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801.

Which one of the following is formed when ethane-1, 2- diol is treated with Conc. H_2SO_4 ?

Answer»

1,4-dioxane
Ethanal
ETHANOIC ACID
ETHENE

SOLUTION : 1,4-dioxane
Discussion
802.

When a solution of XeO_(3) is treated with metal fluoride, the product obtained is……

Answer»

`M^(+)[XeO_(2)F_(2)]^(-)`
`M+[XeO_(3)F]^(-)`
`M+[XeO_(6)F]^(-)`
None of these

Solution :When a solution of `XeO_(3)` is TREATED with `KF` or `CsF`, an oxofluoro SALT, `M^(+)[XeO_(3)F]^(-)` is obtained.
Discussion
803.

Thermdynamic feasibility of the reaction alone cannot decide the rate of the reaction.Explain with the help of one example.

Answer»

Solution :THERMODYNAMIC feasibility (-Ve `DeltaG`) cannot alone decide the rate of reaction because the reaction may be FEASIBLE but its rate my be very very slow because of very high activation energy.
For examples conversion of daimond to graphite is highly feasible but this reaction is very slow because it has high activation energy.
Discussion
804.

What is the difference between the electronic configurations of lanthanoids and actinoids?

Answer»

Solution :Filling of 4F ORBITALS TAKES place in LANTHANOIDS while it is the filling of 5f orbitals in actinoids.
Discussion
805.

The transition element with least atomic number is:

Answer»

Zr
Sc
Os
Pt

Answer :B
Discussion
806.

Which of the following is an nuclear isomer of hydrogen ?

Answer»

Ortho - H
Para-H
both (1) and (2)
None of these

Solution :Ortho HYDROGEN & parahydrogen are NUCLEAR isomer.
Discussion
807.

What do you mean by activity and selectivity of catalysis?

Answer»

Solution :Activity : Activity of a catalyst refer to the chemisorption of reactants reasonably strong. It has ABILITY to increase chemical reaction.
For EXAMPLE : TRANSITION metals show catalytic activity. (Maximum activity group 7 - 9 metal).
Selectivity : Selectivity of a cataysts is its ability to speed up a reaction to YIELD a particular PRODUCT.
For example : `(i) CO + H_2` Combine to form `CH_4` when `Ni ` is the catalyst and methanol when `Cr_2O_3` is catalyst.
`CO + 3H_2 overset("Ni")(rarr) underset("Methane")(CH_4)+H_2O`
`CO + 2H_2 underset(Cr_2O_3)overset(Cu//ZnO)(rarr)underset("Methyl alcohol")(CH_3OH)`.
Discussion
808.

What happens when ammonium chloride is heated with quick lime?

Answer»

SOLUTION :AMMONIA is EVOLVED
Discussion
809.

Which oxide of nitrogen is coloured gas?

Answer»

`N_2O`
`NO`
`N_2O_5`
`NO_2`

ANSWER :D
Discussion
810.

The salt used for performing bead test in qualitative inorganic analysis is

Answer»

`K_(2)SO_(4).Al_(2)SO_(4).24H_(2)O`
`FeSO_(4).(NH_(4))_(2)SO_(4).6H_(2)O`
`Na(NH_(4))HPO_(4).4H_(2)O`
`CaSO_(4).2H_(2)O`

Solution :Microcosmic salt `Na(NH_(4))HPO_(4).4H_(2)O` besidesborax is used in bead test.
Discussion
811.

Which statement about fast and oils is correct :

Answer»

They may be EDIBLE well as inedible :VEGETABLE oils are different than essential oils
Soyabeen oil, CORN oil, olive oil, ETC. are edible oil
All

Answer :D
Discussion
812.

Water acts as excellent solvent due to :

Answer»

HYDROGEN bonding
Neutralnature
High DIELECTRIC constant
None of these

Answer :C
Discussion
813.

Which of the following statements are correct? (i) Chromium has the highest melting point among the series 1 metals. (ii) Nwnber of unpaired electrons is greater in Cr than other elements of series 1. (iii) In any row the melting point of transition metal increases as the atomic nwnber increases.

Answer»

(i) and (iii)
(i) and (II)
(ii) and (iii)
(i), (ii) and (iii)

Solution :In any ROW the melting points of TRANSITION metals RISE to a maximum at `d^(5)` except for anomalous values of Mn and Tc and falls regularly as the atomic number increases.
Discussion
814.

