94420 + Interview Questions in Chemistry in Class 12 Page 1707 InterviewSolution

85301.	Acidified solution of chromic acid on treatment with H_(2)O_(2) gives blue colour which is due to
Answer» `CrO_(3)+H_(2)O+O_(2)` `CrO_(5)+H_(2)O` `H_(2)Cr_(2)O_(7)+H_(2)O+O_(2)` NONE of these Solution :`H_(2)Cr_(2)O_(7)+4O to underset("BLUE peroxide of chromium")(2CrO_(5))+H_(2)O`

Discussion

85302.	AlF_(3) is soluble in HF only in the presence of KF. It is due to the formation of
Answer» `K_(3)[AlF_(3)H_(3)]` `K_(3)[AlF_(6)]` `AlH_(3)` `K[AlF_(3)H]` SOLUTION :`AlF_(3)+3KFtoK_(3)[AlF_(6)]`

Discussion

85303.	Acidified sodium fusion extract on addition of ferric chloride solution gives blood red colouration which confirms the presence of
Answer» S and CI N and S N S Solution :ACIDIFIED sodium fusion EXTRACT on ADDITION of ferric chloride solution gives blood red colouration, which confirms the presence of N and S. Sodium metal (if not used in EXCESS) in compounds containig N and S together FORMS sodium thiocyanate. `Na + C + N+ S toNaCNS`(sodium thiocyanate) `Fe^(3+) + CNS^(-)rarr Fe(CNS)_(3)`(blood red ppt.)

Discussion

85304.	AIF_(3)is soluble in HF only in presence of KF . It is dueto the formation of
Answer» `K_(3) [AIF_(3) H_(3)]` `K_(3) [AIF_(6)]` `AIH_(3)` `K[AIF_(3)H]` ANSWER :B

Discussion

85305.	[A]:If the activation energy of reaction is zero then the rate of reaction does not depend on temperature. [R]:If the activation energy is less then the rate of reactio is more.
Answer» Assertion [A] and REASON [R] both are correct and [R] gives correct explanation of [A] Assertion [A] and reason [R] both are correct but [R] does not give correct explanation of [A] Assertion [A] is wrong but Reason [R] is wrong Assertion [A] is wrong but Reason [R]is correct Solution :If the activation energy (`E_(a)`) is zero then the energy Is not give to reactant to COMPLETE the reaction.It is not necessary to increase the temperature for heat.Therefore the temperatue CHANGE does not affect on RATE of reaction. As the activation of energy is less,the fraction of molecule which undergoes fruit full collision with kinetic energy is more,so rate of reaction increase.

Discussion

85306.	Acidified potassium permanganate solution is decolourised by
Answer» WHITE vitriol Bleaching powder Laughing gas Mohr.s salt Answer :D

Discussion

85307.	AIF_(3) ionic while AlCl_(3) is covalent .
Answer» SOLUTION :Since `F^(-)` is smaller in size, its polarisability is less and therefore it is having more ionic character. Whereas, CL being large in size is having more polarisability and HENCE more COVALENT character.

Discussion

85308.	Acidified potassium dichromate is treated with hydrogen sulphide, IN this reaction, the oxidation number of chormium :
Answer» INCREASE from +3 to +6 decreases from + 6 to +3 REMAINS unchanged decreases from + 6 + 2. Solution :`Cr_(2)O_(7)^(2-) (+6) to Cr^(3+) (3) `

Discussion

85309.	AI_(2)O_(3)is reduced by electrolysisat lowpotentials and high current if 4.0xx10^(4)amperes of curretnis passed through molten AI_(2)O_(3)for 6h what mass of aluminimum is produced ? (Assume 100% currentaluminimumatomicweightof AI=27)
Answer» `9.0xx10^(3)` G `8.1xx10^(4)` g `2.4 xx10^(3)`g `1.3 xx10^(4) g` SOLUTION :The reactionis `AI^(3+) +3e^(-) rarr AI` `therefore E_(AI)=("atomic WEIGHT")/(3)=27/3=9` Now`w =("Eit")/(96500)=(9xx4xx10^(4)xx6xx60xx60)/(96500)` `=8.05 xx10^(4) =8.1 xx10^(4) g`

