This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 85251. |
a.Convert the following a. b. . |
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Answer» SOLUTION :a.` (##KSV_CHM_ORG_P2_C15_S01_020_S01.png" WIDTH="80%"> B. ` (##KSV_CHM_ORG_P2_C15_S01_020_S02.png" width="80%">. |
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| 85252. |
Aland Ga have the same covalent radii because of: |
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Answer» POOR SHIELDING POWER of d-electrons of GA atoms |
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| 85253. |
A colourless liquid P formed a crystalline product with 2,4 dinitrophenyl hydrazine but did notreduce ammoniacal silver nitrate solutionthe possibleformula of P is |
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Answer» `CH_(3)CH_(2)CH_(2)CHO` |
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| 85254. |
Al and Ga are trivalent in their compounds but monovalent compounds are the most stable down the 13th group. Why? |
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Answer» Solution :Down the group `(13th)`, the STABILITY of `+3` state decreases and that of `+1` state INCREASES due to the prominent "inert PAIR" effect. `Al^(3+)gtGa^(3+)gtIn^(3+)gtTI^(3+)` Most stable`to` LEAST stable `Tl^(+) gt In^(+) gt Ga^(+) gt Al^(+)` |
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| 85255. |
Al^(+3). Fe^(+3) & Cr^(+3) are grouped together for qualitative analysis because their |
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Answer» CARBONATES are INSOLUBLE in `NH_(3)` |
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| 85256. |
(A)Colloidal solutionsare stable but colloidal particles do not settle down(R ) Brownianmovement counters the force of gravity actively on colloidal particles |
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Answer» Both (A) and (R ) are TRUE and (R ) is the correct EXPLANATION of (A) |
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| 85257. |
Here, the product X and Y are |
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Answer» `{:(X,, Y) ,( n-"propyl ALCOHOL ",,n- "propyl alcohol "):}` |
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| 85258. |
Acolloidal solution in which a solid is dispersed in a liquid is called: |
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Answer» Gel |
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| 85259. |
Total number of hybrid orbitals involved in bonding in a molecule of 'C'is |
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Answer» 12 |
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| 85260. |
A:CN^(-) is an acid ligand. R: CN^(-) accepts electron pair also. |
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Answer» If both Assertion & REASON are TRUE and the reason is the correct EXPLANATION of the assertion, then MARK (1) |
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| 85261. |
aK_(2)Cr_(2)O_(7)+bKCl+cH_(2)SO_(4)toxCrO_(2)Cl_(2)+yKHSO_(4)+zH_(2)OThe above equation balances when |
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Answer» a = 2, B = 4, c = 6 and X = 2, y = 6, z = 3 |
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| 85262. |
aK_(2)Cr_(2)O_(7) + bKCl+cH_(2)SO_(4)toxCrO_(2)Cl_(2)+yKHSO_(4)+zH_(2) The above equation balances when |
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Answer» `a=2, b=4, c=6` and `x=2, y=6, z=3` c.f. `aK_(2)Cr_(2)O_(7)+bKCl+cH_(2)SO_(4)toCrO_(2)Cl_(2)+yKHSO_(4)+zH_(2)O` |
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| 85263. |
Aclosed vessel contains equal number of nitrogen and oxygen molecules at a pressure of P mm. If nitrogen is removed from the system, then the pressure will be : |
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Answer» P |
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| 85264. |
aK_2Cr_2 O_7+bKCI+cH_2 SO_4to xCrO_2CI_2+ yKHSO_4+zH_2 O the aboveequationbalanceswhen |
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Answer» a=2, b=4,c=6and X=2, y=6 , z=3
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| 85265. |
Acififledsolutionof chromicacidontreatment withH_(2) O_(2)givebluecolourwhichis due to "______" |
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Answer» `CrO_(3)+ H_(2) O + O_(2)` |
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| 85266. |
Airborne bacteria and viruses form a colloidal system of __ in __. The blanks can be correctly filled by: |
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Answer» SOLID, Gas |
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| 85267. |
Acids nature of Zn (OH)_(2) is shown during its reaction with |
| Answer» Answer :C | |
| 85268. |
Aired-Rochow's electronagativity upon |
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Answer» ELECTRON affinity |
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| 85269. |
Acids having higher B.P. than alcohols because of |
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Answer» intra MOLECULAR HB |
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| 85270. |
