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13651.

Which one of the following undergoes reaction with 50% sodium hydroxide solution to give the corresponding alcohol and acid

Answer»

Phenylmethanal
ethanal
ethanol
methanol

Solution :Phenylmethanal
13652.

The structure of the intermediate formed in the Riemer Tiemann reaction is :

Answer»





SOLUTION :
13653.

Two hybrid orbitals have a bond angle of 120^(@). The percentage ofp-character in the hybrid orbital is nearly:-

Answer»

`25%`
`33%`
`50%`
`66%`

Solution :Bond angle `120^(@)`means `SP^(2)` HYBRIDISATION % P character is 66%
13654.

Which of the two components of starch in water soluble ?

Answer»

SOLUTION :AMYLOSE is water SOLUBLE but amylopectin is water INSOLUBLE.
13655.

Which is correct about the heat of combustion:

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The combustion be EXOTHERMIC in some CASES and endothermic in other cases.
Heat of combustion is always exothermic
Its VALUE change with temperature
All

Answer :D
13656.

The treatment of an alkyl halide with underline("silver cyanide ")forms an alkyl cyanide.

Answer»

Solution :The treatment of an ALKYL HALIDE with KCN FORMS an alkyl cyanide.
13657.

Which of the metal is extracted by Hall-Heroult process ?

Answer»

Al
Ni
Cu
Zn

Answer :A
13658.

Which of the following statements about liquid nitrogen is true

Answer»

It is unreactive
It is USED in cryosurgery
It does not decomposes organic compounds
It is very stable

Solution :Cryosurgery is the application of EXTREME cold to destroy abnormal or diseased TISSUE. Liquid or active nitrogen is used as a cooling solution. The super-cooled liquid is sprayed on diseased tissue circulated through a tube called cryophobe.
13659.

The value of paramagnetic moment of Ti^(3+) ion in Bohr magnetons is

Answer»

`5.9`
`1.73`
`2.84`
`3.87`

ANSWER :B
13660.

Which iscorrect for EA ?

Answer»

`CIgtFgtBrgtIgtS`
`O^(_)gtOgtO^(+)`
`S^(-)O^(-)`
`CIgtFgtSgtOgtNgtP`

ANSWER :A
13661.

What are 'X' and 'Y' respectively?

Answer»




ANSWER :B
13662.

Which of the following reacts fastest with concentrated HCI?

Answer»



`(CH_(3))_(3)COH`
`CH_(2)=CH-CH_(2)OH`

Solution :The rate of REACTION depends upon the stability of the carbocations. Out of the following four carbocations possible (i) `C_(6)H_(5)CH_(2)CH_(2)` (ii) `C_(6)H_(5)CHCH_(3)` (iii) `(CH_(3))_(3)C^(+)` (IV) `CH_(2)=CHCH_(2)`
Carbocation (ii) is the most stable since it is not only a `2^(@)` carbocation but is also stabilized by RESONANCE. HENCE alcohol (b) reacts at the fastest rate.
13663.

Why soaps do not work in hard water ?

Answer»

Solution :In hard WATER soapsreactswith calciumandmagnesium ions of hard waterto forminsoluble SOAP. Hencesoaps do notwork in hard water.
`2C_(17)H_(36)COONa + underset("INSOLUBLE calium STERATE")(CaCI_(3) to (C_(17)H_(36)COO)CA)+ 2NaCl`
13664.

Which of the molecules below will react with Ag^(+)?

Answer»

<P>(P), (R ) and (T)
(Q) and (S)
(S) and (U)
(P), (Q),(R ) and (U)

SOLUTION :N//A
13665.

Which of the following statements about Na_(2)O_(2) is not correct ?

Answer»

`Na_(2)O_(2)` oxidises `CR^(3+)` to `CrO_(4)^(2-)` in acid medium
It is diamagnetic in nature
It is the super oxide of sodium
It is a derivative of `H_(2)O_(2)`

ANSWER :C
13666.

What is the oxidation number of nitogen in nitrous oxide.

Answer»

SOLUTION :O.N. of N in NITROUS OXIDE is +1
13667.

What happens when formaldehyde is treated with methanol in the presence of conc. H_(2)SO_(4)?

