94420 + Interview Questions in Chemistry in Class 12 Page 1723 InterviewSolution

86101.	According to Faraday's laws of electrolysis, the discharge of one electrochemical equivalent of ions should involve
Answer» 1 mole of ELECTRONS 96500 MOLES of electrons `1/(96500)` mole of electrons none of these Answer :C

Discussion

86102.	According to Faraday's first Law of electrolysis mass of substance liberated is equal to
Answer» eC eQ et eCt/nF Answer :B

Discussion

86103.	According to Fajan's rule polarisationis more when:
Answer» SMALL CATION and LARGE anion Small cation and small anion Large cation and large anion Large cation and small anion Answer :A

Discussion

86104.	According to Ellingham diagram, the oxidation reaction of carbon to carbon monoxide may be used to reduce which one of the following oxides at the lowest temperature ?
Answer» `Al_(2)O_(3)` `Cu_(2)O` `MgO` `ZnO` Solution :In the graph of `Delta_(r ) G^(@)` vs T for formation of oxides, the `Cu_(2)O` line is almost at the top. So, it is quite EASY to REDUCE oxide ORES of copper directly to the metal by heating with coke both the lines of C, CO and `C, CO_(2)` are at much lower temperature (500-600)K. `Cu_(2)O+C to 2Cu+CO`

Discussion

86105.	According to Ellingham diagram, the oxidation reaction on the carbon to carbon monoxide may be used to reduce which one of the following oxides at the lowest temperature ?
Answer» `Al_2O_3` `Cu_2O` `MGO` `ZNO` ANSWER :B

Discussion

86106.	According to Ellingham diagram , the oxidation reaction of carbon to carbon monoxide may be used to reduce which one of the following oxides at lowest temperature ?
Answer» `Al_2O_3` `Cu_2O` `MGO` ZnO Answer :B

Discussion

86107.	Accordingto Ellingham diagram,theoxidationreactionofcarbontocarbonmonoxidemaybe used toreducewhichone ofthefollowingoxides atthelowesttermperature ?
Answer» ` Al_ 2O _ 3` ` Cu_ 2 O` `MGO ` `ZNO ` Solution :The GRAPHOF` Delta _f G^(@) ` vsT intheEllinghamdiagramshows that` Cu-Cu_2 O`lineis atmostat the top (i.e.,muchhigherthanthose of` AL - Al_ 2 O_ 3 ,Mg- Mg O , Zn - ZnOand Fe- FeO`lines ).Therefore, ` Cu_ 2 O` canbereducedto Cuatthelowest temperature.

Discussion

86108.	According to Ellingham diagram Cr_(2)O_(3) reduced by
Answer» Al Cu Mg Zn ANSWER :A

Discussion

86109.	According to electromagnetic theory of radiation s in photo electric effect which of these statement is incorrect ?
Answer» only those radiations will be ABLE to emit electrtrons from the metal surface WHOSE frequaency is greater than threshold FREQUENCY all the radiations will be able to emit electron form the metal surface there should be no time GAPBETWEEN absorption of photon and EMISSION of electron higher the frequency of incidentradiation morewill be the kineticenergy associatedwith the electron Answer :B

Discussion

86110.	According to electrochemical theory the metal which rusting take place as a result of
Answer» HYDROLYSIS LOCAL action ELECTROLYSIS none Solution :ACCORDING to ELECTROCHEMICAL theory corrosion as a result of local action .