Discussion

85310.	(A)(i) Arrangethe followingin orderof increasingmolarconductivity 1.Mg[Cr(NH_(3))(CI_(3)) 2. [Cr(NH_(3))CI]_(3) [CoF_(6)1_(2) . 3. [Cr(NH_(3))_(3)Ci_(3)] (ii)Silicon carbideis veryhard. Justifythisstatement. (b)(i)Writethe lawfor thefollowingreactions(a) A reactionthat3//2 orderis x areorderin y. (b)A reactionthat issecond orderin Noand firstorder in Br_(2) (ii) Classifythe followingspeciesintoLewisacidsand lewisbasesand showhowcan actLewisacid //Lewisbase ? (a) OH^(-)ions (b)F^(-) (c _ H^(+) (d ) BCI_(3)
Answer» Solution :a (i) Thesecomplexcanionisein solutionas `Mg[Cr(NH_(3)) (CI_(3)) =Mg^(2+)+ [Cr(NH)_(3)) (CI)_(5)]^(2-)` `[Cr(NH_(3))_(3)Ci_(3)]=` DOESNOT IONIZE (ii) silicon carbide isveryhard. It iscovalentsolidcontainsthe atomswhichare bound tegetherin thredimensionalnetworkentirely by covalentbonds.So thecovalentnetworkcrystalsiCis veryhardand havehighmeltingpoint. b (i) `(a) (3)/(2) x + y` (EXCESS ) `to` PRODUCTS (b) 2 No+ `Br_(2)to` Products(2NOBr) (ii) (a) `OH^(-)` ions can domateanelectron pairact aslewisbase. (b) `BCI_(3)` can acceptsan electronpairsinceBoronatomis electrondeficient .Itis a lewisacid.

Discussion

85311.	(a) (i) CalculatepHof 10^(-7) M HCI, (ii)Definecorrosion .Giveoneexample. (b)What isadsorptionisotherm Explain aboutFreundlichadsorptionisotherm.
Answer» Solution :(i) If wedo notconsider `[H_(3)O^(+)]` from theionisationof `H_(2)O` then`[H_(3) O^(+)]=[HCI]` i.e., pH=7 whichis a pHof a neutralsolution.Weknowthat HCIsolutionis acidicthiscasethe concentrationof the acidis verylow `(10^(-7) M)`. Hencethe `H_(3) O^(+)(10^(-7 M)` So in thiscasewe shouldionisation of watercannot be neglected. (ii) Theredoxprocesswhichcausesthe deteriorationof metalis calledcorrosionRustingof ironis anexampleof corrosion.It isan electrochemicalprocess. (b)i.Adsorptionisothermsrepresentthe variationof adsorptionat constanttemperatureadsorptionisothemcan bestudiedquatitatively (ii) A plotbetweenthe amountof adsorbate adn pressureor concentration of . (iii)Freundichadsorptionisotem. (IV) thisequationisapplicationfor adsorptionof gaseson solidsurfaces.TheSameequationbecomes `(x)/(m)=ke^(1//n)` whenusedforadsorptionin solutionwith Cas concentration (v )theseequationquantitivelypredictthe effectof pressure(orconcentration ) on theadsorptionof gasesat constanttemperature. (vi)Takinglogon bothsidesof equation `(x)/(m) =kP^(1//n)` `log(x )/(m)= log k+ (1)/(n )log P` (VII) Hencetheinterceptrepresentsthe valueof logk andthe slope `(b)/(q)` gives `(1)/(n)` (vii)thisequationexplainthe increasesof `(x)/(m)` withincreasin pressure.Butexperimentalvaluesshowsthe deviationat lowpressure . `(IX) LIMITATIONS (a)Thisequationis purelyempiricalovera limitedpressurerange

Discussion

85312.	Acidified potassium dichromate is treated with hydrogen sulphide.In the reaction the oxidation number of chromium :
Answer» Increase from +3 to +6 Decreases from +6 to +3 Remains UNCHANGED Decreases from +6 to +2 Answer :B