Which of the following is NOT a requirement of an ideal drug?

Answer»

Action at DESIRED site.
Efficient and SAFE action.
Minimum SIDE effects.
Oral consumption.

Answer :D
Discussion
815.

Which of the following is the correct set of four quantum numbers for each of the electrons in the 3d sub shell when it is fully occupied?

Answer»

`n=3,L=2,m=0,l=1,2,-2` and `s=+11//2,+-1//2,+-1//2,+-1//2` and `+-1//2`
`n=3,l=1,m=0,l--1,2,-2` and `s=+-1//2,+-1//2,+-1//2,+-1//2` and `+-1//2`
`n=4,l=2,m=0,l=0,1,-12,-2` and `s=+-1//2,+-1//2,+-1//2,+-1//2` and `+-1//2`

ANSWER :A
Discussion
816.

Which of the following solutions is acting as disinfectant?

Answer»

Aqueous SOLUTION of `1 %` phenol 
Aqueous solution of `0.2 %` phenol
Aqueous solution of `2-3 %` iodine
Dilute aqueous solution of BORIC acid 

Solution :Aqueous solution of `1%` phenol
Discussion
817.

The zig-zag movement of the collodal particles in a collodidal sol is called…………

Answer»

SOLUTION :Brownian MOVEMENT
Discussion
818.

Which of the following reaction represents enthalpy of formation of AgCl ?

Answer»

`AG^(+)(AQ) + CL^(-1)(aq) rarr AGCL(s)`
`AgCl(s) rarr Ag(s) + (1)/(2) Cl_(2)(g)`
`Ag(s) + AuCl(s) rarr AgCl(s) + AU(s)`
`Ag(s) + (1)/(2) Cl_(2)(g) rarr AgCl(s)`

Answer :D
Discussion
819.

The solubility product of a sparingly soluble metal hydroxide, M(OH)_(2) at 298 K is 5xx10^(-16)mol^(3)dm^(-9). The ph value of its aqueous and saturated solution is :

Answer»

5
9
`11.5`
`2.5`

SOLUTION :`M(OH)_(2)hArr underset(s)(M^(2+))+underset(2s)(2OH^(-))`
`K_(sp)=(s)(2s)^(2)=4s^(3)=5XX10^(-16)`
`s^(3)=1.25xx10^(-16)=125xx10^(-18)`
`s=(125xx10^(-18))^((1)/(3))=5xx10^(-6)`
`[OH^(-)]=2s=2xx5xx10^(-6)=10^(-5)`
`pOH=-log[OH^(-)]=-LOG10^(-5)=5`
`pH=14-pOH=14-5=9`.
Discussion
820.

Which of the following is an unsymmetrical ether?

Answer»

`CH_3-O-C_3H_7`
`CH_3-O-CH_3`
`C_2H_5-O-C_2H_5`
All of these

Answer :A
Discussion
821.

Vulcanisation makes rubber ........ .

Answer»

more ELASTIC
SOLUBLE in INORGANIC solvent
crystalline
more stiff

ANSWER :A::D
Discussion
822.

Which of the following pairs of elements cannot form an alloy?

Answer»

Zn, Cu
Fe, Hg
Fe, C
Hg, Na.

Solution :MERCURY has the PROPERTY of dissolving nearly all metals, forming liquid or solid solutions called amalgams. It amalgamates well with GOLD, silver and tin, but does not dissolve iron or platinum. Presence of these may result in sickening or flouring of the mercury
Discussion
823.

Which of the following pairs does not have similar geometries ?

Answer»

1. `CH_(4), C Cl_(4)`
2. `BF_(3), NH_(3)`
3. `H_(2)O, H_(2)S`
`4. PCl_(5), SbCl_(5)`

Answer :B
Discussion
824.

The SRP values of three elements A , B and C are +2.37V, -1.85V and -1.36V respectively. So the order of their reducing power will be

Answer»

`AGTBGTC`
`CgtBgtA`
`AgtCgtB`
`BgtCgtA`

Solution :Smallest value of `E_("RED")^(0)` of Zn - strongest reducing agent.
Discussion
825.

