Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

15451.

The tranquilizer obtained from the plant Rauwolfia Serpentine is

Answer»

RESERPINE
iproniazed
chlorodiazepoxide
meparobamate

ANSWER :A
Discussion
15452.

Which one of the following is a tertiary amine?

Answer»

TRIETHYLAMINE
trimethylamine
2-methyl propanamine-2
N-ethyl-N-methyl propanamine-1

Answer :C
Discussion
15453.

When iofoform is heated with silver poweder, thegaseous product formed is:

Answer»

Ehthene
Ethyne
Ethane
Silver iodate

Solution :
Discussion
15454.

Using the data given below find out the strongest reducing agent. E_(Cr_(2)O_(7)^(2-)//Cr^(3+))^(Theta)=1.33V,E_(Cl_(2)//Cl^(-))^(Theta)=1.36V E_(MnO_(4)^(-)//Mn^(2+))^(Theta)=1.51V,E_(Cr^(3+)//Cr)^(Theta)=-0.74V

Answer»

`Cl^(-)`
`CR`
`Cr^(3+)`
`Mn^(2+)`

SOLUTION :Strongest reducing agent is ONE which is oxidized most easiliy, i.e., which has HIGHEST oxidation potential. Given values are REDUCTION potentials. Reversing the sign will give oxidation potentials.thus, `Cr//Cr^(3+)` will have highest oxidation potential (+0.74V). hence, Cr is oxidized most easiliy `(CrtoCr^(3+)+3e^(-))` and, therefore, is the strongest reducing agent.
Discussion
15455.

Which method is not correctly given for refining of crude metals?

Answer»

Distillation : ZINC and mercury
Liquation : tin
Van Arkel: zirconium
MOND's process : lead

Solution :Mond process is USED for nickel.
Discussion
15456.

Write the atomic number of the element in which the filling of 3d-subshell in the atom just starts.

Answer»

SOLUTION :21 (SC).
Discussion
15457.

Which nitrogenous base present in DNA but not in RNA ?

Answer»


ANSWER :THYMINE
Discussion
15458.

What is the correct order of basicity of hydroxide ?

Answer»

`La (OH ) _(3) LT ND (OH) _(9)lt Tb (OH)_(3)lt LU (OH) _(3)`
`La (OH ) _(3) lt Lu(OH) _(3)lt Nd(OH)_(3)lt Tb (OH) _(3)`
`La (OH) _(3) gt Lu(OH ) _(3) gt Nd (OH) _(3)gt (OH) _(3)`
`La (OH )_(3)f gt Nd (OH)_(3) gt Tb (OH)_(3) gt Lu (OH) _(3)`

ANSWER :D
Discussion
15459.

Usuallya brokenironarticleis takentotheweldingshop for repair. But itis difficultto takebrokengirders or thecrakedrailwaytrackto theindustryfor repair.Cantheweldingequipmentbe broughtto thesite forrepair ? Namethe process,illustratethe principleofitsworkingand name some otherpracticleapplicationsof thisprocess.

Answer»

Solution :
Theequipment used for onthe spotwelding is calledaluminothermy.In thisprocess,a mixtureof aluminiumpowderand ferricoxide calledthermiteis IGNITED in aclosedcrucible byinsertinga burningmagnesium ribbonintotheignitionmixtureconsistingof magnesiumpowder and bariumperoxideas shownin the Fig.Theingnition powder burnsto producea largeamountofheatneededto initiatethereaction. Since` Delta_ f G^(@) `of` Al_ 2 O_ 3 `is muchmore negativethan of` Fe _ 2O_ 3,therefore, Al reduces` Fe_ 2O_ 3 `to metalliciron.
`2 Al (S)+Fe_ 2O_3(S)overset (DELTA )toAl _ 2O_ 3( S)+Fe ( l ) `
This reactionis highly exothermic. As a result, Fe isproduced in the moltenstateandthuscan beusedto weldheavymachineryof all kinds,suchas girders, railway tracks, etc.
Besides` Fe_2O_ 3`, Al can ALSOBE usedto reduceoxidesof othermetalssuch as` Cr_2O_3,MN _3O_4 `,etc.
`Cr _2 O_3+2 Al toAl_2O_3 + 2 Cr,3 Mn _3O_ 4 +8Alto4 Al_2O _3+9 Mn `
Discussion
15460.

