Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

X and Y are two elements which form X_(2)Y_(3 and X_(3)Y_(4). If 0.20 mol of X_(2)Y_(3) weighs 32.0g and 0.4mol of X_(3)Y_(4) weighs 92.8g, the atojic weights of X and are respectively:

Answer»

16.0 and 56.0
8.0 and 28.0
56.0 and 16.0
28.0 and 8.0

Answer :C
Discussion
2.

Which of the following represents 3-methylpenta-1,3-diene?

Answer»

`CH_(2)=CH(CH_(2))_(2)CH_(3)`
`CH_(2)=CHCH(CH_(3))CH_(2)CH_(3)`
`CH_(3)CH=C(CH_(3))CH=CH_(2)`
`CH_(3)CH=C(CH_(3))_(2)`

Answer :C
Discussion
3.

Write the electronic configurations of the following ions. (i). Mn^(2+) (ii). Fe^(3+) (iii) Ni^(2+) ltBrgt (iv). Cr^(3+).

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Solution :(i) `[Ar]3d^(5)4S^(0)`
(ii) `[Ar]3d^(5)4s^(0)`
(iii) `[Ar]3d^(8)4s^(0)`
(iv) `[Ar]3d^(3)4s^(0)`.
Discussion
4.

What are the necessary conditions for any compound to show aromaticaly?

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Solution :(i) The system (or species) must be planar (II) It should be cyclic
(III) It must contain (4n+2) delocalised `pi` ELECTRONS where n is an integer (including Zero). THUS conjugated, planar cyclic systems containing 2,6,10,14…. Delocalised `pi` electrons will be aromatic
Discussion
5.

Which of the following reagents cannot be used for the preparation of hydrogen peroxide ?

Answer»

SODIUM peroxide
2 - Ethylanthraquinol
Sodium thiosulphate
Barium peroxide

Answer :C
Discussion
6.

When R-Mg - X , Grignard's Reagent is treated with solvents can yield alkanes. . What is A ?

Answer»

`C_2H_6`
`C_3H_8`
`CH_4`

SOLUTION :
Discussion
7.

What is oxidation number of oxygen in Na_(2)O_(2), Na_(2)O, OF_(2) compounds ?

Answer»

`-2, -1, 0`
`-1, -2, +1`
`-1, -2, +2`
NONE of these

Answer :C
Discussion
8.

What is the ratio between the energies of two radiations, one with a wavelength of 6000 Å and the other with 2000 Å [1 Å = 10^(-10)m]?

Answer»

SOLUTION :`(1)/(3)`
Discussion
9.

When an equimolar mixture of two gases A and B [M_(A)gtM_(B)] is allowed to effuse thrugh a pin hole :

Answer»

B COMES out at a faster rate
relative rate of effusion of A increaes with TIME
fate of effusion of B will always be GREATER
Initially, with equal MOLAR RATIO, rate of effusion of B is greater than rate of effusion of A.

Answer :abd
Discussion
10.

Which one of the following is non-aromatic?

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ANSWER :d
Discussion
11.

The reagents used fro softening of the temporary hardness of water is/are

Answer»

`Ca_(3)(PO_(4))_(2)`
`Ca(OH)_(2)`
`Na_(2)CO_(3)`
`NAOCL`

Solution :`Ca(OH)_(2) and Na_(2)CO_(3)` react with bicarbonates of Ca and Mg present in temporary hard water to form the corresponding insoluble CARBONATES which upon filtration give soft water.
`Ca(HCO_(3))_(2) + Ca(OH)_(2) to 2CaCO_(3) darr + 2H_(2)O`
`Ca(HCO_(3))_(2) + Na_(2)CO_(3) to CaCO_(3) darr + 2NaHCO_(3)`
Discussion
12.

Which of the fallowing compounds can be best prepared by wurtz-reaction?

Answer»

iso-butane
n-butane
n-pentane
iso-pentane

Solution :n-butane
Discussion
13.

What is K_(H) inP_("solute")= K_(H) X_("solute") ? On what does the value of K_(H) depend ?

Answer»


ANSWER :Pure heavy WATER kills SMALL fishes, TADPOLES and mice when fed upon it
Discussion
14.

Which does not form peroxides?

Answer»

Ba
Be
Ca
Sr

Answer :2
Discussion
15.

What is the mole fraction of the solute in a 1.0m aqueous solution ?

