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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 84451. |
Allotrope of sulphur which shows paramagnetic behaviour |
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Answer» `S_(8)` - Rhombic |
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| 84452. |
Allergy in the body is caused by the production of- |
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Answer» vitamins |
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| 84453. |
Alldehydes and Ketones react with NH_(2)OH to form aldoximes and Ketoximes respectively. Configuration of these can be determined by Beckmann rearragement as that group migrates which is anti w.r.t -OH Which step is Rate determening step ? |
| Answer» ANSWER :B | |
| 84454. |
Alldehydes and Ketones react with NH_(2)OH to form aldoximes and Ketoximes respectively. Configuration of these can be determined by Beckmann rearragement as that group migrates which is anti w.r.t -OH [X] overset(H_(2)SO_(4))to overset(H_(2)O)to Ph-NH_(2)+CH_(3)-underset(O)underset(||)(C)-OH Identify the configuration of [X] compound |
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Answer»
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| 84455. |
All three amines 1^@,2^@,3^@ react with 1. H_2O , 2.R-X , 3.HCl , 4.(CH_3CO)_2O |
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Answer» 1,2 |
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| 84456. |
All though electron gain enthalpy of fluorine is less negatibe as compared to chlorine, Fluorine is stronger oxidizing agent then Chlorine becose of (i) Low Enthelpy of dissociation of F-F bond |
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Answer» I,II, correct |
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| 84457. |
All three amine 1^(0),2^(0),3^(0)arereactwith |
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Answer» 1,2 |
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| 84458. |
All the three amines (pri-, sec- and tert-) react with |
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Answer» KOH |
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| 84459. |
All the substances become diamagnetic at : |
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Answer» 4 K |
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| 84460. |
All the s-block elements of the periodic table are placed in the group….. |
| Answer» Answer :A | |
| 84461. |
All the oxygen in 0.5434g sample of pure oxide of iron is removed by reduction in a stream of H_(2). The loss in weight is 0.1210g. What is the formula of the oxide of iron ? (At. Mass of Fe = 56) |
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Answer» SOLUTION :Iron oxide = 0.5434 g Oxygen lost as `H_(2)O=0.1212g` `therefore"Iron "=0.5434-0.1210=0.4224g` `therefore""%" of FE"=(0.4224)/(0.5434)xx100=77.73%` `%" of O=100-77.73=22.27%`  Hence, formula of iron oxide = FEO. |
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| 84462. |
All the nuclei from the initial element to the final element constitute a series which is called |
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Answer» g-SERIES |
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| 84463. |
All the naturally occuring processes proceed spontaneously in a direction which leads to |
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Answer» DECREASE of entropy |
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| 84464. |
All the naturally occuring process i.e., spontaneous proceed spontaneously in a direction which leads to: |
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Answer» DECREASE of FREE energy |
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| 84465. |
All the metals form oxides of the type MO except |
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Answer» Copper |
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| 84466. |
All the metals or iron family have a strong magnetic property commonly referred as |
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Answer» Diamagnetism |
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| 84467. |
All the lanthanoids are_______________soft metals and______________rapidly in air. |
| Answer» SOLUTION :SILVERY WHITE, TARNISH | |
| 84468. |
All the interhalogen compoundsexcept one which has AX_(n) type, can be prepared by direct combination of halogens under appropriate conditions. What is the maximum value of n"___________". |
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Answer» |
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| 84469. |
All the following substances react with water. The pair which gives the same gaseous product is: |
| Answer» Answer :C | |
| 84470. |
All the following statements are correct except…………….. |
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Answer» All the DISACCHARIDES are reducing sugars. Sucrose is a non-reducing sugar |
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| 84471. |
All the following complexes show decrease in their weights when placed in a magnetic balance then the group of complexes having tetrahedral geometry is : (P) Ni(CO)_(4)""(Q) K[AgF_(4)] (R) Na_(2)[Zn(CN)_(4)]""(S) K_(2)[PtCl_(4)] (T) [RhCl(PPh_(3))_(3)] |