Write equations for the following transformation: (a) ._(7)^(17)N (n, p) (b) ._(19)^(39)K(n, alpha)

Answer»

Solution :(a) `._(7)N^(14)(n,p)` indicates that `N^(14)` on bombardment with neutrons gives proton.
`:. "" ._(7)N^(14)+._(0)n^(1) rarr ._(z)X^(m)+._(1)p^(1)`
on eqating at. "no". And mass "no". "on" both sides, we GET
`._(7)N^(14)+._(0)n^(1) rarr._(6)C^(14)+ ._(1)p^(1)`
(B) `._(19)K^(39)(p,alpha)` indicates that `K^(39)` on bombarmentwith proton gives `alpha `-particle.
There, `._(19)K^(39)+._(1)H^(1) rarr ._(18)Ar^(36)+._(2)He^(4)`
(c) `._(11)Na^(22) rarr . _(10)Ne^(22)+ ._(+1)e^(0)(beta^(+)"or positron")`
Discussion
15461.

Which of the following substances show antiferromagnetism?

Answer»

`ZrO_2`
CDO
`CrO_2`
`Mn_2O_3`

ANSWER :D
Discussion
15462.

Which of the following oxides is unstable at moderate temperature?

Answer»

`Al_(2)O_(3)`
`Cr_(2)O_(3)`
MgO
HgO

Answer :D
Discussion
15463.

Whatare antagonistand agonist durgs ?

Answer»

SOLUTION :Drugs which bind to the receptor site and INHIBITS its natural function. They are useful when blocking of message is required.
AGONISTS are the drugs which IMITATE (mimic) the natural messenger by switching on the receptor. They are useful when there is lack of natural chemical messenger.
Discussion
15464.

Which one of the following halogens does not exhibit positive oxidation state in its compounds?

Answer»

I
Br
Cl
F

Answer :D
Discussion
15465.

Vapour pressures of benzene and toluene in a mixute at 50^(@)C are given in mm by P=179 X_(B)+92 where X_(B) is the mole fraction of benzene. Calculate. (a) Vapour pressures of pure benzene and toluene at 50^(@)C.

Answer»

Solution :For pure BENZENE, `X_(B)=1`. HENCE `P_(B)^(@)=179+92="271mm"`
For pure TOLUENE, `X_(B)=0.` Hence `P_(T)^(@)=179xx0+92 = "92 mm"`
Discussion
15466.

Vapour pressures of benzene and toluene in a mixute at 50^(@)C are given in mm by P=179 X_(B)+92 where X_(B) is the mole fraction of benzene. Calculate. (b) Vapour pressure of a liquid mixture obtained by mixing 224 g benzene and 184 g of toluene.

Answer»

Solution :(b) 224 g benzene `(C_(6)H_(6))=(224)/(78)" MOL" = "3 mol,184 g toluene "(C_(6)H_(5)CH_(3))=(184)/(92)=" 2 mol"`
`X_(B)=(3)/(5)=0.6,""X_(T)=(2)/(5)=0.4`
`P_(B)=0.6xx"271 mm"="162.6 mm," P_(T)=0.4xx92 = "36.8 mm", P_("Total")=162.6+36.8="199.4 mm"`
Discussion
15467.

Vapour pressures of benzene and toluene in a mixute at 50^(@)C are given in mm by P=179 X_(B)+92 where X_(B) is the mole fraction of benzene. Calculate. (c) If the vapours are removed and condensed into liquid and again brought to the temperature of 50^(@)C, what would be the mole fraction of benzene in the vapour phase?

Answer»

SOLUTION :Mole fractions in the vapour PHASE : `y_(B)=(P_(B))/(P_("Total"))=(162.6)/(199.4)=0.82,""y_(T)=(P_(T))/(P_("Total"))=(36.8)/(199.4)=0.18`
After CONDENSATION, these are the mole fractions in the liquid phase
New `P_(B)=0.82xx"271 mm" = "222.2 mm,New " P_(T)=0.18xx"92 mm = 16.6 mm,"`
New `P_("Total")=222.2+16.6= 238.8" mm,New " y_(B)=(222.2)/(238.8)=0.93`
Discussion
15468.

which of the following is not heterocyclic compound?

Answer»

Morphine
Heroin
Aspirin
Codein

Answer :C
Discussion
15469.

Which statement is not correct for nitrogen ?

Answer»

Its electronegativity is very high
d-orbitals are AVAILABLE for bonding
It is a typical non-metal
Its MOLECULAR SIZE is small

Answer :B
Discussion
15470.

Why amines have lower boiling points than alcohols and carboxylic acids of comparable molecular mass?

Answer»

Solution : It is due to weaker hydrogen bonding in AMINES than ALCOHOLS and ACIDS.
Discussion
15471.

Though air pollutant, this gas acts as umbrella of life on earth :

Answer»

`SO_2`
CO
`CO_3`
`O_3`

ANSWER :D
Discussion
15472.

Which is used as control rods in nuclear reactors ?

Answer»

Al
Ga
Ti
B

Answer :D
Discussion
15473.