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`1.770`
`0.0354`
`0.0177`
`0.177`

SOLUTION :1.0 m (MOLAL) solution implies that 1 mole of the solute is dissolved in 1000 G of the solvent (WATER)
Mole fraction of solute `= (("1 mol"))/(1" mol"+((100g))/(("18 g mol"^(-1))))=(1)/(56.5)`
`=0.0177`.
Discussion
16.

When mercury is oxidised by H_2O_2the increase in oxidation state of mercury is

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2
5
4
1

Answer :A
Discussion
17.

Using the ideal gas equation how will you calculate the values of R ?

Answer»

Solution :We can calculate R using the equation,
`R=(PV)/(nT)`
(i) P is 1 atm, volume `22.414 md^(3)`. For 1 OLE at 273.15 K.
`R=(1 atm xx22.414 md^(3))/(1 "mol"xx273.15 k)`
`=0.0821 dm^(3) atm. "mol"^(-1)K^(-1)`
(II) (STP),
Where `P=1 "bar" (10^(5)` pascal)
`V=22.71xx10^(-3)m^(3) ` for 1 mole of gas at `273.15K`
`R=(10^(5)Px xx22.71xx10^(-3)m^(3))/(1 "mol"xx273.15K)`
`=8.314 Pam^(3) K^(-1) "mol"^(-1)`
`=8.314xx10^(-2) "bar" m^(3) K^(-1) "mol"^(-1)`
`=8.314xx10^(-2) "bar" dm^(3)K^(-1) "mol"^(-1)`
`=8.314xx10^(-2) bar LK^(-1)"mol"^(-1)`
`=8.314 J K^(-1) "mol"^(-1)`
Discussion
18.

The volume of 2.8g of carbon monoxide at 27^@C and 0.821 atm pressure is (R= 0.0821 "lit-atm" mol^(-1) K^(-1))

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1.5 LIT 
0.3 lit 
3 lit 
30lit

Answer :C
Discussion
19.

Write the IUPAC names of the following :

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SOLUTION :(i) 5-Methylhexa-1, 4-diene
(II) But-1-en-3-yne
(III) 6-Bromoheptanal.
Discussion
20.

What is the atomic mass of oxygen ?

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16.5 U
15.995 u
17 u
18 u

Answer :A::B
Discussion
21.

Which is the Acid in H_2O and CH_3COO^- which one is weak base ?

Answer»

SOLUTION :CONJUGATE base of weak acid, `CH_3COO^-` will be strong and `H_2O` will be weak base.
Discussion
22.

Which of the following sulphides is yellow in colour ?

Answer»

CuS
CDS
ZnS
CoS

Solution :CdS is YELLOW in COLOUR.
Discussion
23.

What is meant by ppm? Where is it used ?

Answer»

Solution :PARTS PER million `= PPM = ("Mass of the solute")/("Mass of solution") xx 10 ^(6)`
(ii) ppm is used to express the quantity of solutes present in small AMOUNTS in solutions.
Discussion
24.

What is the mass of carbon present in 0.5 moles of K_(4)[Fe(CN)_(6)] ?

Answer»


Solution :1 mole of `K_(4)[Fe(CN)_(6)]` contain carbon = 6 g atoms
0.5 mole of `K_(4)[Fe(CN)_(6)]` contain carbon = 3g atoms
MASS of carbon in grams `= (12g)xx(("3 g atoms"))/(("1G ATOM"))=36G` .
Discussion
25.

Which does have more atoms, 1.0 g of hydrogen or 1.0 g of oxygen ?

Answer»

SOLUTION :1.0 G HYDROGEN.
Discussion
26.

The volumes of ozone and chlorine diffusingduring the same time are 35 ml and 29 mL respectively. If the molecular weight of chlorine is 71, calculate the molecular weight of ozone.

Answer»


ANSWER :D
Discussion
27.

Which of the following factors are responsible for theh increase in the rate of a surface catalysed reaction 1. A catalyst provides proper orientation for the reactant molecules to react. 2. Heat of adsorption of reactants on a catalyst helps reactant molecules of overcome activation energy. 3. The catalyst increases thhe activation energy of the reaction. 4. Adsorption increases thhe local concentration of reatant molecules on the surface of the catalyst Select the correct answer using the code given below:-

Answer»

1 and 2
1 and 3
2 and 4
1,2 and 4

Answer :D
Discussion
28.

