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93601.

00 mL of a colloidal solution is completely precipitated by addition of 5.6 mL of 1 M NaCl solution. The coagulation value of NaCl is

Answer»

56
28
14
`5.6`

ANSWER :A
Discussion
93602.

0 . 75 moleof solid 'A_(4)'and 2 moles of gaseous O_(2) are heated in a sealedvessel, completely using up thereactants and producing only one compound. It is found that when the temperature is reduced to the initial temperature, the contents of the vessel exhibita pressure equal to halfthe original pressure. Whatconclusions can be drawn from these data aboutthe product of the reaction ?

Answer»

SOLUTION :Asboth the reactants are limiting reagents, the ratio of stoichiometriccoefficientsof the reactantswould be 0 . 75 : 2 or 3 : 8 for `A_(4) and O_(2)` . Thus,
`3 A_(4) + 8 O_(2) to` Product
As the product EXERTS considerable pressure, it has to be a gas.
Further, as the final pressure is HALF thatof oxygen initially PRESENT, the stoichiometriccoefficient of the product must be halfthatof `O_(2)`, i.e., 4. Obviously, the molecularformula would be `A_(3) O_(4)` to balance theequation.
`3 A_(4) + 8 O_(2) to 4 A_(3) O_(4)`
Discussion
93603.

DEFINITION VALID FOR SINGLE ELECTRON SYSTEM : Ground state: Lowest energy state of any atom or ion is called ground state of the atom.It is n=1. Excited State : States of atom other than the ground state are called excited states. Ionisation energy (IE): Minimum energy required to move an electron from ground state to n=oo is called ionisation energy of the atom or ion. Ionisation Potential (I.P) : Potential difference through which a free electron must be accelerated from rest, such that its kinetic energy becomes equal to ionisation energy of the atom is called ionisation potential of the atom. Excitation Energy : Energy required to move an electron from ground state of the atom to the atom is called excitation energy of that state. Excitation Potential : Potentail difference through which an electron must be accelerated from rest to so that its kinetic energy becomes equal to excitation energy of any state is called excitation potentail of that state. Binding Energy 'or' Seperation Energy : Energy required to move an electron from any state to n=oo is called binding energy of that state. If the I excitation potential of a hypothetical H-like is 62 V, then the value of II excitation energy is about :

Answer»

192 EV
30 eV
216 eV
40.5 eV

Solution :I EXCITATION POTENTIAL `=10.2 Z^2=162 V`
`:.` II excitationenergy `=12.09 Z^2=12.09xx162/10.2=192 eV`
Discussion
93604.

DEFINITION VALID FOR SINGLE ELECTRON SYSTEM : Ground state: Lowest energy state of any atom or ion is called ground state of the atom.It is n=1. Excited State : States of atom other than the ground state are called excited states. Ionisation energy (IE): Minimum energy required to move an electron from ground state to n=oo is called ionisation energy of the atom or ion. Ionisation Potential (I.P) : Potential difference through which a free electron must be accelerated from rest, such that its kinetic energy becomes equal to ionisation energy of the atom is called ionisation potential of the atom. Excitation Energy : Energy required to move an electron from ground state of the atom to the atom is called excitation energy of that state. Excitation Potential : Potentail difference through which an electron must be accelerated from rest to so that its kinetic energy becomes equal to excitation energy of any state is called excitation potentail of that state. Binding Energy 'or' Seperation Energy : Energy required to move an electron from any state to n=oo is called binding energy of that state. If the wavelength of photon emitted from an electron jump n=4 to n=2 in a H-like species is 1216 Å, then the species is :

Answer»

H-atom
`He^+` ION
`Li^(2+)` ion
`Be^(3+)` ion

Solution :Energy of photon`=12400/1246=10.2 EV=(H)_(2to1)=(He^+)_(4to2)`
so, species is `He^+` ion
Discussion
93605.

