,8,3 and `._17Cl`=2,8,7
`underset"Octet incomplete"(overset(Cl)overset|(Cl-Al-Cl))`
Discussion
34.

Which of the following statements is//are correct:

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At equilibrium, vapour pressure of solution and refractive index of EQ. mixture becomes constant.
Equilibrium can be attained in both homogenous and heterogenous reaction.
Approach to the equilibrium is fast in initial STATE but GRADUALLY it DECREASES.
Equilibrium is dynamic in nature

Solution :N//A
Discussion
35.

The statement that is not correct for the periodic classification of elements is.....

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the properties of elements are the periodic functions of their ATOMIC number.
non METALLIC elements are lesser in number than metallic elements.
the first ionization energies along period do not vary in a regular manner with increase in atomic no.
for TRANSITION elements the d-subshells are filled with electrons monotonically with increase in atomic no.

Solution :the first ionization energies along period do not vary in a regular manner with increase in atomic no.
Discussion
36.

The volume of perhydrol which on decomposition gives 1.5 Iit of O_(2) gas at STP is

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25ML
15ML
10ml
0ml

Answer :B
Discussion
37.

While sulphur dioxide and hydrogen peroxide can act as oxidising as well as reducing agents in their reactions, ozone and nitric acid act only as oxidants. Why ?

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Solution :In `SO_(2)`, the O.S. of S is + 4. Sulphur can exhibit any oxidation state in between-2 and + 6. THEREFORE, in `SO_(2)`, it can decrease as well as increase its oxidation state, i.e., it can undergo reduction as well as oxidation. This is why `SO_(2)` can act both as an oxidising and a reducing AGENT. Same is the situation with hydrogen PEROXIDE. In `H_(2)O_(2)`, O atom is in the O.S. of -1. Oxygen can exhibit any oxidation state in between - 2 and 0 (+ 2 also when in combination with F). Therefore, in `H_(2)O_(2)`, it is free to decrease or increase its oxidation state. This is why `H_(2)O_(2)` also acts both as an oxidising and as a reducing agent.
In `O_(3)`, the O.S. of O is zero. It can only decrease its oxidation state either to -1 or to -2, but can not increase its oxidation state. Therefore, `O_(3)` acts only as an oxidant. Same is the situation with nitric ACID. In `HNO_(3)`, the O.S. of N is +5, which is the highest O.S. of N. Therefore, it can only decrease its O.S. This is why `HNO_(3)` also acts only as an oxidant.
Discussion
38.

The values of quantum numbers n, l and m for the fifth electron of boron is

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ANSWER :n=2, l=1, m=-1
Discussion
39.

Which of the following give allylic substitution product?

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SOLUTION :`OSO_4`- SYN HYDROXYLATION.
Discussion
40.

Which of the following is a disproportion reaction ?

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`NO_(3)^(-) + Cu rarr NO + Cu^(2+) `
`HNO_(2) rarr NO_(3)^(-) + NO`
`Zn+ O_(2) rarr ZnO`
`S_(2) O_(3)^(2-) + Cr_(2) O_(7)^(2-) rarr S_(4) O_(6)^(2-) +Cr^(3+)`

ANSWER :B
Discussion
41.

Which are the functional group in the following? Write its name, suffixe and prefix (a) CH_(3)CH_(2)CH_(2)COOH (b) CH_(3)CH_(2)CH_(2)COO^(-)Na^(+) (c ) CH_(3)CH_(2)COOCH_(3) (d) CH_(3)CH_(2)CH_(2)COCl (e ) CH_(3)CH_(2)CH_(2)CONH_(2) (f ) CH_(3)CH_(2)CH_(2)CHO

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SOLUTION :
Discussion
42.

Which is the correct representation of arrow in heterolytic fission of C-C bond in CH_(3)-CN?

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ANSWER :B
Discussion
43.

Wurtz reaction is suitable of the preparation of both symmetrical and unsymmetrical alkanes.

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ANSWER :F
Discussion
44.

Which of the following can show optical isomerism

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SOLUTION :
Discussion
45.

Which of the following molecules have bond order equal to 1?

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1) `NO, HF, HCL, Li_(2), CO`
2) `H_(2),Li_(2),HF,Br_(2),HCl`
3) `Li_(2),B_(2) ,CO,NO,He_2^(+)`
4) `B_2,CO,He_2^(+),NO,HF`

Solution :Bond ORDER of `He_(2)^(+) = 0.5`
Bond order of NO = 2.5
Bond order of CO = 3
Discussion
46.

Which is the possible oxidation states of phosphorous in its compounds ?

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`-3` to +5
`-3`, +3 to +5
`-3` , 0 , +5
0 to +5

Answer :A
Discussion
47.

Which amongst the following is the strongest acid?

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`CHBr_(3)`
`CH(CN)_(3)`
`CHI_(3)`
`CHCl_(3)`

Solution :Of the GIVEN compounds `CH(CN)_(3)` is STRONGEST acid because its conjugate base is stabilised by resonance.

`CHBr_(3) and CHI_(3)` are less stable as their conjugate bases are stabilised by inductive effect of HALOGENS. Conjugate base of `CHCl_(3)` INVOLVES back bonding between 2p and 3p orbitals
Discussion
48.

Which among the following molecules has the largest dipole moment ?

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`CH_(3)CH_(2)CL`
`CHCl_(3)`
`NF_(3)`
`XeF_(4)`

ANSWER :A
Discussion
49.

What kind of steps should be taken to control environmental pollution ?

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Solution :Following steps should be taken to control environmental POLLUTION.
(i) Waste Management : SOLID waste is not the only waste, which you see in your household garbage box. Besides household discards, there are medical, agricultural, industrial and mining WASTES. It these wastes is properly disposed and arranged then the level of environmental pollution can be lowered.
(ii) COLLECTION and Disposal : Domestic wastes are collected in small bins, then transferred to community bins by private or municipal workers then these are carried to the disposable site. At the disposable site, garbage is seprated into biodegradable and non-biodegradable materials.
Non-biodegradable materials such as plastic, glass, metal scraps etc. are sent for recycling. Biodegradable wastes are deposited in land fills and converted into compost.
It the waste is not collected in garbage bins, its find way into the sewers or it is EATEN by cattle. Non-biodegradable wastes like polythene bag, metal scraps, etc. choke the sewers and if it swallowed by cattle can cost their lives.
So, in routine life the domestic wastes should be properly collected and disposed.
Discussion
50.

Which is not a source of pollution ?

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FOREST fire
Coal fire
Volcanoes
Dust storm

Answer :D
Discussion