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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 10901. |
Which drug is non-narcotic and analgesic ? |
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Answer» MORPHINE (A) Penicillin is ANTIMICROBIALS, which is used to DESTROY /prevent the development or inhibit the pathogenic action of microbes. (B) Aspirin and paracetamol are non-NARCOTIC and analgesic. (C) Morphine is narcotic and analgesic. (D) Veronal is TRANQUILIZER and sleeping agent. |
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| 10902. |
When 2-bromo-3-methylbutane is treated with aqueous KOH, it follows S_(N)-1 mechanism. The product formed is : |
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Answer» 3-METHYL-2-butanol `CH_(3)-overset(CH_(3))overset("|")underset(H)underset("|")"C "-overset(H)overset(|)underset(Br)underset(|)C-CH_(3)overset(-Br^(-))rarrCH_(3)-overset(CH_(3))overset("|")underset((2^(@)))underset("H ")underset("|")"C "-overset(H)overset(|)underset(o+)C-CH_(3)overset("Hydnde")underset("Shift")RARR underset((3^(@)))(CH_(3)-underset(o+)overset(CH_(3))overset("|")"C "-overset(H)overset(|)underset(H)underset(|)C-CH_(3))` `CH_(3)-underset(o+)overset(CH_(3))overset("|")"C "-overset(H)overset(|)underset(H)underset(|)C-CH_(3)overset(OH^(-))rarr underset("2 - Methyl -2- butanol")(CH_(3)-overset(CH_(3))overset("|")underset(OH)underset("|")"C "-overset(H)overset(|)underset(H)underset(|)C-CH_(3))` |
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| 10903. |
The structure of ortho-phosphoric acid is: |
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Answer» `O larr overset(H)overset(|)UNDERSET(H)underset(|)P-OH` |
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| 10904. |
What is the pH for a neutral solutions at the normal temperature of the human body |
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Answer» 7.2 |
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| 10905. |
Which one of the following is the coordination number of NaCl ? |
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Answer» 3 |
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| 10906. |
Which of the following halogens shows least number of oxidation states? |
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Answer» FLUORINE |
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| 10907. |
Which of the following given crystal system is the most symmetrical and the most unsymmetrical system respectively? |
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Answer» CUBIC, Hexagonal |
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| 10908. |
What is the electronic configuration of Co^(2+) (At. No. 27) ? |
| Answer» Solution :`Co^(2+)(25e)- 1s^(2)2s^(2)2P^(6)3S^(2)3P^(6)3d^(7)` | |
| 10909. |
Which reaction finds application in the separation and purification of carbonyl compound? Explain. |
Answer» Solution : The bisulphite COMPOUND is WATER soluble and the solution is treated with mineral acid to regenerate the carbonyl compound. So the above reaction is USED in the SEPARATION and purification of carbonyl compound. |
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| 10910. |
Which of the following statements with respect to electrochemical principles of metallurgy are not correct? |
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Answer» In simple electrolysis, the `M^(N^(+))` ions are discharged at positive electrodes |
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| 10911. |
Which of the following compounds b ut incorrect IUPAC nomenclature? |
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Answer» `CH_(3)-CH_(2)CH_(2)-COOCH_(2)H_(5)` |
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| 10912. |
Which solution (s) boil at a greater temperature than 1.8% w/v glucose solution ? (mol. Wt =180) |
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Answer» 0.01m UREA solution |
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| 10913. |
Three moles of electrons are passed through three solutions in succession containing AgNO_3, CuSO_4 and AuCL_3 respectively the molar ratio of amounts of cations reduced at cathode will be |
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Answer» `1:2:3` |
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| 10914. |
What 'semin permeable membrene' ? |
| Answer» Solution :For answer, CONSULT SECTION 12 (OSMOSIS and osmotic pressure) | |
| 10915. |
The strength of H_(2)O_(2) (in g/l ) in 11.2 volume solution of H_(2)O_(2) is |
