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86051.

According to modern periodic law , the chemical properties of elements are the periodic functions of there :

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Density
Atomic number
Mass number
Atomic mass

Answer :B
86052.

According to MO theory, which of the following statements about the magnetic character and bond order is correct regarding O_(2)^(+).

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1. Paramagnetic and bond ORDER `LT O_(2)`
2. Paramagnetic and bond order `GT O_(2)`
3. Diamagnetic and bond order `lt O_(2)`
4. Diamagnetic and bond order `gt O_(2)`

Answer :B
86053.

According to MO theory, O_(2)^(+) possesses :

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bond order of 2.5
three UNPAIRED ELECTRONS
diamagnetic CHARACTER
stability lower than `O_(2)`

Answer :A
86054.

According to Mendeleev's periodic law the properties of elements were the periodic function of :

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ATOMIC weight
Atomic number
Number of electron
None of these

Answer :A
86055.

According to Maxwell's distribution of molecular speeds, the following graph has been drawn for two different samples of gases A and B at temperature T_1 and T_2 respectively.Then, give the correct set of INCORRECT statements : Report your answer as sum of the numbers of incorrect statements. For examples, if statements (1) and (2) are incorrect, then report answer as (1+2)=3

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Solution :At constant TEMPERATURE , decreases in molecular mass causes flatterning of the GRAPH.For same molecular mass of GAS, increase in temperature causes FLATTENING of the graph.
From the above graph,
`(V_(mp))_(T_1)lt(V_(mp))_(T_2):. T_1/M_AltT_2/M_B:. T_2/T_1gtM_B/M_A`
But, `M_B/M_A` may be less than or greater than 1.
`:.` Statements(1),(2)&(3) are wrong. `" " :.`Reported answer=1+2+3=6
86056.

According to Maxwell Boltzmann distribution of energy, ………………. .

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the FRACTION of MOLECULES with most probable kinetic energy DECREASES at higher TEMPERATURES
the fraction of molecules with most probable kinetic energy increases at higher temperatures
most probable kinetic energy increases at higher temperatures
most probable kinetic energy decreases at higher temperatures.

Answer :A::C
86057.

According to Maxwell ,Boltzmann distribution of energy………..

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the fraction of MOLECULES with most probable kinetic energy DECREASES at higher tempreratures.
the fration of molecules with most probable kinetic energy increases at higher temperatures.
Most probable kinetic energy increases at higher temperatures
most probable kinetic energy decreases at higher temperatures

Solution :
From the GRAPH it is clear,
(A)As the TEMPERATURE increases the fraction of molecule at given kinetic energy decreases and height of graph decreases.
(D)As the temperature increases the graph shift towards right SIDE and kinetic energy increases.
86058.

According to Lewis concept which one of the following is not a base

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`OH^(-)`
`H_(2)O`
`Ag^(+)`
`NH_(3)`

Solution :It is electron ACCEPTER so Lewis acid.
86059.

According to Lewis concept of acids and bases, ethers are

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NEUTRAL
acidic
basic
AMPHOTERIC

ANSWER :C
86060.

According to Lewis concept of acids and bases, ether is

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acidic
basic
neutral
amphoteric

Answer :B
86061.

Accodring to Lewis concept of acids and bases, ether is

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acidic
BASIC
NEUTRAL
AMPHOTERIC

Answer :B
86062.

According to Lewis concept, an acid is a substance which

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ACCEPTS protons
DONATES protons
Accepts a LONE pair of electrons
Donates a lone pair of electrons

Answer :C
86063.

According to Le-Chetelier's principle, the equlibrium constant of a reversible reaction will not shift by

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Increasing the temperature of an exothermic reaction
Increasing the temperature of an ENDOTHERMIC reaction
CHANGING the concentrations of the reactants
The EFFECT of catalyst

Answer :D
86064.

According to Le-chatelier's principle, which of the following factors influence a chemical system

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CONCENTRATION only
PRESSURE only
TEMPERATUER only
Concentration, pressure and TEMPERATUE

ANSWER :D
86065.

