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11451.

Which of the following compounds would undergo Cannizzaro's reaction

Answer»

P ropionaldehyde
Benzaldehyde
BROMOBENZENE
Acetaldehyde

ANSWER :B
11452.

The value of B.M in SI units is

Answer»

`9.273 xx 10^(-23)J.T^(-1)`
`9.273 xx 10^(24)J.T^(-1)`
`9.273 xx 10^(-24)J.T^(-1)`
`9.273 xx 10^(23)`

Solution :`9.273 xx 10^(-24)J.T^(-1)`
11453.

Which of the following statements is correct regarding the following reaction ?

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ANSWER :B::C
11454.

What are the products of hydrolysis of lactose ?

Answer»

SOLUTION :`beta-D-`GALACTOSE and `beta-D-`GLUCOSE.
11455.

What is smelting?

Answer»

Solution :Smelting is a PROCESS of REDUCING the roasted metallic oxide to metal in molten condition .In this process,IMPURITIES are removed by the ADDITION of flux as slag.
11456.

What is the general formula of Quinol ?

Answer»

`C_(6)H_(6)O_(2)`
`C_(6)H_(8)O_(2)`
`C_(6)H_(5)O_(2)`
`C_(7)H_(8)O_(2)`

SOLUTION :`C_(6)H_(6)O_(2)`
11457.

The standard emfof a galvaniccellinvolvingcellreactionwith n=2 is found to be 0.295 v at 25^(@)cthe equilibrium constantof thereactionwouldbe(Given F= 96500 C "mol"^(-1)m R =8 .314 "jk"^(-1) "mol"^(-1) )

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`2.0 xx10^(11)`
`4.0 xx10^(12)`
`1.0xx10^(2)`
`1.0 xx10^(10)`

Solution :By NERNST equation`E_(CELL) =E_(cell)^(@)-(2.303 RT)/(nF) log_(120) k`
At equilibriuim `E_(cell) =0`
Given that`R= 8.315 JK^(-1) mol^(-1)`
`therefore E_(Cell)^(@) =(0.0591)/(2) log_(10) K`
`because` Giventhat `E_(cell)^(@) =0.295 V`
`k=1xx10^(10)`
11458.

Which of the following reactions do not give 1^(0) amine ?

Answer»

`Ph-overset(CH_(3))overset(|)CH-OH overset(NaCN,H^(o+))to`
`Ph-CH=CH-overset(O)overset(||)C-NH_(2)overset(NaOCl)UNDERSET(CH_(3)OH)to`
`Ph-C-=C-overset(O)overset(||)C-NH_(2)overset(NAOBR)to`
`Ph-overset(O)overset(||)C-Cl overset(NaN_(3))underset(Delta)to overset(LiAlH_(4))to`

Solution :b,c,d do not give `1^(@)` amine
11459.

Two substances A and B are present such that [A_(0)]=4[B_(0)] and half-life of A is 5 minutes and that of B is 15 minutes . If they start decaying at the same time following first order kinetics how much time later will the concentration of both of them would be same ?

Answer»

`15` minutes
`10` minutes
`5` minutes
`12`minutes

Solution :AMOUNT of A left in `n_(1)` half-lives `=((1)/(2))^(n_(1))[A_(0)]`
Amount of B left `n_(2)` half-lives `=((1)/(2))^(n_(2))[B_(0)]`
At the END, `([A_(0)])/(2^(n_(1)))=([B_(0)])/(2^(n_(2)))`
`implies(4)/(2^(n_(1)))=(1)/(2^(n_(2))){[A_(0)]=4[B_(0)]}`
`:.(2^(n_(1)))/(2^(n_(2)))=4implies2^(n_(1)-n_(2))=(2)^(2)`
`:.n_(1)-n_(2)=2`
`:.n_(2)=(n_(1)-2)`
Also, `t=n_(1)xxt_(1//2(B))t=n_(2)xxt_(1//2)(B))`
(LET, concentration of both become equal after time `t`)
`:.(n_(1)xxt_(1//2(A)))/(n_(2)xxt_(1//2(B)))=1implies(n_(1)xx5)/(n_(2)xx15)=1implies(n_(1))/(n_(2))=3`
From Eqs. `(1)` and `(2)`, we get
`n_(1)=3`, `n_(2)=1`
`t=3xx5=15` minutes
11460.

