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24151.

The reaction of 4 -bromobenzyl chloride with NaCl in ethanol forms

Answer»

4-Bromobenzyl CYANIDE
4-Cyanobenzylchloride
4-Cyanobenzylcyanide
4-Bromo-2-cyanobenzylchloride

SOLUTION :
Nucleophilic SUBSTITUTION of the alkylic halide with `CN^-` group take PLACE.
Discussion
24152.

The reaction obey 1 order with respect to H_(2) and Icl both H_(2(g))+2ICl_((g)) to 2HCl_((g))+I_(2(g)) Which of the following mechanism is consistent with the given fact ? Mechanism A : H_(2(g))+2ICl to 2HCl_((g))+I_(2(g)) Mechanism B : (i) H_(2(g))+ICl_((g)) overset ("slow") underset (HCl_((g))+HI_((g)))( to ) (ii) HI_((g))+ICl_((g)) to HCl_((g))+I_(2)

Answer»

A and B both
NEITHER A nor B
A only
B only

Answer :D
Discussion
24153.

The reaction occuring at the anode during the working of alkaline dry cell -

Answer»

`Zn + H_(2)O to ZNO + 2 OH^(-) + 2e^(-)`
`Zn + 2 OH^(-) to ZnO + H_(2)O + 2 e^(-)`
`Zn to Zn^(2+) + 2e^(-)`
`Zn^(2+) + 2e^(-) to Zn`

Solution :During working the REACTION at anode is OXIDATION of Zn to FORM `ZnO` as
`Zn + 2 OH^(-) to ZnO+ H_(2)O + 2 e^(-)`
Discussion
24154.

The reaction NO_(2(g))+O_((g)) to CO_(2(g)) +NO_((g)) proceeds in the following two steps at 500 K NO_(2(g)) + NO_2to NO+NO_3 Step - 1(slow) NO_3 + CO to CO_2 + NO_2 Step -2 (fast) Which of the following rate expressions is correct for the above reaction ?

Answer»

Rate `=-(d(NO_2])/(dt)=K[NO_2]`
Rate `=-(d[CO])/(dt) = k[NO_2]`
Rate `= -(d[NO_2])/(dt) =k[NO_2]^2`
Rate `=-(d[NO_2])/(dt) = k[NO_2][CO]`

SOLUTION :The rate expression in ACCORDING to the slow step of the reaction .
Rate = `(dx)/(dt) = k [NO_(2)]^(2)`
Discussion
24155.

The reaction not involved in the concentration of bauxite are by Hall's process is

Answer»

`Al_(2)O_(3)+ Na_(2)CO_(3) to 2NaAlO_(3)+CO_(2)`
`2NaAlO_(2)+3H_(2)O+CO_(2) to 2Al(OH)_(3)+Na_(2)CO_(3)`
`2Al(OH)_(3) to Al_(2) O_(3)+3H_(2)O`
`AlN+H_(2)O to AL (OH)_(3)+NH_(3)`

Answer :D
Discussion
24156.

The Product not involved in the concentration of bauxite are by Hall's process is

Answer»

Al
Na
`O_(2)`
`H_(2)`

ANSWER :C
Discussion
24157.

The reaction NO_(2)Cl(g) +NO(g) ltimplies NO_(2)(g) + NOCl(g) is a single step reversible reaction. The energy of activation for the forward reaction is 28.9 kJ and that for the backward reaction is 41.8 kJ. Draw energy level diagram for the reaction. Indicate E_(a)f and E_(a)b and DeltaH in the diagram.

Answer»

SOLUTION :As the energy of activation for the FORWARD reaction is LESS than the value for the backward reaction, this MEANS that the forward reaction is exothermic while the backward reaction is ENDOTHERMIC in nature. The various energy changes have been shown in the figure.
Discussion
24158.