Discussion

85313.	(a)How will you distinguish between Pentan2-one and Pentan-3-one with the help of Iodoform test? (b) How will you bring about following conversions ? (I) Benzoic acid to m-Nitrobenzyl alcohol. (II) Benzaldehyde to Benzophenone. (iii) Benzoic acid to Benzamide.
Answer» SOLUTION :(a) PENTAN -2- ONE givesiodoformtesti.e,yellowppton warmingwith `I_2`and NaOHbutpentan -2- one DOESNOT

Discussion

85314.	(a)How does Primary amine undergoes carbyl amine reaction? Give chemical equation.(b) How is aniline is prepared by Hoffmann bromamide degradation reaction? Give equation.(c) Write the general formula of diazonium salt.
Answer» Solution :(a) PRIMARY amines on heating with chloroform and alcoholic KOH form carbylamines. `R-NH_(2)+CHCl_(3) + underset(Alco)(3KOH) to R-NC + 3KCl + 3H_(2)O_(2)`. (b) When benzenamide is treated with bromine in aqueous solution of sodium hydroxide ANILINE is obtained. (C) `RN_(2)^(+)`

Discussion

85315.	Acidified permanganate solution does not oxidise:
Answer» `C_(2)O_(4)^(2-)` (aq.) `NO_(3)^(-)` (aq.) `S^(2-)` (aq.) `F^(-)`(aq.) SOLUTION :Practically `F^(-)` ION beinga very R.A has no reducing property.

Discussion

85316.	Acidified KMnO_(4) solution is decolourized by
Answer» TOLUENE `MnSO_(4)` `H_(2)O_(2)` `KI ` Answer :C

Discussion

85317.	Alcohols are isomeric with
Answer» Acids Ethers Esters Aldehydes Answer :B

Discussion

85318.	(a)Haematite-Gravity separation process (b)Copper pyrite-Froth floatation (c )Bauxite-Leaching process (d)Pyrolusite-Magnetic separation process
Answer» SOLUTION :(B)COPPER pyrite-froth FLOATATION PROCESS

Discussion

85319.	A_((g))toB_((g)) is a first order reaction. The initial concentration of A is 0.2 mol. "lit"^(-1). After 10 minutes the concentration of B is found to be 0.18"mol. lit"^(-1). The rate constant ("in min"^(-1)) for the reaction is
Answer» `0.2303` `2.303` `0.693` `0.01` ANSWER :A

Discussion

85320.	Ag_((s))\|AgBr_((s))\|Br^(-)(0.011M)\|\|Cl^(-)(0.2M)\|AgCl_((s))\|Ag_((s)) if K_(sp) of AgBr & AgCl at 25^(@)C are 10^(-12) & 10^(10) respectively find which is/are true for above cell at 25^(@)C(log2=0.3)
Answer» As `E_(Ag^(+)//Ag)^(@)` is not given so `E_("CELL")` cannot be determined `E_("cell")` is `0.0413` volt `/_\Glt0` `E^(@)=0` SOLUTION :`E_(cl^(-)//AgCl//Ag)^(@)=E_(Ag^(+)//Ag)^(@)+(RT)/F IN K_(sp)`………..(i) `E_(Br^(-))^(@)//AgBr//Ag=E_(Ag^(+)//Ag)^(@)+(RT)/F In K_(sp)`…..(II) as `E_(Ag^(+)//Ag)^(@)` will be cancelled onn subtractions (i) & (ii) So `E_("cell")` can be determined

Discussion

85321.	Acidified KMnO_4 oxidizes nitrites to
Answer» `N_2` `NO_3` `NO_3^(-)` NO Answer :C

Discussion

85322.	Ag(s)\|Ag^(+)(aq)(0.01M)\|\|Ag^(+)(aq)(0.1M)\|Ag(s)E^(@)\|Ag(s)Ag_((aq))^(@)=0.80 volt
Answer» Cellcannot function as anode and cathode are of the same MATERIAL `E_("cell")=0.0591V` `E_("cell")=0.80V` `E_("cell")=0.0296V` Solution :It is a concentration cell `E_("cell")=(0.0591)/(n)"LOG" (C_(2)(RHS))/(C_(1)(LHS))` `=(0.0591)/(1)"log"(0.1)/(0.01)=0.0591V`

Discussion

85323.	Ag_((s))\|Ag_((aq))^(+)(0.01M)\|\|Ag_((aq))^(+)(0.1M)\|Ag_((s))E_(Ag_((s))//Ag_((aq)))^(@)=0.80volt
Answer» CELL cannot function as anode and cathode are of same MATERIAL `E_(cell)=0.0592V` `E_(cell)=0.80V` `E_(cell)=0.0296V` Solution :For an electrolytic concentration cell, `E_(cell)=(0.0591)/(n)"LOG"(C_(1)(R.H.S.))/(C_(2)(L.H.S.))` `=(0.0591)/(1)"log"(0.1)/(0.01)=0.0591log10=0.0591V`.

