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16301.

Which of the following statements is/are not correct for a close - packed structure ?

Answer»

Each OCTAHEDRAL void is SURROUNDED by SIX spheres and each sphere is surrounded by six octahedral voids
Each octahedral void is surround by six spheres and each sphere is surrounded by three octahedral voids.
Each octahedral void is surrounded by TWO spheres and each sphere is surrounded by eight voids.
Each tetrahedral void is surround by eight spheres and each sphere is surrounded by eight voids.

Answer :B::C::D
Discussion
16302.

Which of the following species can act as reducing agent?

Answer»

`[Co(CO)_(4)]^(-)`
`Mn(CO)_(6)`
`Mn(CO)_(5)`
`Cr(CO)_(6)`

Solution :`Mn(CO)_(6)` can ACT as REDUCING agent because the metal corbonyl is stable when EAN is EQUAL to nearest noble gas configuration.
Discussion
16303.

Which is not a crystalline form of silica?

Answer»

Quartz
Azurite
Cristobalite
Tridymite

Answer :B
Discussion
16304.

When acetamide is treated with Br_2 and an alkali, a primary amine containing one carbon atom less than the starting amide is formed. Name the reaction and write the balanced equation.

Answer»

SOLUTION :Hofmann.s DEGRADATION (or bromamide) REACTION.
Discussion
16305.

Which one of the following could be the melting point of iron ?

Answer»

`25^(@)C`
`37^(@)C`
`500^(@)C`
`1500^(@)C`

SOLUTION :It is because :
(i) the REACTION is endothermic and REQUIRES very high TEMPERATURE .
(ii) the reaction can be initiated only in presence of a catalyst .
(iii) oxides of nitrogen are unstable .
(iv) `N_(2)` and `O_(2)` are unreactive.
Discussion
16306.

Which of the structure represent methyl alpha -D- galactopyranoside ?

Answer»

a
b
c
d

Solution :It is FACT, for DETAILS CONSULT the TEXT BOOK.
Discussion
16307.

Which of the following cell has following reaction ? 2H_(2(g)) +O_(2(g)) to 2H_(2)O_((l))+571.7kJ

Answer»

VOLTAIC CELL
Galvanic cell
FUEL cell
Leclanche cell

Solution :Fuel cell
Discussion
16308.

Which of the following has the lowest pK_(a) value?

Answer»

`CH_(3)-CH_(2)-OVERSET(O)overset(||)C-OH`
`CH_(2)=CH-overset(O)overset(||)C-OH`

`H-CequivC-overset(O)overset(||)C-OH`

ANSWER :D
Discussion
16309.

The reagent which does not react with both, acetone and benzaldehyde is

Answer»

Sodium hydrogensulphite
Phenyl hydrazine
FEHLING's SOLUTION
Grignard reagent

Solution :Fehling's solution does not REACT with ketones, i.e., acetone and AROMATIC aldehydes, i.e., BENZALDEHYE.
Discussion
16310.

The standard enthalpy of combustion of sucrose is -5645 kJ mol^(-1). What is the advantage (in kJ mol^(-1) of energy released as heat) of complete aerobic oxidation compared to anaerobic hydrolysis of sucrose to lactic acid ? Delta H_(f)^(@) for lactic acid, CO_(2) and H_(2)O is -694, -395.0 and -286.0 respectively.

Answer»


Solution :`C_(12)H_(22)O_(11)+12O_(2) rarr 12CO_(2) +11H_(2)O""` [A erobic oxidation]
`DeltaH=-5645" kJ/mole"`
`C_(12)H_(22)O_(11)+H_(2)O rarr 4 CH_(3)-overset(OH)overset(|)(CH)-COOH`
`DeltaH=-249`
Advantage `=5645-249=5396" kJ mol"^(-1)`
Discussion
16311.

What happens when concentrated sulphuric acid is heated with oxalic acid ?

Answer»

Solution :DEHYDRATION TAKES place OR CO and `CO_(2)` is LIBERATED
`{:(COOH),(|),(COOH):}+"Conc. "H_(2)SO_(4)rarr CO+CO_(2)+H_(2)SO_(4).H_(2)O`
Discussion
16312.

When B_(2)H_(4) is allowed to react with following lewis bases, then how many given lewis bases form adduct through symmetrical cleavage of B_(2)H_6)? NH_(3), MeNH_(3), pyridine, CO, T.H.F., PH_(3), PF_(3), Me_(3)N, Me_(3)NH

Answer»


Solution :`to` unsymmetrical cleavage of `B_(2)H_(6)`: with SMALL sized strong lewis BASE like : `NH_(3), MNH_(2), Me_(2)NH`
`to` Symmetrical cleavage of `B_(2)H_(6)` : with large sized strong lewis or weaker lewis base like : `PH_(3), PF_(3), H^(-), CO, T.H.F, Me_(2)N`, pyridine
Discussion
16313.

