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23951.

The reaction take place by mechanism is

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`S_(N^(1))`
`S_(N^(2))`
`S_(N^(i))`
`S_(N^(AE))`

ANSWER :B
23952.

The reaction, "SO"_(2)"Cl"_(2)overset(k_(1))to"SO"_(2)+"Cl"_(2), is a first order reaction with k_(1)=2.2xx10^(-5)"sec"^(-1) at 575 K. What percentage of "SO"_(2)"Cl"_(2) will get decomposed in 90 minutes when the reaction is carried out at 575 K ?

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Solution :Since the REACTION is of the FIRST order (given), `k=(2.303)/(t)LOG""(a)/(a-x)`
Here, we are given that `k=2.2xx10^(-5)"SEC"^(-1)"",""t=90" MINUTES "=90xx60=5400" sec".`
`:.2.2xx10^(-5)s^(-1)=(2.303)/(5400s)log""(a)/(a-x)" or "log""(a)/(a-x)=0.0516" or "(a)/(a-x)="antilog "(0.0516)=1.127.`
or `""a=1.127a-1.127x" or "0.127a=1.127x`
`:.""(x)/(a)=(0.127)/(1.127)=0.113" or "%" decomposed "=0.113xx100=11.3%.`
23953.

The reaction SO_(2)Cl_(2) to SO_(2)+Cl_(2) is a first order reaction with half-life 3.15xx10^(4)s at 320^(@)C. What percentage of SO_(2)Cl_(2) would be decomposed on heating at 320^(@)C for 90 minutes?

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Solution :From half-life data, we can OBTAIN the value of k
`t_(1//2)=(0.693)/(k) or k= (0.693)/(3.15xx10^(4)s)`
Applying first order equation and substituting the values, we GET
`k=(2.303)/(t)"log"([A]_(0))/([A])`
or `(0.693)/(3.15xx10^(4)s)=(2.303)/(90xx60s)"log"(100)/([A])`
or `"log"(100)/([A])=(0.693 XX 90 xx 60)/(2.303xx3.15xx10^(4))=(0.301xx5400)/(3.15xx10^(4))=(16.254)/(315)=0.0516`
or `(100)/([A])="Antilog "0.0516=1.126`
or `[A]=(100)/(1.126=88.8%`
PERCENTAGE of `SO_(2)Cl_(2)` decomposed `=100-88.8=11.2%`.
23954.

The reaction sodium amalgam and water with fructose confirms the presence of ………. .

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SOLUTION :KETO GROUP
23955.

The reaction sequence given below gives product R. The structure of the product R is

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SOLUTION :The GIVEN REACTION is Hunsdiecker reaction.
23956.

The reaction sequence C_(6)H_(5)-CH=CH-Choverset([X])rarr C_(6)H_(5)-CH_(2)-CH_(2)-CH_(2)OH [X] will be

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`LiAlH_(4)`
`NaBH_(4)`
ALUMINIUM ISOPROPOXIDE
All of these

Answer :A
23957.

The reaction S_(2)O_(8)^(2-) + 3I^(-) rarr 2SO_(4)^(2-) + I_(3)^(-) is of first order both with respect to the persulphate and iodide ions. Taking the initial concentration as 'a' and 'b' respectively and taking x as the concentration of the trioxide at time t a differential rate equation can be written. Two suggested mechanisms for the reaction are: (I) S_(2)O_(8)^(2-)+I^(-) rarr SO_(4)I^(-)+SO_(4)^(2-)(fast) I^(-)+SO_(4)I^(-) overset(k_(1)) rarr I_(2) + SO_(4)^(2-)(slow) I^(-)+I_(2) overset (k_(2)) rarr I_(3)^(-)(fast) (II) S_(2)O_(8)^(2-)+I^(-) overset(k_(1)) rarr S_(2) O_(8) I^(3-)(slow) S_(2)O_(8)I^(3-) overset(k_(2)) rarr 2SO_(4)^(2-) +I^(+)(fast) I^(+)+I^(-) overset (k_(3)) rarr I_(2)(fast) I_(2)+I^(-) overset(k_(4)) rarr I_(3)^(-)(fast) For the reaction I_(2)+2S_(2)O_(3)^(2-) rarr S_(4)O_(6)^(2-)+ 2I^(-) (P) -(d[I_(2)])/(dt)=-1/2(d[S_(2)O_(3)^(2-)])/(dt) (Q) -(d[I_(2)])/(dt)=-2(d[S_(2)O_(3)^(2-)])/(dt) (R) (d[I^(-)])/(dt)=-2(d[I_(2)])/(dt)xx(d[S_(2)O_(3)^(2-)])/(dt) (S)(d[S_(4)O_(6)^(2-)])/(dt)=1/2(d[I^(-)])/(dt)

