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91051.

(A) Caro's acis has S atom in + 6 oxidation state (R ) Caro's acid contains the peroxo o _(2) ^(2-) group

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Both (A) and (R ) are TRUE and (R ) is the CORRECT EXPLANATION of (A)
Both (A) and (R ) are true and (R ) is not the correct explanation of (A)
(A) is true but (R ) is false
Both (A) and (R )are false

Answer :A
91052.

A Carnot engine, whose temperature of the source is 400K receives 200 calories of heat at this temperature and rejects 150 calaroies of heat to the sink. What is the temperature of the sink? Also, calculate the efficiency of the engine

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ANSWER :`(300 K, 25%)`
91053.

A Carnot engine, having an efficiency of eta=1//10 as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is

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99 J
90 J
1 J
100 J

Answer :B
91054.

Carnallite is an example of

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Both (A) and (R) are TRUE and (R) is the correct EXPLANATION of (A)
Both (A) and (R) are true and (R) is not the correct explanationof (A)
(A) is true but (R) is false
Both (A) and (R) are false

Answer :D
91055.

A Carnot engine has an efficiency of 40% . If the temperature of the reservoir is 280 K, what is the temperature of the source ?

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ANSWER :(466.6 K)
91056.

(A) Carboxylic acids (R-overset(O)overset(||)C-OH) have a carbonyl group but it does not give the test of carbonyl group. Due to resonance double, the bond character of group is greatly reduced.

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If both (A) and (R) are CORRECT and (R) is the correct EXPLANATION of (A).
If both (A) and (R) are correct but (R) is not correct explanation of (A).
If (A) is correct but (R) is INCORRECT.
If (A) is incorrect but (R) is correct.

ANSWER :A
91057.

(A) Carboxylic acids contain a carbonyl group but do not give characteristic reactions of the carbonyl group. (R) Double bond character of C = O bond in carboxylic acids is greatly reduced due to resonance, as compared to that in aldehydes and ketones.

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Both (A) and (R) are TRUE and (R) is the CORRECT EXPLANATION of (A)
Both (A) and (R) are true and (R) is not the correct explanation of (A)
(A) is true but (R) is false
Both (A) and (R) are false

Answer :A
91058.

A carboxylic acid X is treated with bromine(1 mole) in the presence of a little phosphouus. The isolated product is heated with a strong base and then oxidized with O_(3)//Zn-H_(2)O. one of the two oxidation products is a netural compound which reacts with hydroxylamine to give an oxime, X can be

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`CH_(3)CH_(2)CH(CH_(3))CH_(2)CO_(2)H`
`CH_(3)CH_(2)CH(CH_(3))CO_(2)H`
`CH_(3)CH_(2)CO_(2)H`
`(CH_(3))CHCH_(2)CO_(2)H`

Answer :A
91059.

A carboxylic acid isconverted into its anhybride using

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thionly chloride
SULPHUR chloride
sulphuric
PHOSPHORUS pentoxide

Solution :Carboxylic ACID is coverted into ISTS anhybride by using phosphorus pentaoxide.
91060.

A carboxylic acid of the formula, C_(3)H_(5)O_(2)Br is optically active. What is its structure?

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Solution :`CH_(3)-OVERSET(Br)overset(|)(.^(**)C)H-COOH`2-Bromopropanoic ACID.
91061.

A carboxylic acid can best be converted into acid chloride by using

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`PCl_5`
`SOCl_2`
HCL
ClCOCOCl

Solution :Use of `SOCl_2` and CICOCOCI forms gaseous by products which can be easily removed, GIVING better yield of RCOCI. Further, oxalyl chIoride is particularly easy to use becasue any excess of it can be easily evaporated due to its low b.p. (`62^@C`)
`R-oversetOoverset(||)C-OH +Cl - OVERSET(O)overset"||"C-overset(O)overset(||)C-Cl to R-overset(O)overset(||)C-Cl + HCl uarr + CO uarr + CO_2 uarr`
91062.

A carbonyl compound with molecular weight 86, does not reduce Fehling's solution but forms crystalline bisulphite derivative and gives iodoform test. The possible compound can be

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2-pentanone and 3-pentanone
2-pentanone and 3-METHYL-2-butanone
2-pentanone and pentanal
3-pentanone and 3-methyl-2-butanone

Solution :Both 2-pentanone and 3-methyl-2-butanone being methyl KETONES form crystalline bisulphite derivative and GIVE IODOFORM test.
91063.