Which of the following is not used as an antacid?

Answer»

Magnesium HYDROXIDE
Sodium carbonate
Sodium bicarbonate
Aluminium hydroxide

Solution :Sodium carbonate ~(Na_(2)CO_(3)-"washing soda")` is not USED as an ANTACID.
Discussion
16314.

The vapour density of pure ozone would be :

Answer»

48
32
24
16

Answer :C
Discussion
16315.

Which one of the following is not formed when an electric discharge passes through helium ?

Answer»

`HEH^(+)`
`HeH^(2+)`
`He_(2^(+))`
`He_(2)`

ANSWER :C
Discussion
16316.

Which metal can be purified by liquation ?

Answer»

TIN 
IRON 
LEAD 
NICKEL 

ANSWER :A
Discussion
16317.

What is D in the following reaction ? CH_(3)CH_(2)OH overset(P,I_(2))to A underset("ether")overset(Mg)to B overset(HCHO)to Coverset(H_(2)O)to D

Answer»

N-butyl ALCOHOL
n- Propyl alcohol
Propanol
Butanol

Solution :`underset("Ethanol")(CH_(3)CH_(2)OH )overset(P,I_(2))to CH_(3)CH_(2)I underset("ETHER")overset(Mg)to CH_(3)CH_(2)MgI overset(HCHO)to CH_(3)CH_(2)CH_(2)OMgI overset(H_(2)O)to underset("n- Propyl alcohol")(Mg(OH)I+ CH_(3)CH_(2)CH_(2)OH)`
Discussion
16318.

What is applied to inanimate objects for making them free from microorganisms?

Answer»

DISINFECTANTS 
ANTISEPTICS 
ANTACIDS 
All of the GIVEN 

SOLUTION :Disinfectants
Discussion
16319.

The resistance of 0.5 N solution of an electrolyte in a conductivity cell was found to be 25 ohm. Calculate the equivalent conductivity of the solution if the electrodes in the cell are 1.6 cm apart and have an area of 3.2 cm^(2)

Answer»


SOLUTION :Cell constant = `(l)/(a) = (1.6)/(3.2) = 0.5 cm^(-1)`
`kappa = (1)/(25) XX 0.5 = 2.0 xx 10^(-2) S cm^(-1)`
`Lambda = (2.0 xx 10^(-2) xx 1000)/(0.5) = 40 S cm^(2) "EQUIV"^(-1)`
Discussion
16320.

Which of the followingstatement is not correct ?

Answer»

The coordination number of each type of ion in CsCl crystal is 8.
A METAL that crystallises in bcc structure has a coordination no .of 12.
A unit cell of an IONIC crystal shares some of its ions with other unit cells .
The length of the unit cell in NACL is 552 PM `(r Na^+=95 pm,r Cl^- =181 pm)` .

Answer :B
Discussion
16321.

Which is not a lewis base ?

Answer»

`OH^-`
`AG^+`
`NH_3`
`H^-`

ANSWER :B
Discussion
16322.

Which one of the following is not a correct statement?

Answer»

Physical adsorption is REVERSIBLE in nature
Physical adsorption involves van der Waal's forces
Rate of physical adsorption INCREASES with increase of PRESSURE on the adsorbate
HIGH activation energy is involved

Answer :D
Discussion
16323.

The thermodynamic efficiency of cell is given by :

Answer»

`DeltaH//DeltaG`
`nFE// Delta G`
`nFE//Delta H`
`nFE^@`

ANSWER :C
Discussion
16324.

Which of the following graphs is correct for a first order reaction?

Answer»




ANSWER :A::D
Discussion
16325.

Which of the following pairs of tons would be expected to form precipitate when dilute solutions are mixed ?

Answer»

`BA^(2+),Cl^(-)`
`NH_4^(+), CO_3^(2-) `
`Fe^(3+), OH^(-) `
`NA^(+), SO_4^(2-)`

Answer :C
Discussion
16326.