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<P>only (P)
(P) and (S)
(Q) and (S)
only (R)

ANSWER :B
23958.

The reaction S_(2)O_(8)^(2-) + 3I^(-) rarr 2SO_(4)^(2-) + I_(3)^(-) is of first order both with respect to the persulphate and iodide ions. Taking the initial concentration as 'a' and 'b' respectively and taking x as the concentration of the trioxide at time t a differential rate equation can be written. Two suggested mechanisms for the reaction are: (I) S_(2)O_(8)^(2-)+I^(-) rarr SO_(4)I^(-)+SO_(4)^(2-)(fast) I^(-)+SO_(4)I^(-) overset(k_(1)) rarr I_(2) + SO_(4)^(2-)(slow) I^(-)+I_(2) overset (k_(2)) rarr I_(3)^(-)(fast) (II) S_(2)O_(8)^(2-)+I^(-) overset(k_(1)) rarr S_(2) O_(8) I^(3-)(slow) S_(2)O_(8)I^(3-) overset(k_(2)) rarr 2SO_(4)^(2-) +I^(+)(fast) I^(+)+I^(-) overset (k_(3)) rarr I_(2)(fast) I_(2)+I^(-) overset(k_(4)) rarr I_(3)^(-)(fast) Which mechanism is consistent with the facts given about the reaction rate equation?

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MECHANISM(I)
Mechanism(II)
Both (I) and (II)
NEITHER (I) nor (II)

ANSWER :B
23959.

The reactionSb_2 S_3(s) + 3H_2(g) iff 2Sb(s) + 3H_2S(g)was studied by analysing the equilibriuin mixture for the amount of H S produced. A vessel whose volume was 2.5 litre was filled with 0.01 mole of Sb_2S_3and 0.01 mole of H_2S . After the mixture came to equilibriuin in the closed vessel at 440^@C , the gaseous mixture was removed and the H_2S was dissolved in water, Sufficient Pb^(2+)ions were added to react completely with the H_2Sto precipitate PbS. If 1.029 g of PbS was obtained, what is the value of K_cat 440^@C?

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ANSWER :0.43
23960.

The reaction S_(2)O_(8)^(2-) + 3I^(-) rarr 2SO_(4)^(2-) + I_(3)^(-) is of first order both with respect to the persulphate and iodide ions. Taking the initial concentration as 'a' and 'b' respectively and taking x as the concentration of the trioxide at time t a differential rate equation can be written. Two suggested mechanisms for the reaction are: (I) S_(2)O_(8)^(2-)+I^(-) rarr SO_(4)I^(-)+SO_(4)^(2-)(fast) I^(-)+SO_(4)I^(-) overset(k_(1)) rarr I_(2) + SO_(4)^(2-)(slow) I^(-)+I_(2) overset (k_(2)) rarr I_(3)^(-)(fast) (II) S_(2)O_(8)^(2-)+I^(-) overset(k_(1)) rarr S_(2) O_(8) I^(3-)(slow) S_(2)O_(8)I^(3-) overset(k_(2)) rarr 2SO_(4)^(2-) +I^(+)(fast) I^(+)+I^(-) overset (k_(3)) rarr I_(2)(fast) I_(2)+I^(-) overset(k_(4)) rarr I_(3)^(-)(fast) How could the progress of this reaction be best monitored?

