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24051.	The reaction of Na_2 S_2 O_3 with iodine gives
Answer» Sodium sulphide Sodium SULPHITE Sodium sulphate Sodium TETRATHIONATE Solution :`2Na_(2)S_(2)O_(3) + I_(2) to Na_(2)S_(4)O_(8) + 2NaI`.

24052.	Thereactionof(##MST_MSC_JMA_ORG_CHE_C19_E02_009_Q01.png" width="80%">withHBrgives
Answer» ANSWER :B

24053.	The reaction of methyltrichloroacetate (Cl_(3)"CCO"_(2) "Me") with sodium methoxde (NaOMe) generates
Answer» CARBOCATION CARBENE carbenion carbon RADICAL SOLUTION : THEREFORE, thr product is carbene.

24054.	The reaction of hydrogen and iodine monochlride is given as L H_(2)(g) + 2ICI(g) to 2HCl(g) + I_(2)(g) This reaction is of first order with respect to H_(2)(g) and ICI(g). The following mechanism was proposed for the reaction: Mechanism A: H_(2)(g) + 2ICl(g) to HCl(g) + HI(g), slow HI(g) + ICI(g) to HCI(g) + I_(2)(g) , fast Which of the above mechanism (s) can be consistent with the given information about the reaction?
Answer» A and B both neither A nor B A only B only Solution :d) In the REACTION, slow STEP is the RATE DETERMINING step as given in the mechanism B.

24055.	The reaction of Lucas reagent is fast with
Answer» `(CH_(3))_(3)COH` `(CH_(3))_(2)CHOH` `CH_(3)(CH_(2))_(2)OH` `CH_(3)CH_(2)OH` Answer :A

24056.	The reaction of KMnO_4 and HCl results in
Answer» OXIDATION of Mn in `KMnO_4` and production of `Cl_2` oxidation of Mn in `KMnO_4` and production of `H_2` REDUCTION of Mn in `KMnO_4` and production of `Cl_2` none of these Solution :`2KMnO_4+ 16 overset(-1 )(HCI )to2KCI+2overset( +2) (2MnCI_2 )+ 8 H_2O +5 overset(0 ) CI_2` hereO.Nof Mndecreases from ` +7`in `KMnO_4` of+2`MnCI_2`and thatof CIincreasesfrom ` -1`in HCIto 0in `CI_2`thusreducationof Mnin ` KMnO_4` occurswith producationof `CI_2 `

24057.	The reaction of hydrogen , and iodine monochloride is represented by the equation: H_(2)(g)+2ICl(g)+I_(2)(g) This reaction is first-order in H_(2)(g) and also first-order is ICl(g) . Which of these proposed mechansim can be cnsistent with the given information about this reaction? Mechanism I: H_(2)(g) +2ICl(g) rarr 2HCl(g) +I_(2)(g) MechanismII: H_(2)(g) +2ICl(g) overset("slow")rarrHCl(g) +HI(g) HI(g)+ICl(g) overset("first")rarr HCl(g)+I_(2)(g)
Answer» I only II only Both I and II Neither I nor II Answer :B

24058.	The reaction of hydrogen bromide with propene in absence of peroxide is an example of a/an
Answer» FREE RADICAL addition nucleophilic addition electrophilic substitution electrophilic addition Answer :D

24059.	The reaction of hydrogen and iodine monochloride is given as H_(2 (g)) + 2I Cl_((g)) + I_(2 (g)) This reaction is of first order with respect to H_(2 (g)) and I Cl_((g)) following mechanisms were proposed Mechanism A : H_(2(g)) + 2I Cl_((g)) to HCl_((g)) + I_(2(g)) Mechanism B : {:(H_(2 (g)) + ICl_((g)) to HCl_((g)) + HI_((g)) "Slow") , (HI_((g)) + ICl_((g)) to HCl_((g)) + I_(2(g)) "Fast"):} Which of the above mechanism(s) can be consists with the given information about the reaction
Answer» B only A and B only NEITHER A nor B A only Solution :Rate of reaction determined by rate determining step or slowest step . Because the mechanism B involves ONE molecule of I CL in slowest step so mechanism B is APPROXIMATE .

