Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

What is the effect on solubility of AgCl, when saturated solution of AgCl is added in different solution of 0.1 AgNO_3 and 0.1 NaCl ?

Answer»

SOLUBILITY in `AgNO_3 GT` Solubility in NaCl
Solubility in `AgNO_3 lt` Solubility in NaCl
Solubility in `AgNO_3` = Solubility in NaCl
Solubility in `AgNO_3`+ Solubility in NaCl = `2K_(sp)`

ANSWER :C
2.

What are the sources of dissolved oxygen in water ?

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SOLUTION :Sources of dissolved OXYGEN in water are (i)photosynthesis (II) natural AERATION and (iii) MECHANICAL aeration
3.

We are good at matching things let us try our hand on the following columns :

Answer»


ANSWER :(a-f,l); (B - e,k); (C - H,j); (d - g,i)
4.

What is the shape of H_3O^+ ?

Answer»

SOLUTION :TRIGONAL PYRAMIDAL
5.

Which one of the following is not a broad spectrum antibiotic ?

Answer»

Tetracycline
Chlormycetic
Penicillin
None of these

ANSWER :C
6.

Which of the following have maximum number of P -H bond ?

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`H_3PO_2`
`H_3PO_3`
`H_3PO_4`
`H_4P_2O_7`

ANSWER :A
7.

Type of isomerism not possible with the molecular formula C_(4)H_(10)O is

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chain
optical
functional
geometrical

Solution :SATURATED
8.

What isuncerainty in location of photod of wavelenght 5000Å if wavelenght is known to anaccuracy of 1 pm?

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`7.96xx10^(-14)`
`0.02m`
`3.9xx10^(-8)m`
None

Solution :`Deltalambda.DELTAX GE(lambda^(2))/(4PI)`
`Deltax ge2xx10^(2)m`
9.

What is dry ice and why is it called so ?

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SOLUTION :SOLID `CO_2`. It does not WET the SURFACE when it MELTS.
10.

What is the use of diborane ? Why BH_(3) exists in the form of diborane ?

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Solution :`BH_(3)` EXISTS in the FORM of DIBORANE `(B_(2) H_(6))` because it is electron deficient . Diborane is used as a reducing agent.
11.

What isspeedof electromagneticradiationin vacuum ?Whatis itcalled?

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Solution :The speedof electromagnaticraditionis`3.0 xx 10^(8) MS^(-1) . `itis knownas speedof rightor velocityof LIGHTAND givethesymboli C
12.

Under critical states for one mole of a gas, compressibility factor is

Answer»

`3/8` 
`8/3`
`1`
`1/4`

SOLUTION :At CRITICAL STATE `Z = 3/g.`
13.

Which of the following can be used as oxidant and reductant both?

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`HNO_2`
`SO_2`
`O_2`
`CO`

Solution :The element (in a molecule ) having oxidation STATE in the middle (i.e ., > minimum and < MAXIMUM ) can be used as reductant and oxidant both
14.

The two sources of Zn, that is, ZnSO_(4) and Zn(CH_(3)COO)_(2)2.H_(2)O, can be purchased at the same price per kilogram of compound. Which is the most economical source of Zn and by how much?

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ANSWER :`ZnSO_(4), 35.9%`
15.

Which of the following is not a combustion reaction

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`CO + (1)/(2) O_(2) RARR CO_(2)`
`C + O_(2) rarr CO_(2)`
`C + (1)/(2) O_(2) rarr CO`
`CH_(4)+ 2O_(2) rarr CO_(2) + 2H_(2)O`

Solution :COMBUSTION `rArr` complete oxidation
16.

Which of the following statements are not correct-

Answer»

the SHAPE of `PCl_(5)` is trigonal pyramidal
the geometrical arrangements of ELECTRON pairs around CL in `ClO_(2)^(-)` is square planar.
the geometrical arrangement of electron pairs arround I in `IF_(4)^(-)` is octahedral
The geometrical arrangement of electron pairs around I in `IC l_(3)` is trigonal planar.

Answer :B::D
17.

Write the structure of the following compounds. BF_(3)

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SOLUTION : A = B ATOM , B = F ATOMS
18.

