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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 91251. |
A black sulphide when treated with ozone becomes white. The white compound is : |
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Answer» `ZnSO_(4)` |
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| 91252. |
A black sulphide when treated with ozone becomes white. The white compound is: |
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Answer» `ZnSO_4` |
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| 91253. |
A black dot used as a full stop at the end of a sentence has a mass of about one attogram. Assuming that dot is made up of carbon, calculate the approximate number of carbon atoms present in the dot? |
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Answer» Solution :Mass of CARBON in DOT = 1 ATTOGRAM` =10^(-18)g` Gram atomic mass of carbon = 12 g, i.e., 12 g of carbon contain `6.022xx10^(23)` atoms of carbon `THEREFORE 10^(-18)" g of carbon will contain carbon atoms"=(6.022xx10^(23))/(12)xx10^(-18)=5.02xx10^(4)" atoms"` |
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| 91254. |
A black sulphide is obtained by action of H_2S on: |
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Answer» `CuCl_2` |
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| 91255. |
A black sulphide is formed by the action of H_(2)S on |
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Answer» `CaCI_(2)` |
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| 91256. |
A black mineral on roasting breaks up into two compounds A and B with the liberation of gas C. When air is passed through the molten mixture of A and B, B converts into oxide that can be reduced by air. The mineral is .......... |
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Answer» CHALCOCITE |
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| 91257. |
A black sulphide is formed by the action of H_2 S on |
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Answer» CUPRIC chloride |
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| 91258. |
A black power (X) when treated with common salt and chamber acid gives off a greenish yellow gas (Y). Y on passing through boiling potash yields compounds are of which when heated with X evolves oxygen. What are X and Y? |
| Answer» SOLUTION :`MnO_(2), Cl_(2)` | |
| 91259. |
A black compound 'X' when treated with O_(3) turned white. The compound 'X' is |
| Answer» Answer :B | |
| 91260. |
A black compound of manganese reacts with a halogen acid to give greenish yellow gas. When excess of this gas reacts with NH_3, an unstable trihalide is formed. In this process, the oxidation state of nitrogen changes from |
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Answer» `-3 " to " + 3` |
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| 91261. |
A black compound of manganese reacts with a halogen acid to give greenish yellow gas. When excess of this gas reacts with NH_3 an unstable trihalide is formed. In this process the oxidation state of nitrogen changes from........ |
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Answer» `(-3)` to `(+3)` `underset(-3)(NH_(3)) + 3Cl_(2) to underset(+3)(NCl_(3)) + 3HCl` |
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| 91262. |
A black compound of manganese reacts with a halogen acid to give greenish yellow gas. When excess of this gas reacts with NH_(3) an unstable trihalide is formed. In this process the oxidation state of nitrogen changes from |
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Answer» `-3 " to " + 3` |
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| 91263. |
A black compound of manganese reacts with a halogen acid to give greenish yellow gas. When excess of this gas reacts with NH_(3) an unstable trihalide is formed. In this process the oxidation state of nitrogen changes from .......... . |
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Answer» `-3` to + 3 `overset(-3)(NH)_(3)+ 3Cl_(2) rarr overset(+3)(NCl)_(3)+3HCl` |
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| 91264. |
A black coloured compound (B) is formed on passing H_(2)S through the solution of a compound (A) in NH_(4)OH. |
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Answer» |
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| 91265. |
A black coloured compound (A) on reaction with dilute H_(2)SO_(4) gives a gas (B) which on passing in a solution of an acid ( C) gives a white turbidity (D).Gas (B) when passed in an acidified solution of a compound (E) gives a precipitate (F) soluble in dilute HNO_(3).After boiling this solution when an excess of NH_(4)OH is added a intense blue coloured compound (G) is formed. To this solution on addition of acetic acid and aqueous K_(4)[Fe(CN)_(6)] a chocolate brown precipitate (H) is obtained.On addition of an aqueous solution of BaCl_(2) to an aqueous solution of (E) a white precipitate insoluble in dilute HCl is obtained. Identify the compounds from (A) to (H). |