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By monitoring the colour of the REACTION mixture
By TITRATION of `I_(3)^(-)` with hypo
By precipitation of `I^(-)` with `Ag^(+)`
By monitoring the change in pressure.

Answer :B
23961.

The reaction S_(2)O_(8)^(2-) + 3I^(-) rarr 2SO_(4)^(2-) + I_(3)^(-) is of first order both with respect to the persulphate and iodide ions. Taking the initial concentration as 'a' and 'b' respectively and taking x as the concentration of the trioxide at time t a differential rate equation can be written. Two suggested mechanisms for the reaction are: (I) S_(2)O_(8)^(2-)+I^(-) rarr SO_(4)I^(-)+SO_(4)^(2-)(fast) I^(-)+SO_(4)I^(-) overset(k_(1)) rarr I_(2) + SO_(4)^(2-)(slow) I^(-)+I_(2) overset (k_(2)) rarr I_(3)^(-)(fast) (II) S_(2)O_(8)^(2-)+I^(-) overset(k_(1)) rarr S_(2) O_(8) I^(3-)(slow) S_(2)O_(8)I^(3-) overset(k_(2)) rarr 2SO_(4)^(2-) +I^(+)(fast) I^(+)+I^(-) overset (k_(3)) rarr I_(2)(fast) I_(2)+I^(-) overset(k_(4)) rarr I_(3)^(-)(fast) The general differential equation for the above reaction is:

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`(DX)/(DT) =K[a-x][b-3x]`
`(dx)/(dt)=-k[a-x][b-3x](k GT 0)`
`(dx)/(dt)=k[a-x][b-x](k gt 0)`
`(dx)/(dt)=-k[a-x][b-x](k gt 0)`

Answer :A
23962.

The reaction, RX + R-ONa to R-O-R + NaX is called

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WURTZ REACTION
WILLIAMSON's synthesis
Kolbe's reaction
Hofmann bromamide reaction

Answer :B
23963.

The reaction (s) which does (da) occur in the blast furnace in the extraction of iron from hacmatite are is (are)

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`Fe_(2)O_(3)+CO to 2FeO+CO_(2)`
`FeO+CO to Fe+ CO_(2)`
`Fe_(2)O_(3)+3C to 2FE+3CO`
`CaO+SiO_(2) to CaSiO_(3)`

Solution :Reactions OCCURING in blast furnace are
`3Fe_(2)O_(3)+CO OVERSET(300-400^(@)C) to 2Fe_(3)O_(4)+CO_(2)`
`Fe_(2)O_(4)+CO overset(500-600^(@)C) to 3FeO+CO_(2)`
`FeO+CO overset(700^(@)C toFe+CO_(2)`
Slage is also formed in blast furnace.
`SiO_(2)+CaO to CaSiO_(3)` (slag)
23964.

The reaction RX+Nu^(-)toRNu+X^(-) is an example of

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NUCLEOPHILIC SUBSTITUTION
electrophilic substitution
Nucleophilic addition
Electrophilic addition

Answer :A
23965.

The reaction ,ROH+H_2CN_2 in the presence of HBF_4 gives the following roduct :

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`ROCH_3`
`RCH_2OH`
`ROHCN_2N_2`
`RCH_2CH_3`

SOLUTION :NA
23966.

R-X+2Na+X-Roverset("Dry other")underset(Delta)toR-R+2NaX.If R is aryl group , what is thename of the reaction.

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Kolbe's REACTION
WURTZ reaction
Friedel Crafts reaction
GRIGNARD reaction

Answer :B
23967.

The reaction represents

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nucleophilic substitution
electrophilic addition
electrophilic substitution
elimination REACTION

ANSWER :B
23968.