The reaction : N_(2)O_(5)( "in" (C)Cl_(4) "solution") to2NO_(2)("same solution") +1//2O_(2)(g) is of first order in N_(2)O_(5) with rate constant = 6.2 xx 10^(-4)s^(-1). What is the value of the rate of reaction when [N_(2)O_(5)] with rate constant = 6.2 xx 10^(-4)s^(-1). What is the rate of reaction when N_(2)O_(5)=12.5 mol L^(-1)?

Answer»

`5.15 xx 10^(-5) MOL L^(-1)s^(-1)`
`6.35 xx 10^(-3) mol L^(-1)s^(-1)`
`7.75 xx 10^(-4)molL^(-1)s^(-1)`
`3.85 xx 10^(-4) mol L^(-1)s^(-1)`

Solution :c) rate `=k xx [N_(2)O_(5)]`
`(6.2 xx 10^(-4) s^(-1)) xx (1.25 mol L^(1))`
`7.75 xx 10^(-4) mol L^(-1)s^(-1)`
Discussion
24159.

The reaction N_(2)O_(5) (in C Cl_(4) solution ) to 2 NO_(2) (solution) + (1)/(2) O_(2) (gas ) is of first order in N_(2)O_(5) with rate constant 6.2 xx 10^(-1) s^(-1) . What is the value of rate of reaction when [N_(2)O_(5)] = 1.25 "mole" l^(-1)

Answer»

`7.75 xx 10^(-1) "MOLE" l^(-1) s^(-1)`
`6.35 xx 10^(-3) "mole" l^(-1) s^(-1)`
`5.15 xx 10^(-5) "mole" l^(-1) s^(-1)`
`3.85 xx 10^(-1) "mole" l^(-1) s^(-1)`

SOLUTION :Rate = `k (N_(2)O_(5)) = 6.2 xx 10^(-1) xx 1.25`
= `7.75 xx 10^(-1)` mol `l^(-1) s^(-1)`.
Discussion
24160.

The reaction ,N_2O_5 in 2NO_2 + (1//2)O_2(g) is of first order for N_2O_5 with rate constant 6.2 xx 10^(-4)s^(-1). What is the value of rate of reaction when [N_2O_5]= 1.25 mol L^(-1) ?

Answer»

`5.15 XX 10^(-5) MOL L^(-1) s^(-1)`
`6.35 xx 10^(-3)mol L^(-1)s^(-1)`
`7.75 xx 10 ^(-4) mol L^(-1) s^(-1)`
`3.85 xx 10^(-3) mol L^(-1) s^(-1)`

SOLUTION :`r = K[N_2O_5]= 6.2 xx 10^(-4)xx 1.25 = 7.75 xx 10^(-4)M/s`
Discussion
24161.

The reaction N_(2(g))+O_(2(g))rarr2NO_((g)) is endothermic. The forward reaction is

Answer»

FAVOURED by DECREASE in temperature
favoured by increase in pressure
unchanged on changing pressure
in EQUILIBRIUM POINT shifts by adding catalyst

Solution :`n_(p)=n_(r)`. Therefore, pressure has no effect.
Discussion
24162.

The reaction N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g) is in equlibrium. Now the reaction mixture is compressed to half the volume

Answer»

More of ammonia will be formed
Ammonia will dissociate back into `N_(2)and H_(2)`
There will be no effect on equlibrium
Equlibrium constant of the reaction will change

Solution :`K_(c)=([NH_(3)]^(2))/([N_(2)][H_(2)]^(3)).` What volume is halved, CONCENTRATIONS are DOUBLED. To keep `K_(c)` CONSTATN, increase of `[NH_(3)]` should be more.
Discussion
24163.

The reaction N_2 + 3H_2 hArr 2NH_3 favoured at _____.

Answer»


ANSWER :HIGH PRESSURE
Discussion
24164.

The reaction, MnO_(4)^(2-) +e^(-)hArr MnO_(4)^(-) is shifted to right in

Answer»

an ACIDIC MEDIUM
a BASIC medium
a netural medium
both acidic and bisic MEDIA

ANSWER :A
Discussion
24165.