Discussion

86111.	According to electrochemical mechlanism for corrosion, the metal undergoing corrosion acts as
Answer» cathode anode neither anode nor cathode either anode or cathode depending upon its standard electrode potential Solution :The anode reaction in corrosion is the oxidation of the metal. This process forms metal ions that dissolve in the non-conducting medium, the atomspheric moisture in contect with the metal surface. For example, in the rusting of iron, the oxidation is `Fe(s) rarr Fe^(2+)(aq.)+2e^(-)` We can predict that active metals, which are low oin the `emf` series, should be most susceptible to corrosion. Cesium `(Cs)` and rubidium `(Rb)`, whicha re toward the bottom of the `emf` series, corrode very quickly in MOIST air. Other metals near the bottom of the `emf` seriesusually are STORED away from air, to prevent the swift corrosion that occurs when they come in contact with the atmosphere for any period of time. However, there are exceptions to this role as some active metals like `Al` corrode quite slowly because they form protective oxide conatings. Given an oxidation, there must be a reduction to consume the ELECTRONS released in the anode process. Some of the importment cathode, or reduction, half-reaction in corrosion are `2H^(+)(aq.)+2e^(-) rarr H_(2)(g) ["acid solution"]` `O_(2)(g)+4H^(+)(aq.)+4e^(-) rarr 2H_(2)O(l) ["acid solution"]` `O_(2)(g)+2H_(2)O(l)+4e^(-) rarr 4OH^(-)(aq.) ["neutral or alkaline solution"]` The standard potential of the half-reations in which dissolved `O_(2)` is reeduced are positive,so these reduction are more favorable than those involving `H^(+)` or `H_(2)O` alone. Metals corrode faster aat higher partial pressures of oxygen. because more `O_(2)` then dissolves into the layer of moisture that is in contact with the metal. There is an interesting aspect of corrosion called the principle of differential aeration: If a part of a metal surface is exposed to a relatively high concentration of `O_(2)`, corrosion occurs in anothr region of the metal. The potential DIFFERENCE that leads to corrosion requires the physical separation of the oxidation and reduction process in corrosion, which is the reduction of `O_(2)`, occurs in the region where the concentration of `O_(2)` is highest. Therefore the oxidation half-reaction which does the real damage, takes place elsewhere. In case of iron, the `Fe^(2+)` cations tht form migrate toward the cathodic regions of the metal surface. There they react with water or `OH^(-)` to form `Fe(OH)_(2)`, which undergoes further oxidation to form `Fe(OH)_(3)`, the familiar reddis material called rust. Menshile, the anodic region of the metal surface undergoes the real damage: Holes appear, the surface is eaten away, and the metal's structural strength is wakened. The worst damage seems to occur when the reduction process liberates `H_(2)(g)`, apparently because this gas penetrates below the surface and further weakens the metal. The corrosion of an automoblie a familiar demonstration of the principle of differential aeration. When some of the paint that protects the metal of the automobile chips off, corrosion does not occur at the site of the chipping, Rust does form at this spot, becuase it is the place where the reduction half-reaction occurs. The real damage is done at the anode region, which is a site near the exposed area. We can also demonstrate corrosion by differential aeration by embeddingmetal rods in sand, leaving the upper part of the rods in water. It is the segment of the rod in the sand that corrodes, not the segment in the water. The sand prevents corrodes, not the segment in the water. The sand prevents `O_(2)` from REACHING the metal. The reducing occurs in the oxygen-rich water while the damaging oxidation process occurs in the sand. A metal can corrode if the potential of the half-reaction for its oxidation is relatively more positive than any other oxidation that can occur when it is exposed is the basis of several methods for preventing corrosion.

Discussion

86112.	According to Dulong and Petit's rule, in case of solid elements. Approximate atomic mass =(6.4)/("specific heat") In this rule, specific heat is in
Answer» `KJ kg^(-1)K^(-1)` `cal g^(-1)K^(-1)` `JG^(-1).^(@)C^(-1)` None of these Solution :In Dulong and Petit's RULE the SPECIFIC heat is expressed in cal `g^(-1) K^(-1)` or cal `g^(-1)C^(-1)`.