The stability of the carbanions in the following is…… (i) RC -= overset(Θ)C (iii) R_(2)C = overset(Θ)(C )H (iv) R_(3)C - overset(Θ)( C)H_(2)

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`(iv) gt (ii) gt (iii) gt (i)`
`(i) gt (iii) gt (ii) gt (iv)`
`(i) gt (ii) gt (iii) gt (iv)`
`(ii) gt (iii) gt (iv) gt (i)`

Solution :Higher is the ELECTRONEGATIVITY of ATOM higher will be stability of carbanion on it. Higher is the s-character, higher will be the electronegativity of atom

`R_(3)-C - underset(SP^(3))overset(Θ)(CH_(2))`
19.

Which of the following metal nitrate on heating does not give its metal Oxide?

Answer»

`NaNO_(3)`
`Mg(NO_(3))_(2)`
`CA(NO)_(3)`
`LiNO_(3)`

SOLUTION :(B) `2MG(NO_(3))_(2(s)) overset(Delta)to 2MgO_((s))+4NO_(2(g)) +O_(2(g))`
(C ) `2Ca(NO_(3))_(2(s)) overset(Delta)to 2CaO_((s)) +4NO_(2(g)) +O_(2(g))`
(A) `NaNO_(3(s)) overset(Delta)to 2NaNO_(2(s))+O_(2(g))`
(D) `4LiNO_(3(s)) overset(Delta)to 2Li_(2)O_((s)) +4NO_(2(g)) +O_(2(g))`
`NaNO_(3)` does not form OXIDE but gives `NaNO_(2)` (nitrite) on heating.
20.

Which of the following is correct:

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Due to FORMATION of , Ph-OH does not give Friedel CRAFT acylation REACTION (at normal TEMPERATURE).
Due to formation of

Solution :D) Is REIMER Tiemann carboxylation reaction.
21.

In diborane, the two boron atoms are linked together by two ............ bonds.

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SOLUTION :HYDROGEN, 3c-2e
22.

Which are the atmospheric air pollutants ?

Answer»

Solution :Gaseous air pollutant contains oxides of carbon, NITROGEN and SULPHUR, HYDROGEN sulphide, HYDROCARBONS, OZONE and other oxidizing agents.
23.

Which of the following sequences contain atomic number of only representative elements-

Answer»

3,33,53,87
2,10,22,86
7,17,25,37,48
9,35,55,88

Answer :C::D
24.

Which of the following reactants on reaction with concentrated NaOH followed by acidification gives the following lactone as the only product

Answer»




SOLUTION :
25.

Which of the following is incorrect statement?

Answer»

`GeX_4 (X= F, Cl , Br , I)` is more stable than `GeX_2`
`SnF_4` is IONIC is nature
`PbF_4` is COVALENT in nature
`SiCl_4` is EASILY hydrolysed

Solution :`PbF_4` is covalent in nature
26.

The volume of oxygen liberated at STP from 15 mL of 20 volume H_(2)O_(2) is

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100 ML
150 mL
200 mL
300 mL

Solution :1 mL of 20 volume `H_(2)O_(2)` liberates `O_(2)` at STP =20 mL
`THEREFORE ` 15 mL of `H_(2)O_(2)` will liberate `O_(2)` at STP `=15xx20=300 `mL
27.

The value of DeltaH and DeltaS for the reaction C_("(graphite)")+CO_92)(g) rarr 2CO(g0 are170 kJ and 170JK^(-1) respectively. This reaction will be spontaneous at

Answer»

910 K
1110K
510K
710 K

Solution :`DeltaG =DeltaH - T DeltaS`. For reaction to be spontaneous `DeltaS` should be -ve, i.e.,`DeltaH-TDetlaS lt0 `or `DeltaHlt T DeltaS`
or `TDeltaS gt DeltaH ` or`Tgt ( DeltaH )/( DeltaS) , i.e.,T gt (170000J)/( 170 JK^(-1))`or `T gt 1000K`. Hence, options (b) ISCORRECT. This method can be APPLIED only when `DeltaH` and`DeltaS` both are `+ve`.
Alternatively, for equilibrium, `DeltaG =0`
`i.e., T DeltaS = DeltaH` or `T= ( DeltaH )/( DeltaS) =( 170000)/( 170) =1000K`
For spontaneity , `DeltaG = -ve`which can be so if `T gt 1000 K` ( so that`T DeltaS gt DetalH` in magnitude ) .
28.