To observe an elevation of boiling point of 0.05 ""^(@)C , the amount of solute (Mol. Wt = 100) to be added to 100 g of water (K_b = 0.5) is

Answer»

2g
0.5 g
1 g
0.75 g

Solution :`DeltaT_(b) = 0.05 ""^(@)C, K_(b) =0.5, W_(A) =100g`
`M_(B) = 100 , W_(B) = ?`
`therefore DELTA T_(b) = K_(b) xx (W_B)/(M_B) xx (1000)/(W_A) . rArr 0.05 =0.5 xx (W_B)/(100) xx (1000)/(100)`
`rArr 5 xx 10^(-2) = 5 xx 10^(-1) xx (W_B)/(10) rArr W_(B) = 1 g`
Discussion
826.

White phosphorus reacts with chlorine and the product hydrolysis in the presence of water. Calculate the mass of HCI obtained by the hydrolysis of the product formed by the reaction of 62 g of white phosphorus with chlorine in the presence of water.

Answer»

Solution :The reactions MAY be WRITTEN as under :

124 g `P_4` produces = 438 g HCl
62 g `P_4` produces = `(438)/(124) xx62` g HCl= 219 HCl
Discussion
827.

The structure of TICI is similar to CsCl. What would be the radius ratio in TICI.

Answer»

0.155-0.225
0.225-0.414
0.414-0.732
0.732-1.000

Solution :RADIUS RATIO in TICl is 0.732-1.000 and co-ordination number is 8 and ARRANGEMENT is body CENTRED cubic.
Discussion
828.

Which element is the best oxidising agent?

Answer»

SOLUTION :FLUORINE
Discussion
829.

Which one of the following is a trihydrie alcohol?

Answer»

GLYCOL
ETHANOL
GLYCEROL
SORBITOL

SOLUTION :Glycerol
Discussion
830.

There are how many Bravais lattices?

Answer»

10
11
12
14

Answer :D
Discussion
831.

Write short notes on (a) Amalgamation (b) Hydrometallurgy (c) Self reduction (d) Electrolytic reduction

Answer»

Solution :(a) This process is used for the extraction of noble metals like gold and silver from the native ores. The finely crushed ore is brought into contact with mercury which combines with the metal forming its amalgam. The metal is then recovered by distilling the amalgam.
(b) Hydrometallurgy is the process of bringing the metal into solution by the action of suitable chemical reagents (e.g. sodium cyanide solution or chlorine in presence of water etc.) followed by recovery of the metal by the use of a proper precipitating agent which is a more electropositive metal. For example, poor ores of silver are suspended in a dilute solution of sodium cyanide and air is blown through it when the silver present goes into solution as the argentocyanide complex.From this solution the metal is precipitated by adding zinc turnings.
`{:(4Ag + 8 NaCN + O_(2)("air") + 2H_(2)O rarr 4 Na [Ag(CN)_(2)] + 4 NaOH),(or AgCl + 2NaCN rarr Na[Ag(CN)_(2)]+NaCl),(2Na [Ag(CN)_(2)]+Zn rarr Na_(2) [Zn(CN)_(4)] + 2Ag darr):}`
(C) In some cases no extra reducing agent is required. A part of the sulphide ore is changed to oxide or sulphate which then reacts with the remaining part to give the metal and sulphur dioxide. Copper and lead are obtained by this method.
`{:(2Cu_(2)S + 3O_(2) rarr 2Cu_(2)O + 2SO_(2)),(Cu_(2)S + 2Cu_(2)O rarr 6Cu+SO_(2)),(2PbS + 3O_(2) rarr 2PbO + 2SO_(2)),(PbS + 2O_(2) rarr PbSO_(4)),(PbSO_(4) + PbS rarr 2Pb + 2SO_(2)):}`
(d) The carbon reduction methods are not applicable for the highly electropositive and chemically active metals such as alkali metals, alkaline earth metals, aluminium etc. The OXIDES of these metals are very stable and have to be heated very strongly with carbon in order to reduce them to metals. But at high temperatures these metals combine with carbon to form CARBIDES, thus creating problem. Hence, these metals are extracted by the electrolytic reduction of their fused halides. The metal is liberated at the cathode. Aluminium is however obtained by the electrolytic reduction of alumina `(Al_(2) O_(3))` dissolved in molten cryolite `(Na_(3) AIF_(6))`.
Discussion
832.

What is the statement of Ostwaid's dilution law.