Answer»

SOLUTION :Methylal is FORMED. `HCHO+2CH_(3)Ohoverset("Conc. "H_(2)SO_(4))RARR underset("Methylal")(CH_(2)(OCH_(3))_(2))+H_(2)O`
13668.

Which one of the following statements are true? (1) Transition metals from alloys (2) Transition metals form complexes (3) Zn, Cd and Hg are transition metals (4) K_(2)[PtCl_(6)] is a well known compound, but corresponding nickel compound is not known.

Answer»

1, 2
2, 4
1, 2, 4
2, 3, 4

Answer :C
13669.

Which of the following acid remains unaffected on heating ?

Answer»

Malonic acid
Maleic acid
Fumaric acid
Succinic acid

Solution :
13670.

Write name and structure of monomers of following polymer : Polythene

Answer»

SOLUTION :ETHENE
`H_2C = CH_2`
13671.

Which of the following amino acid at isoelectric point will react with nitrous acid and liberate nitrogen gas ?

Answer»

Phenylalanine
Isoleucine
Lysine
Proline

Solution :Lysine CONTAIN -`NH_(2)` group in its Zwitterion STRUCTURE, so it will react with NITROUS acid and liberate nitrogen gas.
13672.

Which of the following is not sex hormones?

Answer»

testosterone
estrogen
Progesteron
Thyroxin

Answer :D
13673.

The vitamin which maintain the redox potentials of cells is

Answer»

FOLIC ACID
ASCORBIC acid
PYRIDOXINE
Calciferol

Answer :B
13674.

Which of the following amine(s) after diazotization will form deeply coloured azodye with alkaline solution of beta-naphthol :

Answer»




SOLUTION :B,C,d
13675.

Which of the following is not a property of Metallic Solids?

Answer»

Malleability
Ductility
Thermal and ELECTRICAL Conductivity
Insulator

Answer :D
13676.

Which one is not correct ?

Answer»

`t_(1//2)` of zero ORDER REACTION is DEPENDENT of initial CONCENTRATION of reactant
`t_(1//2)` of first order reaction is dependent of initial concentration of reactant
Rate of zero order reaction does not depend upon initial concentration of reactant
Rate of zero order reaction depend upon initial concentration of reactant

Answer :D
13677.

Which of the following statements about the interstitial compounds is incorrect-

Answer»

they have higher MELTING POINTS than the pure metal
they RETAIN metallic CONDUCTIVITY
they are chemically reactive
they are much harder than the pure metal

Answer :C
13678.

Which statement about the order of reaction is correct:

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The order .of reaction MUST be a positive integer
A SECOND order reaction is ALSO bimolecular
The order of reaction INCREASES with increasing temperature
The order of reaction can only be determined by experiment

Answer :D
13679.

Which one of the following is called a carbylamine

Answer»

`RCN`
`RCONH_(2)`
`RCN=NH`
`N NC`.

ANSWER :D
13680.

Which gas is evolved by the treatment of magnesium with very dilute solution of HNO_(3)

Answer»

`N_(2)`
`NO_(2)`
`H_(2)`
`H_(2)O`

Solution :Magnesium and DILUTE `HNO_(3)` reacts to produce `H_(2)` gas this nitrate decomposes on heating to give `NO_(2)` and `O_(2)`
`Mg +underset("nitric acid")underset("Dilute")(2HNO_(3)) to Mg(NO_(3))_(2)+underset("Hydrogen")(H_(2)uarr)`
`2Mg(NO_(3))_(2) OVERSET(DELTA)to2MgO +4NO_(2)+O_(2)`
13681.

The specific conductance of a salt of 0.01M solution is 1.061xx10^(-4)ohm^(-1)cm^(-1) . Molar conductance of a same solution is ( in ohm^(-1)cm^(2)"mole"^(-1))

Answer»

`1.061xx10^(-4)`
`1.061`
10.61
106.1

Answer :C
13682.

The4d and 5d series of transition metals have more frequent metal - metal bonding in their compounds than do the 3d metals. Explain

Answer»

Solution :In the same group of d-block elements, the 4D and 5d transition elements have larger size than that of 3d ELEMENT. Thus, the valnece electrons are LESS tightly held and hence can form metal-metal bond more frequently .( That is why melting point of4d and 5d SERIES as well as enthalpies of atomisationn are higher than those of 3d series ).
13683.

Which of the following have an (18 + 2) electron configuration ?

