InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 8951. |
Which of the following salts is insoluble in water at room temperature but soluble in boiling water |
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Answer» `CaCl_(2)` |
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| 8952. |
What are limitations of Freundlich adsorption isotherm? |
| Answer» Solution :(i) This equation is purely empirical and valid over a limited pressure RANGE. (II) The values of constants K and n also found vary with temperature. (iii) No THEORETICAL explanations were given. | |
| 8953. |
underset((2)OH^(-)///_\) overset((1)NH_(2)-NH_(2))toA A is |
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Answer»
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| 8954. |
The sterochemistry of SN^1reaction of an alkyl halides is |
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Answer» Complete INVERSION of configuration TAKES place |
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| 8955. |
The time taken by a metal ball to drop through a liquid A of height h is 5.0 s, whereas that in liquid B is 7.5 s. If the densities of the metal ball, liquids A and B are 7.8 xx 10^(3), 1.5 xx 10^3 and 4.6 xx 10^3 kgm^(-3) respectively, calculate the viscosity of liquid A. eta(B) = 2.5 cP |
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| 8956. |
Y is |
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Answer»
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| 8957. |
Which of the following statements regarding heavy water are correct ? 1. It is extensively used as a moderator in nuclear reactors 2. It cannot be used in exchange reaction to study reaction mechanism 3. Viscosity of heavy water is relatively smaller than that or ordinary water The dielectric constant of heavy water is smaller than that of ordinary water Select the correct answer using the code given below : |
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Answer» 1 and 2 DIELECTRIC constant of heavywateris smaller than thatof ordinarywater . |
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| 8958. |
What happens when an alkyl halide reacts with AgNO_(2) and the product is reduced ? |
| Answer» Solution :`RX+ AgNO_(2) to RNO_(2) underset(6[H])OVERSET(Sn. HCl)to underset("PRIMARY armine")(R-NH_(2))` | |
| 8961. |
Which element has a greater tendency to form a chain of bonds with itself? |
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Answer» Boron |
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| 8962. |
Which among the following is most reactive ? |
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Answer» `I_(2)` |
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| 8963. |
Which of the following complexes produces three moles of Silver chloride when its one mole is treated with excess of Silver nitrate: |
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Answer» `[Cr(H_(2)O)_(3)Cl_(3)]` |
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| 8964. |
Which of the following equations represents the oxidising action of sulphur dioxide . |
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Answer» `2FE^(3+) + SO_(2) + 2H_2O to 2Fe^(2+) + SO_(4)^(2-) + 4H^(+)` |
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| 8966. |
Which of the following aldohexoses give the same osazone derivative? |
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Answer» I and IV
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| 8967. |
Which type of bonds are responsible for secondary structure of proteins? |
| Answer» SOLUTION :HYDROGEN BONDS. | |
| 8968. |
Which is a strong reducing agent ? |
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Answer» HYDROGEN iodide |
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| 8969. |
Which of the following reaction is proper for ellingham's diagram for graph of DeltaG^@ vs T ? |
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Answer» `MG + 1/2O_(2) to MGO` |
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| 8970. |
Write one example each of (i)a nucleophile (ii) an electrophile. |
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Answer» SOLUTION :(i) Nucleophile : `Cl^(-)` is a nucleophile (II) Electrophile : `Coverset(+)H_(3)` is an electrophile. |
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| 8971. |
Which of the following ethers is not cleaved by concentrated HI even at 525K? |
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Answer»
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| 8972. |
TiCl_(4) fumes strongly in moist air and is hydrolysed by water to give : |
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Answer» TI |
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| 8973. |
Which leaves no track on Wilson cloud chamber |
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Answer» Electrons |
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| 8974. |
Which of the following is a primary amine |
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Answer» `CH_(3)CH_(2)CH_(2)NH_(2)` |
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| 8975. |
What is Bragg's equation ? |
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Answer» Solution :(i) X-ray diffraction analysis is the most powerful TOOL for the determination of crystal structure. (ii )The inferplanar distance (d) between two successive planes of atoms can be calculated using the following equation form the X-ray diffraction data `2d sin theta = n lambda`. The equation is known as Bragg.s equation Where `lambda` = wavelength of X-ray,`""`d= INTERPLANAR distance `theta` = The angle of diffraction`""` n= order of reflection By knowing the values of `theta, lambda and n`, we can calculate the VALUE of d. `d= (nlambda)/(2sintheta)`Using these values, the edge of the unit cell can be calculated. |