The reaction MnO_(4)^(-) + e^(-) to MnO_(4)^(2-) occur in

Answer»

a BASIC MEDIUM
an ACIDIC medium
a NEUTRAL medium
both acidic and basic medium.

ANSWER :A
Discussion
24166.

The reaction MnO_4^(-) + e^(-) rarr MnO_4^(2-) takes place in :

Answer»

BASIC medium
ACIDIC medium
Neutral medium
Both acidic and basic medium

Answer :A
Discussion
24167.

The reaction M^(2)+2e^(-) to M has standard potential of -0.66V . This means

Answer»

M cannot REPLACE hydrogen from acid
M is a REDUCING agent
Both are EQUALLY strong
The CELL between M and `H_(2)` is not possible

Answer :B
Discussion
24168.

The reaction ltBrgt CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-ON a+CH_(3)CH_(2)Cloverset(-NaCl)toCH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-O-CH_(2)-CH_(3) is called.

Answer»

Etard reaction
Gattermann-kock reaction
Williamson synthesis
Williamson CONTINUOUS etherification process.

Solution :It is the CORRECT ANSWER.
Discussion
24169.

C_4 cycle takes place in:

Answer»

BASIC medium
ACIDIC medium
Neutral medium
Both acidic and basic medium

Answer :A
Discussion
24170.

The reaction L to M is started with 10.0 of L. After 30 and 90 minutes 5.0 g and 1.25 g of L respecetively are left. The order of the reaction is

Answer»

0
1
2
3

Solution :`10 g to 5 g to 2.5 g to 1.25 g` takes 30 min in each step i.e. `t_(1//2)`is INDEPENDENT of 'a'. Hence, it is REACTION of 1st order.
Discussion
24171.

The reaction ,RCOOAg + Br_2 overset(C Cl_4)rarr RBr + AgBr+CO_2 is called :

Answer»

HVZ REACTION
Hunsdiecker reaction
Hofmann.s reaction
CARBYLAMINE reaction

ANSWER :B
Discussion
24172.

The reaction L rarr M is started with 10 g of L. After 30 and 90 minute, 5 g and 1.25g of L are left respectively. The order of reaction.is:

Answer»

0
2
1
3

Answer :C
Discussion
24173.

The reaction kinetics can be studied by

Answer»

Measurement of `PH`
TITRATION with HYPO after adding `KI`
Both (a) and (B) are correct
Noneis correct

Solution :`Cl` attached to `N` in reactant oxidizes `KI t o I_(2)` which can be DETERMINED by hypo `(Na_(2)S_(2)O_(3))`.
Discussion
24174.

The reaction ,KI +I_(2-)>KI_3 shows:

Answer»

OXIDATION
REDUCTION
COMPLEX formation
All of these

Answer :D
Discussion
24175.

The reaction is of 1^(st) order.At initial the concentration of reactant is 0.1 mol L^(1) .Rate constant is =3xx10^(-2)s^(-1).Then what is the rate of reaction at initial?

Answer»

`3xx10^(-3)` MOL `L^(-1)s^(-1)`
`2XX10^(-3)` mol `L^(-1)s^(-1)`
`1xx10^(-3)` mol`L^(-1)s^(-1)`
`0.1xx10^(-3)` mol `L^(-1)s^(-1)`

SOLUTION :Rate=k`[R]^(1)`
`=(3xx10^(-2)L^(1)s^(-1))`(0.1 mol `L^(-1)`)
`=3xx10^(-3) "mol" L^(-1) s^(-1)`
Discussion
24176.

The reaction is obtained by the action of alcholic KCN and what?