Discussion

86113.	According to Debye-Huckel-Onsager equation,wedge_(m)^(c)=_____.
Answer» SOLUTION :`wedge_(m)^(C)=wedge_(m)^(@)-Asqrt(c)`

Discussion

86114.	According to de Broglie, matter has a wave character. still we cannot measure the wavelength of even 1 mg mass. It is because:
Answer» actually it does not have a wave CHARACTER WAVELENGTH of PARTICLE cannot be measured the diffraction GRATING required to measure it will be IMPOSSIBLY small it can be measured Answer :C

Discussion

86115.	According to cystal field theory, interaction between central metal atom/ion and ligand is electrostatic in nature. In free metal ions, the five d-orbitals are degenerate. However, in a ligand field e.g., tetrahedral, octahedral, square planar, square pyramidal, trigonal bipyramidal, the degeneracy of 5d-orbitals is lost. If lobes of d-orbitals of central metal atom/ion are along the axes through which ligands are approaching, the energy of corresponding d-orbital is raised more than the d-orbitals having lobes between teh axes. e.g., octahedral complexes, square planar complexes, square pyramidal compexes. The correct order Delta_(o), Delta_(t)" and "Delta_(sp) (where o, t and sp stand for octahedral, tetrahedral and square planar fileds respectively) is :
Answer» `Delta_(o) gt Delta_(SP) gt Delta_(t)` `Delta_(sp) gt Delta_(o) gtDelta_(t)` `Delta_(sp) gtDelta_(t) gt Delta_(o) ` `Delta_(o)gt Delta_(t) gtDelta_(sp)` SOLUTION :`Delta_(t)=(4)/(9)Delta_(0),Delta_(sp)=1.3Delta_(0)impliesDelta_(sp) gt Delta_(0) gt Delta_(t)`

Discussion

86116.	According to cystal field theory, interaction between central metal atom/ion and ligand is electrostatic in nature. In free metal ions, the five d-orbitals are degenerate. However, in a ligand field e.g., tetrahedral, octahedral, square planar, square pyramidal, trigonal bipyramidal, the degeneracy of 5d-orbitals is lost. If lobes of d-orbitals of central metal atom/ion are along the axes through which ligands are approaching, the energy of corresponding d-orbital is raised more than the d-orbitals having lobes between teh axes. e.g., octahedral complexes, square planar complexes, square pyramidal compexes. Which of the following orbitals has the highest energy in square pyramidal ligand field ?
Answer» `d_(xy)` `d_(z^(2))` `d_(x^(2)-y^(2))` `d_(yz), d(zx)` SOLUTION :`Delta_(t)=(4)/(9)Delta_(0),Delta_(sp)=1.3Delta_(0)impliesDelta_(sp) GT Delta_(0) gt Delta_(t)`

Discussion

86117.	According to crystal field theory, the M-L bond in a complex is
Answer» PURELY ionic purely coordinate purely covalent partially covalent Solution :ACCORDING to crystal FIELD THEORY, the bonding in a complex is purely electrostatic or ionic

Discussion

86118.	According to crystal field theory ,The bond between the ligand and central metal atom is __________
Answer» Purely IONIC Purely COVALENT Coordinate 50 % ionic and 50 % covalent ANSWER :A

Discussion

86119.	According to crystal field theory (CFT) :
Answer» order of increasing field strength of LIGANDS is : `F^(-)gtH_(2)OgtNH_(3)` If pairing energy exceeds the MAGNITUDE of crystal field splitting then pairing occurs `d^(4)` to `d^(7)` co-ordination entities are more stable for strong field as compared to weak field cases Tetrahedral complexes have sufficiently LARGE splitting energy to force pairing and therefore, high SPIN configuration are rarely observed. Answer :C

Discussion

86120.	According to combined gas law.
Answer» <P>`PV PROP ( 1)/( V ) ` `( p )/( T ) prop V` `pV prop T` `( V )/( T)prop p ` ANSWER :C

Discussion

86121.	According to collision thery
Answer» collisions are sufficiently violent all collisions are responsible for reaction all collisions are effective only HIGHLY energetic molecules have ENOUGH ENERGY to REACT Solution :Only those collisions are effective collisions which are energetic enough and cross over the threshould energy level.