Answer»

Solution :When dilution INCREASES the degree of association of WEAK electrolyte also increases.
`K_a=(a^2c)/(1-a)`
The STATEMENT is known as Ostwaid.s dilution LAW.
Discussion
833.

What is the covalence of nitrogen in N_2O_5?

Answer»

SOLUTION :COVALENCE of N in `N_2O_5` is FOUR.
Discussion
834.

Waxes are esters of

Answer»

GLYCEROL and FATTY acid
LONG CHAIN ALCOHOLS and long chain fatty acids
glycerol
long chain alcohols

Solution :Waxes are esters of long chain saturated and unsaturated fatty acids with long chain monohydroxy alcohols.
Discussion
835.

The solution used to preserve biological specimens is :

Answer»

TOLLEN's Reagent
Formalin
Vanillin
Acetone.

Answer :B
Discussion
836.

Which of the following is best suited to dry crystals of ammine salts (complexes in which NH_3 is a ligand e.g., [Ni(NH_3)_6]Br_2)

Answer»

Anhy. `CaCl_2`
Anhy. CaO
A mixture of CaO and `NH_4Cl`
None of these

Solution :A mixture of CaO and `NH_4Cl` is used to dry CRYSTALS of COMPLEXES containing `NH_3` as ligands. The water liberated by moist crystals is absorbed by CaO. This moisture helps in the chemical reaction between CaO and `NH_4Cl` to CREATE an atmosphere of `NH_3`which prevents the decomposition of highly UNSTABLE complexes i.e., AMMINE salts.
Discussion
837.

What is 'A' in the following reaction ?

Answer»




Solution :
The reaction TAKES PLACE as PER Markovnikov.s RULE.
Discussion
838.

Write the mechanism of hydration of ethene to yield ethanol.

Answer»

Solution :Direct addition of `H_(2)O` to ethene in PRESENCE of an acid does not occur. Indirectly, ethene is first passed through conc. `H_(2)SO_(4)`, when ETHYL hydrogen sulphate is formed.
`H_(2)SO_(4)rarrH^(+)+""^(-)OSO_(2)OH`

Ethyl hydrogen sulphate on BOILING with water undergoes hydrolysis to form ETHANOL.
Discussion
839.

Write the reactionsinvolved in the following: Gabriel phthalimide synthesis

Answer»

SOLUTION :
Discussion
840.

The wave number of the series limiting line for the Lyman series for hydrogen atom is (R =109678cm^(-1))

Answer»

`82259cm^(-1)`
`109678cm^(-1)`
`1.2157xx10^(5)CM`
`9.1176xx10^(-6)cm`

SOLUTION :According to Rydberg equation
`barv=109678 1/(1^(2))-1/(oo^(2))=109678cm^(-1)`
The limiting line corresponding to `n_(2)=oo`
Discussion
841.

Which hydrogen -like specieswill have the same r adius as that of Bohr orbitof hydrogen atom ?

Answer»

`n=2,Li^(2+)`
`n=2,Be^(3+)`
`n=2,He^(+)`
`n=3,Li^(2+)`

SOLUTION :`r=(n^(2)H^(2))/(4pi^(2)mze^(2))`
Discussion
842.

Which of the following pair of acidic radical can be distinguished by using dil H_(2)SO_(4) ? (I) C_(2)O_(4)^(2-) " and" NO_(3)^(-) "" (II) NO_(3)^(-) " and" NO_(2)^(-) (III) Cl^(-) " and" Br^(-) "" (IV) HCO_(3)^(-) " and" CO_(3)^(2-)

Answer»

I and II
II only
II and IV
III and IV

Solution :
Hence, DISTINCITION is possible.
(III) Both `Cl^(-) " and" BL^(-)` have no REACTION with dil. `H_(2)SO_(4)`.
(IV) Both `HCO_(3)^(-) " and" CO_(3)^(2-)` produce `CO_(2) uarr` which EVOLVES with efferverscences.
Discussion
843.

What mass of H_(2)SO_(4) could be produced (in kg ) in the process given below if 5.52 kg of FeS_(2)is used FeS_(2)(s) + O_(2)(g) to Fe_(2)O_(3)(s)+SO_(2)(g) SO_(2) (g) + O_(2)(g) to SO_(3)(g) SO_(3)(g) + H_(2)SO_(4) (I) to H_(2)s_(2)O_(7)(I) H_(2)S_(2)O_(7)(I) + H_(2)O(l) to H_(2)SO_(4)(sq) (At. wt. of Fe = 56, S = 32)

Answer»


SOLUTION :N/A
Discussion
844.

