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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 84401. |
alpha-(D)-(-)fructose and beta-(D)-(-) differs in orientation at |
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Answer» C-1 |
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| 84402. |
alpha - D -(+)- glucose and beta-D-(+)-glucose are |
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Answer» Epimers |
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| 84403. |
alpha - D - (+) glucose and beta - D - (+) glucose are:-Metameres, Anomers, Geometrical isomers, Fuctional group isomers |
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Answer» METAMERES |
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| 84404. |
alpha - D (+) Glucose and beta - D (+) glucoseare ……… . |
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Answer» Epimers |
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| 84405. |
alpha-chloropropionic acid on treatment with alcoholic KOH followed by acidification gives : |
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Answer» `CH_3-CH(OH)-COOH` |
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| 84406. |
alpha, beta and gamma forms of sulphur differ in |
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Answer» OVERAL packing of rings |
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| 84407. |
alpha-amino acids on heating with Ba(OH)_2 gives : |
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Answer» BA SALT of acid |
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| 84408. |
alpha- Amino acids are the building blocks of proteins. About 20 alpha-amino acids have been isolated by the hydrolysis of proteins. All these amino acids except glycine are chiral and have L-configuration. Ten amino acids (valine , leucine, isoleucine , phenylalanine, methionine , trytophan , threonine , lysine , arginine and histidine) which the body cannot synthesize are called essential amino acids. The remaining ten are called non -essential amino acids. All alpha-amino acids exist are zwitterions each of which has a specific isoelectric point. Above isoelectric point , a alpha-amino acid exists as an anion. Two, three or many alpha-amino acids join together to form di-,tri -or polypeptides or proteins respectively. Each polypeptides or protein has a free amino group at one end called the N-terminal end and a free carboxyl group at the other end called the C-terimal end. Sanger's reagent (i.e., 2,4-dinitrofluorobenzene) is used to determine the N-terminal end while C-terimal end is determined by hydrazinolysis. Which of the following reagents is used to determine the C-terminal end in a polypeptide ? |
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Answer» HYDRAZINE |
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| 84409. |
alpha- Amino acids are the building blocks of proteins. About 20 alpha-amino acids have been isolated by the hydrolysis of proteins. All these amino acids except glycine are chiral and have L-configuration. Ten amino acids (valine , leucine, isoleucine , phenylalanine, methionine , trytophan , threonine , lysine , arginine and histidine) which the body cannot synthesize are called essential amino acids. The remaining ten are called non -essential amino acids. All alpha-amino acids exist are zwitterions each of which has a specific isoelectric point. Above isoelectric point , a alpha-amino acid exists as an anion. Two, three or many alpha-amino acids join together to form di-,tri -or polypeptides or proteins respectively. Each polypeptides or protein has a free amino group at one end called the N-terminal end and a free carboxyl group at the other end called the C-terimal end. Sanger's reagent (i.e., 2,4-dinitrofluorobenzene) is used to determine the N-terminal end while C-terimal end is determined by hydrazinolysis. The acid showing salt-like character in aqueous solution is |
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Answer» acetic ACID |
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| 84410. |
alpha- Amino acids are the building blocks of proteins. About 20 alpha-amino acids have been isolated by the hydrolysis of proteins. All these amino acids except glycine are chiral and have L-configuration. Ten amino acids (valine , leucine, isoleucine , phenylalanine, methionine , trytophan , threonine , lysine , arginine and histidine) which the body cannot synthesize are called essential amino acids. The remaining ten are called non -essential amino acids. All alpha-amino acids exist are zwitterions each of which has a specific isoelectric point. Above isoelectric point , a alpha-amino acid exists as an anion. Two, three or many alpha-amino acids join together to form di-,tri -or polypeptides or proteins respectively. Each polypeptides or protein has a free amino group at one end called the N-terminal end and a free carboxyl group at the other end called the C-terimal end. Sanger's reagent (i.e., 2,4-dinitrofluorobenzene) is used to determine the N-terminal end while C-terimal end is determined by hydrazinolysis. An alpha-amino below its isoelectric point exists as |