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Answer» 17 |
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| 10916. |
The Van’t Hoff factor calculated from association data is always...than calculatedfrom dissociation data: |
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Answer» LESS |
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| 10917. |
What is the non-stoichiometry defect in the crystals ? |
| Answer» SOLUTION :The POINT DEFECT that does not disturb the geometry of a CRYSTAL is called the non-stoichiometry defect. | |
| 10918. |
Which is not essential oil: |
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Answer» TURPENTINE oil |
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| 10919. |
Write integrated rate equation for a first order reaction. |
| Answer» SOLUTION :`K=2.303/tlog[[R_0]]/[[R]]`where k is RATE CONSTANT | |
| 10920. |
Whatwill bethe emf for the given half cell Pt|H_(2)(P_(1)|H^(+)(aq)|H_(2)(P_(2))|Pt |
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Answer» <P>`(RT)/(F)` in `(p_(1))/(p_(2))` `KHS H_(2) (P_(1)) rarr 2H^(+)+2e^(-)` overall reaction `H_(2) (p_(1)) rarr H_(2) (p_(2))` `E=E^(@)-(RT)/(nF) "in" (P_(2))/(P+(1))=0 -(RT)/(2F)=(RT)/(2F) "in" (P_(1))/(p_(2))` |
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| 10921. |
Which of the given compound do not undergo acid catalyzed hydrolysis? |
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Answer» `PH-O-Ph` |
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| 10922. |
The volume of 0.1M Ca(OH)_(2) required to neutralize 10 mL of 0.1 N HCl |
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Answer» 10 mL `=0.1xx2=0.2` for `Ca(OH)_(2)` `becauseN_(1)V_(1)=N_(2)V_(2)` `therefore0.2xxV_(1)=0.1xx10` `therefore V_(1)=(0.1xx10)/(0.2)=5ml` |
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| 10923. |
Which of the following contains the highest percentage of proteins: |
| Answer» Answer :B | |
| 10924. |
Which of the following are true? |
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Answer» van DER waals forces are reponsible for the FORMATION of molecular crytals |
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| 10925. |
Transition metal and their compounds are used as catalyst in industry and in biological system. For example, in the Contact Process, vanadium compounds in the +5 state (V_(2)O_(5) or VO_(3)^(-)) are used to oxidise SO_(2) to SO_(3): SO_(2)+(1)/(2)O_(2) overset(V_(2)O_(5))(to) SO_(3) It is thought thta the actual oxidation process takes place in two stages. In the first step, V^(5+) in the presence of oxide ions converts SO_(2) to SO_(3). At the same time, V^(5+) is reduced to V^(4+). 2V^(5+)+O^(2-)+SO_(2) to 2V^(4+)+SO_(3) In the second step, V^(5+) is regenerated from V^(4+) by oxygen: 2V^(4+)+(1)/(2)O_(2) to 2V^(5+)+O^(2-) The overall process is, of curse, the sum of these two steps: SO_(2) +(1)/(2)O_(2) to SO_(3) Q. During the course of the reaction: |
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Answer» Catalyst undergoes changes in oxidation state |
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| 10926. |
The species in which the central atom uses sp^(2) hybrid orbitals in its bonding is |
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Answer» `PH_(3)` |
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| 10927. |
Transition metal and their compounds are used as catalyst in industry and in biological system. For example, in the Contact Process, vanadium compounds in the +5 state (V_(2)O_(5) or VO_(3)^(-)) are used to oxidise SO_(2) to SO_(3): SO_(2)+(1)/(2)O_(2) overset(V_(2)O_(5))(to) SO_(3) It is thought thta the actual oxidation process takes place in two stages. In the first step, V^(5+) in the presence of oxide ions converts SO_(2) to SO_(3). At the same time, V^(5+) is reduced to V^(4+). 2V^(5+)+O^(2-)+SO_(2) to 2V^(4+)+SO_(3) In the second step, V^(5+) is regenerated from V^(4+) by oxygen: 2V^(4+)+(1)/(2)O_(2) to 2V^(5+)+O^(2-) The overall process is, of curse, the sum of these two steps: SO_(2) +(1)/(2)O_(2) to SO_(3) Q. Which of the following ion involved in the above process will show paramagnetism? |
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Answer» `V^(5+)` |
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| 10928. |
Which is food presentive as well as anti chlor? |
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Answer» `SO_(2)` |
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| 10929. |
