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18151.

Which of the following is an Ionic Solid

Answer»

NaCl
LiF
SiC
Both a and b

Answer :D
Discussion
18152.

Which of the following complexes are homoleptic ?

Answer»

`[CO(NH_(3))_(6)]^(3+)`
`[Co(NH_(3))_(4)Cl_(2)]^(+)`
`[Ni(CN)_(4)]^(2-)`
`[Ni(NH_(3))_(4)Cl_(2)]`

Answer :A::C
Discussion
18153.

Which of the following statements is correct ? IfE_(Cu^(2+)|Cu)^(@) = 0.34 V and E_(Sn^(2+)|Sn)^(@) = -0.136 V , E_(H^(+)|H_2)^(@) = -0.0V

Answer»

`Cu^(+2)` IONS can be reduced by `H_2(g)`
Cu can be oxidized by `H^(+)`
`Sn^(2+)` ions can be reduced by `H_2`
Sn can be oxidized by `Cu^(2+)`

SOLUTION :`Sn^(+2) // Sn`
`2H^(OPLUS) //H_2 , Pt `
`Cu^(+2)// Cu`
`Cu^(+2) + 2e^(-) to Cu`
Discussion
18154.

X underset(("Reductive"))overset("Ozonolysis")toY+Z Y can be obtained by Etard's reaction. Z undergoes disproportionation reaction with concentrated alkali. X could be

Answer»




SOLUTION :
Discussion
18155.

Which of the following is an example of aerosol ?

Answer»

Pumic stone
Foam rubber
Froth
Dust in air

Answer :D
Discussion
18156.

Which one of the following is good oxidising agent ?

Answer»

`EU^(2+)`
`Sm^(2+)`
`CE ^(4+)`
`Yb ^(2+)`

Answer :C
Discussion
18157.

The total number of structuralisomersof C_(4)H_(10)O are :

Answer»

5
6
7
8

Answer :C
Discussion
18158.

Which detergent increase water pollution ?

Answer»

Biohard
Biosoft
(A) and (B) both
None of these 

SOLUTION :Biohard
Discussion
18159.

Whether tin can displace lead from aqueous lead bromide solution:

Answer»

No
Yes , because STANDARD redutionpotential of SnltPb
Yes, because standard REDUCTION POTENTIAL of SngtPb-
None

Answer :B
Discussion
18160.

Which of the following has the highest polarizing power ?

Answer»

`K^(+)`
`CA^(2+)`
`MG^(2+)`
`Na^(+)`

Answer :C
Discussion
18161.

When -N^(+)CH_(3) group is attached to the benzene ring, it directs the incoming electrophile into

Answer»

META POSITION
ortho position
para position
EQUALLY DIRECTS to ortho-para position

Answer :A
Discussion
18162.

Which bond angle, theta would result in the maximum dipole moment for the triatomic molecule XY_2 ?

Answer»

`theta=90^(@)`
`theta=120^(@)`
`theta=150^(@)`
`theta=180^(@)`

Solution :The dipole moment of two dipoles inclined at an angle `theta` is given by the equation `mu= sqrt(X^(2)+Y^(2)+2XY cos theta) cos90^(@)=0` Since the angle INCREASES from `90^(@)` to `180^(@)` the value of `cos theta` becomes more and more - ve and hence resultant dipole moment decreases. Thus, dipole moment is maximum when `theta=90^(@)`.
Discussion
18163.

The units of magnetic moment are

Answer»

NEWTON - OHM
Torrs
BOHR MAGNETON
Pascals

Answer :C
Discussion
18164.

The set representing the correct order of ionicradius is

Answer»

`LI^(+)gtBe^(2+)gtNa^(+)GTMG^(2+)`
`Na^(+)GTLI^(+)gtMg^(2+)gtBe^(2+)`
`Li^(+)gtNa^(+)gtMg^(2+)gtBe^(2+)`
`MG^(2+)gtBe^(2+)gtLi^(+)gtNa^(+)`

Answer :B
Discussion
18165.

What will the nature of the solid solution formed on mixing two solids with large difference in particle size ?