DEFINITION VALID FOR SINGLE ELECTRON SYSTEM : Ground state: Lowest energy state of any atom or ion is called ground state of the atom.It is n=1. Excited State : States of atom other than the ground state are called excited states. Ionisation energy (IE): Minimum energy required to move an electron from ground state to n=oo is called ionisation energy of the atom or ion. Ionisation Potential (I.P) : Potential difference through which a free electron must be accelerated from rest, such that its kinetic energy becomes equal to ionisation energy of the atom is called ionisation potential of the atom. Excitation Energy : Energy required to move an electron from ground state of the atom to the atom is called excitation energy of that state. Excitation Potential : Potentail difference through which an electron must be accelerated from rest to so that its kinetic energy becomes equal to excitation energy of any state is called excitation potentail of that state. Binding Energy 'or' Seperation Energy : Energy required to move an electron from any state to n=oo is called binding energy of that state. If the binding energy of II excitec state of a H-like species is 13.6 eV, then:

Answer»

The atomic number Z of given a H-like species is 2
A photon of energy 30 eV can ionise an ELECTRON from I excited state of given H-like species
Upon de-excitation from n=4 to n=2 is given H-like species, the emitted photon has wavenumber `V=(3R)/(16)`(R=Rydber's constant)
IONISATION potential of given H-like species is 122.4 V

Solution :BINDING energy of II excited state (n=3)`=13.6(Z^2/3^2)=13.6 eV :. Z=3`
`:.` Ionisation potential `=13.6Z^2=13.6xx3^2=122.4 V`
Discussion
93606.

0 . 32 mole of LiAIH_(4) in ether solution was placed in a flask and 74 g (1 mole) of t- butyl alcohol was added. Theproduct LiAIHC_(12)H_(27) O_(3)weighed 81.28 g . Isthe claim that theyield is 'quantitative'a valid oneif Li atoms areconserved ? (Li = 7, Al = 27, H = 1, C = 12 , O = 16)

Answer»

Solution :`{:(LiAIH_(4)""underset("alcohol")OVERSET("t - butyl")to""LiAIHC_(12)H_(27)O_(3)),("0 . 32 mole81 . 28 "g ):}`
Applying POAC for Li atoms,
MOLES of Liin `LiAIH_(4) `moles of Li in `LiAU=IHC_(12) H_(27) O_(3)`
`1 xx ` molesof `LiAIH_(4) = 1 xx ` molesof `LiAIHC_(12) H_(27)O_(3)`
Thus, 0 . 32 mole of `LiAIH_(4)`shouldproduce 0 . 32 mole of `LiAIHC_(12) H_(27) O_(3)` if theyield is QUANTITATIVE, i.e., `100%`
Moles of `LiAIH_(12)H_(27) O_(3) = (81. 28)/(254)= 0 . 32`mole(Rule, 1 Chapter 1)
(mol. wt. of `LiAIHC_(12) H_(27) O_(3) = 254` )
Thus the yield is `100%`
Discussion
93607.

0-2 per cent solution of phenol is :

Answer»

Antiseptic
Disinfectant
Antibiotic
Antiallergic

Answer :A
Discussion
93608.

…… will be formality of solution in which 948 gram potash alum is dissolved in 5 liter solution.(Potash alum - K_(2)SO_(4).Al_(2)(SO_(4))_(3)24H_(2)O Mol. Wt. is 948 gms/mole)

Answer»

0.1 F
0.8 F
0.2 F
0.4 F

ANSWER :D
Discussion
93609.

_____ will not give iodoform test.

Answer»

`HCHO`
`CH_3CH_2OH`
`CH_3CHO`
`CH_3CH(OH)CH_3`

SOLUTION :Butan-1-ol
Discussion
93610.

Which order is correct in spectrochemical series of ligands:

Answer»

`CI^(-)LTF^(-)ltC_2O_4^(2-)ltNO_2^(-)ltCN^-`
`CN^(-)ltC_2O_4^(2-)LTCI^(-)gtNO_2^(-)ltF^-`
`C_2O_4^(2-)ltF^(-)ltCI^(-)gtNO_2^(-)ltCN^-`
`F^(-)ltCI^(-)NO_2^(-)ltCN^(-)ltC_2O_4^(2-)`

Answer :A
Discussion
93611.

,Which of the following graphs is suitable

Answer»




ANSWER :A
Discussion
93612.

( Which of the following with aqueous KOHwill give acetaldehyde ?

Answer»

1,2-Dichloroethane
1,1-Dichloroethane
Chloroacetic acid
Ethyl chloride

Answer :B
Discussion
93613.

. What is the name of the reaction between Benzaldehyde and acetic anhydride?