Discussion

86122.	According to collisiontheory Rate=P.Z_(AB)e^(-Ea)/(RT) What does P indicate in the equation ?
Answer» pressure Collision frequency Arrhenius contant Probability factor Answer :D

Discussion

86123.	According to collision theory of reaction rates
Answer» every collision between reactans leads to CHEMICAL reaction rate of reaction is proportional to velocity of molecules all reactions which OCCUR in GASEOUS phase are zero ORDER reactions rate of reaction is directly proportional to collision frequency Solution :The INCREASE in collision frequency bring in an increase in effective collision and thus rate of reaction increases.

Discussion

86124.	According to collision theory for determiningthe variation of rate of reaction with temperature the rate constant,k= Ae^(-Ea//RT). For most of the practical purposes A and E_(a[Arrhenius factor and Activation energy] are temperature independent. However they may vary slightly. Assuming the conditions given above answer the following questions. "If"A=K,T"and"E_(a)=K_(2)T^(2) and the given equation is still applicable where K_(1)"and" K_(2) are the constant and T represent temperature then which will be correct option? (P) The maximum value of k will be equal to A (Q) At lower temperature rate of reaction will increase with increase in temperature (R) At higher temperature, rate of reaction will decrease with increase in temperature
Answer» <P>All are true Only Q and R are incorrect Only P is incorrect Only P and Q are incorrect Answer :C

Discussion

86125.	According to collision theory of reaction rates, the activation energy is
Answer» the energy GAINED by the molecule on COLLIDING with other molecules. the energy that molecule should POSSESS in order to UNDERGO reaction the energy it should possess so that it can enter into an effective collision the energy it has to ACQUIRE so that it can enter into an effective collision. Answer :D

Discussion

86126.	According to collision theory:
Answer» Collisions are sufficiently violent All COLLISION are responsible for reaction All collisions are effective Only HIGHLY energies MOLECULES have enough ENERGY to react Answer :D

Discussion

86127.	According to collision theory,
Answer» collisions are sufficiently violent all collisions are responsible for reaction all collisions are EFFECTIVE only highly energetic molecules have ENOUGH energy to react. Solution :Only those collisions are effective collisions which are energetic enough and CROSS over the threshold energy level.

Discussion

86128.	According to classification of aminoacids, lysine belongs to the following
Answer» ACIDIC AMINO acid Basic amino acid Neutral amino acid Non-essential amino acid Answer :B

Discussion

86129.	According to CIP rule, the correct arrangment in order of decreasing priority is :-
Answer» `–OH GT –CH_(2)OH gt –CHO gt –COOH ` `–OH gt –COOH gt –CHO gt –CH_2OH ` `–COOH gt –OH gt –CHO gt –CH_(2)OH ` `–COOH gt –CHO gt –CH_(2)OH gt –OH` ANSWER :D

Discussion

86130.	According to Charles's law :
Answer» `((DV)/(DT))_P = K` `((DV)/(DT))_P = -K` `((DV)/(DT))_P= -K/T` NONE of these Answer :A

Discussion

86131.	According to, Charle's law
Answer» <P>`(dV/dT)_(P)=K` `(dV/dT)_(P)=-K` `(dV/dT)_(P)=-K//T` `V PROP T` ANSWER :A::D

Discussion

86132.	According to Charles' law, at constant pressure 100ml of a given mass of a gas with 10^(@)C rise in temperature will become( ( 1)/( 273) = 0.00366)
Answer» 1.100.0366 2.99.9634 3.103.66 4.100.366 Solution :`V_(t) = V_(0) + V_(0) XX 10 xx 0.0036` `= 100 + 100 xx 10 xx 0.0036` `= 103.66`