Which of the following should be most volatile? I) CH_3 CH_2 CH_2 NH_2"" II) "" (CH_3)_3 N "" III)"" "" IV) CH_3 CH_2 CH_3

Answer»

II
IV
I
III

Solution :`1^(@)` and `2^(@)` amines have higher boiling points due to INTERMOLECULAR H-bonding but less votaline than `3^(@)` amines and hydrocarbons of comparable MOLECULAR mass. Further, because of polar C-N bonds, `3^(@)` amines are more polarthan hydrocarbons which are almost non-polar . hence , due to weak DIPOLE -dipol interactions, `3^(@)` amines have higher boilingpoint (i.e. less volatile) than hydrocarbons. in other words, hydrocarbons are more volatile among given compounds as amine are less volatile than hydrocarbon
Discussion
16327.

When a certain amount of ethylene was combusted, 6226 kJ heat was evolved. If heat of combustion of ethylene is 1411 kJ, the volume of O_(2) (at STP) that entered into the reaction is :

Answer»

`296.5` ML
`296.5`LITRES
`6226xx22.4` litres
`22.4`litres

Answer :B
Discussion
16328.

Which compound is not possible of Titanium (Z=22)?

Answer»

`TiO_(2)`
`K_(2)TiF_(6)`
`TiCl_(3)`
`K_(2)TiO_(4)`

ANSWER :D
Discussion
16329.

Which of the following is a highly corrosive salt

Answer»

`FeCl_(2)`
`PbCl_(2)`
`Hg_(2)Cl_(2)`
`HgCl_(2)`

Solution :`HgCl_(2)` has corrosive action. It is highly poisoous. It SUBLIMES on HEATING. It is ,therefore, KNOWN as corrosive SUBLIMATE.
Discussion
16330.

Which of the following statement is correct regarding the aldol condensation ?

Answer»

All aldehydes give this REACTION
Ketones do notgive this reaction
This reaction PROCEEDS in presence of STRONG alkali
Ketones, in which `alpha ` - hydrogen atom is present , give this reaction

Solution :We know that in aldol condensation, `alpha `- hydrogen atoms undergo self- additionbetween two molecules to form `BETA`- hydroxy ketone. Therefore ketone in which `alpha`- hydrogen atom is present, give this reaction .
Discussion
16331.

Write the sources of vitamin and diseases due to vitamin deficiency.

Answer»

SOLUTION :
Discussion
16332.

Which one of the following is a wrong statement about cast iron

Answer»

It is also CALLED pig iron
It CONTAINS about `4.5%` carbon
It is corrosion resistant
It CONTRACTS on cooling

Answer :D
Discussion
16333.

Which of the followingis nitroso nitroalkaneofprimarynitro alkane?

Answer»

`R - UNDERSET(R)underset(|)overset(NO_(2))overset(|)(C) - N = O`
`R - underset(R)underset(|)overset(O-NO_(2))(C)- N= O`
`R - underset(H)underset(|)overset(NO_(2))overset(|)(C)- N =O`
`R - underset(H) underset(|) overset(O-NO)overset(|)(C)-N = O`

Answer :C
Discussion
16334.

Whichtheorycan explainbondingNi ( CO )_ 4

Answer»

MOLECULAR ORBITAL theory
Crystal FIELD theory
Werner's theory
Valence BOND theory

Answer :A
Discussion
16335.

When ethyl acetate was hydrolysed in presence of 0.1N HCI, the rate constant was found to be 5.40X10^-5sec^-1But when 0.1N H_2SO_4 was used for hydrolysis, the rate was used for hydrolysis, the rate to be 6.25X10^-5 sec^-1. Thus it may be concluded that:

Answer»

`H_2SO_4` is stronger than HCI
`H_2SO_4`is WEAKER than HCI
`H_2SO_4` and HCl both have the same STRENGTH
The data are not sufficient to compare the strength of `H_2SO_4` and HCI

Answer :A
Discussion
16336.

The form of iron obtained from blast furnace is:

Answer»

pig IRON
cast iron
WROUGHT iron
MILD STEEL

Answer :A
Discussion
16337.

Which one of the following can act as a reducing agent?

Answer»

`C_6H_5COOH`
`HCOOH`
`CH_3COOH`
`CH_3 - CH_2COOH`

SOLUTION :`HCOOH`
Discussion
16338.

Which of the relationships is wrong?

Answer»

RMS speed `propsqrtp`
DIFFUSION RATE `PROPP`
Diffusion rate `propT`
rms speed `propsqrtT`

Answer :A
Discussion
16339.

You are given benzene, conc. H_(2)SO_(4) and NaOH. Write the equations for the preparation of phenol using these reagents.

Answer»

SOLUTION :
Discussion
16340.

Which of the following is not a seven metals of antiquity?

Answer»

Gold
Silver
Chromium
Tin

Answer :C
Discussion
16341.