Answer»

PERKIN's REACTION
Knoerenagal reaction
CANNIZARO reaction
KOLBE's reaction

SOLUTION :Perkin.s reaction
Discussion
93614.

________________ was the first popular artificial sweetener.

Answer»

SOLUTION :SACCHARIN
Discussion
93615.

......... was proposed by Max Trautz and wilinam lewis.

Answer»

SOLUTION :COLLISION THEORY
Discussion
93616.

…………………. vitamin cannot be stored in a body.

Answer»

D
C
A
K

Answer :B
Discussion
93617.

………… vitamin cannot be stored in a body.

Answer»

D
C
A
K

Answer :B
Discussion
93618.

, underset((ii)H^(+)//Delta)overset((i)Br_(2)//KOH)rarr Product is

Answer»




Solution :Molar MASS DUE to `CMxx(12)/(100)=12""M=100`
Molar mass due to `OMxx(4)/(100)=16""M=400`
Molar mass due to `SMxx(16)/(100)=32""M=200`
Minimum molar mass should be 400
Number of C-atom =`(400xx12)/(12xx100)=4-"atom"`
Discussion
93619.

, underset((ii) CH_(2)I_(2)+NAOH)overset((i)CHCl_(3)+KOH)rarr ?

Answer»




ANSWER :C
Discussion
93620.

, underset(H^(+))overset(CO_(2)//NaOH)(rarr)(A)overset("Acetic Anhydride")rarr underset((B))"Aspirin" Product B is

Answer»




Solution :On INCREASES in pressure, VOLUME of VESSEL decreases , CONC. Of all GASES increases.
Discussion
93621.

, underset(Delta)overset(CO_(2))rarrAunderset(H_(3)PO_(4))overset(Ac_(2)O)rarrB Indentitify B in the sequence

Answer»

METHYL orange
Phenolphthaline
Aspirin
Methyl Blue

Answer :C
Discussion
93622.

, underset(Delta)overset(AlCl_(3))rarr Product formed as?

Answer»




ANSWER :A
Discussion
93623.

, underset(Alc.KOH//Delta)overset(CHClBrI)rarr Appropriate product among the following.

Answer»




ANSWER :A
Discussion
93624.

, underset((2)H_(2)O)overset((1)NaOH)rarr Products formed in two steps are

Answer»




ANSWER :A::B::C::D
Discussion
93625.

, This reaction follows first order kinetics. The rate constant at particular temperature is 2.303xx10^(-2)"hour"^(-1). The initial concentration of cyclopropane is 0.25 M. What will be the concentration of cyclopropane after 1806 minutes? (log 2 = 0.3010)

Answer»

0.125 M
0.215 M
`0.25xx2.303M`
0.05 M

Solution :`k=(2.303/t)log(([A_(0)])/([A]))`
`rArr2.303xx10^(-2)"HOUR"^(-1)=(2.303/(1806 MIN))log(0.25/([A]))`
`rArr((2.303xx10^(-2)"hour"^(-1)xx1806min)/2.303)=log(0.25/([A]))rArr((1806xx10^(-2))/60)=log(0.25/([A]))`
`rArr0.301=log(0.25/([A]))rArrlog2=log(0.25/([A]))rArr2=(0.25/([A]))`
`[A]=(0.25/2)=0.125M`
Discussion
93626.

………………………… the storage form of vitamin A, finds application in proper functioning of our eyes.

Answer»

SOLUTION :RETINOL
Discussion
93627.

, The products above reaction will be :

Answer»




ANSWER :A
Discussion
93628.

, the major product is :

Answer»


`C_(2)H_(5)O-CH_(5)`

ANSWER :A
Discussion
93629.

$: The granules of moder gunpowder (also called black powder) are typically coated with Graphite. !: Graphite prevents the build-up of electrostatic charge.

Answer»

Both the statements are individually true and STATEMENT II is the correct explanation of statement I
Both the statements are individually true but statement II is not correct explanation of statement I
Statement I is true but statement II is false
Statement I is false but statement II is true

SOLUTION :Commercial black POWDER looks black because the little lumps of the stuff are coated with graphite. In the manufacturing process , the pwder's mixedwith water or some other liquid binder, pressed into CAKES and dried, then crushed and screened into powders of various particle size, larger particles producing a slower burn. the graphite serves no chemical purpose, but it libricates the particles, and also makes the bulk powder electrically conductive enough that it is unlikely to initiate proceeding unexpectally because of a static-electricity spark.
Discussion
93630.