Answer»

SOLUTION :The solution is KNOWN as INTERSTITIAL SOLID solution.
Discussion
18166.

When aluminium salts are added to water, Al^(3+) ions are immediately attracted to the negative end of polar water molecules.They form hexaaqualuminum(III) ions, [Al(H_2O)_5]^(2+)+H_3O^+ This is often written simply as Al^(+3)(aq).However the electric field associated with small, highly charged Al^(+3) ion is so intense that it draws electrons in the O-H bonds of water towards itself.This enables the water molecules to become donors.In aqueous solution, free water molecules act as bases and the following equilibrium is established : [Al(H_2O)_(6)]^(3+)+H_2OhArr [Al(OH)(H_(2)O)_(5)]^(2+)+H_3O^(+) Thus, solution of Al^(+3) salts are acidic, in fact as acidic as vinegar. When a base stronger than H_2O, e.g. S^(2-) is added to aqueous aluminium salts further H^+ ions are removed from [Al(H_2O)_6]^(3+) and insoluble aluminium hydroxide precipitates. 2[Al(H_2O)_6]^(3+)(aq)+3S^(2-)(aq)to2[Al(OH)_3(H_2O)_3(s)+3H_2S(g) More stronger base can remove 4H^+ ions are follows : [Al(H_2O)_6]^(3+)+4OH^(-)hArr[Al(OH)_4(H_2O)]^(-)(aq)+4H_2O(l) Which gas would get absorbed when passed into a solution of Al^(+3)(aq) ?

Answer»

`NH_3`
`NO`
CO
`O_2`

SOLUTION :NA
Discussion
18167.

Which of the following conditions favours the existence of a substance in the solid state?

Answer»

HIGH TEMPERATURE
LOW temperature
High THERMAL energy
Weak COHESIVE forces

Solution : Low temperature
Discussion
18168.

When aluminium salts are added to water, Al^(3+) ions are immediately attracted to the negative end of polar water molecules.They form hexaaqualuminum(III) ions, [Al(H_2O)_5]^(2+)+H_3O^+ This is often written simply as Al^(+3)(aq).However the electric field associated with small, highly charged Al^(+3) ion is so intense that it draws electrons in the O-H bonds of water towards itself.This enables the water molecules to become donors.In aqueous solution, free water molecules act as bases and the following equilibrium is established : [Al(H_2O)_(6)]^(3+)+H_2OhArr [Al(OH)(H_(2)O)_(5)]^(2+)+H_3O^(+) Thus, solution of Al^(+3) salts are acidic, in fact as acidic as vinegar. When a base stronger than H_2O, e.g. S^(2-) is added to aqueous aluminium salts further H^+ ions are removed from [Al(H_2O)_6]^(3+) and insoluble aluminium hydroxide precipitates. 2[Al(H_2O)_6]^(3+)(aq)+3S^(2-)(aq)to2[Al(OH)_3(H_2O)_3(s)+3H_2S(g) More stronger base can remove 4H^+ ions are follows : [Al(H_2O)_6]^(3+)+4OH^(-)hArr[Al(OH)_4(H_2O)]^(-)(aq)+4H_2O(l) [Al(OH)_3(H_2O)_3](s) more simply written as Al(OH)_(3)(s) is :

Answer»

ACIDIC
basic
neutral
amphoteric

Solution :NA
Discussion
18169.

What are the main constituents of dettol ?

Answer»

SOLUTION :CHLOROXYLENOL and a-terpineol in a SUITABLE SOLVENT.
Discussion
18170.