The time required for 10% completion of first order reaction at 298K is equal to that required for its 75% completion at 308K. If the pre-expontential factor for the reaction is 3.56xx10^(9)s^(-1), calculate its rate constant at 318K and also the energy of activation.

Answer»

Solution :For first ORDER reactions,
`t=(2.303)/(K)log.(N_(0))/(N_(1))`
At `298K`, `t=(2.303)/(k_(298))log.(100)/(90)`
At `309k, t=(2.303)/(k_(308))log.(100)/(25)`
Since time is same
`(2.303)/(k_(298))log.(100)/(90)=(2.303)/(k_(308))log.(100)/(25)`
or `(0.0458)/(k_(298))=(0.1249)/(k_(308))1`
or `(k_(308))/(k_(298))=(0.1249)/(0.0458)=2.73`
According to ARRHENIUS equation
`2.303log.(k_(308))/(k_(298))=(E_(a))/(8.314)[(1)/(298)-(1)/(208)]`
or `2.303log2.73=(E_(a))/(8.314)[(10)/(298xx308)]`
`E_(a)=76.65kJ`
and `K_(318)=9.306xx10^(-4)s^(-1)`
Discussion
15474.

What is an asymmetric or chiral carbon?

Answer»

Solution :A carbon which is attached to FOUR DIFFERENT atoms/groups is called asymmetric or chiral carbon. For example, the carbon ATOM in `BrI overset(**)(C)HCL` or `CH_(3)overset(**)(C)HOHCH_(2)CH_(3)`.
Discussion
15475.

When ammonia reacts with copper sulphate solution to give complex , the colour of complex is , ………………

Answer»

VIOLET
DEEP BLUE
blue
Red

Solution :deep blue
Discussion
15476.

Which one is the antacid ?

Answer»

Furacin
Sulphapiridine
`NH_(2)CO_(3)`
PENICILLINE 

SOLUTION :`NH_(2)CO_(3)`
Discussion
15477.

What is an adsorption isotherm ? Describe Freundlich adsorption isotherm.

Answer»

SOLUTION :Adsorption isotherm : It represents the variation of the mass of the gas adsorbed PER gram of the ADSORBENT with pressure at CONSTANT temperature.
Discussion
15478.

When lead storage battery discharges , specific gravity of H_(2)SO_(4) decreases to

Answer»

zero
1.17
1.28
1.215

Solution :During discharging of the cell , specific GRAVITY of `H_(2)SO_(4)` DECREASES from 1.215 to 1.17 g/cc.
Discussion
15479.

Which is the correct priority order for absolute configuration ?

Answer»

`–COOH, -CONH_(2), -CHO, -COCH_(3)`
`–COOH_(3) -CONH_(2), -COOH, -CHO`
`–COOH, -CONH_(3), -CONH_(2), -CHO`
`–COOH, -CONH_(2), -COCH_(3), -CHO`

Solution :`–COOH, -CONH_(2), -COCH_(3), -CHO`
Discussion
15480.

Which of the following is known as freon which is used as refrigerant ?

Answer»

`C Cl_(2)F_(2)`
`CHCl_(3)`
`CH_(2)F_(2)`
`CF_(4)`

ANSWER :A
Discussion
15481.

Which of the following is true statement?

Answer»

NUCLEOSIDE + phosphoester bond = nucleotide
DNA's are nucleotide and RNA's are nucleoside
Nucleotide + phosphoester bond = nucleoside
NONE of the above

Solution :Nucleoside + phosphoester bond= Nucleotide
Discussion
15482.

The strongest oxidising agent is:

Answer»

`H_3PO_4`
`HNO_3`
`H_3PO_3`
`HNO_2`

ANSWER :B
Discussion
15483.

Two moles of NH_(3) when put into a previously evacuated vessel ( one litre), partially dossociate into N_(2) and H_(2). If at equlib rium one mole of NH_(3) is present, the equlibrium constant is

Answer»

`3//4 mol^(2) litre^(-2)`
`27//64 mol^(2) litre^(-2)`
`27//32 mol^(2) litre^(-2)`
`27//16 mol^(2) litre^(-2)`

SOLUTION :`2NH_(3)hArrN_(2)+3H_(2)`
`{:("INITIAL concentration",2,0,0),("At EQULIBRIUM concentration",1,1//2,3//2):}`
`K_(c)=([N_(2)][H_(2)]^(3))/([NH_(3)]^(2))=(1//2xx[3//2]^(3))/(I^(2))=27/16`
`[Given 2-2x=1,2x=1,x=1//2]`
Discussion
15484.

Which of the following is an example of S_(N^(2)) reaction?

