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85251.

a.Convert the following a. b. .

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SOLUTION :a.` (##KSV_CHM_ORG_P2_C15_S01_020_S01.png" WIDTH="80%">
B. ` (##KSV_CHM_ORG_P2_C15_S01_020_S02.png" width="80%">.
85252.

Aland Ga have the same covalent radii because of:

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POOR SHIELDING POWER of d-electrons of GA atoms
Poor shielding power of s-electron of Ga atoms
Greater shielding power of s-electrons of a Ga atoms
Greater shielding power of d-electrons of Ga atoms.

Answer :A
85253.

A colourless liquid P formed a crystalline product with 2,4 dinitrophenyl hydrazine but did notreduce ammoniacal silver nitrate solutionthe possibleformula of P is

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`CH_(3)CH_(2)CH_(2)CHO`
`CH_(3)CH_(2)COOC_(2)H_(5)`
`CH_(3)COCH_(2)CH_(3)`
`CH_(3)CH_(2)CH_(2)CH_(2)OH`

ANSWER :C
85254.

Al and Ga are trivalent in their compounds but monovalent compounds are the most stable down the 13th group. Why?

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Solution :Down the group `(13th)`, the STABILITY of `+3` state decreases and that of `+1` state INCREASES due to the prominent "inert PAIR" effect.
`Al^(3+)gtGa^(3+)gtIn^(3+)gtTI^(3+)`
Most stable`to` LEAST stable
`Tl^(+) gt In^(+) gt Ga^(+) gt Al^(+)`
85255.

Al^(+3). Fe^(+3) & Cr^(+3) are grouped together for qualitative analysis because their

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CARBONATES are INSOLUBLE in `NH_(3)`
hydroxides are insoluble in `NH_(3)`
sulphides are SOLUBLE in acid
sulphides are insoluble in acid

Answer :B
85256.

(A)Colloidal solutionsare stable but colloidal particles do not settle down(R ) Brownianmovement counters the force of gravity actively on colloidal particles

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Both (A) and (R ) are TRUE and (R ) is the correct EXPLANATION of (A)
Both (A)and (R ) are true and (R ) is not the correct explanation of (A)
(A) is true but (R ) is false
Both (A) and (R ) are false

Answer :A
85257.

Here, the product X and Y are

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`{:(X,, Y) ,( n-"propyl ALCOHOL ",,n- "propyl alcohol "):}`
`{:(X,, Y) ,( ISO -"propyl alcohol ",,iso - "propyl alcohol "):}`
`{:(X,, Y) ,( n -"propyl alcohol ",, iso - "propyl alcohol "):}`
`{:(X,, Y) ,( iso -"propyl alcohol ",, n - "propyl alcohol "):}`

ANSWER :D
85258.

Acolloidal solution in which a solid is dispersed in a liquid is called:

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Gel
Emulsion
Sol
Precipitate.

Answer :C
85259.

Total number of hybrid orbitals involved in bonding in a molecule of 'C'is

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12
10
18
6

Answer :C
85260.

A:CN^(-) is an acid ligand. R: CN^(-) accepts electron pair also.

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 If both Assertion & REASON are TRUE and the reason is the correct EXPLANATION of the assertion, then MARK (1) 
 If both Assertion & Reason are true but the reason is not the correct explanation of the assertion, then mark (2). 
) If Assertion is true statement but Reason is false, then mark (3).
 If both Assertion and Reason are false statements, then mark (4)

ANSWER :D
85261.

aK_(2)Cr_(2)O_(7)+bKCl+cH_(2)SO_(4)toxCrO_(2)Cl_(2)+yKHSO_(4)+zH_(2)OThe above equation balances when

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a = 2, B = 4, c = 6 and X = 2, y = 6, z = 3
a = 4, b = 2, c = 6 and x = 6, y = 2, z = 3
a = 6, b = 4, c = 2 and x = 6, y = 3, z = 2
a = 1, b = 4, c = 6 and x = 2, y = 6, z = 3