Discussion

85324.	Acidified KMnO_4 is decolourised by:
Answer» OXYGEN Hydrogen Nitric oxide Nascent hydrogen Answer :D

Discussion

85325.	Acidified KMnO_(4) is a very strong oxidising agent. Prove it.
Answer» SOLUTION :(i) In the presence of dilute sulphuric acid, potassium permanganate acts as a very strong oxidising agent. Permanganate ion is converted into `MN^(2+)` ion. `MnO_(4)^(-)+ 8H^(+) + 5e^(-) + Mn^(2+) + 4H_(2)O` (ii) Permanganate oxidises FERROUS salt to ferric salt. `2MnO_(4)^(-)+10Fe^(2+) + 16H^(+) to2Mn^(2+) + 10Fe^(3+) + 8H_(2)O`

Discussion

85326.	Acidified K_2Cr_2O_7 solution turns green when Na_2SO_3 is added to it. This is due to the formation of
Answer» `Cr_(2)(SO_4)_3` `CrO_(4)^(2-)` `Cr_(2)(SO_3)_3` `CrSO_(4)` Answer :A

Discussion

85327.	Find out the incorrect pair(a)Gold ore-Cyanide leaching (b)Nickel ore-Ammonia leaching ( c)Aluminium ore-Alkali leaching (d)silver ore-Acid leaching
Answer» SOLUTION :(d)SILVER ore-Acid LEACHING

Discussion

85328.	Acidified KMnO_(4) can be decolourised by (a)_____.
Answer» ANSWER :`Fe^(2+)or C_(2)O_(4)^(2-),SO_(3)` etc

Discussion

85329.	AgO actually exists as Ag[AgO_(2)], which is diamagnetic in nature. Then which of the following statements is true regarding AgO?
Answer» The arrangement of `O^(2-)` ions AROUND `Ag^(+)` ion is square PLANAR The arrangement of `O^(2-)` ions around `Ag^(+)` ion is tetrahedral The arrangement of `O^(2-)` ions around `Ag^(+)` ion is square planar. Both `(B)` and `(C )` are correct. Solution :It EXISTS as square planar structure.

Discussion

85330.	By passing Na_2SO_(3) to the solution of K_(2)Cr_(2)O_(7), it turns green due to the formation of
Answer» `Cr_(2)(SO_(4))_(3)` `CrO_(4)^(2-)` `Cr_(2)(SO_(3))_(3)` `CrSO_(4)` Solution :`K_(2)Cr_(2)O_(7) + 3NA_(2)SO_(3) + 4H_(2)SO_(4) to 3Na_(2)SO_(4) + K_(2)SO_(4) + Cr_(2)(SO_(4))_(3)`

Discussion

85331.	Acidified K_(2)Cr_(2)O_(7) turns green by
Answer» `CO_(2)` CO `SO_(2)` HCl Answer :C

Discussion

85332.	AgOH solution was neutralized using HNO_(3)solution. If pH of the solution at 50% neutralization point is 8 at 25^(@)C, then pK_(b)of AgOH is:
Answer» `4.00` `5.52` `6.00` `9.48` Solution :As at half NEUTRALIZATION point `POH= 14-pH= 14-8= 6` `rArr pK_(B)= 6`……for AgOH

Discussion

85333.	AgO in Ag(II) complex is
Answer» Diamagnetic paramagnetic Ferromagnetic Neutral Answer :A

Discussion

85334.	Acidified K_2Cr_2O_7 solution turns green by:
Answer» `CO_2` GAS `SO_2` gas HCL gas `H_2S` gas SOLUTION :`SO_2` gas turns ACIDIFIED `K_2Cr_2O_7` solution GREEN

