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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 86201. |
Absolute alcohol cannot be obtained by simple fractional distillation because |
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Answer» PURE `C_(2)H_(5)OH` is unstable |
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| 86202. |
Absolute alcohol can be obtained from rectified spirit |
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Answer» By removing the water in using concentrated sulphuric acid |
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| 86203. |
Absolute alcohol acnnot be obtained by simple fractionation of solution of ethanol and water because: |
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Answer» Boiling POINT are very near |
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| 86204. |
Abscisic acid is |
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Answer» TRIGLYCERIDE of LONG CHAIN alcohol |
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| 86205. |
Above the inversion temperature, mu(J.T. coefficient): |
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Answer» Is positive |
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| 86206. |
Above reaction takes place in three steps : Step a Step b Rate determining step (slow step) is/are |
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Answer» a |
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| 86207. |
Above reaction takes place in three steps : Step a Step b Consider the following aldehydes {:(HCHO,"CCl"_(3)CHO,CH_(3)CHO,C_(6)H_(5)CHO),("(a)","(b)","(c)","(d)"):} The reaction is not given by |
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Answer» a, b |
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| 86208. |
Above given question, the value of rate constant for appearance of AB(g) is : |
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Answer» `2.5xx10^(-4)` |
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| 86210. |
Above conversion can be achieved by |
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Answer» `NH_2-NH_(2)//NaOH` |
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| 86211. |
above compounds (P) & (Q) can be differentiated by : |
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Answer» amm. `AgNO_(3)` |
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| 86212. |
Above compounds can be differentiated by which of the following chemical test? (used in decreasing order) |
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Answer» `NaOH, NaHCO_(3), HCl`  The mixture is composed of a neutral compound m-nitrobenzene, two acids (m-nitrobenzoic acid and m-nitrophenol), and a base (m-nitroaniline). M-nitrobenzoic acid is strong enough as an acid to DECOMPOSE sodium carbonate, m-nitrophenol is not, but does form a salt with sodium hydroxide. Hence, one way in which a separation may be EFFECTED is as follows. Dissolve the mixture in ether (all components are soluble). (i) Extract the ETHEREAL solution with aqueous sodium carbonate. Only m-nitrobenzoic acid enters the aqueous layer, and may be recovered on acidification. (II) Extract the ethereal solution from (i) with aqueous sodium hydroxide. Only m-nitrophenol enters the aqueous layer, and may be recovered on acidification. (III) Extract the ethereal solution form (ii) with hydrochloric acid. Only m-nitroaniline enters the aqueous layer, and may be recovered on basifying the solution. (iv) Evaporate off the ether from the ethereal solution from (iii). This leaves m-nitrobenzene. 
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| 86213. |
Above compounds can be differentiated by using the reagent : |
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Answer» `NAOH`, TOLLEN's reagent, `FeCl_(3)` 
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| 86214. |
Above compounds can be differentiated by the salicylate. Which of the following chemical test ? (used in decreasing order) |
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Answer» `NAOH, FeCl_(3), NaHCO_(3)` |
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| 86215. |
Above1073 K,………… reducesFeOto Fewhilebelow1073K, …………… reducesFe_ 2O _ 3to Fe. |
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Answer» |
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| 86216. |
About "White phosphorous" I. It's ignitiontemperature in very high. II. It glows in the dark due to oxidation. III. White phosphorousis poisonous in nature. IV. It has pungent smell . |
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Answer» II and III only |
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| 86217. |
About "Van-Arkel" |
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Answer» Van-Arkel method used for refining ZIRCONIUM. |
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| 86218. |
About the basic open hearth process, which statement is wrong |
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Answer» Limestone is ADDED to the charge |
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| 86219. |