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Answer» `H_(3)overset(+)N-CHR-COO^(-)` |
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| 84411. |
alpha-amino acid may be prepared by |
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Answer» WILLIAMSON synthesis |
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| 84412. |
Al(OH)_(3) is precipitate if itsproduces (a)____is (b) ____ that K_(sp) |
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Answer» |
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| 84413. |
Al(OH)_(3) darr "(white)" + OH^(-) to [Al(OH)_(4)]^(-) soluble complex White precipitate of Al(OH)_(3) reappears when |
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Answer» a solution of ammonium chloride is added `[Al(OH)_(4)]^(-)+NH_(4)^(+) to Al(OH)_(3) darr +H_(2)O+NH_(3) uarr` |
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| 84414. |
Al(OH)_(3) darr "(white)" + OH^(-) to [Al(OH)_(4)]^(-) soluble complex Identify the correct statement with respect to the gelatinous white precipitate of aluminum hydroxide. |
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Answer» FRESH precipitate dissolves by the ADDITION of strong acid and base |
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| 84415. |
Al(OH)_(3) darr "(white)" + OH^(-) to [Al(OH)_(4)]^(-) soluble complex Fe(OH)_(3) precipitate and Al(OH)_(3) precipitate can be separated by |
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Answer» increasing the `OH^(-)` CONCENTRATION by SODIUM hydroxide. |
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| 84416. |
Alocohols are compounds with general formula R-OH Alcohols are soluble in water. What is the reason? |
| Answer» Solution :ALCOHOLS form HYDROGEN bonds with WATER. | |
| 84417. |
Alocohols are compounds with general formula R-OH How will you convert phenol to benzene? |
Answer» SOLUTION :
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| 84418. |
Alocholic solution of KOH is used for: |
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Answer» Dehalogenation |
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| 84419. |
Almost the following elements the configuration having the highest ionization energy is : |
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Answer» [NE] `3s^2 3p^1` |
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| 84420. |
Almostall …………..areopticallyactiveas theyone or morechiralcarbon. |
| Answer» SOLUTION :CARBOHYDRATES | |
| 84421. |
Almost all amides exist in |
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Answer» SOLID STATE |
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| 84422. |
Almonds are recommended for good health. They not only tend to lower the blood pressure but also contain oils which prevent conorary heart disease responsible for heart attacks. But hemant, a class XII student, told his mother that some of the almonds are bitter in taste. these bitter almonds contain a poison and eating a few of these in one sitting may kill a child. After reading the above passage, answer the following questions: (i) Name the chemical present in bitter almonds an write its hydrolysis products. (ii) How does this chemical act as a poison? (iii) Write the uses of the other hydrolysis products. (iv) What values are displayed by hemant? |
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Answer» SOLUTION :(i) Bitter ALMONDS contain the chemical amygdalin. It, on acid or enzymatic hydrolysis, gives benzaldehyde, glucose and hydrocyanic (HCN) acid. `underset("Amygdalin")(C_(20)H_(27)O_(11)N)+2H_(2)O underset("or Enzyme EMULSION")OVERSET(H^(+))tounderset("Benzaldehyde")(C_(6)H_(5)CHO)+underset("Glucose")(2C_(6)H_(12)O_(6))+HCN` (ii) HCN acts as a poison and kills the person in higher doses. (iii) The other hydrolysis products are glucose and benzaldehyde. Whereas glucose is used as a food but benzaldehyde is used as a flavouring agent in biscuit making and in perfume industry. (iv) Hemant has displayed health conscious values by emphasizing that all bitter things should be taken only after careful examination. |
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| 84423. |
Allylic allohols may be |
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Answer» `1^@`TYPES |
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| 84424. |
Allyl isocyanide contains sigmaand pi bonds respectively as: |
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Answer» `9sigma, 3pi` `overset(H)overset(|)underset(H)underset(|)C=overset(H)overset(|)C-overset(H)overset(|)C-overset(H)overset(|)underset(H)underset(|)C-N-=C""9sigma and 3pi"bonds"` |
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| 84425. |
Allyl isocyanide contains sigma and pi bonds, as |
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Answer» `9 SIGMA` and `3pi` It CONTAINS `9 sigma` and `3pi` bonds. |
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| 84426. |
Allyl isocyanide has |
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Answer» 9 SIGMA BONDS and 4 PI bonds |
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| 84427. |