When aluminium salts are added to water, Al^(3+) ions are immediately attracted to the negative end of polar water molecules.They form hexaaqualuminum(III) ions, [Al(H_2O)_5]^(2+)+H_3O^+ This is often written simply as Al^(+3)(aq).However the electric field associated with small, highly charged Al^(+3) ion is so intense that it draws electrons in the O-H bonds of water towards itself.This enables the water molecules to become donors.In aqueous solution, free water molecules act as bases and the following equilibrium is established : [Al(H_2O)_(6)]^(3+)+H_2OhArr [Al(OH)(H_(2)O)_(5)]^(2+)+H_3O^(+) Thus, solution of Al^(+3) salts are acidic, in fact as acidic as vinegar. When a base stronger than H_2O, e.g. S^(2-) is added to aqueous aluminium salts further H^+ ions are removed from [Al(H_2O)_6]^(3+) and insoluble aluminium hydroxide precipitates. 2[Al(H_2O)_6]^(3+)(aq)+3S^(2-)(aq)to2[Al(OH)_3(H_2O)_3(s)+3H_2S(g) More stronger base can remove 4H^+ ions are follows : [Al(H_2O)_6]^(3+)+4OH^(-)hArr[Al(OH)_4(H_2O)]^(-)(aq)+4H_2O(l) Another ion that would behave similar to Al^(+3)(aq) in forming an acidic solution is :

Answer»

`Be_((AQ))^(2+)`
`Ba_((aq))^(2+)`
`Na^+`
`TL^(-)`

SOLUTION :NA
Discussion
18171.

Why are substances like platinum and palladium often used for carrying out electrolysis of aqueous solutions ?

Answer»

Solution :Platinum and PALLADIUM are INERT MATERIALS for electrodes. They are not attacked by the ions ofthe electrolyte or the products of ELECTROLYSIS. Hence, they are used as electrodes for carrying out the electrolysis.
Discussion
18172.

What are barbiturates ? What is the action of barbiturates on human body ?

Answer»

Solution : Barbaturic acid derivatives are CALLED BARBITURATES. They are hypnotic (SLEEP inducing AGENTS and tranquilizers e.g., valium, serotonin).
Discussion
18173.

When phenolreactes with CHCl_(3) and NaOH followed by acidification, salicyladehyde is obtained. Which ofthe following species are involed in the above-mentioned reaction as intermediates ?

Answer»




Both A and B

Answer :D
Discussion
18174.

When aluminium salts are added to water, Al^(3+) ions are immediately attracted to the negative end of polar water molecules.They form hexaaqualuminum(III) ions, [Al(H_2O)_5]^(2+)+H_3O^+ This is often written simply as Al^(+3)(aq).However the electric field associated with small, highly charged Al^(+3) ion is so intense that it draws electrons in the O-H bonds of water towards itself.This enables the water molecules to become donors.In aqueous solution, free water molecules act as bases and the following equilibrium is established : [Al(H_2O)_(6)]^(3+)+H_2OhArr [Al(OH)(H_(2)O)_(5)]^(2+)+H_3O^(+) Thus, solution of Al^(+3) salts are acidic, in fact as acidic as vinegar. When a base stronger than H_2O, e.g. S^(2-) is added to aqueous aluminium salts further H^+ ions are removed from [Al(H_2O)_6]^(3+) and insoluble aluminium hydroxide precipitates. 2[Al(H_2O)_6]^(3+)(aq)+3S^(2-)(aq)to2[Al(OH)_3(H_2O)_3(s)+3H_2S(g) More stronger base can remove 4H^+ ions are follows : [Al(H_2O)_6]^(3+)+4OH^(-)hArr[Al(OH)_4(H_2O)]^(-)(aq)+4H_2O(l) A base which will behave just like S^(2-):

Answer»

`CO_3^2-`
`CH_3OH`
`NH_4^+`
`NH_2^(-)`

SOLUTION :NA
Discussion
18175.

What happens when Cl_(2) is passed through a hot concentrated solution of a base like Ba(OH)_(2).

Answer»

Solution :On treatment with `Ba(OH)_(2), Cl_(2)` undergoes disproportionation to form barium choride, `BaCl_(2)` and barium chlorate, `Ba(ClO_(3))_(2)`.
`6 Ba(OH)_(2)(conc.)+6 overset(0)(Cl_(2))overset("Hot") RARR 5 overset(-1)(BaCl_(2))+overset(+5)(Ba(ClO_(3))_(2))+6 H_(2)O`
Discussion
18176.