A carbonyl compound with molecular weight 86, does not reduce Fehling's solution, but form crystalline bisulphite derivatives and gives iodoform test. The possible compound can be

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Pentan -2 - one and pentan - 3- one
Pentan -2-one andpentan -3- one
Pentanal
PENT -3- one

ANSWER :B
91064.

A carbonyl compound with molecular mass 86, does not reduce Fehling's solution but forms crystalline bisulphite derivative and gives iodoform test. The possible compound is

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2-pentanone and 3- pentanone
2-pentanone and 3-methyl-2-butanone
2-pentanone and pentanal
3-pentanone and 3-methyl-2-butanone.

Solution :SINCE the compound gives IODOFORM test, it is a methyl ketone. The isomers listed in OPTION (B) RESPOND to this test.
91065.

A carbonyl compound reacts with hydrogen cyanide to form a cyanohydrin which on hydrolysis forms a racemic mixture of alpha-hydroxy acids. The carbonyl compound is

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formaldehyde
acetaldehyde
acetone
diethyl ketone

Solution :Acetaldehyde CYANOHYDRIN `CH_(3) overset(**)(C)H(OH)CN and `lactic ACID `(CH_(3)overset(**)(C)HOHCOOH)` which it gives on hydrolysis contain a chiral carbon and hence exist as racemic MIXTURES. All other compounds are symmetrical and hence their cyanohydrins and the corresponding `alpha`-hydroxy acids are not optically active because they do not contain a chiral carbon.
91066.

A carbonyl compound P,which gives positive iodoform test, undergoes reaction with MemgBr followed by dehydration to give an Olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R, which undergoes intramolecular aldol reaction to give predominantly S. The structure of the products Q and R, respectively, are

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ANSWER :A
91067.

A carbonyl compound P,which gives positive iodoform test, undergoes reaction with MemgBr followed by dehydration to give an Olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R, which undergoes intramolecular aldol reaction to give predominantly S. The structure of the product S is

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ANSWER :B
91068.

A carbonyl compound P,which gives positive iodoform test, undergoes reaction with MemgBr followed by dehydration to give an Olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R, which undergoes intramolecular aldol reaction to give predominantly S. The structure of the carbonyl compound P is

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ANSWER :B
91069.

A carbonyl compound P which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R,which undergoes intramolecular aldol reaction to give predominantly S. Poverset((i)MeMgBr)undersetunderset((iii)H_(2)SO_(4),"heat")((ii)H^(+),H_(2)O)rarrQoverset(O_(3)//Sn^(-),H_(2)O)rarrRoverset(OH^(-))underset("heat")rarrS. The structures of the products Q and R, respectively, are

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ANSWER :B
91070.

A carbonyl compound P which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R,which undergoes intramolecular aldol reaction to give predominantly S. Poverset((i)MeMgBr)undersetunderset((iii)H_(2)SO_(4),"heat")((ii)H^(+),H_(2)O)rarrQoverset(O_(3)//Sn^(-),H_(2)O)rarrRoverset(OH^(-))underset("heat")rarrS. The structure of the product S, is

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ANSWER :B
91071.

A carbonyl compound (P) with the formula C_(2)H_(4)O reacts with CH_(3)MgX followed by hydrolysis to form an alcohol (Q). Name the alcohol Q.

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SOLUTION :PROPAN -2-ol
91072.

A carbonyl compound P, which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R which undergoes intramolecular aldol reaction to give predominantly S. P underset(underset(3.H_(2)SO_(4),Delta)(2. H^(+), H_(2)O))overset(1."MeMgBr")(rarr) "Q " underset(2.Zn,H_(2)O)overset(1.O_(3))(rarr)" R "underset(2.Delta)overset(1. OH^(-))(rarr)S

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ANSWER :A
91073.

A carbonyl compound P which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R,which undergoes intramolecular aldol reaction to give predominantly S. Poverset((i)MeMgBr)undersetunderset((iii)H_(2)SO_(4),"heat")((ii)H^(+),H_(2)O)rarrQoverset(O_(3)//Sn^(-),H_(2)O)rarrRoverset(OH^(-))underset("heat")rarrS. The structure of the carbonyl compound P is

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ANSWER :A::B
91074.