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Answer» <P>Q, R, T |
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| 84473. |
All the following complexes show a decrease in their weights when placed in a magnetic balance. Then Which of these has square planar geometry? |
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Answer» `Ni(CO)_(4)` Although, `F^(-)` is a WFL, but DUE to high charge on `Ag(+3),C.F.S.E.uparrow` |
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| 84474. |
All the following complex ions are found to be paramagnetic P=[FeF_(6)]^(3-)Q=[CoF_(6)]^(3-)R=[V(H_(2)O)_(6)]^(3+)S=[T:(H_(2)O)_(6)]^(3+) The correct order of their paramagnetic moment (spin only) is |
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Answer» `PgtQgtRgtS` |
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| 84475. |
All the following are the effects of depletion of ozone layer, except |
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Answer» It can cause SKIN cancer |
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| 84476. |
All the energy released from the reaction XtoY,Delta_(r)G^(@)=-193" kJ "mol^(-1) is used for oxidizing M^(+) as M^(+)toM^(3+)+2e^(-),E^(@)=-0.25V. Under standard conditions, the number of moles of M^(+) oxidized when one mole of X is converted to Y is (F=96500" C "mol^(-1)). |
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Answer» `M^(+)toM^(3+)+2E^(-),E^(@)=-0.25V` For this reaction, `DeltaG^(@)=-nFE^(@)` `=-2xx96500xx(-0.25)=48250" J "mol^(-1)` `=48.25" kJ "mol^(-1)` i.e., 48.25 kJ of energy is used for oxidizing 1 mole of `M^(+) ` to `M^(3+)` `therefore` No. of moles of `M^(+)` oxidized by 193 kJ of energy `=(193)/(48.25)=4` |
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| 84477. |
All the energy realesed from the reation X rarr Y, Delta_(r) G^(@) = -193 kJ mol^(-1), is used for oxidizing M^(+) as M^(+) rarr M^(3+) + 2e^(-), E^(@) = -0.25 V. Under standard consistions, the number of moles of M^(+) oxidized when on e mol of X is converted to Y is [F = 96,500 C "mol"^(-1)] |
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Answer» |
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| 84478. |
All the energy released from the reaction XrarrY, Delta_(r)G^(@)=-193 kJ mol^(-1) is used for oxidizing M^(+) as M^(+)rarrM^(3+)+2e^(-), E^(@)=-0.25 V Under standard conditions, the number of moles of M^(+) oxidized when one mole of X is converted to Y is [f=96500 C mol^(-1)] |
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Answer» `DeltaG^(@)=-nFE^(@)" For 1 mole of "m^(+)` `DeltaG^(@)=-2xx96500xx(-0.25)J` `=+48250 J//"mole"=48.25KJ//"mole"` ENERGY released by conversion of 1 mole of `XRARRY DeltaG=-193 KJ` Hence mole of `m^(+)` convert `(193)/(48.25)=4` |
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| 84479. |
All the elements, on the basis of long form of periodic table, can be divided into four blocks, s,p, d and f. the ionization energies, electron affinities, electronegativities, atomic and ionic radii and other physical properties usually shown a regular pattern of change within a group or along period with some irregularities. Q. Which of the following element has the maximum value of electronegativity? |
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Answer» Aluminium |
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| 84480. |
All the elements, on the basis of long form of periodic table, can be divided into four blocks, s,p, d and f. the ionization energies, electron affinities, electronegativities, atomic and ionic radii and other physical properties usually shown a regular pattern of change within a group or along period with some irregularities. Q. Which of the following element has the maximum electron affinity? |
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Answer» Nitrogen |
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| 84481. |
All the elements, on the basis of long form of periodic table, can be divided into four blocks, s,p, d and f. the ionization energies, electron affinities, electronegativities, atomic and ionic radii and other physical properties usually shown a regular pattern of change within a group or along period with some irregularities. Q. On moving from Li to F in the second period, there would be a decrease in : |
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Answer» non-metallic property |
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| 84482. |
All the elements of the oxygen family are: |
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Answer» NON- metal |
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| 84483. |
All the elements in a group (family) have a common valency. For example , all the elements of the carbon family (carbon, silicon , germanium , tin and lead) have common valency four . However , some of these elements can also have valency two . Which of the following can have valency two ? |
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Answer» Silicon , germanium and tin |
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| 84484. |
All the elements belonging to second period are: |
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Answer» NORMAL elements |