When aluminium salts are added to water, Al^(3+) ions are immediately attracted to the negative end of polar water molecules.They form hexaaqualuminum(III) ions, [Al(H_2O)_5]^(2+)+H_3O^+ This is often written simply as Al^(+3)(aq).However the electric field associated with small, highly charged Al^(+3) ion is so intense that it draws electrons in the O-H bonds of water towards itself.This enables the water molecules to become donors.In aqueous solution, free water molecules act as bases and the following equilibrium is established : [Al(H_2O)_(6)]^(3+)+H_2OhArr [Al(OH)(H_(2)O)_(5)]^(2+)+H_3O^(+) Thus, solution of Al^(+3) salts are acidic, in fact as acidic as vinegar. When a base stronger than H_2O, e.g. S^(2-) is added to aqueous aluminium salts further H^+ ions are removed from [Al(H_2O)_6]^(3+) and insoluble aluminium hydroxide precipitates. 2[Al(H_2O)_6]^(3+)(aq)+3S^(2-)(aq)to2[Al(OH)_3(H_2O)_3(s)+3H_2S(g) More stronger base can remove 4H^+ ions are follows : [Al(H_2O)_6]^(3+)+4OH^(-)hArr[Al(OH)_4(H_2O)]^(-)(aq)+4H_2O(l) Which of [Al(H_2O)_6]^(3+),H_2S or H_2O is the strongest acid ?

Answer»

`[AL(H_(2)O)_6]^(3+)`
`H_2S`
`H_2O`
all of same

Solution :NA
Discussion
18177.

When two ice cubes are pressed over each other, they unite to form one cube. Which of the forces is responsible to hold them together ?

Answer»

1. Hydrogen bond FORMATION
2. Van der WAALS forces
3. Covalent bonds
4. DIPOLE interactions

Answer :A
Discussion
18178.

Which of the following solutions are isotonic with one another ? (1) 0.15 M urea (2) 0.15 M CaCl_(2) (3) 0.1 M MgSO_(4) (4) 0.15 M glucose Select the correct answer using the codes given below :

Answer»

1 and 4
2 and 4
1, 2 and 4
2, 3 and 4

Solution :`pi=icRT`
(1) `pi(0.15"M UREA")=1xx0.15 "RT"=0.15"RT"`
(2) `pi(0.5"M" CaCl_(2))=3xx0.05 "RT"=0.15"RT"`
(3) `pi(0.1"M" MgSO_(4))=2xx0.1 "RT"=0.2"RT"`
(4) `pi(0.15 "M GLUCOSE")=1xx0.15"RT"=0.15"RT"`
Discussion
18179.

The salt which does not form coloured metaborate in borax bead test.

Answer»

`Fe_(2)(SO_(4))_(3)`
`Al_(2)(SO_(4))_(3)`
`Cr_(2)(SO_(4))_(3)`
`CoSO_(4)`

Solution :`(r_(x_(3)))/(r_(CH_(4)))=sqrt((M_(CH_(4)))/(M_(x_(3))))`
`(4//3)/(1)=sqrt((16)/(M_(x_(3))))""M_(x_(3))=9`
ATOMIC MASS x = 3
`V.D.=(9)/(2)=4.5""d=(MP)/(RT)`
Discussion
18180.

Tin dossolve in boiling caustic soda solution because of the formation of soluble:

Answer»

`SN(OH)_2`
`Sn(OH)_4`
`Na_2SnO_3`
NONE of these

Answer :C
Discussion
18181.

When 3-methylbutan-2-ol is treated with HBr, the following reaction takes place : CH_3-underset(CH_3)underset(|)CH-underset(OH)underset(|)CH-CH_3 overset(HBr)to CH_3 underset(CH_3)underset(|)overset(Br)overset(|)C-CH_2 - CH_3Give a mechanism for this reaction (Hint : The secondary carbocation formed in step-II rearranges to a more stable tertiary carbocation by a hydribe ion shift from 3rd carbon atom).

Answer»

Solution :Step-1: Protonation
`underset("3-Methylbutan-2-ol")(CH_3-underset(CH_3)underset(|)CH-underset(OH)underset(|)CH-CH_3) OVERSET(H^+)to CH_3-underset(CH_3)underset(|)CH-underset(+)underset(OH_2)underset(|)CH-CH_3`
Step-2:FORMATION of `2^@` CARBOCATION by elimination ofa water molecule
Discussion
18182.

which of the following has rubber like properties ?