Which of the following tests could be performed to distinguish between 1-butyene ?

Answer»

METHANOL
`2,2`-dimethylpropanol
`ALPHA`-haloethanol
methanal

Solution :N//A
11461.

Which of the following is the correct unit for measuring nuclear radii?

Answer»

Micron
Millimetre
Angstrom
Ferni

Answer :D
11462.

What may be the stable oxidation state of the transition element with the following d-electron configuration in the ground state of their atoms: 3d^(3), 3d^(5), 3d^(8) and 3d^(4)?

Answer»

SOLUTION :(i) `3d^(3)`: Stable oxidation STATE will be `(+5)` DUE to outer electronic configuration `3d^(3) 4S^(2) (+2, +3,+4,+5)`.
(ii) `3d^(5)`: The outer electronic configuration is `3d^(5) 4s^(2)`, so stable. Oxidation state will be (+2) to (+7) i.e., `(+2), (+3),(+4),(+6),(+7)`
(iii) `3d^(8)`: Stable oxidation state will be (+2) as outer electronic configuration is `3d^(8) 4s^(2) ["(+2)", (+3),(+4)]`
(iv) `3d^(4)`: There is no `d^(4)` configuration in the ground state. The ground state configuration becomes `3d^(5) 4s^(1)`. The stable oxidation state will be `(+3) and (+6)`.
11463.

Write the chemical reaction for the reduction of nitroethane by LiAIH_4

Answer»

SOLUTION :`underset("NITROETHANE")(CH_3 CH_2 NO_2) +6 [H] overset(LiAIH_4 //"ether")tounderset("Ethanamine ")(CH_3 CH_2 NH_2+2H_2 O)`
11464.

Zinc oxide is used in:

Answer»

PAPER bleaching
White paint
Black glasses
Soaps

Answer :B
11465.

Which of the following halogen oxides is ionic:

Answer»

`I_4O_9`
`I_2O_5`
`BrO_2`
`ClO_3`

ANSWER :A
11466.

Which of the following is used as a preservative to prevent spoilage of food?

Answer»

SODIUM sulphate
saccharin
sodium benzoate
ethyl ethanoate

Answer :C
11467.

Which of the following alkenes when passed through conc. H_(2)SO_(4) followed by hydrolysis with boiling water would give tert-butyl alcohol

Answer»

ETHYLENE
ISOBUTYLENE
PROPYLENE
n-Butylene

ANSWER :B
11468.

Which of the following methods of preparation of amines will not give same number of carbon atoms in the chain of amines as in the reactant?

Answer»

Reaction of nitrite with `LiAlH_4`
Reaction of AMIDE with `LiAlH_4`followed by treatment with water
Heating ALKYLHALIDE with POTASSIUM salt of phthalimide followed by hydrolysis
Treatment of amide with bromine in aqueous solution of sodium hydroxide.

Solution :`underset("Amide")(RCONH_2)OVERSET(Br_2 //NaOH)tounderset("Amine with one C-atom less than the amide")(RNH_2)`
Only treatment of amide with `Br_2` in aqueous solution of NaOH wil give an amine with lesser NUMBER of carbon atoms than in the reactant.
11469.

The standard e.m.f. for the cell reaction,2Cu^(+)(aq) to Cu(s) + Cu^(2+)(aq) is + 0.36V at 298 K. The equilibrium constant of the reaction is

Answer»

`5 XX 10^6`
`1.4 xx 10^12`
`7.4 xx 10^12`
`1.3 xx 10^6`

ANSWER :D
11470.

The source of most of the noble gases is:

Answer»

decay of radioactive minerals
The atmospheric air
The natural gases coming out of the carth
The decay of the rocks

Solution :the MAIN FORCE of NOBLE gases are air, air is the POTENTIAL sourace of the first fize Noble gases.
11471.