24060.	The reaction of HNO_(2) with 'A' gives quaternary ammonium salt. A is
Answer» METHYL AMINE Dimethyl amine TRIMETHYL amine Aniline Solution :`R_(3)N+HONOrarrR_(3)N.HONO` called as QUATERNARY ammonium SALT.

24061.	The reaction of HCOOH with conc.H_2SO_4 give :
Answer» `CO_2` CO Oxalic ACID ACETIC acid ANSWER :B

24062.	The reaction ofHCOOH with conc. H_2SO_4 gives
Answer» `CO_2` `CO` OXALIC acid Acetic acid Answer :B

24063.	The reaction of HBr with ethylene is an example of
Answer» SUBSTITUTION reaction Polymerisation Condensation reaction Addition reaction Answer :D

24064.	The reaction of HCOOH with conc. H_(2)SO_(4) gives
Answer» `CO_(2)` `H_(2)C_(2)O_(4)` CO `CH_(3)COOH` Answer :C

24065.	The reaction of H_(2)O_(2) with hydrogen sulphide is an example of ………… reaction.
Answer» ADDITION oxidation reduction acidic Solution :When `H_(2)O_(2)` is reacted with hydrogen SULPHIDE `(H_(2)S)`, it form S and water. In this REACTION `H_(2)S` is oxidised to sulphur. `H_(2)O_(2)` act as oxidising agent. `H_(2)O_(2) + H_(2)S rarr S + 2 H_(2)O`

24066.	The reaction of HBr with
Answer» ANSWER :B

24067.	The reaction of glucose with Tollen's reagent or Fehling's solution confims the presenceof………………..group in glucose.
Answer» SOLUTION :ALDEHYDE

24068.	The reaction of glucose with red P+HI is called :
Answer» SANDMEYER's REACTION Reformatsky reaction GATTERMANN reaction REDUCTION ANSWER :D

24069.	The reaction of glucose with redP+HI is called :
Answer» SANDMEYER's REACTION Reformatsky reaction GATTERMANN reaction REDUCTION ANSWER :D

24070.	The reaction of ethylmagnesium iodide with acetaldehyde gives after acidification
Answer» 2-Butanol 1-Butanol 2-Methyl-2-propanol 2-Methylpropanol Answer :A

24071.	The reaction of ethylene glycol with PI_3gives …………………. .
Answer» `CH_2= CHI` `ICH_2 -CH_2I` `CH_2 = CH_2` `CH -= CH` SOLUTION :`CH_2 = CH_2`

24072.	The reaction of ethylene bromide with zinc yields:
Answer» Alkane Alkene Alkyne All of these Answer :B

24073.	The reaction of ethylene glycol with PI_(3) gives
Answer» `ICH_(2)CH_(2)I` `CH_(2)=CH_(2)` `CH_(2)=CHI` `ICH=CHI` SOLUTION :`{:(CH_(2)OH ""CH_(2)I),(\|""+ PI_(3) to \|""UNDERSET(-I_(2))to CH_(2)=CH_(2)),(CH_(2)OH""CH_(2)I):}`

24074.	The reaction of ethyl p - amiobenzoate with HNO_2 and then with HBF_4 yields a compounds (X), a crystalline ionic compound. Compound (X) , when heated forms C_9H_9O_2F(Y). The compound (Y) is
Answer» <P>ETHYL p - fluorobenzoate ethyl o - fluorobenzoate ethyl m - fluorobenzoate MIXTURE of all the above ANSWER :A

24075.	The reaction of ethyl alcohol and methyl magnesium bromide gives:
Answer» `CH_4` `C_2H_6` `C_3H_8` None Answer :A

24076.	The reaction of ether with HI is preferred than HBr because
Answer» HI is a stronger ACID than HBr<BR>HI gives a higher CONCENTRATION of oxonium ion `I^-`is a better NUCLEOPHILE in `SN^2` reaction than the `Br^-` ion all of these Answer :D