about " potassium permanganate " |
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Answer» Potassiumpermanganateis PREPARED frompyrolusite ore. |
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| 86220. |
About"Potassiumdichromate " I. It is an orangeredcrystalline solid II.It ismeltsat 671 K . III .It ismoderatleysolublein hotwater . IV It ismuchsoluble in coldwater . |
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Answer» I, II and III only |
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| 86221. |
About "Nitric acid " I. It is prepared in large scales by ostwald's process. II. It completely misciblewith water forming a constant boiling mixture. III. It boils at 56^(@)C. |
| Answer» Answer :A | |
| 86222. |
About "Phosphine" |
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Answer» It is PREPARED by HEATING nitric acid. |
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| 86223. |
About half of H_3SO_4 produced in world is used to |
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Answer» MANUFACTURE of soap |
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| 86224. |
About H_2 SO_4, which of the following statements is incorrect ? |
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Answer» REDUCING AGENT |
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| 86225. |
About ''Collision theory'' |
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Answer» Collision theory used to predict the rates of chemical reactions for gases. |
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| 86226. |
About "Electrolytic refining" |
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Answer» The crude metal is refining by ELECTROLYSIS |
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| 86227. |
About " Ammonia" I. Ammonia is formed by the hydrolysis of urea. II. It is heavier than air. III. It can readily liquefied by at aboutatmospheric pressure. IV. Liquid ammonia resembleswater in its physicalproperties. |
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Answer» I, III and IV only |
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| 86228. |
About aminessomestatements are givenbelow, . 1. theypossess towlone pair of electronson nitrogenatom. 2. theseare monoacidic base 3 theirbasicity is one . 4. theycan acceptproton. Among the above , true statements (s) is /are |
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Answer» only 2 and 3 |
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| 86229. |
About a gaseous reaction xX+yY to l L +mM which statement is wrong? |
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Answer» X litres of X combines with y litre of Y to give L and M |
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| 86230. |
About aliphatic hydrocarbon some statements are given below, 1. chlorination takes place slowly in drak 2. idoination is carried in the presence of HgO 3. photochlorination is a electrophilic substitution reaction 4. direct iodination of alkane is ir-reversible reaction Among the above, the correct statement(s) is /are |
| Answer» Answer :D | |
| 86231. |
About 78% of earth atmosphere contains, ……………… . |
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Answer» P |
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| 86232. |
About 3 dm^(3) gastric juice are produced per day in a human body from other body fluids such as blood whose pH = 7.4 at 37^(@) C. What is the minimum work in kJ required to produce 3 dm^(3) gastric juice at the body temperature? The pH of gastric juice =1 |
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Answer» |
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| 86233. |
About 3 dm^(3) gastric juice are produced per day in a human body from other body fluids such as blood whose pH = 7.4at 37^(@)C. What is the minimum work in kJ required to produce 3 dm^(3) gastric juice at the body temperature ? The pH of gastric juice =1. |
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Answer» |
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| 86234. |
About 20 km above the earth there is an ozone layer. Which one of the following statements about ozone and ozone layer is true? |
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Answer» OZONE layer is BENEFICIAL to us because ozone cuts out the ULTRAVIOLET radiation of the sun |
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| 86235. |
Abnormal molar mass is produced by |
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Answer» ASSOCIATION of solute |
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| 86236. |
Abnormal colligative properties are obtained when the solute : |
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Answer» undergoes association. |
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| 86237. |
(a)Between CH_(3)NH_(2)and C_(6)H_(5)NH_(2) which is more base? Give reason. (b) (i) Name the main product when aniline is heated with alcoholic KOH and chloroform. (ii) Give the IUPAC name of (CH_(3))_(2)N-C_(2)H_(5).(c ) Complete the chemical equation.CH_(3)CONH_(2) overset(Br_(2)//NaOH )to |