Discussion

85335.	AgNO_(3)given white ppthypo changing to blackofter sometime .Black ppt is of
Answer» `Ag_(2)S_(2)O_(3)` `Ag_(2)SO_(4)` `Ag_(2)S_(4)O_(6)` `Ag_(2)S` Answer :d

Discussion

85336.	Acidified K_(2)Cr_(2)O_(7) reacts with H_(2)O_(7) to give "…............." coloure due to the formation of "…...................".
Answer» ANSWER :DEEP BLUE, `CrO_(5)`

Discussion

85337.	AgNO_(3(aq) was added to an aqueous KCl solution gradully and the conductivity of the solution was measured. The plot of conductance (Lambda) versus the volume of AgNO_(3) is
Answer» Solution :(d) The plot(s) REPRESENTS the correct trend. The reaction is a PRECEPITATION reaction `underset(("White ppt"))(AgNO_(3)(aq))+KCl(aq) to AgCl(s)+KNO_(3(aq))` `Ag^(+)(aq)+NO_(3)^(-)(aq)+K^(+)(aq)+Cl^(-)(aq) to AgCl(s)+K^(+)(aq)+NO_(3)^(-)(aq)` In this titration, known as conductometric litration, initially the conductance of the solution does not change much because the `Cl^(-)` ions are getting precipitated as AgCl and are replaced by `NO_(3)^(-)` ions Both the ions have nearly the same ionic conductnace Once the precipitation reaction is complete, the further ADDITION of `AgNO_(3)` will increase the concentration of `NO_(3)^(-)`ions in the solution. As a result, the conductance of solution will increase sharply as shown in the curve(s).

Discussion

85338.	Acidified K_2 Cr_2 O_7 turns green by
Answer» `SO_(2)` CO `SiO_(2)` `HCl` SOLUTION :`K_(2)Cr_(2)O_(7)` turns green by `SO_(2)` DUE to its reduction `K_(2)Cr_(2)O_(7)+H_(2)SO_(4)+3SO_(2) to K_(2)SO_(4)+underset("Green")(Cr_(2)(SO_(4))_(3))+H_(2)O`

Discussion

85339.	AgNO_(3(aq)) was added to an aqueous KCl solution gradually and the conductivity of the solution was measured. The plot of conductance A versus the volume of AgNO_3 is
Answer» <P>(P) (Q) (R) (S) ANSWER :D

Discussion

85340.	Acidified K_2Cr_2O_7 changes to green on reactions with
Answer» `SO_2` `FeSO_4` Kl and then ADDING HYPO `NaCl + CONC. H_2SO_4` Solution :`Cr_(2)O_(7)^(-2) + SO_(2) rarr UNDERSET("(green)")(Cr_2(SO_4)_3` `Cr_2O_7^(-2) + FE^(+2) rarr Cr^(+3) +Fe^(+3)`

Discussion

85341.	Acidified K_2Cr_2O_7 on oxidation by H_2O_2 gives:
Answer» BLUE SOLUTION `CrO_5` CHROMIUM peroxide All of these Answer :D

Discussion

85342.	AgNO_(3) overset(Delta)(to)(W)+(X)+O_(2) (X)+H_(2)O to HNO_(2)+HNO_(3) (W)+HNO_(3) to Y+NO+H_(2)O (Y)+Na_(2)S_(2)O_(3)("excess") to (Z)+NaNO_(3) Identify (W) to (Z).
Answer» `W=AG, X=N_(2)O,Y=AgNO_(3),Z=Na_(2)[Ag(S_(2)O_(3))_(2)]` `W=Ag_(2)O, X=NO,Y=AgNO_(3),Z=Na_(3)[Ag(S_(2)O_(3))_(2)]` `W=Ag, X=NO_(2),Y=AgNO_(3),Z=Na_(3)[Ag(S_(2)O_(3))_(2)]` `W=Ag_(2)O, X=N_(2),Y=AgNO_(3),Z=NA[Ag(S_(2)O_(3))_(2)]` Solution :`Na_(2)[overset(II)(FE)(NO)(CN)_(5)]+Na_(2)S to Na[overset(II)(Fe)(CN)_(5)(NOS)]`