According to Le-chatelier's principle, an increase in the temperature of the following reaction will N_(2)+O_(2)hArr2NO-43,200 kcal

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INCREASE the YIELD of NO
Decrease the yield of NO
Not EFFECT the yield of NO
No help the reaction to PROCEED in forward direction

Solution :Being ENDOTHERMIC, the forward reaction is favoured by high temperature.
86066.

According to Le-Chatelier's Principle, the addition of temperature to the following reaction CO_(2(g))+2H_(2)O_(gas)toCH_(4(gas))+2O_(2(gas)) will cause it to the right. Thish reaction is therefore.

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EXOTHERMIC
UNIMOLECULAR
ENDOTHERMIC
Spontaneous

Answer :C
86067.

According to Le-Chatelier's principle adding heat to a solid and liquid in equlibrium with endothermic nature will cause the

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Temperature to rise
Temperature to fall
Amount of SOLID to decrease
Amount of LIQUID to decrease

SOLUTION :Solid + liquid `Harr` Solution `DeltaH=+ve` Increase in temperature favours forward reaction.
86068.

According to law of mass action, the rate of reaction is directly proportional to:

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volume of the container
equilibrium CONSTANT
NATURE of REACTANTS
molar concemtration of reactants

Answer :D
86069.

According to law of mass action rate of a chemical reaction is proportional to

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CONCENTRATION of REACTANTS
MOLAR concentration of reactants
Concentaation of PRODUCTS
Molar concentration of products

ANSWER :B
86070.

According to law of photochemical equivalence the energy absorbed (in ergs/mole) is a given as (h = 6.62 xx 10^(-27) ergs , c = 3 xx 10^(10) cm s^(-1) , N_(A) = 6.02 xx 10^(23) mol^(-1))

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`(1.196 xx 10^(4))/(LAMBDA)`
`(2.859 xx 10^(5))/(lambda)`
`(2.859 xx 10^(16))/(lambda)`
`(1.196 xx 10^(16))/(lambda)`

Solution :Acc., to stark EINSTEIN's law of photochemical EQUIVALENCE
`E= (hc)/(lambda) xx N_(A)`
` E = (6.62 xx 10^(-27) xx3 xx 10^(10) xx 6.02 xx 10^(23))/(lambda)`
`E= (1.196 xx 10^(8))/(lambda)` .
86071.

According to Langmuir adsorption isotherm, the amount of gas adsorbed at very high pressure:

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Reaches a CONSTANT limiting value
Goes on increasing with PRESSURE
Goes on decreasing with PRESSRUE
INCREASES first and decreases later with pressure

Answer :A
86072.

According to Langmuir adsorption isotherm the amount of gas adsorbed at very high pressure :

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Reaches a CONSTANT limiting value
Goes on increasing with pressure
Goes on DECREASING with pressure
Increases first and DECREASES LATER with pressure

Answer :A
86073.

According to Kohlrausch'a law, wedge_(m)^(@) for electrolyte A_(x)B_(y)=_____.

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SOLUTION :`wedge_(m)^(@)` for `A_(X)B_(y)=xlamda_(+)^(@)+ylamda_(-)^(@)`
86074.

According to Kohlrausch law, the limiting value of molar conductivity of an electrolyte A_2B is

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`lambda_(A^(+))^(OO) +lambda_(B^(-2))^(oo)`
`1/2 lambda_(A^(+))^(oo)+lambda_(B^(-2))^(oo)`
`2lambda_(A^(+))^(oo)+1/2 lambda_(B^(-2))^(oo)`
`2lambda_(A^(+))^(oo) +lambda_(B^(-2))^(oo)`

86075.

According to kinetic theory of gases, the incorrect statement is

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COLLISIONS of gas molecules are perfectly elastic
Particle of gas moves in all POSSIBLE directions in straight line
Gas molecules are considered as point masses
At a particular tamperature all molecules have same KINETIC energy

Answer :C
86076.