Transition metal and their compounds are used as catalyst in industry and in biological system. For example, in the Contact Process, vanadium compounds in the +5 state (V_(2)O_(5) or VO_(3)^(-)) are used to oxidise SO_(2) to SO_(3): SO_(2)+(1)/(2)O_(2) overset(V_(2)O_(5))(to) SO_(3) It is thought thta the actual oxidation process takes place in two stages. In the first step, V^(5+) in the presence of oxide ions converts SO_(2) to SO_(3). At the same time, V^(5+) is reduced to V^(4+). 2V^(5+)+O^(2-)+SO_(2) to 2V^(4+)+SO_(3) In the second step, V^(5+) is regenerated from V^(4+) by oxygen: 2V^(4+)+(1)/(2)O_(2) to 2V^(5+)+O^(2-) The overall process is, of curse, the sum of these two steps: SO_(2) +(1)/(2)O_(2) to SO_(3) Q. Catalytic activity in transition metals depends on: |
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Answer» Their ABILITY to exist in different OXIDATION states |
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| 10930. |
Write the structure of an isomer of compound C_(4)H_(9)Br whichis most reactive towards S_(N) 1 reaction. |
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Answer» Solution :Isomer of the compound `C_(4)H_(9)BR` which is most reactive towards `S_(N)1` REACTION is `CH_(3) - UNDERSET(CH_(3))underset(|)OVERSET(CH_(3))overset(|)C-Br` |
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| 10931. |
Which of the following is/are formed when ozone reacts with the unburnt hydrocarbons in polluted air ? (i) Formaldehyde (ii) Acrolein(iii) Peroxyacetyl nitrate (iv) Fonnic acid |
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Answer» (i) and (iv) Peroxyacetyle NITRATE (PAN) |
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| 10932. |
Whichof the followinghas lowestkb value ? |
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Answer» BENZENAMINE |
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| 10933. |
Transition metal and their compounds are used as catalyst in industry and in biological system. For example, in the Contact Process, vanadium compounds in the +5 state (V_(2)O_(5) or VO_(3)^(-)) are used to oxidise SO_(2) to SO_(3): SO_(2)+(1)/(2)O_(2) overset(V_(2)O_(5))(to) SO_(3) It is thought theta the actual oxidation process takes place in two stages. In the first step, V^(5+) in the presence of oxide ions converts SO_(2) to SO_(3). At the same time, V^(5+) is reduced to V^(4+). 2V^(5+)+O^(2-)+SO_(2) to 2V^(4+)+SO_(3) In the second step, V^(5+) is regenerated from V^(4+) by oxygen: 2V^(4+)+(1)/(2)O_(2) to 2V^(5+)+O^(2-) The overall process is, of curse, the sum of these two steps: SO_(2) +(1)/(2)O_(2) to SO_(3) Q. Transition metals and their compounds catalyse reactions because: |
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Answer» They have completely filled s-subshell |
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| 10934. |
There are two principal types of electrochemical cells. A galvanic cell is an electrochemical cell that produces electricity as a result of spontaneous reaction occurring inside it. An electrolytic cell is an electrochemical cell in which a non-spontaneous reaction is driven by an external source of current. any redox reaction may be expressed in terms of two half reactions which are conceptual reactions showing the lowss and gain of electrons. each half reaction has a difinite value of standard electrode potential. the overall reaction is represented by a universally accepted method. knowing the standard electrode potential of the half reactions, the standard EMF of the cell can be calculted. the standard EMF further helps in the calculation of free energy change, equilibrium constant of the cell reaction as well as parameters like solublity products of a sparingly soluble salt. a cell can also be set up in which the two electrodes may be of the same (type, e.g., both may be hydrogen electrodes but the concentration of H^(+) ions in the two solutions may be different. Such cells are called concentration cells. Q. The standard reduction for two reactions are given below: AgCl(s)+e^(-)toAg(s)+Cl^(-)(aq),E^(@)=0.22V Ag^(+)(aq)+e^(-)toAg(s),E^(@)=0.80V The solubility product of AgCl under standard conditions of temperature (298K) is given by |
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Answer» `1.6xx10^(-5)` `AgCl(s)hArrAg^(+)(aq)+Cl^(-)(aq),E^(@)=-0.58V` APPLYING Nernst eqn, `E=E^(@)-(0.0591)/(1)"log"([Ag^(+)][Cl^(-)])/([AgCl(s)])` Putting `[AgCl(s)]=1` and at equilibrium E=0 `E^(@)=0.0591log[Ag^(+)][Cl^(-)]=0.0591logK_(SP)` or `-0.58=0.0591logK_(sp)` `logK_(sp)=-9.8139=overline(10).1861` `K_(sp)=1.535xx10^(-10)` |