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Answer» `2HNO_(3) to 2NO_(2)+H_(2)O+[O]` `H_(2)S+[O]to H_(2)O+S darr ("white")(HNO_(3)` is strong oxidising agent). `CuSO_(4)+H_(2)S to CuS darr +H_(2)SO_(4)` `3CuS + 8HNO_(3) to 3Cu^(2+) + 6NO_(3)^(-)+3S darr +2NO uarr+4H_(2)O.` `2NO_(3)^(2-)+CU^(2+) +4NH_(4)OH to [Cu(NH_(3))_(4)]^(2+) (NO_(3))_(2)` (intense blue coloured solution )+`4H_(2)O` `[Cu(NH_(3))_(4)(NO_(3))_(2)+K_(4)[Fe(CN)_(6)] to Cu_(2)[Fe(CN)_(6)] darr` (chocolate BROWN). `Ba^(2+)+CuSO_(4) to BaSO_(4) darr ("white") +Cu^(2+)` |
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| 91266. |
A black are [x]on fraiment Na_(2)CO_(3) in the presence of air gives a green compound (a). When Rreen compound (a) died in water it producess dark precipitate (b) and pink solution (e) crystal of (e) when treated with propene produces dark ppr (b) Metal present in ore extracted by |
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Answer» electrolytic method The dark green `K_(2)MnO_(4)` disproportionates in a neutral or acidic solution to give permangante. `3MnO_(4)^(-2)+4H^(o+) to underset((c))(2MnO_(4)^(-))+ underset((B))(MnO_(2))+2H_(2)O` `MnO_(2)` is dark precipitate (b) and `KMnO_(4)` solution is pink solution (c) When `KMnO_(4)` reacts with propene (unsaturated compounds) it is reduced to `MnO_(2)` (b) `CH_(3)-CH-=CH_(3) OVERSET("Cold" KMnO_(4)//OH^(-))toCH_(3)- underset(OH) underset(|)(CH)- underset(OH) underset(|)(CH_(2)) underset((b))(MnO_(2))` The metal present in ore `X(MnO_(2))` is N which is extracted by thermite process. `3Mn_(3)O_(4)+8Al to 9 Mn+4Al_(2)O_(3)` heat |
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| 91267. |
A black are [x]on fraiment Na_(2)CO_(3) in the presence of air gives a green compound (a). When Rreen compound (a) died in water it producess dark precipitate (b) and pink solution (e) crystal of (e) when treated with propene produces dark ppr (b) Solution overset (Sa_(2)//H^(+)) to (d) "solution" overset("reagent")underset((R)) to (c) solution reagent (R) can be used. |
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Answer» `OH^(-)//SO_(3)` The dark GREEN `K_(2)MnO_(4)` disproportionates in a neutral or acidic solution to give permangante. `3MnO_(4)^(-2)+4H^(o+) to underset((c))(2MnO_(4)^(-))+ underset((b))(MnO_(2))+2H_(2)O` `MnO_(2)` is dark precipitate (b) and `KMnO_(4)` solution is pink solution (c) When `KMnO_(4)` reacts with propene (unsaturated compounds) it is reduced to `MnO_(2)` (b) `CH_(3)-CH-=CH_(3) OVERSET("Cold" KMnO_(4)//OH^(-))toCH_(3)- underset(OH) underset(|)(CH)- underset(OH) underset(|)(CH_(2)) underset((b))(MnO_(2))` `KMnO_(4) + 5SO_(2)+2H_(2)O overset(H^(o+)) to K_(2)SO_(4)+2MnSO_(4)+2H_(2)SO_(4)` `Mn^(+2) overset("Reagent") underset((R)) to underset((C)) (MnO_(4)^(-))` The reagent .R. is strong oxidizing AGENT. `:.R=PbO_(2)//H^(o+)` |
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| 91268. |
A black are [x]on fraiment Na_(2)CO_(3) in the presence of air gives a green compound (a). When Rreen compound (a) died in water it producess dark precipitate (b) and pink solution (e) crystal of (e) when treated with propene produces dark ppr (b) Geometry around central atom in (a) and (c) respectively |
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Answer» tetrahedral, tetrahedral The dark green `K_(2)MnO_(4)` disproportionates in a NEUTRAL or acidic solution to GIVE permangante. `3MnO_(4)^(-2)+4H^(o+) to underset((C))(2MnO_(4)^(-))+ underset((b))(MnO_(2))+2H_(2)O` `MnO_(2)` is dark precipitate (b) and `KMnO_(4)` solution is PINK solution (c) When `KMnO_(4)` reacts with propene (unsaturated compounds) it is reduced to `MnO_(2)` (b) `CH_(3)-CH-=CH_(3) overset("Cold" KMnO_(4)//OH^(-))toCH_(3)- underset(OH) underset(|)(CH)- underset(OH) underset(|)(CH_(2)) underset((b))(MnO_(2))` The geometry of `MnO_(4)^(-2) and MnO_(4)^(-)` ions is tetrhydral 
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| 91269. |
A bivalent metal as an equivalent mass of 32. The molecular mas of the metal nitrate is |
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Answer» 168 `M^(2+)=32` `:.` atomic mass of `M=32xx2=64` The metal nitrate FORMED has the formula `M(NO_(3))_(2)` `:.` moleclar mass of themetal nitrate `=64+28=96=188` |
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| 91271. |
A biologicalCatalystis |
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Answer» An AMINO ACID |
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| 91272. |
A binary solid has zinc blend structures with B^(-) ions constituting the lattice and A^(-) ions occupying 25% tetrahedral voids. The formula of acid is: |
| Answer» ANSWER :C | |