Answer»

1-butyl ehtyl ether
2-methyl 1-propene
2-2-dimethyl butane
isopropyl n-propyl ether

Solution :Sodium ETHOXIDE is a strong base. The nucleophile `C_(2)H_(5)O^()` can not attack at the carbon of C-Cl due to steric hindrance. Hence, ELIMINATION reaction occursto fomr alkene.
`CH_(3)- UNDERSET(CH_(3)) underset(|)overset(CH_(3)) overset(|)C-Cl+ underset("alc")(C_()H_(5)ONa)+ CH_(3)- overset(CH_(2)) overset(||)C-CH_(3)+C_(2)H_(5)OH+NaCl`
Discussion
24177.

The reaction is known as

Answer»

pinacol-pinacolone rearrangement
curtius rearrangement
benzidine rearrangement
none of these

Solution :SEE some NOTE WORTHY POINTS of NITRO compounds.
Discussion
24178.

The reaction :is known as …..

Answer»

Sandmeyer's REACTION
Balz-schiemann reaction
BIRNBAUM - Simonini reaction
GATTERMAN reaction

Answer :B
Discussion
24179.

The reactionis fastest when X is:

Answer»

CL
`NH_(2)`
`OC_(2)H_(5)`
`OCOR`

Solution :ACID CHLORIDES REACT fastest.
Discussion
24180.

The reaction is carried out in the presence of pyridne, Which of the followingmechanisms does it follow?

Answer»

`SN^(1)`
`SN^(2)`
`SN^(i)`
`E2`

SOLUTION :NA
Discussion
24181.

The reaction involving the treatment of benzene diazonium chloride with copper powder and HCl is treated as:

Answer»

SANDMEYER's REACTION
GATTERMANN's reaction
Ulmann's reaction
Kolbe's reaction

Answer :B
Discussion
24182.

The reaction involved in the oil of Winter Green test is salicylic acid underset(conc." "H_(2)SO_(4))overset(Delta)to product. The product is treated with Na_(2)CO_(3) solution. The missing reagent in the above reaction is

Answer»

NaOH
Ethanol
Methanol
Phenol

Solution :The DIRECT esterification of methanol with SALICYLIC acid in the PRESENCE of conc. `H_(2)SO_(4) `gives methyl SALICYLATE or oil of winter green.
.
Discussion
24183.

The reaction involving condensation of acetic anhydride with a n aromatic aldehyde by a carboxylate ion is an exaple of :

Answer»

ALDOL condensation
BENZOIN condensation
Perkin's reaction
Wurtz reaction

Answer :C
Discussion
24184.

The reaction involved in the oil of Winter Green test is: salicylic acid underset (Conc. H_(2)SO_(4))overset(X,Delta)(to) Product. The product is treated with Na_(2)CO_(3) solution. The missing reagent X in the above reaction is

Answer»

NaOH
Ethanol
METHANOL
Phenol

Solution :The direct esterification of methanol with slaicyhlic ACID in the presence of CONC. `H_(2)SO_(4)` gives methyl salicylate or oil of WINTER green.
Discussion
24185.

The reaction involved in the oil of winter Green test is salicyclic acid underset("conc." H_(2)SO_(4))overset('X',Delta)(rarr)product. The product is treated with Na_(2)CO_(3) solution. The missing reagent 'X' in the above reaction is :

Answer»

NaOH
ethanol
methanol
phenol

Answer :C
Discussion
24186.

The reaction intermediate formed in the given reaction bears (AAK_MCP_35_NEET_CHE_E35_021_Q01)

Answer»

POSITIVE charge
NEGATIVE charge
Both positive and negative charge
No charge

Answer :D
Discussion
24187.

The reaction intermediate carbenes are produced from"

Answer»

diazo methane
ketene
`CHCl_(3)//C_(2)H_(5)ONA`
all of these

Answer :D
Discussion
24188.