. The above reaction is known as

Answer»

Schmidt REACTION
Curtius reaction
HOFMANN REARRANGEMENT
Lossen rearrangement

Answer :A
Discussion
93631.

……………………… test is used to identify primary amine.

Answer»


ANSWER :CARBYLAMINE reaction (or) HOFFMANN MUSTARD oil reaction
Discussion
93632.

(+) tartaric acid has a specific rotation of +12 unit when measured in 12cm polarimeter tube and 2g/ml concentration at given temperature and light. When it is diluted to half the concentration, length of tube and other parameters being same, then the specific rotation will be:

Answer»

`+6 " unit"`
`+12 " unit"`
`-6 " unit"`
`+24 " unit"`

ANSWER :B
Discussion
93633.

_____ takes part in the chlorination of benzene.

Answer»


ANSWER :Chloroniumion `(CL^+)`
Discussion
93634.

.................... stop or slow down the growth of microorganisms used on inanimate objects.

Answer»

SOLUTION :DISINFECTANTS
Discussion
93635.

................. stop or slow down the growth of microorganisms applied to living tissues.

Answer»

SOLUTION :ANTISEPTIC
Discussion
93636.

............ stop negative effect of enzymes and receptors by interacting with them.

Answer»

DRUGS
Acid 
Base
All of the GIVEN 

SOLUTION :Drugs
Discussion
93637.

________________ stimulates the secretion of pepsin and hydrochloric acid.

Answer»

SOLUTION :HISTAMINE
Discussion
93638.

……… solution has highest freezing point.

Answer»

`1 m K_(4)[FE(CN)_(6)]`
1 m NaCl
1 m glucose
1 m KCl

Answer :C
Discussion
93639.

........... solids possess excellent electrical and thermal conductivity.

Answer»

SOLUTION :METALLIC
Discussion
93640.

................ selectively reduces alkyl cyanide to form imines which on hydrolysis gives aldehyde.

Answer»

SOLUTION : Diisobutyl ALUMINUM HYDRIDE
Discussion
93641.

sec-Butylamine is a 1° amine.

Answer»


ANSWER :T
Discussion
93642.

............ salts are used in tanning of leather.

Answer»

SOLUTION :CHROMIUM
Discussion
93643.

.................. reduces fever by causing the hypothalamus to override a prostaglandin-induced increase in temperature.

Answer»

SOLUTION :NON steroidalanti INFLAMMATORY DRUGS ( or ) NSAIDS
Discussion
93644.

.............. reduce the pain without causing impairment of consciousness.

Answer»

SOLUTION :ANALGESICS
Discussion
93645.

........... reactions are faster as compared to reaction involving solid or liquid reactants.

Answer»

SOLUTION :GAS PHASE
Discussion
93646.

............... reaction is generally used for the preparation of esters of higher alcohol from that of a lower alcohol.

Answer»

SOLUTION :TRANSESTERIFICATION
Discussion
93647.

, Rate of reaction toward Beckmann rearrangement wheny= underset((i))CH_(3)CO_(2)^(-),underset((ii))Cl-CH_(2)-Co_(2)^(-),underset((iii))Ph-SO_(3)^(-)

Answer»

(i) gt (ii) gt (iii)
(ii) gt (i) gt (iii)
(iii) gt (ii) gt (i)
(iii) gt (i) gt (ii)

Solution :(C ) Since RDS INVOLVE REMOVAL of leaving group, RATE of reactions compound by leaving group tendency.
`""Ph-SO_(3)^(Θ)gtCl-CH_(2)-CO_(2)^(Θ)gtCH_(3)-CO_(2)^(Θ)`
(weak base good leaving group)
Discussion
93648.

.................... provide relief from allergic effects.

Answer»

SOLUTION :ANTIHISTAMINES
Discussion
93649.

........... protected by gelatin is known as Argyrol.

Answer»

SOLUTION :SILVER SOL
Discussion
93650.

, Product 'P' is as major product

Answer»




SOLUTION :`pH=(1)/(2)[pk_(W)-pk_(b)-logC]`
`pH=(1)/(2)[13-6+2]=4.5`
Discussion