Which of the following has least mass

Answer»

2 g ATOM of nitrogen
`3xx10^(23)` atom of C
1 MOLE of S
7.0 g of Ag

Solution :(a) `2` gm atom of nitrogen `=28 gm`
(b) `6xx10^(23)` atoms of C has MASS `=12` gm
`3xx10^(23)` atoms of C has mass `=(12xx3xx10^(23))/(6xx10^(23))=6 gm`
(c) 1 mole of S has mass `=32` gm
(d) 7.0 gm of Ag
So, lowest mass `=6` gm of C.
Discussion
16342.

The value of Henry’s constant,K_(H)is ………….. .

Answer»

<P>greater for GASES with higher solubility
greater for gases with lower solubility
constant for all gases
not related to the solubility of gases

Solution :ACCORDING to Henry's LAW
`IMPLIES p prop x`
As value of `K_(H)` rises solubility of gases decreases.
Discussion
16343.

The vander waals constant for gases A,B and C are as follows: {:(Gas,a//dm^(6)KPa mol^(-2),b//dm^(3) mol^(-1)),(A,405.3,0.027),(B,1215.9,0.030),(C,607.95,0.032):} Which gas has (i) Highest critical temperature (ii) The largest molecular volume (iii) Most ideal behaviour around STP?

Answer»

Solution :`T_(c) = (8a)/(27Rb)` Since, `R` is constant, higher the value of `a//B`, higher will be CRITICAL temperature, `V_(c) = 3b` and `V_(c) prop V_(m)` (for a PARTICULAR gas) therefore higher the value of `V_(c)`, higher will be molar volume of the gas.
If the critical temperature is close to `273K`, gas will behave ideally around the `STP`. Let us illustrate teh result in a tabular form.
`{:(Gas,a//dm^(6)KPa mol^(-2),b//dm^(3)mol^(-1),T_(c),V_(c),a//b),(A,405.3,0.027,534.97K,0.081,1.501xx10^(4)),(B,1215.9,0.030,1444.42K,0.09,4.053xx10^(4)),(C,607.95,0.032,677.07K,0.096,1.89xx10^(4)):}`
(i) `B` gas has the largest critical temperature.
(ii) `C` gas has the largest molecular volume.
(iii) `A` gas has the most ideal behaviour around `STP`
Discussion
16344.

Which is most basic?

Answer»

Ammonia
Primary amine
Secondary amine
Tertiary amine

Answer :C
Discussion
16345.

Which of the following will fail to react with potassium dichromate and dilute sulphuric acid

Answer»

ETHYL alcohol (ethanol)
Acetaldehyde (ethanal)
Secondary propyl alcohol (2-propanol)
Acetone (PROPANONE)

Solution :Acetone oxidise by `K_(2)Cr_(2)O_(7)` & conc. `H_(2)SO_(4)` into carboxylic acid. It is not oxidised by DILUTE `H_(2)SO_(4)`.
Discussion
16346.

Which are solid

Answer»

`XeF_2`
`XeF_4`
`XeF_6`
All

Answer :D
Discussion
16347.

What are food preservatives ? Give two examples , Comment upon the preservatives action of sodium metabisulphite

Answer»

SOLUTION :Chemical substances which are used to protect food against bacteria, yeasts and MOULDS are CALLED preservatives. For EXAMPLE, SODIUM benzoate, sodium metabisulphite, etc.
Discussion
16348.

The total number of tetrahedral voids in the face centred unit cell is

Answer»

6
8
10
12

Solution :Number of ATOMS per UNIT cell in a FCC unit cell = 4 `""because` Number of tetrahedral voids = `2 xx4` = 8
Discussion
16349.

Why aluminium cannot be extracted by reducing alumina with carbon?

Answer»

Solution :Alumina`(Al_(2)O_(3))` cannot be REDUCED by using CARBON because aluminum has more affinity for oxygen than carbon.Therefore,aluminium cannot be EXTRACTED by reducing alumina with carbon.
Discussion
16350.

What is the mole fraction of the solute in a 1.00 m aqueous solution?

Answer»

0.0354
0.0177
0.177
1.77

SOLUTION :1.0 m aqueous solution means 1 MOLE of the solute is present in 1000 G of water
`"1000 g of "H_(2)O=(1000)/(18)" moles = 55.5 moles"`
i.e., `n_(H_(2)O)=55.5`
Mole fraction,
`x_("solute")=(n_("solute"))/(n_("solute")+n_(H_(2)O))=(1)/(1+55.5)=0.0177`
Discussion