Answer»

Fibres
Thermosetting POLYMERS
THERMOPLASTIC polymers
ELASTOMERS

ANSWER :D
Discussion
18183.

What is the effect of pH on the solution of K_(2)Cr_(2)O_(7) solution?

Answer»

Solution :In aqueous solution `:`` underset("Dichromate ion ( ORANGE red)")(Cr_(2)O_(7)^(2-))+H_(2)O hArr underset("Chromate ion ( YELLOW)") (2CrO_(4)^(2-))+ 2H^(+)`
In acidic MEDIUM (i.e., decreasing pH ) ,equilibrium SHIFTS backward and the colour is organe red. In basic medium (i.e., increasin pH ), equilibrium will shift forward and thesolution is yellow .
Discussion
18184.

Which of the following are used in aluminium extraction? Cryolite feldspar, carbon, ferrosilicon, iron, Nal, Calcium carbide, nitrogen gas, NaOH.

Answer»


SOLUTION :In the extraction of .Al..
Cryolite USED to decrease the M.pt. of `Al_(2)O_(3)` and increases it.s conductivity.
Gas carbon lined in side the iron tank acts as cathode. Anode is BUNCH of Carbon RODS.
NaOH used as leaching agent.
In serpecks process `Al_(2)O_(3)` heated with coke at `1800^(@)C` in the PRESENCE of `N_(2)` gas
`Al_(2)O_(3)+3C+N_(3) to 2AIN+3CO`
`:. 5` components are used in Al extraction.
Discussion
18185.

When acidulated water (dil. H_(2)SO_(4) solution) is electrolysed,w ill the pH of the solution be affected ? Justify your answer.

Answer»

Solution :* There is no change in PH value. pH value depend on the `H^(+)` ION concentration of any solution.
* In acidic water, electrolysis of dilute solution of `H_(2)SO_(4)` gives following reaction.
`H_(2)SO_(4) to 2H^(+)+SO_(4)^(2-)`
* Reduction of `H^(+)` ions is carried out near cathode.
`2H^(+)+2e^(-) to H_(2(g))`
* On the surface of anode `H_(2)O` get oxidized not `SO_(4)^(2-)` ion
`H_(2)O_((l)) to (1)/(2) O_(2)+2H^(+)+2e^(-)`. . . (ii)
OVERALL reaction=(i)+(ii)
`H_(2)O_((l)) to H_(2(g)) +(1)/(2)O_(2(g))`
* So, in this reaction, concentration of `H^(+)` or `OH^(-)` ions does not change. So, pH remains CONSTANT.
Discussion
18186.

What is conductivity ? Give note on it.

Answer»

Solution :* Conductivity (G) : The inverse of resistance (R) is called CONDUCTANCE (G).
`therefore G=(1)/(R)=(A)/(rhol)=k((A)/(l))`
Conductivity=`(1)/("resistance")=(1)/("resistivity "rho)((A)/(l))`
`k=(1)/(rho)=(1)/("resistivity")`
* SI unit of conductivity G : The SI unit of conductance is siemens, represented by the symbol .S. and is equal to `OHM^(-1)` (also known as mho) or `Omega^(-1)`.
`1S=ohm^(-1)=1Omega^(-1)=1mho`
* Conduction of CURRENT is LESS due to resistance of ions present in electrolytic cell.
Discussion
18187.

X underset(AlCl_(3))overset(HCl)to Y overset(KOH(aq))to C_(2)H_(5)OH In the above reaction reactant 'X' is

Answer»

`C_(2)H_(5)CI`
`C_(2)H_(2)`
`C_(2)H_(4)`
`C_(2)H_(5)Br`

ANSWER :C
Discussion
18188.

Which of the following reaction represent incorrect major product.

Answer»

`CH_(3)-overset(O)overset("||")(C)-NH-CH_(3) overset(KOBr)(rarr) CH_(3)-NH_(2)`


Answer :A
Discussion
18189.

What is ambidentate ligand ? Give an example ?