Air was drawn through a solution containing 38 g of solute in 100 g of water, andthen through water. The loss of weight of water was 0.0551 g and the total weight of water absorbed in sulphuric acid tube was 2.2117 g. Find the molecular weight of the dissolved substance |
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Answer» Solution :Raoult.s LAW:LOWERING of VP / VP of SOLVENT= MOLE fraction of solute `(0.0551)/(2.2117) = (38//M)/ |
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| 85271. |
Acids have higher boiling points due to |
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Answer» PLEASANT smell |
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| 85272. |
Airpollution is not caused by: |
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Answer» POLLEN grains |
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| 85273. |
Air pollution from the leakage of methyl isocyanate gas from the Union carbide factory in Bhopal caused a major tragedy on: |
| Answer» Answer :A | |
| 85274. |
Acids and esters are |
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Answer» CHAIN isomers |
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| 85275. |
Air pollution effects are usually found on |
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Answer» Leaves |
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| 85276. |
Acidosis is diagnosed when blood pH: |
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Answer» FALLS below 7.35 |
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| 85277. |
Acidity of which of the following compound is quite high compared to the rest of the given compounds- |
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Answer»
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| 85278. |
Air open vessel at 127^(@)C is heated until 1//5^(th) of air in it has been expelled. Assuming that the volume of vessel remains constant the temperature to which the vessel has been heated is |
| Answer» Answer :D | |
| 85279. |
Acidity of phenol is because of …. |
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Answer» RESONANCE STRUCTURE of PHENOXIDE ION |
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| 85280. |
Air pollution causing photochemical oxidants production include |
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Answer» Oxygen, chlorine, FUMING nitric acid |
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| 85281. |
Acidity of diprotic acids in aqueous increases in the order |
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Answer» `H_(2)Te LT H_(2)S lt H_(2)Se` |
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| 85282. |
Air cotains 79 % N_2 and 21% O_2 by volume.If the barometric pressure is 750 mm Hg the partial pressure of oxygen is : |
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Answer» 157.7 MM of Hg |
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| 85283. |
Acidity of diprotic acids in aqueous solutions increases in the order |
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Answer» `H_(2)S lt H_(2)Se lt H_(2)Te` `H_(2)Slt H_(2)Se lt H_(2)Te`. |
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| 85284. |
Air contains 79 % N_(2) and 21 % O_(2) by volume. If the barometric pressure is 750 mmHg. The partial pressure of oxygen is |
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Answer» 157.7 MM Hg |
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| 85285. |
Acidity of diprotic acids in aqueous solutions increases in the order : |
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Answer» `H_(2)S lt H_(2)Se lt H_(2)TE` |
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| 85286. |
Air contains O_(2) and N_(2) in the ratio of 1:4. Calculate the ratio of solubilities in terms of mole fraction of O_(2) and N_(2) dissolved in water at atmospheric pressure and room temperature at which Henry's constant for O_(2) and N_(2) are 3.30xx10^(7) torr and 6.60xx10^(7) torr respectively. |
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Answer» Solution :At 1 BAR pressure, Partial pressure of `O_(2)(p_(O_(2)))=(1)/(5)xx"1 bar"="0.2 bar,Partial pressure of "N_(2)(p_(N_(2)))=(4)/(5)xx"1 bar= 0.8 bar"` `{:("Applying Henry's law,",p_(O_(2))=K_(H)(O_(2))xxx_(O_(2)),or,x_(O_(2))=(p_(O_(2)))/(K_(H)(O_(2)))),(,p_(N_(2))=K_(H)(N_(2))xx x_(N_(2)),or, x_(N_(2))=(p_(N_(2)))/(K_(H)(N_(2)))):}` `therefore (x_(O_(2)))/(x_(N_(2)))=(p_(O_(2)))/(K_(H)(O_(2)))xx(k_(H)(N_(2)))/(p_(N_(2)))=(p_(O_(2)))/(p_(N_(2)))xx(K_(H)(N_(2)))/(K_(H)(O_(2)))=("0.2 bar")/("0.8 bar")xx(6.60xx10^(7)" TORR")/(3.30 xx10^(7)" torr")=(1)/(2), i.e., x_(O_(2)):x_(N_(2))=1:2` |
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| 85287. |
Air contains 20% oxygen by volume. Calculating the theoretical volume of air which will be required for burning 200 m^(3) of acetylene gas completely. All volumes are measured under the same conditions of temperature and pressure. |