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| 84485. |
All the element from nitrogen family have two paired s-electron and three unpaired p-electron in their valence shell thus exhibit three covalence, by sharing of three electron pair to attain stable noble gas configuration except nitrogen all have got vacant d-orbital. All the element of this group exhibit +3 oxidation state in hydride. The tendency to show-3 ionic nature is not possible due to high energy consideration. However, nitrogen being smallest and most electronegative and thus forms N^(3) ion in nitrides such as Mg_(3)N_(2). Ca_(3)N_(2) etc. Rest of all shows -3 oxidation state in covalent compounds. The +3 oxidation state are covalent and ionic both. The +5 oxidation states are covalent as they can not from M^(+5) ions due to high energy involve there in. The tendency to show M^(+3) ionic state however increase down the group due to inert pair effect. The most unstable hydride among the following is: |
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Answer» `NH_(3)` |
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| 84486. |
All the element from nitrogen family have two paired s-electron and three unpaired p-electron in their valence shell thus exhibit three covalence, by sharing of three electron pair to attain stable noble gas configuration except nitrogen all have got vacant d-orbital. All the element of this group exhibit +3 oxidation state in hydride. The tendency to show-3 ionic nature is not possible due to high energy consideration. However, nitrogen being smallest and most electronegative and thus forms N^(3) ion in nitrides such as Mg_(3)N_(2). Ca_(3)N_(2) etc. Rest of all shows -3 oxidation state in covalent compounds. The +3 oxidation state are covalent and ionic both. The +5 oxidation states are covalent as they can not from M^(+5) ions due to high energy involve there in. The tendency to show M^(+3) ionic state however increase down the group due to inert pair effect. Pick up incorrect statement: |
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Answer» `PH_(4)^(+)` ion tetrahedral LIKE `NH_(4)^(+)` and is obtained when `PH_(3)` is bonded to proton. |
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| 84487. |
All the element from nitrogen family have two paired s-electron and three unpaired p-electron in their valence shell thus exhibit three covalence, by sharing of three electron pair to attain stable noble gas configuration except nitrogen all have got vacant d-orbital. All the element of this group exhibit +3 oxidation state in hydride. The tendency to show-3 ionic nature is not possible due to high energy consideration. However, nitrogen being smallest and most electronegative and thus forms N^(3) ion in nitrides such as Mg_(3)N_(2). Ca_(3)N_(2) etc. Rest of all shows -3 oxidation state in covalent compounds. The +3 oxidation state are covalent and ionic both. The +5 oxidation states are covalent as they can not from M^(+5) ions due to high energy involve there in. The tendency to show M^(+3) ionic state however increase down the group due to inert pair effect. Collectively the element of group 15 are called |
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Answer» Pnicopens |
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| 84488. |
All the element from nitrogen family have two paired s-electron and three unpaired p-electron in their valence shell thus exhibit three covalence, by sharing of three electron pair to attain stable noble gas configuration except nitrogen all have got vacant d-orbital. All the element of this group exhibit +3 oxidation state in hydride. The tendency to show-3 ionic nature is not possible due to high energy consideration. However, nitrogen being smallest and most electronegative and thus forms N^(3) ion in nitrides such as Mg_(3)N_(2). Ca_(3)N_(2) etc. Rest of all shows -3 oxidation state in covalent compounds. The +3 oxidation state are covalent and ionic both. The +5 oxidation states are covalent as they can not from M^(+5) ions due to high energy involve there in. The tendency to show M^(+3) ionic state however increase down the group due to inert pair effect. Pick out the incorrect statement: |
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Answer» Red phosphorus cansist of complex CHAIN structure is BLACK phosphorus has layer structure. |
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| 84489. |
All the compounds listed in column I react with water. Match the result of the respective reactions with the appropriate options listed in column II. |
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Answer» |
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| 84490. |
All the compounds listed in Column I react with water. Match the result of the respective reactions with the appropriate options listed in column II |
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Answer» |
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| 84491. |
All the complexes of Pt(+II)" and "Au(+III) with strong field as well as with weak field ligands are square planar. Statement-2: The crystal field splitting Delta_(0) is larger for second and third row transition elements, and for more highly charged species. This larger value of Delta_(0) energetically favours the pairing of electron for square planar geometry. |