Answer»

`PB^(2+)`
`Cd^(2+)`
`BI^(3+)`
`SO_4^(2-)`

Answer :A::C
13684.

The sum of ns and (n-l)d electrons in Tc are

Answer»


SOLUTION :`TC-[KR] 4d^5 5d^2`
13685.

Which one is Lewis acid ?

Answer»

`PCl_(3)`
`AlCl_(3)`
`NCl_(3)`
`AsCl_(3)`.

Answer :B
13686.

When ethyl alcohol is oxidised by copper, then which of the following aldehyde is formed ?

Answer»

FORMALDEHYDE
Acetyldehyde
Benzaldehyde
Crotonaldehyde

Solution :We know that , `CH_3CH_2OH overset"Cu/573 K"to CH_3CHO + H_2`
THUS PRIMARY alcohol which is ETHYL alcohol `(CH_3CH_2OH)` is reduced by copper and forms acetaldehyde `(CH_3CHO)`
13687.

Why alcohols cannot be used as solvents with (a) Grignard reagent

Answer»

Solution :Alcohols are sufficiently acidic to react with STRONG BASES `R^(-) : and H^(-)` :
`CH_(3)OH+H-overset(H)overset(|)underset(H)underset(|)C-MgX rarr CH_(4)+(CH_(3)O)-MgX`
`4CH_(3)OH+LiAlH_(4)rarr 4H_(2)+LiAl(OCH_(3))_(4)`
13688.

Which one of the following compounds does not form an ozonide

Answer»

Ethene
Propyne
Propene
PROPANE

Solution :Propane is a SATURATED compound. Ozonide is formedonly by ALKENES or ALKYNES
13689.

Which of the following order is correct for the property mentioned in brackets?

Answer»

`S^(2-) GT Cl^(-) gt K^(+) gt Ca^(+)" (Ionization energy)"`
`C lt N lt F lt O" (2nd Ionization energy)"`
`B gt Al gt Ga gt In gt Tl" (ELECTRONEGATIVITY)"`
`Na^(+) gt Li^(+)GTMG^(3+) gt Be^(2+) gt Al^(3+)"(lonic radius)"`

Answer :B
13690.

Volume of 0.5 M Ba (OH)_(2) require to neutralize 100 ml 0.8 M H_(3) PO_(3) is :

Answer»

`100 ML`
`240 ml`
`160 ml`
`120 ml`

Solution :`Ba(OH)_(2) rarr n = (0.5 xx V mL)`
`H_(3)PO_(3) rarr n = (0.8 xx 100 mL)`
`H_(3)PO_(3)` is a diabasic acid
Equal moles of `Ba(OH)_(2)` and `H_(3)PO_(3)` are needed
`n_(Ba (OH)_(2)) = n_(H_(3)PO_(3)`
`M_(1)V_(1) = M_(2) V_(2)`
`0.5 xx (V)/(1000) = 0.8 xx (100)/(1000)`
`V = (8 xx 100)/(5) = 6 mL`
13691.

Which of the following is least ionic

Answer»

`C_(2)H_(5)CL`
KCl
`BaCl_(2)`
`C_(6)H_(5)N^(+)H_(3)Cl^(-)`

SOLUTION :Ethyl chloride is an organic compound so it will be COVALENT
13692.

Two gases A and B having molecular weigths 60 and 45 respectively are enclosed in a vessel. The wt. of A is 0.50 g and that of B is 0.2 g. The total pressure of mixture is 750 mm. Calculate partial pressure of the two gases.

Answer»

SOLUTION :Given wt. of gas A=0.50 g
mol wt. of gas A=60
Wt, of gas B =0.2 g. Molecular wt. gas B =45
`P_(T) =750 mm`
From Dalton.s law of PARTIAL pressure
`P_(A) =P_(T) xx` MOLE frection of A.
`=750 xx (0.50//60)/((0.50)/(60)+(0.2)/(45))=489.23 mm`.
`P_(T) =P_(A) +P_(B)`
`THEREFORE P_(B) =P_(T)-P_(A)=750-489.23`
`=260.77 mm`.
13693.