Answer :D
85262.

aK_(2)Cr_(2)O_(7) + bKCl+cH_(2)SO_(4)toxCrO_(2)Cl_(2)+yKHSO_(4)+zH_(2) The above equation balances when

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`a=2, b=4, c=6` and `x=2, y=6, z=3`
`a=4, b=2, c=6` and `x=6, y=2, z=2`
`a=6, b=4, c=2` and `x=2, y=3, z=2`
`a=1, b=4, c=6` and `x=2, y=6, z=3`

SOLUTION :`(({:(KCl+H_(2)SO_(4)toKHSO_(4)+HClxx6),(K_(2)Cr_(2)O_(7)+6HCL to 2Cr_(2)O_(2)Cl_(2)+2KCl+3H_(2)O):})/(4KCl+6H_(2)SO_(4)+K_(2)Cr_(2)O_(7)to6KHSO_(4)+2CrO_(2)Cl_(2)+3H_(2)O))/`
c.f. `aK_(2)Cr_(2)O_(7)+bKCl+cH_(2)SO_(4)toCrO_(2)Cl_(2)+yKHSO_(4)+zH_(2)O`
85263.

Aclosed vessel contains equal number of nitrogen and oxygen molecules at a pressure of P mm. If nitrogen is removed from the system, then the pressure will be :

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P
2P
P/2
`P^2`

ANSWER :C
85264.

aK_2Cr_2 O_7+bKCI+cH_2 SO_4to xCrO_2CI_2+ yKHSO_4+zH_2 O the aboveequationbalanceswhen

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a=2, b=4,c=6and X=2, y=6 , z=3
a=4 ,b=2 ,c=6 and x=6 ,y=2 ,z=3
a = 6, b=4, c= 2 and x = 6, y = 3, z =2
a = 1, b = 4, c = 6 and x=2, y = 6, z = 3

Solution :
85265.

Acififledsolutionof chromicacidontreatment withH_(2) O_(2)givebluecolourwhichis due to "______"

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`CrO_(3)+ H_(2) O + O_(2)`
`H_(2)Cr_(2) O_(7)+ H_(2) O+ CO_(2)`
`Cr_(2)O_(3) + H_(2) O +O2`
`CrO_(5) + H_(2) O`

Answer :D
85266.

Airborne bacteria and viruses form a colloidal system of __ in __. The blanks can be correctly filled by:

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SOLID, Gas
Gas, solid
Solid, solid
Solid, liquid

Answer :B
85267.

Acids nature of Zn (OH)_(2) is shown during its reaction with

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`H_(2)SO_(4)`
HCl
NaOH
None

Answer :C
85268.

Aired-Rochow's electronagativity upon

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ELECTRON affinity
effective nuclear change
Radius
B &C both

ANSWER :D
85269.

Acids having higher B.P. than alcohols because of

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intra MOLECULAR HB
dimerisation of ACID
DIPOLE - dipole attraction
VANDER Waals FORCE of attraction

Answer :B
85270.

Air was drawn through a solution containing 38 g of solute in 100 g of water, andthen through water. The loss of weight of water was 0.0551 g and the total weight of water absorbed in sulphuric acid tube was 2.2117 g. Find the molecular weight of the dissolved substance

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Solution :Raoult.s LAW:LOWERING of VP / VP of SOLVENT= MOLE fraction of solute
`(0.0551)/(2.2117) = (38//M)/
85271.

Acids have higher boiling points due to

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PLEASANT smell
waxy solid
hydrogen BONDING
`-COOH` group

Answer :C
85272.

Airpollution is not caused by:

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POLLEN grains
hydroelectric power
industries
automobiles

Answer :B
85273.

Air pollution from the leakage of methyl isocyanate gas from the Union carbide factory in Bhopal caused a major tragedy on:

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`DEC. 2, 1984`
`Dec. 15 1983`
`Dec. 10, 1982`
`Dec. 4, 1988`

Answer :A
85274.