Which are the transition elements and inner transition elements ?

Answer»

Solution :3d transition element : Sc (Z = 21) to Zn (Z = 30)
4d transition element: Y (Z = 39) to Cd (Z = 48)
5d transition element: La (Z = 57) to HG (Z = 80)
6d transition element: Ac (Z = 89) to Cn (Z = 112)
4F inner transition elements or Lanthanoid series : Ce (Z = 58) to Lu (Z = 71)
5finner transition elements or ACTINOID series: Th (Z = 90) to Lr (Z = 103)
29.

What are ideal solution ? Give example.

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Solution :An ideal solution is a solution in which each component i.e. the SOLUTE as WELL as the SOLVENT obeys the Raoult.s LAW over the entire range of CONCENTRATION.
30.

Which of the following has pyramidal shape?

Answer»

`XeF_4`
`XeO_3`
`XeF_2`
`XeF_6`

ANSWER :B
31.

The specific test for H_(2)S_(2) is

Answer»

It turns STARCH iodide PAPER to blue COLOUR
It WHITENS BLACKENED lead paintings
Its turns `Ti(SO_(4))` solution to orange colour
It decolourise acidfied `KMnO_(4)` solution

Solution :Only`H_2 O_2` turns`Ti (SO_4)_2`solution toorangecolour .
32.

Write the Lewis structure of the nitrite ion,NO_2^-.

Answer»

SOLUTION :
33.

why carbon show catendation but silicon does not ?

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Solution :As we move down the group 14, the ATOMIC size increasesand HENCETHE STRENGTH of the element -elementbond, i.e, the bonddissociationenthalphy decreasessteadily. Consequentlythe tendencyfor CATENDATION decreasesdown the group with increasingatomic NUMBER.
34.

Which element shown less shield effect ?

Answer»

Group-12, period-4
Group-12, period-3
Group-12, period-2
Group-12, period-5

Answer :C
35.

Which of the following alkene is the most stable

Answer»

`CH_(3)-CH=CH_(2)`
`CH_(3)-CH=CH-CH_(2)`
`(CH_(3))C=CHCH_(3)`
`(CH_(3))_(2)C=C(CH_(3))_(2)`

Solution :No.of stability a NUMBER of `alpha`-H ATOMS
36.

Which one of the following statements is incorrect in relation to ionization enthalpy?

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Ionization enthalpy increases for each SUCCESSIVE electron.
The greatest INCREASE in ionization enthalpy is experienced on REMOVAL of electron from core noble gas configuration .
End of valence ELECTRONS is marked by a big jump in ionization enthalpy.
Removal of electron from orbitals bearing lower n value is easier than from orbital having higher n value.

Answer :d
37.

Which is the product of the following reaction ?

Answer»




SOLUTION :
38.

The standard electrode potentials of few metals are give below AI (-1.66 v),cu(+0.34V),Li(-3.05 v),Ag(+0.80 v) and Zn (-0.76) V) Which of these will behave as the strongest oxidising agent and which as the strongest reducing agent ?

Answer»

Solution :Since `E^(@)` value of LI (-3.05 V) is thelowest while that of AG(+0.80 V) lis the HIGHEST therefore Li is the strongest reducing agent while `Ag^(+)` is the strongest oxidising agent
39.

What is the value of the equilibrium constant for the following reaction at 400 K ? 2NOCl(g) hArr 2NO(g) + Cl_(2)(g) Delta H^(@) = 77.5 kJ mol^(-1), R = 8.3124 J mol^(-1) K^(-1), Delta S = 135 J K^(-1) mol^(-1).

Answer»

Solution :`Delta G = Delta H - T Delta S`
`Delta G = 77.5 XX 1000 J - 400 K + 135 J K^(-1) = 77500 J - 54000 J = 23500 J`
`Delta G = -2.303 RT LOG K`
`23500J = -2.303 xx 8.314 xx 400 K log K`
`log K = (-23500)/(19.147 xx 400 K) = (-235)/(76.588) = -3.068`
K = ANTILOG (-3.608)
`"Antilog" (0.932 - 4)= "Antilog" (0.93) xx 10^(-4) = 8.55 xx 10^(-4)`.
40.