The reaction ,RCOOH overset(C_2H_5OH+Na)rarrRCH_2OH is called:

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Corey HOUSE reaction
Bonveault-Blanc reaction
Clemmensen reduction
None

Answer :B
23969.

The reaction,RCl + NaI overset(" Dry acetone")to R - I + NaCl is known as

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WURTZ REACTION
FITTING reaction
Wurtz-Fitting reaction
FINKELSTEIN's reaction .

ANSWER :D
23970.

The reaction , RCH_(2)CH_(2)COOHunderset(Br_(2))overset("Red P")toRCH_(2)underset(Br)underset(|)(CHCOOH)is called :

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REIMER Tiemann REACTION
HELL Volhard ZELINSKY reaction
Cannizzaro 's reaction
Sandmeyer 's reaction.

Answer :B
23971.

The reaction RCH_(2)CH_(2)COOHoverset(Red P + Br_2) toR - CH_(2) - CH(Br) -COOH

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Reimer- Tiemann REACTION
Hell-Volhard - Zelinsky reaction
CANNIZZARO reaction
Sandmeyer reaction .

Answer :B
23972.

The reaction RCH_(2)CH_(2)COOH overset(Red P)underset(Br_(2))toRCH_(2)-underset(Br)underset(|)(C)HCOOH is called as

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CANNIZZARO REACTION
Hell Volhared ZELINSKY reaction
Reimer Teimann reaction
Sandmeyer reaction

ANSWER :B
23973.

The reaction rate the does not decrease with time is

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pseudo first ORDER reaction
first order reaction
zero order reaction
SECOND order reaction

Answer :C
23974.

The reactionRC-=CR overset("Lindlar catalyst")underset (H_2) (rarr)

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CIS alkene
Trans alkene
Allkane
None of these

Answer :C
23975.

The reaction rate at a given temperature is slower when :

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The ENERGY of ACTIVATION is higher
The energy of activation is lower
Entropy changes
Initial CONCENTRATION of the REACTION REMAINS constant

Answer :A
23976.

The reaction R_(2)C=NNH_(2)overset(C_(2)H_(5)Ona)rarrR_(2)CH_(2)+N_(2) is called

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CLEMMENSEN REDUCTION
Hunsdiecker REACTION
Tischenko reaction
Wolff-Kishner reduction.

SOLUTION :
This is Wolff-kishner Reduction.
23977.

The reaction rate at a given temperature becomes slower then

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The FREE energy of activation is HIGHER
The free energy of activation is lower
The entropy CHANGES
The initial concentration of the reactants remains CONSTANT

Solution :Slowest reaction rate indicates higher energy of activation .
23978.

The reaction rate at a given temperature becomes slower,then ……

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the free ENERGY of activation is higher
the free energy of activation is lower
the ENTROPY changes.
the INITIAL CONCENTRATION of the REACTANTS remains constant.

Answer :A
23979.

The reaction R_(2)C="NNH"_(2)overset(C_(2)H_(5)ONa)rarrR_(2)CH_(2)+N_(2) is called

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CLEMMENSEN reduction
Hundicker reaction
Fischenko reaction
Wolff Kishner reducion.

Solution :DUE to the PRESENCE of `alpha` HYDROGEN in 2-Methyl PROPIONALDEHYDE
23980.

The reaction R - C -=N underset(H_(3)O^(+))overset(SnCl_(2)+HCl)to R - CHO + NH_(3)

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ROSENMUND's reduction
STEPHEN's reduction
Clemmenson's reduction
CANNIZZARO's reaction

ANSWER :B
23981.

The reaction R-Cl+KIoverset("Acetone")rarrRI+KCl is known as :

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Hunsdiecker reaction
Finkelstein reaction
WURTZ Fitting reaction
Ulmann reaction

ANSWER :B
23982.