| 91273. |
A binary solution constitutes ……………number of phases |
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Answer» ONE |
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| 91274. |
A binary solid ( AB ) has a rock salt structure . If the edge length is 500 pm , and radius of cation is 80 pm , find the radius of anion |
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Answer» 100 pm |
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| 91275. |
A Binary solid has rocksalt structure The edge length is 400 pm and the radius of cation is 75 pm, the radius of anion is |
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Answer» 100pm |
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| 91276. |
A binary solid (A^+B^-) has a zinc blende structure with B^-ions constituting the lattice and A^+ions occupying 25% tetrahedral holes .The formula of solid is : |
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Answer» AB |
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| 91277. |
A binary solid (A^+B^-)has a rock salt structure .If the edge length is 400 pm and radius of cation is 75 pm the radius of anion is : |
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Answer» 100 pm |
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| 91278. |
A binary solid (A^+B^-)has a rock salt structure .If the edge length is 400 pm and radius of cation is 80 pm the radius of anion is : |
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Answer» 120 pm |
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| 91279. |
A binary liquid solution of n-heptane and ethyl alcohol is prepared . Which of the following ststements correctly representsthe behaviour of thisliquid solution ? |
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Answer» The solution FORMED is an IDEAL solution |
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| 91280. |
A binary liquid solution is prepared by mixing n-heptane and ethanol. Which one of the following statements is correct regarding the behaviour of the solution? |
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Answer» The solution is non-ideal, showing- ve deviation from Raoult's Law. |
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| 91281. |
A binary liquid solution is prepared by mixing n-heptane and ethanol. Which one of the following statements is correct regarding the behaviour of the solution ? |
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Answer» The solution formed is non-ideal. |
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| 91282. |
A biological catalyst is essentially a/an: |
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Answer» An AMINO acid |
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| 91283. |
Biliquid propellant contains |
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Answer» Liquid hydrazine |
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| 91284. |
A big, irregular-shaped contained water , the sp. Conductance of which was 2.56 xx 10^(-5) "mho cm"^(-1). 500g of NaCl was then added to the water and the sp. cond. after the addition of NaCl, was found to be 3.10 xx 10^(-5) "mho cm"^(-1). Find the capacity of the vessel if it is fully filled with water. (Lambda_(NaCl)^(@) = 149.9) |
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Answer» SOLUTION :Let the volume of the vessel be V CC. Number of equivalent of NaCl `= ("wt. in grams")/("eq. weight")` `= (500)/(58.5) = 8.547` `therefore` volume of water (cc) containing 1 eq. of NaCl `= (V)/(8.547)` The sp. cond. of the NaCl solution (only due to presence of `NA^(+)` and `Cl^(-)` ions) `= 3.10 xx 10^(-5) - 2.56 xx 10^(-5)` `= 0.54 xx 10^(-5)` `therefore Lambda_(NaCl) = 0.54 xx 10^(-5) xx (V)/(8.547)` Sicne the vessel is big, the resulting solution MAY be supposed to be dilute. `therefore Lambda_(NaCl) = Lambda_(NaCl)^(@)` `0.54 xx 10^(-5) xx(V)/(8.547) = 149.9` `V = 2.37 xx 10^(8)` cc. |
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| 91285. |
Answer any FOUR of the following questions. b. (i) Name the main product when aniline is heated with alcoholic KOH and chloroform. (ii) Give the IUPAC name of (CH_3)_2 N- C_2 H_5 |
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Answer» Solution :(a) `CH_3NH_2` is more basic `-CH_3` gp is an electron RELEASING GROUP, it exerts +I effect and INCREASES electron density on N-atom and electrons are localized on N-atom. (b) (i) PHENYL isocyanide (Phenyl Carbylamine) (ii) N,N-dimethylethanamine (c )`CH_3NH_2 + 2NaBr + Na_2CO_3 + 2H_2O or CH_3NH_2` Detailed Answer: (b)  (c) `CH_3CONH_2 + Br_2+ 4NaOHto CH_3NH_2 + 2NaBr + Na_2CO_3 + 2H_2O` |
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| 91286. |
(a) BH_(3) (b) Cl^(o+) (c) H_(3)O^(o+) (d) CO_(2) (e) overset(o+)(N)H_(4) (f) overset(o+)(N)a. how many electrophile is present in given species: |