Discussion

86133.	According to Charle's law
Answer» `((DV)/(dT))_(P)=K` `((dV)/(dT))_(P)=-K` `((dV)/(dT))_(P)=-(K)/(T)` NONE of the above Answer :D

Discussion

86134.	According to C.F.T, attraction between the central metal ion and ligands in a complex is purely electrostatic. The transition metal which forms the central atom cation in the complex is regarded as a positive ion. It is surrounded by negative ligands or neutral molecules which have a lone apir of electrons, if the ligand is a neutral molecule such as NH_(3), the negative and of the dipole in the molecule is directed towards the metal cation. the electrons on the central metal ion are under repulsive forces from those on the ligands. thus the electrons occupy the d-orbitals remain away from the direction of approach ligands. Q. The value of 'x' in the complex H_(x)[Co(CO)_(4)] (on the basis of EAN rule), and geometry arround Co ion respectively is:
Answer» 1, SQUARE planar 2, tetrahedral 1, tetrahedral 2, square planar Answer :C

Discussion

86135.	According to C.F.T, attraction between the central metal ion and ligands in a complex is purely electrostatic. The transition metal which forms the central atom cation in the complex is regarded as a positive ion. It is surrounded by negative ligands or neutral molecules which have a lone apir of electrons, if the ligand is a neutral molecule such as NH_(3), the negative and of the dipole in the molecule is directed towards the metal cation. the electrons on the central metal ion are under repulsive forces from those on the ligands. thus the electrons occupy the d-orbitals remain away from the direction of approach ligands. Q. The crystal field-spliting order for Cr^(3+) cation is octahedral field for ligands CH_(3)COO^(-),NH_(3),H_(2)O,CN^(-) is:
Answer» `CH_(3)COO^(-) LT H_(2)O lt NH_(3) lt CN^(-)` `CH_(3)COO^(-) lt NH_(3) lt H_(2)O lt CN^(-)` `H_(2)O lt CH_(3)COO^(-) lt NH_(3) lt CN^(-)` `NH_(3) lt CH_(3)COO^(-) lt H_(2)O lt CN^(-)` ANSWER :A

Discussion

86136.	According to C.F.T, attraction between the central metal ion and ligands in a complex is purely electrostatic. The transition metal which forms the central atom cation in the complex is regarded as a positive ion. It is surrounded by negative ligands or neutral molecules which have a lone apir of electrons, if the ligand is a neutral molecule such as NH_(3), the negative and of the dipole in the molecule is directed towards the metal cation. the electrons on the central metal ion are under repulsive forces from those on the ligands. thus the electrons occupy the d-orbitals remain away from the direction of approach ligands. Q. Correct relationship between pairing energy (P) and C.F.S.E. (Delta_(o)) in
Answer» <P>`Delta_(o) LT P` `Delta_(o) lt P` `Delta_(o)=P` cannot comment Answer :B

Discussion

86137.	According to CFT the energy of t_(2g) orbitals in an octahedral complex
Answer» DECREASE by `2/5Delta_0` INCREASE by `2/5 Delta_0` increase by `3/5 Delta_0` decrease by `3/5 Delta_0` ANSWER :A

Discussion

86138.	According to bronstedconcept, the acids in the reaction : NH_3+H_2O=NH_4+OH^- are:
Answer» `NH_3` and `NH_4^+` `H_2O` and`OH^-` `H_2` and `NH_4^+` `NH_3` and `OH^-` ANSWER :B

Discussion

86139.	According to Bronsted principle, an aqueous solution of HNO_(3) will contain
Answer» `NO_(2)^(-)` `NO_(3)^(-)` `NO_(2)^(+)` `NO^(+)` Solution :ACCORDING to Bronsted PRINCIPLE `HNO_(3)` is acid they give `H^(+)` in aqueous solution and FORM `NO_(3)^(-)`.