The reaction in which the yield of the products can not be increased by the application of high pressure is –

Answer»

`PCl_(3) (g) + Cl_(2) (g)hArrPCl_(5) (g)`
`N_(2) (g) + 3H_(2) (g)hArr2NH_(3) (g)`
`N_(2) (g) + O_(2) (g)hArr2NO (g)`
`2SO_(2) (g) + O_(2) (g)hArr2SO_(3) (g)`

ANSWER :C
Discussion
24189.

The reaction in which the samesubstance undergoes oxidationas well as reduction is called "…..................." reaction.

Answer»


ANSWER :DISPROPORTIONATION
Discussion
24190.

The reaction in which the same substance undergoes both oxidation and reduction is known as __________ reaction.

Answer»

SOLUTION :DISPROPORTIONATION
Discussion
24191.

The reaction in which phenol differs from alcohol is

Answer»

it UNDERGOES esterification with carboxylic acid
it reacts with ammonia
it forms yellow crystals of IODOFORM
it liberates `H_(2)` with Na metal

Solution :Iodoform test is exhibited by ethyl alcohol acetaldehyde, acetone, methyl ketones and those ALCOHOLS which possess `CH_(3) CH(OH) `- group. This test is not GIVEN by phenols.
Discussion
24192.

The reaction in which hydrogen is not one of the product is

Answer»


(`AKK_MCP_36_NEET_CHE_E36_017_A01`)

ANSWER :D
Discussion
24193.

The reaction in which heat is absorbed is known as:

Answer»

EXOTHERMIC
Endothermic
Reversible
NONE of the above

ANSWER :B
Discussion
24194.

The reaction in which DeltaHgtDeltaU is

Answer»

`N_(2(g)) + O_(2(g)) to 2NO_(g)`
`CaCO_(3(s)) to CaO_(s) + CO_(2(g))`
`N_(2(g)) + 3H_(2(g)) to 2NH_(3(g))`
`CH_(4(g)) + 2O_(2(g)) to CO_(2(g)) + 2H_(2)O_((L))`

Solution :(b) As `DeltaH = DeltaU + Deltan_(g)RT`
For the reaction, `CaCO_(3(s)) to CaO_(s)+CO_(2(g))`
`Deltan_(g)=1`
`:. DeltaH gt DeltaU`
Discussion
24195.

The reaction in the Kipp.s apparatus stops on closing the outlet, because:

Answer»

The acid becomes weak
Gas STARTS coming out from top
A protective film is formed on IRON SULPHIDE
The contact between sulphide and the acid is broken by the presence of gas collected in the FREE surface of the middle chamber

Answer :D
Discussion
24196.

The reaction in which catalyst and reactant have one phase are known as:

Answer»

GASEOUS reaction
Homogeneous CATALYTIC reaction
Heterogeneous catalytic reaction
None

Answer :B
Discussion
24197.

The reaction , illustrate :

Answer»

Gabriel.s phthalimide reaction
A good METHOD to prepare pure
secondary amine
A reaction which can be extended to
preparation of `ALPHA`- amino acid
None

Answer :A
Discussion
24198.

The reaction H_(2)S+H_(2)O_(2)rarrS+2H_(2)Oshows

Answer»

acidic nature of `H_(2)O_(2)`
basic nature acition of `H_(2)O_(2)`
OXIDISING ACTION of `H_(2)O_(2)`
reducing action of `H_(2)O_(2)`

ANSWER :C
Discussion
24199.

The reaction ,H2​ S+H2​ O2​ →S+2H2​ O shows :

Answer»

`ACIDIC nature ofH_2O_2`
Alkaline nature of`H_2O_2`
OXIDISING ACTION of `H_2O_2`
Reducing action of `H_2O_2`

Answer :C
Discussion
24200.

The reaction, H_2S+H_2O_2 rarrS+2H_2O manifests:

Answer»

ACIDIC NATURE of `H_2O_2`
Alkaline nature of `H_2O_2`
Oxidising nature of `H_2O_2`
REDUCING nature of `H_2O_2`

ANSWER :C
Discussion