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| 8976. |
The steady decrease in atomic size in lanthanide series is called lanthanide confraction and in all amounts to |
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Answer» 150 Pm |
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| 8977. |
The small size and high charge of Al^(3+) ion gives it a high charge density which is responsible for its tendency to show (a) covalency in its compounds in the gaseous state (b) high hydration energy which stabilizes its compounds in solution, and (c) high lattice energy of its compounds in the solid state. Thus aluminium can forms both covalent and ionic bond. Like halides of boron, halides of aluminium do not show back bonding because of increase in size of aluminium. Actually aluminium atoms complete their octets by forming dimers. Thus chloride and bromide of aluminium exist as dimers, both in the vapour state and in polar-solvents like benzene while the corresponding boron halides exists as monomer. In boron trihalides the extent of back bonding decreases with increases with increase in size of halogens and thus lewis acid character increases. All BX_(3) are hydrolysed by water but BF_(3) shows a different behaviour. Which one of the following statements is correct ? |
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Answer» All boron trihalides are hydrolysed to boric acid. (B)Anhydrous `AlCl_(3)` is covalent. ( c)
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| 8978. |
Give reasons: Zr and Hf have almost identical radii. |
| Answer» SOLUTION :DUE to lanthanoid CONTRACTION, the atomic radii of 4d- and 5D- transition series elements are ALMOST same. | |
| 8979. |
The small size and high charge of Al^(3+) ion gives it a high charge density which is responsible for its tendency to show (a) covalency in its compounds in the gaseous state (b) high hydration energy which stabilizes its compounds in solution, and (c) high lattice energy of its compounds in the solid state. Thus aluminium can forms both covalent and ionic bond. Like halides of boron, halides of aluminium do not show back bonding because of increase in size of aluminium. Actually aluminium atoms complete their octets by forming dimers. Thus chloride and bromide of aluminium exist as dimers, both in the vapour state and in polar-solvents like benzene while the corresponding boron halides exists as monomer. In boron trihalides the extent of back bonding decreases with increases with increase in size of halogens and thus lewis acid character increases. All BX_(3) are hydrolysed by water but BF_(3) shows a different behaviour. The dimeric structure of aluminium chloride disappears when: |
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Answer» it dissolves in water |
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| 8981. |
Which is not deflected by magnetic field ? |
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Answer» Neutron |
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| 8982. |
The small size and high charge of Al^(3+) ion gives it a high charge density which is responsible for its tendency to show (a) covalency in its compounds in the gaseous state (b) high hydration energy which stabilizes its compounds in solution, and (c) high lattice energy of its compounds in the solid state. Thus aluminium can forms both covalent and ionic bond. Like halides of boron, halides of aluminium do not show back bonding because of increase in size of aluminium. Actually aluminium atoms complete their octets by forming dimers. Thus chloride and bromide of aluminium exist as dimers, both in the vapour state and in polar-solvents like benzene while the corresponding boron halides exists as monomer. In boron trihalides the extent of back bonding decreases with increases with increase in size of halogens and thus lewis acid character increases. All BX_(3) are hydrolysed by water but BF_(3) shows a different behaviour. Which of the following reaction is incorrect ? |
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Answer» `BF_(3) (g)+F^(-)(aq) to BF_(4)^(-)` |
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| 8983. |
Write the expression for Freundlich's equation to describe the behaviour of adsorption from solution. |
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Answer» Solution :Freundlich equation for adsorption from solution is GIVEN by `(x)/(m)=kC^(1/n)` where x is the mass (in grams) of the SUBSTANCE adsorbed on m G of the adsorbent. C is the CONCENTRATION of the solution. k and `1/n` are constants. |
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| 8984. |
The small size and high charge of Al^(3+) ion gives it a high charge density which is responsible for its tendency to show (a) covalency in its compounds in the gaseous state (b) high hydration energy which stabilizes its compounds in solution, and (c) high lattice energy of its compounds in the solid state. Thus aluminium can forms both covalent and ionic bond. Like halides of boron, halides of aluminium do not show back bonding because of increase in size of aluminium. Actually aluminium atoms complete their octets by forming dimers. Thus chloride and bromide of aluminium exist as dimers, both in the vapour state and in polar-solvents like benzene while the corresponding boron halides exists as monomer. In boron trihalides the extent of back bonding decreases with increases with increase in size of halogens and thus lewis acid character increases. All BX_(3) are hydrolysed by water but BF_(3) shows a different behaviour. Which of the following statements about anhydrous aluminium chloride is correct ? |