The standard enthalpy of formation of NH_(3) is -46.0kJmol^(-1). If the enthalpy of formation of H_(2) from its atoms is -436kJmol^(-1), the average bond enthalpy of N-H bond in NH_(3) is

Answer»

`-964kJmol^(-1)`
`-352kJmol^(-1)`
`+1056kJmol^(-1)`
`-1102kJmol^(-1)`

Solution :Given, `(1)/(2)N_(2)(g)+(3)/(2)H_(2)(g) to NH_(3)(g),DeltaH_(f)^(@)=-46.0" kJ "MOL^(-1)`
`2H(g)toH_(2)(g),DeltaH_(f)^(@)=-436" kJ "Mol^(-1)`
`2N(g)toN_(2)(g),DeltaH_(f)^(@)=-712" kJ "mol^(-1)`
Bond enthalpy of `NH_(3)`
`=3BE_(N-H)[(1)/(2)BE_(N-N)+(3)/(2)BE_(H-H)]`
`-46=3N-N-[-(1)/(2)xx712-(3)/(2)xx436]`
`3N-H=-1056" kJ "mol^(-1)`
`N-H=(1056)/(3)=-352" kJ "mol^(-1)`
13694.

Which of the following will undergo aldol condensation?

Answer»

Acetaldehyde
Propanaldehyde
Benzaldehyde
Trideutereo acetaldehyde

Solution :Both have `ALPHA` HYDROGEN and will UNDERGO ALDOL CONDENSATION.
13695.

Write some uses of bromine.

Answer»

Solution :USED as oxidising agent
Used as GERMICIDE
Used for TESTING unsaturation in organic compound.
13696.

Which dicyclic base is present in RNA ?

Answer»

GUANINE
THYMINE
CYTOSINE
URACIL

SOLUTION :Guanine
13697.

Which of the following does not react with acetyl chloride ?

Answer»

`(C_(2)H_(5))_(2)NH`
`C_(2)H_(5)NH_(2)`
`CH_(3)NH_(2)`
`(CH_(3))_(3)N`.

ANSWER :D
13698.

Two liquid A and B form an ideal solution on mixing. The vapour pressure of solution having 1 mole A and 3 mole B is 550 mm at 300 K temp. The vapour pressure will increased by 10 mm. on addition of 1 mole B to the solution. What will be the vapour pressure of A and B individually ?

Answer»

<P>500 and 600
200 and 300
300 and 400
400 and 600

Solution :Suppose X = A and Y = B
`P_(A)^(0)X_(A)+P_(B)^(0)X_(B)=P_("TOT")`
`therefore P_(A)^(0)((1)/(1+3))+P_(B)^(0)((3)/(1+3))=550 mm`
`therefore 0.25 P_(A)^(0)+0.75P_(B)^(0)=550 mm`….(1)
Now add 1 mole B to MIXTURE
`0.20 P_(A)^(0)+0.80 P_(B)^(0)=560 mm` .....(2)
multiply (1) by 4
`therefore P_(A)^(0)+3P_(B)^(0)=2200`
multiply (2) by 5
`therefore P_(A)^(0)+4P_(B)^(0)=2800`
`therefore P_(A)^(0)=400 mm =P_(X)^(0)`
`P_(A)^(0)=600 mm = P_(Y)^(0)`.
13699.

Volume occupied by hydrogen gas at 2 atm and 273 .^(@)C which contain 2 gm atoms of hydrogen is -

Answer»

`11.2` litre
`44.8` litre
2 litre
`22.4` litre

Solution :`n_(H) = 2` (GIVEN)
`n_(H_(2)) = (n_(H))/(2) = (2)/(2) = 1`
`PV = nRT` for `H_(2)` GAS
`2 xx V_(H_(2)) = 1 xx 0.0821 xx 546`
`2 xx V_(H_(2)) = 2 xx 22.4`
`V_(H_(2)) = 22.4` litre
13700.

Two oxides of lead were separately reduced to metallic lead by heating in a current of hydrogen and the following data obtained: (i) Mass of yellow oxide taken = 3.45 g, Loss in mass during reduction = 0.24 g (ii) Mass of brown oxide taken = 1.227 g, Loss in mass during reduction = 0.16 g Show that the above data illustrate the Law of Multiple Proportions.

Answer»

Solution :CALCULATE the mass of lead combined with 1 g of oxygen in each CASE which are 13.375 g and 6.669 g, i.e, in the RATIO of `2:1`.