24077.	The reaction of ethene with oxygen in presence of a silver catalyst gives:
Answer» ETHYLENE glycol Ethylene epoxide Glyoxal Acetaldehyde Answer :B

24078.	The reaction of ethanol with H_2SO_4 does not give:
Answer» `C_2H_4` `C_2H_5OC_2H_5` `C_2H_2` `C_2H_5HSO_4` ANSWER :C

24079.	The reaction of dimerisation of NO_(2) in N_(2)O_(4) is 2NO_(2)hArrN_(2)O_(4). The reaction is carried out by taking 1 mole each of NO_(2) and N_(2)O_(4) in a closed vessel of 1 litre at 400 K. The equilibrium pressure was found to be 77 atm. After attaining the equilibrium, 1 mole of N_(2)O_(4) is added in the quilibrium mixture.The total pressure at equilibrium would be:
Answer» `65.2 atm` `121.5 atm` `140.0 atm` `128.2 atm` Solution :`{:(N_(2)O_(4),hArr,2NO_(2)),(2,,1),((2-x),,(1+2x)):}` `K_(C)=((1+2x)^(2))/((2-x))=4.44` `:. X=0.7` TOTAL MOLE `=3+x=3+0.7=3.7` `=121.50 atm`

24080.	The reaction of electrolysis of sodium acetate to form ethane is known as ...
Answer» KOLBE's ELECTROLYTIC DECARBOXYLATION Perkin's REACTION Clemmenson reaction CANNIZARO reaction Solution :Kolbe.s electrolytic decarboxylation

24081.	The reaction of dimerisation of NO_(2) in N_(2)O_(4) is 2NO_(2)hArrN_(2)O_(4). The reaction is carried out by taking 1 mole each of NO_(2) and N_(2)O_(4) in a closed vessel of 1 litre at 400 K. The equilibrium pressure was found to be 77 atm. Addition of one mole of an inert gas to the above equilibrium shows that degree of dissociation and equilibrium pressure of N_(2)O_(4) is
Answer» `prop` decrease, `P=77 atm` `prop` increase, `P=77 atm` `prop` does not change, `P=110.0 atm` `prop` DECREASES, `P=110.0 atm` Solution :The DISSOCIATION of `N_(2)O_(4)` remains unaffected since addition of inert gas at CONSTANT volumedoes not change `'alpha'` ALSO `P=3.35xx0.0821xx400=110 atm`

24082.	The reaction of dimerisation of NO_(2) in N_(2)O_(4) is 2NO_(2)hArrN_(2)O_(4). The reaction is carried out by taking 1 mole each of NO_(2) and N_(2)O_(4) in a closed vessel of 1 litre at 400 K. The equilibrium pressure was found to be 77 atm. The molecular weight of N_(2)O_(4) in equilibrium mixture, when equilibrium pressure in 77 atm is:
Answer» `58.72` `76.5` `62.2` `82.4` SOLUTION :`0.65xx92+1.70xx46=Mxx2.35` `:. M=58.72`

24083.	The reaction of dimerisation of NO_(2) in N_(2)O_(4) is 2NO_(2)hArrN_(2)O_(4). The reaction is carried out by taking 1 mole each of NO_(2) and N_(2)O_(4) in a closed vessel of 1 litre at 400 K. The equilibrium pressure was found to be 77 atm. The ratio of moles of N_(2)O_(4) and NO_(2) at equilibrium is :
Answer» `2.62` 0.38` `3.62` `0.28` SOLUTION :`(n_(N_(2)O_(4)))/(n_(N O_(2)))=(1-x)/(1+2x)=0.65/1.70=0.38`