Which among the following compounds show geometrical isomerismI)1- butene II) 2-butene III) 2-methyl-2-butene IV) 2-pentene

Answer»

II,III
II,III,IV
II,IV
I,II,IV

Solution :DOUBLE bonded CARBON with same GROUPS does not show geometrical isomerism
41.

The value of carbon-carbon triple bond length is …………….

Answer»

1.33Å
1.20Å
1.54Å
1.43Å

Solution :1.20Å
42.

Which type of attraction force pressure in ideal gas ?

Answer»

Solution :There is no attraction forces present in IDEAL gas. It is assumed that INTER MOLECULAR forces are not present between the molecular of an ideal gas this ideal gas is HYPOTHETICAL.
43.

Which of the following reagent is used to find out carbon-carbon multiple bonds?

Answer»

GRIGNARD reagent
Bayer's reagent
Sandmayer's reagent
Gattrman reagent

Answer :B
44.

Which one of the following is an intensive property?

Answer»

SPECIFIC HEAT capacity
Mass
Enthalpy
Heat capacity

Answer :A
45.

When an alkali metal dissolves in liquid ammonia , the solution can acquire different colours . Explainthe reasons for this type of colour change .

Answer»

Solution :The dilute solution of alkali metals in liquid AMMONIA exhibit dark blue colour because ammoniated electrons absorb energy corresponding the red region of the visible light .
`M + (x + y) NH_(3) to [M (NH_(3))_(x) ]^(+) + underset("Ammoniated electrons")(e^(-) (NH_(3))_(y))`
However , if the concentration INCREASES above 3M, the colour CHANGES to copper-bronze and the solution acquires metallic lustre due to the formationof METAL ion clusters.
46.

What are the salient features of Valence Bond (VB) theory?

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Solution :(i) When half filled orbitals of TWO atoms overlap, a covalent BOND will be formed between them.
(ii) The resultant overlapping orbitals are occupied by the two electrons with opposite spins.
For example when `H_(2)` is formed, the two 1s electron of two hydrogen atoms get paired up and occupy the overlapped orbitals.
(iii) The strength of a covalent bond depends upon the extent of overlap of atomic orbitals. Greater the overlap, larger is the energy RELEASED and stronger will be the bond formed.
(iv) Each atomic ORBITAL has a specific direction (except s-orbital which is spherical) and hence orbital overlap takes place in the direction that maximises overlap.
(v) Depending upon the nature of overlap, the bonds are classified as `sigma` covalent bond and `pi` covalent bond.
(vi) When two atomic orbitals overlap linearly along the axis, the resultant bond is called a sigma `(sigma)` bond. This overlap Is also called "head-on-overlap" or "axial overlap"
(vii) When two atomic orbitals overlap Sideways the resultant covalent bond is called a `(pi)` bond.
47.

Which of the following can show geometrical isomerism?(i) Propene (ii) But-1-ene (iii) But-2-ene (iv) Pent-2-ene

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SOLUTION :III and IV
48.

Which of the following oxides is most acidic in nature ?

Answer»

MGO
BEO
BaO
CaO

Solution :As electropositive character of alkaline earth metals increases down the group , the basic character of their OXIDES increases . Thus BeO is least basic and hence most acidic . Actually , BeO is AMPHOTERIC in nature .
49.

Which of the following is correct with respect to bond length of the species ?

Answer»

`C_(2) gt C_(2)^(2-)`
`B_(2)^(+) gt B_(2)`
`Li_(2)^(+) gt Li_(2)`
`O_(2) gt O_(2)^(-)`

SOLUTION :Bond order : `C_(2)= 2 , C_(2)^(2-) = 3 , B_(2) = 1 , B_(2)^(+) = 0.5 ` ,
`Li_(2) = 1 , Li_(2)^(+) = 0.5 , N_(2)= 3 , N_(2)^(+) = 2.5 , O_(2) = 2 `
`O_(2)^(-) = 1.5` . Greater the bond order , SHORTER is the bond length
50.

Which of the following shows the correct order of decreasing stability?

Answer»




ANSWER :B