Answer»

Solution :AMBIDENTATE Ligands : Some unidentate ligands have more than one donor ATOM and these may co-ordinate to the METAL ion through either of the two atoms these types of ligands are called ambidentate ligands.
Exapme: `M larr NO_2` Nitro group
(N is the donor atom)
`M larr ONO` Nitro group
(O is the donor group)
Discussion
18190.

Which one of the following forms propane nitrile as the major product?

Answer»

`"Ethyl bromide"+"alcoholic KCN"`
`"Propyl bromide"+"alcoholic KCN"`
`"Propyl bromide"+"alcoholic AgCN"`
`"Ethyl bromide "+"alcoholic AgCN."`

Solution :`underset("bromide")underset("Ethyl")(CH_(3)CH_(2)Br)+KCN OVERSET("Alcohol")rarr underset("Propane nitrile")(CH_(3)CH_(2)CN)`
Discussion
18191.

When H_(2)S gas is passed into aq ZnCI_(2) solutionwhite ppt of ZnS is obtained.

Answer»


Solution :`ZnCI_(2) +H_(2)S rarr ZNS + 2HCI`
ZnS isformed the remainsoluble due to FORMATION of HCI ,ZnS is PRECIPITATE when `H_(2)S` is passed in ammoniv=calmediumhence false
Discussion
18192.

Which of the following is associated with Torsional strain?

Answer»

REPULSION between BOND pair of electrons
Size of the GROUPS present at adjacent atoms
Bond angle strain
Attraction of OPPOSITE charges

Answer :A
Discussion
18193.

Which equiations (s) might be used to illustrate the action of nitric acid as an oxidant ?

Answer»

<P>`P_(4)O_(10) + 4HNO_(3) to 4HPO_(3) + 2N_(2)O_(5)`
`6Fe^(2+) + 8HNO_(3) to 6Fe^(3+) + 2NO + 4H_(2)O + 6NO_(3)^(-)`
`CO_(3)^(2-) + 2HNO_(3) to CO_(2) + H_(2)O + 2NO_(3)^(-)`
`Cu + 4HNO_(3) to Cu^(2+) + 2NO_(3)^(-) + 2H_(2)O + 2NO_(2)`

Solution :N/A
Discussion
18194.

What is the mole fraction of a solute, in 2.5 m aqueous solution ?

Answer»

SOLUTION :`x_B = (m)/(m + (1000)/(M_A) ) = (2.5)/(2.5 + 1000/18) = (2.5 XX 18)/(1045)= 45/1045 = 0.043`
Discussion
18195.

Which one of the following has diamagnetism?

Answer»

`Co^(2+)`
`CU^(2+)`
`MN^(2+)`
`SC^(3+)`

ANSWER :D
Discussion
18196.

Which of the foil owing is most basic?

Answer»

`CH_(3)CH_(2)NH_(2)`
`CH_(3)CONH_(2)`
`C_(6)H_(5)CONHCH_(3)`
`NH_(2)NH_(2)`

Solution :In OPTION (d) due to /-effect of `NH_(2)` group, the electron DENSITY on the other N-atom decreases. As a result, `NH_(2)NH_(2)` is a much weaker base than `NH_(3)` and aliphatic amines. Further in options (b) and (c), due to -R-effecr of the C = O group, the electron-density on the N-atom decreases. As a result, amides are much weaker BASES than `NH_(3)` and aliphatic amines. Thus, cthylaminc is most basic, i.e. , option (a) is correct.
Discussion
18197.

Which of the following cannot be formed ?

Answer»

`He^(2+)`
`He^+`
He
`He_2`

ANSWER :D
Discussion
18198.

Which of the following conformations is most stable for butane ?

Answer»

STAGGERED
Skew
Gauche
Eclipsed

ANSWER :A
Discussion
18199.

Write the IUPAC names of the following coordination compounds : [Pt(NH_(3))_(2)Cl(NH_(2)CH_(3))]Cl

Answer»

SOLUTION :diamminechlorido(METHYLAMINE )PLATINUM(II) CHLORIDE.
Discussion
18200.

Which of the following are water pollutants?

Answer»

Smoke
Industrial waste
Detergent
Ammonia

Answer :B
Discussion