24084.	The reaction of dimerisation of NO_(2) in N_(2)O_(4) is 2NO_(2)hArrN_(2)O_(4). The reaction is carried out by taking 1 mole each of NO_(2) and N_(2)O_(4) in a closed vessel of 1 litre at 400 K. The equilibrium pressure was found to be 77 atm. The equilibrium pressure at which dissociation of N_(2)O_(4) will show degree of dissociation of N_(2)O_(4) to be 0.50 in the above case:
Answer» `82.1 ATM` `65.7 atm` `72.0 atm` `70.0 atm` SOLUTION :`{:(N_(2)O_(4),hArr,2NO_(2)),(1,,1),(0.5,,1+0.5xx2):}` Moles at equilibrium `=2.5` `:. P_(at EQ.)=2.5xx0.0821xx400` `=82.1 atm`

24085.	The reaction of dimerisation of NO_(2) in N_(2)O_(4) is 2NO_(2)hArrN_(2)O_(4). The reaction is carried out by taking 1 mole each of NO_(2) and N_(2)O_(4) in a closed vessel of 1 litre at 400 K. The equilibrium pressure was found to be 77 atm. Which statements is correct for given values of teh reactions.?
Answer» Dissociation of `N_(2)O_(4)` occurs with degree of dissociation of `N_(2)O_(4) 0.35` Formation of `NO_(2)` occurs and TOTAL moles of `NO_(2)` at equilibrium `1.35` Dissociation of `N_(2)O_(4)` occurs leaving `0.35` moles at equilibrium Formation of `NO_(2)` occurs with total moles at equilibrium `2.70` SOLUTION :`underset(1)(2NO_(2)) hArr underset(N_(2)O_(4))` Total moles TAKEN `=2`, `:. P=2xx0.0821xx400=65.7 atm` Given equilibrium pressure is `77` atm, thus reaction should SHOW the CHANGE where total number of moles increases i.e., dissociation of `N_(2)O_(4)`. `{:(N_(2)O_(4),hArr,2NO_(2)),(1,,1),(1-x,,1+2x):}` Total moles at eq.=`2+x` `=(PV)/(RT)=(77xx1)/(0.0821xx400)=2.35` `:. x=0.35`

24086.	The reaction of dimerisation of NO_(2) in N_(2)O_(4) is 2NO_(2)hArrN_(2)O_(4). The reaction is carried out by taking 1 mole each of NO_(2) and N_(2)O_(4) in a closed vessel of 1 litre at 400 K. The equilibrium pressure was found to be 77 atm. The numerical value of K_(c) and K_(p) the reaction actually taking place in container is :
Answer» `4.44,145.8` `0.23,7.56` `146.13,4.8xx10^(3)` `6.8xx10^(-3),6` Solution :`K_(C)=((1.70)^(2))/0.65=4.44` and `K_(p)=K_(c)xx(RT)^(DELTAN)` `=4.44xx0.0821xx400=145.8`

24087.	The reaction of cyanamide, NH_(4)CN(s), with dioxygen was carried out in a bomb calorimeter, and DeltaU was found to be -742.7 kJ mol^(-1) at 298 K. calculate the enthalpy change for the reaction at 298 K. NH_(4)CN(g)+(3)/(2)O_(2)(g) to N_(2)(g)+CO_(2)(g)+H_(2)O(l)
Answer» `-741.46" kJ "mol^(-1)` `741.46" kJ "mol^(-1)` `241.46 " kJ "mol^(-1)` `-241.6" kJ "mol^(-1)` Solution :`NH_(4)CN(s)+(3)/(2)O_(2)(g) to N_(2)(g)+CO_(2)(g)+H_(2)O(l)` `Deltan_(g)=n_(p)-n_(r)=2-(3)/(2)=(1)/(2)=0.5` `DeltaH=DeltaU+Deltan_(g)RT` `DeltaH=-742.7" kJ "mol^(-1)` `+(0.5xx8.314xx10^(-3)" kJ "mol^(-1)xx298K)` `=-743.7+1238.786xx10^(-3)` `=741.46" kJ "mol^(-1)`