Acids and esters are

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CHAIN isomers
POSITION isomers
FUNCTIONAL isomers
metamers

ANSWER :C
85275.

Air pollution effects are usually found on

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Leaves
Stems
Flowers
Roots

Answer :A
85276.

Acidosis is diagnosed when blood pH:

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FALLS below 7.35
Rises above 7.45
BOTH (A) AND (B)
NONE of the above

Answer :A
85277.

Acidity of which of the following compound is quite high compared to the rest of the given compounds-

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ANSWER :C
85278.

Air open vessel at 127^(@)C is heated until 1//5^(th) of air in it has been expelled. Assuming that the volume of vessel remains constant the temperature to which the vessel has been heated is

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`177^(@)C`
`277^(@)C`
`377^(@)C`
`477^(@)C`

Answer :D
85279.

Acidity of phenol is because of ….

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RESONANCE STRUCTURE of PHENOXIDE ION
Resonance structure of phenol
Oxygen is moreelectro NEGATIVE than hydrogen
Not given

Solution :Resonance structure of phenoxide ion
85280.

Air pollution causing photochemical oxidants production include

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Oxygen, chlorine, FUMING nitric acid
Nitrous oxide, nitric acid fumes, nitric oxide
Ozone, peroxyacetyl NITRATE, aldehydes
Carbon monoxide, SULPHUR dioxide

Answer :C
85281.

Acidity of diprotic acids in aqueous increases in the order

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`H_(2)Te LT H_(2)S lt H_(2)Se`
`H_(2)Se lt H_(2)Te lt H_(2)S`
`H_(2)S lt H_(2)Se lt H_(2)Te`
`H_(2)Se lt H_(2)S lt H_(2)Te`

Solution :BOND LENGTH increases from `H_(2)S` to `H_(2)Te`.
85282.

Air cotains 79 % N_2 and 21% O_2 by volume.If the barometric pressure is 750 mm Hg the partial pressure of oxygen is :

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157.7 MM of Hg
175.5 mm of Hg
315.0 mm of Hg
None of the above

Answer :A
85283.

Acidity of diprotic acids in aqueous solutions increases in the order

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`H_(2)S lt H_(2)Se lt H_(2)Te`
`H_(2)Se lt H_(2)S lt H_(2)Te`
`H_(2)Te lt H_(2)S lt H_(2)Se`
`H_(2)Se lt H_(2)Te lt H_(2)S`

Solution :As the SIZE of the element (X) increases, the bond length of the H-X bond increases and its bond strength decreases. In other WORDS, tendency of the H-X bond to dissociate to give `H^(+)` ions increases and hence ACIDITY increases in the ORDER :
`H_(2)Slt H_(2)Se lt H_(2)Te`.
85284.

Air contains 79 % N_(2) and 21 % O_(2) by volume. If the barometric pressure is 750 mmHg. The partial pressure of oxygen is

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157.7 MM Hg
175.5 mm Hg
315.0 mm Hg
none of the above

Answer :A
85285.

Acidity of diprotic acids in aqueous solutions increases in the order :

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`H_(2)S lt H_(2)Se lt H_(2)TE`
`H_(2)Se lt H_(2)S lt H_(2)Te`
`H_(2)Te lt H_(2)S lt H_(2)Se`
`H_(2)Se lt H_(2)Te lt H_(2)S`

ANSWER :A
85286.

Air contains O_(2) and N_(2) in the ratio of 1:4. Calculate the ratio of solubilities in terms of mole fraction of O_(2) and N_(2) dissolved in water at atmospheric pressure and room temperature at which Henry's constant for O_(2) and N_(2) are 3.30xx10^(7) torr and 6.60xx10^(7) torr respectively.