The reaction quotient, Q is expresse as some as, that for equilibrium constant K.The value of Q for the given composition of a reaction mixture helps us to know whether the reaction will move forward or backward or remain in equlibrium. It helphs to pedict the effect of pressure on the direction of the gaseous reaction. In some reactions, addition of inert gas also favours either the formation of reactansts or products. The value of equlibrium constant of a reaction changes with change of temperture and the change is gives by van't Hoff equation, d ln K_(p)//dT=DeltaH^(@)//RT^(2) where enthalpy change, DeltaH^(@), is taken as constant in the small temperatue range. For the above reaction in equlibrium, helium gas was added but the mixture was allowed to expand to keep the pressure constant. Then

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More of ammonia will be formed
Ammonia will dissociate back into `N_(2)and H_(2)`
There will be no effect on EQULIBRIUM
Equlibrium constant of the reaction will change

SOLUTION :As volume in increased, concentration will decrease. To KEEP `K_(c)` constant, `[NH_(3)]` shouyld decrease more.
23983.

The reaction quotient, Q is expresse as some as, that for equilibrium constant K.The value of Q for the given composition of a reaction mixture helps us to know whether the reaction will move forward or backward or remain in equlibrium. It helphs to pedict the effect of pressure on the direction of the gaseous reaction. In some reactions, addition of inert gas also favours either the formation of reactansts or products. The value of equlibrium constant of a reaction changes with change of temperture and the change is gives by van't Hoff equation, d ln K_(p)//dT=DeltaH^(@)//RT^(2) where enthalpy change, DeltaH^(@), is taken as constant in the small temperatue range. Which of the following will be correct

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Plot of LN `K_(p)` VERSUS `1//T^(2)` will be linear with +ve slope
Plot of ln `K_(p)` versus `1//T`will be linear with +ve slope
Plot of ln `K_(p)` versus `1//T^(2)` will be linear with-ve slope
Plot of ln `K_(p)` versus `1//T` will be linear with -ve slope

SOLUTION :`(d lnK_(p))/(dT)=(DeltaH^(@))/(RT^(2))"GIVEN ln"K_(p)=(DeltaH^(@))/(RT)."Hence, polt of " ln K_(p)vs1//T` will be linear with slope `=-DeltaH^(@)//R.`
23984.

The reaction quotient (Q) for the reaction N_(2(g))+3H_(2(g))iff2NH_(3(g)) is given by Q=([NH_(3)]^(2))/([N_(2)][H_(2)]^(3)) The reaction will proceed from right to left if

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`Q=K_(c)`
`QltK_(c)`
`QgtK_(c)`
`Q=0`

Solution :The reaction PROCEEDS from right to left when `QgtK_(c)`, so that Q tends to decrease to BECOME EQUAL to `K_(c)`.
23985.

The reaction quotient (Q) for the reaction N_(2(g))+3H_(2(g))hArr2NH_(3(g)) is given by Q=([NH_(3)]^(2))/([N_(2)][H_(2)]^(3)). The reaction will proceed from right to left is

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`Q=0`
`Q=K_(C)`
`QltK_(c)`
`QgtK_(c)`

SOLUTION :If `QgtK_(c)` reaction will proceed right to left to decrease CONCENTRATION of product.
23986.

The reaction products of the reaction between C_6H_5NH_2 ,CHCl_3 and KOH are :

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`C_6H_5NC+KCL`
`C_6H_5OH+NH_4Cl +H_2O`
`C_6H_5Cl +NH_4Cl+KCL`
`C_6H_5CN+KCl`

ANSWER :A
23987.

The reaction products of

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`C_(6)H_(5)OH+ CH_(3)I`
`C_(6)H_(5)I+CH_(3)OH`
`C_(6)H_(5)CH_(3)+HOI`
`C_(6)H_(6)+CH_(3)OI`

Answer :A
23988.

The compound with zero dipole moment is

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Methanal
Ethanal
Propanal
Methyl ethanoate

Answer :A
23989.

Which compound on reaction with ethyl magnesium bromide and water will from 2- methyl-2 butanol:

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Methanal
Ethanal
Propanal
Methyl ethanoate

Answer :A
23990.

