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7351.

Which of the following is correct for both the following coordination compounds ? (P) CoCl_(3).6NH_(3) and (Q) PtCl_(4).5NH_(3)

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They give white PRECIPITATE with `AgNO_(3)` solution
The have DIFFERENT PRIMARY valencies for the central metal ions.
Both (a) and (b)
None of these

Solution :`(P)to[Co(NH_(3))_(5)Cl]Cl_(2)`
`(Q)to[Pt(NH_(3))_(5)Cl]Cl_(3)`
7352.

Which of the following reactions will yield phenol ?

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SOLUTION :
7353.

Which of the following reaction/statement is incorrect?

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Benzenediazonium chloride is prepared by the REACTION of aniline with nitrous acid at 273 - 278 K

The conversion of primary aromatic amines into diazonuim salts is known as DIAZOTISATION
Diazonium salt is not GENERALLY stored, used IMMEDIATELY after its preparation

Solution :Benzenediazonium chloride is prepared by the reaction of aniline with nitrous acid at 273-278 K . The conversion of primary aromatic amines into diazonium salts is known as diazotisation. Due to its unstability, the diazonium salt is not generally stored and is used immediately after its preparation.
`C_6H_5NH_2 + NaNO_2 + 2HCl overset(273-278 K)to C_6H_5N_2^(+)Cl^(-) + NaCl + 2H_2O`
Temperature must vary from `0.5^@ C`
7354.

Which one of the following cannot be estimated byl_2?

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`SnCl_2`
`CU^(2+)`
`Na_2S_2O_3`
 `H_2S`

ANSWER :B
7355.

Which of the following compound would give secondary alcohol when reacts with an excess of phenyl magnisium bromide followed by hydrolysis.

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`C_(6)H_(5)-CH_(3)CN`

Answer :C
7356.

When C_2H_5OH is mixed with ammonia and passed over heated alumina, the compound formed is :

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`C_2H_5NH_2`
`C_2H_4`
`C_2H_5OC_2H_5`
`CH_3OCH_3`

ANSWER :A
7357.

The volume occupied by 22.4 g of a gas ("vap. Density" = 11.2) at NTP is

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22.4 LITRE
11.2 litre
44.8 litre
1 litre

Solution :`V= (NRT)/(P)=(((22.4)/(22.4)) xx0.0821 XX 273)/(1)=22.4`
7358.

Which two reagents are required to produce D.D.T. ?

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CHLORAL and Chloroform
Chloral and Chlorobenzene
Chloroform and Chlorobenzene
Chloroform and `C Cl_(4)`

ANSWER :B
7359.

The solution which are isotonic with 6% (W/V) solution of urea are :

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18% (W/V) solution of glucose
0.5 M solution of `BaCI_(2)`
1M solution of sucreose
1 M solution of scetic acid

Solution :(a,c) Osmotic pressure `(PI)=iCRT`
`C_((Urea))=6g/100mL=60G/L=((60g))/((60"g mol"^(-1)))=1M`
`ppi_((urea))=iCRT=RT(i=1)`
`pi_((glucose))=18g/100mL=180G/L=((180g))/((180"g mol"^(-1)))=1M`
`pi_("glucose")=iCRT=RT.I(i=1)`
`(b)pi(BaCI_(2))=iCRT=(3)xx(0.5)RT=1.5RT` ltbtgt `(c) pi_(("sucrose"))=CRT=(1)RT=RT`
`(d)pi_(("acetic acid"))=CRT=iCRT=2xx1RT=2RT`
Thus (a) and (c) are isotonic with 6% solution of urea.
7360.

What is Rosenmund's reduction? What is the purpose of adding BaSO_(4) in it?

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Solution :(i) When reduced with hydrogen in the presence of 'poisoned' palladium catalyst, they form aldehydes. This reaction is called Rosenmund reduction.
`underset("Acetyl chloride")(CH_(3)-underset(O)underset(||)(C)-CL)+H-Hunderset(BaSO_(4))overset(Pd)tounderset("Acetaldehyde")(CH_(3)-underset(O)underset(||)(C)-H)+HCl`
(ii) `BaSO_(4)` is used as a catalytic poison to stop the reduction at the stage of aldehyde.
(iii) Otherwise, the aldehyde formed will be further reduced to primary alcohol.
7361.

To which series will the following elements belong? ""_(103)^(257)Lr, ""_(99)^(254)Es, ""_(95)^(243)A m

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SOLUTION :`(4n+1, 4n+2, 4n+3)`
7362.

Which of the given statements is incorrect about boric acid?

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It is a weak monobasic acid
It is not a PROTONIC acid
It ACTS as a lewis acid by accepting electrons
It is a TRIBASIC acid

Answer :D
7363.

What are primary cells?