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Answer» SOLUTION :(a)`CH_(3)NH_(2)` because in methylamine, `CH_(3)` GROUP is ELECTRON donating Which increases the electron density on nitrogen atom due to +I effect. (B)(i)Phenyl isocyamide. (ii) N, N-dimethylethanamine. (c)`CH_(3)CONH_(2) overset(Br_(2)//NAOH )to CH_(3)NH_(2) + 2NaBr +Na_(2)CO_(3) + 2H_(2)O` |
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| 86238. |
A,B,C,and D are four elements whose standard oxidation potentials are +2.82V , +2.71V ,+1.67V and -2.87V. The strongest reducing agent is |
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Answer» A |
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| 86239. |
A,B,C and D elements form compounds AC, A_(2)D and BD. If AC and A_(2)D are radioactive and BD is not radioactive compound, then which among the following pair of compounds may not be radioactive: |
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Answer» `A_(2) and BD` |
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| 86240. |
Find out the correct pair: (a)Bauxite-Iron (b)Siderite-Aluminium (c )Malachite-Copper (d)Argentite-Gold |
| Answer» SOLUTION :(C )Malachite-Copper | |
| 86241. |
AB_(2) andA_(2)B_(3) are two compounds of the elements A and B 0.15 mole of each of these compounds weights 9.3and 15.9g respectively. Find the atomic masses of A and B. |
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Answer» Solution :LET atomic masses of A and B be 'a' and 'b' respectively. `THEREFORE 0.15(a+2b)=9.3g` 0.15(2a+3b)=15.9g i.e., a+2b=62 On SOLVING EQUATIONS (i) and (ii) b=18 and a=26 |
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| 86242. |
AB to A+B is a zero order reaction,if K=4xx10^(-1) "molelitre"^(-1)"second"^(-1),then how much will be the production rate in mole "litre"^(-1)"second"^(-1) for A? |
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Answer» `2xx10^(-1)` |
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| 86243. |
AB is an ionic solid. If the ratio of ionic radii of A^(+) and B^(+) is 0.52. What is the co-ordination number of B? |
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Answer» 2 |
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| 86244. |
AB crystallizes in a body centred cubic lattice with edge length 'a' eqal to 387 pm. The distance between two oppositely charged ions in the lattice is : |
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Answer» 200pm `= ( sqrt( 3))/( 2) a = ( 1.732 xx ( 387p m))/( 2) = 335 `pm |
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| 86245. |
AB crystallises in a bcc lattice with edge length ‘a’ equal to 387 pm. The distance between two oppositely charged ions in the lattice is |
| Answer» Answer :A | |
| 86246. |
AB crystallizes in a body centred cubic lanice with edge length 'a' equal to 387 pm. The distance between two oppositely charged ions in the Janice is : |
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Answer» 335 pm the distance between the two oppositely charged ions. `=(a)/(2)sqrt(3)` `=(387xx1.732)/(2)=335` pm. |
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| 86247. |
A,B and C are ideal gases. Their molecular weights are 2,4 and 28 respectively. The rate of diffusion of these gases follow the order |
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Answer» `C gt A gt B` As the molecular weight of the gas increases, rate of diffusion decreases. |
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| 86248. |
AB, A_2 and B_2 are diatomic molecules. If the bond enthalpies A_2 AB and B_2 are in the ratio 1:1:0.5 and the enthalpy of formation of AB fron A_2 and B_2 is -100 kJ mol^-1, what is the bond enthalpy of A_2: |
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Answer» 200 KJ `mol^-1` |
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| 86249. |
(a)Azulene has an appreciabel dipole moment.Write the reasonance structure that explains the dipole moment and its aromaticity. (b)In the cse of halogen-substituted azulenes,a halogen atom onC-6can be displace bynucleophile while one onC-1is unreactive towards nucleophile .Rationalise this differemce in behaviou. |
Answer» Solution : The major CONTRIBUTION to the HYBRID must be one that involves charge separation ,having aromatic five-and seven-membered rings. (b)  `ArSN` intermediate reaction is favoured by five-membered ring WOTH cyclopentadienyl anion character(aromatic). In the second case`BAR(e)`discoalisation into the other (seven-membered)ring result in eight`bar(e)`-in that ring ,which DOESNOT stablise it. 
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| 86250. |
A(aq)rarrB(aq)+C(aq) is first order reaction. "Time"""t""oo "moles of reagent " ""n_(1)""n_(2) Reaction prgress is measured with the help of titration of reagent 'R'. If all A, B and C react with reagent and have 'n' factors [n factor,eq. mass=("mol.mass")/(n) in the ratio of 1:2:3 with the reagent, the k in terms of t, n_(1) and n_(2) is : |
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Answer» `k=10/tln(n_(2)/(n_(2)-n_(1)))` |
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