Vapour pressure of solution containing 2 mol of liquid A (P_A^@ = 80 torr) and 3 mol of liquid B (P_B^@= 100 torr) is 87 torr. We canconclude that

Answer»

there is negative deviation from RAOULT's law
boiling POINT is higher than that EXPECTED for ideal solution
molecular attractions between unlike molecules arestronger than those between like molecules
all of these statements are correct

Solution :For ideal solution vapour pressure of solution `=P_A^@x_A + P_B^@x_B`
`80xx2/5 + 100 xx3/5 = 92` torr
Since observed vapour pressure of solution >ideal vapour pressure, the solution shows negative deviation.
Discussion
845.

Write the monomers of the following sugars and explain how they are linked. (i) Sucrose (ii) Maltose (iii) Lactose

Answer»

Solution :(i) Sucrose :
D - glucose and D - fructose LINKED by `alpha` - 1, 2 glycosidic bond.
(ii) Maltose :
TWO MOLECULES of `alpha` - D - glucose linked by `alpha` - 1, 4 glycosidic bond.
(iii) Lactose :
`beta` - D - glucose and `beta` -D galactose linked by `beta` - 1, 4 glycosidic bond.
Discussion
846.

Which of the following elements show fractional oxidation state in any of their compounds?

Answer»

<P>P
CI
I
N

Solution :I in`KI_3`and N`N_3H`showsfractionaloxidationstate
Discussion
847.

Whether a negative value of pH is possible

Answer»

Yes
No
Some times
None of these

Answer :B
Discussion
848.

underset((1atm25^@C))(Pt:H_2)//underset((0.01M))(HCOOK)//// underset((0.01 M))((NH_4 Cl)) // underset((1 atm ,25^@ C))(H_2,Pt )K_b value ofHCOO^(-) and NH_3are10^(-6) and 10^(-8) respectively. The potential of the given cell is

Answer»

`-0.0591 V `
`0.3546 V `
` 0.2364 V `
`-0.3564 V `

SOLUTION :`[HCOOK] = 10^(-2) implies (H^(oplus))_(a) = sqrt((K_w XX K_a)/(C)) , [H^(oplus)]_a = sqrt((10^(-14) xx 10^(-8))/(10^(-2))) = ((10^(-7) xx 10^(-4))/(10^(-1)))`
`(H^(oplus))_a = 10^(-11 + 1) = 10^(-10) and (NH_4Cl) = 10^(-2)`
` (H^(oplus))_(C) = sqrt((K_w xx C )/(K_b)) = sqrt((10^(-14) xx 10^(-2))/(10^(-8))) , (H^(oplus))_(C) = (10^(-7) xx 10^(-1))/(10^(-4)) = 10^(-8 + 4) = 10^(-4) and E = (+0.0591)/(1) log""([H^(oplus)]_c)/([H^(oplus)]_a) = (+ 0.0591)/(1) log ""((10^(-4))/(10^(-10))) = 0.0591 xx 6 = 0.3546V `
Discussion
849.

Which of the following is the triad of a homologous series -

Answer»

`CH_(3)NH_(2), (CH_(3))_(2)NH, (CH_(3))_(3)N`
`C_(2)H_(5)OH, (CH_(3))_(2)CHOH`,
`H_(3)C -UNDERSET(CH_(3))underset(|)OVERSET(CH)overset(|)(C)-O-CH_(3)`
`CH_(3)-CH_(2)-underset(O)underset(||)(C)-H`,
`H_(3)C-underset(O)underset(||)(C)-CH_(2)-CH_(3)`,
`H_(3)C-underset(O)underset(||)-CH_(2)-CH_(2)-CH_(3)`
`CH_(2) = CH_(2), CH_(3) - CH = CH_(2)`,
`C_(2)H_(5) -CH = CH_(2)`

Answer :D
Discussion
850.

Which one of the following formula represents Ostwald's dilution law for a binary whose degree of dissociation is alpha and concentration C.

Answer»

`K=((1-ALPHA)C)/(alpha)`
`K=(alpha^2 C)/( 1-a)`
`K=((1-a)C)/(alpha^2)`
`K=(alpha^2 C)/((1-alpha)C)`

ANSWER :B
Discussion