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Answer» Solution :`{:(2C_(2)H_(2),+,SO_(2),rarr,4CO_(2),+,2H_(2)O(g)),("2vol",,"5vol",,"4vol",,"2vol"),("1vol",,"2.5vol",,"2vol",,"2vol"):}` Thus , 500 `m^(3)` OXYGEN is required for complete combustion of 200 `m^(3)` of acetylene, 20 `m^(3)` of oxygen is PRESENT in 100 `m^(3)` of air. `500 m^(3)` of oxygen will be present in `=(100)/(20)xx50m^(3)` of air `=2500 m^(3)` of air |
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| 85288. |
Air contain O_(2) and N_(2) in the ration of 1 : 4 The Henry constant for O_(2) and N_(2) are 3.30 xx 10^(7) torr and 6.60 xx 10^(7) torr respectively. Ration of solubility of O_(2) and O_(2) dissolved in water at atomspheric pressure and room temperature is |
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Answer» `1:4` `P_(N2)=4/5 xx 1 "bar" = 0.8 "bar"` A/c. to Henry's law. `Xo_(2)=(Po_(2))/(K_(H)(o_2)) "and"X_(N2)=P_(N2)/(K_(H)(N_(2)))` `(Xo_(2))/X_(N2)=P_(O2)/(K_(H)(o2)) xx (K_(H)(N_(2)))/P_(N2)=P_(o2)/P_(N2)xx (K_(H)(N2))/(K_(H)(o_(2)))` `0.2/0.8 xx (6.60 xx 10^(7))/(3.30 xx 10^(7))=1/2` `X_(O2) : X_(N2) RARR S_(O2) : S_(N2) =1 : 2 ` |
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| 85289. |
Acidity of BF, can be explained on which of the following concepts ? |
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Answer» Arrhenius concept |
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| 85290. |
Air contain 20 % oxygen by volume. Calculate the theoretical volume of air. Which will be required for buring 100 cm^(3) of propane completely. All volume are measured under same conditions of temperature and pressure. |
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Answer» `500 m^(3)` `100 m^(3)` `O_(2)` required for complete cumbustion of propane `= 500 m^(3)` Amount of air `rArr X m^(3)` `(20.)/(100) XX x = 500` `x = 2500 m^(3)` air |
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| 85291. |
Acidity of BF_(3) can be explained on the basis of which of the following concepts ? |
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Answer» Arrhenius concept |
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| 85292. |
Acidity increases with increasing number of electron - withdrawing substituents on the alpha- carbon. Explain with example. |
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Answer» Solution :Acidity increases with increasing NUMBER of electron withdrawing substituents on the `ALPHA `- CARBON atom. For EXAMPLE, `Cl_3C – COOHgtCl_2CH – COOHgt Cl – CH_2COOH gtCH2COOH` The effect of various, electron withdrawing GROUPS on the acidity of a carboxylic acid follows the order, `-NO_2 gtt -CN gt - F gt - Br gt -I gt Ph` |
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| 85293. |
Air can oxidise sodium sulphite in aqueous solution but cannot do so in the case of sodium arsenite. If however, air is passed through a solution containing both sodium sulphite and sodium arsenite then both are oxidised. This is an example of: |
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Answer» POSITIVE catalysis |
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| 85294. |
Acidified zinc sulphate solution used as an electrolyte during electrolytic refining of zinc should contain about __________. |
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Answer» 3% FREE `H_(2)SO_(4)` |
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| 85295. |
(A)Increasein surface area increases rate of evaporaton (R ) Stronger the intermolecular force faster rate of evaportion at a given temperature |
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Answer» Both (A) and (R ) are TRUE and (R ) is the correct explanation of (A) |
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| 85296. |
Acidified solution of Chromic acid on treatment with H_2O_2yields. |
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Answer» `CrO_3+H_2O+O_2` |
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| 85297. |
A:In Hall process Aluminium is purified.B:Al_2O_3(aq)is used in Hall process. |
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Answer» If both Assertion & Reason are TRUE and the reason is the CORRECT explanation of the assertion, then mark (1). |
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| 85298. |
Acidified solution of sodium thiosulphate are unstable because in thiosulphate: |
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Answer» The sulphur ATOMS are at UNSTABLE OXIDATION state of + 2 |
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| 85299. |
(A)In Haber's synthesis, the rate of formation of NH_(3) is increased by adding Fe. (R ) Fe acts as catalyst for Haber's synthesis. |
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Answer» Both (A) and (R ) are TRUE and (R ) is the CORRECT EXPLANATION of (A) |
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| 85300. |
AIF_(3) is soluble in HF only in presence of KF: It is due to the formation of - |
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Answer» `K_(3)[AIF_(3)H]` |
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