24088.	The reaction of Cu with hot conc. H_(2)SO_(4) produc
Answer» `SO_(2)` `H_(2)S` `H_(2)` `CU^(+)`ions Answer :A

24089.	The conversion of primary aromtatic amines in to diazonium salts is known as
Answer» esterificationof NITROGEN COMBINATION of nitrogenand HALOGEN diazotisation dinitration SOLUTION :Definition

24090.	The reaction of conc. HNO_3 and phenol forms
Answer» BENZOIC acid salicylic acid o- and p-nitrophenol picric acid Answer :D

24091.	The reaction of conc. HNO_(3) and phenol forms
Answer» BENZOIC acid Salicylic acid o-and p-nitrophenol Picric acid Solution :

24092.	The reaction of Cl_(2) gas with cold-dilute and hot-concentrated NaOH in water give sodium salts to two (different) oxoacids of chlorine, P and Q, respectively. The Cl_(2) gas reacts with SO_(2) gas, in presence of charcoal, to give a product R. R reacts with white phosphours to give a compound S. On hydrolysis. S gives an oxoacid of phosphorus T. Q. P and Q, respectively, are the sodium salts of
Answer» HYPOCHLOROUS & CHLORIC acids Hypochlorous & CHLOROUS acids Chloric & PERCHLORIC acids Chloric & hypochlorous acids Answer :A

24093.	The reaction of Cl_(2) gas with cold-dilute and hot-concentrated NaOH in water give sodium salts to two (different) oxoacids of chlorine, P and Q, respectively. The Cl_(2) gas reacts with SO_(2) gas, in presence of charcoal, to give a product R. R reacts with white phosphours to give a compound S. On hydrolysis. S gives an oxoacid of phosphorus T. Q. R, S and T, respectively
Answer» `SO_(2)Cl_(2),PCl_(5) & H_(3)PO_(4)` `SO_(2)Cl_(2),PCl_(3)&H_(3)PO_(3)` `SOCl_(2),PCl_(3)&H_(3)PO_(2)` `SOCl_(2),PCl_(5)&H_(3)PO_(4)` Solution :(a) `Cl_(2)+"cold DIL. "NaOHtoNaOCl+NaCl` `Cl_(2)+"hot conc. "NaOHtoNaClO_(3)+NaCl` NaOCl is salt of hypochlorous acid=F `NaOCl_(3)` is salt of chloric acid=Q. `Cl_(2)+SO_(2) overset("CHARCOAL")toSO_(2)Cl_(2)(R)` `PCl_(5)+H_(2)O to H_(3)PO_(4)(T)+HCL`

24094.	The reaction of chloroform with alcoholic KOH and p-toluidine forms :
Answer» ANSWER :B

24095.	The reaction of chlorobenzene with NaOH is known as……………. .
Answer» KOLBE's reaction Riemer-Tiemann reaction Dow's process CUMENE synthesis Solution :Dow.s process

24096.	The reaction of chloro benzene with aqueous NaOH to give phenol is known as …………………. .
Answer» SOLUTION :DOWS PROCESS

24097.	The reaction of chlorine with propene at 400-600^(@)C gives mainly :
Answer» `CH_(3)CHClCH_(2)Cl` `underset(Cl)underset("\|")(CH_(2))underset(Cl)underset("\|")(CH)underset(Cl)underset("\|")(CH_(2))` `CH_(3)CH=CHCl` `ClCH_(2)CH=CH_(2)` SOLUTION :`CH_(2)=CH-CH_(3)underset(400-600^(@)C)OVERSET(Cl_(2))rarrCH_(2)=CH-CH_(2)Cl` It is known as ALLYLIC substitution reaction.

24098.	The reaction of chlorine with propene at 500-600^(@)C proceeds through the formation of :
Answer» PROPYL CARBONIUM ION ALLYL carbonium ion allyl free radical VINYL free radical Answer :C

24099.	The reaction of chlorine with CO in the presence of sun light gives
Answer» `COCl_(2)` `CO_(2)CI_(2)` `HNO_(3)` `H_(2)SO_(4)` ANSWER :A

24100.	The reaction of chioroform with alcoholic KOH and p-toludine forms
Answer» ANSWER :B

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