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Solution :At 1 BAR pressure,
Partial pressure of `O_(2)(p_(O_(2)))=(1)/(5)xx"1 bar"="0.2 bar,Partial pressure of "N_(2)(p_(N_(2)))=(4)/(5)xx"1 bar= 0.8 bar"`
`{:("Applying Henry's law,",p_(O_(2))=K_(H)(O_(2))xxx_(O_(2)),or,x_(O_(2))=(p_(O_(2)))/(K_(H)(O_(2)))),(,p_(N_(2))=K_(H)(N_(2))xx x_(N_(2)),or, x_(N_(2))=(p_(N_(2)))/(K_(H)(N_(2)))):}`
`therefore (x_(O_(2)))/(x_(N_(2)))=(p_(O_(2)))/(K_(H)(O_(2)))xx(k_(H)(N_(2)))/(p_(N_(2)))=(p_(O_(2)))/(p_(N_(2)))xx(K_(H)(N_(2)))/(K_(H)(O_(2)))=("0.2 bar")/("0.8 bar")xx(6.60xx10^(7)" TORR")/(3.30 xx10^(7)" torr")=(1)/(2), i.e., x_(O_(2)):x_(N_(2))=1:2`
85287.

Air contains 20% oxygen by volume. Calculating the theoretical volume of air which will be required for burning 200 m^(3) of acetylene gas completely. All volumes are measured under the same conditions of temperature and pressure.

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Solution :`{:(2C_(2)H_(2),+,SO_(2),rarr,4CO_(2),+,2H_(2)O(g)),("2vol",,"5vol",,"4vol",,"2vol"),("1vol",,"2.5vol",,"2vol",,"2vol"):}`
Thus , 500 `m^(3)` OXYGEN is required for complete combustion of 200 `m^(3)` of acetylene, 20 `m^(3)` of oxygen is PRESENT in 100 `m^(3)` of air.
`500 m^(3)` of oxygen will be present in `=(100)/(20)xx50m^(3)` of air
`=2500 m^(3)` of air
85288.

Air contain O_(2) and N_(2) in the ration of 1 : 4 The Henry constant for O_(2) and N_(2) are 3.30 xx 10^(7) torr and 6.60 xx 10^(7) torr respectively. Ration of solubility of O_(2) and O_(2) dissolved in water at atomspheric pressure and room temperature is

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`1:4`
`4 : 1`
`1 : 2`
`2 : 1`

Solution :At 1 bar, `Po_(2)=1/4 XX1 "bar"=0.2 "bar",`
`P_(N2)=4/5 xx 1 "bar" = 0.8 "bar"`
A/c. to Henry's law.
`Xo_(2)=(Po_(2))/(K_(H)(o_2)) "and"X_(N2)=P_(N2)/(K_(H)(N_(2)))`
`(Xo_(2))/X_(N2)=P_(O2)/(K_(H)(o2)) xx (K_(H)(N_(2)))/P_(N2)=P_(o2)/P_(N2)xx (K_(H)(N2))/(K_(H)(o_(2)))`
`0.2/0.8 xx (6.60 xx 10^(7))/(3.30 xx 10^(7))=1/2`
`X_(O2) : X_(N2) RARR S_(O2) : S_(N2) =1 : 2 `
85289.

Acidity of BF, can be explained on which of the following concepts ?

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Arrhenius concept
Bronsted-Lowry concept
LEWIS concept
Bronsted-Lowry as well as Lewis concept

Solution :B in `BF_(3)` is ELECTRON deficient and HENCE, it has a TENDENY to accept a pair of electrons.
85290.

Air contain 20 % oxygen by volume. Calculate the theoretical volume of air. Which will be required for buring 100 cm^(3) of propane completely. All volume are measured under same conditions of temperature and pressure.

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`500 m^(3)`
`2500 m^(3)`
`100 m^(3)`
`5000 m^(3)`

Solution :`C_(3)H_(8) + 5O_(2) rarr 3 CO_(2) + 4 H_(2)O`
`100 m^(3)`
`O_(2)` required for complete cumbustion of propane `= 500 m^(3)`
Amount of air `rArr X m^(3)`
`(20.)/(100) XX x = 500`
`x = 2500 m^(3)` air
85291.