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| 10935. |
There are two principal types of electrochemical cells. A galvanic cell is an electrochemical cell that produces electricity as a result of spontaneous reaction occurring inside it. An electrolytic cell is an electrochemical cell in which a non-spontaneous reaction is driven by an external source of current. any redox reaction may be expressed in terms of two half reactions which are conceptual reactions showing the lowss and gain of electrons. each half reaction has a difinite value of standard electrode potential. the overall reaction is represented by a universally accepted method. knowing the standard electrode potential of the half reactions, the standard EMF of the cell can be calculted. the standard EMF further helps in the calculation of free energy change, equilibrium constant of the cell reaction as well as parameters like solublity products of a sparingly soluble salt. a cell can also be set up in which the two electrodes may be of the same (type, e.g., both may be hydrogen electrodes but the concentration of H^(+) ions in the two solutions may be different. Such cells are called concentration cells. Q. The standard electrode potential (E^(@)) for OCl^(-)//Cl^(-) and Cl^(-)//(1)/(2)Cl_(2) respectively are 0.94 V and -1.36V. the E^(@) value for OCl^(-)//(1)/(2)Cl_(2) will be |
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Answer» `-0.42V` (i) `OC l^(-)+H_(2)O+2e^(-)toCl^(-)+2OH^(-),E_(1)^(@)=0.94V` (ii) `Cl^(-)to(1)/(2)Cl_(2)+e^(-),E_(2)^(@)=-1.36V` (iii) `OC l^(-)+H_(2)O+e^(-)to(1)/(2)Cl_(2)+2OH^(-),E_(3)^(@)=?` Eqn. (iii) can be obtained by adding eqns. (i) and (ii). hence, in TERMS of their free energies `(DeltaG^(@)=-nFE^(@))` `DeltaG_(3)^(@)=DeltaG_(1)^(@)+DeltaG_(2)^(@)` `-1xxFxxE_(3)^(@)=-2xxFxx(0.94)xx1xxF(xx1.36)` or `E_(3)^(@)=2xx0.94-1.36=0.52V` |
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| 10936. |
Write the structure of following alcohols: |
Answer» SOLUTION : 
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| 10937. |
There are two principal types of electrochemical cells. A galvanic cell is an electrochemical cell that produces electricity as a result of spontaneous reaction occurring inside it. An electrolytic cell is an electrochemical cell in which a non-spontaneous reaction is driven by an external source of current. any redox reaction may be expressed in terms of two half reactions which are conceptual reactions showing the lowss and gain of electrons. each half reaction has a difinite value of standard electrode potential. the overall reaction is represented by a universally accepted method. knowing the standard electrode potential of the half reactions, the standard EMF of the cell can be calculted. the standard EMF further helps in the calculation of free energy change, equilibrium constant of the cell reaction as well as parameters like solublity products of a sparingly soluble salt. a cell can also be set up in which the two electrodes may be of the same (type, e.g., both may be hydrogen electrodes but the concentration of H^(+) ions in the two solutions may be different. Such cells are called concentration cells. Q. The reaction (1)/(2)H_(2)(g)+AgCl(s)toH^(+)(aq)+Cl^(-)(aq)+Ag(s) occurs in the galvanic cell |
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Answer» `Ag|AgCl(s)|KCL(aq)|AgNO_(3)(aq)|Ag` |
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| 10938. |
The spin only magnetic moment value (in Bohr magnetion units) of Cr(CO)_(6) is |
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Answer» 0 `._(24)Cr=[Ar] 3d^(5)4s^(1)` As CO is a STRONG ligand, all the six unpaired electrons will PAIR up, i.e., there will be no unpaired electron. HENCE, `mu=0` |
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| 10939. |