According to kinetic theory of gases, for a diatomic molecule

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The pressure exerted by the gas is proportional to the mean velocity of the MOLECULES
Thepressure exerted by the gas is proportional to the root mean SQUARE velocity of the molecules
The root mean square velocity is INVERSELY proportional to the temperature
The mean translational kinetic energy of the molecules is proportional to the absolute temperature.

Solution :All molecules of an ideal gas show random motion. They COLLIDE with each other and walls of container during which they lose or gain energy so they may not have same kinetic energy always.
86077.

According to kinetic theory of gases, a gas consists of a large number of discrete, .... And ...... parucles calied…

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Solution :(a) RATE of DIFFUSION of the gas `PROP sqrt((1)/(M)) and M_(N_(2)) gt M_(He) gt M_(H_(2))`
(b) 1:24
86078.

According to IUPAC system, CH_3 CH_2 CN is named as ...... while CH_3 CH_2Noverset(to )= C is named as .....

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SOLUTION :PROPANENITRILE, ETHYL ISOCYANIDE
86079.

According to IUPAC sodium nitroprusside is named as

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SODIUM pentacyanonitrosyl FERRATE(II)
Sodium pentacyanonitrosyl ferrate(III)
Sodium nitroferriccyanide
Sodium nitroferrocyanide

Answer :A
86080.

According to IUPAC nomenclature, sodium nitro prusside is named as:

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SODIUM nitro ferricyanide
sodium nitro ferrocyanide
sodium pentacyanonitrosyl ferrate (II)
sodium pentacyanonitrosyl ferrate (III)

SOLUTION :`Na_(2)[Fe(CN)_(5)NO]` is sodium pentacyanonitrosylferrate (III).
86081.

According to IUPAC nomenclature, sodium nitroprusside is named as

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Sodium nitroferricyanide
Sodium nitroferrocyanide
Sodium pentacyanonitrosylferrate (II)
Sodium pentacyano nitrosylferrate (III)

Solution :Sodium nitroprusside, `Na_(2)[Fe(CN)_(5)NO]`, is NAMED as sodium pentacyano nitrosyl FERRATE (III). In this compound, NO is present as `NO^(+)` and Fe has + 2 charge. On the basis of this, the actual name should be sodium pentacyanonitrosonium ferrate (II).
86082.

According to Huckel's rule, an aromatic compound is a ring compound, which contain _____ electrons.

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ANSWER :(4N + 2)PI
86083.

According to Huckel 's law, which is true?

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`(4n +2)PI` ELECTRONS
`(2N +4)pi` electrons
`(4n +4PI)` electrons
`(3n+3 pi)` electrons

Answer :A
86084.

According to Huckel rule, the aromatic compounds must have delocalised pi-electrons equal to (n is integer) :

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(4N + 1)
(4n + 2)
4n
(2n + 2)

Answer :B
86085.

According to Huckel, monocyclic compounds will show aromaticity when it has

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`4pi` ELECTRONS
`6PI` electrons
`4pi + 2` electrons
`(4n+2)PI` electrons

Answer :B, D
86086.

According to Henry's law, the plot of …………………versus………………..is linear with slope equal to ……………… .

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Solution :equilibrium pressure, mole FRACTION in the solution,Henry's CONSTANT `(K_(H))`.
86087.

According to Hess's law, the heat of reacftion depends upon

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initial condition of REACTANTS
initial and FINAL conditions of reactants
intermediate path of the reaction
end conditions of reactants

Solution :According to HESS's LAW, the heat of reactin depends UPON the initial and final condition of reactants.
86088.

According to Hess's law, the heat of reaction depends upon

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initial condition of reactants
initial and final condition of reactants
intermediate path of the reaction
end CONDITIONS of reactats

Solution :ACCORDING to HESS's LAW, the heat of reaction depends UPON the initial and final condition of reactants.
86089.

According to Henry's Law , the partial pressure of gas (P_(g)^(1)) is directly , propotional to molefraction of gas in dissolved state , i.e. , P_("gas")^(1)=K_(H).X_("gas"). Which are correct .