Acidity of BF_(3) can be explained on the basis of which of the following concepts ?

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Arrhenius concept
Bronsted Lowry concept
LEWIS concept
Bronsted Lowry as well as Lewis concept.

SOLUTION :`BF_(3)`is Lewis ACID because it accepts ELECTRONS.
85292.

Acidity increases with increasing number of electron - withdrawing substituents on the alpha- carbon. Explain with example.

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Solution :Acidity increases with increasing NUMBER of electron withdrawing substituents on the `ALPHA `- CARBON atom. For EXAMPLE,
`Cl_3C – COOHgtCl_2CH – COOHgt Cl – CH_2COOH gtCH2COOH`
The effect of various, electron withdrawing GROUPS on the acidity of a carboxylic acid follows the order,
`-NO_2 gtt -CN gt - F gt - Br gt -I gt Ph`
85293.

Air can oxidise sodium sulphite in aqueous solution but cannot do so in the case of sodium arsenite. If however, air is passed through a solution containing both sodium sulphite and sodium arsenite then both are oxidised. This is an example of:

Answer»

POSITIVE catalysis
Negative catalysis
Induced catalysis
Auto-catalysis

Answer :C
85294.

Acidified zinc sulphate solution used as an electrolyte during electrolytic refining of zinc should contain about __________.

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3% FREE `H_(2)SO_(4)`
5% free `H_(2)SO_(4)`
10% free `H_(2)SO_(4)`
20% free `H_(2)SO_(4)`

ANSWER :A
85295.

(A)Increasein surface area increases rate of evaporaton (R ) Stronger the intermolecular force faster rate of evaportion at a given temperature

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Both (A) and (R ) are TRUE and (R ) is the correct explanation of (A)
Both (A)and (R ) are true and (R ) is not the correct explanation of (A)
(A) is true but (R ) is FALSE
Both (A) and (R ) are false

ANSWER :C
85296.

Acidified solution of Chromic acid on treatment with H_2O_2yields.

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`CrO_3+H_2O+O_2`
`Cr_2O_2 +H_2O+O_2`
`CrO_5 +H_2O+K_2SO_4`
`H_2Cr_2O_7 +H_2O +O_2`

ANSWER :C
85297.

A:In Hall process Aluminium is purified.B:Al_2O_3(aq)is used in Hall process.

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If both Assertion & Reason are TRUE and the reason is the CORRECT explanation of the assertion, then mark (1).
If both Assertion & Reason are true but the reason is not the correct explanation of the assertion, then mark (2)
If Assertion is true STATEMENT but Reason is false, then mark
 If both Assertion and Reason are false statements, then mark (4)

Answer :D
85298.

Acidified solution of sodium thiosulphate are unstable because in thiosulphate:

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The sulphur ATOMS are at UNSTABLE OXIDATION state of + 2
The two sulphur atoms are different oxidation states of +6 and -2
The S-S BOND are unstable bonds
Thio componds contain sulphur in zero oxidation state

Answer :B
85299.

(A)In Haber's synthesis, the rate of formation of NH_(3) is increased by adding Fe. (R ) Fe acts as catalyst for Haber's synthesis.

Answer»

Both (A) and (R ) are TRUE and (R ) is the CORRECT EXPLANATION of (A)
Both (A)and (R ) are true and (R ) is not the correct explanation of (A)
(A) is true but (R ) is false
Both (A) and (R ) are false

ANSWER :A
85300.

AIF_(3) is soluble in HF only in presence of KF: It is due to the formation of -

Answer»

`K_(3)[AIF_(3)H]`
`K_(3)[AIF_(3)H_(3)]`
`K_(3)[AIF_(6)]`
`AIH_(3)`

ANSWER :C