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Answer» 5 |
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| 91287. |
A bidentate ligand is |
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Answer» pyridine |
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| 91288. |
A bettery is constructed of Cr and Na_(2)Cr_(2)O_(7). The unbalanced chemical equation when such a battery discharges is following: Na_(2) Cr_(2) O _(7)+ Cr+ H^(+)to Cr^(3+) +H_(2)O+ Na^(+) If one Faraday of electricity is passed through the battery during the charging, the number of moles of Cr^(3+) removed from the solution is |
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Answer» `4/3` `Cr _(2) O_(7)^(2-) +6E^(-) +14H^(+) to 2Cr^(3+) +7H_(2)O` Oxidation half reaction : `Cr to Cr^(3+) +3E ^(-)` Overall reaction : `Cr_(2) O_(7)^(2-) +Cr+ 14 H^(+)+3e^(-) to 3Cr^(3+) +7H_(2)O` 3F of electricity =3 moles of `Cr ^(3+)` If of eleclricity `=3/3` moles of `Cr ^(3+)` |
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| 91289. |
A better reagent for oxidation of primary alcohols to aldehydes in good yield is |
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Answer» `CrO_3 +C_2H_5N + HCL` |
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| 91290. |
A beta-hydroxyl carbonyl compound is obtained by the action of NaOH on |
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Answer» HCHO |
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| 91291. |
A beta-hydroxy carbonly compound is obtained by the action of NaOH on |
| Answer» Answer :C | |
| 91292. |
A : Benzyl bromide when kept in acetone water it produces benzyl alcohol.R : The reaction follows S_(B)2 mechanism. |
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Answer» Assertion and REASON both are CORRECT and reason is correct EXPLANATION of assertion. 
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| 91293. |
A benzene ring deactivedby strongand moderate electronswithdrawinggroupthat is, any meta directing group, is notelectron richenough to undergoes Friedel-Carftsreactions. Friedel- Crafts reactionalso do not occur with NH_(2) group as it react with AlCl_(3) and produce deactivatinggroup . whichof the following cannotbe startindmaterial for thiccompounds Ph-underset(O)underset(||)C-CH_(2)-Ph? |
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Answer»
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| 91294. |
A : Benzene on reaction with V_(2)O_(5) gives maleic anhydride at high temperature. R : V_(2)O_(5) act as reducing agent. |
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Answer» If both ASSERTION & REASON are true and the reason is the correct EXPLANATION of the assertion, then mark (1). |
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| 91295. |
(A) Benzaldehyde gives a positive test with Benedict's and Fehiling solution. (R) Benzaldehyde forms black precipitate or silver mirror with Tollens' reagent |
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Answer» If both (A) and (R) are correct and (R) is the CORECT EXPLANATION of (A) |
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| 91296. |
A : K_(4)[Fe(CN_(6))]is diamagnetic R: The alignments of magnetic dipoles are in compensatory to give zero magnetic moment |
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Answer» Both (A) and (R) are TRUE and (R) is the correct EXPLANATION of (A) |
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| 91297. |
(A) Benzaldehyde is more reactive than acetaldehyde towards nucleophilic attack. (R) The combined effect of -I and +R effects of phenyl group decreases the electron density on the carbon atom of C=O group in benzaldehyde. |
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Answer» Both (A) and (R) are TRUE and (R) is the CORRECT EXPLANATION of (A) |
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| 91298. |
(A) Benzaldehyde forms two oximes on reacting with NH_(2)OH. (R) The two oximes arise due to geometrical isomerism around C=N bond. |
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Answer» |
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| 91299. |
(A) Benedicts reagent can be used to distinguish benzaldehyde from aceldehyde. (R) The C-H bond of CHO group in benzaldehyde is stronger than C-H bond of CHO group in acetaldehyde. |
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Answer» Both (A) and (R) are TRUE and (R) is the correct explanation of (A) |
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| 91300. |
(A) Below 2.2 Kelvin, helium is called super fluid(R) Helium has abnormally low viscosity below 2.2 Kelvin |
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Answer» Both (A) and (R) are TRUE and (R) is the correct EXPLANATION of (A) |
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