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Solution :PRIMARY cells are those in which the redox reaction OCCURS only once and the cell BECOMES DEAD after sometime and cannot be USED again.
7364.

Which pair of elements can form multiple bond with itself and oxygen ?

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`F,N`
`N, Cl`
`N,P`
`N,C`

ANSWER :D
7365.

You are given benzene, conc. H_2SO_4 and NaOH. Write the equations for the preparation of phenol using these reagents.

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Solution :`UNDERSET("BENZENE")(C_6H_6)underset(("Sulphonation"))OVERSET(conc.H_2SO_4.Delta)tounderset("Benene sulphonic acid")(C_6H_5SO_3H)underset(-Na_2SO_3)overset("NaOH. fuse. 573 K")tounderset("SOD Phenoxide")(C_6H_5ONa)underset(-NaCl)overset(Dil. HCL)to underset("Phenol")(C_6H_5OH)`
7366.

What will be the product of reaction, ""_(101)^(255)Md (alpha, 2n)?

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`""_(103)^(256)Lr`
`""_(102)^(257)No`
`""_(103)^(257)Lr`
`""_(82)^(205)Pb`

Solution :`""_(101)^(255)Md + ""_(2)^(4)ALPHA to ""_(103)^(257)Lr + 2 ""_(0)^(1)n`
7367.

Which of the following does not form lyophilie sol?

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gelatin
gum
`As _(2)S_(3)`
STARCH.

ANSWER :C
7368.

Write the mechanism of corrosion.

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ANSWER :
7369.

underset((g))(A)+1/2underset((g))(B)tounderset((g))(2C)+1/2underset((g))(D) the rate of disappearance of B is x. What is the rate of appeance of C?

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3x
x/2
2x
4x

Solution :`A+1/2Bto2C+1/2D,(r_(B))/((1//2))=(r_(c))/2,2r_(B)=(r_(C))/2,r_(C)=4r_(B)=4XX`
7370.

Write IUPAC name of: CH_(3)-CH_(2)-CH=CH-overset(O)overset(||)(C)-H

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SOLUTION :Pent-2-en-1-al
7371.

Which of following compound gives positive isocyanide test?

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`CH_(3)-NH-CH_(3)`
`CH_(3)-CH_(2)-NH_(2)`
`CH_(3)-NH-Ph`
`CH_(3)- underset(CH_(3)) underset(|)-CH_(3)`

ANSWER :B
7372.

Which of the following is nitrogenous fertilizers

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Bone MEAL
Thomas meal
NITRO phosphate
AMMONIUM sulphate

Solution :Ammonium sulphate is a NITROGENOUS fertilizers.
7373.

Which of the following pair of substances are used as promoter in Haber process for production of NH_3 ?

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FeO and Fe
KCL and `AlCl_(3)`
`K_(2)O` and `Al_(2)O_(3)`
KCl and `FeCl_(3)`

ANSWER :C
7374.

What would be the atomic number of the missing species in the given transmutation .^(10)B(alpha,n)__________

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ANSWER :`7`
7375.

Which metal is purified by electrolytic method ?

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TIN 
SILICON 
ZINC 
Mercury 

Answer :C
7376.

The reagent used in the conversion of Benzaldehyde to Benoin is ...........

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SOLUTION : ALCOHOLIC KCN
7377.

What is lanthanoid contraction? Mention the cause for it.

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SOLUTION :The gradual decrease in the ATOMIC and ionic RADII of lanthanide elements due to poor shielding of 4F electrons.
7378.

Two liquids X and Yform an ideal solution. At 300 K, vapour pressure of the solution containing I mol of X and 3 mol of Y is 550 mmHg. At the same temperature, if 1 mol of Y isfurther added to this solution, vapour pressure of the solution increases by I 0 mmHg. Vapour pressure ( in mmHg) of X and Yin their pure states will be, respectively:

Answer»

300 and 400
400 and 600
500 and 600
200 and 300

Solution :`P _("total") =p_(A) ^(@)X_(A) + p _(B)^(@) X _(B)`
`550 =p_(A)^(@) xx1/4 +p_(B)^(@) xx3/4`
`p _(A)^(@) + 3P _(B)^(@) =550 xx 4 ""…(i)`
In seond case
`P _("total") = p_(A)^(@) xx1/5 +p_(B)^(@) xx4/5`
`p _(A) ^(@)_ +4P _(B)^(@) =560 xx5 ""...(II)`
Subtract (i) from (ii)
`therefore jp _(B)^(@) =560 xx5-550 xx 4=600`
`because p _(A)^(@) =400`
7379.

Which of the following statements is true regarding molecularity and order of reaction?