Discussion

85343.	Acidified iodates are reduced to…..by SO_2
Answer» Iodites Iodide Iodine None Answer :C

Discussion

85344.	AgNO_(3) solution can't be stored in copper vessels, because. . . .
Answer» `E_(Ag^(+)\|Ag)^(Theta) gt E_(Cu^(2+)\|Cu)^(Theta)` `E_(Ag^(+)\|Ag)^(Theta) lt E_(Cu^(2+)\|Cu)^(Theta)` `E_(Ag^(+)\|Ag)^(Theta) ne E_(Cu^(2+)\|Cu)^(Theta)` Ag is precious metal. SOLUTION :Following reaction occur and `Cu^(2+)` ions are formed in solution. `2AgNO_(3)+Cu_((S)) to Ag_((S)) +Cu_((aq))^(2+)+2NO_(3(aq))^(-)` `E_(Ag^(+)\|Ag)^(Theta)=0.80V, E_(Cu^(2+)\|Cu)^(Theta)=0.34V` So, reduction of `Ag^(+)` occur. And `Ag^(+)` is oxidizing AGENT. oxidation of `Cu^(2+)` occur and reaction occur for those WHOSE `E_(cell)^(Theta)` is LESS.

Discussion

85345.	Acidification results in cleavage of bond at___carbon.
Answer» ANSWER :2

Discussion

85346.	AgNO_3 gives yellow ppt. with:
Answer» `KIO_3` KI `CHI_3` `CH_2I_2` ANSWER :B

Discussion

85347.	AgNO_(3) gives yellow ppt with
Answer» `KIO_(3)` KI `CHI_(3)` `CH_(2)I_(2)` Answer :B

Discussion

85348.	AgNO_(3) gives red precipitate with
Answer» Nal KCI `NaNO_(3)` `Na_(2)CrO_(4)` Answer :D

Discussion

85349.	Acidifed K_(2)Cr_(2)O_(7) oxidises H_(2)S to :
Answer» `SO_(2)` `SO_(3)` S `H_(2)SO_(4) + S` Solution :`3H_(2)S + Cr_(2)O_(7)^(2-) + 8H^(+) to 2Cr^(3+) + 3S + 7H_(2)O`

Discussion

85350.	AgNO_(3) gives a red ppt. with
Answer» `KI` `NABR` `NaNO_(3)` `K_(2)CrO_(4)` Solution :`2AgNO_(3)+K_(2)CrO_(4)rarrunderset("(Red)")(Ag_(2)CrO_(4))+2KNO_(3)`

Discussion

Explore topic-wise InterviewSolutions in .

Acidified solution of chromic acid on treatment with H_(2)O_(2) gives blue colour which is due to

AlF_(3) is soluble in HF only in the presence of KF. It is due to the formation of

Acidified sodium fusion extract on addition of ferric chloride solution gives blood red colouration which confirms the presence of

AIF_(3)is soluble in HF only in presence of KF . It is dueto the formation of

[A]:If the activation energy of reaction is zero then the rate of reaction does not depend on temperature. [R]:If the activation energy is less then the rate of reactio is more.

Acidified potassium permanganate solution is decolourised by

AIF_(3) ionic while AlCl_(3) is covalent .

Acidified potassium dichromate is treated with hydrogen sulphide, IN this reaction, the oxidation number of chormium :

AI_(2)O_(3)is reduced by electrolysisat lowpotentials and high current if 4.0xx10^(4)amperes of curretnis passed through molten AI_(2)O_(3)for 6h what mass of aluminimum is produced ? (Assume 100% currentaluminimumatomicweightof AI=27)

(a) (i) CalculatepHof 10^(-7) M HCI, (ii)Definecorrosion .Giveoneexample. (b)What isadsorptionisotherm Explain aboutFreundlichadsorptionisotherm.

Acidified potassium dichromate is treated with hydrogen sulphide.In the reaction the oxidation number of chromium :

(a)How will you distinguish between Pentan2-one and Pentan-3-one with the help of Iodoform test? (b) How will you bring about following conversions ? (I) Benzoic acid to m-Nitrobenzyl alcohol. (II) Benzaldehyde to Benzophenone. (iii) Benzoic acid to Benzamide.