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Answer» Statement-1 is TRUE, Statement-2 is True , Statement-2 is a CORRECT EXPLANATION for Statement-1. |
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| 84492. |
All the boron trihalides exceptBI_(3) may be prepared by direction between the elements. Boron trihalides consist of trigonal-planar BX_(3) molecules. Unlike the halides of the other elements in the group they are monomeric in the gas, liquid and solid states, BF_(3) and BCl_(3) are gases, BBr_(3) is a volatile liquid and BI_(3) is a solid. Boron trihalides are Lewis acids because they form simple Lewis complexes with suitable bases, as in the reaction: BF_(3)(g)+NH_(3)(g)toF_(3)B-NH_(3)(s) However, boron chlorides, bromides and iodides are susceptible (sensitive) to protolysis by mild proton sources such as water, alcohols and even amines, for example BCl_(3) undergoes rapid hydrolysis: BCl_(3)(g)+3H_(2)O(l)toB(OH)_(3)(aq)+3HCl (aq)It is supposed that the first step in the above reaction is the formation of the complex Cl_(3)B larr OH_(2) which then eliminates HCl and reacts with water. Which of the following reactions is incorrect ? |
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Answer» `BF_(3)(g) +F^(-)(aq)rarr [BF_(4)]^(-)(aq)` |
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| 84493. |
All the boron trihalides exceptBI_(3) may be prepared by direction between the elements. Boron trihalides consist of trigonal-planar BX_(3) molecules. Unlike the halides of the other elements in the group they are monomeric in the gas, liquid and solid states, BF_(3) and BCl_(3) are gases, BBr_(3) is a volatile liquid and BI_(3) is a solid. Boron trihalides are Lewis acids because they form simple Lewis complexes with suitable bases, as in the reaction: BF_(3)(g)+NH_(3)(g)toF_(3)B-NH_(3)(s) However, boron chlorides, bromides and iodides are susceptible (sensitive) to protolysis by mild proton sources such as water, alcohols and even amines, for example BCl_(3) undergoes rapid hydrolysis: BCl_(3)(g)+3H_(2)O(l)toB(OH)_(3)(aq)+3HCl (aq)It is supposed that the first step in the above reaction is the formation of the complex Cl_(3)B larr OH_(2) which then eliminates HCl and reacts with water. Which is correct about the hydrolysis of BX_(3)? |
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Answer» All `BX_(3)` UNDERGO hydrolysis to produce `B(OH)_(3) (aq)` and `HX(aq)`. |
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| 84494. |
All the boron trihalides exceptBI_(3) may be prepared by direction between the elements. Boron trihalides consist of trigonal-planar BX_(3) molecules. Unlike the halides of the other elements in the group they are monomeric in the gas, liquid and solid states, BF_(3) and BCl_(3) are gases, BBr_(3) is a volatile liquid and BI_(3) is a solid. Boron trihalides are Lewis acids because they form simple Lewis complexes with suitable bases, as in the reaction: BF_(3)(g)+NH_(3)(g)toF_(3)B-NH_(3)(s) However, boron chlorides, bromides and iodides are susceptible (sensitive) to protolysis by mild proton sources such as water, alcohols and even amines, for example BCl_(3) undergoes rapid hydrolysis: BCl_(3)(g)+3H_(2)O(l)toB(OH)_(3)(aq)+3HCl (aq)It is supposed that the first step in the above reaction is the formation of the complex Cl_(3)B larr OH_(2) which then eliminates HCl and reacts with water. Which of the following is the correct prediction about observed B-X bond length, in BX_(3) molecules? |
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Answer» `B-F` bonf length in `BF_(3)` is FOUND to be less than theoretical value because the electronegativity values of `B(2.04)` and `F(4.0)` suggest the bond to be ionic and hence the attraction between oppositely charged ions MUST decrease the bond length |
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| 84495. |
All the actinoids are ................ and most of them have .......... half lives. |
| Answer» SOLUTION :RADIOACTIVE, SHORT | |
| 84496. |
All terpenes have carbon skeletons made up of: |
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Answer» Isoprenes UNITS |
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| 84497. |
The correct order of solubility of the sulphates of alkaline earth metals in water is |
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Answer» `Mg GT CA gt BA gt Be gt SR` |
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| 84498. |
All spinel structures do not have |
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Answer» CCP array of anions |
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| 84499. |
All sixteen possible aldohexose have been isolated or synthesised. Only three occurin nature thereare : |
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Answer» D-glucose |
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| 84500. |
All reactions which have chemical disintegration |
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Answer» Is REVERSIBLE |
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