The reaction product of the compound ‘A’ with excess of methyl magnesium iodide followed by acidic hydrolysis yields tertiary butanol. The compound could be

Answer»

methanol
ethanol
PROPANAL
METHYL ethanoate

ANSWER :D
23991.

The reaction product of C_(6)H_(5)OCH_(3)+Hioverset(/_\)rarr…. Is :

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`C_(6)H_(5)OH+CH_(3)I`
`C_(6)H_(5)I+CH_(3)OH`
`C_(6)H_(5)CH_(3)+HOI`
`C_(6)H_(6)+CH_(3)OH`

Solution :N//A
23992.

The reaction Ph-OH + dilute HNO_3 to? Gives predominately

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2-nitrocarbolicacid
4-nitrocarbolicacid
2,4,6- trinitrocarbolic acid
3-nitro CARBOLIC acid

Answer :A
23993.

The reaction P_(4)+3NaOH+3H_(2)Oto3NaH_(2)PO_(2)+PH_(3) is an example of

Answer»

DISPROPORTIONATION reaction
Neutralisation reaction
Double DECOMPOSITION reaction
Pyrolytic reaction

Answer :A
23994.

The reaction overset(+ )(ArN_2 Cl^(-) overset(Cu// HCl )to ArCl +N_2 +CuCl is named as

Answer»

Sandmeyer REACTION
Gatterman reaction
Claisen reaction
Carbylamine reaction

Solution :`ArN_(2)^(+) CL^(-)OVERSET(CU // HCl ) toArCl+N_2+Cu Cl `. It is Gatterman reaction.
23995.

The reaction of zinc with dilute and concentrated nitric acid respectively produces :

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`NO_(2)` and `N_(2)O`
`N_(2)O` and `NO_(2)`
`NO_(2)` and NO
NO and `N_(2)O`

Solution :`4Zn + underset("dilute")(10HNO_(3)) to 4Zn(NO_(3))_(2) + N_(2)O + 5H_(2)O`
`Zn + underset("CONC")(4HNO_(3)) to Zn(NO_(3))_(2) + 2NO_(2) + 2H_(2)O`
23996.

The reaction of zinc with dilute and concentrated nitric acid, respectively, produce

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`NO_(2) and N_(2)O`
`N_(2)O and NO_(2)`
`NO_(2) and NO`
`NO and N_(2)O`

ANSWER :B
23997.

The reaction of zinc with dilute and concentrated nitric acid, respectively produces -

Answer»

`NO_2 and N_2O`
`N_2O and NO_2`
`NO_2 and NO`
`NO and N_2O`

ANSWER :B
23998.

The reaction of white phosphorus with aqueous NaOH gives phosphine along with another compound. The reaction type , the oxidation states of phosphorus in phosphine and the other product are respectively

Answer»

redox reaction , -3 and -5
redox reaction , +3 and +5
disproportionation reaction , -3 and -5
disproportionation reaction , -3 and +1

SOLUTION :`overset(0)(P_(4))+3NaOH + 3H_(2)O RARR 3NaH_(2) overset(+1)(PO_(2))+overset(-3)(PH_(3))`
It is a disproportionation reaction. In this reaction, oxidation state of P increases from 0 in `P_(4)` to +1 in `NaH_(2)PO_(2)` and decreases from 0 in `P_(4)` to -3 in `PH_(3)`.
23999.

The reaction of white phosphorus with aqueous NaOH gives phosphine along with another phosphorus containing compound. The reaction type , the oxidation states of phosphorus in phosphine and the other product are respectively

Answer»

REDOX REACTION , –3 and –5
redox reaction , +3 and +5
disproportionation reaction , –3 and +1
disproportionation reaction , –3 and +3

Answer :C
24000.

The reaction of which halogens with water is endothermic

Answer»

`F_(2)`<BR>`Cl_(2)`
`Br_(2)`
`I_(2)`

SOLUTION :`DeltaG=Ve`, non-spontaneous