Allyl isocyanide contains ……..and …….bonds : |
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Answer» `9 SIGMA ` and `3pi` |
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| 84428. |
Allyl iodide can be obtained from allyl chloride. Explain. |
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Answer» Solution :Allyl chloride when heated with SODIUM iodide in PRESENCE of acetone, allyl iodide is formed. `CH_(2)= CH-CH_(2)Cl + NaI UNDERSET("HEAT,"-NaCl)overset("acetone")rarr CH_(2)=CH-CH_(2)I` This is a halogen exchange reaction and is called Finkelstein reaction |
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| 84429. |
Allyl cholride can be distinguished from vinyl chloride by NaOH and silver nitrate test. |
| Answer» Solution :Vinyl chloride does not respond to NAOH and silver nitrate test because of DOUBLE bond character DUE to resonance. This STOPS the release of chloride IONS. | |
| 84430. |
Allyl chloride on dehydrochlorination gives: |
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Answer» Propadiene |
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| 84431. |
Allyl chloride on dehydrochlorination gives |
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Answer» PROPADIENE |
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| 84432. |
Allyl chloride on dehydrochlorination gives ……. |
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Answer» Propadiene |
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| 84433. |
Allyl chloride is hydrolysed more readily than n-propyl chloride. Why ? |
| Answer» Solution :Allyl chloride shows HIGH reactivity as the carbocation formed by HYDROLYSIS is stabilized by resonance while no such stabilization of carbocation EXISTS in case of n-propyl chloride. | |
| 84434. |
Allyl chloride is hydrlysed more readily than n-propyl chloride. Why? |
Answer» Solution :In `S_(N)1` reactions, carbocations are the intermediates. OBVIOUSLY more stable the carbocation, more reactive is the alkyl halide. Since ALLYL chloride upon ionization gives allyl cation which is stabilized by RESONANCE but the carbocation obtained from n-propyl chloride is not, therefore, allyl chloride UNDERGOES hydrolysis MUCH faster than n-propyl chloride. 
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| 84435. |
Allyl bromide and n- propyl bromide can be distinguished by: |
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Answer» `AgNO_3` SOLUTION |
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| 84436. |
Allyl bromide is 3-bromopropene. |
| Answer» | |
| 84437. |
Alloys of which metal are light and strong and used in the manufacture of aeroplanes : |
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Answer» Cr |
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| 84438. |
Alloys of which metal are light and strong and are used in the manufacture of aeroplane parts: |
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Answer» Cr |
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| 84439. |
Alloys are generally prepare to modify the property A) malleability B) toughness C) resistance to corrosion |
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Answer» A and B are CORRECT |
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| 84440. |
Alloyused in making anchors, bolts, chains and wires |
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Answer» PIG iron |
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| 84441. |
Alloy used for making ball mills |
| Answer» Solution :Manganese steel | |
| 84442. |
Alloy Select the correct statement based on the above scheme : |
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Answer» Layer X CONTAINS Zinc & Silver |
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| 84443. |
Alloy of .... Metal are light and strong and so are used in the manufacture of aeroplane parts |
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Answer» Cr |
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| 84444. |
Alloy of Misch metal consists of |
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Answer» 95% of actionoid metal, +5% IRON |
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| 84445. |
Alloy is an example of : |
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Answer» Gel |
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| 84446. |
Alloy formation ability of transition elements is due to |
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Answer» same crystalline structures |
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| 84447. |
Alloy formation gives rise to: |
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Answer» DECREASE in corrosion |
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| 84448. |
Allotropic form of phosphorous which show chemiluminescence |
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Answer» WHITE phosphorous |
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| 84449. |
Allotropy is due to ___________ |
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Answer» DIFFERENCE in CHEMICAL PROPERTIES |
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