Answer»

`CH_(3)Br +OH^(-) to CH_(3)OH+Br^(-)`
`CH_(3)-underset(Br)underset(|)(C)H-CH_(3)+OH^(-) to CH_(3)-underset(OH)underset(|)(C)H-CH_(3)`
`CH_(3)CH_(2)Ohoverset(-H_(2)O)(to) CH_(2)=CH_(2)`
`(CH_(3))_(3)C-Br+OH^(-) to (CH_(3))_(3)COH +Br^(-)`

Solution :Only `1^(@)` alkyl HALIDES (i.e., `CH_(3)Br`) undergo `S_(N^(2))` REACTION.
Discussion
15485.

What will be the mass of O_2 molecule in grams?

Answer»

`5.31X10^-23` G
`32 g`
`16 g`
`2.6X10^-23` g

Answer :A
Discussion
15486.

What is the geometry of water molecule ?

Answer»

Distorted tetrahedral
Tetrahedral
Trigonal planar
Diagonal

Solution :Geometry of molecule be predicted by using the formula
`H=(1)/(2)[Ve+V-C+A]`
VE = valence shell ELECTRONS of the central ATOM
Y=number of MONOVALENT atom
C = TOTAL positive charge
A = total negative charge
In case of `H_(2)O` molecule,
`H=(1)/(2)[6+2-0+0]=4`
Hybridisation of `H_(2)O` molecule comes out to be `sp^(3)`. Thus the geometry of `H_(2)O` molecule is tetrahedral but the SHAPE is distroted tetrahedral or angular due to presence of two lone pair of electrons.
Discussion
15487.

Write the structure of the following Br_3

Answer»

SOLUTION :
Discussion
15488.

Which is a natural colloidal?

Answer»

SODIUM chloride
Urea
Cane sugar
Blood

Answer :D
Discussion
15489.

Which one of the following should be ozonolysed to get a mixture of ethanal and propanone?

Answer»

PROPENE
But-2-ene
Ethylene
2-methyl-but-2-ene

Solution :2-methyl-but-2-ene
Discussion
15490.

Which of the following is responsible for transportation of negative ions in galvanic cell ?

Answer»

Electrodes
SALT bridge
External path with COPPER wire.
None of above

Solution :Salt bridge
Discussion
15491.

Which elements in 3d series has minimum enthalpy of atmoisation ?

Answer»

Sc
Mn
Co
Zn

Answer :D
Discussion
15492.

Which of the following cannot e prepared by sandmeyer's reaction?

Answer»

Chlorobenzene
Bromobenzene
IODOBENZENE
FLUOROBENZENE

Solution :Iodobenzene and fluorobenzene.
Discussion
15493.

Write the formula for the following complex : Potassium tetrachloridonickelate(II)

Answer»

Solution :POTASSIUM tetrachloridonickelate(II)
`K_(2)[NiCl_(4)]`
Discussion
15494.

What is the oxidation number of Cr in Cro 5. The silicate anion in the mineral kinotic is a chain of three SiO_(4) tetrahedral that share corners with adjacent tetrahedral. What is negative charge on the silicate anion.

Answer»

SOLUTION :`-8`
Discussion
15495.

Which of the following pair act as acids ?

Answer»

`H_(2)O, CH3OO​^(-)`
`H_(2)O, H_(3) O​ ^(-) `
`CH_(3)COOH, H_(3) O​^(+)`
`CH_(3)COOH, CH_(3)COO​ ^(-) `

ANSWER :C
Discussion
15496.

Which of the following statements is / are correct?

Answer»

`DeltaG^(@)` depends on cell reaction
`E_("cell")^(@)` depends upom making up of the cell
Both `DeltaG^(@) and E^(@)` are path FUNCTIONS
`E^(@)` is path FUNCTION but `DeltaG^(@)` is a state function.

Solution :`DeltaG` depends on cell reaction , `E_("cell")^(0)` Depends UPON making up of cell `E^(0)` is path function `DeltaG^(0)` is a state function
Discussion
15497.

When an acidified solution of ferrous ammonium sulphate it treated with potassium permanganate solution, the ion which is oxidised is

Answer»

`MnO_(4)^(-)`
`NH_(4)^(+)`
`FE^(++)`
`SO_(4)^(2-)`

Answer :C
Discussion
15498.

When phenol is treated with bromine water, white precipitate is obtained. Give the structure and the name of the compound formed.

Answer»

SOLUTION :
Discussion
15499.

Which transition elements exhibit +8 oxidation state

Answer»

CU, Zn`
`RU, OS`
`AG, AU`.
`Cu, Cr`

Answer :B
Discussion
15500.

Which of the following compound of Xenon has pyramidal geometry ?

Answer»

`XeF_4`
`XeO_3`
`XeF_2`
`XeOF_4`

SOLUTION :
Discussion