(a)How does Primary amine undergoes carbyl amine reaction? Give chemical equation.(b) How is aniline is prepared by Hoffmann bromamide degradation reaction? Give equation.(c) Write the general formula of diazonium salt.

Acidified permanganate solution does not oxidise:

Acidified KMnO_(4) solution is decolourized by

Alcohols are isomeric with

(a)Haematite-Gravity separation process (b)Copper pyrite-Froth floatation (c )Bauxite-Leaching process (d)Pyrolusite-Magnetic separation process

A_((g))toB_((g)) is a first order reaction. The initial concentration of A is 0.2 mol. "lit"^(-1). After 10 minutes the concentration of B is found to be 0.18"mol. lit"^(-1). The rate constant ("in min"^(-1)) for the reaction is

Ag_((s))|AgBr_((s))|Br^(-)(0.011M)||Cl^(-)(0.2M)|AgCl_((s))|Ag_((s)) if K_(sp) of AgBr & AgCl at 25^(@)C are 10^(-12) & 10^(10) respectively find which is/are true for above cell at 25^(@)C(log2=0.3)

Acidified KMnO_4 oxidizes nitrites to

Ag(s)|Ag^(+)(aq)(0.01M)||Ag^(+)(aq)(0.1M)|Ag(s)E^(@)|Ag(s)Ag_((aq))^(@)=0.80 volt

Ag_((s))|Ag_((aq))^(+)(0.01M)||Ag_((aq))^(+)(0.1M)|Ag_((s))E_(Ag_((s))//Ag_((aq)))^(@)=0.80volt

Acidified KMnO_4 is decolourised by:

Acidified KMnO_(4) is a very strong oxidising agent. Prove it.

Acidified K_2Cr_2O_7 solution turns green when Na_2SO_3 is added to it. This is due to the formation of

Find out the incorrect pair(a)Gold ore-Cyanide leaching (b)Nickel ore-Ammonia leaching ( c)Aluminium ore-Alkali leaching (d)silver ore-Acid leaching

Acidified KMnO_(4) can be decolourised by (a)_____.

AgO actually exists as Ag[AgO_(2)], which is diamagnetic in nature. Then which of the following statements is true regarding AgO?

By passing Na_2SO_(3) to the solution of K_(2)Cr_(2)O_(7), it turns green due to the formation of

Acidified K_(2)Cr_(2)O_(7) turns green by

AgOH solution was neutralized using HNO_(3)solution. If pH of the solution at 50% neutralization point is 8 at 25^(@)C, then pK_(b)of AgOH is:

AgO in Ag(II) complex is

Acidified K_2Cr_2O_7 solution turns green by:

AgNO_(3)given white ppthypo changing to blackofter sometime .Black ppt is of

Acidified K_(2)Cr_(2)O_(7) reacts with H_(2)O_(7) to give "…............." coloure due to the formation of "…...................".

AgNO_(3(aq) was added to an aqueous KCl solution gradully and the conductivity of the solution was measured. The plot of conductance (Lambda) versus the volume of AgNO_(3) is

Acidified K_2 Cr_2 O_7 turns green by

AgNO_(3(aq)) was added to an aqueous KCl solution gradually and the conductivity of the solution was measured. The plot of conductance A versus the volume of AgNO_3 is

Acidified K_2Cr_2O_7 changes to green on reactions with

Acidified K_2Cr_2O_7 on oxidation by H_2O_2 gives:

AgNO_(3) overset(Delta)(to)(W)+(X)+O_(2) (X)+H_(2)O to HNO_(2)+HNO_(3) (W)+HNO_(3) to Y+NO+H_(2)O (Y)+Na_(2)S_(2)O_(3)("excess") to (Z)+NaNO_(3) Identify (W) to (Z).

Acidified iodates are reduced to…..by SO_2

AgNO_(3) solution can't be stored in copper vessels, because. . . .

Acidification results in cleavage of bond at___carbon.

AgNO_3 gives yellow ppt. with:

AgNO_(3) gives yellow ppt with

AgNO_(3) gives red precipitate with

Acidifed K_(2)Cr_(2)O_(7) oxidises H_(2)S to :

AgNO_(3) gives a red ppt. with