Discussion

86140.	According to Bronsted-Lowry concept, the correct order of relative strength of bases follows the order
Answer» `CH_(3)COO^(-) gt Cl^(-) lt OH^(-)` `CH_(3)COO^(-) gt OH^(-) gt Cl^(-)` `OH^(-) gt CH_(3)COO^(-) gt Cl^(-)` `OH^(-) gt Cl^(-) gt CH_(3)COO^(-)` SOLUTION :Relative of bases can be shown by their CONJUGATE acids. Conjugate acid or `OH^(-)` is `H_(2)O` which is a weak acid conjugate acid of `CH_(3)COO^(-)` is `CH_(3)COOH` which is stronger than `H_(2)O`. While conjugate acid of `Cl^(-)` is HCL which is strongest out of there. so the order of relative strength of bases is `OH^(-) gt CH_(3)COO^(-) gt Cl^(-)`.

Discussion

86141.	According to Bronsted lowry, water is a/an
Answer» Base Acid Acid and base both Salt Solution :Because it gain and also lose the PROTON `H_(2) + H_(2) RARR H_(3)O^(+) + OH^(-)`.

Discussion

86142.	According to Bronsted-Lowry concept, base is a substance which is
Answer» A PROTON donor An ELECTRON PAIR acceptor A proton acceptor An electron pair donor Answer :C

Discussion

86143.	According to Bohr's theory the radius of electron in an orbit described by principal quantum number n and atomic number Z is proportional to:
Answer» `Z^2n^2` `Z^2/n^2` `Z^2/n` `n^2/Z` ANSWER :D

Discussion

86144.	According to Bohr's theory the energy required for the transition of H atom from n=6 to n=8 state is
Answer» equal to the energy required for the transition from N=5 to n=7 state larger than in (A) less than in (A) equal to the energy required for the transition from n=7 to n=9 state. Solution :As the VALUE of n INCREASES, the DIFFERENCES between the energy shells DECREASE.

Discussion

86145.	According to Bohr's theory, the angular momentum of an electron is 5 th orbit is
Answer» `1.0 h//pi` `10 h//pi` `2.5 h//pi` `25h//pi` Solution :ANGULAR MOMENTUM in NTH orbit `=(nh)/(2pi)` `:.` Angular momentum in 5TH orbit `=(5h)/(2pi)` `=2.5h//pi`

Discussion

86146.	According to Bohr's theory, the angular momentum for an electron of 5th orbit is
Answer» `10h//pi` `5h//2pi` `25h//pi` `5pi//2h` SOLUTION :ANGULAR momentum `mvr=n H/(2pi)=(5h)/(2pi)`

Discussion

86147.	According to Bohr's theory E_(n) =Total energy K_(n) =Kinetic energy V_(n) =Potential energyr_(n) = Radius of nth orbit Match the following : Column -IColumn -II (A)V_(n) //K_(n ) = ?( p ) 0 (B ) If radius of nth orbit propEn^(x) , x = ?( q)-1 ( C ) Angular momentum in lowest orbital ( r ) - 1 (D )( 1)/( r^(n)) prop Z^(4) , y = ?( s ) 1
Answer» Answer :`( A rarr s), ( B rarr R ) , ( C rarr p ), ( D rarr Q ) `

Discussion

86148.	According to Bohr's theory,
Answer» when the atom gets the REQUIRED energy from the outside, electrons JUMP from LOWER orbits to higher orbits and remain there when the atom gets the required energy from outside, electrons jump from lower orbits to higher orbits and remain there for very short intervals of TIME and return back to the lower orbit, radiating energy. angular momentum of the electron is proportional to its quantum number angular momentum of the electron is independent of its quantum number. Solution :Angular momentum=`nh/(2pi)`

Discussion

86149.	According to BIS, what is the per centage of TFM in bath Soap of grade - 3?
Answer» more than 65% but LESS than `76%` more than `56%` but less than `60%` more than `60%` but less than `65%` `76%` or more Answer :C