A carbonyl compound P, which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R, which undergo intramolecular aldol reaction to give predominantly S. Poverset(1.MeMgBr)undersetunderset(3.H_(2)SO_(4),Delta)(2.H^(+),H_(2)O)rarrQ overset(1.O_(3))underset(2.Zn,H_(2)O)rarr Roverset(1.OH^(+))underset(2.Delta)rarr S The structure of the product S is

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SOLUTION :
91075.

A carbonyl compound P, which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R, which undergo intramolecular aldol reaction to give predominantly S. Poverset(1.MeMgBr)undersetunderset(3.H_(2)SO_(4),Delta)(2.H^(+),H_(2)O)rarrQ overset(1.O_(3))underset(2.Zn,H_(2)O)rarr Roverset(1.OH^(+))underset(2.Delta)rarr S The structure of the products Q and R, respectively, are

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SOLUTION :
91076.

A carbonyl compound P, which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R, which undergo intramolecular aldol reaction to give predominantly S. Poverset(1.MeMgBr)undersetunderset(3.H_(2)SO_(4),Delta)(2.H^(+),H_(2)O)rarrQ overset(1.O_(3))underset(2.Zn,H_(2)O)rarr Roverset(1.OH^(+))underset(2.Delta)rarr S The structure of the carbonyl compound P is

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SOLUTION :
91077.

A carbonyl compound gives a positive lodoform test but but does not reduce Tollen's reagent or Fehling's solution. It forms a cyanohydrin with HCN, which on hydrolysis gives a hydroxy acid with a methyl side chain. The compound :-

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Acetaldehyde
Propionaldehude
Acetone and ACETIC ACID
Crotonaldehyde

Answer :C
91078.

A carbonyl compound 'A'' react with hydrogen cyanide to give cyanohydrin 'B' which on acid hydrolysis gives optically active alpha - hydroxy propanoic acid 'C' Compounds A, B, C respectively are ,

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`HCHO, H - UNDERSET(CN) underset(|) overset(H)overset(|) (C) - OH,H - underset(COOH) underset(|) overset(H) overset(|) (C) - OH `
`CH_(3) - CHO,CH_(3) - underset(CN) underset(|) overset(H) overset(|) (C) - OH,CH_(3) - underset(COOH) underset(|) overset(H) overset(|) (C) - OH`
`C_(2)H_(5) - CHO,C_(2)H_(5) - underset(CN) underset(|) overset(H) overset(|) (C) - OH,C_(2) H_(5) - underset(COOH) underset(|) overset(H) overset(|) (C) - OH`
`CH_(3) - overset(CH_(3))overset(|) (C) = O ,CH_(3) - underset(CN) underset(|) overset(CH_(3))overset(|) (C) - OH ,CH_(3) - underset(COOH) underset(|) overset(CH_(3)) overset(|) (C) - OH`

Answer :B
91079.

A carbonyl compound A having molecular formula C_5H_10 Oforms crystalline precipitate with sodium bisulphate and gives positive iodoform test. A does not reduce Fehling solution. Identify A.

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Solution :(i) `UNDERSET("(Pentan - 2 - ONE)")(CH_3-CH_2-CH_2-undersetoverset(||)(O)(C ) - CH_3) overset(NaHSO_3)(to) underset("(White crystalline precipitate)")(CH_3-CH_2-CH_2 - undersetoverset(|)(OSO_2Na)oversetunderset(|)(OH) ) `
(ii) Pentan - 2 - one gives positive iodoform test, but it does not reduce Fehling.s solution.
(iii) Hence carbonyl COMPOUND A having molecular formula `C_5H_10 O`is pentan - 2 - one.
`underset("2-pentanone")(CH_3-CH_2 - CH_2 = undersetoverset(||)(O)(C ) - CH_3)`
91080.

A carbonyl compound A having molecular formula C_(5)H_(10)O forms crystalline precipitate with sodium bisulpite and gives positive iodoform test. A does not reduce Fehling solution. Identify A.