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`K_(H)` is charecteristic constant for a given gas solvent SYSTEM
Higher is the value of `K_(H)` LOWER is solubility of gas for a given partial pressure of gas
`K_(H)` has temperature dependence
`K_(H)` INCREASES with temperature

Answer :A::B::C::D
86090.

Accordingto Hardy - Schulzerule, whichif the followinghashighestflocculatingpower?

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`AI^(3+)`
`Ba^(2+)`
`NA^(+)`
NONEOF the above

ANSWER :A
86091.

According to Hardy- Schulze rule, the coagulating power of cation follows the order :

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`NA^(+)GTBA^(2+)gtAl^(3+)`
`AL^(3+)gtBa^(2+)gtNa^(+)`
`BA^(2+)gtAl^(3+)gtNa^(+)`
`Al^(2+)gtNa^(+)gtBa^(2+)`

Solution :More the change on CATION, higher the coagulating power.
86092.

According to hard and soft acid base principle, a hard acid

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Has low charge density
Shows preference for soft BASES
Shows preference for DONOR ATOMS of low electronegativity
Is not polarizable

Solution :A hard ACID shows preference for soft bases and vice-versa.
86093.

According to Graham's law at a given temperature the ratio of the rates of diffusion r_(A)//r_(B) of gases A and B is given by

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<P>`(p_(A)/p_(B))(M_(A)/M_(B))^(1/2)`
`(M_(A)/M_(B))(p_(A)/p_(B))^(1/2)`
`(p_(A)/p_(B))(M_(B)/M_(A))^(1/2)`
`(M_(A)/M_(B))(p_(B)/p_(A))^(1/2)`

ANSWER :C
86094.

According to Graham's law at a given temperature the ratio of the rates of diffusionr_(A) //r_(B) of gases A and B is given by

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<P>`( P_(A) //P_(B)) ( M_(A) //M_(B))^(1//2)`
`(M_(A) //M_(B) )(P_(A) //P_(B))^(1//2)`
`(P_(A) //P_(B)) ( M_(B) //M_(A))^(1//2)`
`(M_(A) //M_(B)) ( P _(B)//P_(A))^(1//2)`

ANSWER :C
86095.

According to Freundlich adsorption isotherm, which of the following is correct?

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<P>`x/m prop P^o`
`x/m prop P^'`
`x/m prop P^(1//n)`
All of the above are CORRECT for different ranges of PRESSURE

Answer :D
86096.

According to Freundlich adsorption isotherm, which of the following is correct ?

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`x/m PROP p^(@)`
`x/mprop p^(1)`
`x/mprop p^(1//n)`
All the above are correct for different ranges of pressure

Solution :All the given EXPESSION are correct for different ranges of pressure.
86097.

According to Freundlich adsorption isotherm, the adsorption at low pressure is proporational to:

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P
`1//P`
`P^(@)`
`P ^(n),` (where `n =0` to 1).

Solution :Frendlich adsorption ISOTHERM is
`(x)/(m) = kP ^(1//n)`
At low pressure, the graph of `(x)/(m) vs P` is almost STRAIGHT LINE which indicates that `x/m` is directly proportional to pressure.
`(x)/(m) PROP P or (x)/(m) = kP`
86098.

According to Freundlich adsorption isotherm,

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<P>`x/m = K p`
`m/x = (KP)^(1/n)`
`x/m = kp^(1/n)`
`x/m = (k)/(p^(1/n))`

ANSWER :C
86099.

According to Fajan's rules, ionic bonds are formed when

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cations have low positive CHARGE, large size and anions have large size
catios have low positive charge and SMALL size
cations have high positive charge and lareg size
cations have low positive charge, large size and anions have small size

Solution :For greater ionic character of the bond, the cation should have low polarising POWER and the ANION should have small polarisability.
86100.

According to Faradays's first law m = ZIt, where Z is

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REACTION quotient
effective NUCLEAR charge
atomic number
electrochemical equivalent

Answer :D