Discussion

86150.	According to Bayer's strain theory which is highly stable?
Answer» Cyclobutane Cyclopentane Cycloheptane Cyclohexane Solution :BAYER's strain theory - The amount of strain is directly proportional to the angle through which a VALENCY bond has deviated from its normal position i.e. Amount of deviation (d). `d = (1)/(2)(109^(@)28'` - valency angle) In cyclobutane , `d = (1)/(2) (109^(@)28' - 90^(@)) = 9^(@)44'` In cyclopentane , `d = (1)/(2) (109^(@)28' - 108^(@)) = 0^(@)44'` In cyclohexane, `d = (1)/(2) (109^(@)28' - 120^(@)) = -5^(@)16'` In cycloheptane , `d = (1)/(2) (109^(@)28' - 135^(@)) = -9^(@)33'` Cyclopentane is more stable and LESS reactive compared to cyclobutane, and cyclohexane and cycloheptane are free from angle of strain.Therefore quite stable.But actually Bayer's theory fails for the rings containing six or more carbone ATOMS.

Discussion

Explore topic-wise InterviewSolutions in .

According to Faraday's laws of electrolysis, the discharge of one electrochemical equivalent of ions should involve

According to Faraday's first Law of electrolysis mass of substance liberated is equal to

According to Fajan's rule polarisationis more when:

According to Ellingham diagram, the oxidation reaction of carbon to carbon monoxide may be used to reduce which one of the following oxides at the lowest temperature ?

According to Ellingham diagram, the oxidation reaction on the carbon to carbon monoxide may be used to reduce which one of the following oxides at the lowest temperature ?

According to Ellingham diagram , the oxidation reaction of carbon to carbon monoxide may be used to reduce which one of the following oxides at lowest temperature ?

Accordingto Ellingham diagram,theoxidationreactionofcarbontocarbonmonoxidemaybe used toreducewhichone ofthefollowingoxides atthelowesttermperature ?

According to Ellingham diagram Cr_(2)O_(3) reduced by

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According to Dulong and Petit's rule, in case of solid elements. Approximate atomic mass =(6.4)/("specific heat") In this rule, specific heat is in

According to Debye-Huckel-Onsager equation,wedge_(m)^(c)=_____.

According to de Broglie, matter has a wave character. still we cannot measure the wavelength of even 1 mg mass. It is because:

According to crystal field theory, the M-L bond in a complex is

According to crystal field theory ,The bond between the ligand and central metal atom is __________

According to crystal field theory (CFT) :

According to combined gas law.

According to collision thery

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According to collision theory of reaction rates

According to collision theory of reaction rates, the activation energy is

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According to classification of aminoacids, lysine belongs to the following

According to CIP rule, the correct arrangment in order of decreasing priority is :-

According to Charles's law :

According to, Charle's law

According to Charles' law, at constant pressure 100ml of a given mass of a gas with 10^(@)C rise in temperature will become( ( 1)/( 273) = 0.00366)

According to Charle's law

According to CFT the energy of t_(2g) orbitals in an octahedral complex

According to bronstedconcept, the acids in the reaction : NH_3+H_2O=NH_4+OH^- are:

According to Bronsted principle, an aqueous solution of HNO_(3) will contain

According to Bronsted-Lowry concept, the correct order of relative strength of bases follows the order

According to Bronsted lowry, water is a/an

According to Bronsted-Lowry concept, base is a substance which is

According to Bohr's theory the radius of electron in an orbit described by principal quantum number n and atomic number Z is proportional to:

According to Bohr's theory the energy required for the transition of H atom from n=6 to n=8 state is

According to Bohr's theory, the angular momentum of an electron is 5 th orbit is

According to Bohr's theory, the angular momentum for an electron of 5th orbit is

According to Bohr's theory,

According to BIS, what is the per centage of TFM in bath Soap of grade - 3?

According to Bayer's strain theory which is highly stable?