The removal of two atoms or groups one generally hydrogen (H^(+)) and the other a leaving group (L^(-)) resulting in the formation of unsaturated compound is known as elimination reaction. In E_(1) (elimination) reactions the C-L bond is broken heterolytically (in step 1) to form a carbocation (as inS_(N^(1)) reaction) in which (L^(-)) is lost (rate determining step). The carbocation (in step 2) loses a proton from the beta- carbon atom by a base (nucleophile) to form an alkene. E_(1) reaction is favoured in compounds in which the leaving group is at secondar (2^(@)) or tertiary(3^(@)) Position. In E_(2) (elimination) reactions two sigma bonds are broken and a pi-bond is formed simultaneously.E_(2) reactions occur in one step through a transition state. E_(2) reactions are most common in haloalkanes (particulary 1^(@)) and better the leaving group higher is the E_(2) reaction. In E_(2) reactions, both the leaving groups should be antiplaner. E_(1) cb (Elimination unimolecular conjugate base) reaction involves the removal of proton by a conjugate base (step 1) to produce carbanion which loses a leaving group to form an alkene(step 2) and is a slow step 2-Bromopentane is heated with potassium ethoxide in ethanol. The major product obtained is :

Answer»


2-Ethoxypentanetrans-pent-2-ene

Solution :N//A
11472.

To which colloidal system does milk belong?

Answer»

SOLUTION :EMULSION of FATS DISPERSED in WATER.
11473.

The unstable oxidation of Sm is

Answer»

`+4 and +3`
`+4`
`+3`
`+2`

ANSWER :D
11474.

Two liquids A and B on mixing produce a warm solution. Which type of deviation from Raoult's law does it show?

Answer»

Solution :Warming up of the solution MEANS that be PROCESS of MIXING is EXOTHERMIC, i.e., `DeltaH_("mixing")=-ve.` This implies that the solution shows a NEGATIVE deviation.
11475.

When a crystal of the solute is introduced into a super saturated solution of the solute

Answer»

the SOLUTE DISSOLVES
the excess solute crystallises out
the SOLUTION becomes unsaturated
the solution remains super SATURATED

Solution :Super saturated state is metastable state.
11476.

Which one of the following is a non steroidal anti inflammatory drug?

Answer»

ASPIRIN
morphine
haloperidol
IBUPROFEN

Solution :ibuprofen
11477.

Which of the following has tetragonal system?

Answer»

`CaSO_4` 
`K_2Cr_2O_7`
ZNO 
All of these 

ANSWER :A
11478.

Which oxide does not act as a reducing agent ?

Answer»

NO
`NO_(2)`
`N_(2)O`
`N_(2)O_(5)`

ANSWER :4
11479.

The relative strength of inter-ionic/ intermolecular forces in the decreasing order is :

Answer»

ion-dipole `gt` dipole-dipole `gt` ion-ion 
dipole-dipole `gt` ion-dipole `gt` ion-ion 
ion-ion `gt` ion-dipole `gt` dipole-dipole 
ion-dipole `gt` ion-ion `gt` dipole-dipole 

SOLUTION :Ion-ion interactions are stronger because they have stronger electrostatic forces of attraction WHEREAS DIPOLES have PARTIAL CHARGES and hence the electrostatic forces in their case would be relatively weak.
11480.

Which of the following petroleum corresponds to kerosene oil

Answer»

`C_15-C_18`
`C_10-C_12`
`C_5-C_9`
`C_1-C_9`

ANSWER :B
11481.

Transition metals and their compounds contain catalystic property, because….

Answer»

they POSSESS MAGNETIC PROPERTY
they are chemically reactive
their d-orbitals are incompeletly filled
they possess the property to have more than one OXIDATION state

Answer :D
11482.

Which of the following is liquid at room temperature ?

Answer»

`CH_(3)I`
`CH_(3)Br`
`CH_(3)CH_(2)CL`
`CH_(3)F`

ANSWER :1
11483.

What volume of 0.25mol of oxygen occupy at 8.2atm pressure and 127^(@)C according to ideal gas law ?

Answer»

1L
1.5L
0.1L
4.5L

Solution :`V = ( NRT)/( p ) = ( 0.25 XX 0.082 xx 400)/( 8.2 ATM) = 1L`
11484.

Which of the following an reaction with H_(2)S will produce metal sulphide?

Answer»

`COCl_(2)`
`CuCl_(2)`
`[Cd(CN)_(4)]^(2-)`
`[Zn(OH)_(4)]^(2-)`

SOLUTION :B. `CuCl_(2)+H_(2)StoCuS+2HCl`
C. `[Cd(CN)_(4)]^(2-)+H_(2)StoCdS+2H_(+)+4CN^(-)`
D. `(Zn(OH)_(4)]^(2-)+H_(2)StoZnS+2OH^(-)+2H_(2)O`
11485.