What is the mass of one molecule of methane ?

Answer»




SOLUTION :Mass of one MOLECULE `=(16)/(6.022 XX 10^(23))`
`= 2.657xx10^(-23)`
Discussion
29.

Which one of the following is the correct set with reference to molecular formula, hybridisation of central atom and shape of the molecule?

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`CO_(2), SP^(2)` bent
`H_(2)O,sp^(2)` bent
`BeCl_(2)`, sp, LINEAR
`H_(2)O, sp^(3)` linear

Answer :C
Discussion
30.

Which of the following reactions is/are feasible? (a) CH_(3)COOH+HC"OO"Na to""(b) HC=C-Na=H_(2)O to

Answer»


ANSWER :(a) Not FEASIBLE(B) Feasible(C) Not feasible(d) Not feasible
Discussion
31.

Which of the following properties of liquid increases on increasing temperature :

Answer»

VAPOUR pressure
Viscosity
Surface tension
Boiling point

Answer :A
Discussion
32.

What weight of CaCO_(3) must be decomposed to produce the sufficient quantity of carbon dioxide to convert 21.2 kf of Na_(2)CO_(3) completely in NaHCO_(3). [Atomic mass Na=23, Ca=40] CaCO_(3) rightarrow CaO + CO_(2) Na_(2)CO_(3) + CO_(2) + H_(2)O rightarrow 2NaHCO_(3)

Answer»

100Kg
20kg
120Kg
30Kg

Answer :B
Discussion
33.

What are the uses of freons?

Answer»

Solution :(i) FREONS are USED as refrigerants in refrigerators and air conditioners.
(II) It is used as a propellant for foams and aerosols.
(III) It is used as a propellant for foams to spray out deodorants, shaving CREAMS and insecticides.
Discussion
34.

Which type of hybridisation of each carbon is there in the compound ? CH_(3)-CH=CH-CN

Answer»

`SP^(3),sp^(2),sp^(2),sp`
`sp^(3),sp^(2),sp^(2),sp^(3)`
`sp^(3),sp^(2),sp^(3),sp^(3)`
`sp^(3),sp^(2),sp,sp^(3)`

ANSWER :A
Discussion
35.

What is ionic equilibrium ?

Answer»

Solution :In AQUEOUS solution of weak ELECTROLYTES, the EQUILIBRIUM is set up between the IONS and the undissociated electrolyte is called ionic equilibrium.
e.g. `CH_3COOH + aq HARR CH_3COO_((aq))^(-) + H_((aq))^(+)`
Discussion
36.

What mass of MnO_2is reduced by 35mL of 0.16N oxalic acid in acid solution ? The skeleton equation is, MnO_(2) + H^(+) + H_(2)C_(2)O_(4) rarr CO_2+H_2O+Mn^(2+)

Answer»

8.7 G
0.24 g
0.84 g
43.5 g

SOLUTION :`1000xx(W)/55xx2=35xx0.16`
`w = (35xx0.16xx55)/2000`
`3x = -8 , w =(0.16xx35xx55)/(2xx1000)=024 g`
Discussion
37.

Which of the following reaction will give alkyne ?

Answer»

`CH_3underset(Cl)underset(|)CH-underset(Cl)underset(|)CH-CH_3 underset(H_3O^(+))overset(NaNH_2)to `
`CH_3CH_2 CHBr_2 underset((ii) NaNH_2)overset((i) ALC. KOH)to`
`R-C -= CNA overset(R^(1)-X)to`
Potassium maleate `overset("electrolysis")to`

SOLUTION : Preparation of ALKYNES
`{:(CHCOOK),(||),(CHCOOK):} overset("Electrolysis")to {:(CH),(|||),(CH):} + 2CO_2 + 2KOH + H_2`
`R-C -= CNa overset(R^(1)-X)to R -C -= C - R^(1) + NAX`
`R-CHBr - CH_2Br - + 2NaNH_2 to R - C -= CH + 2NaBr`
Discussion
38.

Which of the following compounds shall not produce propene by reaction with HBr followed by elemination (or) only direct elimination reaction

Answer»


`CH_(3)-CH_(2)-CH_(2)-OH`
`H_(2)C=C=O`
`CH_(3)-CH_(2)-CH_(2)Br`

Answer :B::C
Discussion
39.