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Order of the reaction can be determined from stoichiometry of the reaction
For the COMPLEX reaction,the fastes step decides order of the reection.
Molecularity cannot be defined for the REACTIONS OCCURING in more than one step.
The order of the reaction for trimolecular reaction is always 2

Answer :C
7380.

Victor Meyer's test is not given by

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`(CH_(3))_(3)COH`
`C_(2)H_(5)OH`
`(CH_(3))_(2)CHOH`
`CH_(3)CH_(2)CH_(2)OH`

Solution :Tertiary alcohols such as `(CH_(3))_(3)COH` do not GIVE Victor Meyer.s test.
7381.

Which of the following is better fuel ?

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Solid
Liquid
Gaseous
Semi solid

Answer :C
7382.

Which of following is not considered transition element?

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Zn
Ag
Au
All of these

Answer :A
7383.

Which of the following does not involve sp^(3) hybridisation of the central atom ?

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`SiH_(4)`
`NH_(3)`
`SF_(4)`
`H_(2)O`

ANSWER :C
7384.

What volume of 0.1M KMnO_(4) is needed to oxidize100 mgof FeC_(2)O_(4) in acid solution ?

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`4.1` ML
`8.2` ml
`10.2` ml
`4.6` ml

SOLUTION :Meq. of `KMnO_(4) = " Meq. of " FeC_(2)O_(4)`

` :. V = 4.1` ml
7385.

Which of the following will not produce ethane?

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REDUCTION of `CH_3COOH` with HI and RED P
Reduction of `CH_3COCH_3` with HI and red P
Soda LIME decarboxylation of sodium propionate
Hydrogenation of ethene in PRESENCE of Raney Ni

Solution :Reduction of `CH_3 COCH_3` with HI/red P will give propane.
7386.

What is the relationship between depression in freezing point of a solution and molecular mass of the solute ?

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Solution :DEPRESSION in freezig point `(DeltaT_f)` is related with molecular mass (M) of solute as FOLLOWING : < br> `DeltaT_f = K _f "(W xx 1000)/(M xx W)`
where `K_f` = molal elevation constant of SOLVENT < br> w = wt. of solute in gm
W = wt. of solution in gm
7387.

Which of the following ions give ppt. with BaCl_(2) solution?

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`SO_(4)^(2-)`
`S_(2)O_(3)^(2-)`
`S^(-2)`
`SO_(3)^(2-)`

Solution :`BaCl_(2)+SO_(4)^(2(-)) to BaSO_(4)+2CL^((-)), BaCl_(2)+S^(2(-)) to BAS, BaCl_(2)+SO_(3)^(2(-)) to BaSO_(3)`
7388.

Total number of paramagnetic complexes which are inner orbital complexes : (i) [Cr(NH_(3))_(6)]Cl_(3) "" (ii)[Co(NH_(3))_(6)](NO_(3))_(2)"" (iii)[Ni(NH_(3))_(6)]SO_(4) (iv) K_(2)[PtCl_(6)]. "" (v) [V(H_(2)O)_(6)]SO_(4) "" (vi) [Mn(NH_(3))_(6)]SO_(4) (vii)[Fe(H_(2)O)_(5)(NO)]SO_(4) "" (viii)K_(3)[CuCL_(4)]"" Na_(4)[Fe(CN)_(5)(NOS)]

Answer»


ANSWER :2(i & V)
7389.

The substrate molecules are held by enzymes with________.

Answer»

COVALENT bond
hydrogen bond
van der Waal's force
all of these

Answer :D
7390.

Which of the following is not true for ligard-metal complex?

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(a) LARGER the ligand, the more stable is the metal-ligand bond
(b) Highly CHARGED ligand forms strong bond
(c) Larger the permanent dipole moment of ligand, the more stable is the bond
(d) Greater the ionization potential of central metal, the stronger is the bond

Solution :The CHARGE does not DECIDE the FORMATION of bond but availability of lone pair decides the formation of coordinate bond.
7391.

Write the formula for optical purity & enantiomeric excess.

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Answer :`%"OPTICAL purity" = ("observed optical rotaion")/("optical rotation of pure enantiomer") XX 100`
`%"Enantiomeric excess" = (|d-l|)/(d+l) xx 100 = ("excess of ONE enantiomer over other")/("entire mixture") xx 100`
7392.

Which of the following does not contain a hydrophobic structure?

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Linseed oil
LANOLIN
Glycogen
RUBBER

Solution :Linseed oil, lanolin and glycogen attract WATER hence CONTAIN a hydrophilic structure but rubber does not attract water and thus does not contain a hydrophibic structure.
7393.

Derive the relationship between elevation in boiling point and molar mass.

Answer»

SOLUTION :`DeltaT_f m = k_f [(w_2/M_2 XX 1000/w_1)]`
7394.

Which of the following reactions is taking place resultingin discolouration of marble of the buildings like Taj Mahal?