Which of the following is not an endothermic reaction

Answer»

Dehydrogenation
Ethane to ethene
Combustion of propane
Change of chlorine MOLECULE into chlorine atoms

Solution :The enthalpy of combustion i.e., `DeltaH` is ALWAYS NEGATIVE . It means combustion is an exothermic reaction
11486.

The statement " if0.003 molesof a gasaredissolvedin 900g ofwaterunder a pressureof1 atmosphere , 0.006 moleswill bedissolvedundera pressureof2 atmospheres". Illustrates : ____.

Answer»

Dalton'slawof PARTIAL PRESSURE
GRAHAM's law
Roault'slaw
HENRY's law

Answer :D
11487.

Which is most readily nitrated

Answer»

Benzene
PHENOL
Aniline
Nitrobenzene

Solution :Phenol is most EASILY NITRATED
11488.

Which of the following compounds exhibits stereoisomerism?

Answer»

2-Methylbutanoic ACID
2-Methyl-1-butene
3-Methyl BUTANOIC acid
3-Methyl-1-butene

ANSWER :A
11489.

Writethenameofthemethodofconcentratedappliedforthefollowingores:(i) Zincblende (ii) Haematite (iii) Bauxite

Answer»

SOLUTION :(i) ZINC blende-Frothfloatationsinceitisasulphideore.
(II) Haematite-Hydraulicwashingsince oreparticles are heavierthanimpuritiesofsilicaandclay.
(III) Bauxite-LeachingwithNaOHsinceoreparticlesaresolubleinNaOHbutimpuritiesare not.
11490.

What happens when a freshly prepared precipitate of Fe(OH)_3 is shaken with a small amount of FeCl_3 solution ?

Answer»

Solution :When a FRESHLY prepared PRECIPITATE of `Fe(OH)_3` is shaken with a small amount of `FeCl_3` solution, we obtain a colloidal solution of `Fe(OH)_3`. This process is KNOWN as PEPTISATION
11491.

Which of the following Freundlich adsorption isotherm represents the adsorption of a gas by a solid (P_s=Saturation pressure)

Answer»


(##AAK_MCP_21_NEET_CHE_E21_010_Q02##)
(##AAK_MCP_21_NEET_CHE_E21_010_Q03##)

ANSWER :A
11492.

Which of the following equation solution will have higher boiling point at1atm. Pressure ?

Answer»

`1M FeCl_(3)`
`1M CaCl_(2)`
`1MKCl`
1 M Urea `[CO(NH_(2))_(2)]`

SOLUTION :Concentration of particles is MAXIMUM in `FeCl_(3)` solution so ELEVATION of boiling point will be maximum and so actual boiling point will be HIGHEST.
11493.

Which of the following packing is more efficient:

Answer»

square CLOSE - PACKING
hexagonal close pakcing
tetrahedral arrangeement
pentagonal arrangement

ANSWER :B
11494.

Which of the following statements is right in a compound

Answer»

a halogen ATOM bonded to sp-c arbon atom is an alkyl HALIDE
a halogen atom bonded to spa.carbon atom is an ALKYLHALIDE
a halogen atom bonded to sp-carbon atom is an alkylhalide
a halogen atom bonded to any TYPE of carbon - atom is an alkyl halide

Answer :A
11495.

Under what conditions, glucose is converted to gluconic acid and saccharic acid ?

Answer»

Solution :Glucose is CONVERTED to gluconic ACID when oxidized by `Br_(2)//H_(2)O`and oxidized to saccharic acid in presence of conc. `HNO_(3)`
`{:(""CHO),("|"),(" "(CHOH)_(4)),("|"),(""CH_(2)OH):}overset(Br_(2)"WATER")rarrunderset("Gluconic acid")({:(""COOH),("|"),(" "(CHOH)_(4)),("|"),(""CH_(2)OH):})`
`{:(""CHO),("|"),(" "(CHOH)_(4)),("|"),(""CH_(2)OH):}overset("Conc. "HNO_(3))rarrunderset("Saccharic acid")({:(""COOH),("|"),(" "(CHOH)_(4)),("|"),(""COOH):})`
11496.