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Solution :An CARBONYL caompound having MOLECULAR formula `C_(5)H_(10)O` giving positive iodoform test and does not reduce Fehling solution is 2 - pentanone.
`underset(2-"pentanone")(CH_(3)-CH_(2)-OVERSET((A))(CH_(2)-underset(O)underset(||)(C)-CH_(3)))+NaHSO_(3)tounderset("Pentanone bisulphite")(CH_(3)-CH_(2)-CH_(2)-underset(OH)underset(|)overset(SO_(3)Na)overset(|)(C)-CH_(3)`
`therefore` Compound (A) is 2 - pentanone.
91081.

A carbonyl compoun 'A' reacts with hydrogen cyanide to form a cyanohydrin 'B' which gives an optically alpha hydroxy and 'C' .'C' gives positive iodoform test. A,B and C respectively are given by the set:

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ANSWER :B
91082.

A carbonyl compound can be prepared by hydration of acetylene. It reacts with ammonia to form (X) and with hydroxylamine to form (Y). It undergoes Wolff-Kishner reduction to form Z. X, Y and Z are

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Acetaldimine ACETALDOXIME and ethane
Diacetone amine, acetoxime and PROPANE
Acetaldoxime , SEMICARBAZONE and propane
Aldol, hydrazone and alcohol.

ANSWER :A
91083.

A carbonium ion is formed when a covalent bond between two atoms in an organic compound undergoes:

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Homolysis
Heterolysis
Cracking
Pryrolysis

Answer :B
91084.

A carbonyl compound reacts with HCN to form a cyanohydrin which on hydrolysis forms a racemic mixture of hydroxy acids. The compounds is

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acetaldehyde
acetone
diethyl ketone
Formaldehyde

Answer :A
91085.

Identify correct statement/s from the following: (a) Carbon is found in the native form as graphite. (b) Coal contains large quantities of carbon ( c ) Clay is important source for carbon. (d) Carbon exists in many allotropic forms.

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91086.

A carboncompoundwhichis solublein conc. HClsolution , on treatmentwith f sodiumnitrite give anitrogengas .

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`C_(2)H_(5)NH_(2)`
`CH_(3)NH_(2)`
`CH_(3)CH_(2)CH_(2)NH_(2)`
all of these

Solution :All primary aminegives `N_(2)`GAS with`NaNO_(2) + HCl`.
91087.

A carbon compound contains 12.8% of carbon, 2.1% of hydrogen and 85.1% bromine . The molecule mass of compound is 187.9. calculate the molecular formula of the compound (Atomic mass H=1.008,C=12,Br=79.9)

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`CH_(3)BR`
`CH_(2)Br_(2)`
`C_(2)H_(4)Br_(2)`
`C_(2)H_(3)Br_(3)`

Solution :Number of 'C' ATOMS `=(%)/(100)xx("Molecular MASS")/("Atomic mass")`
`(12.8)/(100)xx(187.9)/(12)=2`
Number of 'H' atoms `=(%)/(100)xx("Molecular mass")/("Atomic mass")`
`=(2.1)/(100)xx(187.9)/(1.008)=4`
Number of 'Br' atoms `=(%)/(100)xx("Molecular mass")/("Atomic mass")`
`=(85.1)/(100)xx(187.9)/(79.9)=2`
Molecular FORMULA `=C_(2)H_(4)Br_(2)`.
91088.

A carbon compound contains 12.8% of carbon, 2.1% of hydrogen and 85.1% of bromince. The molecular weight of the compound is 187.9. Calculatte the molecular formula of the compound. (Atomic weight of H +1.008, C = 12.0 and Br = 79. 9))

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`CH_(3)Br`
`CH_(2)Br_(2)l`
`C_(2)H_(4)Br_(2)`
`C_(2)H_(3)Br_(3)`

Answer :C
91089.

A carbon compound containing only carbon and oxygen has an approximate molecular mass of 290. On analysis. It is found to contain 50% by mass of each element. What is the molecular formula of the compound?

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Solution :
The empirical formula `=C_(4)O_(3)`
Empirical formula mass `=(4xx12)+(3xx16)=96`
MOLECULAR mass =290
`n=("Mol.mass")/("Emp.mass")=(290)/(96)=3` APPROXIMATELY
Molecvular formula `=NXX` empirical formula
`=3xxC_(4)O_(3)=C_(12)O_(9)`
91090.