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`CaCO_(3)+H_(2)SO_(4)RARR CaSO_(4)+H_(2)O+CO_(2)`
`CaCO_(3)+2HClrarr CaCl_(2)+H_(2)O+CO_(2)`
`CaCO_(3)+H_(2)OrarrCa(OH)_(2)+CO_(2)`
`CaCO_(3)rarrCAO+CO_(2)`

Answer :A
7395.

When 3-Phenylpropene reacts with HBr in the presence of an organic peroxide, the major product formed is:

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2-Bromo-1-phenylpropane<BR>1,2-Dibromo-3-phenylpropane
3-(o-bromophenyl)propane
1-Bromo-3-phenylpropane

Solution :`C_(6)H_(5)-CH_(2)-CH=CH_(2)underset(("peroxide"))overset(HBr)toC_(6)H_(5)-CH_(2)-CH_(2)-CH_(2)-Br.`
7396.

Which of the following statements about benzaldehyde is/are true?

Answer»

REDUCES Tollens' reagent
Undergoes aldol condensation
Undergoes CANNIZZARO reaction
Does not form an ADDITION COMPOUND with SODIUM hydrogen sulphite

Answer :A::C::D
7397.

Which of the following compounds would undergo Aldol condensation, which the Cannizzaro reaction and which neither ? Write the structures of the expected produces of aldol condensation and Cannizzaro reaction : (i) Methanal (ii) 2-Methylpentanal (iii) Benzaldehyde (iv) Benzophenone (v) Cyclohexanone (vi) 1-Phenylpropanone (vii) Phenylacetaldehyde (viii) Butan-1-ol (ix) 2,2 Dimethylbutanal.

Answer»

Solution :(i),(iii) and (ix) will give Cannizzaro reaction DUE to absence of `alpha`-HYDROGE.
(ii),(V),(VI) and (vii) will give aldol condensation due to presence of `alpha`- hydrogen.
(iv) and (viii) will neither undergo Cannizzaro's reaction nor Aldol condensation because benzophenone does not give `alpha`-hydrogen and butanol is alcohol , not ALDEHYDE which cannot undergo aldol condensation.
7398.

What is the difference between a double salt and a coordination compound ? OR Illustrate with example the difference between a double salt and a coordination compound.

Answer»

Solution :`{:("Double SALT","Coordination compound"),("1. Double salts exist only in the solid state and dissociate into their constituent ions in the aqueous solutions.","1. Coordination compounds exist in the solid state as WELL as in the aqueous or non-aqueous solutions."),("2. Double salts LOSE their identity in the solution.","2. They do not lose their identity completely."),("3.The properties of double salts are same as those of their constituents.","3. The properties of coordination compounds are different from their constituents."),("4. Metal ions in the double salts show their normal VALENCE.","4. Mental ions in the coordination compounds show two valences namely primary valence and secondary valence satisfied by anions or neutral molecules called ligands."),("5. For example, in" K_(2)SO_(4)"."K_(2)SO_(4)"."Al_(2)(SO_(4))_(3)"."24H_(2)O". The ions " K^(+)","Al^(3+) and SO_(4)^(2-)" show their properties.","5. For example, in "K_(4)[Fe(CN)_(6)]",ions "K^(+) and [Fe(CN)_(6)]^(4-)"ions show their properties."):}`
7399.

Two oxides of a metal contain 36.4% and 53.4% of oxygen by mass respectively. If the formula of first oxide is M_(2)O, then that of the second is

Answer»

`M_(2)O_(3)`
`MO`
`MO_(2)`
`M_(2)O_(5)`

Solution :In `M_(2)O`, 36.4 PARTS of O combine with M = 63.6
parts, i.e., 2 ATOMS of `M-=63.6` parts
`"or1 ATOM of M = 31.8 parts"`
1 atom of O = 36.4 parts
In 2nd oxide, oxygen present = 53.4 parts
`therefore"M present = 46.6 parts"`
31.8 parts of M = 1 atom of M
`"46.6 parts of M"=(1)/(31.8)xx46.6" parts = 1.5 atoms"`
36.4 parts of O = 1 atom of O
`"53.4 parts of O"=(1)/(36.4)xx53.4=1.5" atoms"`
`therefore" In 2nd oxide M : O" = 1.5:1.5=1:1`
Hence, formula is MO
Alternatively, if m is the atomic mass of M,
For `M_(2)O,(16)/(14+16X)xx100=53.4`
`or (16x)/(14+16x)=0.534 or 16x=.476+8.544x`
or `7.456x=7.476 or x=1`
Hence, the formula is MO.
7400.

Uranium ultimately decays into a stable isotope of

Answer»

Radium
Carbon
LEAD
Neptunium

Solution :Lead is a STABLE ISOTOPE