Vapour pressure of pure acetone and chloroform at 328 K are 741.8 mm Hg and 632.8 mm Hg respectively. Assuming that they form ideal solution over the entire range of composition, plot P_("total"), P_("chloroform"), and P_("acetone") as a function of x_("acetone"). The experimental data observed for different compositions of mixture is :{:(100x x_("acetone"),0,11.8,23.4,36.0,50.8,58.2,64.5,72.1),(P_("acetone")//mm Hg,0,54.9,110.1,202.4,322.7,405.9,454.1,521.1),(P_("chloroform")//mm Hg,632.8,548.1,469.4,359.7,257.7,193.6,161.2,120.7):}From the question, we have the following data.

Answer»

SOLUTION :`{:(x_("ACETONE"),0,11.8,23.4,0.360,0.508,0.582,0.645,0.721),(P_("acetone")//mm Hg,0,54.9,110.1,202.4,322.7,405.9,454.1,521.1),(P_("chloroform")//mm Hg,632.8,548.1,469.4,359.7,257.7,193.6,161.2,120.7),(P_("total"),632.8,603.0,579.5,562.1,580.4,599.5,615.3,641.8):}`

It can be observed from the graph that the plot for the `P_("total")` to the solution curves DOWNWARDS. Therefore, the solution shows NEGATIVE deviation from the IDEAL behaviour.
11497.

Which of the compound show optical isomerism ? 1.cis-[Co(NH_(3))_(4)Cl_(2)]^(+) ""2.trans-[Co(en)_(2)Cl_(2)]^(+) 3. cis-[Co(en)_(2)Cl_(2)]^(+)"" 4.[Co(en)_(3)]^(3+) Select the correct answer using the codes given below:

Answer»

1 and 2
2 and 3
3 and 4
1,3 and 4

Solution :(1) `cis-[Co(NH_(3))_(4)Cl_(2)]^(+)` has plane of symmetry as well as centre of symmetry , so OPTICALLY inactive.
(2) `trans-[Co(en)_(2)Cl_(2)]^(+)` has plane of symmetry as well as centre of symmetry , so optically inactive.
(3 ) `cis-[co(en)_(2)Cl_(2)]^(+)` lacks plane of symmetry as well as centre of symmetry , so optically active.
(4) `[Co(en)_(3)]^(3+)` lacks AXIS of INTERNAL rotation, so optically active.
11498.

Which of the following pairs of ions are isoelectronic and isostructural?

Answer»

`CO_(3)^(2-),NO_(3)^(-)`
`CIO_(3)^(-),CO_(3)^(2-)`
`SO_(3)^(2-),NO_(3)^(-)`
`ClO_(3)^(-),SO_(3)^(2-)`

SOLUTION :NO. of electrons in `CO_(3)^(2-) = 6 + 3 xx 8 + 2 = 32, "" ` No. of electrons in `NO_(3)^(-) = 7 + 3 xx 8 + 1 = 32`
Thus `CO_(3)^(2-)` and `NO_(3)^(-)` are ISOELECTRONIC.
Further both `CO_(3)^(2-)` and `NO_(3)^(-)` are planar since C as well N atoms are `sp^2` hybridized
11499.

The total number of electrons present in 18mL. Water(density 1g/mL) is:

Answer»

`6.023xx10^(23)`
`6.023xx10^(24)`
`6.023xx10^(25)`
`6.023xx10^(21)`

Solution :MASS =18g
NUMBER of molecules of `H_(2)O` in 18g mass `=6.023xx10^(25)`
Number of electrons in 18g water `=6.023xx10^(@3)xx10`
`=6.023xx10^(24)`
`because ` Each MOLECULE of water contains 10 electrons.
11500.

Which is solubein NaNO_(2)and dil HClformingsalt ?

Answer»

`(CH_(3))_(3)CNH_(2)`
`(CH_(3))_(2)CHNH_(2)`
`(CH_(3))_(2)NH`
`(CH_(3))_(3)N`

Solution :Tertiaryaminesolubelin `NaNO_(2)`+ HClformingwatersolublesalt.
`(CH_(3))_(3) N + HNO_(2) to (CH_(3))_(3) NH^(+) Cl^(-)`