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Answer» It is an IONIC compound. |
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| 8985. |
When pH of a solution is 2, the hydrogen ion concentration in moles "litre"^(-1) is ............. |
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Answer» `1xx10^(-12)` |
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| 8986. |
What is the primary structuralfeature necessaryfor a molecule to make it useful in a condensation polymerization reaction ? |
| Answer» Solution :Condensation POLYMERIZATION involves a repititive condensation reaction between two bifunctional monomers. The reaction results in the loss of some SIMPLE molecule such s as water, alcohol, etc. in such a WAY that the product of reaction at each step is again a bifunctional COMPOUND. HENCE, the sequence of condensation goes on resulting in the formation of polymer. | |
| 8987. |
Which of the following compounds has wrong name ? |
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Answer» `CH_(3)-CH_(2)-CH_(2)-COO-CH_(2)CH_(3)" Ethyl butanoate"` `overset(1"")(CH_(3))-underset(OH)underset(|)overset(2"")(CH)-underset(CH_(3))underset(|)overset(3"")(CH)-overset(4"")(CH_(3))" : 3-Methyl-2-butanol "` |
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| 8988. |
Which reaction characteristics are changing by the addition of a catalyst to a reaction at constant temperature…… (i)Activation energy (ii)Equilbrium constant (iii)Reaction entropy (iv)Reaction enthalpy |
| Answer» Answer :A | |
| 8989. |
Which match is incorrect |
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Answer» DOW's PROCESS-manufacture of phenol |
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| 8990. |
When pure sulphuric acid is electrolysed, the product obtained at anode is : |
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Answer» `H_2S_2O_8` |
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| 8991. |
Which of the following element exhibits the strongest tendncy to from bonds. |
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Answer» `O` This `p_(pi)-d_(pi)` bonding is similar to that found in the oxides and oxoacids of P but it is contrast to the more common `p_(pi)-d_(pi)` type of double bond found in alkenes and alkynes. The size of the d orbital MUST be similar to the size of the `p` orbital to obtain effeectives `p_(pi)-d_(pi)` overlap. Since size`0`. the `d` orbital increases as we move down the group,`S` forms stronger`p_(pi)-d_(pi)` bonds relative to the bigger elements in the group.the nuclear charge is increasesd and more and more `s` and `p` electrons are added as we move across a period in the periodic Table. The size of the atom and HENCE the size of `d` orbitals decreases from`Si` and `P` and then form `S` to `Cl`. The decreases in the size of the `3d` orbitals in this series of elements leads to progressively stronger`p_(pi)-d_(pi)` bonds.THUS in the silicates there is hardly any `p_(pi)-d_(pi)` bonding. Thsu `SiO_(4)` units polymerize into an enormous variety of structures linked by `Si-O-Si sigma` bonds. In the phosphates `pi`-bonding is even stronger and has BECOME a dominant factor. Thus only a small amount of polymerization occurs. consequently, only a few polymeric compounds are known with `S-O-S` linkages. for chlorine, `p_(pi)-d_(pi)` bonding is so strong that no polymerization of oxyanions occurs. It is more appropriate to explain the `pi` bonding in terms of delocalized molecular orbitals convering several atoms, in cases where thee is more than one `pi` bond in the molecule. |
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| 8992. |
Whichof the following deactivates the aromatic nucleas? |
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Answer» `-CH_(3)` |
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| 8993. |
Why ammonia is extermely soluble in water? |
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Answer» Due to FORMATION of intra - molecular H - BONDING with water. |
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| 8994. |
Which of the following values of heat of formation indicates that the product is least stable |
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Answer» `-94` kcal |
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| 8995. |
Which of the following names is/are correct for the compound Na[CoCl_(2)(NO_(2))(sigma-C_(3)H_(5))(NH_(3))_(2)] ? |
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Answer» SODIUM allyldiamminedichloridonitrito-N_conaltate (III) |
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| 8996. |
Which of the following defects are stoichiometric or non-stoichiometric? (1) Metal excess defect (2) Schottky defect (3) Metal deficiency defect (4) Frenkel defect. |
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Answer» Solution :STOICHIOMETRIC defect: SCHOTTKY defect, FRENKEL deffect. Non-stoichiometric defect: Metal excess defect, Metal deficiency defect. |
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| 8997. |
Which of these is the correct relationship between bar and atmosphere? |
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Answer» `1 "ATM" = 1.013 "BAR"` |
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| 8998. |
Transition elements form binary compounds with halogens. Which of the following elements will form MF_(3) type compounds ? |
| Answer» Solution :Cr and Co from `CrF_(3)`and `CoF_(3)`. Cu and Ni DONOT form `CuF_(3)` and `NiF_(3)` | |
| 8999. |
Who studied and analysed about colloids? |
| Answer» Solution :Thomas Graham | |
| 9000. |
The shape of ethane is |
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Answer» Triangular |
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