There are two principal types of electrochemical cells. A galvanic cell is an electrochemical cell that produces electricity as a result of spontaneous reaction occurring inside it. An electrolytic cell is an electrochemical cell in which a non-spontaneous reaction is driven by an external source of current. any redox reaction may be expressed in terms of two half reactions which are conceptual reactions showing the lowss and gain of electrons. each half reaction has a difinite value of standard electrode potential. the overall reaction is represented by a universally accepted method. knowing the standard electrode potential of the half reactions, the standard EMF of the cell can be calculted. the standard EMF further helps in the calculation of free energy change, equilibrium constant of the cell reaction as well as parameters like solublity products of a sparingly soluble salt. a cell can also be set up in which the two electrodes may be of the same (type, e.g., both may be hydrogen electrodes but the concentration of H^(+) ions in the two solutions may be different. Such cells are called concentration cells. Q. If hydrogen electrodees dipped in two solutions of pH=3 and pH=6 are connected by a salt bridge, the emf of the resulting cell is |
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Answer» 0.177 V `H_(2)|H^(+)(c_(1))||H^(+)(c_(2))|H_(2)` `E_(cell)=(0.0591)/(1)"LOG"(c_(2))/(c_(1))=0.0591"log"(10^(-3))/(10^(-6))` `=0.0591xx3=0.1773V`. |
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| 10940. |
Which of the following pairs constitutes a buffer ? |
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Answer» NaOH and NaCl |
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| 10941. |
Which of the following statement(s) is/are incorrect regarding S_N 1 reaction? I) Rearrangement is possible. II) Proceeds with complete inversion of configuration. III) Rate depends on polarity of solvent. IV) The strength of the nucleophile is important in rate determining step. |
| Answer» Answer :A | |
| 10942. |
What is the hybrid state and oxidation state of sulphur in Caro's acid ? |
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Answer» `sp^2,+10` |
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| 10943. |
Three Faraday's of electricity are passed through molten Al_2O_3,aq. solution of CuSO_4 and molten NaCl taken in three different electrolytic cells. The amounts of Al, Cu and Na deposited at the electrodes will be |
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Answer» 1 mole : 2 MOLES: 3 moles |
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| 10944. |
Which of the following is not correct regarding sucrose? |
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Answer» Acid CATALYSED hydrolysis of sucrose yields I mole of D-glucose and 1 mole of L-fructose. Sucrosedoes.t undergo MUTAROTION BECAUSEOF nothavinghemiacetal form . |
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| 10945. |
The S.I. unit of pressure is : |
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Answer» TORR |
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| 10946. |
Write the names of monomers of the following polymers : (i)[-overset(H)overset(|)(N) -(CH_(2))_(6)- overset(H)overset(|)(N) - overset(O)overset(||)(C) - (CH_(2))_(4) - overset(O)overset(||)(C)-]_(n) (ii) [-overset(O)overset(||)(C) - (CH_(2))_(3)- overset(H)overset(|)(N) - ]_(n)(iii) [-CF_(2) - CF_(2)-]_(n) |
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Answer» Solution : Ans. ( Hexamethylenediamine, `H_(2)N-(CH_(2))_(6)—NH_(2)`, and adipic ACID, `HOOC - (CH)_(4) – COOH` (ii) Caprolactam (iii) Tetrafluoroethene, `F_(2)C = CF_(2)` |
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| 10947. |
There are nine elements A to I. these are belongs to p-block element other than halogen. If atomic number of B is average of atomic number of A and C and atomic number of E is average of atomic number of D and F and atomic number of H is average of atomic number of G and I. atomic numbers of B, E and H are 7,15 and 83 respectively and atomic numbers of C, I and F are greater than A, G and D respectively. Q. The incorrect order is: |
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Answer» `F GT E`: Second IONISATION energy |
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| 10948. |
Which of the following polymers can be used for lubrication and as an insulator? |
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Answer» SBR |
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| 10949. |
The volatility of HF is low because of : |
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Answer» its LOW polarizability |
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| 10950. |
Which one of the followin reactionyield diacetone alcohol from carbonyl compound ? |
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Answer» CANNIZZARO's reaction `CH_(3)COCH_(3) + CH_(3)COCH_(3) OVERSET(Ba(OH)_(2)) to CH_(3)C(OH) (CH_(3))CH_(2)COCH_(3)` |
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