A carbohydrate X having molecular mass 180 g mol^(-1)has one primary alcoholic group and four secondary alcoholic group . It reacts with acetic anhydride to form pentaacetate . The molecular mass of pentaacetate formed is …………...........

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180
210
390
42

Answer :C
91091.

A carbohydrate which cannot be hydrolyzed to simpler compounds is called:

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Monosaccharide
Polysaccharide
Disaccharide
Trisaccharide

Answer :A
91092.

A carbohydrate which cannot be hydrolysed to simple compounds is called ...............

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SOLUTION :MONOSACCHARIDE
91093.

A carbohydrate that cannot be hydrolysed to simpler forms is called

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disaccharide
monosaccharide
polysaccharide
trisaccharide

SOLUTION :MONOSACCHARIDES cannot be HYDROLYSED to SIMPLE FORMS.
91094.

A carbohydrates in soluble in water is

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glucose
fructose
Cellulose
sucrose

Answer :C
91095.

A cannot engine operates between temperature T and 400 K(T>400K). If efficiency of engine is 25%, the temperature T is:

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400 K
500 K
533.3 K
600 K

Answer :C
91096.

(A) : Cannizzaro reaction is a disproportionation reaction. (R) : Cannizzaro reaction is performed using acid .

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Both A & R are true, R is the correct EXPLANATION of A
Both A & R are true, R is not correct explanation of A
A is true, R is FALSE
A is false, R is true

ANSWER :C
91097.

A can be prepared by

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`Ph-UNDERSET(O)underset(||)C-Cl+NH_(3)RARR`
`Ph-underset(O)underset(||)C-Cl+NH_(3)OVERSET(POCl_(3))underset(DELTA)rarr`

Answer :B
91098.

'A' can be

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`PbCl_(2)`
`SbCl_(3)`
`SnCl_(2)`
`RbCl`

ANSWER :D
91099.

(a). Calculate triangleG_(f)^(@) of the following raection: Ag^(+)(aq)+Cl^(-)toAgCl(s) given triangleG_(f)^(@)(AgCl)=-109kJ//"mole",triangleG_(f)^(@)(Cl^(-))=-129kJ//"mole",triangleG_(f)^(@)(Ag^(+))=77kJ//"mole" Represent the above reaction in form of a cell. Calculate E^(@) of the cell. find log_(10)K_(sp) of AgCl at 25^(@)C (b). 6.539xx10^(-2)g of metallic Zn (atomic mass =65.39amu) was added to 100 mL of saturated solution of AgCl. Calculate log_(1)([Zn^(2+)])/([Ag^(+)]^(2)) at equilibrium at 25^(@)C given that Ag^(+)+e^(-)toAg""E^(@)=0.80V Zn^(2+)+2e^(-)toZn""E^(@)=-0.76V Also find how many moles of Ag will be formed (take (114)/(193)=0.59,(1.56)/(0.059)=26.44)

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Solution :(a). `triangleG_(R)^(@)=-109+129-77=-57kJ//mol`
cell representation `Ag|AgCl||Cl^(-)|Ag^(+)|Ag`.
`-1xx96500xxE^(@)=057xx10^(3)`
`E^(@)=0.59"volt"`
`0=0.59-(0.059)/(1)log((1)/(K_(SP)))`
`logK_(SP)=-10`.
(b). `ZntoZn^(2+)+2e^(-),""0.76"volt"`
`underline(2Ag^(+)+2e^(-)to2Ag,""0.80"volt")`
`underline(Zn+2Ag^(+)toZn^(2+)+2Ag,) ""E_(cell)^(@)=1.56"volt"`
`n_(2n)=(6.539)/(65.39)=10^(-3)mol""[Ag^(+)]=sqrt(K_(sp))=10^(-5)M`
`0=1.56-(0.059)/(2)logK""n_(Ag^(+))=10^(-5)xx0.1=10^(-6)M`.
`n_(Ag)=10^(-6)molimplieslogK=52.8`
91100.

A calculated amount of I_(2) is used in the preparation of hypo by Spring's reaction because:

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Hypo OXIDISES `I_(2)` if EXCEES `I_(2)` is PRESENT
Excees `I_(2)` oxidises hypo
Excees hypo decreases the solubility of `I_(2)` in water
Hypo and `I_(2)` form an addition compound

Answer :B