Which one of the following has an electrovalent linkage?

Answer»

`CH_(4)`
`MgCI_(2)`
`SiCI_(4)`
`BF_(3)`

Answer :B
Discussion
40.

Which one of the following compounds shows the presence of intra molecular hydrogen bond?

Answer»

CELLULOSE
Concentrated acetic acid
`H_(2) O_(2)`
HCN

Solution :Cellulose
In acetic acid `H_(2) O_(2)` and HCN INTER molecular hydrogen bond PRESENT but in cellulose intramolecular hydrogen bond present.
Discussion
41.

What is the structure of IF_7 ?

Answer»

SQUARE pyramidal
Trigonal bipyramidal
OCTAHEDRAL
PENTAGONAL bipyramidal

Answer :D
Discussion
42.

The types or bonds present in CuSO_(4) 5H_(2)O (blue vitriol) are

Answer»

ELECTROVALENT and COVALENT
electrovalent, covalent, co-ordinate and HYDROGEN BOND
covalent and co-ordinate covalent
electrovalent

Answer :B
Discussion
43.

Whichof the followingsetsrepresents a collectionof isoelectronicspecies? (Atnos. Cs = 55,Br= 35)

Answer»

`CA^(2+) , Cs^(+) Br`
`Na^(+) Ca^(2+) , Mg^(2+)`
`N^(3-) , F^(-), Na^(+)`
`Be, A1^(3+) CI^(-)`

SOLUTION :NA
Discussion
44.

When an ideal gas at a pressure P, temperature T and volume V is isothermally compressed to ((V)/(n)), its pressure becomes P_("iso") and if the same process is carried out adiabatically and reversibly, its pressure becomesP_("adia"). Which of the following is correct for (P_("iso"))/(P_("adia")) ?

Answer»

1
N
`n^(gamma)`
`n^(1- gamma)`

Solution :For ISOTHERMAL process PV= constant
For ADIABATIC process `PV^(gamma)`= constant
Discussion
45.

The work done when 65.38g of zinc dissolved completely in HCl in an open beaker at 300k

Answer»

`-2494 J`
`- 249.4J`
`1J`
`- 24.94J`

ANSWER :A
Discussion
46.

Which process is exothermic ?

Answer»

CONDENSATION
FUSION
sublimation
vaporization

ANSWER :a
Discussion
47.

What is the normality of 5.3%(w/v) aqueous solution of Na_(2)CO_(3)?

Answer»


ANSWER :0.5 MOL `L^(-1)` and 1 EQ `L^(-1)`
Discussion
48.

Which of the following combination will produce H_(2) gas ?

Answer»

Cu metal and conc. `HNO_(3)`
ZN metal and NaOH (aq)
Au metal and NaCN (aq) in the presence of air
Fe metal and conc. `HNO_(3)`

Solution :NITRIC being a strong oxidising AGENT, oxidises initially Cu to `CUO` which further reacts with `HNO_(3)` to form `Cu(NO_(3))_(2)` with the evolution of `NO_(2)` gas. However , `H_(2)` gas is not produced.
Fe becomes passive in conc. `HNO_(3)` DUE to the formation of an impervious layer of iron oxide on its surfacewhich prevents the further action. Au reacts with NaCN in presence of air to form soluble complex of dicyanoaurate (I)
`underset("Dicyanoaurate "(I))(4Au + 8 NaCN+ 2H_(2)O + O_(2) to 4Na [Au(CN)_(2)]+4NaOH`)
Only Zn reacts withe NaOH solution to evolve `H_(2)` gas
`Zn+2NaOH overset(Delta)to underset("Sod. zincate")(Na_(2)ZnO_(2))+H_(2)`
Discussion
49.

The type of isomerism shown by the following compounds is CH_(3)CH_(2)CH_(2)CH_(2)CH_(3),CH_(3)-overset(CH_(3))overset(|)(C)H-CH_(2)CH_(3),CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH_(3)

Answer»

POSITION isomerism
metamerism
ring-chain isomerism
chain isomerism

Answer :D
Discussion
50.

What are free radical initiators? Give an example.

Answer»

Solution :The types of reagents that PROMOTE homolytic cleavage in substrate are called as free radical initiators. They are short LIVED and are highly REACTIVE.
Example: (i) Azobisisobutyronitrile (AIBN) (II) BENZYL peroxide.
Discussion